a) d[C₈H₁₂]/dt = k * [C₄H₆]ᵃ, b) d[C₄H₆]/dt = -k * [C₄H₆]ᵃ . c) i. Zero order: ln([C₄H₆]0/[C₄H₆]) = -kt, [C₄H₆] = [C₄H₆]0 * e⁽⁻kt⁾, ii. First order:, ln([C₄H₆]/[C₄H₆]0) = -kt, [C₄H₆] = [C₄H₆]0 * e⁽⁻kt⁾, iii. Second order:, 1/[C₄H₆]=kt + 1/[C₄H₆]0, [C₄H₆] = 1 / (kt + 1/[C₄H₆]0), d) From the graphs in part (c), the experimental rate order of this reaction is first order. e) The experimental reaction rate constant, k, can be determined from the slope of the first order plot and has units of 1/s.
The balanced chemical reaction for the Diels-Alder condensation of butadiene (C₄H₆) to yield a substituted cyclohexene (C₈H₁₂) is C₄H₆+ C₄H₆-> C₈H₁₂. The overall differential rate law is d[C₈H₁₂]/dt = k * [C₄H₆]ᵃ, where k is the reaction rate constant and a is the reaction rate order. The differential rate law for C₄H₆is d[C₄H₆]/dt = -k * [C₄H₆]ᵃ. The rate order is determined from the linearized form of the data, which shows that the reaction is first order with a reaction rate constant k having units of 1/s.
a. The balanced chemical reaction and the overall differential rate law assuming the overall reaction rate is only a function of C₄H₆ concentration (CC₄H₆), reaction rate constant (k), and reaction rate order (a) is given by:
C₄H₆ + C₄H₆ -> C₈H₁₂
d[C₈H₁₂]/dt = k * [C₄H₆]ᵃ
b. The differential rate law for C₄H₆ is given by:
d[C₄H₆]/dt = -k * [C₄H₆]ᵃ
c. The linearized form of CC₄H₆ as a function of time for each reaction order:
i. Zero order:
ln([C₄H₆]0/[C₄H₆]) = -kt
[C₄H₆] = [C₄H₆]0 * e⁽⁻kt⁾
ii. First order:
ln([C₄H₆]/[C₄H₆]0) = -kt
[C₄H₆] = [C₄H₆]0 * e⁽⁻kt⁾
iii. Second order:
1/[C₄H₆] = kt + 1/[C₄H₆]0
[C₄H₆] = 1 / (kt + 1/[C₄H₆]0)
d. From the graphs in part (c), the experimental rate order of this reaction is first order.
e. The experimental reaction rate constant, k, can be determined from the slope of the first order plot and has units of 1/s.
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silicon has a bandgap of 1.12 ev at 300 k. assume the fermi level is in the middle of the bandgap, determine the probability that a state at the bottom of the conduction band is occupied by an electron at 300 k.
The probability that a state at the bottom of the conduction band is occupied by an electron at 300 K is given by f(E_CB).
At 300 K, the probability that a state at the bottom of the conduction band is occupied by an electron can be calculated using the Fermi-Dirac distribution. The Fermi-Dirac distribution gives the probability that a state with energy E is occupied by an electron at temperature T, and is given by:
f(E) = 1 / (exp[(E - E_F) / (k_B T)] + 1)
Where E_F is the Fermi level, k_B is the Boltzmann constant, and T is the temperature in kelvin.
Since the Fermi level is in the middle of the bandgap, E_F = (E_CB + E_VB) / 2 = (1.12 eV / 2) = 0.56 eV.
Substituting the values into the equation, we get:
f(E_CB) = 1 / (exp[(E_CB - 0.56 eV) / (k_B * 300 K)] + 1)
Since E_CB = 1.12 eV, we get:
f(E_CB) = 1 / (exp[(1.12 eV - 0.56 eV) / (k_B * 300 K)] + 1)
= 1 / (exp[0.56 eV / (k_B * 300 K)] + 1)
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write a polynomial function of lowest possible degree with integral coefficients, the zeros of which include 4 and 4-i
Polynomial function of lowest possible degree with integral coefficients, is x³- 12x² + 49x - 68
Complex roots (zeros) occur in conjugate pairs
Thus 4 - i is a zero then 4+ i is a zero
Given the zeros are x = 4, x = 4± i, then the factors are (x-4), (x-(4- i)) and (x - (4 + i)) The polynomial is the product of the factors, SO
expand the second pair of factors
p(x) = (x-4)(x - 4+ i)(x - 4-i)
p(x) = (x-4)((x-4)2 - 12) , where ( i² = -1 )
p(x) =(x-4)(x² - 8x + 16 + 1)
p(x) = (x-4)(x² - 8x + 17)
now expand the polynomial
p(x) =x³- 8x² + 17x-4x² + 32x - 68
collecting the like terms
p(x) = x³- 12x² + 49x - 68.
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Which of the following statements is true for ideal gases, but is not always true for real gases? Choose all that apply.
(a) Collisions between molecules are elastic
(b) Molecules are in constant random motion
(c) Replacing one gas with another under the same conditions, has no effect on pressure
(d) There are no attractive forces between molecules.
For ideal gases, statements (b) and (c) are accurate, but not usually for actual gases. Pressure is unaffected by switching from one gas to another under the same circumstances.
What distinguishes an ideal gas from a real gas in particular?A theoretical gas called an ideal gas is one that has many of randomly moving particles but doesn't have any interparticle interactions. The converse is true of a real gas; its molecules interact, and it takes up space. PV hence always equals nRT as a result of this.
Why is the theory of ideal gas invalid under high pressure and low temperature?The ideal gas law breaks down at low temperatures and high pressures because the gas's volume is so small, causing the molecules' intermolecular distance to shorten.
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Consider a hypothetical reaction in which A and B are reactants and C and D are products. If 23g of A completely reacts with 27g of B to produce 11g of C, how many grams of D will be produced?
According to law of conservation of mass, if 23 g of A reactant completely reacts with 27 g of B to produce 11 g of C,39 grams of D product will be produced.
What is law of conservation of mass?According to law of conservation of mass, it is evident that mass is neither created nor destroyed rather it is restored at the end of a chemical reaction .
Law of conservation of mass and energy are related as mass and energy are directly proportional which is indicated by the equation E=mc².Concept of conservation of mass is widely used in field of chemistry, fluid dynamics.
Law needs to be modified in accordance with laws of quantum mechanics under the principle of mass and energy equivalence.This law was proposed by Antoine Lavoisier in the year 1789.
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Name an atom that loses one electron when it reacts with another atom
Answer:
Na Atom
Explanation:
use electron configurations orbital notation and electron dot structures to represent the formation of an ionic compound from the metal strontium and nonmetal chlorine
For metal strontium cation - E.C.- [Kr], electron dot structure - Sr^2+, and for nonmetal chloride anion - E.C. - [Ne] 3s2 3p6, electron dot structure - Cl^-.
The formation of the ionic compound strontium chloride (SrCl2) from the metal strontium (Sr) and nonmetal chlorine (Cl) can be represented using electron configurations, orbital notation, and electron dot structures.
1. Electron Configuration:
Strontium (Sr): [Kr] 5s2
Chlorine (Cl): [Ne] 3s2 3p5
2. Orbital Notation:
Strontium (Sr): [Kr] 5s2
Chlorine (Cl): [Ne] 3s2 3p6
3. Electron Dot Structure:
Strontium (Sr): Sr
Chlorine (Cl): Cl
In the formation of an ionic compound, electrons are transferred from the metal (Sr) to the nonmetal (Cl) to form ions with a complete electron configuration. Strontium loses two electrons to form a cation with a 2+ charge, while chlorine gains one electron from each strontium atom to form an anion with a 1- charge.
The resulting electron configurations, orbital notations, and electron dot structures for the ions are as follows:
1. Electron Configuration:
Strontium cation (Sr2+): [Kr]
Chloride anion (Cl-): [Ne] 3s2 3p6
2. Orbital Notation:
Strontium cation (Sr2+): [Kr]
Chloride anion (Cl-): [Ne] 3s2 3p6
3. Electron Dot Structure:
Strontium cation (Sr2+): Sr^2+
Chloride anion (Cl-): Cl^-
These ions can then bond ionically to form the compound SrCl2. The compound is held together by the electrostatic attraction between the positively charged strontium cation and the negatively charged chloride anion.
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civil refer to individual rights, such as the freedom of speech and religion, while civil refer to equality under the law for different groups such as racial or religious minorities.
Civil refer to equality under the law for different groups such as racial or religious minorities or individual rights, such as the freedom of speech and religion and is a true statement.
What is Civil?This is referred to as a type of law that pertains to persons, things, and relationships that develop among them.
Such include the right of an individual to be able to do things freely such as religion, association without any form of discrimination thereby making it the correct choice.
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The full question:
civil refer to individual rights, such as the freedom of speech and religion, while civil refer to equality under the law for different groups such as racial or religious minorities. true/ false
NEED to turn in TONIGHT!
For the reaction: Ti(s)+2F2(g)→TiF4(s)
compute the theoretical yield of the product (in grams) for each of the following initial amounts of reactants.
b. 2.5 g Ti, 1.5 g F2
c. 0.239 g Ti, 0.287 g F2
The theoretical yield of the product (in grams) for each of the following initial amounts of reactants is 2.45 grams and 0.47 grams.
According to Stoichiometry
n = m ÷ M
n = number of moles m = mass (grams)M = molecular mass (g/mol)Atomic massa. Ti (s) + 2 F₂ (g) → TiF₄ (s)
m Ti = 2.5 gb. Ti (s) + 2 F₂ (g) → TiF₄ (s)
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In the combustion of hydrogen gas, hydrogen reacts with oxygen from the air to form water vapor.
hydrogen+oxygen⟶water
If you burn 28.8g of hydrogen and produce 258g of water, how much oxygen reacted?
Answer:
Below
Explanation:
If the used 28,8 g of hydrogen reacted completely....the rest of the 258 must be the oxygen
258 - 28.8 = 229.2 gm of Oxygen
According to the stoichiometry of the mentioned chemical equation, 230.4 g of oxygen reacts with 28.8 g hydrogen.
What is chemical equation?Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.
A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .
The first chemical equation was put forth by Jean Beguin in 1615.By making use of chemical equations the direction of reaction ,state of reactants and products can be stated. In the chemical equations even the temperature to be maintained and catalyst can be mentioned.
According to the stoichiometry, 4 g hydrogen react with 32 g oxygen thus 28.8 g hydrogen requires 28.8×32/4=230.4 g oxygen.
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A solution contains both iron(II) and iron(III) ions. A 50.00-mL sample of the solution is titrated with 35.0 mL of 0.0280 M KMnO4, which oxidizes Fe2+ to Fe3+. The permanganate ion is reduced to manganese(II) ion. The equation for this reaction isAnother 50.00-mL sample of the solution is treated with zinc, which reduces all the Fe31 to Fe21. The equation for this reaction isThe resulting solution is again titrated with 0.0280 M KMnO4; this time 48.0 mL is required. What are the concentrations of Fe2+ and Fe3+ in the solution?
The concentrations of Fe2+ and Fe3+ in the solution are [Fe2+] = 0.0196 M and [Fe3+] = 0.0269 M, respectively.
Let's assume the initial concentrations of Fe2+ and Fe3+ ions in the solution to be [Fe2+] and [Fe3+], respectively.
The first titration (with 35.0 mL of 0.0280 M KMnO4) oxidizes Fe2+ ions to Fe3+ ions.
n(Fe2+) = (35.0 mL) x (0.0280 M) = 0.980 mol
The second titration (with 50.00 mL of the solution after zinc reduction) gives the number of moles of Fe3+ ions remaining in the solution.
n(Fe3+) = (0.0280 M) x (48.0 mL) = 1.344 mol
Using the mole ratio, we can now find the initial concentrations of Fe2+ and Fe3+ ions in the solution:
[Fe2+] = n(Fe2+) / (50.00 mL) = 0.980 / (50.00 mL) = 0.0196 M
[Fe3+] = n(Fe3+) / (50.00 mL) = 1.344 / (50.00 mL) = 0.0269 M
Titration is a laboratory technique used in chemistry to determine the concentration of an unknown substance. It is a type of analytical method that involves adding a known volume of a standard solution (titrant) to a solution of the unknown substance (analyte) until a reaction is complete and the end-point is reached. The end-point is the point at which a change in color or some other observable change indicates that the reaction is complete.
The end-point is used to determine the exact amount of titrant required to react with the analyte and to calculate the concentration of the unknown substance. The results of a titration are used in various applications such as determining the purity of substances, monitoring the production of chemical products, and determining the effectiveness of certain chemical reactions. Titration is a simple, cost-effective, and widely used technique in the field of analytical chemistry.
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A sample of ethanol containing 0.35 mol is cooled from 125.0cC to 62.0oC. Given the data below, select all the options that correctly reflect how to calculate the total heat change for the process.Boiling point for ethanol at 1 atm = 78.5oC; ΔHovap = 40.5 kJ/mol; Cliq = 1130 J/mol⋅oC; and sgas = 65.9 J/mol⋅oC
The total heat change for the process is : ΔH = -45. 6 kJ
The total heat change for the process can be calculated using the following equation:
Where m is the mass in moles, and ΔHovap is the enthalpy of vaporization.
In this case, the total heat change can be calculated as follows:
ΔH = -40. 5 kJ / mol + 0. 35 mol(1130 J/ mol⋅ oC)(62. 0oC - 125. 0oC) + 0. 35 mol(65. 9 J/ mol ⋅ oC)ln(1/1)
ΔH = -45. 6 kJ
Ethanol is an organic compound, also known as ethyl alcohol or grain alcohol. It is a clear, colorless liquid with a characteristic pleasant odor and a burning taste. It is highly flammable, and is usually derived from crops such as corn, wheat, or sugar cane. It is commonly used as a fuel, a solvent, and an ingredient in many alcoholic beverages.
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You notice that the majority of the electrons in NaCl spend their time around the chlorine. You also notice that the electrons in H2 are evenly distributed among two atoms. Which two types of bonds are represented in these molecules?
a. covalent bonds in NaCl; ionic bonds in H2
b. ionic bonds in NaCl; ionic bonds in H2
c. covalent bonds NaCl; covalent bonds in H2
e. ionic bonds in NaCl; covalent bonds in H2
The types of bonds that are represented by those molecules are ionic bond (in NaCl) and covalent bonds (in H₂).
In general, there are three ways that molecules can form atomic bonds:
Ionic bondAn ionic bond involves the electrostatic attraction between oppositely charged ions/two atoms with different electronegativities. An example is the bond between Na⁺ and Cl⁻ to form NaCl.
Covalent bondA covalent bond is where two or more atoms share their valence electrons. An example is the bond between two hydrogen (H) atoms to form H₂.
Metallic bondA metallic bond is where the bonding electrons are delocalized over a lattice of atoms.
Attached below is an image of a covalent bond that is forming the compound H₂. In it, two hydrogens (H) atoms share each of their electrons.
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What is the mass of 0.80 moles of Mg?
The mass of 0.80 moles of Mg are 19 gram.
What do you mean by the molar mass ?The term molar mass (M) is defined as the mass of a chemical compound divided by its total amount of substance measured in moles.
It is defined as MB = m/nB, where m is the total mass of a sample of pure substance and nB is the amount of substance B in moles.
Given:
0.80 moles of Mg = ?
Convert to "g" (units of "g" ; that is "grams" of "Mg" ).
The molar mass of "Mg" is 24.305 g / mol
0.80 mol × (24.305 g Mg / 1 mol Mg) = ? g Mg ??
we have,
(0.80 × 24.305) g of Mg
= 19.444 gram
Round this number to 2 (two) significant figures therefore, there are 2 (two) significant figure in our given amount of Mg " 0.80 mol" ;
= 19 gram
Thus, the mass of 0.80 moles of Mg are 19 gram.
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Kindly help me with the number 2 answer
The number of moles of nitrogen, N in 65 moles of Pb(NO₃)₄ is 260 moles
How do I determine the number of mole of N?We'll begin by obtaining the number of mole of N in one mole of Pb(NO₃)₄. Details below:
From the formula of Pb(NO₃)₄, we can see that there are 4 moles of N in 1 mole of Pb(NO₃)₄
With the above information, we can determine the number of mole of N in 65 moles of Pb(NO₃)₄. This is illustrated below:
1 mole of Pb(NO₃)₄ contains 4 moles of N
Therefore,
65 mole of Pb(NO₃)₄ will contain = (65 moles × 4 moles) / 1 mole = 260 moles of N
Thus, we can conclude from the above calculation that the number of mole of N is 260 moles
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which molecules have dipole-dipole forces? check all that apply. which molecules have dipole-dipole forces?check all that apply. ch3cl ccl4 hcl
All three molecules [tex]CH_3Cl, HCl, CCl_4[/tex] have dipole-dipole forces acting on them.
[tex]CH_3Cl[/tex] or chloromethane- Carbon provides the positive end of the dipole and Cl being more electronegative forms the negative end of the dipole. The bond is slightly polar in nature.
Dipole-dipole forces are formed in [tex]HCl[/tex] or hydrochloric acid because the chlorine atom holds a slightly value of AH charge whereas the charge on hydrogen is slightly value of AH. Because of this force of attraction, a small dipole-dipole force acts between two HCl molecules.
Intermolecular forces of attraction between atoms of [tex]CCl_4[/tex] or carbon tetrachloride is also known as the London Dispersion Force of Attraction. Attraction takes place between temporary dipoles in the structure.
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Complete Question:
which molecules have dipole-dipole forces among the given options?
1) [tex]CH_{3}Cl[/tex]
2) [tex]CCl_4[/tex]
3) [tex]HCl[/tex]
check all that apply.
select the correct conversion factor for each step in the following roadmap for a substance with a density of 1 g/ml. mass mass volume
A conversion factor is a number used to change one set of units to another, by multiplying or dividing. To convert kilograms in grams and litres in millilitres, multiply with 1000 it is also known as unit conversion.
So, when converting from kilogrammes to grammes, we must first multiply by a conversion factor with kilogrammes in the denominator. As a result, kilogrammes will cancel and Graham's will be in the denominator. So the fact that there are 1000 grammes in one kilogramme is the equality that makes this true. So 1000 g and one kilogramme would be our first conversion, and kilogrammes would then cancel. To convert to millimetres, use the density conversion with one gramme in the denominator and one millimetre in the numerator because grammes will cancel.
This will give us a millilitre answer. So the first conversion we'd like to use is 1000 g over one kilogramme. So that goes in the first box, and the second box converts mass and grammes to volume. Do you prefer the one mil leader over the one g . These are the conversion factors you would need to use to complete these two steps from kg to ml.
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If the Rf of a compound is 0.860 and the compound moved 5.34 cm, calculate the distance the solvent front moved.
Distance the solvent front moved = Distance moved by compound / R f, Distance the solvent front moved = 5.34 cm / 0.860, Distance the solvent front moved = 6.21 cm.
How much advance should the solvents front be permitted to make?The bulk solvent should never climb above the line we drew.Allow the solvent to be drawn up the plate by capillary action until it is about 1 cm from of the end.Never permit the solvent to move all the way to a plate's edge.As soon as the plate is removed, make a pencil mark over the solvent front.
How Describe the solvent distance?The retention value in chromatography is used to calculate the solvent distance (Rf value). This stands out among all solvents.By contrasting the retention values of known samples, the unidentified solvent can be identified.
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move to the safety shower if you spill hazardous chemicals on your skin or clothing . stand under the shower and pull the lever. remove clothing and continue flushing the area for
Take he safety shower Remove your shirt and any other items of clothes from the area where the chemical was present.
When a dangerous chemical comes into touch with the skin, it has the potential to harm the body. Many dangerous compounds have the potential to enter the body through the skin.
As a precaution, you must remove your lab coat, shirt, and any other items that came into touch with the dangerous chemical once it has already soaked into your lab coat. Doing so will prevent the chemical from entering your body via the skin. Some of these substances can harm the skin directly, thus it is important to avoid them.
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When an action potential occurs, sodium gates open, resulting in the inside of the cell becoming more negative relative to the outside.
When a voltage change crosses the threshold, the wattage na+ in the axonal barrier will open. The entry of sodium is responsible for the growing component of the nerve impulse, but the influx of ions also depolarizes nearby axonal regions. When the depolarization approaches the threshold, the nerve impulse descends the axon.
Is depolarization advantageous or detrimental?Depolarization occurs when an electrical shift occurs in a nerve cell. The majority of cells have a negative charge in comparison to their environment. Through the brief process of depolarization, the cell's internal charge changes from negative to positive.
Does depolarization occur when sodium channels are opened?Depolarization, a rapid increase in potential that occurs in neurons, is an all-or-nothing process that is started by the opening of sodium within the plasma membrane's ion channels. Repolarization, the ensuing restoration to the resting potential, is facilitated by the activation of na / k channels.
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which of the following produce an alkaline / acid h2s (k/a h2s) reaction on tsi and an k/k h2s on lia? a. edwardsiella b. proteus vulgaris c. salmonella d. citrobacter e. providencia f. morganella morganii
Based on the given information, the microorganisms that produce an alkaline/acid H2S reaction on TSI (Triple Sugar Iron) and a K/K H2S reaction on LIA (Lysine Iron Agar) are given here.
a. Edwardsiella - Alkaline/Acid H2S on TSI and K/K H2S on LIA
c. Salmonella - Alkaline/Acid H2S on TSI and K/K H2S on LIA
d. Citrobacter - Alkaline/Acid H2S on TSI and K/K H2S on LIA
e. Providencia - Alkaline/Acid H2S on TSI and K/K H2S on LIA
f. Morganella morganii - Alkaline/Acid H2S on TSI and K/K H2S on LIA
These microorganisms produce hydrogen sulfide (H2S), which reacts with the iron in the TSI and LIA media to produce a characteristic change in the media's pH. The change in pH can be either alkaline or acidic, depending on the microorganism. A K/K H2S reaction on LIA indicates the presence of H2S in the bacterial colony, while a K/A H2S reaction on TSI indicates both the presence of H2S and an alkaline reaction.
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⁷ 168 g of iron reacts with excess oxygen to form 232 g of an oxide of iron. iron + oxygen H ratio iron oxide a. Calculate the mass of oxygen in the iron oxide. b. Calculate the males of oxygen in the oxide. c. Calculate the moles of iron in the iron oxide. d. Calculate the ratio of the iron to oxygen to give the formula of this oxide of iron. formula
The mass of the oxygen that reacted is 70.4 g.
What is the reaction of iron and oxygen?
The reaction between iron and oxygen is called rusting and is a oxidation process. The balanced chemical equation for the reaction is:
4 Fe + 3 O2 -> 2 Fe2O3
Number of moles of iron = 168 g/56 g/mol = 3 moles
Number of moles of iron III oxide = 232 g /160 g/mol
= 1.45 moles
The mass of the oxygen that reacted is;
If 3 moles of oxygen produces 2 moles of oxide
x moles of oxygen would produce 1.45 moles ofn the oxde
x = 3 * 1.45/2
= 2.2 moles
Mass of the oxygen = 2.2 moles * 32 g/mol
= 70.4 g
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When 3,3-dimethylbut-1-ene is treated with HBr alone, the major product is 2-bromo-2,3-dimethylbutane. When the same alkene is treated with HBr and peroxide, the sole product is 1-bromo-3,3-dimethylbutane. Explain these results by referring to the mechanisms.
It yields 2-bromo-2,3-dimethylbutane as the final product. The proton is added to the radical process after the bromine anion. 1-bromo-3,3-dimethylbutane.
Which of the following types of chemicals results from an alkene's hydration?1 Response. Alcohol is created when alkene and water interact. Electrophilic addition is the reaction at hand. The double bond of the carbon in an alkene with a high electron density is attacked by water.
What do examples of hydration of alkenes mean?Alkene Hydration Example: ethanol is produced by the hydration of ethylene. An alkene with the condensed structural formula H2C=CH2, ethylene is also known as. The double bond (C=C) in the ethene molecule is the active site.
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(q011) water can be used to dilute and clean up oil paint, because oil uses a natural binder: linseed oil, which is made from flax plants. T/F
False. Water cannot be used to dilute and clean up oil paint because oil and water do not mix.
The pigments in oil paint are held together by a natural binder, such as linseed oil, which is derived from flax plants. Water cannot dissolve this binder since it is not soluble in water. As a result, using water to remove oil paint might cause streaks and smudging rather than really removing the paint.
Solvents like turpentine or mineral spirits are frequently used to remove oil paint. These solvents have the ability to break down the linseed oil binder, making it simple to clean brushes, palettes, and surfaces of paint. Solvents can be combustible and emit toxic fumes, thus it is crucial to handle them carefully. Using solvents in well-ventilated spaces or while wearing appropriate respiratory protection is also recommended.
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Which of the following is a type of crystalline solid? Select all that apply.
Select all that apply:
O metallic
O ionic
O covalent network
O molecular
Crystalline solids often fall into one of four categories. These categories include network covalent solids, ionic solids, metallic solids, and molecular solids.
Which one of the following describes crystalline structure?In contrast to its non-crystalline form, a crystalline structure comprises highly tightly packed atoms, leading to a high density of the material.
How many different kinds of crystalline solids exist?Four categories of crystalline solids exist in solid ions Electrostatic attractions keep positive and negative ions together as they develop. They stand out in the solid state due to their extremely high melting temperatures, brittleness, and poor conductivity.
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calculate the ph of a 0.010 m solution of ch3co2h. the ka of ch3co2h is 1.8 x 10-5. report your answer to two decimal places without units.
The pH of a 0.010 M solution of CH3COOH (acetic acid) can be calculated using the concentration of the hydrogen ion (H+) and the Ka value of the acid. The answer to two decimal places, the pH of the solution is 4.75.
pH Value is a measure of the acidity or alkalinity of a solution. It is expressed on a scale of 0 to 14, with 7 being neutral. A solution with a pH less than 7 is considered acidic and a solution with a pH greater than 7 is considered alkaline or basic. The pH value is an important factor in many biological, chemical, and environmental processes.
In industrial processes, pH values are often monitored and controlled to ensure that reactions occur under optimal conditions. For example, the pH of water used in boilers must be maintained within a specific range to prevent corrosion and scale buildup.
The pH value is a simple but powerful tool for measuring and understanding the acidity or alkalinity of a solution. It provides critical information for a wide range of applications, from health and agriculture to industrial processes and environmental monitoring.
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what is the final concentration when 275mL of water is added to 155mL of 0.130M KCl?
Answer:
Below
Explanation:
.130 * .155 = initial number of moles of KCL
then add .275 liter of water bringing total volume to .275 + .155 = .430 Liter
moles of KCl divided by volume = concentration
.130*.155 / (.430) = .047 M
Which of the following metals would be oxidized by water and oxygen in an acidic environment but not in basic environment? [answer A, B,C,D] A- Cr B- Hg C- Zn D- Cu'
The metal that would be oxidized by water and oxygen in an acidic environment but not in basic environment is Zinc (Zn). The answer is C.
Zinc reacts with water and oxygen to form zinc hydroxide and zinc oxide in a basic environment. However, in an acidic environment, zinc ions will be reduced to zinc metal by the hydrogen ions (protons) in the solution, rather than being oxidized. This is because the hydrogen ions are strong enough to reduce the zinc ions, while in a basic environment, the hydroxide ions are not strong enough to reduce the zinc ions and instead they oxidize the zinc to form zinc hydroxide.
On the other side, Chromium (Cr), Mercury (Hg), and Copper (Cu) can be oxidized by water and oxygen in both acidic and basic environments.
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What is the molecular formula for a compound that is 34.31% sodium, 17.93% carbon, 47.76% oxygen, and has a molar mass of 134.00g?
The molecular formula for the compound is Na2CO3.
What is the molecular formula?A molecular formula is a representation of a chemical compound that shows the types and numbers of atoms in a single molecule of the substance. It is typically written in the form of "CxHyOz", where "C" stands for carbon, "H" stands for hydrogen, and "O" stands for oxygen. formula, which shows the simplest whole-number ratio of atoms in a compound.
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Consider the reaction:
2A (g) + 3 B (g) → 2 C (g) ΔHrxn = +254.3 kJ
What will be the enthalpy change (in kJ) if 0.812 mol B reacts in excess A?
Answer:
The enthalpy change (in kJ) if 0.812 mol B reacts with excess A is +202.3 kJ. This can be calculated by first determining the number of moles of A that are needed to react with 0.812 mol B. Since the mole ratio of A to B is 2 : 3, the number of moles of A needed is 0.812 mol B x (2/3) = 0.5413 mol A. Then, the enthalpy change can be calculated as 0.5413 mol A x (254.3 kJ/2 mol A) = 202.3 kJ.
which of the following products would be produced from hydroboration/oxidation of 1-pentyne? e only a and b only b and e only a only
The products of the hydroboration/oxidation of 1-pentyne are A and B only. A is the primary product, which is 2-methyl-2-pentanol, and B is the secondary product, which is 2-ethyl-1-pentanol.
When 1-pentyne is subjected to hydroboration/oxidation, a boron atom is added to the double bond, forming a new tertiary carbon center. The boron atom is then oxidized to form a hydroxyl group, which is the primary product (A).
The secondary product (B) is formed when the tertiary carbon center undergoes an E2 elimination, resulting in the formation of an ethyl group.
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