Calculate the 95onfidence interval for the true population mean based on a sample with =225, =8.5, and =45. function

The absolute-value equation to find Jason's max and min speeds is |x| = |55 ± 5| mi/h and the maximum speed is 60 mi/h and the minimum speed is 50 mi/h.

Absolute Value equation:

An absolute value equation in the form | ax + b | has the following properties:

If c < 0 , | a x + b | = c has no solution .

If c = 0 , | a x + b | = c has one solution .

If c > 0 , | a x + b | = c has two solutions .

Given,

Jason is driving his car at 55mi/h he needs to keep his car within 5 mi/h of his current speed.

Here we need to write solve an absolute-value equation to find Jason's max and min speeds.

We know that, the current speed = 55 mi/h

And he want to keep the speeds within 5 mi/h of his current speed.

Let x be the unit that measure the maximum and minimum speed.

So,

The maximum speed.

|x| = 55 + 5 = 60 mi/h

and the minimum speed,

|x| = 55 - 5 = 50 mi/h

So, the absolute value of the equation is,

|x| = |55 ± 5| mi/h

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Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

The expression that is equivalent to the given expression is 3⁶/7¹⁵

From the question, we are to determine the expression that is equivalent to the given expression

The given expression is

[tex]\left(\frac{7^{-3} }{3^{-2} \times 7^{2}} \right)^{3}[/tex]

Simplifying

[tex]\left(\frac{7^{-3} }{3^{-2} \times 7^{2}} \right)^{3}[/tex]

[tex]\left(\frac{7^{-3 \times 3} }{3^{-2 \times 3} \times 7^{2 \times 3}} \right)[/tex]

[tex]\left(\frac{7^{-9} }{3^{-6} \times 7^{6}} \right)[/tex]

= [tex]\left( 7^{-9} \times \frac{1}{3^{-6}} \times \frac{1 }{7^{6}} \right)[/tex]

= [tex]\left( \frac{1}{7^{9} } \times 3^{6} \times \frac{1 }{7^{6}} \right)[/tex]

= [tex]\left(\frac{3^{6} }{7^{9} \times 7^{6}} \right)[/tex]

= [tex]\frac{3^{6} }{7^{9+6}}[/tex]

= [tex]\frac{3^{6} }{7^{15}}[/tex]

Hence, the expression that is equivalent to the given expression is 3⁶/7¹⁵

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so a lot of detachment is really just a former way of saying, like if then so it's if you pass a final, then you pass the class. You passed the final.

Therefore you pass the class, right? So it's the law of attachment basically says, Okay, if U then D and we're just told that U is true.

Answer:

56247,89

Step-by-step explanation:

Answer:

gegrgryyrryryryyryryr

Arrangement of students from shortest to tallest is

Kim 56.03 < Roy 56.14 < Alexa 56.3 < Tom 57.1.

As given in the question,

Number of students =  4

Height of the students

Kim = 56.03 units

Alexa = 56.3 units

Roy = 56.14 units

Tom = 57.1 units

Arrange the students from shortest to tallest

56.03 < 56.14 < 56.3 < 57.1

Kim < Roy < Alexa < Tom

Therefore, arrangement of students from shortest to tallest is

Kim 56.03 < Roy 56.14 < Alexa 56.3 < Tom 57.1.

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Answer:

Step-by-step explanation:

y=csc(x)      x∈ [-2,2]

[tex]A.\\\displaystyle\\Increasing: \ [-2,-\frac{\pi }{2})U(\frac{\pi }{2},2]\\\\Decreasing:\ (-\frac{\pi }{2},0)U(0,\frac{\pi }{2} ) \\\\B.\\\\Relative\ min:\ 1\\\\Relative \ max:\ -1[/tex]

                                           Watching the graph:

Answer:

[tex]\textsf{Increasing}:\left[-2,-\dfrac{\pi}{2}\right) \textsf{ and }\left(\dfrac{\pi}{2},2\right][/tex]

[tex]\textsf{Decreasing}:\left(-\dfrac{\pi}{2}, 0\right) \textsf{ and }\left(0, \dfrac{\pi}{2}\right)[/tex]

[tex]\textsf{Relative min}: \left(\dfrac{\pi}{2},1 \right)[/tex]

[tex]\textsf{Relative max}: \left(-\dfrac{\pi}{2},-1 \right)[/tex]

Step-by-step explanation:

Part A

Given function:

[tex]f(x)=\csc (x), \quad -2\leq x\leq 2[/tex]

[tex]\csc(x)=\dfrac{1}{\sin(x)}[/tex]

Therefore, the function f(x) is undefined when sin(x) = 0, leading to vertical asymptotes at the value of x where sin(x) = 0.

[tex]\sin(x) = 0 \textsf{ at }x = 0\pm 2 \pi n, \pi \pm 2 \pi n[/tex]

Therefore, f(x) has a vertical asymptotes at x = -2π, -π, 0, π, 2π etc.

Where the graph of the sine function increases, the graph of the cosecant function decreases.

Where the graph of the sine function decreases, the graph of the cosecant function increases.  

The sine function increases on the intervals:

[tex]\left(-\dfrac{\pi}{2}\pm 2 \pi n, \dfrac{\pi}{2}\pm 2 \pi n\right)[/tex]

and decreases on the intervals:

[tex]\left(\dfrac{\pi}{2}\pm 2 \pi n, \dfrac{3\pi}{2}\pm 2 \pi n\right)[/tex]

Therefore, for the interval -2 ≤ x ≤ 2, the cosecant function f(x):

Increases on the intervals:

[tex]\left[-2,-\dfrac{\pi}{2}\right) \textsf{ and }\left(\dfrac{\pi}{2},2\right][/tex]

Decreases on the intervals:

[tex]\left(-\dfrac{\pi}{2}, 0\right) \textsf{ and }\left(0, \dfrac{\pi}{2}\right)[/tex]

Part B

The relative minimums of the graph of the sine function are the relative maximums of the graph of the cosecant function.

The relative maximums of the graph of the sine function are the relative minimums of the graph of the cosecant function.

The sine function has a range of -1 ≤ sin(x) ≤ 1.

Therefore, its minimum points are when sin(x) = -1 and its maximum points are when sin(x) = 1.

[tex]\sin(x)=-1 \implies x=\dfrac{3\pi}{2}\pm 2 \pi n \implies \textsf{Minimum points}: \left(\dfrac{3\pi}{2}\pm 2 \pi n ,-1 \right)[/tex]

[tex]\sin(x)=1 \implies x=\dfrac{\pi}{2}\pm 2 \pi n \implies \textsf{Maximum points}: \left(\dfrac{\pi}{2}\pm 2 \pi n,1 \right)[/tex]

Therefore, the minimum and maximum points of the cosecant function in the given interval -2 ≤ x ≤ 2 are:

[tex]\textsf{Relative min}: \left(\dfrac{\pi}{2},1 \right)[/tex]

[tex]\textsf{Relative max}: \left(-\dfrac{\pi}{2},-1 \right)[/tex]

Note in the attached graph:

The function g that is finally graphed after the transformations are applied is g(x) = -5f(-x) - 10

The function is given as:

f(x)

Next, we apply the transformations

So, we have:

(1) reflect about the x-axis;

This is represented as

(x, y) = (x, -y)

So, we have

g(x) = -f(x)

(2) shift down 2 units;

This is represented as

(x, y) = (x, y - 2)

So, we have

g(x) = -f(x) - 2

(3) stretch vertically by a factor 5;

This is represented as

(x, y) = (x, 5y)

So, we have

g(x) = 5(-f(x) - 2)

Evaluate

g(x) = -5f(x) - 10

(4) reflect about the y-axis.

This is represented as

(x, y) = (-x, y)

So, we have

g(x) = -5f(-x) - 10

Hence, the function g that is finally graphed after the following transformations are applied is g(x) = -5f(-x) - 10

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In linear equation the solution set of the equations x = 1/2, y = -3.

What in mathematics is a linear equation?

Multiply both sides of the equation by a

coefficient -  2(4x - 3y ) = 11 × 2

                     3 ( 10x + 2y ) = ( - 1 ) × 3

apply multiplicative distribution law

8x - 6y = 11 × 2

3( 10x + 2y ) = (-1) × 3

calculate the first terms

8x - 6y = 22

3( 10x + 2y ) = ( -1) × 3

remove the parentheses

8x - 6y = 22

30x + 6y = -3

add up the two equation

8x - 6y + ( 30x + 6y ) = 22 + ( -3)

remove parentheses  - 8x - 6y + 30x + 6y = 22 -3

cancel the unknown variables - 8x + 30x = 22 -3

combine like terms - 38x = 22 - 3

calculate the sum or difference - 38x = 19

reduce the greatest common factor on both

sides of equation - 2x = 1

divide both sides of the equation by the coefficient of variable - x = 1/2

substitute one unknown quantity into the elimination 8 * 1/2 - 6y = 22

reduce the expression to the lowest term 4-6y = 22

reduce the greatest common factor on both sides of the equation

2 - 3y = 11

Rearrange unknown terms to the left side of the equation - 2 - 3y = 11

calculate the sum or difference  -3y = 9

reduce the greatest common factor on both sides of the equation   -y = 3

divide both sides of the equation by the coefficient of variable   y = -3

the solution set of the equations

x = 1/2

y = -3

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Answer:

a=4

ST=48

As we know ,

RT=RS+ST=7a+12a=19a

And RT=76

That’s why RT=19a=76 => a = 76/19=4

ST=12a=12*4=48

then we find ,

a=4

ST=48

In geometry, variables often appear in problems related to perimeter, area and volume. Typical problems provide you with some precise measurements and ask you to find out an unknown measurement, or variable.

Determine which formula you need. For example, if you're working with the area of a triangle, you need to know that area equals one half the base times the height, or A=1/2bh.

Plug the known values into the formula. Using the area of the triangle example, assume you know that the area is 100 square inches and the base is 20 inches. When you plug these values into the formula, you get 100=1/2 (20h). The height of the triangle is the variable.

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Answer:

=0.0000541

Step-by-step explanation:

[tex]\frac{0.00541}{10^2}[/tex]
[tex]\frac{0.00541}{100}[/tex]
[tex]=0.0000541[/tex]

Answer:0.0000541

Step-by-step explanation:

Firstly, you'll simplify 10².

10²÷0.00541 ---> 100 ÷ 0.00541

Then, you'll divide 100 by 0.00541.

100 ÷ 0.00541 ---> 18484.2883549

The amount of blood that a cylindrical tube hold will be 0.23 cubic dm.

Let r be the radius and h be the height of the cylinder. Then the volume of the cylinder will be

V = π r²h cubic units

A cylindrical tube 14.5 cm high and 4.5 cm in diameter is used to collect blood samples. Then the radius of the cylinder will be

r = d / 2

r = 4.5 / 2

Then the volume of the cylinder will be

V = π r²h

V = 3.14 (4.5 / 2)² × 14.5

V = 3.14 × 20.25 × 14.5 / 4

V = 921.98 / 4

V = 230.5 cubic cm

V = 0.23 cubic dm

The amount of blood that a cylindrical tube hold will be 0.23 cubic dm.

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An absolute value inequality that represents all the distances you may be from your house is -14 ≤ x ≤ 14.

Inequality:

Basically, inequality is the relation which makes a non-equal comparison between two numbers or other mathematical expressions.

Given,

You plan on going golfing this weekend with a friend. you can either go to your favorite course which is 14 miles north of your house or to your friends favorite course which is 14 miles south of your house.

Here we need to write an absolute value inequality that represents all the distances you may be from your house.

Consider your house is in the center.

So, both sides you have the Golf course.

So, it can be written as

-14 for north side one and 14 for the south side one.

And let x be the distance between the house and the golf course.

So, it can be written as the inequality,

=> -14 ≤ x ≤ 14.

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Answer:

So bassiccalyy the answer is 3344/3 because it is not equivalent to 4

Linear equations are equations that has a leading degree of 1. The value of x that makes the equation true is 1/4

Linear equation are equations that has a linear degree of 1. The standard linear equation is y = mx + b

Given the expression below

2(3 - 7x) = 4 - 6x

Expand

6 - 14x = 4 - 6x

Collect the like terms

6 - 14x = 4 - 6x

-14x + 6x = 4 -6

-8x = -2

Divide both sides by -8

-8x/-8 = -2/-8

x = 1/4

Hence the value of x that makes the equation true is 1/4

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The rate of change for each set of ordered pairs is:

a. 1/2

b. 3

c. 7

The average rate of change = change in y / change in x.

Average rate of change for (2,3.5), (6,5.5):

Average rate of change = (5.5 - 3.5)/(6 - 2) = 2/4 = 1/2

Average rate of change for (-1,0), (0, 3):

Average rate of change = (3 - 0)/(0 - (-1)) = 3/1 = 3

Average rate of change for (3,-3), (4,4):

Average rate of change = (4 -(-3))/(4 - 3) = 7/1 = 7

Therefore, the rate of change for each set of ordered pairs is:

a. 1/2

b. 3

c. 7

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The purchase price of a 5-year zero coupon bond will be $768.87.

The quantity of anything is stated as though it were a fraction of a hundred. A quarter of 100 can be used to express the ratio. Per 100 is what the term percent signifies. The symbol ‘%’ is used to symbolize it.

Let x be the price before 5 years.

If it is purchased today and has a face value of $1,000. Then we have

(1 + 0.046)(1 + 0.049)(1 + 0.052)(1 + 0.055)(1 + 0.068) x = 1000

(1.046 × 1.049 × 1.052 × 1.055 × 1.068) x = 1000

1.3 x = 1000

x = $768.87

The purchase price of a 5-year zero coupon bond will be $768.87.

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The mean of samples 10, 10, 10, 10, 10, and 16 will be 11.

The mean is the straightforward meaning of the normal of a lot of numbers. In measurements, one of the markers of focal propensity is the mean. The normal is alluded to as the number-crunching mean. It's the proportion of the number of genuine perceptions to the absolute number of perceptions.

In a sample of n = 6, five individuals all have scores of x = 10 and the sixth person has a score of x = 16.

Then the data set will be given below.

10, 10, 10, 10, 10, 16

Then the mean of the data set will be

Mean = (10 + 10 + 10 + 10 + 10 + 16) / 6

Mean = 66/6

Mean = 11

Thus, the mean of the sample will be 11.

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The post image coordinates are - A'(12,3), B'(10, -5) and C'(7,0)

Here, we are given 3 points A (-6, 15), B (-8,7) and C (-11, 12)

We are given the following translation rule- (x + 18) and (y - 12)

Let us take each point one by one-

A (-6, 15)

here x = -6

⇒ x + 18 = -6 + 18 = 12

and y = 15

⇒ y - 12 = 15 - 12 = 3

Thus the post image of A is (12, 3)

B (-8,7)

here x = -8

⇒ x + 18 = -8 + 18 = 10

and y = 7

⇒ y - 12 = 7 - 12 = -5

Thus the post image of B is (10, -5)

C (-11, 12)

here x = -11

⇒ x + 18 = -11 + 18 = 7

and y = 12

⇒ y - 12 = 12 - 12 = 0

Thus the post image of C is (7, 0)

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Anne's family wouldn't have gotten there until about 5:55 pm.

How Distance  is that?

The arrival time is the travel time added to the start time. The travel time is given by ...

 time = distance/speed

At 50 miles per hour, the travel time would be ...

 time = 383.5/50 = 7.67 . . . . hours

The fraction of an hour is ...

 (0.67 hours)×(60 min/hour) = 40.2 min

Adding the travel time to the start time, we get an arrival time of ...

 10:15 am + 7:40 = 17:55 = 5:55 pm

Anne's family wouldn't have gotten there until about 5:55 pm.

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The spherical tank with a capacity of 750 gallons has a radius of 2.88ft.

Volume refers to the total amount of space an object occupies. It also determines the capacity of the object.

Given the fact that 1 gallon is about 0.1337 ft^3, and the spherical tank has a capacity of 750 gallons, then it's volume or capacity can be converted from gallons to ft^3 by multiplying 750 with 0.1337.

1 gallon = 0.1337 ft^3

750 gallons = 750(0.1337 ft^3)

750 gallons = 100.275 ft^3

To solve for the radius of the spherical tank, use the formula for the volume of sphere given by the formula:

V = 4/3πr^3

where V = 100.275 ft^3

100.275 ft^3 = 4/3πr^3

r^3 = 23.93889288 ft^3

r = 2.882048957ft

Rounding off to the nearest hundredth of a foot:

r = 2.88ft

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Answer:

yes hdhdhzbw Ziad uebs U ue susna

Answer:

-96/7x or 13.714x

Step-by-step explanation:

-4/7+ 2/7x - 14x+4/7

first we do

4/7-4/7 which is zero, so we can cancel those out.

then we do

2/7x-14x ( or you can do -14x+2/7, it’s the same thing

use your calculator to make this easier. if you look you’ll be able to find a fraction button on most

after we do 2/7x-14x , we get -96/7x

if you want it in a fraction just divide and you’ll get -13.714x

Left-handedness is _more_______ common than usual among mathematicians and ___more_____ common than usual among artist

The relationship between handedness and mathematical ability is still highly controversial.

While some researchers have claimed that left-handers are gifted in mathematics and strong right-handers perform the worst in mathematical tasks, others have more recently proposed that mixed-handers are the most disadvantaged group.

However, the studies in the field differ with regard to the ages and the gender of the participants, and the type of mathematical ability assessed.

To disentangle these discrepancies, we conducted five studies in several Italian schools (total participants: N = 2,314), involving students of different ages (six to seventeen) and a range of mathematical tasks.

The results show that (a) linear and quadratic functions are insufficient for capturing the link between handedness and mathematical ability; (b) the percentage of variance in mathematics scores explained by handedness was larger than in previous studies.

The last theory drawing a causal link from handedness to mathematical ability through cognition is the hemispheric indecision hypothesis.

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