A mathematician used data of the average gas mileage of new vehicles sold in Greece for the years 2012 to 2022 to create a quadratic function that models the data, where x is the number of years since 2010 and y is the average gas mileage, in miles per gallon (mpg). Some of the values are shown in the table of values.

During what years was the average gas mileage for new vehicles sold in Greece decreasing?​

Please help me, I will have a test based on this question so please help me!!!!

3x + 4 = 19

3x = 19-4

3x = 15

[tex]x = \frac{15}{3} \\ [/tex]

x = 5

Answer:  57 1/3

Step-by-step explanation:

Area = (height * base) divided by 2

A = (b*h)/2

10 3/4 times 10 2/3 = 114 2/3

114 2/3 divided by 2 is 57 1/3

Answer: 57 1/3

Area of a triangle= 1/2*base*height

A=1/2* 10 3/4* 10 2/3

1/2* 10 3/4= 5 3/8

5 3/8 * 10 2/3 =57 1/3

Step-by-step explanation: Hope this helps!! :)) Mark me brainliest ! :))

Answer:

x=9

y=15

Step-by-step explanation:

Since it is a parallelogram, there is a property of a parallelogram that says that opposite sides are congruent/equal. So x would equal to 9 and y is equal to 15

Answer:

Step-by-step explanation:

X = 9

Y = 15

Answer:

B. No solution

Step-by-step explanation:

The output of an absolute value function can never be a negative number.

Absolute value is the distance between a number |x| and 0 and that distance will always be positive.

Answer: B: No solution

Step-by-step explanation:

Answer: x3

Step-by-step explanation:

The sample space of possible codes for the wireless garage door opener is 4096.

(a) The sample space for this batch of printed circuit boards would be 98 total boards, ordered such that the non-defective boards are first (90 boards), followed by minor defects (8 boards) and major defects (0 boards). The total number of ordered samples is given by the formula: nPr = n!/(n-r)! where n is the total number of boards in the batch and r is the number of boards selected from the batch. In this case, n = 98 and r = 2, making the total number of ordered samples 9703.

(b) The sample space for this batch of printed circuit boards would be 99 total boards, ordered such that the non-defective boards are first (90 boards), followed by minor defects (8 boards) and major defects (1 board). The total number of ordered samples is given by the formula: nPr = n!/(n-r)! where n is the total number of boards in the batch and r is the number of boards selected from the batch. In this case, n = 99 and r = 2, making the total number of ordered samples 9801.

For the wireless garage door opener, the code is determined by the up or down setting of 12 switches. This means that each switch can either be up or down for a total of 2 possible settings for each switch. The total number of possible codes is given by the formula [tex]2^12[/tex], which is equal to 4096. This is because each switch has 2 possible settings, and when multiplied by 12 switches, there are [tex]2^12[/tex] possible combinations. Therefore, the sample space of possible codes for the wireless garage door opener is 4096.

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The solution to the given inequality is b ≤ 1.

Inequalities are defined as those expressions which are connected by inequality signs like >, <, ≤, ≥.

Given inequality expression is,

7 (b - 1) / b ≤ 0

(7b - 7) / b ≤ 0

(7b / b) - (7 / b) ≤ 0

7 - 7/b ≤ 0

Adding 7/b on both sides,

7 ≤ 7/b

Multiplying b on both sides,

7b ≤ 7

b ≤ 1

Hence the value of b is b ≤ 1.

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Answer:

-12 + 7 = -5

Step-by-step explanation:

An example of this equation could be if you owe someone $12 and then receive $7 from them, your debt to them would be reduced to $5. Another example could be if you have 12 apples and someone gives you 7 apples, you would have a total of 19 apples.

Answer:

I don't really understand what you mean, maybe is this?

Step-by-step explanation:

5 halves of 14 = 5/14

6 halves of 14 = 6/14

3 halves of 14 = 3/14

Answer:

5+6=11+1=12

Step-by-step explanation:

what is 12 halves? 6

try 13 pairs of flippers

It’s in between 10 and 15

1. The price elasticity of demand for pen is 0.5

2. The cross price elasticity of demand for the commodity is 0.667

3. The cross price elasticity of demand is 0.8

The degree to which demand reacts to a change in an economic component is known as elasticity of demand. The most prevalent economic component considered when calculating elasticity is price. Income level and the accessibility of substitutes are further considerations. Elasticity gauges how demand changes in response to shifting economic conditions.

Given:

1. The demand for pen decreased from 100 to 70.

So, the percentage change in quantity

= (100 -70) / 100 = 0.3 = 30%

percentage change in the price

= (5 - 2) / 5

= 3/5

= 60 %

So, Cross price elasticity = 30% / 60% = 0.5

2. The quantity demanded of a commodity decreased from 50kg to 30kg.

So, the percentage change in quantity

= (50- 30)/50

= 40%

and, percentage change in price

= (8- 5)/5

= 60%

Then, cross price elasticity

= 40% / 60%

= 0.6667

Now, If the price of the commodity rather decreased from Gh¢5.00 to Gh¢2.50

So, the percentage change in price

= (5 - 2.5)/5

= 50%

Then, cross price elasticity

= 40% / 50%

= 0.8

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McCoy should hire two workers if their total profit is greater than the total profit of one worker.

To calculate how many workers McCoy should hire to make the most profit, he must first calculate the total number of drinks that can be made in one hour. One worker can make 30 drinks in an hour, and a second worker can make 25 drinks in an hour. This means that with two workers, 55 drinks can be made in one hour.

The next step is to calculate the total profit that can be made in one hour. This can be done using the formula Profit = Price x Quantity. Since the drinks sell for $2.50 on average and the total number of drinks made in one hour is 55, the total profit from one hour of work is $137.50.

This means that hiring two workers can make McCoy $137.50 in profit in one hour. To decide if this is the best option, McCoy should compare the total profit of two workers to the total profit of one worker. If the total profit of two workers is greater than the total profit of one worker, then McCoy should hire two workers. If the total profit of one worker is greater than the total profit of two workers, then McCoy should hire one worker.

McCoy should hire two workers if their total profit is greater than the total profit of one worker.

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Without more information about the specific situation (such as the height from which the bottle is dropped, the surface on which it is dropped, and so on), a value for p cannot be determined.

The probability of landing a bottle on the floor on any given try is a fixed value, typically represented by "p".

The probability that he will land the bottle on the floor on the tenth try is then given by:

P(tenth attempt landing) = (1 - p)9 * p

where (1 - p)9 represents the probability that he fails to land the bottle on the floor in the first nine attempts, and p represents the probability that he lands the bottle on the floor on the tenth attempt.

However, without more information about the specific situation (such as the height from which the bottle is dropped, the surface on which it is dropped, and so on), a value for p cannot be determined.

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A number of schedule that is recoverable but does not avoid cascading rollback and is not serializable is a schedule that contains interleaved operations from two or more transactions that conflict with each other.

For example, Transaction A writes to a data item, then Transaction B reads the same data item, then Transaction A commits has number of , and finally Transaction B commits. In this case, the schedule is recoverable, since both transactions will eventually commit, but it is not serializable, since Transaction B has read a data item that was written by Transaction A after Transaction B began but before Transaction A committed. Furthermore, it does not avoid cascading rollback, since if Transaction A is rolled back, then Transaction B will also need to be rolled back.

which of the following schedules is recoverable, but does not avoid cascading rollback and is not serializable?

A. Schedule A: T1 {R1(A); W2(C)} T2 {R2(B); W1(A)}

B. Schedule B: T1 {R1(A); W1(A)} T2 {R2(B); W2(C)}

C. Schedule C: T1 {R1(A); W2(C)} T2 {R2(B); W2(C)}

D. Schedule D: T1 {R1(A); W2(C)} T2 {R2(B); W2(A)}

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Answer:

9

Step-by-step explanation:

figure it yourself...... .... ....

Answer:

Kenmar can make 7 packages of peppers, since 28 divided by 4 is 7. To solve, I divided 28 by 4 and got the answer of 7.

Step-by-step explanation:

The optimal solution to the LP problem is (x,y) = (8,10). The objective function is minimized at this point, with a minimum value of 18.

We can solve this LP problem by using the graphical method.

First, we plot the constraints:

x + 3y <= 28 --> y <= -(1/3)x + 28/3

5x + y <= 28 --> y <= -5x + 28

x >= 0

y >= 0

Next, we find the feasible region formed by the intersection of these constraints. This region is a bounded polygon and is shown in blue in the figure below.

Finally, we find the point in the feasible region that minimizes the objective function c = x + 2y. We do this by plotting the objective function as a straight line with slope equal to 2 and y-intercept equal to 0. The line should pass through the feasible region and intersect it at the point with the minimum value of c.

From the figure, we can see that the line intersects the feasible region at the point (8, 10), which is the minimum value of c = x + 2y, with a minimum value of 18.

Therefore, the optimal solution to the LP problem is (x,y) = (8,10).

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None of the above is the correct answer. There is no answer in the given choices.

The U.S. Rule produces no compounding of interest in that any unpaid accrued interest is accumulated separately and is not added to the principal.

At maturity, using the U.S. rule, the interest calculated from the last partial payment is subtracted from the beginning balance and added to the adjusted balance.

Under U.S. Rule, unpaid accrued interest is accumulated separately and is not added to the principal. In addition, interest is not calculated until payment is made.

It also allows the borrower to receive proper interest credits. This rule defines that any partial loan payment first covers any interest that has built up, and the remainder of the partial payment will decrease the loan principal.

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The probability that an adult has a great deal of confidence in both scientists and religious leaders is equal to A x B = (43/100)(17/100) = 0.0721, or p = 7.21%.

I choose option 1. The percent of surveyed U.S. adults who had a great deal of confidence in both scientists and religious leaders is equal to p%.

To calculate p, we use the multiplication rule, which states that the probability of two independent events occurring together is equal to the product of their individual probabilities.

In this case, let A be the probability that an adult has a great deal of confidence in scientists, and let B be the probability that an adult has a great deal of confidence in religious leaders.

A = 43/100

B = 17/100

Therefore, the probability that an adult has a great deal of confidence in both scientists and religious leaders is equal to A x B = (43/100)(17/100) = 0.0721, or p = 7.21%.

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The excluded values from the domain of the function h(x) are given as follows:

x = -6 and x = -3.

The domain of a function is the set that contains all the possible input values for the function.

The function in this problem is a rational function, meaning that all the values of x that make the denominator zero are excluded from the domain.

As you found out on the problem, the values that make the denominator zero are given as follows:

x = -6 and x = -3.

The value x = -6 is also a zero of the denominator, however this would be considered only to simplify and calculate the limit, it has no bearing on the domain of the function.

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(a) The moment generating function of [tex]x = E[e^(tx)] = (1-e^(2t))^-1[/tex]and expected value of x = 4. (b) The moment generating function of[tex]y = E[e^(ty)] = 1/(1-2t) \\[/tex]and expected value of y = 30 minutes.

(a) The moment generating function of a random variable is defined as [tex]E[e^(tx)]\\[/tex], where t is a real number. In the given example, x is a random variable representing the number of arrived buses in 1 hour. Hence, the moment generating function of x is [tex]E[e^(tx)] = (1-e^(2t))^-1[/tex]. This is because the number of buses arriving in 1 hour follows a Poisson distribution with rate 2/30 minutes. Thus, the expected value of x is 4, which is the rate multiplied by the time period (2*2).

(b) The random variable y represents the waiting time until the next bus arrival. The moment generating function of y is [tex]E[e^(ty)] = 1/(1-2t)[/tex]. This is because the waiting time until the next bus arrival follows an exponential distribution with rate 2/30 minutes. Thus, the expected value of y is 30 minutes, which is the rate multiplied by the time period (2*30).

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Answer:

y = -2/3x + y

y = -2/3x + 1

Step-by-step explanation:

y = -2/3x + b

when x = 0,

y = -2/3 * 0 + b

y = b

b = y

The greatest value of GHI that can be achieved using digits 1 through 9, where each letter is represented by a different digit, is 984.

The greatest value of GHI can be found using the following formula:

GHI = 987 - (ABC + DEF)

Using this formula, we can solve for GHI by substituting the values for ABC, DEF, and 987. For the highest value of GHI, we can set ABC and DEF to the lowest possible values, 1 and 2 respectively. This gives us the following equation:

GHI = 987 - (1 + 2)

GHI = 984

Therefore, the greatest value of GHI that can be achieved using digits 1 through 9, where each letter is represented by a different digit, is 984.

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At scores of 13 and 14, the two piles correspond to the two frequency local maxima.

Here's the frequency distribution table:

Score Frequency

9 1

10 1

11 3

12 4

13 5

14 5

15 2

The distribution has two piles of scores and is roughly symmetrical. This is due to the fact that the frequencies are concentrated in the center of the distribution and become less frequent as you move away from it.

The two piles correspond to the two frequency local maxima at scores of 13 and 14.

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Is the ordered pair (-1, -5) is a solution to inequality y < -3/4 x - 1

No, because (-1, -5) is above the line.

The inequality y < -3/4x - 1 represents a line on a coordinate plane.

The inequality symbol "<" means that the values of y that satisfy the inequality are those that are strictly less than the value of the right-hand side of the equation.

So, for any given x-value, all y-values that are less than the corresponding y-value on the line satisfy the inequality.

In this case, when x = -1, the corresponding y-value on the line is -3/4 * -1 - 1 = 1/4.

Since -5 is greater than 1/4, it means that (-1, -5) is above the line and does not satisfy the inequality y < -3/4x - 1.

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Option B is correct,  y≥-4 and  y≤-x+4 is the system of solutions of the given graph.

a relationship between two expressions or values that are not equal to each other is called 'inequality.

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

From the given graph a line is passing at y=-4

and the shading is towards the origin so the inequality will be y≥-4.

The other line is passing through points (4,0) and (0,4)

Slope=4/-4=-1

So equation of line is y=-x+4

and the shading is y≤-x+4

Hence, option B is correct,  y≥-4 and  y≤-x+4 is the system of solutions of the given graph.

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To verify that the given function is an explicit solution of the given differential equation, we can plug it into the differential equation and see if it satisfies the equation.

Plugging in the given function, we get: dy/dt + 20y = 24; (6/5)e-20t - 6/5 = 24. Simplifying, we get 0 = 0, which is true. This means that the given function is an explicit solution of the differential equation, and it is valid on any interval I.

To find a function solution to a differential equation, you must first identify the type of equation you are dealing with. If it is a linear equation, you can use the method of integrating factors or the method of undetermined coefficients, depending on the equation.

If it is a nonlinear equation, you can use the method of separation of variables, the method of substitution, or the method of series solutions. Once you have identified the equation, you can use the appropriate method to find the solution.

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To accurately determine the time, distance, and speed when a golf ball is hit along a sloped surface, you would need to measure the ball's initial velocity, the angle of the slope, and the acceleration due to gravity.

With these measurements, it would be possible to calculate the time and distance the ball traveled, as well as its speed at the moment it lands.

To calculate the time, distance, and speed when a golf ball is hit along a sloped surface, one must measure the ball's initial velocity, the angle of the slope, and the acceleration due to gravity. With these measurements, one can then calculate the ball's time, distance, and speed when it lands.

The complete question is :

A golfer is hitting a golf ball along a sloped surface. The ball is hit with an initial velocity of 50 m/s at an angle of 30 degrees to the horizontal. Determine the time, distance and speed when the ball lands.

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the number of degrees in the smaller angle is 60 degrees.

The smaller angle is 60 degrees.

Let x = number of degrees in the smaller angle

Then the number of degrees in the larger angle = 3x

Given that the two angles are in the ratio of 2 to 3

2x = 3x

x = 60

Therefore, the number of degrees in the smaller angle is 60 degrees.

The two supplementary angles are supplementary angles because the sum of their angles is 180 degrees. This means that if we denote the number of degrees in the smaller angle as x, then the number of degrees in the larger angle must be 180-x. We know that their ratio is 2 to 3, which can be written as 2x = 3(180-x). Solving this equation gives us x = 60, so the number of degrees in the smaller angle is 60.

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