The average acceleration is negative, indicating that the plane is slowing down. The required equation for average acceleration is a = [tex]\frac{(7.81 m/s - 71.5 m/s)}{ t}[/tex]
The average acceleration of the plane during landing can be calculated using the following equation:
a = [tex]\frac{V_f - V_i}{t}[/tex]
Where:
a = average acceleration
v f = final velocity = 7.81 m/s
vi = initial velocity = 71.5 m/s
t = time taken to reduce speed = [tex]\frac{(vf - vi) }{a}[/tex]
Substituting v f and vi in the equation, we get:
[tex]a = \frac{(7.81 m/s - 71.5 m/s)}{ t}[/tex]
Next, we can use the distance traveled during landing (796 m) and the average acceleration to find the time taken to reduce speed. We can use the equation:
[tex]d = vi \times t + (1/2) \times a \times t^2[/tex]
Where:
d = distance traveled = 796 m
Substituting the value of vi and a, we get:
[tex]796 m = 71.5 m/s \times t + (1/2) \times a \times t^2[/tex]
Solving for t:
[tex]t = \sqrt{(796 m / (1/2) \times a) + (71.5 m/s)^2 / a^2)}[/tex]
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give 5 examples of the 3 types of heat transfer
The three modes of heat transfer are conduction, convection and radiation. Conduction takes place in solids and convection takes place in liquids and gases. Radiation is the mode of heat transfer through vacuum.
What is heat transfer ?Heat will transfer from a hotter region to the colder region due to the differential distribution of temperature. There are three modes of heat transfer namely conduction, convection and radiation. Conduction takes place in solids and convection takes place in liquids and gases. Radiation is the mode of heat transfer through vacuum.
Heat and light is reaching from the sun to earth by radiation. The ground is warming up through the conduction process. Similarly all the solid substances are heating up by conduction.
The water resources are warming up by convection currents, in which the hotter molecules rises above and make the whole liquid warm.
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the height of the mercury column in a barometer reads 725 mm. a barometer is made of a glass tube sitting in an open container of mercury. the glass stem is partly filled with the mercury. how will the height of the mercury column change when the atmospheric pressure decreases?
The height of the mercury column in a barometer is directly proportional to the atmospheric pressure. As atmospheric pressure decreases, the height of the mercury column decreases. Conversely, as atmospheric pressure increases, the height of the mercury column increases.
This relationship between the height of the mercury column and atmospheric pressure is described by Pascal's law, which states that pressure applied to an enclosed fluid is transmitted equally in all directions throughout the fluid. In the case of a barometer, the mercury in the glass stem is an enclosed fluid, and the atmospheric pressure acts on it, causing it to rise or fall.
So, if the atmospheric pressure decreases, the mercury column's height will also decrease. The exact amount of change in the height of the mercury column will depend on the amount of decrease in atmospheric pressure and the specifics of the barometer setup.
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the crew of a cargo plane wishes to drop a crate of supplies on a target below. to hit the target, when should the crew drop the crate? ignore air resistance. view available hint(s)for part a the crew of a cargo plane wishes to drop a crate of supplies on a target below. to hit the target, when should the crew drop the crate? ignore air resistance. when the plane is directly over the target before the plane is directly over the target after the plane has flown over the target
To hit the target with the crate of supplies, the crew should drop the crate when the plane is directly over the target.
This is because the crate will be initially moving with the same horizontal velocity as the plane. When dropped, the crate will begin to fall vertically due to the force of gravity,
Gravity is a fundamental force in the universe that causes objects to be attracted to each other. It is the force that governs the motion of planets, stars, and galaxies, and is responsible for keeping them in their orbits.
According to the theory of gravity proposed by Sir Isaac Newton, every object in the universe exerts a gravitational force on every other object, with the strength of the force depending on the mass of the objects and the distance between them. This force is proportional to the product of the masses of the two objects, and inversely proportional to the square of the distance between them
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Walter Cannon criticized the James-Lange theory on multiple points. Which one of the following is one of those criticisms?
Explanation:
Walter Cannon challenged the James-Lange theory, criticizing it on several grounds. Which of the following is one of those criticisms? Cannon pointed out that bodily reactions are similar for many emotions, yet our subjective experience of various emotions is very different.
a sperm whale can accelerate at about 0.110 m/s2 when swimming on the surface of the ocean. how far will a sperm whale travel if it starts at a speed of 0.900 m/s and accelerates to a speed of 2.18 m/s ? assume the whale travels in a straight line.
The distance traveled by the sperm whale at a speed of 0.9 m/s with an acceleration of 0.11 m/s² is 17.91 m
The initial speed of the sperm whale = 0.9 m/s
The acceleration of the sperm whale = 0.11 m/s²
The final speed of the sperm whale is 2.18 m/s
The distance traveled by the sperm whale can be found using the formula,
v² = u² + 2as
where v is the final velocity
u is the initial velocity
a is the acceleration of the sperm whale
d is the distance traveled by the sperm whale
Let's substitute the known values in the above equation we get
2.18² = 0.9² + 2 x 0.11 x s
4.75 = 0.81 + 0.22 x s
4.75 - 0.81 = 0.22 x s
0.22 x s = 3.94
s = 3.94 / 0.22
s = 17.91 m
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why does the blind spot from the optic disc in either eye not result in a blind spot in the visual field?
With both eyes open, the blind spots are not perceived because the visual fields of the two eyes overlap. Indeed, even with one eye closed, the blind spot can be difficult to detect subjectively because of the ability of the brain to “fill in” or ignore the missing portion of the image.
What is the structure of eye ?The optically transparent aqueous humour, lens, and vitreous body are all enclosed by three coatings that make up the eye. The cornea and sclera make up the outermost coat, while the choroid, ciliary body, and iris make up the intermediate coat and, from the rear to the front, the major blood supply to the eye.
Due to the fact that both eyes' fields of vision overlap, the blind spot is ignored and does not result in a blind spot in the visual field. Additionally, even with one eye closed, the brain has the capacity to ignore or make up for the affected area.
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Calculate the kinetic energy and the velocity required for a 70kg pole vaulter to pass over a 5.0m high bar. Assume the vaulter’s centre of mass is initially 0.90m off the ground and reaches its maximum height at the level of the bar itself.
Answer:
Below
Explanation:
The vaulter's entire KE will be converted to PE to clear the bar (5-.9) = 4.1 m above the COM.
PE required = mgh = 70 ( 9.81)(4.1) = 2815.5 J
KE required will then be 2815.5 J
(As an aside: = 1/2 mv^2 = 2815.5 = 1/2 ( 70)(v^2) shows v = 9 m/s)
3. the coefficient of friction between a soccer ball and a court is 0.52, and its mass is 425 gm. how much horizontal force is required to make the shoe slide?
The horizontal force that is required to make the shoe slide is 2.1658N.
Horizontal force = static friction
Static friction = uMg
u is coefficient of friction
g = acceleration due to gravity
M is the mass of the body that is .0425 kg.
Force required = (0.52 x 0.425 x 9.8) N
= 2.1658N
A horizontal force is a force that operates in a direction parallel to the horizon. The cycle's speed tends to slow down due to an opposing force called air resistance force, which acts in the opposite direction. Both the applied force and the air resistance force are considered horizontal forces when the direction is taken into account. Jumps and horizontal medicine ball throws can help increase the horizontal force produced. The Standing Long Jump, Standing Triple Jump, and horizontal jumps over hurdles or boxes are some of these jumps.
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a spring has a natural length of 10 cm. if a 25 n force is required to keep it stretched to a length of 20 cm, how much work w (in j) is required to stretch it from 10 cm to 15 cm? (round your answer to two decimal places.)
A spring has a natural length of 10 cm then the work w (in j) is required to stretch it from 10 cm to 15 cm is 156.25 J.
We can use the formula for the work done by a spring: W = (1/2) k ([tex]x_{2}[/tex] - [tex]x_{1\\}[/tex]) where W is the work done, k is the spring constant, [tex]x_{2}[/tex] is the final length of the spring, and [tex]x_{1\\}[/tex] is the initial length of the spring.
First, we need to find the spring constant. We can use the force applied and the extension of the spring to calculate it:
F = k([tex]x_{2}[/tex] - [tex]x_{1\\}[/tex])
25 N = k (20 cm - 10 cm)
k = 2.5 N/cm
Now we can use this value of k to calculate the work done to stretch the spring from 10 cm to 15 cm:
W = (1/2) (2.5 N/cm) ((15 cm)^2 - (10 cm)^2)
W = (1/2) (2.5 N/cm) (225 cm^2 - 100 cm^2)
W = (1/2) (2.5 N/cm) (125 cm^2)
W = 156.25 J
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a dark screen with a 2mm hole in it is placed between a light bulb emitting light and a viewing screen. what will you see on the viewing screen?
When the light beams that have been reflected or refracted actually touch after reflection or refraction, a true image is created. On a screen, an actual image can be obtained.
What does "screen" mean in optics?projection screen, a surface used to display an optical projector's picture. The main criteria for materials to be used as screens is a high level of reflection. The lenticular, glass bead, and mat white screens are the three most popular kinds of screens.
How do pictures show up on a screen?To generate a picture visible to a human eye, pixels on electrical devices can emit light, filter light, or reflect light. Here is an output from a laser printer that has been enlarged. The output of an inkjet printer printer is magnified below. The dots that make up the finished image can be seen.
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a car and a truck start from rest at the same instant, with the car initially at some distance behind the truck. the truck has a constant acceleration of 2.10 m/s2 and the car an acceleration of 3.40 m/s2 . the automobile overtakes the truck after the truck has moved 60.0 m .
v truck equals 2.10 m/s^2 * t(v=velocity)
v car equals 3.40 m/s^2 * t.
In order to obtain the solution, we can lastly enter the known value of d = 60.0 m:
Sqrt(2 * 60.0 m / (3.40 m/s^2 - 2.10 m/s^2) yields t = 5.14 s.
v truck is equal to 2.10 m/s^2 * 5.14 s, or 10.67 m/s.
17.87 m/s is equal to v car = 3.40 m/s^2 * 5.14 s.
With a speed of 17.87 m/s and a truck speed of 10.67 m/s, respectively, the vehicle passes the truck after 5.14 seconds.
An object's rate of change in position in a certain direction is described by a vector quantity called velocity. Its formula is the product of the positional change and the time change. In other terms, velocity refers to a direction in which an object is moving at a certain speed. Meters per second (m/s) or any other measure of distance travelled in a given amount of time can be used to describe velocity. When describing the motion of objects in various contexts, such as the movement of planets and stars or that of projectiles and vehicles, velocity is a key notion in physics. The forces acting on an object and its acceleration can cause its velocity to fluctuate over time. being aware of speed
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two trains on separate tracks move toward each other. train 1 has a speed of 123 km/h; train 2, a speed of 66 km/h. train 2 blows its horn, emitting a frequency of 560 hz. what is the frequency heard by the engineer on train 1?
Two trains on the separate tracks move toward each other. Train 1 has speed of 123 km/h, train 2, speed of 66 km/h. Train 2 blows its horn, emitting a frequency of 560 hz. The frequency heard by the engineer on train 1 is 662.41 Hz.
Train 1 (observer) :
Speed = 109 km/h = 30.2 m/s
Train 2 (source) :
Speed = 99 km/h = 27.5 m/s
Train 2 emitting frequency = 500 Hz
The expression is as follows :
F = F' ( v + v1 / ( v - v2 )
Where
F' = 560 Hz
v is velocity of sound = 343 m/s
v1 = 30.2 m/s
v2 = 27.5 m/s
Frequency = 560 ( ( 343 + 30.2 ) / 343 - 27.5 ))
Frequency = 560 × (373.2 / 315.5)
Frequency = 662.41 Hz
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a large piece of ice breaks loose from the roof of a chalet at a ski resort and slides across the snow-covered terrain. it passes over the top of a hill in a path that has the shape of the arc of a circle of radius r . what is the speed v of the piece of ice as it passes over the top of the hill if the normal force exerted on it at this point is half its weight?
The speed v of the piece of ice as it passes over the top of the hill if the normal force exerted on it at this point is half its weight is [tex]v= \sqrt{\dfrac{gr}{2}}[/tex].
During the sliding over the top of the hill, the forces acting upon the piece of ice are gravitational force, [tex]F_g[/tex] = mg toward the ground,
and centrifugal force is given by [tex]F_c = \dfrac{mv^2}{r}[/tex] acting from the ground,
so the total normal force exerted on it at this point (toward the ground) is half its weight, [tex]F_n = \dfrac{1}{2} mg[/tex].
Using the Newton's second law of motion,
[tex]\dfrac{1}{2} mg = mg - \dfrac{mv^2}{r}[/tex]
Solving this,
[tex]v= \sqrt{\dfrac{gr}{2}}[/tex]
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Please help
Predict what would happen if you dropped a 1 lb ball from 10ft in the air into sand and measured the size of the crater, and then a 10lb ball from 10ft in the air and then measured the size of the crater.
Answer:
If you drop a 1 lb ball from 10 ft in the air into sand and measure the size of the crater, and then a 10 lb ball from 10 ft in the air and measure the size of the crater, you would expect to see that the crater created by the 10 lb ball is larger than the crater created by the 1 lb ball. This is because the larger mass of the 10 lb ball will result in a greater impact force upon hitting the sand, which in turn will cause a larger excavation of the sand and thus a larger crater.
how did mesoamerica civilizations use astronomy--the study of stars and planets, in their everyday lives?
The answer is option A, B, and D.
Mesoamerican civilizations used astronomy in many aspects of their everyday lives. They developed calendars based on the movement of stars and planets, using observations to determine the seasons of the year and to track the cycles of agricultural planting and harvesting. They also used the movement of stars and planets to track animal herds, as the migration patterns of animals were closely tied to astronomical events.
Additionally, their beliefs about astronomy were closely tied to their religious practices, and they used their understanding of astronomy to predict the future and make decisions about important events such as wars, marriages, and trade. The study of astronomy was an integral part of the daily life of Mesoamerican civilizations and played a key role in their cultural, economic, and political development.
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which of the following does not describe a way in which machines function? by enhancing range of motion and speed of movement so that resistance can be moved farther or faster than an applied force by balancing multiple forces by altering the resulting direction of an applied force by enhancing force in an attempt to increase total force needed to overcome a resistance
The method by which machines increase range of motion and speed of movement so that resistance can be moved farther or more quickly than an applied force is not described in the following.
Which of the following best describes the gravitational attraction of the earth on an object: biomechanics force levers?The earth pulls your body downward, which is known as gravity. The location where your body's mass is concentrated is known as your center of gravity. A hypothetical location where the force of gravity seems to act is the center of gravity (COG) of an organism.
Which of the following claims regarding friction force is false?No relative motion exists between the two contact surfaces in a rolling motion. Therefore, in a rolling motion, the friction does not do any work. Because of this, rolling friction is lower than sliding or kinetic friction.
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A small section of an electric field is shown with points A, B, and C. Rank the
magnitude of the electric field at those three points from largest to smallest.
The rank of magnitude of electric field is given by:
point A > point B > point C.
What is electric field line?An great approach to see electric fields is with electric field lines. They had their beginnings with Michael Faraday himself.
At one point, a field line is drawn perpendicular to the net. As a result, the direction of the electric field at any place is the same as the tangent to the electric field line.
Second, the relative strength (magnitude) of the electric field at a location is correlated with the relative density of the field lines around that point.
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What happens when a substance moves below its freezing point? And What happens when it moves above its boiling point???
When a substance moves below its freezing point, it undergoes a phase change from a liquid to a solid.
When a substance moves above its boiling point, it undergoes a phase change from a liquid to a gas.
What happens when a substance moves below its freezing point?When a substance moves below its freezing point, it undergoes a phase change from a liquid to a solid. This happens because the temperature is low enough that the energy of the particles in the liquid is insufficient to overcome the forces of attraction between them. As a result, they slow down, come together, and form a solid.
On the other hand, when a substance moves above its boiling point, it undergoes a phase change from a liquid to a gas. This occurs because the temperature is high enough to provide enough energy to the particles in the liquid to overcome the forces of attraction between them. The particles then move apart, form into a gas, and eventually escape into the atmosphere as a vapor.
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the radius of the planet mercury is 2440 km. its mass is 3.3 x 1023 kg. what is the gravitational field strength at the surface?
Collars that emit radio waves are sometimes placed on animals to find their location. Which is the BEST reason for using radio waves as a method of tracking the animals?
The best reason for using radio waves on animals is to locate where the animals are and to keep track of them.
How can animals be tracked?VHF radio tracking, satellite tracking, and global positioning system tracking are the three types of radio tracking systems used by scientists. Radio waves are used as a method of tracking animals because they can travel over long distances, even through obstacles, and can be easily detected with a receiver.
Additionally, radio waves can be emitted continuously, allowing for continuous monitoring of the animal's location. This makes radio waves a convenient and effective means of tracking animals in many different environments.
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you are loading a dart gun. the spring that launches the dart has a spring constant 3350 n/m and a normal length of 10 cm. you push the dart into the gun and it contracts the spring until it is 2.0 cm long. how much force does the spring exert on the dart the instant it is released? enter your answer in newtons (e.g if the force is 100n, enter your answer as 100)
Whatever speed can the dart gain if it separates from spring when it hits its natural lengths (x = 0)? = 3.0 m/s in the horizontal, the spring's force was the only one acting on the dart (friction was ignored).
Where on the springs motion does the speed increase the quickest?The greatest location, x=A, correspond to a velocity of zero, and the position with the maximum speed is x=0. The "initial condition" in t=0, where the mass is located at x=A and moving at v=0, corresponds to =0.Here the natural length of the spring is 35cm and the spring is compressed to 14cm in length. the force exerted on bow by the spring is 21cm/(100cm/m)=> F = 5.04N
What is the strongest dart gun available?The fastest-firing Nitro dart blaster is the N-Strike Elite HyperFire. With new batteries, this fully motorised blaster can fire up to 5 dart per second, allowing kids to pelt targets with a barrage of darts.
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Answer: 268 N
Explanation:
[tex]F_{spring} =k_{s} (L-L_{0})=-3350(0.02-0.10)[/tex]
is there any other position where the electric field magnitude is zero? if so, what is that location in terms of d ?
No, the electric field magnitude is zero only at the midpoint between the two charges, i.e. at a distance of d/2.
In order to determine the location of the electric field zero, we set the electric fields for each point charge to be equal to one another because that is the point at which they will cancel one another out. The electric potential does not necessarily equal zero just because the electric field is zero at a certain location. The situation of two similar charges that are spread apart is an excellent example. Even when the electric field is not zero at a given point, the electric potential can nonetheless be zero there. Because it is 0 at a point inside the solid body of the conductor, the electric field caused by induced charges at the sphere's center is zero.
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explain the action of the conventional shock absorber on both compression (jounce) and rebound stokes.
The typical shock absorber is made to lessen both the shock, or "jounce," felt during compression strokes and the amount of rebound felt during rebound strokes.
The shock absorber uses hydraulic pressure during compression strokes to slow down and absorb the shock, or jounce, of the vehicle when it travels over bumps or potholes. The kinetic energy of the shock is transformed into thermal energy by a piston, cylinder, and hydraulic fluid, which work together to accomplish this. The shock absorber works to lessen the vehicle's rebound or bounce during rebound strokes, making the ride more comfortable. It accomplishes this by utilizing a valve to control the hydraulic fluid's flow and produce resistance, which aids in absorbing the rebound's energy.
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Suppose you throw a 0.0520 kg ball with a speed of 10.0 m/s and
at an angle of 30.0° above the horizontal from a building 12.0 m high.
a) What will be its kinetic energy when it hits the ground?
b) What will be its speed when it hits the ground?
The kinetic energy of the ball of 0.0520 kg with a velocity of 10 m/s is 2.6 J. The speed of the ball when it hits the ground will be 15.3 m/s.
What is kinetic energy ?Kinetic energy of an object is the energy generated by virtue of its motion. It is related to the mass and velocity as follows:
Ke = 1/2 mv²
Given that, m = 0.0520 kg
velocity v= 10 m/s
then Ke = 1/2 × 0.0520 Kg × (10 m/s )² = 2.6 J.
The kinetic energy of the ball when it hits the ground will be equal to the potential energy. Then, the speed of the when it hits the ground is calculated as:
v =√2gh
v = √(2 × 9.8 m/s 12 m)
= 15.3 m/s.
Therefore, the speed of the ball when it hits the ground will be 15.3 m/s.
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a 45.0-kg girl is standing on a 150-kg plank. the plank, originally at rest, is free to slide on a frozen lake, which is a flat, frictionless surface. the girl begins to walk along the plank at a constant velocity of 1.50 m/s to the right relative to the plank. (a) what is her velocity rela- tive to the surface of the ice? (b) what is the velocity of the plank relative to the surface of the ice?
(a) The relative velocity of Girl relative to the surface of the ice is given by: v = (1.50 m/s) * (45 kg / 195 kg) = 0.45 m/s
(b) The velocity of the plank relative to the surface of the ice is given by: v = (1.50 m/s) - (0.45 m/s) = 1.05 m/s
(a) To find the velocity of the girl relative to the surface of the ice, we must consider the motion of the plank.
The plank and the girl have a combined mass of 150 kg + 45 kg = 195 kg.
Since the girl is walking to the right at 1.50 m/s relative to the plank, her velocity relative to the surface of the ice is given by:
v = (1.50 m/s) * (45 kg / 195 kg) = 0.45 m/s
(b) To find the velocity of the plank relative to the surface of the ice, we must subtract the velocity of the girl relative to the surface of the ice from the velocity of the girl relative to the plank.
The velocity of the plank relative to the surface of the ice is given by:
v = (1.50 m/s) - (0.45 m/s) = 1.05 m/s
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a cat jumps straight up 3.00 m. how much time does it spend in the top 1.00 m (ascending and descending)?
The cat spends equal amounts of time ascending and descending, it spends a total of approximately 0.449 s in the top 1 m of its jump.
To determine the time spent by the cat in the top 1 m, we need to find the time it takes to travel the first 1 m of its 3 m jump. The motion of the cat can be modeled as a vertical, projectile motion problem. The time it takes to travel a given vertical distance can be found using the formula:
[tex]$t = \sqrt{\frac{2d}{g}}$[/tex]
Where d is the vertical distance traveled and g is the acceleration due to gravity [tex](9.8 m/s^2)[/tex]. Plugging in d = 1m and g = [tex]9.8$ m/s^2[/tex], we find that the time it takes to travel the first 1 m is
[tex]$t = \sqrt{\frac{2 \cdot 1}{9.8}} = \sqrt{\frac{2}{9.8}} \approx 0.449s[/tex]
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does putting batteries in the freezer recharge them?
Simply put, no. Try not to be hard on you if this is the first time you've heard it; in some cases, a belief was once accurate. A bulk of energy storage units kept in fridge are basic AA, AAA, C, & D batteries.
What three types of batteries are there?There are three main battery kinds that may be used by consumers. They are lithium ion, nickel metal hydride, and alkaline. Each kind has benefits and drawbacks. Each of them has a unique position in the history of technology.
What kind of battery is ideal?With the greatest energy density of just about any battery cell, lithium batteries are made of this very light metal. As a result, they have a higher energy capacity than battery systems or any other separate bat of a similar size. Additionally, they work admirably in the both cold and warm environments.
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as electrons are passed down the etc associated with ps ii, they lose energy. what happens to this energy?
Electrons lose energy when they pass through the proteins that exist between PSII and PSI. This energy is utilised to transport hydrogen atoms from the stroma to the thylakoid lumen.
As soon as electrons are lost, each photosystem is replenished with electrons from another source. The PSII reactive center receives electrons from water, but the PSI reactive center fills with electrons flowing down the electron transport chain from her PSII.
Two electrons lost from photosystem II are replaced by water molecule fission. Breaking down water also releases hydrogen ions into the lumen. This contributes to a hydrogen ion gradient similar to that produced by mitochondrial electron transport. Electrons move via a succession of proteins from photosystem II. This electron transport system uses the energy of electrons to drive hydrogen ions into the interior of the thylakoid.
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treat each of your eyes as a circular aperture of diameter 3.4 mm. light of wavelength 442 nm is used to view two point sources that are 139 m distant from you. how far apart must these two point sources be if they are to be just resolved by your eye? assume that the resolution is diffraction limited and use rayleigh's criterion.
The resolution limit for a circular aperture of diameter d for a light of wavelength λ is given by the formula, d = 1.22λ/D, where D is the separation between two point sources. So for the given situation,
d = 1.22 x 442 x 10^-9 m / 139 m = 1.22 x 442 x 10^-9 m / 139 m.
Solving for D, we get
D = 1.22 x 442 x 10^-9 m / (3.4 x 10^-3 m) = 1.22 x 442 / 3.4 x 10^-6 m = 1.22 x 442 x 10^6 / 3.4 m = 0.0635 m. Therefore, the two-point sources must be separated by 0.0635 meters to be just resolved by the eye.
The result of imaging a point object through a circular aperture, such as our eye's lens or iris, is not a point but a diffraction pattern. This is true, especially when the object's size and the light's wavelength are comparable.
Concentric circles that become dimmer as we go away from the center are formed by a circular aperture. They are referred to as Airy discs.
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a person is holding a rock and a ball, they throw the ball down and then drop the rock, do they have the same acceleration?
No, they don't have the same acceleration because the thrown ball accelerates faster.
Acceleration is simply defined as change in velocity over time elapsed (a = Δv/t). An object is accelerating if it is slowing down, speeding up, or changing directions. Force can make objects accelerate. If an object is at rest or is moving at a constant velocity, then it's not accelerating.
Gravity in classical mechanics is defined as a type of force. Force of gravity is sometimes called weight. Weight is equal to mass times acceleration due to gravity (W = mg).
Both the ball and the rock are affected by Earth's gravity. However, since the ball's initial speed isn't zero, it moves faster than the dropped rock, and the ball will hit the ground first.
Learn more about acceleration at https://brainly.com/question/460763.
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