Which function has a horizontal asymptote of y = 3?
f(x) = 3(2x)
f(x) = 2(4)x–3
f(x) = 2(3x)
f(x) = 2(4x) + 3

The matrix M is:

M = [8 -2]

[1 0]

This satisfies the relation [an] = [an-1] * M.

The matrix M is determined by the recurrence relation. The first row of the matrix represents the coefficients of an and an-1 in the expression for an+1, and the second row represents the coefficients of an-2 and an-3.

Here, in the recurrence relation an+1 = 8an - 2an-1, the coefficient of an is 8 and the coefficient of an-1 is -2, so the first row of the matrix M is [8 -2].

Similarly, the second row of the matrix represents the coefficients of an-2 and an-3 in the expression for an-1. However, in the recurrence relation, there is no explicit expression for an-2 and an-3, so we set them to zero in the second row of the matrix, giving [1 0].

Thus, the matrix M is:

M = [8 -2]

[1 0]

This satisfies the relation [an] = [an-1] * M.

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Dani can walk around the track 8 times.

In mathematics, "inequality" refers to a relationship between two expressions or values that are not equal to each other. To solve the inequality, you may multiply or divide each side by the same positive number, add the same amount to each side, take the same amount away from each side, and more. You must flip the inequality sign if you multiply or divide either side by a negative number.

Dani wants to spend less than 1 hour at the gym.

She will spend 20 minutes lifting weights and then will walk around the indoor track.

It takes her 4.5 minutes to walk around the track.

The number of times that Dani can walk around the track,

< (60 - 40)/4.5

< 40/4.5

< 8.9

Therefore, she can walk around 8 times around the track.

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The vehicle going at 60 mph travelled 88 feet in one second

An equation is an expression that shows the relationship between two or more numbers and variables using mathematical operations. An equation can be linear, quadratic, cubic and so on, depending on the degree of the variable.

Speed is the ratio of distance to time taken. It is given by:

Speed = distance / time

If a vehicle is going 60 mph.

1 second = 1/3600 hr

Therefore in one second:

Speed = distance / time

60 mph = distance / (1/3600)

distance= 60 * 1/3600 = 1/60 miles

1 mile = 5280 feet

1/60 miles = 1/60 miles * 5280 feet per mile = 88 feet

The vehicle travelled 88 feet

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Due to length restrictions, we kindly invite to check the explanation for further detail on how to complete a maze with trigonometric functions.

In this question we must go through a maze formed by 16 squares, fifteen of them with cases of right triangles, we must apply trigonometric functions to complete the maze. To complete this task, we need to use the following trigonometric function:

sin θ = y / √(x² + y²)

cos θ = x / √(x² + y²)

tan θ = y / x

Where:

Now we proceed to show how deal with the maze:

Step 1:

x = 19 · cos 28°

x = 16.78 (LEFT)

Step 2

x = 39 / tan 59°

x = 23.43 (LEFT)

Step 3:

x = 31 · sin 71°

x = 29.311 (RIGHT - DOWN)

Step 4:

x = 12 · tan 25°

x = 5.600 (RIGHT)

Step 5:

x = 27 / sin 48°

x = 36.332 (RIGHT)

Step 6:

x = 38 / cos 14°

x = 39.163 (DOWN - LEFT)

Step 7:

x = 16 · cos 54°

x = 9.405 (RIGHT)

Step 8:

x = 29 / tan 74°

x = 8.316 (DOWN)

Step 9:

x = 17 · sin 42°

x = 11.375 (LEFT)

Step 10:

x = 47 · tan 29°

x = 26.052 (LEFT)

Step 11:

x = 31 / sin 63°

x = 34.792 (LEFT)

Step 12:

x = 24 / cos 51°

x = 38.136 (UP)

Step 13:

x = 46 · tan 31°

x = 27.640 (RIGHT)

FINISH

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Answer:

n =1/2

Step-by-step explanation:

24n + 60 = 72

24n = 72 - 60

24n = 12 /24

n = 1/2

Answer:

n=1/2

Step-by-step explanation:

24n+60=72

24n=72-60

24n=12

n=12/24

n=1/2

Answer: Q is the answer.

Step-by-step explanation:

Answer:

y'=|x-5|-1

Step-by-step explanation:

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The value of 'B' in the table is 45.

Data refers to the elements that make up persons, things, events, and ideas.

It could be an integer, a title, or anycast. Data must be tabulated after collection in order to study their prominent characteristics.

The presentation of data is the name given to such a configuration.

Bar Chart, Histogram, Line Graph, Pie Chart, Frequency Distribution Table.

Given, A three-column table.

Part     A    C     D

Part    30   36   46        

Whole B    54   69

In D it is 23×2 and 23×3.

Similarly, in C it is 18×2 and 18×3.

Therefore, In A it is 15×2 and 15×3 = 45.

the value of B in the table is 45.

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An inequality to represent the regular price of snacks, if i can buy using the coupon, x ≤ $13

Inequalities are the comparison of mathematical expressions, whether one quantity is greater or smaller in comparison to another quantity.

We use these symbols to represent inequalities, '>' , '<', '≥', '≤'

Given that,

There are two coupons available, $8 and a $5 off on buying snacks

Let's call the regular price of the snacks "x".

Since you have a $5 off coupon,

the price you would actually pay would be x - $5.

And since you only have $8, the price you pay for the snacks cannot be greater than $8:

x - $5 ≤ $8

Adding $5 to both sides:

x ≤ $13

So, the regular price of the snacks must be less than or equal to $13 if you want to use the coupon and still have enough money to pay for them.

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The respective units in the statements above are kg, L,cm

A unit of measurement is a definite magnitude of a quantity, defined and adopted by convention or by law, that is used as a standard for measurement of the same kind of quantity.

Given here: Different quantities

a) Boris saw an elephant and its mass is mentioned.

Now we know,The Metric System of Measurements uses the mass units: gram (g), kilogram (kg) and tonne (t).

Thus the mass of the elephant is 4000 kg/tonne(t)

b) Greg used some volume of liquid in the shower

Now the units of liquid primarily used daily life is liters

Thus Greg used about 130 L of water

c) "The spacebar on the keyboard " in this statement the emphasis is on length and we know the units of length are m, cm etc.

Thus the length of the spacebar on the keyboard is 11 cm long.

Hence, The respective units in the statements above are kg, L,cm

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The [tex]& r_x(h)+r_y(h) \\[/tex] mean and autocovariance functions are free of t , the process [tex]$\left\{X_t+Y_t\right\}$[/tex] is stationary.

Solution: [tex]$\left\{x_t\right\} \&\left\{y_t\right\}$[/tex] are uncorrelated stationary process i.e.[tex]$x_\gamma \& I_s$[/tex] ax uncorrelated for every r and s process [tex]$\left\{x_t+y_t\right\}$[/tex] is stationary.

The sum of the autocovariance functions of {[tex]x_{t}[/tex]} and {[tex]y_{t}[/tex]}.

The autocovariance function (ACF) is defined as the sequence of covariances of a stationary process. That is suppose that {Xt} is a stationary process with mean zero, then {c(k) : k 2 Z} is the ACF of {Xt} where c(k) = E(X0Xk). Clearly different time series give rise to different features in the ACF.

⇒Var[tex]& \left(X_t+Y_t\right)={Var}\left(X_t\right)+{Var}\left(Y_t\right) \\[/tex]

⇒[tex]& E\left(X_t+Y_t\right)=\mu_x+\mu_y \\[/tex]

⇒[tex]& r_{x+y}(h)={cov}\left(X_{t+h}+Y_{t+h}, X_t+Y_t\right) \\[/tex]

[tex]& ={cov}\left(X_{t+h}, X_t\right)+{cov}\left(Y_{t+h}, Y_t\right)+0 \\[/tex]

[tex]& =r_x(h)+r_y(h) \\[/tex]

Since, the mean and autocovariance functions are free of t , the process [tex]$\left\{X_t+Y_t\right\}$[/tex] is stationary

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Answer:

$168.75

Step-by-step explanation:

If you need this for 7 and a half hours, start off by multiplying 22.50 by 7.  

22.50 x 7 = 157.5

Now find half of 22.50 to account for the half.  

22.50/2 = 11.25

Finally, add 157.5 and 11.25, and that should be your answer.  :)

157.5 + 11.25 = $168.75

I hope this helped!! :)

The solution to the system of inequalities is following as y ≤ -4 ;y ≤ - x + 4

Inequality is defined as mathematical statements that have a minimum of two terms containing variables or numbers that are not equal.

As per option (A), we have the system of inequality as follows:

y ≤ -4

y ≤ - x + 4

The region is above the graph, hence our inequality should be y ≤ - x + 4

The inequality sign part comes from visible the graph, the line is drawn using a dashed line, hence the line is included in the region.

Thus, this graph corresponds to a system of inequalities which is the correct answer that would be option (A).

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The call to selection causes the statement of algorithms of the  elements[minded] = temp; in line 19 of the method to be executed three times.

The declared array is 30 40 10 50 20; int [] err; The selection Sort method would be used to sort the array shown above. Flip the numbers 10 and 30 around. Move the numbers 20 and 40 around. exchange the new position of 40 for the number 50. Consequently, line 19 of the selection Sort algorithm would be run three times. Anyone static can access the method because it has the access specifier public. Accessing static members in this situation is independent of the object. This means that the method returns a void or nothing at all. A grouping of homogeneous (same type) components is known as an array. Option "B" is the appropriate way to provide a two-dimensional array into a function in the computer language; the following options are incorrect:

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The solution of the initial value problem is y = -3x/(3㏑x - 1)

An initial value problem is a differential equation in which the initial value of the function is given.

Since we have the initial value problem

y' = (xy + y²)/x² , y(1) = 3.

We see that it is a homogeneous differential equation.

A homogeneous differential equation is a differential equation in which the powers of x and y are the same.

So, we proceed to solve the equation as folows.

Let y = vx.

So,

So, substituting these two into the differential equation, we have that

y' = (xy + y²)/x²

dy/dx = (xy/x² + y²/x²

xdv/dx + v = y/x + (y/x)²

xdv/dx + v = v + v²

xdv/dx = v²

Now using the method of separation of variables, we have that

dv/v² = dx/x

Integrating both sides, we have that

∫dv/v² = ∫dx/x

-v⁻¹ = ㏑x + C

-1/v = ㏑x + C

Substituting v = y/x into the equation, we have that

- 1/y/x = ㏑x + C

-x/y = ㏑x + C

So, making y subject of the formula, we have that

y = -x/(㏑x + C)

Since y(1) = 3, we have that

3 = -1/(㏑1 + C)

3 = -1/(0 + C)

3 = -1/C

C = -1/3

So, y = -x/(㏑x + (-1/3))

y = -x/(㏑x - 1/3)

y = -x/(3㏑x - 1)/3

y = -3x/(3㏑x - 1)

So, the solution is y = -3x/(3㏑x - 1)

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The sampling method being used is given as follows:

Systematic sampling.

Samples may be classified as:

Hence in this problem we have a systematic sample with k = 15.

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Answer:

Option A.

Step-by-step explanation:

Answer:

33

Step-by-step explanation:

The highest number is 50 and the lowest number is 17.

50 - 17 = 33

The population after seven years is  12301

The velocity is 194 m/s

The acceleration is 126 m/s^2

We know that we need to use the equation that can be written by the value that says that;

P = Poe^rt

P = population at time t

Po = Initial population

t = time

r = population growth rate

We now have that;

3Po =Poe^11r

3 = e^11r

r = ln3/11

r = 0.0998

In the next seven years;

P = 6117e^0.0998* 7

P = 12301

Then we have the equation;

s(t) = 7t^3 + 5t + 9

v(t) = 21t^2 + 5

at t = 3

We have 194 m/s

Then also;

a(t) = 42t

At t = 3

We have 126 m/s^2

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The point $p$ has coordinates such that the ratio of the distances $ap$ to $pb$ is $1$ to $3$.

To find the coordinates of point $p$ along the directed line segment $ab$, we will use the ratio of $ap$ to $pb$ being $1$ to $3$. First, we need to find the length of $ap$ and $pb$. To do this, we will use the formula for the distance between two points: [tex]$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$[/tex]. We know the coordinates for points $a$ and $b$, so we can plug them into the formula to find the length of $ab$, which is $d_{ab}$. We can then use the ratio of $1$ to $3$ to find the lengths of $ap$ and $pb$. $d_{ap}=\frac{1}{4}d_{ab}$ and $d_{pb}=\frac{3}{4}d_{ab}$. We can then use the formula for the distance between two points again, this time with the coordinates of $a$ and $p$, to find the coordinates of $p$. Finally, we can plug the coordinates of $p$ back into the formula to check if the ratio of $ap$ to $pb$ is indeed $1$ to $3$.

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In this case, with a standard deviation of 8 and a Z-score of 1.96 (which represents the 95th percentile), the interval would be from 85 - (8 * 1.96) to 85 + (8 * 1.96), or approximately 69 to 101.

A normal distribution of standardized test scores with a mean of 85 and a standard deviation of 8 has an approximately 95 percent of scores that fall between two points on the distribution. These points are commonly referred to as the "margin of error" and are used to create a confidence interval around the mean. To find the interval, we use the standard deviation and the Z-score to determine the number of standard deviations away from the mean the interval bounds lie. In this case, with a standard deviation of 8 and a Z-score of 1.96 (which represents the 95th percentile), the interval would be from 85 - (8 * 1.96) to 85 + (8 * 1.96), or approximately 69 to 101. This means that if the test scores are normally distributed, approximately 95 percent of the scores will fall between 69 and 101.

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Modal interval is discussed below.

Statistics is the science concerned with developing and studying methods for collecting, analyzing, interpreting and presenting empirical data.

Given is the modal interval.

        MODE = [tex]$L + h\frac{(f_{m} -f_{1}) }{(f_{m} -f_{1} ) + (f_{m} - f_{2} )}[/tex]

Therefore, Modal interval is discussed above.

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Answer:

False

Step-by-step explanatio

its like saying

398

399

3100.

makes no sense

The receiving and giving money, gifts, and other types to get a favor from the government or from an institution or from an organization is amounts to bribe which is not an ethical practice.

The magnitude of the corruption in the form of a bribe may vary from the place of practice that is in situations where it has taken place.

This practice of taking bribe is considered to be an immoral act and it is punishable under the Foreign Corrupt Practices Act (FCPA) which became law in 1977 in the USA.

The main aim of the Act is to fight bribery and corruption from foreign countries and the US government as used by this law to control the unethical practice.

Types of bribery:

Active bribery

Passive bribery

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The solution of the complex function is ( 71- 8i ) / (16 +8i).

The area of mathematical analysis that studies functions of complex numbers are known as complex analysis, often known as the theory of functions of a complex variable.

Given that the function is ( 2 -7i) / ( 4 - 9i). The complex function will be solved as below:-

E = ( 2 -7i) / ( 4 - 9i)

E = ( 2 -7i) x ( 4 + 9i ) / ( 4 - 9i) x ( 4 + 9i )

E = ( 8 - 8i + 63 ) / ( 4 - 9i )²

E = ( 71 - 8i ) / ( 16 - 8i )

Therefore, the solution of the complex function is ( 71- 8i ) / (16 +8i).

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The number of wild mustangs in Utah and Nevada are 2745 and 18985

respectively.

An equation of degree one is known as a linear equation.

A linear equation of two variables can be represented by ax + by = c.

From the given information let the number of wild mustangs in Utah be 'x'

So, The number of wild mustangs in Nevada is 6x + 2515.

Therefore, x + 6x + 2515 = 21730.

7x = 21730 - 2515.

7x = 19215.

x = 19215/7.

x = 2745.

So, The number of wild mustangs in Utah is 2745 and hence the number of wild mustangs in Nevada is 6×2745 + 2515 = 18985.

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The correct statement regarding the exponential function in this problem is given as follows:

B. This table represents exponential growth because as the number gets bigger, so does the total number overall.

The situation is modeled with an increasing exponential function, which has the format presented as follows:

y = ab^x.

In which:

The rate of change for this problem is given as follows:

b = 5.

As the absolute value of the rate of change is greater than 1, the exponential function is a growth function.

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The lengths of the segments formed by two secants are proportional to the distances of the points where the secants intersect the circle from the center of the circle.

If we denote the lengths of the two segments as x and y, and the distance between the center of the circle and the point of intersection of the secants as d, then x/y = d1/d2, where d1 and d2 are the distances between the center and the points of intersection of the secant with the circle.

When two secants intersect a circle at two distinct points, the lengths of the segments formed by the two secants are proportional to the distances between the center of the circle and the points of intersection. This is because the two segments are radii that connect the center of the circle to the points of intersection of the secants with the circle.

The proportionality between the lengths of the segments and the distances from the center can be expressed mathematically as x/y = d1/d2, where x and y are the lengths of the two segments, d1 and d2 are the distances between the center and the points of intersection of the secants with the circle, and x/y represents the ratio of the lengths of the two segments.

So, as the distances from the center to the points of intersection increase, the lengths of the segments will also increase in the same ratio. And if the distances from the center decrease, the lengths of the segments will decrease in the same ratio.

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