Saturated, unsaturated, and supersaturated are three terms used to characterize solutions. These are the right responses.
How saturated, unsaturated, or supersaturated is the solution?Less solute is present in an unsaturated solution than the solution can dissolve. In comparison to saturated solutions, supersaturated solutions have more dissolved solute and may dissolve more solute at a given temperature. Solutions that have less dissolved solute than the solvent's saturation point are said to be unsaturated solutions (at that specific temperature gradient).
What distinguishes saturation from supersaturation?A saturated solution is one that dissolves the most solute possible at a particular temperature. To saturate it, a solution containing more solute than that is needed.
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The given question is incorrect. The correct question is:
Which can best identify how solutions can be classified based on solubility?
a. unsaturated
b. desaturated
c. saturated
d. supersaturated
an automobile gasoline tank holds 40kg of gasoline. when gasoline burns, 140 of oxygen is consumed and carbon dioxide and water are produced. whats the total mass of carbon dioxide and water produced
40 + 140 = 180 kg of water and carbon dioxide were created in total when gasoline burns.
How much fuel can a tank in a car hold?An average gasoline tank holds 13 to 16 gallons. For instance, the fuel capacity of a Ford Focus is 13.5 gallons, that of an Elantra is 14, and that of a Mazda 3 ranges from 14.9 to 15.9 gallons, depending on the model.
Mass of gasoline plus mass of oxygen equals the combined mass of carbon dioxide and water produced.
combined mass of the water and carbon dioxide produced = 40 + 140 = 180 kg The chemical reaction will appear as follows:
the following equation: fuel + oxygen + carbon dioxide + water + heat
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I need help solving this chemical equation. Thank you. Step by step explanation of it also.
Balance the following equation:
3Cu (s) + 8HNO₃ (aq) ⟶ 3Cu(NO₃)₂(aq) + 2NO (g) + 4H₂O (l)
Reaction equilibrium is a condition where the components of the reactants and reaction products remain in the system, in a state of equilibrium the rate of the reaction to the right is equal to the rate of the reaction to the left.
Cu → Cu²⁺ + 2e⁻ ⟶ Equation (1)
NO₃⁻ + 4H⁺ + 3e⁻ ⟶ NO + 2H₂O ⟶Equation (2)
Equation (1) × 3+ Equation (2) ×2(for equalising electrons)
3Cu ⟶ 3Cu²⁺ + 6e⁻
2NO₃⁻ + 8H⁺ + 6e⁻ ⟶ 2NO + 4H₂O
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3Cu + 2NO₃⁻+ 8H⁺ ⟶ 3Cu²⁺ + 2NO + 4H₂O
But 8H⁺ + 8NO₃⁻ ⟶ 8HNO₃
The 6 NO₃²⁻ combine with Cu²⁺
So, balanced equation is:
3Cu (s) + 8HNO₃ (aq) ⟶ 3Cu(NO₃)₂(aq) + 2NO (g) + 4H₂O (l)
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convert 4.5cm^3 to mL