Five people received the following scores on a personality test: 8,12,6,9 and 15. calculate the mode,median,mean and range of this distribution of scores.
The set of scores has the following:
Mean = 10Median = 6Mode = No modeRange = 7Arrange the scores in ascending order
6,8,9,12,15
No. of observation = 5 (odd)
1) Mean:[tex]Mean = \frac{Sum of observations}{No. of observations}[/tex]
[tex]Mean=\frac{6+8+9+12+15}{5}[/tex]
∴ Mean = 10
2) Median:Since the no. of observations is odd, thus the median will be:
[tex]Median= \frac{(n+1)}{2}[/tex]
[tex]Median = \frac{5+1}{2 }[/tex]
∴ Median = 6
3) Mode:For sets 6,8,9,12,15, there is no mode available because no value in the set appears more than once.
Hence, this set of values has no mode.
4)Range:Range = Highest value - Lowest value
Range = 15 - 8
∴ Range = 7
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When auscultating a client's chest, the nurse hears swishing sounds of normal breathing. how would the nurse document this finding?
When auscultating a client's chest, the nurse hears swishing sounds of normal breathing the would the nurse document this finding as adventitious sounds.
Chest auscultation involves employing a medical instrument to concentrate to a patient's system and deciphering the lungs sounds detected. it's a basic element of physical examination that may assist within the designation of metabolic process problems and identification of adventitious sounds.
Holding it between the index and finger of your dominant hand, place the chest piece of the stethoscope flat on the patient's chest exploitation mild pressure. Using a 'stepladder' approach hear breath sounds on the anterior chest.
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