The points Q (7, 6), R(-1,5), S(-5, -2), and T(3, -1) form a quadrilateral.
Find the desired slopes and lengths, then fill in the words that BEST identifies the type of quadrilateral.

Answer:

The value 0.031 represents the interest rat, which means the annual compounded interest rate is 3.1%

First option

Step-by-step explanation:

The general equation for amount accrued A with a principal P at an annual compound interest rate of i%(r/100 in decimal) compounded n times a year for t years is given by

[tex]A = P\left(1 + \dfrac{r}{n}\right)^{nt}[/tex]

Here r = i/100 which is a decimal

Looking at the specific equation
[tex]A = 2400\left(1 + \dfrac{0.031}{4}\right)^{4t}[/tex]

we can see that P = 2440, the initial investment

0.031 is the annual interest rate in decimal

Expressed as percentage that would be 0.031 x 100 = 3.1% per year

So the correct answer is the first option which states
The value 0.031 represents the interest rat, which means the annual compounded interest rate is 3.1%

There are 1365 different ways to pick a president, treasurer, and secretary from a club of fifteen people.

The number of ways to pick a president, treasurer, and secretary from a club of fifteen people can be calculated using the formula for combinations:

[tex]C(n,r) = n! / (r! (n-r)!)[/tex]

Where n is the number of people in the club and r is the number of positions to be filled.

In this case, we want to calculate the number of ways to choose 3 people from a group of 15, so n = 15 and r = 3.

Plugging these numbers into the formula, we get:

[tex]C(15,3) = 15! / (3! (15-3)!) = 15! / (3! 12!) = 15*14*13 / (3*2*1) = 1365[/tex]

Therefore, there are 1365 different ways to pick a president, treasurer, and secretary from a club of fifteen people.

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The value of H is 20 in the proportion 4 over H equals 5 over 25.

A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0.

A proportion is an equation in which two ratios are set equal to each other

4 over H equals 5 over 25

4/H=5/25

Apply cross multiplication

4×25=5H

100=5H

Divide both sides by 5

20=H

Hence, the value of H is 20 in the proportion 4 over H equals 5 over 25.

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Both of the solutions differ in their constant integration.

A. ∫6x³(x⁴+1)dx

if we apply the distributive property:

∫6x³(x⁴+1)dx = ∫(6x⁷+ 6x³)dx = (6/8)x⁸ + (6/4)x⁴ + C = (3/4)x⁸ + (3/2)x⁴ + C

A. ∫6x³(x⁴+1)dx

If we use the substitution

w = x⁴+1

⇒ dw = 4x³dx  ⇒  x³dx = (1/4)dw

we have

∫6x³(x⁴+1)dx = 6∫w*(1/4)dw = (6/4)∫w dw = (3/2) (w²/2) + C = (3/4)w² + C

returning the change we get

∫6x³(x⁴+1)dx = (3/4)(x⁴+1)² + C

For these answers, we can apply Notable Identities as follows

(x⁴+1)² = (x⁴)² + 2*x⁴*(1) + (1)² = x⁸ + 2x⁴ + 1

then

(3/4)(x⁴+1)² + C₂ = (3/4)(x⁸ + 2x⁴ + 1) + C = (3/4)*x⁸ + (3/2)*x⁴ + (3/4) + C

We can assume (3/4) + C as a constant, then

∫6x³(x⁴+1)dx = (3/4)*x⁸ + (3/2)*x⁴ + C

Both of the solutions differ in their constant integration.

Both solutions are primitive of the same function, which must only fulfill a condition that is to differentiate into a constant, and in this case, they fulfill it.

It is not usual that using different methods of integration obtain different primitives, but it is not uncommon, there are quite a few known cases in which this happens and absolutely nothing happens.

It is normal. Two functions that differ in a constant have the same derivative and therefore, both functions are primitive of that same derivative.

C is often forgotten as a result.

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Answer:

Step-by-step explanation:

100 %.

a) The general solution is: I(t) = (E0/R) * (1 - exp(-Rt/L)) * u(t)

b) The general solution is: I(t) = (E0/R) * (1 - exp(-Rt/L)) * 8(t)

c) The general solution is: I(t) = (E0/sqrt(R^2 + (Lw)^2)) * (sin wt + (R/Lw) * cos wt) * exp(-Rt/L)

a) When E(t) = E0u(t) (where u(t) is the unit step function), the solution to the differential equation L *(dI/dt) +RI = E0u(t) can be found using the method of partial fraction expansion.

The general solution is:

I(t) = (E0/R) * (1 - exp(-Rt/L)) * u(t)

b) When E(t) = E0 8(t) (where 8(t) is the impulse function), the solution to the differential equation L *(dI/dt) +RI = E0 8(t) can be found using Laplace transforms.

The general solution is:

I(t) = (E0/R) * (1 - exp(-Rt/L)) * 8(t)

c) When E(t) = E0 sin wt, the solution to the differential equation L *(dI/dt) +RI = E0 sin wt can be found using Laplace transforms or by solving the characteristic equation.

The general solution is:

I(t) = (E0/sqrt(R^2 + (Lw)^2)) * (sin wt + (R/Lw) * cos wt) * exp(-Rt/L

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19. We can see here the wrong statement is:

B. The market demand (supply) curve is flatter than the individual demand (supply) monopoly market.

20. D. All of the above reveals basic economic question that every economy should try to resolve.

21. The statement that commits a post-hoc fallacy is: B. It is because of president bush's visit to Germany that the Ethiopian agriculture is backward.

22.  From the PPF the law of increasing opportunity cost is implied by

A. The negative slope of the curve

A logical fallacy known as post hoc occurs when one occurrence is assumed to be the reason for a subsequent event just because it happened earlier (also known as post hoc, ergo propter hoc).

We see here that the given answers above are actually correct.

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Random assignment minimizes bias between experimental and control groups because it ensures that each group has an equal chance of receiving any given treatment.

Random sampling minimizes bias between a sample and a population because it ensures that each member of the population has an equal chance of being included in the sample.

Random assignment and random sampling are both used to minimize bias between different groups and populations, ensuring that each group or member has an equal chance of receiving any given treatment or being included in a sample.

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El grafico de la ecuación cuadratica se puede ver en la imagen del final.

Digamos por ejemplo que queremos completar la tabla de abajo:

x: -1, 0, 1, 2

y:

Para ello, debemos evaluar la ecuación cuadratica que nos dieron en esos valores de x.

si x= -1

y = 2*(-1)²+3 = 5

si x = 0

y = 2*(0)²+3 = 3

si x = 1

y = 2*(1)²+3 = 5

si x = 2

y = 2*(2)²+3 = 11

Entonces the table is:

x: -1, 0, 1, 2

y:  5, 3, 5, 11

Para graficar esto, simplemente grafica todos los puntos que conocemos y debemos conectarlos con una curva, el grafico está abajo.

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Option C is correct, the graph shows a dashed line, which passes through a point negative 2 comma 0 and a point 0 comma negative 2, with shading above the line.

a relationship between two expressions or values that are not equal to each other is called 'inequality.

The given inequality is −3x − 3y < 6

Minus three times  of x minus three times of y less than six.

Now let us solve for y

-3y<6+3x

Divide both sides by 3

-y<2+x

y>-x-2

The graph of the inequality is given in the attachment.

When we observe the graph the line is dashed line, which passes through a point negative 2 comma 0 and a point 0 comma negative 2, with shading above the line.

Hence, Option C is correct, the graph shows a dashed line, which passes through a point negative 2 comma 0 and a point 0 comma negative 2, with shading above the line.

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2. After the movie.

3. Because they left the dogs out.

1. I missed the game.

4. They left the dogs out.

5. Employees leave frequently at the casino.

An independent clause is a combination or combination of words in which there is a subject, a verb, and has a complete and understandable meaning or meaning. In other words, an independent clause is a clause that can stand alone.

There are special features in an independent clause that we must know. The characteristics of an independent clause are as follows:

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The function notation for A would be A(x) = y

From the question, we have the following parameters that can be used in our computation:

This means that

The function can be expressed as

y = A(x)

This implies that:

The function A relates x and y

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Complete question

A is a relationship between two variables x and y such that every input x produce exact one output y​. What is the function notation of A

The inverse matrix is (b) [tex]\left[\begin{array}{ccc}-19&9&-7\\15&-7&6\\-2&1&-1\end{array}\right][/tex]

From the question, we have the following parameters that can be used in our computation:

x + 2y + 5z = 14

3x + 5y + 9z = -1

x + y - 2z = 6

When represented as a matrix, we have

[tex]\left[\begin{array}{ccc}1&2&5\\3&5&9\\1&1&-2\end{array}\right][/tex]

The determinant is calculated as

D = 1 * (5 * -2 - 9 * 1) - 2 * (3 * -2 - 9 * 1) + 5 * (3 * 1 - 5 * 1)

Evaluate

D = 1

This means that the matrix is invertible

Next, we calculate the cofactor elements

5 * -2 - 9 * 1 = -19

3 * -2 - 9 * 1 = -15

3 * 1 - 5 * 1 = -2

2 * -2 - 5 * 1 = -9

1 * -2 - 5 * 1 = -7

1 * 1 - 2 * 1 = -1

2 * 9 - 5 * 5 = -7

1 * 9 - 5 * 3 = -6

1 * 5 - 2 * 3 = -1

So, we have

   [tex]\left[\begin{array}{ccc}-19&-15&-2\\-9&-7&-1\\-7&-6&-1\end{array}\right][/tex]

Next, create the adjoint or the adjugated matrix

[tex]A = \left[\begin{array}{ccc}-19&15&-2\\9&-7&1\\-7&6&-1\end{array}\right][/tex]

Transpose the adjoint

[tex]A^T = \left[\begin{array}{ccc}-19&9&-7\\15&-7&6\\-2&1&-1\end{array}\right][/tex]

Divide by the determinant

[tex]A^T = \left[\begin{array}{ccc}-19&9&-7\\15&-7&6\\-2&1&-1\end{array}\right][/tex]

Hence, the inverse is (b) [tex]\left[\begin{array}{ccc}-19&9&-7\\15&-7&6\\-2&1&-1\end{array}\right][/tex]

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The number of 20-sided die in 80 is 33

From the question, we have the following parameters that can be used in our computation:

The table of values

On the table, we have

20-sided = 5

Total = 12

So, we have

P(20-sided) = 5/12

For 80 dice, we have

Expected value = 5/12 * 80

Expected value = 33

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The expression for total cost per month is 30(100000+2000f).

Standard deviation is the positive square root of the variance. Standard deviation is one of the basic methods of statistical analysis. Standard deviation is commonly abbreviated as SD and denoted by 'σ’ and it tells about the value that how much it has deviated from the mean value.

The standard deviation formula is σ = √∑(xi-μ)²/N

A) The expression for total cost per month

Let the number of flites be f.

Total cost = 30(100000+2000f)

B) The expression for total revenue per month

Rise airlines has the current capacity to fly a mean of 15 flites a day with a standard deviation of 12.

So, total revenue per month

= 30(100000+2000×15)

= $3,900,000

C) Here, σ=12, μ=15, N=60

σ = √∑(xi-μ)²/N

12= √∑(xi-15)²/60

144=(xi-15)²/60

8640=(xi-15)²

xi-15=92.95

xi=108

Therefore, the expression for total cost per month is 30(100000+2000f).

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Answer:

0.32

Step-by-step explanation:

The correct statement is: She should calculate the ratio between the number of calories she burned versus the number of miles she ran.

The quantitative relation between two amounts shows the number of times one value contains or is contained within the other. for example-"the ratio of computers to students is now 2 to 1"

Given here: The table containing data calories vs miles run.

You can tell if a table shows a proportional relationship by calculating the ratio of each pair of values. If those ratios are all the same, the table shows a proportional relationship.

Thus calculating the ratio for each pair of entries we get

1) ratio=118/1.2

      =295:3a  or unit rate 98.33 calories per mile

2) 190/2= 95:1 or unit rate 95 calories per mile

3) 226/2.4=565:6 or unit rate94.1

clea,rly the ratios are different.

Hence, The table containing the data doesn't form a proportional relationship.

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the branch of statistics for the scenario given regarding 10,000 Students is Descriptive Statistics.

In a study, descriptive statistics are used to describe the fundamental characteristics of the data. They provide brief summaries regarding the measures and samples. They serve as the foundation for virtually every quantitative data analysis, along with straightforward graphics analysis.

In most cases, descriptive statistics are different from inferential statistics. When you use descriptive statistics, you simply describe what the data show or are. With inferential statistics, you are attempting to draw inferences from data that go beyond the immediate facts. For instance, we attempt to infer what the general population might think from the sample data using inferential statistics.

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Answer:A and V

correct me if I’m wrong

Or give me more information about the question

The rule of functions to solve for C(N(h)) is composition of functions. The cost when h = 8 hours is $3680.

To solve C(N(h)), the rule used is composition of functions, where the output of one function N(h) is used as the input to another function C(x).

First, evaluate C(x) to get its output and then plug that output into N(h) to get the final output.

Given the two functions, the cost in dollars to produce x shovels, C(x) = 12x + 450, and the number of shovels that can be produced in h hours, N(h) = 40h, we can find the cost when h hours of production time is used by finding C(N(h)).

To find C(N(h)), we first find N(h) to get the number of shovels produced in h hours and then plug that into C(x) to find the cost:

C(N(h)) = C(40h) = 12(40h) + 450 = 480h + 450

So, the rule for C(N(h)) is C(N(h)) = 480h + 450.

When h = 8 hours, the cost to produce shovels is given by C(N(8)) = 480(8) + 450 = 3680 dollars.

Therefore, it will cost $3680 to produce shovels in 8 hours.

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Parametric equations for the tangent line to the curve with the given parametric equations at the specified point are

x=s

y=1-4s

z=0

Derivatives of a function in parametric form: There are instances when rather than defining a function explicitly or implicitly we define it using a third variable. This representation is when a function y(x)  is represented via a third variable which is known as the parameter is a parametric form. A relation between x and y can be expressible in the form x = f(t) and y = g(t) is a parametric form representation with parameter as t

In mathematics, a parametric equation defines a group of quantities as functions of one or more independent variables called parameters.

At the point (0, 1,0) t = 0

Find the tangent vector:

[tex]\frac{dx}{dt}=1=x_t\\y_t=\frac{dy}{dt}=-4e^{-4t}\\\\Z_t=5-5t^4[/tex]

The tangent vector for all points  is

[tex]v(t)=i-4e^{-4t}j+(5-5t^4)k\\\\v(0)=i-4j[/tex]

The vector equation of the tangent line is

(x,y,z0=(0,1,0)+s(i-4j)

The parametric equation for this line is

x=s

y=1-4s

z=0

The complete question is -

Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. x = t, y = e−4t, z = 5t − t5; (0, 1, 0) x(t), y(t), z(t) = t,1−4t,5t Illustrate by graphing both the curve and the tangent line on a common screen.

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Emmet ran 1/8 mile further than he walked.

A fraction is written in the form of p/q, where q ≠ 0.

Fractions are of two types they are proper fractions in which the numerator is smaller than the denominator and improper fractions where the numerator is greater than the denominator.

Given, Emmet ran 3/8 of a mile and walked 1/4 of a mile.

Therefore, The number of more miles he run than he walked can be obtained by subtracting the number of miles he walked from the number of miles he ran which is,

= (3/8 - 1/4) miles.

= (3 - 2)/8.

= 1/8 miles.

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The rule is a linear equation:

y = 2x + 1

We want to write an expression that represents the following rule, it is:

"double the input, then add 1"

The input is represented by the variable x, so if we double it and then we add 1, the rule will be:

y = 2x + 1

So we have a linear equation.

And, using the notation on the image, we can write this as:

x → 2x + 1 → y

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The solution is, 0.75 can be written as fraction = 3/4.

A fraction represents a part of a whole or, more generally, any number of equal parts. When spoken in everyday English, a fraction describes how many parts of a certain size there are, for example, one-half, eight-fifths, three-quarters.

here, we have,

A terminating decimal, such as 0.75, has an exact number of nonzero digits.

so, it can be written as fraction

0.75

=75/100

=3/4

Hence, The solution is, 0.75 can be written as fraction = 3/4.

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The rule for function g is:

g(x) =   (x + 2)⁴ + 1

And this is a translation of 2 units to the left of f(x).

Here we know that the function f(x) is:

f(x) = x⁴ + 1.

And function g is written as:

g(x) = f(x + 2)

Replacing f(x) we will get:

g(x) =  (x + 2)⁴ + 1

That is the rule for g(x).

Now let's identify the transformation.

We know that a horizontal shift of N units is written as:

g(x) =f(x + N)

if N > 0 the shift is to the left.

if N < 0 the shift is to the right.

Here we have:

g(x)=f(x+2)

So this is a shift of 2 units to the left.

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The area of the composite figure is equal to 71.07 in² square yards.

The composite figure is made up of a trapezium and a quarter of a circle, so we shall calculate for the areas of the two figures and then add the result to get the total area of the composite figure as follows:

area of the trapezium = [(6 + 10)/2] yd × 8 yd

area of the trapezium = (16/2) yd × 8 yd

area of the trapezium = 8 yd × 8 yd

area of the trapezium = 64 yd²

area of circle = πr²

area of circle = 22/7 × 3 × 3

area of circle = 198/7

a quarter area of the circle = 198/7 ÷ 4

a quarter area of the circle = 7.07 square yard

total area of the composite figure = 64 yd² + 7.07 yd²

total area of the composite figure = 71.07 yd²

Therefore, the area of the composite figure is equal to 71.07 yd² square yard.

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You and three friends buy a pizza with 8 slices to share. Each friend gets 2 slices each because 1 divided by 1/4 is 25% and 25% of that pizza is 2 slices

Answer:

-3/5

Step-by-step explanation:

I attached a photo so you can see my work

First, we can simplify the left side of the equation:

-3(x + 2) = -3x - 6

Now, we can substitute this expression into the equation:

-3x - 6 = 5y

Next, we can isolate the y variable on one side of the equation by dividing both sides by 5:

-3x/5 - 6/5 = y

Finally, to find the value of y when x = -1, we substitute -1 for x in the expression:

-3(-1)/5 - 6/5 = y

-3/5 - 6/5 = y

-9/5 = y

So, when x = -1, y = -9/5.

Using dynamic programming, a recurrence relation can be used to compute the minimum edit distance between two strings.

The following are the base case(s) for computing EDIT-DIST(A, B):

If either string A or string B is empty, the cost of transforming string A to string B is the other string's length. For example, if A = "" and B = "ALGORITHM," then EDIT-DIST(A, B) = 8, because A to B requires 8 insertions.

The following is the recurrence relation for computing EDIT-DIST(A, B):

Let L(i, j) denote the shortest edit distance between string A's first I characters and string B's first j characters. Then,

L(i, j) = min { L(i - 1, j) + cd, L(i, j - 1) + ci, L(i - 1, j - 1) + cs(if Ai != Bj) }

where:

L(i - 1, j) + cd is the cost of deleting the last character of A,

L(i, j - 1) + ci is the cost of inserting a character in A to match the last character of B,

L(i - 1, j - 1) + cs is the cost of substituting the last character of A with the last character of B.

The above recurrence relation can be used to compute the minimum edit distance between two strings using dynamic programming.

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