Which equation matches the graph of the greatest integer function given below?

Answer:

10°C

Step-by-step explanation:

F = 50

C = 5/9 * (F - 32) = 5/9 * (50 - 32) = 5/9 * 18 = 5 * 2 = 10

The quadrilateral A'B'C'D' is the result of reflecting and translating the quadrilateral ABCD.

In this problem we find a representation of a quadrilateral and its image on a Cartesian plane. That image is the result of the following rigid transformations, that is, transformations applied on geometric loci such that Euclidean distance is conserved at every point of the locus.  

After a careful inspection, we find that the following two rigid transformations were done:

Now let is prove this steps:

Given: A(x, y) = (- 5, - 7), B(x, y) = (- 5, - 2), C(x, y) = (- 3, - 4), D(x, y) = (- 3, - 7)

Reflection:

A''(x, y) = (- 5, - 7) + (0, 14)

A''(x, y) = (- 5, 7)

B''(x, y) = (- 5, - 2) + (0, 4)

B''(x, y) = (- 5, 2)

C''(x, y) = (- 3, - 4) + (0, 8)

C''(x, y) = (- 3, 4)

D''(x, y) = (- 3, - 7) + (0, 14)

D''(x, y) = (- 3, 7)

Translation

A'(x, y) = (- 5, 7) + (7, 0)

A'(x, y) = (2, 7)

B'(x, y) = (- 5, 2) + (7, 0)

B'(x, y) = (2, 2)

C'(x, y) = (- 3, 4) + (7, 0)

C'(x, y) = (4, 4)

D'(x, y) = (- 3, 7) + (7, 0)

D'(x, y) = (4, 7)

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The variance and standard deviation for the frequency of pupils per teacher in some states of US is; Variance= 4.62 = 4.6 and Standard Deviation = 2.14 = 2.1

Variance(σ²) is a measure of dispersion. A measure of dispersion is a quantity that is used to check the variability of data about an average value. Data can be of two types - grouped and ungrouped. When data is expressed in the form of class intervals it is known as grouped data.

The standard deviation(σ) of a random variable, is the square root of its variance. It is algebraically simpler, though in practice less robust, than the average absolute deviation.

That means;

Standard Deviation = √variance.

For the given data the sum of frequencies = 1+16+11+7+1+2= 38.

Midpoint is 12,15,18,21,24,27.

ni x mi = 12,240,198,147,24,54.

Sum of ni + mi = 675.

Mean (u) =  17.76

mi - u is -5.76,-2.76,0.24,3.24,6.24,9.24.

(mi - u)² is 33.17,7.61,0.057,10.49,38.93,85.37.

Sum of (mi - u)² = 175.62.

Variance = Sum of (mi - u)² / sum of frequencies

= 175.62/38

= 4.62 = 4.6.

Standard deviation = √variance.

= √4.62

= 2.14 = 2.1.

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The linear equation would be y = 18 - 4x which represents the distance Jordan still has to walk after x hours.

The y-intercept represents the total distance Jordan has to walk.

Distance is defined as the product of speed and time.

We have to determine the distance.

So distance = speed× time

Given that his speed is 4 mph and x hours of walking, then:

So distance = 4 × x

Let it Start of the trail: 0 miles

And the end of the trail: 18 miles​

The trail length is 18 miles, so if he walked 1 mile, 18 - 1 = 17 miles are left, in general:

⇒ y = 17 - 4(x)

Here y would be the distance Jordan still has to walk.

The y-intercept would be if substitute x = 0, then:

⇒ y = 17- 4(0)

⇒ y = 17

This represents the total distance Jordan has to walk

Hence, the linear equation would be y = 18 - 4x which represents the distance Jordan still has to walk after x hours.

The y-intercept represents the total distance Jordan has to walk.

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x = -3 a possible solution for |x| = 3, |–x| = 3 and –|x| = –3.

Here, we are given 6 equations and we need to check for which of the following, x = -3 is a solution.

Let us look at each equation one by one,

1. |x| = 3

if x = -3

|-3| = 3

3 = 3

Hence, -3 is a solution to this equation.

2. |x| = –3

if x = -3

|-3| = -3

3 ≠ -3

Hence, -3 is not a solution to this equation.

3. |–x| = 3

if x = -3

|3| = 3

3 = 3

Hence, -3 is a solution to this equation.

4. |–x| = –3

if x = -3

|3| = -3

3 ≠ -3

Hence, -3 is not a solution to this equation.

5. –|x| = –3

if x = -3

-|3| = -3

-3 = -3

Hence, -3 is a solution to this equation.

4. –|x| = 3

if x = -3

-|3| = 3

-3 ≠ 3

Hence, -3 is not a solution to this equation.

Thus, equations |x| = 3, |–x| = 3 and –|x| = –3 are correct.

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Your solution was incomplete. Check for full content below-

For which equations below is x = –3 a possible solution? Check all that apply.

|x| = 3

|x| = –3

|–x| = 3

|–x| = –3

–|x| = –3

–|x| = 3

The range that would be the most approx to represent the numerical data on the vertical axis is B. 20 to 100.

Bar graph :

Bar graphs are the pictorial representation of data (generally grouped), in the form of vertical or horizontal rectangular bars, where the length of bars is proportional to the measure of data

The range that would be the most approx to represent the numerical data on the vertical axis is B. 20 to 100.

because

it is not possible to have zero number of cars that have a particular color,

in That way, we can eliminate options C and D .

in option A the range is too small which is not possible.

the table is not included but the range of 20 to 100 is most appropriate for the number of cars in town with a particular color.

this is because towns would normally have between hundreds and thousands of cars which means that cars of a particular color would be between 20 and 100 at least.

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The range that would be the most approx to represent the numerical data on the vertical axis is B. 20 to 100.

Bar graph :

Bar graphs are the pictorial representation of data (generally grouped), in the form of vertical or horizontal rectangular bars, where the length of bars is proportional to the measure of data

The range that would be the most approx to represent the numerical data on the vertical axis is B. 20 to 100.

because

it is not possible to have zero number of cars that have a particular color,

in That way, we can eliminate options C and D .

in option A the range is too small which is not possible.

the table is not included but the range of 20 to 100 is most appropriate for the number of cars in town with a particular color.

this is because towns would normally have between hundreds and thousands of cars which means that cars of a particular color would be between 20 and 100 at least.

a meal can be chosen is 546 different ways.

Answer:

a. (0, -5)

b. (4, -5)

c. (-5, 0)

Step-by-step explanation:

Answer:

I think it's the Distributive Property

Step-by-step explanation:

I think it's this because in order to get the parentheses out you have to multiply by the outside number.

5(x+2) and get 5x+10

The simplified fraction is [tex]\frac{1}{9^{20} }[/tex].

The fraction is [tex]\frac{9^{4} }{9^{24} }[/tex], we have to solve the fraction in the simplest form

[tex]\frac{9^{4} }{9^{24} }[/tex]

[tex]9^{4-24}[/tex]

As we know that, [tex]a^{m}[/tex]/[tex]a^{n}[/tex]= [tex]a^{m-n}[/tex]

[tex]9^{-20}[/tex]

1/[tex]9^{20}[/tex]

Therefore the simplified value is 1/[tex]9^{20}[/tex] which is in the form of a fraction.

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The plane will be at an altitude of 21,000 feet, 6 minutes after lift off.

For any equation, x = y + a, if we are given the value of any one of the variables, that is either x or y, we can find the value of the other.

Here, we are given an equation

a = 3400t + 600

where a = altitude of the plane in feet

and t = time (in minutes) passed after the plane's lift off

If the altitude of the plane is 21,000 feet

⇒ a = 21,000

Substituting this in the equation, we get

21,000 = 3400t + 600

21,000 - 600 = 3400t

20,400 = 3400t

3400t = 20,400

t = 20,400/ 3,400

t = 204/ 34

t = 6

Thus, the plane will be at an altitude of 21,000 feet, 6 minutes after lift off.

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As per given condition of Joyce bought twice of she had at first ,number of stickers bought by Joyce is equal to 32.

As given in the question,

Let x represents the number of Michelle stickers

and y represents the number of Joyce stickers

As per given condition,

Michelle and Joyce had an equal number of stickers

x =y __(1)

Joyce bought twice she had at first and had 4 times as many stickers as Michelle

2y = 4(x-8) __(2)

From (1) and (2) ,

2y = 4 ( y-8)

⇒ 2y = 4y -32

⇒4y -2y = 32

⇒ 2y = 32

Therefore, as per given condition of Joyce bought twice of she had at first ,number of stickers bought by Joyce is equal to 32.

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Answer:

As per given condition of Joyce bought twice of she had at first ,number of stickers bought by Joyce is equal to 32.

Step-by-step explanation:

[tex]\huge\text{Hey there!}[/tex]

[tex]\large\textsf{Looks like you are finding the \boxed{sum} in this question you are \boxed{\rm{adding}} .}[/tex]
[tex]\large\textsf{Now, let us solve for your given equation.}[/tex]

[tex]\mathsf{(-}\large\textsf{10})\large\textsf{ + 1}\\\\\large\textsf{To find the given answer to this equation, you have to START at }\mathsf{-}\textsf{10 \&}\\\large\textsf{go UP 1 space to the right \& you have reached your answers.}\\\\\mathsf{(-}\large\textsf{10})\large\textsf{ + 1}\\\mathsf{= -}\large\textsf{10 + 1}\\\mathsf{= -\large\textsf{9}}\\\\\\\huge\textbf{Therefore, your answer should be:}\\\huge\boxed{\mathsf{-9}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

Answer:   Choice D

Valid. The inner circle is those who protrice a hocethorn, and the outer circle is those who are dribbed.

=======================================================

Explanation:

Refer to the diagram below. It's a visual representation of what choice D is describing.

The "protrice a hocethorn" circle is denoted as "circle P" or simply "P" for short. While circle D refers to those who are dribbed.

If we throw a dart randomly at the inner circle, then we always will land in the outer circle. This is because the inner circle is completely contained within the outer circle. The inner circle is a subset of the outer circle.

If you land in circle P, then you land in circle D.

But Steve did not land in circle D (premise 2). This must mean he could not possibly have landed in circle P.

This is how we reach the conclusion that he did not protrice a hocethorn

For more information, check out the modus tollens rule. Some logic textbooks may refer to it as "denying the consequent".

----------------------------

Here's another example of modus tollens

We can think of the events "it rains" and "the grass got wet" as two dominoes. If the second domino did not fall over, then there's no way the first one did. This is because first one topples the second.

Shop Layout, in a scene shop, sheet lumber (such as lauan, plywood, masonite, and MDF) is commonly stored flat in an area that is at least  C. 4'x8'.

The most common size (area) for sheet lumber is  4 x 8 feet, about 32ft² or 2.97m².

Other areas that sheet lumber can occupy include 2 x 2 feet, 2 x 4 feet, 4 x 4 feet, and 4 x 10 feet.

This implies that sheet lumber does not usually come in the following sizes: 4'x6', 8'x8', and 6'x10'.

Length of sheet lumber = 8 feet

Width of sheet lumber = 4 feet

Area of sheet lumber = 32 ft² (8 x 4)

Thus, according to Shop Layout, in a scene shop, sheet lumber (such as lauan, plywood, masonite, and MDF) is commonly stored flat in an area that is at least  C. 4'x8'.

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Answer: None of the above

Step-by-step explanation:

Answer:

  16∛2

Step-by-step explanation:

It looks like you want to simplify ...

  6∛16 +∛128

Radicals are simplified by removing any powers corresponding to the index of the radical. Here, we're taking cube roots, so the expression is simplified by removing cubes from under the radical.

  [tex]6\sqrt[3]{16}+\sqrt[3]{128}=6\sqrt[3]{2^3\cdot2}+\sqrt[3]{4^3\cdot2}\\\\=6\cdot2\sqrt[3]{2}+4\sqrt[3]{2}=(12+4)\sqrt[3]{2}\\\\=\boxed{16\sqrt[3]{2}}[/tex]

Answer:780

Step-by-step explanation:

Answer

The answer would be 630

Step-by-step explanation:

69+69 = 138

138+69 =207

207 - 6 = 201

201 + 9  = 210

210 -69 = 141

141 + 69 =210

21 + 420 = 630

The cost to waterproof a canvas truck cover that is 15’ x 24 will be D. $180.

It should be noted that from the information, it costs $0.50 per square yard to waterproof canvas.

Therefore, the cost to waterproof a canvas truck cover that is 15’ x 24 will be:

= 15 × 24 × $0.50

= $180.00

In conclusion, the correct option is D.

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Answer:

1 only

Step-by-step explanation:

1 only, as the other points have defined values.

The function g(x) increases at a faster rate and has a greater initial value.

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The probability of getting a number divisible by five is 1 / 9.

We are given that:

a fair six-sided die is thrown 2 times.

Sample space will be:

S = { (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6) }
Let E = probability of getting a number divisible by five

Possible outcomes:

= { (1, 4), (2, 3), (3, 2), (4, 1) }

P(E) = 4 / 36 = 1 / 9

Therefore, the probability of getting a number divisible by five is 1 / 9.

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Answer:

x = c / (7 - h)

Step-by-step explanation:

c = 7x - hx

c = x(7 - h)

x = c / (7 - h)

Answer:

No

Step-by-step explanation:

The question is asking for difference which is another term for subtraction.In that regard Amy is correct, however the question asks for the difference between 3 and -5 which means she'd have to subtract 3 from -5 not the other way around.

Answer:

8b + 9 = 7

Step-by-step explanation:

Answer:

0.246

Step-by-step explanation:

p(virus) = 0.09

= 1-p(none test positive)

=1-(1-0.09)^3

=1-0.91^3

=0.246

Answer:
-8

Step-by-step explanation:

Given the following question:

-8 + 13 + (-13)
Use PEMDAS to solve this question:
13 + (-13) = 0
-8 + 0 = -8
= -8

Hope this helps.

Hello..!

[tex] \: \: \ \: \: \: \: \: \: \: \: \: \: \ \sf \red{ - 8 + 13 + ( - 13)}[/tex]

[tex] \blue{\underline{ \green{ \underline{\sf \green{Explantation: }}}}}[/tex]

First, to solve the problem we take into account the Law of Signs:

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \green{\underline{ \blue{\underline{ \red{\sf Law \: of \: \: Signs:}}}}} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: - \times + = - [/tex]

Once we have the law of signs, we will eliminate the parentheses to subtract, taking into account the law of signs

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \sf \green{ - 8 + 13 - 13}[/tex]

Then we must subtract knowing that when there is a minus and a plus it is automatically minus

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf \blue{- 5 - 13}[/tex]

Well, now we will subtract the only thing we have left, which in this case is 5 -13, which gives us -8

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \sf \: The \: \: result \: \: is \: \: from \\ \: \: \: \: \: \: \: \sf \green\longmapsto \pink{ - 8}[/tex]

¿Doubts? in the comments

Answer:

Can someone help me please

Answer: 4 0 4

Step-by-step explanation: