What is a set of values in math?

Answer:

1, 0.75, 1.25, 3, 0

Step-by-step explanation:

To find the value of the function, we find the y coordinate of the point with the given x value.

There are 5548 students majoring in computer science.

This problem is related to percentage we have to calculate the number of students with the percentage given. After multiplying the percent given to the total number of students we will get the required number of students.

Given that the total number of students in the university class is =7600

Also 73% of students are majoring in computer science.

Number of students majoring in computer science is = (73/100) of 7600

                                                                                   = 73×76

                                                                                   = 5548 students

So, the total number of students majoring in computer science is 5548.

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Answer: -30

Step-by-step explanation:

Answer:

the answer would be -30!!!

Step-by-step explanation:

i took the quiz.

The limit of the composite function is given as follows:

lim x->7 f(g(x)) = 2.

A limit is given by the value of function f(x) as x tends to a value.

From the graph of g(x), we have that the lateral limits at x = 7 are given as follows:

[tex]\lim_{x \rightarrow 7^-} = \lim_{x \rightarrow 7^+} = -2[/tex]

Hence:

lim x->7 f(g(x)) = f(lim x->7 g(x)) = f(-2).

Looking at the graph of f(x), we have that:

f(-2) = 2.

Hence:

lim x->7 f(g(x)) = 2.

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Answer:

52/129

Step-by-step explanation:

The equation in slope-intercept firm for this line is y = -4/3x - 13

Linear equations are equations that have constant average rates of change. Note that the constant average rates of change can also be regarded as the slope or the gradient

The given parameters are

Slope, m = -4/3

Point (x1, y1) = (-6, -5)

The linear equation is calculated as

y = m(x - x1) + y1

So, we have

y = -4/3(x + 6) - 5

Open the bracket

y = -4/3x - 8 - 5

Evaluate the difference

y = -4/3x - 13

Hence, the equation in slope-intercept firm for this line is y = -4/3x - 13

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Answer:

domain: {3,6,9}

range: {1,4,9}

Step-by-step explanation: take the x values in increasing order for domain and the y values in increasing order for range. Do not repeat values.

Brief The Question Please, Thank You

Step-by-step explanation:

ok, let's try this again. we need to explain congruence then in its details as an implicit part of the proof, as everything boils down to that.

due to AE = FC we also know that ED = BF.

because as ABCD is a parallelogram, it means AD = BC (and AB = DC).

and AD || BC, AB || DC.

as AD = AE + ED and BC = BF + FC, it means that

AE + ED = BF + FC

with AE = FC we can then simplify to

ED = BF.

as AD || BC, so is also ED || BF.

since the distance from E to D is the same as for B to F, it means that EB and DF must be equidistant to each other, and that means they are parallel.

and because ED || BF, that also means that both line segments are equidistant from each other, and that means that the connections between their end points (EB and DF) must have the same lengths.

therefore, the shape is a quadrilateral with 2 pairs of parallel and equally long line segments. and that is the definition of a parallelogram.

so, BEDF is a parallelogram.

The minuend and the subtrahend of 696 - 275 can be decomposed to give;

600 + 90 + 6

-

200 + 70 + 5

400 + 20 + 1

The decomposition into place values is chosen because of ease of reinforcing knowledge.

The decomposition method of subtraction involves decomposing the subtrahend, which is the smaller number and the place value of the numbers can be simply subtracted from the minuend.

In the subtraction, 696 - 275, the minuend is 696, while the subtrahend is 275.

Decomposing the subtrahend, gives;

275 = 200 + 70 + 5

Decomposing the minuend, gives;

696 = 600 + 90 + 6

The subtraction expression in the question, 696 - 275 gives;

696

-275

The above can therefore be decomposed as follows;

600 + 90 + 6

-

200 + 70 + 5

400 + 20 + 1

400 + 20 + 1 = 421

Therefore;

696 - 275 = 421

The reason the decomposition into place values of each digit is chosen is so as to make use of the easier understanding of subtracting numbers that are multiples of 10.

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The equation that represents Diego's cash flow is cash flow = $3,000-$2,715.

Cash flow is the difference between cash inflows and cash outflows. Cash inflow are additions to the cash flow. An example of cash inflow is monthly income. Cash outflow would reduce the cash flow. An example of cash inflow is expenses.

Cash inflow = income - expense

$3,000 - $2,715

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Distance of upper bond and lower bond is 120,000 and 150,000 centimeter

Given:

Number of steps walk = 1500 steps

Each step count = 90 centimeters

Correction in each step = 10 cm nearest

Find:

Lower bound and upper bound for d

Computation:

Lower bound step length = 90 - 10

Lower bound step length = 80 centimeters

Upper bound step length = 90 + 10

Upper bound step length = 100 centimeters

Lower bound d = 1500 × 80

Lower bound d = 120,000 centimeters

Upper bound d = 1500 × 100

Upper bound d = 150,000 centimeters

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Answer:

Step-by-step explanation:

Given function:

[tex]y=\dfrac{x-3}{x^2-2x-3}[/tex]

The domain is the set of all possible input values (x-values).

Factor the denominator of the function:

[tex]\implies y=\dfrac{x-3}{(x-3)(x+1)}[/tex]

The domain of the given function is restricted as the function is undefined when the denominator equals zero, and when both the numerator and denominator equal zero.  

Therefore, the function is undefined when x = -1 and x = 3.

Therefore, the domain is (-∞, -1) ∪ (-1, 3) ∪ (3, ∞).

The range is the set of all possible output values (y-values).

As the domain is restricted, the range is also restricted.

Therefore, the range is (-∞, 0) ∪ (0, ¹/₄) ∪ (¹/₄, ∞).

A function f(x) is continuous when, for every value [tex]c[/tex] in its domain:

[tex]\text{$f(c)$ is de\:\!fined \quad and \quad $\displaystyle \lim_{x \to c} f(x) = f(c)$}[/tex]

Point Discontinuity (holes): When a rational function has a factor with an x that is in both the numerator and the denominator.

Therefore, there is a point discontinuity at x = 3.

Infinite Discontinuity: A vertical asymptote occurs when the denominator of a rational function is zero. This is considered an infinite discontinuity when the graph exists on both sides of the asymptote.

Therefore, there is an infinite discontinuity at x = -1.

Stationary points occur when the gradient of a graph is zero.

Therefore, to find the x-coordinate(s) of the stationary points of a function, differentiate the function, set it to zero and solve for x.

[tex]\begin{aligned}y & =\dfrac{x-3}{x^2-2x-3}\\\\\implies \dfrac{\text{d}y}{\text{d}x} & = \dfrac{(x^2-2x-3)(1) - (x-3)(2x-2)}{\left(x^2-2x-3\right)^2}\\\\ & = \dfrac{(x-3)(x+1)-(x-3)(2x-2)}{\left((x-3)(x+1)\right)^2}\\\\& = \dfrac{(x-3)[(x+1)-(2x-2)]}{(x-3)^2(x+1)^2}\\\\ & = \dfrac{(x-3)(-x+3)}{(x-3)^2(x+1)^2}\\\\ & = \dfrac{-(x-3)^2}{(x-3)^2(x+1)^2}\\\\& = \dfrac{-1}{(x+1)^2}\end{aligned}[/tex]

[tex]\begin{aligned}\dfrac{\text{d}y}{\text{d}x} & = 0\\\implies \dfrac{-1}{(x+1)^2} & = 0\\ -1 & \neq 0\end{aligned}[/tex]

Therefore, there are no stationary points and no minimum/maximum points.

[tex]\textsf{A function is \textbf{increasing} when the \underline{gradient is positive}} \implies \dfrac{\text{d}y}{\text{d}x} > 0[/tex]

[tex]\textsf{A function is \textbf{decreasing} when the \underline{gradient is negative}} \implies \dfrac{\text{d}y}{\text{d}x} < 0[/tex]

Increasing

[tex]\begin{aligned}\dfrac{\text{d}y}{\text{d}x} & > 0\\\implies \dfrac{-1}{(x+1)^2} & > 0\\ \dfrac{1}{(x+1)^2} & < 0\\ \textsf{If $\dfrac{1}{a} < 0$ then $a < 0$}:\\(x+1)^2 & < 0\\ \textsf{As $(x+1)^2\geq 0$, no solution.}\end{aligned}[/tex]

Decreasing

[tex]\begin{aligned}\dfrac{\text{d}y}{\text{d}x} & < 0\\\implies \dfrac{-1}{(x+1)^2} & < 0\\ \dfrac{1}{(x+1)^2} & > 0\\ \textsf{If $\dfrac{1}{a} > 0$ then $a > 0$}:\\(x+1)^2 & > 0\\ \end{aligned}[/tex]

[tex]\textsf{For $a^n > 0$, if $n$ is even then $a < 0$ or $a > 0$}[/tex]

[tex]\implies x+1 < 0 \implies x < -1[/tex]

[tex]\implies x+1 > 0 \implies x > -1[/tex]

Combine the intervals:

(-∞, -1) ∪ (-1, ∞)

Therefore:

[tex]\textsf{A function is \underline{even} when $f(x) = f(-x)$ for all $x$.}[/tex]

[tex]\textsf{A function is \underline{odd} when $-f(x) = f(-x)$ for all $x$.}[/tex]

As there is no symmetry about the y-axis (even symmetry) and no origin symmetry (odd symmetry), the symmetry of the function is neither.

Answer:

Domain: (-∞, -1) ∪ (-1, 3) ∪ (3, ∞)

Range: [0, ∞)

Continuity: Point discontinuity (hole) at x = 3.

Infinite discontinuity (vertical asymptote) at x = -1.

None

Decreasing function: (-∞, -1) ∪ (-1, ∞)

Symmetry: Neither

The simplified value of the expression given as 3^2018 + 3^2015 / 3^2017 + 3^2016 is 7/3

The expression is given as:

3^2018 + 3^2015 / 3^2017 + 3^2016

Factor out 3^2015 in the expression

So, we have

3^2015(3^3 + 1)/3^2015(3^2 + 3)

Cancel out the common factor

(3^3 + 1)/(3^2 + 3)

Evaluate the exponents

(27 + 1)/(9 + 3)

This gives

28/12

Simplify

7/3

Hence, the simplified value of the expression given as 3^2018 + 3^2015 / 3^2017 + 3^2016 is 7/3

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7y+2=3x-5 is the given equation. Finding the point that does not lie on the specified line, 7y+2=3x-5, is the next step.

To determine whether or not the point meets the provided equation, we will simply enter in the supplied point.

Check for (2,-1/7)

Connect it to 7y+2=3x–5.

7(-1/7)+2=3(2)-5

-1+2=6-5

1=1

Which is correct; as a result, this point is on the line 7y+2=3x-5.

Verify (3,-2/7)

Connect it to 7y+2=3x–5.

7(-2/7)+2=3(3)-5

-2+2=09-5

1=4

Which is False; as a result, the supplied line 7y+2=3x-5 does not include this point.

Connect it to 7y+2=3x–5.

7(-1)+2=3(0)-5

-7+2=0-5

-5=-5

Which is correct; as a result, this point is on the line 7y+2=3x-5.

Verify (1, -4, 7)

Connect it to 7y+2=3x–5.

7(-4/7)+2=3(1)-5

-4+2=3-5

-2=-2

This is why I'm making this point

lies on the line 7y+2=3x-5 that is presented.

Verify (-1, -10/7)

Connect it to 7y+2=3x–5.

7(-10/7)+2=3(-1)-5

-10+2=-3-5

-8=-8

Which is correct; as a result, this point is on the line 7y+2=3x-5.

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Answer:

7561413

Step-by-step explanation:

6561413+1000000=    Equals Calculator Answer/////7561413

Answer:

7561413

Step-by-step explanation:

The calculator it equals 7561413

Answer:

greatest -( 9/36, -21/28, -7 )- smallest

Answer:

9/36

-7

-21/28

Step-by-step explanation:

You actually had them in the correct order

Answer:

y= -3x-4.

Step-by-step explanation:

1) the slope-interception form is:

y=slope*x+i, where i - interception;

2) using the given two points it is possible to calculate the slope:

[tex]slope=\frac{5+1}{-3+1}=-3;[/tex]

then the required equation has the form:

y=-3x+i;

3) in order to calculate the 'i', it is enough to substitute the coordinates of the one point into this form of the required equation:

-1=-3*(-1)+i; ⇒ i=-4.

4) finally, the required equation is:

y=-3x-4.

P.S. the suggested way is not the shortest one.

The quotient of A = - 210 and B = - 15 is 14.

The Euclid's Division Lemma says when a number 'a' is divided by a number 'b' gives the quotient to be 'q' and the remainder to be 'r' then the following relation -> a = bq + r exists, where 0 ≤ r < b.

Dividend [a] = Divisor [b] × Quotient [q] + Remainder [r]

Given two numbers A = - 210 and B = - 15

The resultant quotient when A is divided by B can be calculated using Euclid's division lemma. Initially, we will assume remainder [r] = 0.

If the quotient is in decimals, we will change the remainder according to it else if the quotient is a whole number, the remainder will remain 0.

Using Euclid's division lemma -

Dividend [a] = Divisor [b] × Quotient [q] + Remainder [r]

- 210 = - 15 x q + 0

- 210 = - 15 x q

q = - 210 / - 15 = 14

Since, the quotient is a whole number, the remainder will remain zero.

Therefore, the quotient of A = - 210 and B = - 15 is 14.

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Answer:

4    + 4√2

Step-by-step explanation:

[tex]CD=\sqrt{\left( 4-4\right)^{2} +\left( -5 - (-1)\right)^{2} } \\\\\\ =\sqrt{\left( 0\right)^{2} +(-4)^{2} }\\\\\\\ = \sqrt{16 }\\\\\\ =4[/tex]

[tex]DE=\sqrt{\left( 2-4\right)^{2} +\left( -3 - (-5)\right)^{2} } \\\\\\ =\sqrt{\left(-2\right)^{2} +(2)^{2} }\\\\\\\ = \sqrt{8 }\\\\\\ =2\sqrt{2}[/tex]

[tex]\text{\bf{EC} $=\sqrt{\left( 4-2\right)^{2} +\left( -1 - (-3)\right)^{2} } \\\\\\ =\sqrt{\left( 2\right)^{2} +(2)^{2} }\\\\\\\ = \sqrt{8 }\\\\\\ =2\sqrt{2}$}[/tex]

Perimeter (∆CDE) = CD + DE   + EC

                             = 4    + 2√2 + 2√2

                             = 4    + 4√2

                             ≈ 9.7

Answer:

4cm

Step-by-step explanation:

the ratio of the two scales is 100,000:300,000 which simplifies to 1/3

1/3 x 12 =4

The area of the region inside the rectangle that surrounds the square is; 162 square meters

We are given that;

Side length of square = 6 m

Width of rectangle = 11 m

Length of rectangle = 18m

Thus;

Area of rectangle = width * length = 11 * 18 = 198 square meters

Area of square = side * side = 6 * 6 = 36 square meters

Area of region inside rectangle not inside square = (area of rectangle) - (area of square) = 198 - 36 = 162 square meters

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Answer:2/3

Step-by-step explanation:

Product Y would be allocated 20% of the machine setups cost

Product Z  would be allocated 80% of the machine setups cost

What is activity-based costing?

Activity-based costing is a costing method where overhead cost of production are allocated based on the cost driver responsible for the overhead rather than using the plantwide overhead rate based on direct labor-hours.

In this case, we need to first of all determine the machine setups cost per per setups, based on the fact there 300 setups for both products Y and Z

machine setup  cost per setup=Machine setups cost/Number of setups

Machine setups cost=$180,000

Number of setups=300

machine setup  cost per setup=$180,000/300

machine setup  cost per setup=$600

Total set up cost for product Y=60*$600=$36000

Total set up cost for product Y as %=$36,000/$180,000=20%

Total set up cost for product Z=240*$600=$144,000

Total set up cost for product Z as %=$144,000/$180,000=80%

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The missing coordinate can either be - 16 or 8.

Let the missing coordinate be x.

Now, we know that the distance between (-3, -4) and (6, x) is 15.

Using the distance formula, we get that:

Distance² = (x₂ - x₁)² + (y₂ - y₁)²

Substituting the values in the formula, we get that:

15² = (6 + 3)² + ( x + 4)²

225 = 9² + x² + 16 + 8 x

225 = 81 +x² + 16 + 8 x

225 = x² + 8 x + 97

x² + 8 x - 128 = 0

x² + 16 x - 8 x -128 = 0

x ( x + 16) - 8 ( x + 16) = 0

(x + 16)(x - 8) = 0

x = -16 or x = 8.

Therefore, the missing coordinate can either be - 16 or 8.

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To solve an linear equation we need to use BODMAS rule.

Here the given equation is;

(x+8-x+8)

We know very well that if two like numbers have opposite sign and are added then it gets cancelled and gives zero as the result.

Similarly, here x and -x gets cancelled and we get 16 as the result.

If we get the solution of an equation as zero then we may say that the equation has no real solution. That means there are no values of the unknown which will complete the equation.

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Answer: Sue fills 32/3 (Decimal form = 10.6667 containers)

Step-by-step explanation: 8 divided by 3/4 equals 32/3. If you need it in decimal form it's 10.6667

Please heart this or rate it :)

Answer:

10 2/3 containers BUT can only fully fill 10 containers

Step-by-step explanation:

to solve this equation you need to divide 8 by 3/4

8 / 3/4

that is

8/1 / 3/4

when dividing fractions you must flip the second number and multiply both numbers together

8/1 * 4/3

32/3 is your answer

or

10 2/3

she can fully fill 10 containers

If the point N lying on the Line segment MP, divides MP such that the ratio of MN to NP is 6 to 1, and the coordinates of M(-13, 20) and P(1-1), then the coordinates of "N" is

As per the question statement, N lying on the Line segment MP, divides MP such that the ratio of MN to NP is 6 to 1.

We are required to find out the coordinates of "N".

To solve this question, we need to know the formula to calculate the coordinates of a point (Say "c") that divides a line segment AB in the ratio of (m:n).

The formula goes as:

Abscissa of c [tex](x_{3})=\frac{mx_{2}-nx_{1} }{m-n}[/tex]

and, Ordinate of c [tex](y_{3})=\frac{my_{2}-ny_{1} }{m-n}[/tex]

where, [tex](x_{1}, y_{1})[/tex] are the coordinates of point A, while

[tex](x_{2}, y_{2})[/tex] are the coordinates of point B.

Using our given data in the above formulae, we get

Abscissa of N =  [tex]\frac{(6*1)-[1*(-13)]}{6-1} =\frac{6-(-13)}{5}=\frac{6+13}{5}=\frac{19}{5}[/tex]

And, Ordinate of N = [tex]\frac{[6*(-1)-(1*20)}{6-1} =\frac{(-6)-20}{5}=\frac{-(20+6)}{5}=\frac{-26}{5}[/tex].

Hence, our concerned point N = [tex](\frac{19}{5}, \frac{-26}{5})\\[/tex].

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Answer:

[tex]=4620000x[/tex]

Step-by-step explanation:

[tex]=1000000\cdot \:4.62x[/tex]
[tex]=4620000x[/tex]

Answer:

4620000

Step-by-step explanation:

4.62x10^6

1000000x4.62