A quadratic function has A) straight lines that do both increase, decrease or stay constant on the same graph. B) curved lines that only increase or decrease. C) curved lines that do both increase and decrease on the same graph. D) straight lines that only increase or decrease. E) straight lines that do both increase and decrease on the same graph

If the point N lying on the Line segment MP, divides MP such that the ratio of MN to NP is 6 to 1, and the coordinates of M(-13, 20) and P(1-1), then the coordinates of "N" is

As per the question statement, N lying on the Line segment MP, divides MP such that the ratio of MN to NP is 6 to 1.

We are required to find out the coordinates of "N".

To solve this question, we need to know the formula to calculate the coordinates of a point (Say "c") that divides a line segment AB in the ratio of (m:n).

The formula goes as:

Abscissa of c [tex](x_{3})=\frac{mx_{2}-nx_{1} }{m-n}[/tex]

and, Ordinate of c [tex](y_{3})=\frac{my_{2}-ny_{1} }{m-n}[/tex]

where, [tex](x_{1}, y_{1})[/tex] are the coordinates of point A, while

[tex](x_{2}, y_{2})[/tex] are the coordinates of point B.

Using our given data in the above formulae, we get

Abscissa of N =  [tex]\frac{(6*1)-[1*(-13)]}{6-1} =\frac{6-(-13)}{5}=\frac{6+13}{5}=\frac{19}{5}[/tex]

And, Ordinate of N = [tex]\frac{[6*(-1)-(1*20)}{6-1} =\frac{(-6)-20}{5}=\frac{-(20+6)}{5}=\frac{-26}{5}[/tex].

Hence, our concerned point N = [tex](\frac{19}{5}, \frac{-26}{5})\\[/tex].

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Answer:

Step-by-step explanation:

To get your answer, you would want to use the expression -3.5/60. So your answer will be -0.058.

To solve an linear equation we need to use BODMAS rule.

Here the given equation is;

(x+8-x+8)

We know very well that if two like numbers have opposite sign and are added then it gets cancelled and gives zero as the result.

Similarly, here x and -x gets cancelled and we get 16 as the result.

If we get the solution of an equation as zero then we may say that the equation has no real solution. That means there are no values of the unknown which will complete the equation.

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The area of the region inside the rectangle that surrounds the square is; 162 square meters

We are given that;

Side length of square = 6 m

Width of rectangle = 11 m

Length of rectangle = 18m

Thus;

Area of rectangle = width * length = 11 * 18 = 198 square meters

Area of square = side * side = 6 * 6 = 36 square meters

Area of region inside rectangle not inside square = (area of rectangle) - (area of square) = 198 - 36 = 162 square meters

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Answer:

domain: {3,6,9}

range: {1,4,9}

Step-by-step explanation: take the x values in increasing order for domain and the y values in increasing order for range. Do not repeat values.

The solutions of the equations of the situation can be:

z = 1 , y = 5, x = 4

z= 2 , y = 3, x = 5

z=3 , y = 1, x = 6

z = 0 , y = 7, x =3

The question can be expressed as a equation

6 x + 8 y + 10 z = 84

also, x + y + z = 10

⇒ x = 10- y - z

Putting it in first equation,

6(10 - y - z ) +8y + 10z = 84

⇒ 60 +2y + 4z = 84

⇒2(y + 2z ) = 14

⇒ y + 2z = 7

Now putting

z = 1 , we get y = 5,

z= 2 , y = 3

z=3 , y = 1

z = 0 , y = 7

So, only 4 possible solutions.

Therefore, there can only be 4 possible solutions for the equations.

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Answer:

  6 quarts

Step-by-step explanation:

You want to know the number of quarts of 100% antifreeze to add to 6 quarts of 20% antifreeze to make a 60% solution.

Let x represent the number of quarts of 100% antifreeze added to the solution. Then the total amount of antifreeze in the mixture is ...

  20%(6) +100%(x) = 60%(6 +x)

Simplifying the equation, we have ...

  1.2 +x = 3.6 +0.6x

  0.4x = 2.4 . . . . . . . . . subtract 0.6x+1.2 from both sides

  x = 6 . . . . . . . . . . divide by 0.4

6 quarts of pure antifreeze must be added.

Product Y would be allocated 20% of the machine setups cost

Product Z  would be allocated 80% of the machine setups cost

What is activity-based costing?

Activity-based costing is a costing method where overhead cost of production are allocated based on the cost driver responsible for the overhead rather than using the plantwide overhead rate based on direct labor-hours.

In this case, we need to first of all determine the machine setups cost per per setups, based on the fact there 300 setups for both products Y and Z

machine setup  cost per setup=Machine setups cost/Number of setups

Machine setups cost=$180,000

Number of setups=300

machine setup  cost per setup=$180,000/300

machine setup  cost per setup=$600

Total set up cost for product Y=60*$600=$36000

Total set up cost for product Y as %=$36,000/$180,000=20%

Total set up cost for product Z=240*$600=$144,000

Total set up cost for product Z as %=$144,000/$180,000=80%

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The limit of the composite function is given as follows:

lim x->7 f(g(x)) = 2.

A limit is given by the value of function f(x) as x tends to a value.

From the graph of g(x), we have that the lateral limits at x = 7 are given as follows:

[tex]\lim_{x \rightarrow 7^-} = \lim_{x \rightarrow 7^+} = -2[/tex]

Hence:

lim x->7 f(g(x)) = f(lim x->7 g(x)) = f(-2).

Looking at the graph of f(x), we have that:

f(-2) = 2.

Hence:

lim x->7 f(g(x)) = 2.

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Answer: N * (n+7) = n^2 + 7n

Step-by-step explanation:

This equation would be the number, n, times n+7 because n+7 is 7 more than n. To do this, you have an equation like this:

N * (N+7). You would then do distributive property, and n*n would be n squared, and n*7 would be 7n. This would give you a combined answer of n squared + 7n, or n^2 +7n.

Answer:

You either lose everything or gain everything (losing is more probable :) )

Step-by-step explanation:

Greetings from Brasil...

Checking the side limits of the function f(x), we find that they are equal, so there is a limit of f(x) as x approaches 4

check the attachment

Answer:

[tex]=4620000x[/tex]

Step-by-step explanation:

[tex]=1000000\cdot \:4.62x[/tex]
[tex]=4620000x[/tex]

Answer:

4620000

Step-by-step explanation:

4.62x10^6

1000000x4.62

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\mathsf{16 \dfrac{40}{50}}[/tex]

[tex]\mathsf{= \dfrac{16\times50 + 40}{50}}[/tex]

[tex]\mathsf{= \dfrac{800 + 40}{50}}[/tex]

[tex]\mathsf{= \dfrac{840}{50}}[/tex]

[tex]\mathsf{= 840\div50}[/tex]

[tex]\mathsf{= 16.8}[/tex]

[tex]\huge\textbf{Therefore, your answer should be:}[/tex]

[tex]\huge\boxed{\mathsf{16.8}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

The Lagrangian is

[tex]L(x,y,\lambda) = x^2 + y^2 - \lambda (x + y - 1)[/tex]

Find its critical points.

[tex]\dfrac{\partial L}{\partial x} = 2x - \lambda = 0 \implies x = \dfrac\lambda2[/tex]

[tex]\dfrac{\partial L}{\partial y} = 2y - \lambda = 0 \implies y = \dfrac\lambda2[/tex]

[tex]\dfrac{\partial L}{\partial\lambda} = -(x+y-1) = 0 \implies x + y = 1[/tex]

From the first two conditions, [tex]x=y[/tex], so

[tex]x + y = 2x = 1 \implies x = y = \dfrac12[/tex]

At the point (1/2, 1/2), compute the Hessian determinant of [tex]f(x,y)[/tex].

[tex]H(x,y) = \begin{bmatrix} \dfrac{\partial^2f}{\partial x^2} & \dfrac{\partial^2f}{\partial x \partial y} \\\\ \dfrac{\partial^2f}{\partial y\partial x} & \dfrac{\partial^2f}{\partial y^2} \end{bmatrix} = \begin{bmatrix}2&0\\0&2\end{bmatrix}[/tex]

[tex]H(x,y)[/tex] is positive definite for all [tex]x,y[/tex], which indeed indicates a local minimum at (1/2, 1/2), so that

[tex]\min\left\{x^2+y^2 \mid x+y=1\right\} = f\left(\dfrac12,\dfrac12\right) = \dfrac14+\dfrac14 = \boxed{\dfrac12}[/tex]

Answer: by doing math

Step-by-step explanation:

Answer:

52/129

Step-by-step explanation:

Answer:

7561413

Step-by-step explanation:

6561413+1000000=    Equals Calculator Answer/////7561413

Answer:

7561413

Step-by-step explanation:

The calculator it equals 7561413

Answer:

greatest -( 9/36, -21/28, -7 )- smallest

Answer:

9/36

-7

-21/28

Step-by-step explanation:

You actually had them in the correct order

Answer: -30

Step-by-step explanation:

Answer:

the answer would be -30!!!

Step-by-step explanation:

i took the quiz.

The missing coordinate can either be - 16 or 8.

Let the missing coordinate be x.

Now, we know that the distance between (-3, -4) and (6, x) is 15.

Using the distance formula, we get that:

Distance² = (x₂ - x₁)² + (y₂ - y₁)²

Substituting the values in the formula, we get that:

15² = (6 + 3)² + ( x + 4)²

225 = 9² + x² + 16 + 8 x

225 = 81 +x² + 16 + 8 x

225 = x² + 8 x + 97

x² + 8 x - 128 = 0

x² + 16 x - 8 x -128 = 0

x ( x + 16) - 8 ( x + 16) = 0

(x + 16)(x - 8) = 0

x = -16 or x = 8.

Therefore, the missing coordinate can either be - 16 or 8.

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The base-ten numeration system is the system that utmost of the world uses moment. Place value refers to the value of each number in a number. The English language is a transnational language.

What is the base ten number system, place value?

The base-ten numeration system is the system that utmost of the world uses moment. No one knows exactly why the number ten was chosen as the base for this system, but it's theorized that it's due to the number of fritters that humans retain. Fingers are veritably fluently assessable as counting tools. The base-ten numeration system consists of ten integers( 0, 1, 2, 3, 4, 5, 6, 7, 8, 9), and groups figures into ten.

     2. Understanding Place Value -

Place value refers to the value of each number in a number. For illustration, the number 753 has three" places" or columns each with a specific value. In this three-number number, the 3 is in the" bones " place, the 5 is in the" knockouts" place, and the 7 is in the" hundreds" place.

Beginning ideas of Place Value and Base Ten:

In other words, the 3(three) represents three single units, so the value of this number is three. The 5(five) is in the knockout place, where values increase by multiples of 10(ten). So, the 5(five) is worth (5)five units of 10(ten), or 5(five) x 10(ten), which equals 50(fifty). The 7(seven) is in the hundreds(100) place, so it represents seven units of 100(hundred), or 700(seven hundred).

Problems Faced by Students in Speaking the English Language -

The English language is a transnational language. It's a demand of the moment’s world. For surviving in society, people have to understand and speak the English language easily.

In this world, you go far and wide people can speak the English language or indeed understand the English language.

The English language plays a lesser part for the people in a society. The English language is an important subject for people whose English language isn't their native language.

The base-ten numeration system is the system that utmost of the world uses moment.

Place value refers to the value of each number in a number.

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Answer: no 25 is a perfect square

Step-by-step explanation:

Distance of upper bond and lower bond is 120,000 and 150,000 centimeter

Given:

Number of steps walk = 1500 steps

Each step count = 90 centimeters

Correction in each step = 10 cm nearest

Find:

Lower bound and upper bound for d

Computation:

Lower bound step length = 90 - 10

Lower bound step length = 80 centimeters

Upper bound step length = 90 + 10

Upper bound step length = 100 centimeters

Lower bound d = 1500 × 80

Lower bound d = 120,000 centimeters

Upper bound d = 1500 × 100

Upper bound d = 150,000 centimeters

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Answer:

4    + 4√2

Step-by-step explanation:

[tex]CD=\sqrt{\left( 4-4\right)^{2} +\left( -5 - (-1)\right)^{2} } \\\\\\ =\sqrt{\left( 0\right)^{2} +(-4)^{2} }\\\\\\\ = \sqrt{16 }\\\\\\ =4[/tex]

[tex]DE=\sqrt{\left( 2-4\right)^{2} +\left( -3 - (-5)\right)^{2} } \\\\\\ =\sqrt{\left(-2\right)^{2} +(2)^{2} }\\\\\\\ = \sqrt{8 }\\\\\\ =2\sqrt{2}[/tex]

[tex]\text{\bf{EC} $=\sqrt{\left( 4-2\right)^{2} +\left( -1 - (-3)\right)^{2} } \\\\\\ =\sqrt{\left( 2\right)^{2} +(2)^{2} }\\\\\\\ = \sqrt{8 }\\\\\\ =2\sqrt{2}$}[/tex]

Perimeter (∆CDE) = CD + DE   + EC

                             = 4    + 2√2 + 2√2

                             = 4    + 4√2

                             ≈ 9.7

The numbers that are equivalent to two and seven fifteenths are; thirty-seven fifteenths, 2.46 repeating where the 6 is repeating

We want to find  the numbers that are equivalent to two and seven fifteenths. This fraction is a mixed fraction and can be expressed as;

2⁷/₁₅

Converting this to an improper fraction gives us;

37/15

Now, in the first mixed fraction, we can turn the fraction into decimal like this; 2 + 7/15 = 2 + 0.46666 = 2.466666....

Thus, looking at the given options, the only correct option is;

C: thirty-seven fifteenths, 2.46 repeating where the 6 is repeating

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The quotient of A = - 210 and B = - 15 is 14.

The Euclid's Division Lemma says when a number 'a' is divided by a number 'b' gives the quotient to be 'q' and the remainder to be 'r' then the following relation -> a = bq + r exists, where 0 ≤ r < b.

Dividend [a] = Divisor [b] × Quotient [q] + Remainder [r]

Given two numbers A = - 210 and B = - 15

The resultant quotient when A is divided by B can be calculated using Euclid's division lemma. Initially, we will assume remainder [r] = 0.

If the quotient is in decimals, we will change the remainder according to it else if the quotient is a whole number, the remainder will remain 0.

Using Euclid's division lemma -

Dividend [a] = Divisor [b] × Quotient [q] + Remainder [r]

- 210 = - 15 x q + 0

- 210 = - 15 x q

q = - 210 / - 15 = 14

Since, the quotient is a whole number, the remainder will remain zero.

Therefore, the quotient of A = - 210 and B = - 15 is 14.

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Answer:

Given as at the end of the proof flowchart we are only left with one unknown m∠3, the logical conclusion is that we're proving that m∠3 = 180° - 54° = 126°

Answer:2/3

Step-by-step explanation:

The equation in slope-intercept firm for this line is y = -4/3x - 13

Linear equations are equations that have constant average rates of change. Note that the constant average rates of change can also be regarded as the slope or the gradient

The given parameters are

Slope, m = -4/3

Point (x1, y1) = (-6, -5)

The linear equation is calculated as

y = m(x - x1) + y1

So, we have

y = -4/3(x + 6) - 5

Open the bracket

y = -4/3x - 8 - 5

Evaluate the difference

y = -4/3x - 13

Hence, the equation in slope-intercept firm for this line is y = -4/3x - 13

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