If you travel 100km west and then 500km west, what is the total displacement

Answers

Answer 1

Answer: 600 km west

Explanation:

When looking at total distance/displacement, simply add the two given quantities together. Note- in the future, make sure to pay attention to units and directions of components. For example, if it was 100 km east and then 500 km west, your total would be -100 km west + 500 km west, giving you 400 km west.


Related Questions

Why are there flat spots on
heating curves of substances like
water?

Answers

The melting and boiling processes are represented by the flat sections. It is knows that temperatures don’t change during the melting and boiling stages until the phase transitions are finished. As a result, the relevant portions on the heating curve are flat.

Calculate the wavelength of a photon (in nm) emitted when an electron transitions from the n = 3 state to the n = 1 state in the hydrogen atom.

Answers

The wavelength of a photon (in nm) emitted when an electron transitions from the n = 3 state to the n = 1 state in the hydrogen atom is 103 nm

What is a Wavelength ?

A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places (adjacent crests) in the consecutive cycles.

There are two energy levels, n1 and n2.

Beginning with Rydberg's equation, write:

The Rydberg is useful for figuring out the wavelength of light emitted when an electron switches from one energy level of an atom to another, for as from higher to lower or lower to higher. When an electron moves from one orbital to another, the energy will change.

1/λ = R(1/n1^2 - 1/n2^2)

1/λ = 1.097 x 10^7 (1/1^2 - 1/3^2)

1/λ = 1.097 x 10^7(8/9)

1/λ = 9/8.776 x 10^7 = 103 x 10^-9 m = 103 nm

Hence, the wavelength of a photon is 103 nm

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Roughly how many times farther is it from the sun to alpha centauri than from the sun to jupiter?

Answers

From the sun to Alpha Centauri than from the sun to Jupiter it is 105 times further. The age of Alpha Centauri is 5.3 billion years older. It also moves in a totally different way. Even though it is close by, it is only passing.

What if Alpha Centauri replaced the position of the Sun?

Alpha Centauri A is around 100,000 miles farther away, 10% more massive, and a little bigger than our Sun. All of the planets' orbits will become more elliptical as a result of the increased mass. The reality that Alpha Centauri A is 50% brighter than our star, placing Earth slightly inside the habitable zone, is much worse for the Earth. Most of Earth's surface is currently uninhabitable due to its average surface temperature of 43 degrees Celsius, according to Universe Sandbox 2. It has been clearly stated to us, though, that a temperature so high would most likely lead to an uncontrollable greenhouse effect by increasing the amount of water vapor in the atmosphere.

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Sound travels faster in air if the air temperature is group of answer choices warm. average. cold.

Answers

Sound travels faster in the air if the air temperature is warm

Everything comes down to the chemical composition of air and sound. Sound molecules travel faster through the air particles in warm air. So, at an air temp of 70°F at sea level, the scientific estimation of the sound speed is 767 mph. Sound, on the other hand, travels the fastest in warmer temperatures air. It moves at 740 miles per hour in subzero temperatures.

Although sound travels slower in cooler air temperatures, it can travel further. The waves are refracted from wallets of warm air and returned to the ground as a result. This sound wave then oscillates between cold and warm air and the surface, causing it to travel further.

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After you perform gel electrophoresis on your pcr product, you see that one sample has a 200 bp band and the other does not. what can you conclude from these results?

Answers

After performing gel electrophoresis on the pcr product, you see that one sample has a 200 bp band and the other does not this shows that 200 bp band is significantly larger than the size of primer dimers unless the primers are 100 bp long, they are not visible.

Gel electrophoresis is the process used to evaluate the success of the PCR reaction.A closer examination of the suitability of agarose gel electrophoresis is done for assessing PCR product yield.

PCR is a series of chemical reactions that take place outside a living cell

Use of 2% agarose gel and 100bp marker and spreading the marker strips properly with 80-90V is done to avoid heating.

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a bag is dropped from a hovering helicopter. the bag has fallen for 1.6 s. what is the bag's velocity?

Answers

The bag's velocity when a bag is dropped from a hovering helicopter is 15.68m/s

Its initial velocity is zero. In a free-falling body, the value of the final velocity is obtained through the equation

                                           Vf =u + gt

u = o ( because the bag is dropped, so it falls starting from rest)

Vf = gt

u is initial velocity

Vf is final velocity

t is time

where g is the acceleration due to gravity, 9.8 m/s².

using above values we get

 Vf = (9.8 m/s²)(1.6s)

= 15.68m/s

The bag's velocity when a bag is dropped from a hovering helicopter is 15.68m/s

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Two solid metal balls all have the same radius. one is made of aluminum, the other of gold. if the balls are resting at the bottom of a pool of water, which ball has the largest buoyant force?

Answers

The buoyancy force on the gold ball will be more than that of aluminum.

What is buoyancy force?

An upward force applied by a fluid against the weight of an item that is partially or totally submerged is known as upthrust, also known as buoyancy. Pressure in a fluid column increases with depth due to the weight of the fluid on top.

Given that two solid metal balls all have the same radius. one is made of aluminum, the other of gold. And the balls are resting at the bottom of a pool of water.

The buoyancy force at the bottom force will be calculated by finding the density of the balls.

Buoyancy force = Volume inside water x Density X g

Density of gold = 19.3 g / cc

Density of aluminium = 2.7 g / cc

Since the density of the gold ball is more than the density of the aluminum ball.

Therefore, the buoyancy force on the gold ball will be more than that of aluminum.

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6. Read the following statements. If the italicized word is used correctly,
answer "correct." If the italicized word is not used correctly, rewrite the
statement with the correct word.
a. Taylor's weight is 65 kilograms.
b. I went on a diet and my mass decreased.
c.
I went to the Moon and I lost mass, even though I didn't lose any of
my matter.

Answers

The following statements have italicized word, and has 2 correct  statement and 1 incorrect statement.

a. Taylor's weight is 65 kilograms. : Its correct.

b. I went on a diet and my mass decreased. : Its correct.

c. I went to the Moon and I lost mass, even though I didn't lose any of my matter. : Its incorrect.

What is weight?

The weight is a term shows the mass of the object and the gravity working on it. Example is that a person who feel heavy in earth that same person feel very light on moon cause the gravity will work on that object verry small in comparison to earth.

How can we say that the third statement is incorrect?

a. Taylor's weight is 65 kilograms. It is a complete sentence. So its a correct statement.

b. I went on a diet and my mass decreased. : Its correct. Its also a complete sentence. So its a correct statement.

But, c. I went to the Moon and I lost mass, even though I didn't lose any of my matter. This sentence is incorrect because the mass of the person remains same in the moon but the gravity become lesser in the moon so he felt lighter.

So, according to the theory the statement is incorrect.

The correct statement would be:

c. I went to the Moon and I lost weight, even though I didn't lose any of my matter.

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How far does an object go after the pushing force is removed till it stops. the object's speed is 1.70 m/s when the pushing force is removed. friction is 52.0 n and mass of object is 80.0kg

Answers

By using uniform motion, the object will travel 2.22 meters until it stops.

We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.

From the question above, we know that

vo = 1.70 m/s

F = -52 N

m = 80 kg

vt = 0 m/s

Find the deceleration

F = m . a

-52 = 80 . a

a = -0.65 m/s²

Find the distance using the second equation

vt² = vo² + 2a . s

0² = 1.7² + 2(-0.65) . s

1.3s = 2.89

s = 2.22 meters

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Flag what horizontally applied force will accelerate a 400 kg crate at 1m/s2 across a factory floor against a friction force half its weight?

Answers

A horizontally applied force of 2400 N will accelerate a 400 kg crate at 1 m/s^2.

In the given diagram, the free body diagram (FBD) of a block is shown.

Here the two vertical forces, normal reaction(N) and weight(W) cancel each other while the horizontal forces do not cancel each other and provide acceleration to the block.

According to the given situation,

Applied Force - Frictional Force = ma

Here the frictional force is half the weight of the body 2000 N.

Putting the given values in the above equation,

F - F1 = 400 x 1

F - 2000 = 400

F = 2400 N

Hence, a horizontally applied force of 2400 N will accelerate a 400 kg crate at 1 m/s^2.

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Which of the points a(9, 0, 1), b(9, 7, 3), and c(1, 8, 6) is closest to the yz-plane? which point lies in the xz-plane?

Answers

The distance of a point to the yz-plane is given by the absolute value of the x coordinate. So, for point A, the distance is equal to,

Dyz = | -4 | = 4 units

Next, for point B, the distance is equal to,

Dyz = | 3 | = 3 units

Lastly, for point C, the distance is equal to,

Dyz = | 2 | = 2 units

Since point C has the smallest distance to the yz -plane, this point is closest to the yz-plane.

Unlike the regular 2-dimensional Cartesian coordinate system, a three-dimensional coordinate system contains three axes. To plot points in this coordinate system, the point's ordered triple must be known, (x,y,z,).Each coordinate on the ordered triple represents a point that lies on one of the axes

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Apartment traveling on a straight road at 15.0m/s accelerate uniformly to a speed of 21.0m/s in 12.0 seconds the total distance traveled by the car in this 12.0 seconds time interval is

Answers

By using uniform motion, the distance traveled by the car is 216 m.

We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.

From the question above, we know that

vo = 15 m/s

vt = 21 m/s

t = 12 s

Find the acceleration

vt = vo + a . t

21 = 15 + a . 12

12a = 6

a = 0.5 m/s²

By using the third equation, we can calculate the distance

s = vo . t + 1/2 . a . t²

s = 15 . 12 + 1/2 . 0.5 . 12²

s = 180 + 36

s = 216 m

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what is nuclear emission?

Answers

Energy given off by matter in the form of tiny fast-moving particles (alpha particles, beta particles, and neutrons) or pulsating electromagnetic rays or waves

A car is traveling at a speed of 33 m/s . (a) what is its speed in kilometers per hour? (b) is it exceeding the 90 km/h speed limit?

Answers

According to the statement:

a) speed is equal to 118 km/h in kilometres per hour.

b) yes it is exceeding 90km/h.

What does speed mean?

The pace at which an object's position changes in any direction is referred to as speed. Speed is defined as the ratio of something like the distance traversed to the time required to cover that distance. . . Speed is a scalar quantity since it just has a direction and no magnitude..

How are the speeds determined?

Speed is determined by dividing the distance by the time. Calculating the units for speed requires knowledge of the units for both time and distance.. The units in this example will be meters per second (m/s), since the distance is measured in meters (m) and the time is measured in seconds (s).

(a)s₂= 118.km/h is its speed in kilometres per hour.

1h = 3600s

1km = 1000m

s₂= (33m/s) *[tex]\left(\frac{60 \times 60}{1000}\right)[/tex]

= 118.8km/h

s₂= 118.km/h

(b) yes it is exceeding 90km/h.

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using a(n) researchers can examine the brain's magnetic fields, which help researchers understand how certain tasks influence brain activity based on the speed and strength of the magnetic field.

Answers

Magnetoencephalography (MEG) allows researchers to examine the brain's magnetic field. Which helped researchers to understand how certain tasks influence brain activity.

It isn't. Invaluable tool to study the large scale brain activity. And interactions with the body.

MEG was developed in 1960s .

In this technique weak magnetic forces associated with electrical activities of brain are monitored .

It collects activity from neurons visualized as brain waves and it is used with MRI in magnetic source imaging.

Med fields passes through the head without any distortion.

It provides a Spatial and temporal resolution.

Magnetoencephalography (MEG) allows researchers to examine the brain's magnetic field.

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At what temperature will 1.30 mole of an ideal gas in a 1.30 l container exert a pressure of 1.05 atm?

Answers

The temperature of the ideal gas is 12.76 K.

We need to know about the ideal gas theory to solve this problem. The ideal gas is assumed that there is no interaction between particles in a gas. It can be determined by the equation

P . V = n . R . T

where P is pressure, V is volume, n is the number of moles gas, R is the ideal gas constant (8.31 J/mol.K) and T is temperature.

From the question above, we know that

n = 1.3 mol

V = 1.30 l = 1.3 x 10¯³ m³

P = 1.05 atm = 1.05 x 1.01 x 10⁵ Pa = 106050 Pa

By substituting the following parameters, we can calculate the temperature

P . V = n . R . T

106050 . 1.3 x 10¯³ = 1.3 . 8.31 . T

T = 137.865 / 10.803

T = 12.76 K

Hence, the temperature of the gas is 12.76 K.

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When 5.0 a at 110 v flows in the primary of an ideal transformer, how many amps at 24 v can flow in the secondary?

Answers

The current that can flow in the secondary is 23 A

According to Transformation ratio,

[tex]V_{p}[/tex] / [tex]V_{s}[/tex] = [tex]I_{s}[/tex] / [tex]I_{p}[/tex]

where,

[tex]V_{p}[/tex] = Voltage across the primary coil

[tex]V_{s}[/tex] = Voltage across the secondary coil

[tex]I_{s}[/tex] = Current in the primary coil

[tex]I_{p}[/tex] = Current in the secondary coil

Given that,

[tex]V_{p}[/tex] = 110 V

[tex]V_{s}[/tex] = 24 V

[tex]I_{p}[/tex] = 5 A

[tex]V_{p}[/tex] / [tex]V_{s}[/tex] = [tex]I_{s}[/tex] / [tex]I_{p}[/tex]

110 / 24 = [tex]I_{s}[/tex] / 5

[tex]I_{s}[/tex] = 22.9 = 23 A

Transformation ratio is the ratio of secondary voltage to primary voltage.

Therefore,  The current that can flow in the secondary is 23 A

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At which lettered point or points is the object moving to the left, if the positive x-direction corresponds to its rightward movement?

Answers

At F the object moving to the left, if the positive x-direction corresponds to its rightward movement.

Δx = [tex]X _{2}[/tex] - [tex]X_{1}[/tex]

where,

Δx = Change in position

[tex]X _{2}[/tex] = Final position

[tex]X_{1}[/tex] = Initial position

If Δx is positive, the object is moving forwards ( Right ).

If Δx is negative, the object is moving backwards ( Left ).

If the curve is moving from top to bottom Δx will be negative and if the curve is moving from bottom to top Δx will be positive.

So, in this given curve, at the points B, C and D, the curve is moving from bottom to top meaning that the object is moving to the right and at the point F, the curve is moving from top to bottom meaning that the object is moving to the left.

Therefore, At F the object moving to the left, if the positive x-direction corresponds to its rightward movement.

The given question contains no distance - time graph. I considered the attached image as the graph.

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Which persuasive writing strategy involves quoting a consumer, who is satisfied with a specific product or service, in a news release?

Answers

In a news release, using a consumer who is happy with a particular good or service as a testimonial might be persuasive.

What do you understand by consumer?

Consumers are described as people or organizations who utilize or consume goods and services. Customers might be consumers or exist solely as customers; they are the buyers of products and services inside the economy.

Businesses may select how to promote their goods and services most effectively by comprehending how consumers think, feel, and make decisions. This aids in predicting consumer behavior and helps marketers promote their already-available goods and services.

Consumer behavior is the study of how consumers choose things based on their needs, wants, and desires as well as how they purchase and utilize them.

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A student adds two displacement vectors with magnitudes of 6.0 m and 8.0 m,

Answers

The correct answer is  (E)  It could have any value between 2.0 km and 14.0 km depending on how the vectors are oriented.

The magnitude of the resultant displacement could have any value between 2.0 km and 14.0 km depending on how the vectors are oriented.

How is resultant displacement calculated?

In physics, displacement (which is a vector quantity) refers to a change in an object's position. When you compute displacement, you compare an object's original and final locations to determine how "out of place" it is. The formula you employ to calculate displacement will be based on the variables presented to you in a particular problem.

The resultant is the vector sum of each individual vector. The different vectors are combined to produce the outcome. By combining the separate displacements using vector addition techniques, the outcome can be calculated.

Therefore the resultant displacement can have any value from 2-14. It depends upon the orientation of displacement vectors.

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The complete question is:

"A physics student adds two displacement vectors with magnitudes of 8.0 km and 6.0 km. Which one of the following statements is true concerning the magnitude of the resultant displacement? A) It must be 10.0 km. B) It must be 14.0 km. C) It could be equal to zero kilometers, depending on how the vectors are oriented. D) No conclusion can be reached without knowing the directions of the vectors. E) It could have any value between 2.0 km and 14.0 km depending on how the vectors are oriented."

Part A: Resolve t = 8 (interpolate)

Answers

The displacement and velocity values at time, t = 8 seconds are; 11.76 and -0.545 respectively

How can interpolating be used to find variable values at a given time?

Part A

The possible values in the table are;

Displacement;

t = 7 seconds, y = 10.02

t = 8 seconds, y = 11.01

t = 9 seconds, y = 13.5

Velocity;

t = 7 seconds, y = 0.06

t = 8 seconds, y = -0.05

t = 9 seconds, y = -1.15

The equation for interpretation which is a form of linear equation is presented as follows;

[tex]y - y_0 = \frac{y_1 - y_0}{x_1 -x_0} \times (x - x_0)[/tex]

Interpolating for the displacement at t = 8.0 seconds is as follows;

[tex]y - 10.02 = \frac{13.5 - 10.02}{9 - 7} \times (8 - 7)[/tex]

Which gives the displacement at t = 8.0 seconds as 11.76

Interpolating for the velocity at t = 8.0 seconds is as follows;

[tex]y - 0.06 = \frac{(-1.15) - 0.06}{9 - 7} \times (8 - 7)[/tex]

Which gives the velocity at t = 8.0 seconds as -0.545

The values for the displacement and velocity obtained by interpolation (11.76 and -0.545) are different from the displacement and velocity values in the table at t = 8 which are; 11.01 and -0.05 respectively

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Which ball takes a greater force to stop: a slow-moving ball or a fast-moving ball of the same mass? explain your reasoning in terms of newton's second law.

Answers

The fast-moving ball will require a greater force to stop than the slow-moving ball of the same mass because the fast-moving ball has more acceleration than the slow-moving ball.

Newton's second law of motion states that "the magnitude of the force acting on an object is equal to the mass of that object and and the acceleration with which it moves.

In other words, the rate of acceleration with which a body moves is directly proportional to the force needed to stop it, and inversely proportional to the mass of the body. Thus, the faster an object moves, the greater the force that will be required to stop it.

That is why the fast-moving ball in the question needed a greater force to stop it than the slow-moving ball, even though they are of the same mass.

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6. Predicting If you added salt instead of sugar
to a pitcher of lemonade, how would this
change the properties of the lemonade?
—NEED HELPP NOWW
also wouldn’t the properties stay the same because every substance has the the same properties and table salt and table sugar are examples of pure substance??

Answers

The lifespan of lemonade is significantly extended if salt is used in place of sugar. In other words, it lasts a lot longer than it would typically.

Despite having a similar appearance, salt and sugar taste considerably differently. Chemically, they differ greatly as well. Salt is an ionic compound comprised of sodium and chloride. Contrarily, sugar contains covalent bonds and is made up of carbon, oxygen, and hydrogen. Similar to adding a pinch of the traditional sodium chloride to baked goods like pies or cakes, adding salt to lemonade can help enhance the sweet flavors and lessen any bitterness that may be present.

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A proton, which is the nucleus of a hydrogen atom, can be modeled as a sphere with a diameter of 2.4fm and a mass of 1.67x10-27kg. determine the density of the proton.

Answers

The density of a proton is 2.87 x 10^19 kg/m^3.

The density of a proton can be calculated by dividing its mass by its volume i.e.,

Density = Mass/Volume

The mass of a proton is given to be 1.67 x 10^-27 kg.

As the proton is assumed to be a sphere, its volume will be 4/3 π r^3.

Thus, density = 1.67 x 10^-27/ (4/3 x π x r^3)

Putting radius of proton(r) = 2.4 fm = 2.4 x 10^-15 m

The density comes out to be 2.87 x 10^19 kg/m^3.

Thus, the density of a proton is 2.87 x 10^19 kg/m^3.

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If the lead can be extracted with 92.5fficiency, what mass of ore is required to make a lead sphere with a 7.00 cm radius? the density of lead is 11.4 g/c

Answers

If the lead can be extracted with 92.5 efficiency, the mass of ore is required to make a lead sphere with a 7.00 cm radius is 17.707 kg.

To find the mass of ore, the given values are,

The radius of the lead sphere is r = 7.0 cm,

The lead can be extracted with, η = 92.5% = 0.925 efficiency.

What is the Density?

Density is the substance's mass per unit of volume.

We know the density of lead as,

⇒ p = 11.4 g/cm³ .

The volume of the lead sphere is,

V = 4/3πr³

   = 4/3π(7)³

V = 1436.7 cm³.

Mass of the lead present in the lead sphere is,

m = p . V

    = 11.4  × 1436.7

    = 16379 g

m = 16.379 kg

From the expression of efficiency, we calculate the mass of the ore,

η = Mass of lead obtained / Mass of the ore to be taken

0.925 = 16.379 kg / Mass of the ore to be taken

Mass of the ore to be taken = 17.707 kg

If the lead can be extracted with 92.5 efficiency, the mass of ore is required to make a lead sphere with a 7.00 cm radius is 17.707 kg.

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If the frequency of a wave is
20
H
z
, what is the period of the wave?

Answers

Answer: 0.05 secs is the time period

The amount of downward force exerted by an object under the pull of gravity is its?

Answers

The correct answer for the amount of downward force exerted by an object under the pull of gravity is its Weight.

Weight is a restraining force. The magnitude of weight is denoted by the symbol w. Galileo was instrumental in demonstrating that, in the absence of air resistance, all objects fall with the same acceleration g. Normal force is defined as the force exerted on an object by a surface. When an object is at rest, its net force is equal to zero; thus, the downward force (weight) must equal the upward force (normal force). Because weight acts downward, it will be negative. It is determined by the object's mass and the acceleration due to gravity, which is 9.8 m/s2 on Earth. The weight formula is F = m 9.8 m/s2, where F is the object's weight in Newtons (N) and m is the mass in kg .

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You are given the equation(s) used to solve a problem. write a realistic problem for which this is the correct equation(s) number 72

Answers

Complete Question

In Problems 69 through 72 you are given the equation(s) used to solve a problem. For each of these,

(a) Write a realistic problem for which this is the correct equation(s).

The electric field due to a point charge at distance of 1 um is given as 1.5x10^6 N/C

E = (9*10^9 Nm^2/C^2*N*1.6*10^-19 C)/(1*10^-6)^2

E = 1.5x10^6 N/C

Hence, Electric field is 1.5x10^6 N/C

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A tortoise can run with a speed of 16.3 cm/s, and a hare can run 220.2 cm/s. In a race, they both start at the same time, but the hare stops to rest for 1.6 min. The tortoise wins by 108 cm.

What was the length of the race in cm?

Answers

The correct answer is 369.2765m

Speed of tortoise = v_t= 16.3cm/s=0.163m/s

Speed of hare= v_h=220.2cm/s=2.202m/s

Rest time of hare is t_r=1.6min

Tortoise wins by distance of x = 108cm=1.08m

Consider that S is the length of a racetrack.

At the conclusion of the race, calculate the tortoise's distance travelled.

S=v_t×t

S=0.163m/s×t ______(1)

Here, t is the race's actual time.

Find out how long the hare spent racing.

t_h=t-t_r

t_h=t-1.6min×(60s/1min)

t_h=(t-2160)s

At the conclusion of the race, determine the hare's distance travelled.

S-x=v_h×t_h

S-1.08m=2.2×(t-2160)s

S=2.2×(t-2160)s+1.08m_____(2)

To determine the race time, substitute equation (1) for equation (2).

0.163m/s×t=S=2.2×(t-2160)s+1.08m

0.163t=2.26t-4752+1.08

4752-1.08=2.26t-0.163t

4750.92=2.097t

4750.92/2.097=t

2265.5=t

To determine the length of the race or the track, substitute the amount of time in equation (1).

S=0.163m/s×t

S=0.163×2265.5

S=369.2765m

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Randomly assigning students to different groups in an expeirment on memory would be

Answers

The correct answer is an important measure for controlling bias.

An effective way to prevent under-coverage in a memory experiment would be to randomly assign students to two separate groups.

The scientific method that must be repeatable and the data must be empirical for science to be trusted.

When scientists publish their work, they include enough information so that other scientists can repeat the experiment and obtain the same outcomes.

Additionally, in contrast to theories that are not supported by facts, the scientific method is founded on empirical evidence, which is derived from personal observations of the outside world.

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