What is the measure of 2HPL?
H
(12x - 15)"
(8x + 33)

The spray rate of the park sprinkler is equal to 46 gallons per minute.

In this problem we find that a park sprinkler that can spray a capacity of 1,748 gallon of water in a time of 38 minutes and we are asked to calculate the spray rate by the following fomula:

r = Q / t

Where:

If we know that Q = 1748 gallon and t = 38 min, then the spray rate is:

r = (1748 gallon) / (38 min)

r = 46 gallons per minute

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A medium popcorn costs $16.875 and a small drink costs $2.50.

Two or more expressions with an Equal sign is called as Equation.

Let x be the unit cost of a medium popcorn and y be the unit cost of a small drink.

Shana  bought one medium popcorn and three small drinks for $14.75

1x+3y=14.75..(1)

y = (14.75 - x) / 3...*

Allyson bought two medium popcorns and five small drinks, she paid $26

2x+5y=26..(2)

Substitute * value in equation 2

2x + 5((14.75 - x) / 3) = 26

Expanding and simplifying the right-hand side:

2x + 14.75 - (5/3)x = 26

Combining like terms:

(2/3)x + 14.75 = 26

Solving for x:

(2/3)x = 11.25

x = 16.875

So, a medium popcorn costs $16.875 and a small drink costs (14.75 - x) / 3 = $2.50.

Hence,  a medium popcorn costs $16.875 and a small drink costs $2.50.

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The value of the tax for the meal is $1.05.

The government levies a consumption tax known as a sales tax on the purchase of goods and services. At the point of sale, a standard sales tax is imposed, collected by the shop, and paid to the government.

Depending on the regulations in that country, a business may be responsible for sales taxes in that jurisdiction if it has a presence there, which can be a physical site, an employee, or an associate.

Given the  cost of the meal = $15.00

and rate of tax = 7%

converting the rate of tax into decimal form,

rate of tax = 7% = 7/100

rate of tax = 0.07

amount of tax = cost x rate of tax

amount of tax = 15 x 0.07

amount of tax = $1.05

Hence the amount of tax is $1.05.

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In the expression ax + b = 3(x - a), the value of x is solved to be

To solve for x the parenthesis is first expanded as below

ax + b = 3(x - a)

ax + b = 3x - 3a

collecting terms with x variables

b + 3a = 3x - ax

b + 3a = x(3 - a)

isolating x dividing through by (3 - a) will result to

b + 3a / (3 - a) = x(3 - a) / (3 - a)

b + 3a / (3 - a) = x

hence x = b + 3a / (3 - a)

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The numeric values of the graphed function are given as follows:

To obtain the numeric values from the graph, we must plot a vertical line at each x-coordinate, and then verify where the vertical line intersects the graph.

At x = -2, the vertical line would intersect the graph at y = 2, hence:

f(-2) = 2.

At x = -0, the vertical line would intersect the graph both at y = 1 and y = 3, however y = 3 has the closed circle, hence hence:

f(0) = 3.

At x = 4, the vertical line would intersect the graph at y = 1, hence:

f(4) = 1.

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The equation which represents the graph is y = −3x − 3, the correct option is B.

An equation is an expression that shows the relationship between two or more numbers and variables.

A mathematical equation is a statement with two equal sides and an equal sign in between. An equation is, for instance, 4 + 6 = 10. Both 4 + 6 and 10 can be seen on the left and right sides of the equal sign, respectively.

Given

Line that passes through the points 0 comma negative 3 and negative 1 comma 0

The equations;

y=-1x/3-3

y = −3x − 3

y = −1/3x + 1/3

y = −3x − 1/3

Now, solving the equations

(0,3)(1,0)

y = −3x − 3

y = −3*1 − 3

Therefore, the equation will be y = −3x − 3.

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The Camel stopped at  22.4 km south of the Oasis

To solve this problem, we can use basic trigonometry. If the camel travelled at a bearing of 106° from the oasis and stopped 27 km east of the oasis, we can use the tangent function to find the distance south of the oasis.

Let's call the distance south of the oasis "d". Then, using the tangent function:

tan 106° = d / 27

Solving for "d", we get:

d = 27 * tan 106°

Using a calculator, we can find the approximate value of d to be about 22.4 km.

So, the camel stopped about 22.4 km south of the oasis.

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A first course in differential equations with modeling applications ninth edition is a textbook that covers the basics of differential equations and their applications in mathematical modeling.

It begins with an introduction to the concepts of differential equations, including the definition, solution methods, and the concept of modeling. It then covers topics such as first-order linear equations, higher-order linear equations, systems of linear differential equations, and nonlinear equations. It also has a chapter on boundary-value problems, which is a type of differential equation that involves a set of boundary conditions that must be satisfied for the solution to be valid.

In order to solve differential equations with boundary-value problems, we must first define the boundary conditions that must be satisfied for the solution to be valid. This involves setting up the boundary conditions in terms of the dependent and independent variables of the equation. We then solve the equation using the boundary conditions and the equation itself. The solution is then used to calculate values for the independent and dependent variables at the boundary points. Finally, we can verify the solution by substituting the calculated values into the equation and seeing if the solution is valid.

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The interval notation of the given sets of A and B are A U B : {z│z is all real Numbers (lR)} and A ∩ B : {z│4 <  z ≤ 8} (less than equal to for 8).

Sets are groups of clearly defined objects or elements in mathematics. A set is represented by a capital letter symbol, and the cardinal number of a set enclosed in a curly bracket indicates how many elements there are in a finite set.

A set can be of many different forms, such as an empty set or null set, which is one without any elements.

An illustration of a null set is A =.

It only has a finite number of components.

Instance: A = 1, 2, 3, 4.

The items of an infinite set are unbounded.

The set of all whole numbers is represented by the expression A = x.

A U B : {z│z is all real Numbers (lR)}    

∩ means and common area in both hence:

A ∩ B : {z│4 <  z ≤ 8} (less than equal to for 8)

The interval notation of the given sets of A and B are A U B : {z│z is all real Numbers (lR)} and A ∩ B : {z│4 <  z ≤ 8} (less than equal to for 8).

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30.2% is the necessary probability that it is a horror or comedy movie title.

Given:

There are 168 films in the horror category.

There are 118 films in the mystery category.

The following formula can be used to get the total number of movies in the video rental store:

Total number of outcomes is =  (168 + 220 + 118 + 308 + 134) =948

Let P (H) represent the likelihood that it will be a horror film, and P (M) represent the likelihood that it will be a mystery. In addition, we presumptively believe that a film can only fall into one of two categories: mystery or horror. The likelihood that a horror or mystery film will be chosen as a rental can be calculated as follows:

[tex]P(M or H) = P(H) + P(M)[/tex]

                [tex]=\frac{168}{948} +\frac{118}{948}[/tex]

                [tex]=\frac{168+118}{948}[/tex]

                [tex]=\frac{286}{948}[/tex]

                ≈[tex]0.302[/tex]

Therefore, 30.2% is the necessary probability.

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Load is when the collection of forces is applied on the beam or segment then it is called load and the unit of the load is the newton.

To solve these questions there are a few steps to follow:

first, as per the question we have to draw a free-body diagram by considering point A.

Resolve the force in the x-direction:

[tex]R_A_x=0[/tex]

Resolve the force in the y-direction:

[tex]R_A_y-150-300=0\\\\R_A_y=450lb[/tex]

Now take the moment about point A, we get

[tex]M_A+(150*1.5)+(300*3)=0\\\\M_A=-1125lb.ft[/tex]

Next, draw a free-body diagram by considering point B.

Resolve the force in the x-direction:

[tex]R_B_x=0[/tex]

Resolve the force in the y-direction:

[tex]R_B_y-550-300=0\\\\R_B_y=850lb.[/tex]

Now take the moment about point B, we get

[tex]M_B+(550+5.5)*(300*11)=0\\\\M_B=-6325lb.ft[/tex]

And the last one draws a free-body diagram by considering point C.

Resolve the force in the x-direction:

[tex]R_C_x=0[/tex]

Resolve the force in the y-direction:

[tex]R_C_y-250-650-300=0\\\\R_C_y=1200lb.[/tex]

Now take the moment about point B, we get

[tex]M_C+(650+6.5)*(300*13)=0\\\\M_B=-8125lb.ft[/tex]

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Answer: width = 2/15 miles

Step-by-step explanation:

Area of a rectangle = l * w

In this case, our equation is 3/9 = 5/2 * w

What we need to do to find the width, is isolate the w variable.

To do so, the 5/2 is going to be divided by itself to get the variable w completely isolated.

With equations like this, whatever you do on one side, you do to the other. So, the area will also be divided by 5/2.

3/9 / 5/2  the common term "Keep, Change, Flip (KCF)" can be used to solve this.

You keep the first fraction as is, change the division sign to multiplication, and flip the second fraction to its reciprocal.

3 x 2 = 6

9 x 5 = 45

6/45 can be further reduced with the GCF of 3 resulting in your answer,

width = 2/15 miles

Answer:

1/6

Step-by-step explanation:

0.333 - 1/3

0.6667 - 1/6

0.2 - 2/10

0.2857 - 2/7

The integral of the current I(t) over the interval [a,b] represents the change in the charge Q from time t=a to t=b.

The current in an electrical circuit is defined as the rate at which charge is flowing through a conductor. The equation that represents the current is I(t) = dQ(t)/dt, where Q(t) is the charge at time t and dQ(t)/dt is the derivative of Q(t) with respect to time, representing the rate of change of charge.

The integral of I(t) with respect to time between the limits a and b, i.e. ∫I(t)dt between the limits a and b, represents the change in the charge from time t = a to time t = b. This is because the definite integral of a rate of change gives the total change in the quantity being measured, in this case, the charge.

So, [tex]\int\limits^a_b {|(t)} \, dt = Q(b) -Q(a)[/tex], which represents the change in the charge from time t = a to time t = b.

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The total payment of the family is given as $336

The family`s payment would be  $2725

The model that elates payments and charges is Payment = $250 + (1 - insurance payment percentage) * (charge - $250)

a) If the dental charge is $680, then the family's payment is:

Deductible: $250 (the family has to pay this first)

Remaining charges: $680 - $250 = $430

The insurance company pays for 80% of the remaining charges, which is 0.8 * $430 = $344

Therefore, the family has to pay for 100% - 80% = 20% of the remaining charges, which is 0.2 * $430 = $86

So, the total payment by the family is $250 + $86 = $336

b) If the dental charge is $4500, then the family's payment is:

Deductible: $250 (the family has to pay this first)

Remaining charges after deducting the deductible: $4500 - $250 = $4250

The insurance company pays for 80% of the remaining charges that do not exceed $1500, which is 0.8 * $1500 = $1200

So, the remaining charges for the family to pay after the insurance pays for the first $1500 of the remaining charges: $4250 - $1500 = $2750

The insurance company pays for 50% of the remaining charges that exceed $1500, which is 0.5 * $2750 = $1375

Therefore, the family has to pay for 100% - 50% = 50% of the remaining charges that exceed $1500, which is 0.5 * $2750 = $1375

So, the total payment by the family is $250 + $1200 + $1375 = $2725

c) The model that relates the payments and charges is:

Payment = $250 + (1 - insurance payment percentage) * (charge - $250)

where the insurance payment percentage is 80% if the charge is between $250 and $1500, and it is 50% if the charge exceeds $1500.

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Answer:

12

Step-by-step explanation:

6

×12=72

=72answer is=12

Answer:

Step-by-step explanation:

srry need the points

Answer:

Step-by-step explanation:

27)    

x = 88

180 - 47 - 88 = 45

y = 180 - 88 - 45 = 47

28)

2x - 1 = 53

2x = 54

x = 54/2 = 27

(4y + 5) + 53 + 90 = 180

4y = 32

y = 32/4 = 8

The value of c that minimizes MSE is given by the equation above:

c = sum(y * x) / sum(x²)

To determine the value of c that minimizes the mean squared error (MSE), we must first find the derivative of MSE with respect to c and set it equal to zero. This will give us the critical points, which can then be tested to determine if they correspond to a minimum or maximum.

        dJ(c) / dc = 2 * sum((y - (c * x)) * (-x)) / n

       c = sum(y * x) / sum(x²)

        d² J(c) / dc² = -2 * sum(x²) / n

        c = sum(y * x) / sum(x²)

Note that this method assumes that J(c) is a convex function, which is typically the case for the MSE loss function.

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Nominal scales categorize data without order. Ordinal scales categorize data with order. Interval scales have equal units, but no true zero. Ratio scales have equal units and a true zero.

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Applying the classification angles, the values of x= 29° and y=8.5°.

They are a lot of classifications for angles like complementary angles, supplementary angles, right angles, and others. See below:

From the figure, it is possible to see that:

       6x-36=138

       6x=138+36

       6x=174

         x=174/6

         x=29°

       4y+8+138=180

       4y=180-138-8

        4y=180-146

         4y=34

          y=34/4

         y=8.5°

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Answer:

Step-by-step explanation:

eres un pendejo

For a, b, and c being independent random variables uniformly distributed over (0,1), the joint cumulative distribution function of a, b, and c is given by:

F(a,b,c) = abc

For the probability that all of the roots of the equation Ax2 + Bx + C = 0 are real, we can use the quadratic formula to solve for the roots:

x = [-B +/- sqrt(B^2 - 4AC)]/2A

To ensure that these roots are real, we must make sure that the discriminant B^2 - 4AC is greater than or equal to 0. The probability that this is the case is given by the integral of the joint cumulative distribution function over the range 0 <= B^2 - 4AC >= 0, which evaluates to 1/8.

Therefore, the probability that all of the roots of the equation Ax2 + Bx + C = 0 are real is 1/8.

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Answer:

f(g(-2)) = -3

Step-by-step explanation:

2((-2) - 3) + 7

2(-5) + 7

-10 + 7

-3

Hope this helps!

  x/(x-intercept) + y/(y-intercept) = 1x + 5y = 15x/15 + 5y/15 = 1x/15 + y/3 = 1Plot the points (15, 0) and (0, 3), and draw a line through them. That is your graph.

If the point you end up at is coordinate (0.25, 0) then you would have ran one full lap around the track.

1. The given track is a circular track with a radius of 0.25 miles, and the center of the track is at (0, 0).

2. If you end up at the point (0.25, 0), then you would have ran one full lap around the track. This is because the coordinates of the point you end up at, (0.25, 0), are the same as the coordinates of the circumference of the track, which is located 0.25 miles from the center of the track.

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Option d. 88 is the correct answer. A firm with an 8% dividend growth rate and a return on equity of 20% must have a plowback ratio of % of 88.

The equation for the payout proportion (P) is:

P = Profits/Income

The equation for the plowback proportion (PB) is:

PB = 1 - P

Where Profits is how much profits paid out, and Income is the net gain of the firm.

On the off chance that a firm has a profit development pace of 8% and a profit from value of 20%, then we can utilize the accompanying equation to compute its income:

Profit = Profits/(Return on Value - Profit Development Rate)

Connecting the numbers, we get:

Profit = Profits/(0.2 - 0.08) = Profits/0.12

Now that we know the recipe for income, we can find the payout proportion:

P = Profits/Income = Profits/(Profits/0.12) = 0.12

Lastly, the plowback proportion:

PB = 1 - P = 1 - 0.12 = 0.88

So the firm unquestionable necessity a plowback proportion of 88%. Subsequently, the right response is: 67%.

The plowback proportion is the piece of income that a firm holds as opposed to delivering as profits. It's determined as 1 short the payout proportion, which is the proportion of profits to income. To find the plowback proportion for a firm with a 8% profit development rate and 20% profit from value, you can utilize a recipe to find its income and afterward work out the payout proportion lastly deduct it from 1 to find the plowback proportion. The plowback proportion is 88%.

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The firm with an 8% dividend growth rate and a return on equity of 20% must have a plowback ratio of %. multiple choice question.

a. 40

b. 2.5

c. 67

d. 88

The line x=1 is a vertical asymptote of the function[tex]f(x)=x2−1x2−7x+6[/tex], but the line x=-1 is not, and the limit of a function approaching a vertical asymptote can be either positive infinity or negative infinity depending on the value of the function.

a. The line x=1 is a vertical asymptote of the function  because when x tends to 1, the denominator tends to 0, resulting in an undefined value for the function.

b. The line x=-1 is not a vertical asymptote of the function [tex]f(x)=x2−1x2−7x+6[/tex] because when x tends to -1, the denominator does not tend to 0, resulting in a finite value for the function.

c. If g has a vertical asymptote at x=1 and[tex]x→1 +limg(x)=[infinity][/tex], then [tex]x→1 −limg(x)=[infinity][/tex] is not necessarily true. This is because the limit of a function approaching a vertical asymptote can be either positive infinity or negative infinity depending on the value of the function as it approaches the asymptote. For example, if g(x) = 1/x, then[tex]x→1 +limg(x)=[infinity][/tex] The line x=1 is a vertical asymptote of the function [tex]f(x)=x2−1x2−7x+6[/tex], but the line x=-1 is not, and the limit of a function approaching a vertical asymptote can be either positive infinity or negative infinity depending on the value of the function.

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The value of x from the given figure is 155°.

The exterior angle theorem states that the measure of an exterior angle is equal to the sum of the measures of the two remote interior angles of the triangle.

From the given figure,

By angle sum property,

90°+35°+a=180°

125°+a=180°

a=55°

Now, angles at a point on straight line is

55°+b°+60°=180°

b=65°

Using exterior angle theorem, we get

x=90°+65°

x=155°

Therefore, the value of x is 155°.

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The Venn diagram shown to Region V: Items in A, B, and C are represent A' ∩ B' ∪ C

It is given that the diagram we need to find the regions represent the set.

A Venn diagram is an illustration that uses circles to show the relationships among things or finite groups of things. Circles that overlap have a commonality while circles that do not overlap do not share those traits. Venn diagrams help to visually represent the similarities and differences between two concepts.

So from the Venn diagram, the item represents the regions four, five, six and seven.

Therefore, it can be written us for Union Fight, Union Six, Union Seven. Therefore, we concluded that the regions represent see R. C.

Which is equal to for Union Fighting Union Six, Union Seven.

We have here, region represent A' ∩ B' ∪ C

Therefore, the Venn diagram shown to regions represent

A' ∩ B' ∪ C is Region V: Items in A, B, and C.

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The circumference and the area of the circular flower bed are given as follows:

The area of a circle of radius r is given by π multiplied by the radius squared, as follows:

A = πr²

The radius is half the diameter, hence it has the value given as follows:

r = 0.5d

r = 0.5 x 12

r = 6.

Then the area is obtained as follows:

A = π x 6²

A = 36π units squared.

The circumference is given by the multiplication of the diameter by π, hence:

C = 12π units.

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