When an object is thrown with an angle with horizontal, it makes projectile motion
It is given that angle of projectile was 25 degree
The formulas of projectile motion is as follows:
component of velocity at time t = Vxcos[tex]\alpha[/tex]
time of maximum height= vsin[tex]\alpha[/tex] /g
maximum height = (v sin[tex]\alpha[/tex] )^2/2g
horizontal range = v^2 sin2[tex]\alpha[/tex]/g
v is given to be 20 m/s
time of flight is given by v 2sin[tex]\alpha[/tex]/g
therefore, time of flight = 20 x 2x0.4226 /10 = 1.690 seconds
maximum horizontal range = 20 x 20 x 0.766/10 =30.641 meters
Disclaimer: The value of acceleration due to gravity is assumed to be 10 m/s^2 also the speed of velocity has no unit and hence m/s has been considered
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How can urban or rural infrastructure play a role in a community recreation?
Urban or rural infrastructure can play an important role in a community recreation because these infrastructure is used by people of the community for the recreational purpose.
How can urban or rural infrastructure play a role in a community recreation?Urban Community:
The density of population and networks of activities, the cities contain publics buildings as well as government buildings which have organized religion, commerce, social interactions. So these peoples and the buildings provide the focus for communities.
The Urban infrastructure consists of gas distribution, urban transport, primary health services and many other things.
Rural Community:
Agriculture is the main fundamental need for the rural areas people which forms the basis of rural economy. A farmer has to perform various agriculture activities for which he needs the cooperation of his family and usually need a very large area for the farming.
So we can conclude that Urban or rural infrastructure can play an important role in a community recreation because these infrastructure is used by people of the community for the recreational purpose.
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Is the following equation dimensionally correct?
P=√pgh.
where
P is pressure in units of Kg.m/s²/m².
p is density in units of Kg/m³.
g is gravitational acceleration in units of m/s².
h is height in units of m.
The correct answer is :
P = ρgh yields the hydrostatic pressure, which is accurate.
The pressure a liquid applies to nearby bodies when it is at rest is known as hydrostatic pressure.
Water at rest exerts a force known as hydrostatic pressure. It is caused by the water's continual pressure on the basement walls.
The force that blood applies to blood channel walls is a typical illustration of hydrostatic pressure.
Depending on the liquid's density ('ρ'), the height of the water column ('h'), and the acceleration caused by gravity ('g'), the hydrostatic pressure is indicated by the letter "P" of a liquid column.
Because of this, the parameters and the supplied equation P = gh are both accurate.
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II Two electrons are in the vicinity of a proton. The potential energy of the
proton is
-1.6 x 10-25 J. (a) What is the potential at the proton's position? (b) If one of
the electrons is 1.0 cm from the proton, what is the distance of the second
electron from the proton?
Please explain HOW to answer this(especially part B)
There are two electrons close to a proton. The proton's potential energy is
the energy possessed by a body by virtue of its position relative to others, stresses within itself, electric charge, and other factors.
9.216 x 10^-8 N
q1 = 1.6 x 10^-19 C
q2 = - 1.6 x 10^-19 C
r = 5 x 10^-11 m
A source of electrostatic force is
F = k q1 q2 / r^2
F = (5 x 10-11)2 / (9 x 109 x 1.6 x 10-19 x 1.6 x 10-19)
F = 9.216 x 10^-8 N
Due to the nature of the charges being in opposition to one another, this force is appealing.
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The surface of the pool table is ℎ=0.790 m from the floor.
The winner of the competition wants to know if he has broken the world speed record for the break shot of 32 mph (about 14.3 m/s ). If the winner's ball landed at a distance of =5.05 m from the table's edge, calculate the speed of his break shot 0. Assume friction is negligible.
At what speed 1 did his pool ball hit the ground?
The calculated velocity is 3.88 m/s
Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. In other words, velocity is a vector, whereas speed is a scalar value. The parameters of speed are time divided by distance. The most often used unit of speed in daily life is the kilometer per hour (km/h), or miles per hour in the US and the UK. The SI's unit of speed is the meter per second (m/s) (mph).
h = 0.5g*t² = 0.77 4.9t²
= 0.77\st²
= 0.1571
t = 0.396 seconds or fall.
Dx = Xo*t, or 5.15 meters.
Xo * 0.396 = 5.15
Break speed is X= 13 m/s.
V² = V² + 2g*h.
V² = 0 + 19.6*0.77
= 15.09
V = 3.88 m/s
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What is the mass of a 10.4 cm³ cube of lead.
The mass of a 10.4 cm³ is, approximately, 117.42 grams.
Explanation:Volume of the cube: 10.4 cm³
Now, let's look up the density of lead:
Density of lead: 11.29 g/cm³.
This value fo density tells us that 1 cm³ of lead has a mass of 11.29g. Hence, we can stablish the following rule of 3 to find the mass of our cube.
1 cm³ ----------------> 11.29 g
10.4 cm³------------> x
x= (10.4 cm³ ⋅ 11.29 g)/1 cm³
x= 117.42 g.
Conclusion.
The mass of a 10.4 cm³ is, approximately, 117.42 g.
Carrie has experienced brain damage to her left hemisphere. She will most likely experience difficulty with which ability?
A) putting a puzzle together
B) recognizing faces
C)judging time and rhythm
D)understanding sarcasm and irony
the tension T in Newtons in the string of a yoyo of mass 0.001kg is give by the function of two variables (see equation in photo).
find the approximate change in T if R increases from 4cm to 4.1cm and r increases from 0.8cm to 0.9cm. use your answer to explain if the tension increases or decreases.
The change in the tension if the radii r changes from 4.0 cm to 4.1 cm, and R changed from 0.8 cm to 0.9 cm is negative, therefore, tension reduces.
How can the correct description of the change in the graph of the function be found?
Mass of the yoyo = 0.001 kg
Initial value of the spindle radius, R = 4 cm
Initial length of the radius of the yo–yo, r = 0.8 cm
The final values are;
R2 = 4.1 cm, r2 = 0.9 cm
Which gives;
[tex]T_{r \:R} = \frac{0.001 \cdot g \cdot R }{2 \cdot r^{2} + R^2} [/tex]
Which gives;
[tex]T_{{r _1 \:R _1 }} = \frac{0.001 \times 9.8 \times 0.04 }{2 \times 0.008^{2} + 0.04²} = \frac{49}{216} [/tex]
[tex]T_{{r _2 \:R _2 }} = \frac{0.001 \times 9.8 \times 0.041 }{2 \times 0.009^{2} + 0.041^2} = frac{2009}{9215} [/tex]
Therefore;
[tex] \Delta T_{{r \:R }} = frac{2009}{9215} - \frac{49}{216} = - \frac{17591}{1990440} [/tex]
Given that difference between the final and the initial states is negative, the the value of the tension decreases
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Select the correct answer.
A force Fmaking an angle 9 with the horizontal is acting on an object resting on the table. Which statement Is true for the motion of sliding the
object on the table?
• A. It Is Independent of all the forces acting on the object.
O B. It depends only on the forces acting along the x-axis.
O C. It depends only on the forces acting along the y axis.
O D. It depends only on the normal force acting on the object.
O E. It depends only on the frictional force acting on the object.
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At the end of a race a runner decelerates from a velocity of 9.00 m/s at a rate of 0.300 m/s2.
(a) How far does she travel in the next 15.0 s?
(b) What is her final velocity?
(a)In the next 15.0s, she traveled 101.250 m.
(b) 4.50 m/s is the runner's final speed.
Given:- initial velocity = 9m/s , deacceleration = 0.3 m/s2
distana(d), she moves in time (t)=15 s,
and we must determine this using the second equation of motion.
S = ut + 1/2 at2,
where s = the distance
u = initial velocity
t = time
a=-d = 0.300m/s
t=15.0
By putting all values in the formula above,
we have
d = (9.00)x(15.0)-1/2 (0.300) (15.0)²
d= 101.250 m.
In the next 15.0s, she traveled 101.250 m.
final speed (v) =?
from 1 Equation of Motion : v = u+at.
To solve, v=?
u=9.00 m/s
a= -d= 0.300 m/s²
t=15.0
v=u+at
v= 9 - 0.300 X15.0
= 4.50 m/s
4.50 m/s is the runner's final speed.
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1. You are part of a new team of colleagues at work and you are trying to remember everyone's
name. What part of the brain would be responsible for making sure you know who everyone is?
a. Hippocampus
b. Hypothalamus
c. Amygdala
d. Thalamus
The part of the brain that would be responsible for making sure you know who everyone is Hippocampus; option A
What is the brain?The brain is the organ in the body which controls the function of other organs in the body.
The brain is made up of cells called neurons.
The brain is divide into three main parts namely:
the cerebrum,the brainstem, andthe cerebellumThe cerebrum consists of two cerebral hemispheres the outer layer called the cortex.
The brainstem consists of the medulla, pons, and midbrain.
The cerebellum consists of three lobes the anterior lobe, the posterior lobe and the flocculonodular lobe.
The hippocampus is part of the temporal lobe which controls recognition and dentification of people.
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You are asked to do an experiment to measure g. You set up a device that drops a metal ball from rest from a height of 1.650 meters. Using an accurate timing device that detects the release of the ball and it’s landing in the floor, you measure the average time of the falling ball to be 0.585 seconds. What do you measure the value of g as?
The value of g of the metal ball that falls from a height of 1.65 m at an average of 0.585 seconds is 4.82 m / s²
a = v / t
v = d / t
a = Acceleration
v = Velocity
d = Distance
t = Time
d = 1.65 m
t = 0.585 s
v = 1.65 / 0.585
v = 2.82 m / s
g = a = 2.82 / 0.585
g = 4.82 m / s²
Here the acceleration is called as g because the ball is falling vertically. That is why it is called as g ( Acceleration due to gravity )
Therefore, the value of g of the metal ball that falls from a height of 1.65 m at an average of 0.585 seconds is 4.82 m / s²
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a body of mass 7.5kg is moving with the velocity of 1.2, if a force of 15newton is applied to the body calculate its velocity after 2 seconds
The velocity is 5.2 m/s
Force as per the Newton's second law of motion is defined as, for constant mass, mass times the acceleration
F= m x a
where m is the mass of the body in kilograms and a is the acceleration is m/s^2
Now we know that acceleration is nothing but rate of change of velocity
i.e. a= (v -u)/t
where v is the final velocity
u is the initial velocity
and t is the time frame in which change takes place
Now the data given to us is as follows:
Force F= 15 Newton
initial velocity u =1.2 m/s
t= 2 seconds
We are required to find the final velocity v
Now putting the values in the equation,
F= m (v-u)/t
15 = 7.5 (v-1.2)/2
30= 7.5v -9
7.5v=39
v=39/7.5= 5.2 m/s
Hence the velocity is 5.2m/s
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A reconnaissance plane flies 512 km away
from its base at 742 m/s, then flies back to its
base at 1113 m/s.
What is its average speed?
Answer in units of m/s.
Answer in units of m/s
The average speed of round trip is 1192.8 m/s
Average speed of the round trip is
2*994*1491/(994+1491)
= 1192.8 m/s
The overall distance the object covers in a given amount of time is its average speed. A scalar value represents the average speed. It has no direction and is indicated by the magnitude.The mean value of a body's speed over a period of time is its average speed. Since a moving body's speed is not constant over time and fluctuates, the average speed formula is required. The numbers of total time and total distance travelled can be used even with fluctuating speed.Learn more about average speed at:
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1. A bullet is fired into a tree trunk (Figure 1.12), striking it with an ini- tial velocity of 350 m/s. If the bullet penetrates the tree trunk to a depth of 8.0 cm and comes to rest, what is the acceleration of the bullet?
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Raoul and Maria set out walking from their aunt's house. Raoul walks a certain distance straight east and then a certain distance straight north. A crow passing overhead starts from the same point as Raoul, but flies in a straight line. Raoul observes that the crow flies a total distance of 500 m in a direction 35° north of east to reach the same final point as Raoul. Maria starts from the same point as Raoul, but she walks first straight west and then straight south. Her final point is 700 m from the starting point in a direction that is 55° south of west. How far did Raoul walk on the east leg of his trip? How far on the north leg? Similarly, how far did Maria walk on the west leg and how far on the south leg? Express these quantities in terms of displacement vectors and their components, using a coordinate system with the +x axis pointing east and the +y axis pointing north.
Answer:
no entiendo tu pregunta
A 50-cm-long spring is suspended from the ceiling. A 210 g mass is connected to the end and held at rest with the spring unstretched. The mass is released and falls, stretching the spring by 16 cm before coming to rest at its lowest point. It then continues to oscillate vertically.
The value of spring constant (k) is 25 N/m.
Conservation of energy, potential energy of a stretched spring, gravitational potential energy, frequency of oscillation in a spring coupled to a mass, and variation of acceleration due to gravity with altitude are the principles necessary to answer the given problem.
To begin, use energy conservation to equal change in gravitational potential energy on mass attached to spring and elastic potential energy of stretched spring. Then, in the equation, substitute the specified numbers and solve for the spring constant. Then, calculate the amplitude by taking half of the value of spring stretching from equilibrium, and the frequency of oscillation by using the calculation for frequency of oscillation in a stretched string in terms of mass and spring constant.
Formula apply
U=mgh
U=1/2kx^2
putting the value of K ,x ,mass and g then
k is 25N/m
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What is the escape speed from the Moon?
The Moon’s mass is 7.4×10^22 kg and its radius is 1700 km.
The speed of a spacecraft moving in a circular orbit just above the lunar surface: v = 1700 m/s
Express your answer using two significant figures.
v = __________ m/s
Answer:
1/2 m v^2 - G M m / R escape velocity equal to energy at surface
v^2 = 2 G M / R = 2 * 6.67E-11 * 7.4E22 / 1.7E6
v^2 = 2 * 6.67 * 7.4 / 1.7 * 105 = 5.81E6
v = 2410 m/s = 2400 m/s
Which option best describes the average acceleration from 40 to 70 s?
C. The average acceleration is positive and smaller in magnitude than the initial acceleration.
What is average velocity?Average velocity is defined as the change in position or displacement (∆x) divided by the time intervals (∆t) in which the displacement occurs.
a = Δv/Δt
where;
Δv is change in velocityΔt is change in timea = (250 - 248) / (70 - 40)
a = 0.067 m/s²
Thus, we can conclude that the average acceleration is positive and smaller in magnitude than the initial acceleration.
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1.
A car is driving on a circular track tha has a diameter of 6km and
traveled across the black shaded region in 1 hour. What will the
cars velocity be in meters/seconds. 1 km= 1000 meters
6 km
V=²& D=vt T = ²
The velocity of the car moving in the circular path is determined as 1.67 m/s.
What is linear velocity?Linear velocity is the measure of the rate of change of displacement with respect to time when the object moves along a straight path.
v = d/t
where;
d is the distance of the objectt is time of motionv = (6 x 1000 m) / (1 x 3600 s)
v = 1.67 m/s
Thus, the velocity of the car moving in the circular path is determined as 1.67 m/s.
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Sasha is measuring the rate of heat energy given off by an incandescent light bulb. The theoretical value is 55.4 watts. Her measurement has a 2.17 error. Which of the following values may have been Sasha's measurement? (Choose all that apply)
A. 1.20 watts
B. 54.2watts
C.56.6watts
D.53.23watts
E. 57.57watts
The measurement of Sasha, given the data from the question is 57.57 watts (Option E)
How to determine Sasha's measurementThe following data were obtained from the question:
Theoretical value = 55.4 wattsAbsolute error = 2.17 wattsSasha' measurement =?To obtain Sasha's measurement, we shall determine the experimental measurement. This is illustrated below:
Absolute error = Experimental measure - theoretical measurement
2.17 = Experimental measure - 55.4
Collect like terms
Experimental measure = 2.17 + 55.4
Experimental measure = 57.57
Thus, we can conclude that Sasha' measurement is 57.57 watts (Option E)
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Applying a constant net force to an object causes it to accelerate at 0=9.0 m/s2.
What will the acceleration 3 of the object be if the force is doubled and the mass is doubled?
The acceleration of the object be if the force is doubled and the mass is doubled is equal to 9m/s².
let the initial mass of the object be m₁.
given:
initial acceleration (a₁) = 9m/s²
initial constant force (F₁) = constant (k)
therefore,
F₁= m₁×a₁ ------------------------------- equation 1
now,
according to the the question the force is doubled
i.e.
new force (F) = 2×F₁
and the mass too is doubled,
i.e.
new mass of the object(m)=2×m₁
new equation for force and acceleration:
F= m ×a
2F=2m₁×a --------------------------equation 2
dividing equation 2 by equation 1
we get,
[tex]\frac{2F}{F}=\frac{2m₁×a}{m₁×a₁ }[/tex]
a = a₁
a=9m/s²
the acceleration of the object be if the force is doubled and the mass is doubled is equal to 9m/s².
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Rattlesnake Frequency A timber rattlesnake (Crotalus horridus) shakes its rattle at a characteristic frequency of about 3100 shakes per minuteWhat is this frequency in shakes per second?
Answer:
See below
Explanation:
31 00 sh / min / 60 s / min = 51 2/3 shakes per second
5.
In 1934, the wind speed on Mt. Washington in New Hampshire reached a record high.
Suppose a very sturdy glider is launched in this wind, so that in 45s the glider reaches the
speed of the wind. If the glider undergoes constant acceleration of 2.29m/s², what is the
wind's speed? Assume the glider is initially at rest.
The Speed of wind will be 103.5 m/s.
It is stated in the question that a glider is launched into the wind and in 45 seconds it attains the speed of the wind. Also, It is given that it attains a constant acceleration of 2.29m/s² and it starts moving from a state of rest.
We know the relation between velocity, time, and acceleration can be represented by Newton's first equation: v = u + at
where, v = Final velocity, u = Initial velocity, a = Acceleration, and t = Time
In this case, we have to find the final velocity of the glider to know the speed of the wind, and u = 0, a = 2.29m/s², t = 45sec
Putting values in the equation we get :
=> v = 0 + (2.29)*45
=> v = 103.5
Hence, the Speed of wind will be 103.5 m/s
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If a dolphin swims at 1.85 m/s, how far will the dolphin have traveled after 6.0 s?
The distance traveled by by the dolphin is determined as 11.1 m.
What is distance?The distance traveled by an object is the product of speed and time of motion of the object. It measures the total path covered by the object.
The distance traveled by by the dolphin is calculated as follows;
Distance = speed x time of motion
Distance = 1.85 m/s x 6 s
Distance = 11.1 m
Thus, the distance traveled by by the dolphin is determined as 11.1 m.
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Two birds are flying south for the winter. Bird 1 reaches its destination in 6 hours, while bird 2 reaches its destination in 12 hours. If bird 2 covers twice as much distance as bird 1, what is the ratio of their average speeds (bird 1/bird 2)?
1.0
0.8
1.2
0.5
The correct answer is option ( A) the ratio of their average speeds (bird 1/bird 2) is 1.0
velocity = distance / Time
Let us assume distance covered by Bird 1 = d
case 1 (Bird 1) :-
time = 6 hours
velocity(Bird1) = d/6 = 0.167*d
case 2 (Bird 2) :-
time = 12 hours
distance is twice of Bird 1 = 2d
velocity(Bird2) = 2d/12 = 0.167*d
now, velocity of Bird1/Bird2 = (0.167*d)/(0.167*d) = 1.0
So,velocity of (Bird1/Bird2) is 1.0 .
Average velocity / Average speed = Total displacement / Total distance. Remember that the numerator is less than or equal to the denominator. As a result, the ratio is always equal to or less than one. Distance traveled divided by time taken is the most commonly used formula for calculating average speed. The other formula is to add the initial and final speeds together and divide by two.
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The actual mass of a metal sphere was reported in the manual catalog to be 3.53 kg.
A group of 4 students were assigned to perform an experiment and measure the mass of the sphere each one of them using a different scale or balance.
Student 1 reported 3.6 kg
Student 2 reported 3.5 kg
Student 3 reported 3.12 kg
Student 4 reported 3.476 kg
Which of the four students reported the most precise measurement?
1. Student 1
2. Student 2
3. Student 3
4. Student 4
The student that gave the most precise measurement is student 2.
What is a precise measurement?A precise measurement is one that is close together especially when we have a replicate measurement. The measurements that are close together are said to be presence. A measurement is accurate when the measurement is quite close to the true value. Precision ad accuracy are very important in a measurement.
In this case, let us consider the measurement of each student;
Student 1 reported 3.6 kgStudent 2 reported 3.5 kgStudent 3 reported 3.12 kgStudent 4 reported 3.476 kgWe can see that the student that gave the most precise measurement is student 2.
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76. Two electric charges -6μC and
+6μC are placed respectively in two
points A and B distant of 1m apart. The
electric field is null at the point C:
A.Located in the middle of the
segment AB
B.Located outside segment AB at
1m from A.
C.Located outside segment AB at
1m from B
D.Outside the line AB
E.No answer is right.
The correct answer is option (A) Located in the middle of the segment AB the electric field is null at the point C .
When a positive and negative charge interact, their forces act in the same direction, from positive to negative. As a result, opposite charges attract each other: the electric field and forces generated by two electrical charges of opposite polarity.
The two charges are to each other.The electric field will not be zero between two opposite charges. For opposite charges, the point of zero electric fields will lie outside the system along the line joining attracted the two charges.The field is strongest where the lines are closest together. The electric field lines converge toward charge one and away from charge two, indicating that charge one is negative and charge two is positive.
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Part A
What is the instantaneous velocity of a freely falling object 5.0 s after it is released from a position of rest?
Express your answer to two significant figures and include the appropriate units.
v=
The instantaneous velocity of a freely falling object is 49.0 m/s
the instantaneous velocity is calculated by the first equation of the motion that is v = u + at here u = initial velocity and a is acceleration and t is time since its freely falling object the acceleration is acceleration due to gravity that is 9.8 m/s and the initial velocity is 0m /s the time given is 5 sec so putting it into equation 0+ 9.8X 5= 49.0 m/s
The instantaneous velocity of an object is the limit of the average velocity as the elapsed time approaches zero, or the derivative of x with respect to t: v ( t ) = d d t x ( t ) . v ( t ) = d d t x ( t ) . Like average velocity, instantaneous velocity is a vector with dimension of length per time.
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what type of force os your answer in number 4?
The electromagnetic force, the weak nuclear force, the strong nuclear force, and gravity.
The strong force, weak force, electromagnetic force, and gravitational force are the four fundamental forces operating in the universe. They each operate within different parameters and have unique strengths. Although gravity has an infinite range, it is the weakest force. Although it has an infinite range, the electromagnetic force is much stronger than gravity. The weak and strong forces are dominant only at the level of subatomic particles and are only effective over very small distances. Even though it has a weaker name than gravity, the weak force is actually the weakest of the three. The strongest of the four fundamental interactions is the strong force, as its name suggests.
Actually, out of the four fundamental forces, gravity is the weakest. The four forces are the electromagnetic force, gravity, the weak nuclear force, and the strong nuclear force, in that order.
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The speed of a train increases from 100 km/hr to 250 km/hr in 5 minutes. What is its acceleration?
Answer:30 km/hr2 is the exal
Explanation: