The mass is moving with an acceleration of 13.299 m/s².
What is the straight forward meaning of acceleration?The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics. They are vector quantities, accelerations.
According to therefore mentioned statement,
the direction of the net force applied on an object determines its acceleration;
according to mentioned data;
F₁=30N
F₂=10N
Net force on object;
F=F₁+F₂
F=F₁y+F₂Cos30°(-x)+F₂ Sinx(-y)
F=3y+10×(√3/2)(-x)+10×(1/2)(-y)
F=ma
ma=-5√3/2(x)+25y
2a=-5√3x/2+25y
a=-5√3x+25y
magnitude(a)=√(-5√3/2)²+(25/2)²
(a) =13.299m/s²
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At the end of a race a runner decelerates from a velocity of 9.00 m/s at a rate of 0.300 m/s2.
(a) How far does she travel in the next 15.0 s?
(b) What is her final velocity?
(a)In the next 15.0s, she traveled 101.250 m.
(b) 4.50 m/s is the runner's final speed.
Given:- initial velocity = 9m/s , deacceleration = 0.3 m/s2
distana(d), she moves in time (t)=15 s,
and we must determine this using the second equation of motion.
S = ut + 1/2 at2,
where s = the distance
u = initial velocity
t = time
a=-d = 0.300m/s
t=15.0
By putting all values in the formula above,
we have
d = (9.00)x(15.0)-1/2 (0.300) (15.0)²
d= 101.250 m.
In the next 15.0s, she traveled 101.250 m.
final speed (v) =?
from 1 Equation of Motion : v = u+at.
To solve, v=?
u=9.00 m/s
a= -d= 0.300 m/s²
t=15.0
v=u+at
v= 9 - 0.300 X15.0
= 4.50 m/s
4.50 m/s is the runner's final speed.
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Which of these objects could be falling with constant acceleration?
Object 1 and Object 2 will have a constant acceleration.
We know the expression for Displacement, Acceleration, and Time can be represented by the equation: S = ut + 1/2at². We will compare cases for each object at a given position and time and check if the object maintains a constant acceleration.
=> S = ut +1/2at², where S = Displacement/position of object, u = Initial velocity, t = time, a = acceleration.
For Object 1,
Case 1 : 0.44 = 0*0.3 + 1/2*a*(0.3)²
a = 9.78
Case 2 : 3.14 = 0*0.08 + 1/2*a*(0.8)²
a = 9.81
Acceleration is approximately constant for object 1.
For Object 2:
Case 1 : 0.06 = (0) (0.3) + ½ a (0.3)²
a = 1.33
Case 2: 3.09 = (0) (2.1) + ½ a (2.1)²
a = 1.40
Acceleration is approximately constant for object 2.
For Object 3:
Case 1 : 0.44 = (0) (0.3) + ½ a (0.3)²
a = 9.78
Case 2: 3.09 = (0) (2.1) + ½ a (2.1)²
a = 1.40
Acceleration has a lot of differences in both cases of Object 3 so it's not constant.
Hence, Object 1 and Object 2 have constant acceleration.
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A TV takes in 600J of electrical energy and gives out 300J of light, 240J of sound and 60J of heat energy (be careful here!). Calculate the efficiency.
Answer:
90%
Explanation:
The energy efficiency formula runs like efficiency = useful energy output/energy input * 100%.
The energy output here is 600 (300+240) and the input is 600J. However since its heat energy of 60 you won't include that. So you will input the output and the energy input in the formula and you will get 540/600=0.9
So your answer is 90%.
Sorry if its confusing, have a good day! :D
Two birds are flying south for the winter. Bird 1 reaches its destination in 6 hours, while bird 2 reaches its destination in 12 hours. If bird 2 covers twice as much distance as bird 1, what is the ratio of their average speeds (bird 1/bird 2)?
1.0
0.8
1.2
0.5
The correct answer is option ( A) the ratio of their average speeds (bird 1/bird 2) is 1.0
velocity = distance / Time
Let us assume distance covered by Bird 1 = d
case 1 (Bird 1) :-
time = 6 hours
velocity(Bird1) = d/6 = 0.167*d
case 2 (Bird 2) :-
time = 12 hours
distance is twice of Bird 1 = 2d
velocity(Bird2) = 2d/12 = 0.167*d
now, velocity of Bird1/Bird2 = (0.167*d)/(0.167*d) = 1.0
So,velocity of (Bird1/Bird2) is 1.0 .
Average velocity / Average speed = Total displacement / Total distance. Remember that the numerator is less than or equal to the denominator. As a result, the ratio is always equal to or less than one. Distance traveled divided by time taken is the most commonly used formula for calculating average speed. The other formula is to add the initial and final speeds together and divide by two.
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2. The longest snake ever found was a python that was 10.0 m long. Sup-
pose a coordinate system large enough to measure the python's length is
drawn on the ground. The snake's tail is then placed at the origin and the
snake's body is stretched so that it makes an angle of 60.0° with the posi-
tive x-axis. Find the x and y coordinates of the snake's head. (Hint: The y-
coordinate is positive.)
Answer:
See below
Explanation:
Hypotenuse is snake length 10 m
y coordinate = 10 sin 60 = 8.7 m
x coordinate = 10 cos 60 = 5m
In a longitudinal wave, the medium moves
left to right
up and down
in circles
In a longitudinal wave, the particles of the medium have to and fro motion about their mean motion, along the direction of wave motion.
Longitudinal waves are waves in which the displacement of the medium is in the same (or the opposite) direction as the wave propagation and the medium vibration is parallel ("along") to the direction the wave travels. Because they create compression and rarefaction when passing through a material, mechanical longitudinal waves are also known as compressional or compression waves. A nice illustration is a wave down the length of a stretched Slinky toy, where the space between the coils grows and shrinks. Examples from the real world include seismic P-waves and sound waves (which are oscillations in pressure, a particle's displacement, and a particle's velocity) (created by earthquakes and explosions).
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Four people participate in a rope competition. Two of them pull the rope right exerting forces of magnitude 330 N and 380 N. The other two pull left exerting forces of magnitude 320 N and 410N.
A rope competition is played out between four participants. They both pull on the rope to the right while producing forces between 330 N and 380 N. The other two pull to the left with forces of 320 N and 410 N, respectively.
T2 = 250 and T1 = 250.57 [N] .57[N]
In order to create a free body diagram with all the forces acting on the body, we must first extract all the information they provide about the issue.
The free body diagram and associated forces are shown in the accompanying figure.
The T1 and T2 forces can be found by adding up the forces on the Y-axis; these forces are equal because they are a precondition for the problem. Therefore, this equation can be solved.
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What is the escape speed from the Moon?
The Moon’s mass is 7.4×10^22 kg and its radius is 1700 km.
The speed of a spacecraft moving in a circular orbit just above the lunar surface: v = 1700 m/s
Express your answer using two significant figures.
v = __________ m/s
Answer:
1/2 m v^2 - G M m / R escape velocity equal to energy at surface
v^2 = 2 G M / R = 2 * 6.67E-11 * 7.4E22 / 1.7E6
v^2 = 2 * 6.67 * 7.4 / 1.7 * 105 = 5.81E6
v = 2410 m/s = 2400 m/s
Sam's mom says: "We're about to eat dinner! Don't go more than a few blocks from home!" Is Sam's mom
more worried about Sam's distance or his displacement? Circle one and explain why you picked it.
Answer:
Displacement
Explanation:
I think Sam's mom isn't worried with how far away he goes, but will be upset if he isn't home fast enough for dinner.
The makers of brand A hand sanitizer want to prove that their sanitizer kills more bacteria than the other 4 leading brands of sanitizer. They organize 60 test subjects into 6 groups of 10 test subjects. The test subjects participate everyday for one week, the data for the experiment is shown below where the final average number of bacteria still remaining is given.
Table 1. Effectiveness of Hand Sanitizer on Bacteria
[See Attached]
Please develop a CONCLUSION for this experiment.
Based on the results of the experiment, it can be concluded that the claim by Brand A that their sanitizer kills more bacteria than the other 4 leading brands of sanitizer is true.
What is an experiment?An experiment is a procedure carried out to support or refute a hypothesis, or determine the efficacy or likelihood of something previously untried.
The experiment is the foundation of the scientific method, which is a systematic means of exploring the world around us.
Experiments takes place in laboratories, but can also be performed anywhere at any time.
There are some steps in the scientific methods which includes:
Make observations.Formulate a hypothesis.Design and conduct an experiment to test the hypothesis.Evaluate the results of the experiment.Accept or reject the hypothesis.If necessary, make and test a new hypothesis.Considering the data table from the experiment:
The results of this study concur with brand A goals as hand sanitizers producers as product effectiveness has improved over time. The performance of brands A has indicated improved effectiveness as their claims has been found true with respect to other manufacturers of the sanitizer. This study showed that brand A hand sanitizers were tested and found more effective against selected brands.
In conclusion, the results of the experiments showed that in the comparison between the brands of hand sanitizers, brand A were most effective.
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In a biathalon race you first ride a bicycle at an average speed of 19.1 mi/h for 18.5 miles, then you must run for another 5.5 miles. With what average speed, in miles per hour, must you run if your average speed for the entire race is to be 14.5 mi/h?
The average speed you must run is 7.97 mph.
What is average speed?
The average speed of an object is the ratio of total distance traveled by the object to
Average speed = total distance / total time of motion
Total time of motion = total distance / average speed
total time = (18.5 + 5.5) / (14.5)
total time = 1.66 hours
time taken during the bicycle ridet1 = 18.5 / 19.1
t1 = 0.97 hour
time taken during the runt2 = 1.66 hr - 0.97 hr
t2 = 0.69 hr
Average speed during the runv = 5.5 miles /0.69 hr
v = 7.97 mph
Thus, the average speed you must run is 7.97 mph.
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The surface of the pool table is ℎ=0.790 m from the floor.
The winner of the competition wants to know if he has broken the world speed record for the break shot of 32 mph (about 14.3 m/s ). If the winner's ball landed at a distance of =5.05 m from the table's edge, calculate the speed of his break shot 0. Assume friction is negligible.
At what speed 1 did his pool ball hit the ground?
The calculated velocity is 3.88 m/s
Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. In other words, velocity is a vector, whereas speed is a scalar value. The parameters of speed are time divided by distance. The most often used unit of speed in daily life is the kilometer per hour (km/h), or miles per hour in the US and the UK. The SI's unit of speed is the meter per second (m/s) (mph).
h = 0.5g*t² = 0.77 4.9t²
= 0.77\st²
= 0.1571
t = 0.396 seconds or fall.
Dx = Xo*t, or 5.15 meters.
Xo * 0.396 = 5.15
Break speed is X= 13 m/s.
V² = V² + 2g*h.
V² = 0 + 19.6*0.77
= 15.09
V = 3.88 m/s
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Rattlesnake Frequency A timber rattlesnake (Crotalus horridus) shakes its rattle at a characteristic frequency of about 3100 shakes per minuteWhat is this frequency in shakes per second?
Answer:
See below
Explanation:
31 00 sh / min / 60 s / min = 51 2/3 shakes per second
A tank of oxygen has 125 kPa of pressure. The pressure is increased to 200 kPa and the final volume is 0.5 L. What was the initial volume?
According to the given data initial volume =0.667 L
Why is it called Boyle's law?Boyle observed that the product of the pressure and volume are observed to be nearly constant. For a perfect gas, the result of volume and pressure is a precise constant. Boyle's Law is the name given to the relationship among pressure and volume in his honor.
Who discovered Boyle's law?Boyle was a modern chemical pioneer in the 17th century, best known for his law of gases. Robert Boyle (1627–1691) is credited with discovering the renowned Boyle's law, which states that a gas's volume decreases with rising pressure and vice versa
Briefing:Since the change occurs at constant temperature (i.e. an isothermal change), Boyle's law applies,
i.e. p[tex]_1[/tex]V[tex]_1[/tex] = p[tex]_2[/tex]V[tex]_2[/tex] where p[tex]_1[/tex] = 125 kPa, p[tex]_2[/tex] = 200 kPa and V[tex]_2[/tex]=0 .5L
Hence, (150)V[tex]_1[/tex] = (200)(0.5)
from which, volume V[tex]_1[/tex] = 200×0.5/150=0.6667L
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a body of mass 7.5kg is moving with the velocity of 1.2, if a force of 15newton is applied to the body calculate its velocity after 2 seconds
The velocity is 5.2 m/s
Force as per the Newton's second law of motion is defined as, for constant mass, mass times the acceleration
F= m x a
where m is the mass of the body in kilograms and a is the acceleration is m/s^2
Now we know that acceleration is nothing but rate of change of velocity
i.e. a= (v -u)/t
where v is the final velocity
u is the initial velocity
and t is the time frame in which change takes place
Now the data given to us is as follows:
Force F= 15 Newton
initial velocity u =1.2 m/s
t= 2 seconds
We are required to find the final velocity v
Now putting the values in the equation,
F= m (v-u)/t
15 = 7.5 (v-1.2)/2
30= 7.5v -9
7.5v=39
v=39/7.5= 5.2 m/s
Hence the velocity is 5.2m/s
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A float starts 9.2 m west of a grand stand ( the origin ) for the parade . It heads towards the grandstand at the rate of 1.5m/s . Where is the float located at 3.5s?
The float is 3.95 m west of the grandstand after 3.5 s of its start.
What is Distance in relation with physics?The distance is defined as the total length of the path taken by a moving body in order to reach the final position starting from initial position. Mathematically -
Distance [d] = Speed [s] x time [t]
Given that a float starts from 9.2 m west of a grand stand for the parade with the speed of 1.5 m/s. Therefore we can write -
Speed [s] = 1.5 m/s
Distance between float and grandstand [D] = 9.2 m
The location of the float after 3.5 seconds of its start is as follows-
d = s x t
d = 1.5 x 3.5
d = 5.25
Therefore -
Distance between the float and the grandstand after 3.5 seconds of its start = D - d = 9.20 - 5.25 = 3.95 m
Therefore, the float is 3.95 m west of the grandstand after 3.5 s of its start.
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An object with a mass of 20 kg has a het force of 80 N acting on it. What is the acceleration of the object?
Explanation:
f=ma
a=f/m
a=80/20 = 4m/s
1.
A car is driving on a circular track tha has a diameter of 6km and
traveled across the black shaded region in 1 hour. What will the
cars velocity be in meters/seconds. 1 km= 1000 meters
6 km
V=²& D=vt T = ²
The velocity of the car moving in the circular path is determined as 1.67 m/s.
What is linear velocity?Linear velocity is the measure of the rate of change of displacement with respect to time when the object moves along a straight path.
v = d/t
where;
d is the distance of the objectt is time of motionv = (6 x 1000 m) / (1 x 3600 s)
v = 1.67 m/s
Thus, the velocity of the car moving in the circular path is determined as 1.67 m/s.
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If one pound of force acts through a distance of two feet, one foot-pound of work is done.
True
False
It is false that if one pound of force acts through a distance of two feet, one foot-pound of work is done.
What is work?Work is a measure of energy expended in moving an object. It is most commonly calculated by multiplying the force by distance.
It is said that no work is done if the object does not move.
According to this question, if one pound of force acts through a distance of two feet, a work of one pound-two feet is done.
It is therefore, false that if one pound of force acts through a distance of two feet, one foot-pound of work is done.
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Applying a constant net force to an object causes it to accelerate at 0=9.0 m/s2.
What will the acceleration 3 of the object be if the force is doubled and the mass is doubled?
The acceleration of the object be if the force is doubled and the mass is doubled is equal to 9m/s².
let the initial mass of the object be m₁.
given:
initial acceleration (a₁) = 9m/s²
initial constant force (F₁) = constant (k)
therefore,
F₁= m₁×a₁ ------------------------------- equation 1
now,
according to the the question the force is doubled
i.e.
new force (F) = 2×F₁
and the mass too is doubled,
i.e.
new mass of the object(m)=2×m₁
new equation for force and acceleration:
F= m ×a
2F=2m₁×a --------------------------equation 2
dividing equation 2 by equation 1
we get,
[tex]\frac{2F}{F}=\frac{2m₁×a}{m₁×a₁ }[/tex]
a = a₁
a=9m/s²
the acceleration of the object be if the force is doubled and the mass is doubled is equal to 9m/s².
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A force of 30 N is exerted on a wheeled cart. There is so little friction you can
ignore it. The acceleration of the cart is 6 m/s². Find the mass of the cart.
Answer:
force =mass*acceleration due to gravity
mass=force/acceleration
mass =30/6
mass=5kg
When water boils, is it steam or water vapor?
Answer:
It is water vapor.
Explanation:
When water boils, it is changing state from a liquid to a gas.
Answer: It is water vapor. When water boils, it is changing state from a liquid to a gas.
Explanation:
phys 181 check picture
Answer:
see below
Explanation:
a^3 = 125 m^3
b^2 = 8.41 s^2
c = 45 m/s Plug these values into the equation
125 / ( 8.41 * 45) = .33 m^2 / s
I need help with this question , thank you
Answer:
Should be 400m
Explanation:
2. How long will it take for a bicycle to travel across from point A to
point D as shown below in the figure if his velocity was 4 m/s. Hint: use
Pythagorean Theorem () to find your displacement. A²+ B² = (²
A
25m
B
25m
D
35m
C
V = & Devt T=B
Answer:
I guess equal to ABD
How do you find the x and y components of a vector ?
Answer:
If you were given the vector in vectorial form, for example, <5,7>, then the first number (5) will always be the x component and the second number (7) is the y component.
In other cases, you are given the magnitude of the vector and the angle created by said magnitude with respect to the y or x axis. In these cases, you must use the magnitude and angle of the vector as if it was the hypotenuse of a right triangle and find the values of x and y as the legs of said triangle using the sine and cosine created by the magnitude of the vector and the value of said magnitude.
---------------------------------------------------------------------------------------------------------
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A 50-cm-long spring is suspended from the ceiling. A 210 g mass is connected to the end and held at rest with the spring unstretched. The mass is released and falls, stretching the spring by 16 cm before coming to rest at its lowest point. It then continues to oscillate vertically.
The value of spring constant (k) is 25 N/m.
Conservation of energy, potential energy of a stretched spring, gravitational potential energy, frequency of oscillation in a spring coupled to a mass, and variation of acceleration due to gravity with altitude are the principles necessary to answer the given problem.
To begin, use energy conservation to equal change in gravitational potential energy on mass attached to spring and elastic potential energy of stretched spring. Then, in the equation, substitute the specified numbers and solve for the spring constant. Then, calculate the amplitude by taking half of the value of spring stretching from equilibrium, and the frequency of oscillation by using the calculation for frequency of oscillation in a stretched string in terms of mass and spring constant.
Formula apply
U=mgh
U=1/2kx^2
putting the value of K ,x ,mass and g then
k is 25N/m
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Is it possible for an object to be accelerating and at rest at the same time? Explain.
Answer:
Yes
Explanation:
acceleration is a change in velocity, so an object might be momentarily at rest but a split-second later have some speed, i.e. it can be changing its velocity even if it is momentarily at rest.
Question 4 of 10
Which of the following describes the reactants of a chemical reaction?
OA. The chemicals on the right side of a chemical equation
B. The substances that are formed
OC. The substances that are made
O D. The chemicals on the left side of a chemical equation
The substances that are altered and the chemicals on the right side of a chemical equation are the results of a chemical reaction. B and D are the appropriate choices.
Reactants are the substance(s) in a chemical equation to the left of the arrow. A component that is present at the outset of a chemical reaction is known as a reactant. Products are the substance(s) to the right of the arrow. A substance that remains after a chemical reaction is complete is known as a product. The creation of products from the reaction of two reactants is known as a chemical reaction. The compounds that result from a reaction are called products. The substances that are original materials are the reactants.
On the left side of the reaction are the reactants, and on the right are the products. B and D are the proper choices as a result.
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The speed of a train increases from 100 km/hr to 250 km/hr in 5 minutes. What is its acceleration?
Answer:30 km/hr2 is the exal
Explanation: