5x - 8x - 7=-3x+5-7 won’t pull an answer to check my answer

The all four angles are ∠AEC=40o, ∠BEC=140o, ∠AED=140o, ∠BED=40o.

What are vertically  angles?

Vertical  angles are formed when two lines cross at a point. They are always on an equal footing. In other words, four angles are created anytime two lines cross or intersect. It is evident that two opposed angles are equal and are referred to as vertical angles.

Given that

∠BOC+∠AOC=280o   (AB and CD intersect at point E)

we know that, ∠AED and ∠BEC are vertically opposite angles ∠AED=∠BEC

we know that, ∠AED=∠BEC

so it can be written as

∠AED+∠AED=180o,

2∠AED=280o,

∠AED= 140o,

∠AED=∠BEC=140o

we know that ∠AEC and ∠AEC form a linear pair

So it can be written as

∠AEC+∠AED=180

substituting the values

∠AEC+140o=180o

∠AEC=40o

we know that ∠AEC and ∠BED are vertically opposite angles

∠AEC=∠BED=40o

Therefore, ∠AEC=40o, ∠BEC=140o, ∠AED=140o, ∠BED=40

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Answer:

The last one -4÷0 cannot be answered

Step-by-step explanation:

Answer:

-4/0

Step-by-step explanation:

This is an undefined answer, due to the fact that it would come out as:

0.00000e00000

This would be an undefined problem.

Answer:

1:27pm

Step-by-step explanation:

52 + 8 = 1 hour

29 - 8 = 21

1 hour and 21 minutes

2:48 - 1:21

1:27pm

Answer:

Bar A : 266 calories; Bar B : 251 calories

Step-by-step explanation:

Assume bar A's caloric content is "a" and bar B's caloric content is "b".

1. a + 2b = 768

2. 2a + b = 783

Add both equations together.

3. 3a + 3b = 1551

Divide both sides by 3.

4. a + b = 517

Subtract equation 4 from equation 1.

5. a + 2b - a - b = 768 - 517

Evaluate.

6. b = 251

Subtract b's value from equation 2.

7. 2a + b - b = 783 - 251

Evaluate.

8. 2a = 532

Divide both sides by 2.

9. a = 266

Answer:

#1 = -2

Step-by-step explanation:

First, we need to make -2 2/3 an improper fraction. An improper fraction is a fraction whose numerator is bigger than its denominator.

you first multiply the whole number (ignoring the negative sign for now) by the denominator:

2*3=6

then you add the numerator:

6+2=8

finally you put that number over the denominator and then put the negative sign back:

-8/3

Next, you can use keep change flip to solve the division

You keep the first fraction, change the division sign to a multiplication sign, and flip the numerator and the denominator of the second fraction:

-8/3 divided by 4/3 becomes -8/3 x 3/4

finally you multiply across as you would normally and simplify

-8/3 x 3/4= -24/12

-24/12 simplified is -2

:D

if you need help with the rest just comment on this response and I'll try to answer as soon as I can

Answer:

(2,7), (6,-2),

Step-by-step explanation:

After finding the points you plug them in to the distance formula:

d=√((x2-x1)²+(y2-y1)²)

d=√[(6-2)²+(-2-7)²]

Quadratic equations are all those equations that can be reformulated in a standard format (αx² + bx + c(=0) where the value of x is unknown and the values of the coefficients (a, b and c) are unknown.

These equations can always be solved using the quadratic formula, although sometimes it is also possible to use factorization or isolation of variables.

Expand squared

It is distributed

Combine like terms.

Move terms to the left

Subtract the numbers

Use the quadratic formula.

                        [tex]\large\displaystyle\text{$\begin{gathered}\sf x=\frac{-b\pm\sqrt{b^{2}-4ac } }{2a} \end{gathered}$}[/tex]

In standard form we identify "a", "b" and "c" from the original equation and add to the quadratic formula.

                      [tex]\large\displaystyle\text{$\begin{gathered}\sf x=\frac{-(-14)\pm\sqrt{(-14)^{2}-4\cdot1\cdot41 } }{2\cdot1} \end{gathered}$}[/tex]

Simplify

                                         [tex]\large\displaystyle\text{$\begin{gathered}\sf x=\frac{14\pm4\sqrt{2} }{2} \end{gathered}$}[/tex]

Separate equations

To solve for the unknown variants, we split the equation into two: one with a plus sign and the other with a minus sign.

                                       [tex]\large\displaystyle\text{$\begin{gathered}\sf x=\frac{14+4\sqrt{2} }{2} \end{gathered}$}[/tex]

                                       [tex]\large\displaystyle\text{$\begin{gathered}\sf x=\frac{14-4\sqrt{2} }{2} \end{gathered}$}[/tex]

Solve

Order and isolate the variant to find each solution.

                                            [tex]\large\displaystyle\text{$\begin{gathered}\sf x=7+2\sqrt{2} \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x=7-2\sqrt{2} \end{gathered}$}[/tex]

                            [tex]\red{\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{\blue{Answer \ \ \longmapsto \ \ x=7\pm2\sqrt{2} }} \end{gathered}$}}}[/tex]

Answer:

Step-by-step explanation:

7(i)

[tex]\displaystyle\\\frac{d}{dx}\{x*(3x-5)^\frac{5}{3} \}=\frac{dx}{dx} *(3x-5)^\frac{5}{3}+x*\frac{d}{dx} \{(3x-5)^\frac{5}{3} \}\\\\ \frac{d}{dx}\{x*(3x-5)^\frac{5}{3} \}=1*(3x-5)^\frac{5}{3} +x*\frac{5}{3}*(3x-5)^{\frac{5}{3} -1}*\frac{d}{dx} \{(3x-5)\}\\\\ \frac{d}{dx}\{x*(3x-5)^\frac{5}{3} \}=(3x-5)^\frac{5}{3} +\frac{x*5*(3x-5)^{\frac{2}{3}}*3 }{3} \\\\\frac{d}{dx}\{x*(3x-5)^\frac{5}{3} \}=(3x-5)^\frac{5}{3} +5x*(3x-5)^\frac{2}{3} \\\\[/tex]

[tex]\displaystyle\\\frac{d}{dx}\{x*(3x-5)^\frac{2}{3} \}=(3x-5)^\frac{2}{3}*((3x-5)^{\frac{5}{3}-\frac{2}{3}} + 5x)\\\\\frac{d}{dx}\{x*(3x-5)^\frac{2}{3} \}=(3x-5)^\frac{2}{3} *(3x-5)^\frac{3}{3}+5x) \\\\\frac{d}{dx}\{x*(3x-5)^\frac{2}{3} \}=(3x-5)^\frac{2}{3} *(3x-5+5x)\\\ \frac{d}{dx}\{x*(3x-5)^\frac{2}{3} \}=(8x-5)*(3x-5)^\frac{2}{3}[/tex]

7(ii)

[tex]\int\limits {(x*(3x-5)^\frac{2}{3}) } \, dx \\Let\ \sqrt[3]{3x-5} =u\\Hence,\\(\sqrt[3]{3x-5})^3=u^3\\ 3x-5=u^3\\3x-5+5=u^3+5\\3x=u^3+5\\[/tex]

Divide both parts of the equation by 3:

[tex]\displaystyle\\x=\frac{u^3+5}{3}\\\\dx=\frac{d}{du} \{\frac{u^3+5}{3}\} \\dx=\frac{3u^2}{3} du=\\\\dx=u^2du\\Hence,\\\\\int\limits {\frac{u^3+5}{3}* u^2*u^2} \, du =\\\\\int\limits {\frac{u^3+5}{3} *u^4} \, du =\\\\\int\limits {\frac{u^7+5u^4}{3} } \, du =\\\\\frac{1}{3} \int\limits {u^7} \, du +\frac{1}{3}\int\limits {5u^4} \, dxu =\\\\[/tex]

Answer: A=32 B=19

Step-by-step explanation:

The radius of the pool with height as 0.5 cm and volume as 12,000 cm³ is 87.39 cm.

We have that:

Radius of the water pipe = 0.74 cm

r = 0.74 cm

It fills a 12 L bucket in 4 minutes

1 L = 1000 cm³

12 L = 12,000 cm³

Volume of water put in the pool = 12,000 cm³

Height of the pool that rise = 5 mm = 0.5 cm.

H = 0.5 cm

Let the radius of the pool be R.

Volume = π r² h

Substituting the values, we get that:

12,000 = ( 22 / 7 ) R² ( 0.5 )

R² = 7636.36

R = 87.39 cm

Therefore, we get that, the radius of the pool with height as 0.5 cm and volume as 12,000 cm³ is 87.39 cm.

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I have two answers depending on the format. I'm not sure if the entire function is to the 2ndpower or not. Either way, it's either 256 or 4.

The inequality notation for the given interval is -∞ < x ≤ -11 and -8 ≤ x < ∞

Disclaimer:

Considering the given interval as (-∞, -11] ∪ [-8, ∞).

Given interval is a union of two intervals.

The first interval denotes the set of all real numbers which are less than or equal to -11.

And the second interval denotes the set of all real numbers which are greater than or equal to -8.

The inequalities can be written as below:

(-∞, -11] ⇒ x ≤ -11 (or) -∞ < x ≤ -11

[-8, ∞) ⇒ x ≥ -8 (or) -8 ≤ x < ∞

And there is a union symbol between these two intervals.

So, x should satisfy both inequalities.

x ≤ -11 and x ≥ -8

or the above can be written as

-∞ < x ≤ -11 and -8 ≤ x < ∞

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The area of the triangle is 1200√5 cm².

Given that, the sides of the triangle are 70cm,80cm and 90cm.

We need to find the area of a triangle using Heron's formula.

As per Heron's formula, the value of the area of any triangle having lengths, a, b, c, perimeter of the triangle, P, and semi-perimeter of the triangle as 's' is determined using the below-given formula:

Area of triangle = √s(s-a)(s-b)(s-c), where s = Perimeter/2 = (a + b + c)/2

Now, semi perimeter = (70+80+90)/2=120

Area of triangle=√120(120-70)(120-80)(120-90)

=√120×50×40×30

=√40×3×2×25×40×30

=40×5√3×2×3×2×5

=40×5×3×2√5

=1200√5 cm²

Therefore, the area of the triangle is 1200√5 cm².

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Answer:

Step-by-step explanation:

perimeter of rectangular: 2(a+b)

we know from the graph, assume that a = 2x b = x+ 3

so the perimeter (C) in terms of x is C = 2(2x + x +3) = 6x + 6

well, tis noteworthy that whenever we have an absolute value equation is really a piece-wise function in disguise, namely the absolute expression is really two in disguise.

[tex]8x=2|6x-2|\implies \cfrac{8x}{2}=|6x-2|\implies 4x=|6x-2|\implies \begin{cases} 4x=+(6x-2)\\ 4x=-(6x-2) \end{cases} \\\\[-0.35em] ~\dotfill\\\\ 4x=+(6x-2)\implies 4x=6x-2\implies 0=2x-2 \\\\\\ 2=2x\implies \cfrac{2}{2}=x\implies \boxed{1=x} \\\\[-0.35em] ~\dotfill\\\\ 4x=-(6x-2)\implies 4x=-6x+2\implies 10x=2\implies x=\cfrac{2}{10}\implies \boxed{x=\cfrac{1}{5}} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill x= \begin{cases} 1\\[1em] \frac{1}{5} \end{cases}~\hfill[/tex]

Answer:

203 1/3  calories

Step-by-step explanation:

I make a proportion for inches of pizza to calories

[tex]\frac{6}{610}[/tex] = [tex]\frac{16}{x}[/tex]  I know that a 6 inch pizza has 610 calories, so I am trying to figure out how many calories are in a 16 inch pizza.

I can cross multiply to get

6x = (16)(610)

6x = 9760  Divide both sides by 6

x = 1626 [tex]\frac{2}{3}[/tex]  This is how many calories are in a whole pizza.  Now I want to know how many calories are in 1 slice.  I would take this number and divide by 8.

1626 2/3 as an improper fraction would be

[tex]\frac{4880}{3}[/tex] ÷ 8 Which is the same as

[tex]\frac{4880}{3}[/tex] x [tex]\frac{1}{8}[/tex] =[tex]\frac{4880}{24}[/tex]=203 [tex]\frac{1}{3}[/tex]

Length of the other leg is  13.23 inches.

Pythagoras theorem states that the square of the length of hypotenuse is equal to sum of the squares of other two legs.Hence if L is the length of the other leg in inches, then20^2=5^2+l^2

or

400=225+L^2

or

L^2=400−225=175

Hence L=√175=13.23

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The linear equation for both Uber and Lyft  will be Y = 0.75x + 3 and

Y = 0.5x + 5 .

A linear equation is an algebraic equation of the form y = mx+b. Involving only a constant and a first-order (linear) term, where m is the slope and b is the y-intercept. Occasionally, the above is called a "linear equation of two variables," where y and x are the variables.

Here we have,

Uber charge $3 fix on every trip and additional charges on per mile $0.75

So, linear equation be

Y = 0.75x + 3 where, x = no. of mile covered

Similarly, lyft charge $5 fix and $0.5 as an additional

So, linear equation be

Y = 0.5x + 5 where, x = no. of mile covered

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The slope of the lines containing the following points (-2, 1) & (-5,5) is [tex]\frac{-4}{3}[/tex].

As per the question statement, two points lie (-2, 1) & (-5,5) on a line.

We are supposed to find the slope of the line.

To solve this question, we need to know the formula to calculate the Slope of line passing through two points [tex](x_{1} ,y_{1} )[/tex] and [tex](x_{2} ,y_{2} )[/tex] which is given by

[tex]m=\frac{y_{2}-y_{1} }{x_{2}-x_{1}}[/tex]

Since given in the question statement, our concerned points are (-2, 1) & (-5,5), we can consider [tex][x_{1}=(-2)] , [x_{2}=(-5)], [y_{1}=1][/tex] and [tex][y_{2}=5][/tex].

Using these values into above mentioned formula, we get,

Slope (m) = [tex]\frac{5-1}{[(-5)-(-2)]}=\frac{4}{-3}=\frac{-4}{3}[/tex].

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The given algebraic expression 8x ia a one degree polynomial forming the straight line.

Polynomials are algebraic expressions with indeterminates and constants in them.

For the given  algebraic expression 8x;

As, the highest exponent of the variable part 'x' is 1 that is why the degree of the polynomial is one.

This implies that for every value of x there is a single value of value of functions.

This will form the straight line when graph is plotted for them.

Thus, the given algebraic expression 8x is called the one degree polynomial.

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The general term of the function is y = 4000 + 100x

The given parameters are

Guaranteed = $4000

Monthly raise = $100

Let the number of months be x, and the total earning be y

So, we have:

y = Guaranteed + Monthly raise * x

This gives

y = 4000 + 100 * x

Evaluate

y = 4000 + 100x

Hence, the general term of the function is y = 4000 + 100x

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The volume of the water filled in the cylinder A is 141.77  cm³.

A cylinder is a 3 solid that contains two parallel bases connected at a fixed distance by a curved surface.

The formula for the volume of the cylinder is;

Volume = πr²h

Where, π = 3.14,

radius r = 3 cm.

height h = 10 cm.

Put the values and obtain the volume.

Volume = (3.14)(3)²(10)

Volume = 282.74  cm³.

As, the cylinder is half filled with water;

Water volume = 282.74/2  cm³

Water volume = 141.77  cm³

Thus, the volume of water filled in cylinder A is 141.77  cm³.

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The correct question is-

Cylinder A has radius 3 cm and height 10 cm. Cylinder A is half full of water.

Work out the volume of water in Cylinder A.

On the 4th day of the school, the secret Quinten shared with his closest friend will be known to 16 persons.

A sequence in which the ratio of any term and its previous term is equal to a fixed constant called common ratio [r] is called geometric progression. For example -

3, 6, 12, 24, ... and so on.

Given that Quinten shares a secret with his friend and each person that hears the secret shares the secret with a new person each day.

On the first day only 2 people know the secret i.e. Quinten and his close friend. Now, they both will tell one new person on second day, which means that by the end of second day four persons will know the secret. Now, these four persons will share with new individual, this gives us a total of 8 persons, who knows the secret by the end of day three and so on.

Now, we get the following sequence -

2, 4, 8, ...... and on.

Now, we can clearly see that -

4/2 = 8/4 = 2

Therefore, this sequence is a geometric progression with common ratio

r = 2.

Assume the 4th term of GP is x. Therefore -

x/8 = 2

x = 16

Therefore, on the 4th day of the school, the secret Quinten shared with his closest friend will be known to 16 persons.

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Answer:

No

Step-by-step explanation:

If Q is the midpoint of PR, then PQ=QR.

[tex]5(x+2)=8x-3 \\ \\ 5x+10=8x-3 \\ \\ 3x=13 \\ \\ x=\frac{13}{3} \\ \\ \implies PQ=5\left(\frac{8}{3} +2 \right) \neq 36[/tex]

This means PQ + QR = PR isn't 72, and thus Q is not the midpoint of PR.

The ratio strength of the final product is 1:0.4.

One technique to indicate concentration is through ratio strength, which uses a ratio to characterize drug concentration. In this context, concentration is defined as the quantity of a solute that makes up one unit in the whole volume of a solution or combination. You should be an expert in ratio strength calculations as a pharmacy student. Ratio strength uses a ratio to describe the medication concentration. So, what it implies is, you have one unit of solute contained in the complete amount of preparation and so generally your ratio strength is expressed as one is to something. In the case of a weight-in-weight, volume-in-volume, or weight-in-volume situation, you would interpret a ratio of 1:2,000 differently.

Drug strength = 800mg

whole volume =2ltrs

The ratio of the solution in 1 ltr is = 400 mg

The ratio strength of the solutions is = 1:0.4

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The equation to represent the situation is given as $2h -$10 = 0

We have been given that

    Money earned by Shane for babysitting =  $8 per hour

    Money earned by Shane for walking dogs = $6 per hour

Let the number of hours spent by Shane be h hours

Tips she received for babysitting = $12

Tip she received for walking dogs = $10

Total amount earned by Shane for babysitting = $8*h + $12

Also Shane worked two more hours for walking dogs then the amount will be = 2*$6 = $12

Total amount earned by Shane for walking dogs = $6*h + $12 + $10

                                                                                  = $6h + $22

As she earned the same total amount of job the equation will be given as

  $8h + $12 = $6h + $22

  $2h -$10 = 0

Which is the required equation

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