identify two factors that determine the amount of electricity that can be generated by an indi-vidual hydroelectric power plant. (2 points)

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Answer 1

Two factors that determine the amount of electricity that can be generated by an individual hydroelectric power plants - It depends on the vertical distance through which the water falls and the flow rate, or amount of water that flows past a certain point per unit time, The greater the distance that the water falls, the more potential energy it had and the more electricity is generated the more kinetic energy it has and the more .

Impoundment, diversion, and pumped storage facilities are the three different types of hydroelectric facilities. Hydropower plants vary in their utilisation of dams. Despite the fact that not all dams were constructed for hydropower, they have been successful in supplying vast amounts of renewable energy to the grid. As of 2020, fewer than 2,300 of the more than 90,000 dams in the United States were producing electricity. The other dams are utilised for water supply, irrigation, flood control, stock/farm ponds, and recreation. Hydropower facilities come in a variety of sizes, from modest initiatives providing electricity for a single house or community to massive undertakings. 

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true/false. two competing models attempt to explain the motions and changing brightness of the planets: ptolemy's geocentric model and copernicus' heliocentric model. sort the characteristics according to whether they are part of the geocentric model, the heliocentric model, or both solar system models.

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The geocentric model is a solar system model that places the Earth at the center and explains the motion of the planets through circular paths. The heliocentric model, on the other hand, places the Sun at the center and explains the motion of the planets through orbit around the Sun. The changing brightness of the planets is explained by their varying distances from either the Earth (geocentric model) or the Sun (heliocentric model).

True, two competing models were created to explain the motions and changing brightness of the planets. These were Ptolemy's geocentric model and Copernicus' heliocentric model. The geocentric model, as its name suggests, places the Earth at the center of the solar system and the planets, including the Sun, orbit around it. The heliocentric model, on the other hand, places the Sun at the center of the solar system and the planets, including Earth, orbit around it.

In the geocentric model, the planets move in circular paths called epicycles, which are superimposed on larger circular paths called deferents. The changing brightness of the planets is explained by their varying distances from the Earth.

The heliocentric model explains the motion of the planets as the result of their orbit around the Sun. The changing brightness of the planets is also explained by their varying distances from the Sun.

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an initially motionless test car is accelerated uniformly to 135 km/h in 7.88 s before striking a simulated deer. the car is in contact with the faux fawn for 0.755 s, after which the car is measured to be traveling at 71.0 km/h.a. What is the magnitude of the acceleration of the car before the collision?b. What is the magnitude of the average acceleration of the car during the collision?c. What is the magnitude of the average acceleration of the car during the entire test, from when the car first begins moving until the collision is over?

Answers

The magnitude of the acceleration of the car before the collision is  4.23[tex]\frac{m}{ (s ^ 2)}[/tex] and the magnitude of the average acceleration of the car during the collision is -16 [tex]\frac{m}{ (s ^ 2)}[/tex] and the magnitude of the average acceleration of the car during the entire test, from when the car first begins moving until the collision is over is 2.46[tex]\frac{m}{ (s ^ 2)}[/tex].

Velocity of car before collision is [tex]v_{1}[/tex] = 120km / h

Velocity of car after collision is, [tex]v_{2}[/tex] = 76.5km / h .

Time taken by a car before collision is, t =7.88:

Acceleration of car before collision is calculated as;

a = [tex]\frac{v-u}{t}[/tex]

a =[tex]\frac{120\times \frac{5}{18}-0 }{7.88}[/tex]

a = 4.23[tex]\frac{m}{ (s ^ 2)}[/tex]

Therefore magnitude of acceleration of a car before collision a = 4.23  [tex]\frac{m}{ (s ^ 2)}[/tex]

The average vehicle acceleration at the time of impact is computed as;

[tex]a_{avg}[/tex] = [tex]\frac{v-u}{t}[/tex]

[tex]a_{avg}[/tex] =[tex](120-76.5)\times \frac{5}{18}[/tex]

[tex]a_{avg}[/tex] =0.755 s

[tex]a_{avg}[/tex] =-16 [tex]\frac{m}{ (s ^ 2)}[/tex]

Here, a negative sign shows that the average acceleration is moving in the opposite direction from where the car is travelling.

[tex]a_{avg}[/tex] = [tex]\frac{v-u}{t}[/tex]

[tex]a_{avg}[/tex] =[tex]\frac{ (120-76.5)\times \frac{5}{18}}{0.755}[/tex]

[tex]a_{avg}[/tex] =-16[tex]\frac{m}{ (s ^ 2)}[/tex]

Here, the negative sign denotes that the average acceleration is occurring in the opposite direction to the motion of the car.

Therefore, the average acceleration of a car during collision is [tex]a_{avg}[/tex] =16 [tex]\frac{m}{ (s ^ 2)}[/tex]

and in direction opposite to the direction of car.

The average acceleration of the car during the test is calculated.

as,

[tex]a_{2}[/tex]=[tex]\frac{v-u}{t}[/tex] =[tex]76.5\times a_{2}[/tex]= [tex]\frac{76.5\times\frac{5}{18} }{7.88-0.75}[/tex]

[tex]a_{2}[/tex]=2.46[tex]\frac{m}{ (s ^ 2)}[/tex]

Therefore, the average acceleration of a car during entire test is a_{2} = 2.46[tex]\frac{m}{ (s ^ 2)}[/tex]

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The light given off by a sodium vapor lamp used for public lighting has a wavelength of 589 nm.
a. What is the frequency of this radiation?
b. What is the energy of one photon of the sodium vapor?

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The wavelength of the yellow light produced by a sodium lamp post is 589 m. What frequency does this light have. (Response: 5.093 x 10'/Sec)

What wavelength of electromagnetic radiation does sodium emit at 589.0 nm?

It is assumed that the radiation's wavelength is 589 nm. Therefore, option C is appropriate because the frequency of irradiation is 5.09 1014 s1.

When sodium's surface is exposed to electromagnetic radiation with a wavelength of 300 nm?

Electrons with a kinetic energy of 1.68 105 Jmol1 are released from the surface of sodium when electromagnetic radiation with a wavelength of 300 nm falls on it.

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A 0.14 kg ball is dropped from a height and hits the ground at a velocity of -9 m/s (the negative sign shows the downward direction of the ball's motion). After
touching the ground for a short period of time, the ball bounces back at a velocity of +8.5 m/s. What is the impulse on the ball due to the floor?

Answers

Answer:

Impulse = Δp = 2.45 kg m/s

Explanation:

Impulse = change in momentum = final momentum - initial momentum

The initial momentum of the ball before hitting the ground is given by:

m * v_i = 0.14 kg * -9 m/s = -1.26 kg m/s

The final momentum of the ball after bouncing back is given by:

m * v_f = 0.14 kg * 8.5 m/s = 1.19 kg m/s

So the change in momentum is:

Δp = v_f - v_i = 1.19 kg m/s - (-1.26 kg m/s) = 2.45 kg m/s

Impulse = Δp = 2.45 kg m/s

part a of the drawing shows a bucket of water suspended from the pulley of a well; teh tension in the rope is 92.0 n. part b shows the same bucket of water being pulled up from the well at a constant velocity. what is the tension in the rope in part b?

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In part b of the drawing, the bucket of water is being pulled up from the well at a constant velocity. In this situation, the tension in the rope must provide the force necessary to balance the weight of the bucket and any friction forces.

The force required to lift the bucket is equal to the weight of the bucket plus the force of friction. If the tension in the rope is less than the force required to lift the bucket, the bucket will not move. If the tension in the rope is greater than the force required to lift the bucket, the bucket will accelerate upward.

Since the bucket is being lifted at a constant velocity, this means that the tension in the rope must equal the force required to lift the bucket. Therefore, the tension in the rope in part b of the drawing is equal to the weight of the bucket plus the force of friction. If this value is not given, it cannot be determined without additional information.

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A man exerts a horizontal force of 145 N on a crate with a mass of 31.2 kg.

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Answer:

Below

Explanation:

If you can't overcome the force of friction....the crate will not move

so friction force = 145 N

Coeff of friction =  Ff / Normal force = 145 / (31.2 * 9.81) = .47

An astronomer finds an object at a distance of 6.8 AU from theEarth. Which type of object is this likely to be?
A A comet in our solarsystem.
B A star in ourGalaxy.
C An artificial satelliteorbiting the Earth.
D A distant galaxy.

Answers

I think the answer is A

a physicist at a fireworks display times the lag between seeing an explosion and hearing its sound, and finds it to be 0.700 s. (enter your answers to at least four decimal places. use the following relationship between kelvin and celsius: t(k)

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As just a unit for one unit, both scales are connected. A change of one unit on the Kelvin scale corresponds to a change of one degree on the Celsius scale. The following equation relates the Kelvin scale to the Celsius scale: K Equals 0C - 273.15.

How would you define Celsius in plain English?

Water's freezing point is 0 degrees Celsius, or centigrade, and its boiling point is 100 degrees Celsius. Swedish Swedish scientist Anders Celsius created the Celsius scale in 1742; due to the 100-degree gap between the designated points, it is sometimes referred to as the centigrade scale.

What is the reputation of Celsius?

As the acknowledged father of Swedish astronomy, Anders Celsius is most known for developing the Celsius temperature scale, often known as the centigrade scale, on which the boiling point of water is expressed as 100°C and the freezing point as 0°C.

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warm air over the beach rise while cooler dense air the ocean rushes in due to

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Answer: Convection causes the warmer air over land to expand and rise, which in turn causes low air pressure over the land. The cooler air over the ocean rushes in to replace the warm air that just rose over land. This causes a sea breeze.

Explanation:

hope this helped ;) ! -middle schooler

Answer:

convection

Explanation:

heat rises up

fill in the blank. after thomson's work showed that atoms contain smaller charged particles called electrons, millikan conducted experiments on charged oil droplets. from these experiments millikan precisely determined the to___ratio of an electron.

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After Thomson's work showed that atoms contain smaller charged particles called electrons, Millikan conducted experiments on charged oil droplets. From these experiments, Millikan precisely determined the mass-to-charge ratio of an electron.

In 1897, J. J. Thomson replаced the mаgnetic field with аn electric field in а cаthode rаy tube with аn improved vаcuum, аnd he showed thаt the cаthode rаys were аttrаcted to the positive plаte аnd repelled by the negаtive plаte. This confirmed thаt the cаthode rаys were composed of negаtively chаrged pаrticles. Thomson cаlled these pаrticles corpuscles, but they hаve come to be cаlled electrons, а nаme suggested by George Johnstone Stoney in 1891.

Thomson wаs аble to cаlculаte the mаss to chаrge rаtio, аnd the results of his experiments аnd cаlculаtions suggested thаt electrons were аbout 1/1000 the mаss of hydrogen аtoms, suggesting thаt аtoms аre composed of pаrticles smаller thаn the аtoms itself. Becаuse the results of his experiments were independent of the gаs in the tube, he concluded thаt аll substаnces contаin these sаme electrons.

In 1909, Robert Millikаn аnd Hаrvey Fletcher observed chаrged oil droplets fаlling between two electricаlly chаrged plаtes. Millikаn аssumed thаt this wаs the chаrge of аn electron, аnd from the mаss to chаrge rаtio determined by Thomson, the mаss of the electron wаs found to be аbout 1/1836 the mаss of а hydrogen аtom, confirming thаt аtoms аre composed of pаrticles much smаller thаn even the smаllest аtom.

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a block of mass m1 is at rest on a long frictionless table, one end of which is terminated in a wall. another block of mass m2 is placed between the first block and the wall and set in motion to the left with constant speed v2i. assuming that all collisions are completely elastic, find the value of m2 for which both blocks move with the same velocity after m2 has collided once with m1 and once with the wall. assume the wall to have infinite mass.

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After a collision, the center of mass velocity of this system of two balls with masses m1 and m2 and velocities v1 and v2 is ( m1 v1 + m2 v2 ) / ( m1 + m2 ).

What is the momentum law of motion?

Momentum is the force needed to stop an item moving at a certain speed in a given amount of time. It is calculated by multiplying an object's mass by its velocity. The sum of the individual momenta determines the overall momentum for any array of many objects.

p = m.v

p = Momentum

m = Mass

v = Velocity

For ball 1,

m = m1

v = v1

p1 = m1 v1

For ball 2,

m = m2

v = v2

p2 = m2 v2

Center of mass velocity = Total momentum / Total mass

Total momentum is = p1 + p2

Total mass is= m1 + m2

Center of mass velocity is= ( p1 + p2 ) / ( m1 + m2 )

Center of mass velocity is= ( m1 v1 + m2 v2 ) / ( m1 + m2 )

Therefore, center of mass velocity  of this system of two balls is

Center of mass velocity = ( m1 v1 + m2 v2 ) / ( m1 + m2 ).

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Calculate the force of Earth's gravity on a spacecraft 2.00 Earth radii above the Earth's surface if its mass is 1700 kg.A) 2014 NB) 2330 NC) 1755 ND) 2610 N

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The correct option is D, the force of Earth's gravity on a spacecraft 2.00 Earth radii above the Earth's surface is 2610 N.

The force of Earth's gravity on a spacecraft can be calculated using the equation F = G * (m1 * m2) / r^2, Earth's surface is approximately 2 * 6,371,000 m = 12,742,000 m). Plugging in the values, we get:

F = 6.67 x 10^-11 Nm^2/kg^2 * (5.97 x 10^24 kg * 1700 kg) / (12,742,000 m)^2

F = 2610 N

Force is a term used in physics to describe the influence that causes an object to undergo a change in motion. It is a vector quantity, meaning it has both magnitude and direction. Force can cause an object to move, change its speed, or change its direction. It can also cause a stationary object to start moving. There are several types of forces, including gravitational forces, electrical forces, magnetic forces, and friction forces. Force can also be described as a push or a pull.

Force is an essential concept in physics as it helps us understand the behavior of objects and how they interact with each other. For example, the force of gravity keeps planets in orbit around the sun. The force of friction is what allows us to walk on the ground without slipping. The force of air resistance affects the motion of projectiles and affects the speed of vehicles.

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a 95kg halfback moving at 4.1 m/s on an apparent breakaway for a touchdownd what was their mutual speed

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When a 95-kg halfback moving at 4.1 m/s is tackled from behind by an 85-kg cornerback running at 5.5 m/s in the same direction, their mutual speed immediately after the tackle is 1.96 m/s.

The mutual velocity of two colliding bodies is the velocity of the center of mass of the system after the collision. In an inelastic collision, the total momentum of the system is conserved, but the kinetic energy is decreased. The final velocity of the system can be calculated by dividing the total momentum by the total mass of the system.

In this case, the mutual velocity after the tackle is equal to the velocity of the center of mass of the system formed by the halfback and the cornerback. By using the equation for the center of mass velocity, the mutual velocity after the tackle can be calculated as follows:

v_cm = (m1 × v1 + m2 × v2) / (m1 + m2)

where v_cm is velocity of the center of mass (mutual velocity or mutual speed),  m1 is the mass of the halfback, v1 is the initial velocity of the halfback, m2 is the mass of the cornerback, and v2 is the initial velocity of the cornerback.

v_cm = (95 kg × 4.1 m/s + 85 kg × 5.5 m/s) / (95 kg + 85 kg)

v_cm = 1.96 m/s

So the mutual speed immediately after the tackle was 1.96 m/s.

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Your question seems missing, but I suppose the question was:

"A 95-kg halfback moving at 4.1 m/s on an apparent breakaway for a touchdown is tackled from behind. When he was tackled by an 85-kg cornerback running at 5.5 m/s in the same direction, what was their mutual speed immediately after the tackle?"

A satellite of mass 2,000 kg is in an elliptical orbit about the Earth. When the satellite reaches point A, which is the closest point to the Earth, its orbital radius is 1.2x10'm and its orbital velocity is 7.1x 103 m/s. (Me = 6x1024 kg and Re = 6.4x10 m) a. Determine the total mechanical energy of the satellite at point A, assuming that the gravitational potential energy is zero at an infinite distance from the Earth. b. Determine the angular momentum of the satellite at point A. c. What is the minimum speed of the satellite at point A in order to escape from Earth? When the satellite reaches point B, which is the furthest point from the Earth, its orbital radius is 3.6x107m. d. Determine the speed of the satellite at point B.

Answers

A satellite of mass 2,000 kg is in an elliptical orbit about the Earth. When the satellite reaches point A, which is the closest point to the Earth, its orbital radius is 1.2x10'm and its orbital velocity is 7.1x 103 m/s. (Me = 6x1024 kg and Re = 6.4x10 m). So, the total mechanical energy of the satellite at point A is -0.6x10^13 J, assuming that the gravitational potential energy is zero at an infinite distance from the Earth.

The total mechanical energy (E) of an object in orbit is given by the equation E = kinetic energy (K) + potential energy (U).

At point A, the kinetic energy (K) is given by the equation K = (1/2)mv^2, where m is the mass of the satellite (2,000 kg) and v is its velocity (7.1x10^3 m/s).

The potential energy (U) is given by the equation U = -GMe/r, where G is the gravitational constant (6.67x10^-11 Nm^2/kg^2), Me is the mass of the Earth (6x10^24 kg), and r is the distance of the satellite from the Earth (1.2x10^6 m).

Substituting the values into the equations and solving, we get:

K = (1/2)(2,000 kg)(7.1x10^3 m/s)^2 = 3.0x10^13 J

U = -(6.67x10^-11 Nm^2/kg^2)(6x10^24 kg)/(1.2x10^6 m) = -3.6x10^13 J

E = K + U = 3.0x10^13 J + (-3.6x10^13 J) = -0.6x10^13 J

So, the total mechanical energy of the satellite at point A is -0.6x10^13 J, assuming that the gravitational potential energy is zero at an infinite distance from the Earth.

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If a ball is thrown in the air with a velocity 50 ft/s, its height in feet t seconds later is given by y = 50t − 16t^2.
(a) Find the average velocity for the time period beginning when t = 2 and lasting
0.5 second
0.1 second
0.05 second
0.01 second

Answers

The average velocity for the time period beginning when t = 2s and lasting 0.5s is 39.625ft/s, 0.1s is 15.6ft/s, 0.05s is 14.8ft/s, 0.01s is 16ft/s

Given the initial velocity of the ball (u) = 50ft/s

The motion is given as: [tex]y = 50t - 16t^2[/tex] where y is the height of the ball.

We can see that it is similar to [tex]y = ut + 1/2at^2[/tex] such that 1/2a = 16 then a = 32m/s2

The initial time when the ball is thrown in air (t1) = 2s

The total distance a particle has travelled divided by the total amount of time it has taken to travel that distance is the definition of an object's average velocity. So, let the height h1 be covered in t1s and h2 be covered in t2s such that average velocity (v) = h2-h1/t2-t2

(a) Initially, t1 = 2s and t2 = 2+0.5s = 2.5s where [tex]y = 50t - 16t^2[/tex]

Then h1 = 50 x 2 - 16 x 2x2 = 36ft

h2 = 50 x 2.5 - 16 x (2.5)x2.5 = 115.25

V = 115.25 - 36/2.5-2 = 79.25/2 = 39.625ft/s

(b) Let t2 = 0.1 + 2 = 2.1s then,

h2 = 50 x 2.1 - 16 x (2.1)x2.1 = 34.44ft

V = 34.44 - 36/0.1 = -1.56/0.1 = -15.6ft/s

(c) Let t2 = 0.05 + 2 = 2.05s then,

h2 =  50 x 2.05 - 16 x (2.05)x2.05 = 35.26ft

V = 35.26 - 36/ 0.05 = -0.74/0.05 = -14.8ft/s

(d) Let t2 = 0.01 + 2 = 2.01s then,

h2 =  50 x 2.01 - 16 x (2.01)x2.01 = 35.84ft

V = 35.84 - 36/ 0.01 = -0.16 /0.01 = -16ft/s

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gaussian surfaces a and b enclose the same positive charge q. the area of gaussian surface a is three times larger than that of gaussian surface b. the electric flux through gaussian surface a is

Answers

In this case it will be equal to the flux of electric field through the Gaussian surface B as Flux through S(A) = Flux through S (B ) =  Charge inside/ ∈₀

Gauss's law states that the net total electric charge inside a Gaussian surface equals the total electric flux. The electric flux will remain constant even if the Gaussian surface is three times bigger if both surfaces have an equal amount of total electric charge.

Now that we have an arbitrary charge distribution, we can determine the electric flux through any closed surface. We discovered that any electric field lines entering the surface at one point must necessarily exit at another point of the surface if a closed surface lacks any charge inside where an electric field line can terminate. Therefore, the electric flux will not exist if a closed surface has no charges inside the enclosed volume.

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T/F if an object decelerates then its instant velocity vectory is oriented anit-parallel with the direction of motion

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True, object decelerate then its instant velocity  is oriented antiparallel with the direction of motion.

velocity is a term that describes the speed and direction of a point's motion For example, a circular paths' direction is always perpendicular to a line from the point to the circle's centre. A point always moves in a direction that is tangent to its path (a radius). The speed at which the point is travelling along its route in time is known as the magnitude of the velocity. If a point travels a specific distance along its path in a predetermined amount of time, its average speed throughout that time is equal to the travelled distance divided by the travel time.

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let us focus on one of the spheres after the charge has been placed on the system. which combination of analysis models below correctly describes one of the spheres in this situation and will be of most use to us for solving this problem

Answers

The combination of analysis models that correctly describes one of the spheres in this situation and will be most useful for solving the problem depends on the specific details and requirements of the problem at hand.

Some commonly used models for analyzing charged spheres include the electric field generated by a point charge, Coulomb's law, and the method of images. The choice of the most appropriate model will depend on the specific conditions and requirements of the problem, such as the distribution of charge on the spheres and the distance between them. Charge is a fundamental property of matter that refers to the amount of electrical energy in a system. It is measured in units of Coulombs and can be positive, negative or neutral. Charge can interact with other charges through the electric force, which is described by Coulomb's Law. This interaction can result in a number of phenomena, including attraction, repulsion, and the transfer of electrical energy from one object to another. Understanding charge and its interactions is crucial for many fields, including physics, engineering, and chemistry, and has many practical applications, such as in electronics, power generation and storage, and in medical imaging technologies

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using the laplace transform of u(t) for cos3wt, derive y(t) using the magnitude and phase formula discussed in class.

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The laplace transform of u(t) for cos3wt, then [tex]y(t) = (1/6) [e^(3it) + e^(-3it)]u(t).[/tex]

Let Y(s) represent y's Laplace transform (t).

Since [tex]y(t) = u(t)cos3wt[/tex], we can write:

[tex]Y(s) = U(s) * [s/(s^2 + 9)][/tex]

Using the magnitude and phase formula discussed in class, we can express y(t) as:

[tex]y(t) = (1/6) [e^(3it) + e^(-3it)]u(t)[/tex]

The Laplace transform is a mathematical transformation used to solve differential equations. It takes a function of time, f(t), and transforms it into a function of a complex variable, F(s), which is known as the Laplace transform of f(t). This transform is useful for analyzing linear, time-invariant systems, and is used in many engineering fields to solve differential equations, such as in electrical, mechanical and control engineering.

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Holding your hand at arm's length, you can readily block sunlight from reaching your eyes. Why can you not block sound from reaching your ears this way?

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The diffraction of visible light around an obstruction the size of your hand is completely inconsequential since the wavelength of visible light is incredibly small in compared to the proportions of your hand.

What is the SI unit and wavelength?

Wavelength is the distance represented by the length of one cycle of a wave. The wavelength symbol is, and the SI unit for wavelength is the metre (m).

What does a wavelength look like?

Here are a few examples of wavelengths: The Yellow Light illustration is suitable. All visible light has a wavelength that ranges from 400 to 700 nanometers (nm). The wavelength of yellow light is around 570.nanometers. (nm) Wavelength (nm) (nm).

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determine the position, velocity, and acceleration of a. (you must provide an answer before moving to the next part.) the position, velocity, and acceleration of a when t

Answers

If you know the position function of an object, you may quickly get its velocity function via taking its derivative.

What is the connection between location and velocity?

The direction and speed of an object's motion are its velocity. In other terms, velocity is the rate at which an object's position changes. Position includes direction by indicating whether an object is traveling backwards or forwards down a line, sidewards upward and downward in the two or three dimensions, or in any combination of these directions.

Give an illustration of the relationship between acceleration and velocity.

If an object's velocity is changing, it is accelerating. As a type of vector, velocity has both direction and magnitude. As a result, any acceleration can be explained these three methods an East to North-East direction shift.

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A sound source producing 1.40 kHz waves moves toward a stationary listener at one-half the speed of sound. What frequency will the listener hear? Now, suppose instead that the source is stationary and the listener moves toward the source at one-half the speed of sound. What frequency does the listener hear?

Answers

When the sound source is moving towards the stationary listener at one-half the speed of sound, the frequency heard by the listener will be 1.40 kHz.

When the source is stationary and the listener moves towards the source at one-half the speed of sound, the frequency heard by the listener will be 1.80 kHz. This is because the Doppler effect causes the frequency of a sound wave to increase as the source moves towards the listener and decrease as the source moves away from the listener.

Frequency is a measure of how often a wave or signal repeats itself over a given period of time. Frequency is usually measured in hertz (Hz), which means the number of cycles per second. Frequency is an important concept in physics, as it is used to describe waveforms such as sound, light, and radio signals.

Frequency is also used to describe the properties of an object or system, such as its resonant frequency.

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which of the following statements about the visible spectrum of the light emitted by the sun is true?

Answers

Correct option is B, The solar spectrum consists of hundreds of dark absorption lines superimposed on a bright continuous spectrum that peaks in the yellow, near the center of the visible region.

Which spectrum does the Sun produce?

In addition, our Sun generates light in the ultraviolet, X-ray, and even gamma-ray ranges. The majority of the Sun's radiation, however, is found in the infrared, visible, and ultraviolet portions of the electromagnetic spectrum.

What is the electromagnetic spectrum?

The electromagnetic spectrum is made up of radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, gamma rays, and cosmic rays, in decreasing order of frequency and increasing order of wavelength.

The term for the collection of all electromagnetic radiation in the cosmos is the electromagnetic spectrum, or EM spectrum. In the form of electric and magnetic waves, this kind of energy permeates the cosmos and enables the transmission of information and energy.

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Complete question -

Which of the following statements about the visible spectrum of the light emitted by the Sun is true?

A. It consists of hundreds of bright emission lines that cluster near the middle of the visible region.

B. It consists of hundreds of dark absorption lines superimposed on a bright continuous spectrum that peaks in the yellow, near the center of the visible region.

C. It consists of a few dark absorption lines on a continuous spectrum that is otherwise independent of wavelength.

D. It consists of a few bright lines widely separated from each other, mostly in the yellow portion of the visible range.

E. It consists of a smooth blackbody curve corresponding to a temperature of 6300 K, with no other prominent absorption or emission features.

Calculate the x-component of the electric field at point P due to charge Q1. Write your answer in units of N/C.
A positive charge of magnitude Q1 = 0.45 nC is located at the origin. A negative charge Q2 = -9.5 nC is located on the positive x-axis at x = 6.5 cm from the origin. The point P is located y = 7.5 cm above charge Q2.

Answers

The x-component of the electric field at point P due to charge Q1 is 270 N/C.

The query asks what charge Q1 is responsible for the x component of the electric field vector at point P. In light of this, you disregard charge Q2's contribution.

Assume that point P contains a little positive charge. By definition, the strength of the electric field caused by charge Q1 at point P is:

E = [tex]\frac{kQ1}{d^{2} }[/tex] where k is the coulomb constant and d is the straight-line distance from Q1 to P.

The distance, d, is the hypotenuse of the triangle formed by the point P, charges Q1 and Q2. Therefore,

d = [tex]\sqrt{0.065^{2} } + \sqrt{0.075} ^{2}[/tex] = 0.099 m

Now, finding the electric field, we get:

E = 8.99 × [tex]10^{-9} Nm^{2} C^{-2}[/tex] × 0.45 × [tex]10^{-9}[/tex] / [tex]0.099^{2}[/tex] = 412 n/c

The x component of the electric field, [tex]E_{x}[/tex], would be:

412 × cos49° = 270 N/C.

The Electric field points away from positive charges (q > 0) and towards negative charges. In Maxwell's equations, the E-field is always a vector field with three dimensions. This indicates that it consists of three parts: an x, y, and z component that respectively determine the x, y, and z directions of the electric field.

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a student conducts an experiment in which a cart is pulled by a variable applied force during a 2 s time interval. in trial 1, the student exerts the force on a cart of mass m . in trial 2, the student exerts the force on a cart of mass 3m .

Answers

As long as the force and time are the same, all vehicles experience the same change in momentum, regardless of their mass.

Given the time interval force applied on cart = 2s

The mass of cart in trail 1 = m

The mass of cart in trail 2 = 3m

The mass of cart in trail 3 = 5m

From Newtons laws of motion: F = ma where F is the force applied and a is the acceleration and v = v0 + at where v0 is the initial velocity.

So, v = v0 + (F/m)t

We know that momentum is defined as mass x velocity such that:

p = mv then the change in momentum is seen as: Δp = mv - mv0

Δp = m(v0 + Ft/m) - mv0

Δp = Ft

Since the force and time are the same for all vehicles, we can see that the change in momentum is independent of the mass of the vehicles.

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complete question: A student conducts an experiment in which a cart is pulled by a variable applied force during a 2sec time interval. In trial 1, the student exerts the force on a cart of mass M. In trial 2, the student exerts the force on a cart of mass 3M. In trial 3, the student exerts the force on a cart of 5M. In which trial will the cart experience the greatest change in momentum from 0 sec to 2 sec?

mark climbs up onto the roof of his house to hang a new flood light above the garage. being afraid of heights, mark carefully looks over the edge and ponders a possible fall to the ground below. the top of the roof is 5 meters 5 meters above the ground below. if mark has a mass of 65 kg 65 kg , which of the following values is mark's gravitational potential energy? use g

Answers

This potential energy is known as gravitational potential energy. It is the gravitational field's potential energy that is released when two objects fall in close proximity to one another.

The short answer to the question of potential energy

The term "potential energy" refers to the energy that is conserved or stored in a material or object. The location, configuration, or status of the substance or object determines the stored energy.

Which potential energy is an example?

Energy that has been stored is called potential energy. A battery, a stretched spring, and lifting an object are some examples. There are two major categories of energy: potential and kinetic.

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A circuit contains two resistors linked in parallel; each resistor has a resistance of 20 Ω . What is the circuit's total resistance?

Answers

The resultant resistance of the resistor combination   is 10 Ω.

What is resistor?

A resistor is an electrical component that controls or restricts how much electrical current can pass across a circuit in an electronic device. A specified voltage can be supplied via resistors to an active device like a transistor.

Resistance of each resistor is = 20 Ω

The resistors are connected parallelly.

Hence, the resultant resistance of the resistor combination  = (20 ||20)  Ω

= (20 × 20) ÷ (20 + 20)  Ω

= 10  Ω.

Therefore, the resultant resistance of the resistor combination   is 10 Ω.

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1. A) If the radius of a cylinder increases by a factor of 2.73, by what factor does the volume change? Assume that the height of the cylinder stays the same.​

Answers

The new volume of the cylinder will increase by a factor of 7.453.

What is the volume of a cylinder?

The volume of a cylinder is calculated by applying the following equation as shown below.

V  = πr²h

where;

r is the radius of the cylinderh is the height of the cylinder

when the radius increases by a factor of 2.73, the new volume will become;

V = π(2.73r)²h

V = 7.453 πr²h

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If the voltage across a circuit of constant resistance is doubled, the power dissipated by that circuit will O A. be two times as large. O B. be four times as large. O C. decrease to one-half the original power. O D. decrease to one-fourth the original power. QUESTION 17 The network shown is assembled with uncharged capacitors X, Y, and Z, with cx = 4.0 pF, CY = 6.0 pF, and Cz- 5.0 pF. The switches 51 and 52 are initially open, and a potential difference Vab = 120 V is applied between points a and b. After the network is assembled, switch Sy is then closed, but switch S2 is kept open. What is the final potential difference across capacitor X? Assume all numbers jare accurate to 2 significant figures, Y = +120V Ñ… Z O A. 120 V O B.60 V O C.82 V O D.75 V O E. 67 V

Answers

The first question has an answer: twice the voltage across a constant resistance circuit quadruples the power lost by that circuit (Option B). Sorry, but I require additional network information to solve for the ultimate potential difference across capacitor X in the second question.

What is voltage?

Voltage is a quantitative measure of the potential difference in charge between two places in an electrical field. It is also known as electromotive force. Voltage is the force exerted by the power source of an electrical circuit to move charged electrons (current) through a conducting loop, allowing them to do work such as lighting a lamp. Voltage refers to the "pressure" exerted by electricity. Voltage is measured in units known as volts (V), and greater voltages cause more electricity to flow to an electrical equipment.

Here,

The answer to the first question is that doubling the voltage across a constant resistance circuit doubles the power wasted by that circuit fourfold (Option B). Sorry, but I need more information about the network to solve for the ultimate potential difference across capacitor X in the second question.

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What would the power (Watts) be for a speaker if it draws 3.0 Amps of current when connected to a 12.0 Volt source?

Answers

The power of Speaker can be calculated by

[tex]P=V.i\\P=(12).(3)\\P=36W[/tex]

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