what is the answer for this 3x+4x+5x+...+43x

The solution to the expression is x= 18

15 over x=2 equals 3 over 4 can be written as follows

15/x+2 = 3/4

Cross multiply both sides

15×4= 3(x+2)

60= 3x +6

collect the like terms

3x= 60-6

3x= 54

divide both sides by the coefficient of x which is 3

3x/3 = 54/3

x= 18

Hence the value of x in the expression is 18

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Answer:

Step-by-step explanation:

30 feet.

The equation could be used to find the maximum speed of a hippopotamus h is C. 75 = 3h + 18

The question has to do with linear equation

A linear equation is a mathematical expression in which the highest power of the unknown is 1.

Let

Given that the maximum speed, in miles per hour, of a cheetah is 18 more than 3 times  the maximum speed of the hippopotamus

Now, since the maximum speed of the hippopotamus is h, 3 times the maximum speed of the hippopotamus is 3h.

Since the cheetah is 18 more than 3 times  the maximum speed of the hippopotamus, we have that

x = 3h + 18

Substituting x = 75 into the equation, we have

75 = 3h + 18

So, the equation could be used to find the maximum speed of a hippopotamus h is C. 75 = 3h + 18

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Answer:

P = -8

Step-by-step explanation:

There are 7 rabbits sold for $7 and 13 rabbits sold for $11.

Substitution method:

In the substitution method, we must substitute the value of one given variable in terms of the other given variable and find the solution.

Given,

A pet shop sold 20 rabbits for $192.

Some of the rabbits sold for $7 each and the rest for $11 each.

Here we need to find the number of rabbits sold in each case.

Let us consider x be the number of rabbits sold for $7 and y be the number of rabbits sold for $11.

We know that, the total number of rabbits sold = 20.

So, it can be written as,

=> x + y = 20

Here we have to rewritten this equation as,

=> x = 20 - y ----------------------(1)

We know that, total amount for sold rabbits = 192

So, it can be written as,

=> 7x + 11y = 192 -----------------------(2)

Apply the value of x to equation (2),

Then we get,

=> 7(20 - y) + 11y = 192

=> 140 - 7y + 11y = 192

=> 4y + 140 = 192

=> 4y = 192 - 140

=> 4y = 52

=> y = 52/4

=> y = 13.

Apply the value of y on the equation (1),

Then we get,

=> x = 20 - y

=> x = 20 - 13

=> x = 7

Therefore, there are 7 $7 rabbits and 13 $11 rabbits are sold.

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Answer:

It would be 3710.

Step-by-step explanation:

Answer:

y = 2x + 3

Step-by-step explanation:

i gotchu

Answer:

[tex]x=27, \quad x= \dfrac{1}{27}[/tex]

Step-by-step explanation:

[tex]\boxed{\begin{minipage}{3.7 cm}\underline{Logs Laws}\\\\$\log_ba=\dfrac{\log_ca}{\log_cb}$\\\\\\$\log_ab=c \iff a^c=b$\\\end{minipage}}[/tex]

Given equation:

[tex]\log_3x=9\log_x3[/tex]

Change the base of  9logₓ3  to base 3:

[tex]\begin{aligned}\implies \log_3x & =9\log_x3\\\\& =\dfrac{9\log_33}{\log_3x}\\\\&=\dfrac{9(1)}{\log_3x}\\\\&=\dfrac{9}{\log_3x}\end{aligned}[/tex]

Therefore:

[tex]\implies \log_3x=\dfrac{9}{\log_3x}[/tex]

[tex]\textsf{Let }\log_3x=u:[/tex]

[tex]\implies u=\dfrac{9}{u}[/tex]

[tex]\implies u^2=9[/tex]

[tex]\implies u=\pm3[/tex]

[tex]\textsf{Substitute back in }u=\log_3x:[/tex]

[tex]\implies \log_3x=\pm3[/tex]

Case 1

[tex]\implies \log_3x=3[/tex]

[tex]\implies 3^3=x[/tex]

[tex]\implies x=27[/tex]

Case 2

[tex]\implies \log_3x=-3[/tex]

[tex]\implies 3^{-3}=x[/tex]

[tex]\implies \dfrac{1}{3^3}=x[/tex]

[tex]\implies x=\dfrac{1}{27}[/tex]

Answer: x=3   x=1/27

Step-by-step explanation:

[tex]log_3x=9log_x3\\[/tex]

The area of acceptable values:

[tex]x > 0\ \ \ \ x\neq 1\\Hence,\\x\in(0,1)U(1,+\infty)[/tex]

Solution:

[tex]\displaystyle\\log_3x=\frac{9}{log_3x} \ \ \ \ \ \boxed{ log_ab=\frac{1}{log_ba} }\\\\Multiply\ both\ parts\ of\ the\ equation\ by\ log_3x :\\\\log^2_3x=9\\log^2_3x=3^2\\ log_3x=б3\\\\log_3x=3\\\\x=3^3\\x=3*3*3\\x=27\\\\\\log_3x=-3\\x=3^{-3}\\\displaystyle\\x=(\frac{1}{3})^3\\ x=\frac{1}{3}*\frac{1}{3}*\frac{1}{3} \\ x=\frac{1}{27}[/tex]

Answer: The equations are:

X+3=Y;

45X + 75Y  = 1455 ;

The variables used are X and Y specifying number of small and large boxes

Step-by-step explanation:

Let X be  the number of small boxes

Let Y be  the number of big boxes

The first equation is:  X+3=Y;  (  Since there were 3 more small boxes shipped than large boxes )

The second equation is:    45X + 75Y  = 1455   ( this is because the small box weighs 45 pounds and big box weighs 75 pounds.  The total weight of the small boxes is 45 times the weight of each individual box. And the total weight of the second boxes is equal to 75Y.)

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Answer:

Step-by-step explanation:

The variables used are A and B specifying number of small and large boxes

Let the number of small box is A

Let the number of large box is B

The first equation is:  A+3=B;

(  Since there were 3 more small boxes shipped than large boxes )

The second equation is:    45A + 75B  = 1455   ( this is because the small box weighs 45 pounds and large box weighs 75 pounds.  The total weight of the small boxes is 45 times the weight of each  box. And the total weight of the second boxes is equal to 75B.)

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20/100

That is the answer if u want it simplified it is 1/5

Answer:

20/100 simplified is 1/5

Step-by-step explanation:

it is the fraction form

Answer:

The cost per unit of an item is called unit cost

Answer:986

Explanation? Calculator;)

Answer: 986

Step-by-step explanation? It’s easier to use a calculator.

(2x6)^3/2  in it's simplest form is equal to 41.56. See the computation below.

Using BODMAS, we say

(2 x 6) = 12

12^(3/2)

= 41.5692

[tex]$\approx$[/tex] 41.56

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Based on the definition of a function,

1. The relation on the right is not a function.

2. Domain: {20, 70, -60}

Range: {3, -6, 2, 5}

A relation that is defined as a function has each domain value that is assigned to only one possible range value, in such a way that, each of the domain element cannot have two different range element that corresponds to it.

1. The relation on the right has a domain element, -60, which corresponds to two different range element, -6 and 2.

Therefore, the relation on the right is not a function.

2. The domain of the relation that is not a function is: {20, 70, -60}

The range of the relation that is not a function is: {3, -6, 2, 5}

In summary, based on the definition of a function,

1. The relation on the right is not a function.

2. Domain: {20, 70, -60}

Range: {3, -6, 2, 5}

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Answer:

The smaller number is 27 and the larger number is 44

Step-by-step explanation:

Let x = the larger number

Let y = the smaller number

x + y = 71

x = y + 17  Substitute in y + 17 for x in the first equation.

x + y = 71

y +17 + y = 71  Combine the y's.

2y + 17 = 71  Subtract 17 from both sides of the equation

2y = 54  Divide both sides of the equation by 2

y = 27.  Plug 27 in for y for either of the two original equation to find x

x + y = 71

x + 27 = 71  Subtract 27 from both sides of the equation

x = 44

The ratio of circumference/diameter for all circles is π. And the ratio of force/mass for all freely-falling bodies will be g.

Let d be the diameter of the circle. The circumference of the circle will be

C = πd units

The ratio of circumference to diameter for all circles is pie.

C/D = πd / d

C/D = π

Then the ratio of force to mass for all freely-falling bodies will be

The force acting on a free-falling body of mass (m) is mg. Then we have

Force/Mass = mg / m

Force/Mass = g

Where g is the acceleration due to gravity.

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Answer:

Angle Bisector I believe

Step-by-step explanation:

Apologies if I am wrong

The given bounded region is the set

[tex]R = \left\{(x,y) ~:~ 0 \le x \le 1 \text{ and } x^4 \le y \le x^{1/4} \right\}[/tex]

assuming the curves are [tex]y=x^4[/tex] and [tex]x=y^4\implies y=x^{1/4}[/tex] (since [tex]x>0[/tex] in the first quadrant).

The coordinates of the centroid are [tex](\bar x, \bar y)[/tex] where [tex]\bar x[/tex] and [tex]\bar y[/tex] are the average values of [tex]x[/tex] and [tex]y[/tex], respectively, over the region [tex]R[/tex]. These are given by the ratios

[tex]\bar x = \dfrac{\displaystyle \iint_R x \, dA}{\displaystyle \iint_R dA} \text{ and } \bar y = \dfrac{\displaystyle \iint_R y\,dA}{\displaystyle \iint_R dA}[/tex]

Compute the area of [tex]R[/tex].

[tex]\displaystyle \iint_R dA = \int_0^1 \int_{x^4}^{x^{1/4}} dy \, dx \\\\ ~~~~~~~~ = \int_0^1 \left(x^{1/4} - x^4\right) \, dx \\\\ ~~~~~~~~ = \frac45 - \frac15 = \frac35[/tex]

Integrate [tex]x[/tex] and [tex]y[/tex] over [tex]R[/tex].

[tex]\displaystyle \iint_R x \, dA = \int_0^1 \int_{x^4}^{x^{1/4}} x \, dy \, dx \\\\ ~~~~~~~~ = \int_0^1 x \left(x^{1/4} - x^4\right) \, dx \\\\ ~~~~~~~~ = \int_0^1 \left(x^{5/4} - x^5\right) \, dx \\\\ ~~~~~~~~ = \frac49 - \frac16 = \frac5{18}[/tex]

[tex]\displaystyle \iint_R y \, dA = \int_0^1 \int_{x^4}^{x^{1/4}} y \, dy \, dx \\\\ ~~~~~~~~ = \frac12 \int_0^1 \left((x^{1/4})^2 - (x^4)^2\right) \, dx \\\\ ~~~~~~~~ = \frac12 \int_0^1 \left(x^{1/2} - x^8\right) \, dx \\\\ ~~~~~~~~ = \frac12 \left(\frac23 - \frac19\right) = \frac5{18}[/tex]

Then the centroid's coordinates are

[tex]\bar x = \dfrac{\frac5{18}}{\frac35} = \boxed{\frac{25}{54}} \approx 0.463[/tex]

[tex]\bar y = \dfrac{\frac5{18}}{\frac35} = \boxed{\frac{25}{54}}[/tex]

By using simple rule of three, a period of 9.5 years on Venus is equivalent to 2134.65 terrestrial days.

One year on Earth is equivalent to 365.3 days and one year on Venus is equivalent to 224.7 days, the equivalent terrestrial time of 9.5 years on Venus is found by simple rule of three:

x = 9.5 yr × (224.7 days / 1 yr)

x = 2134.65 days

A period of 9.5 years on Venus is equivalent to 2134.65 terrestrial days.

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Answer:

x = 14    y = 59

Step-by-step explanation:

the angle (5x - 11) is equal to the angle (3x + 17) and 3x+ 17 is equal to y

5x - 11 = 3x + 17

5x - 3x = 17 + 11

2x = 28

x = 28/2

x = 14

3x+17 = y

3(14) + 17 = y

y = 59

Step-by-step explanation:

Fact 1: Alternate angles are equal.

Angles, (5x-11)° and (3x+17)° are ALTERNATE angles and so,

(5x-11)° = (3x+17)°

5x - 3x = 17 + 11

2x = 28

x = 28 ÷ 2

x = 14

NB: x does NOT have the degree sign because it's NOT an angle on its own, but rather within the bracket/part of the calculation to get the angle degree.

Fact 2: Opposite angles are equal.

Y° and (3x+17)° are OPPOSITE angles

y = (3x+17)°

y = (3x14) + 17

y= 42 + 17

y = 59°

Hope this helps!

Answer:

64 and 13 I hope this helps

Step-by-step explanation:

Answer:

20%

Step-by-step explanation:

20/25 = blue

This means 5/25 of the balls in the bag are NOT blue

(25-20 = 5)

We need to convert 5/25 to a percentage

[tex]\dfrac{5}{25} = \dfrac{5\times4}{25\times4}=\dfrac{20}{100}[/tex]

% = per cent

"per" means "out of"

"cent" means "one hundred"

so

20/100 = 20%

The range of the situation is 30 to 55.

An equation is a mathematical expression that contains an equals symbol. Equations often contain algebra. Algebra is used when you do not know the exact number in a calculation.

Given:

A vinyl decal shop charges a set-up fee of $25.00

$5.00 for each decal printed.

as, f(x)=5x+25 represents the total cost of the set-up fee

we have 6 cheerleaders

put x= 1

5x+25 = 5+25 = 30

and x=6

5x+25= 5*6+25= 30+25= 55

Hence, the range is 30 to 55.

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The correct option is C. x² + (x – 2)² = 100.

The equation which depicts x, the side length of the greater square is  x² + (x – 2)² = 100.

In geometry, a square is a plane figure with 4 equal sides as well as 4 right (90°) angles. A square is a subset of a rectangle (an equilateral rectangle) and a subset of a parallelogram (an equilateral & equiangular one).

Now, as per the question;

This is given by relation shown by expression;

x² + (x-2)² = 100

Therefore, the equation which represents x, the side length of the greater square is x² + (x-2)² = 100.

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The complete question is-

A group of students is given a 10 by 10 grid to cut into individual unit squares. The challenge is to create two squares using all of the unit squares. Their teacher states that after the two new squares are formed, one should have a side length two units greater than the other.

Which equation represents x, the side length of the greater square?

A. x² + (x – 2)² = 10

B. x² + 2x² = 10

C. x² + (x – 2)² = 100

D. x² + 2x² = 100

First order equations include linear equations. In the coordinate system, the linear equations are defined for lines. A linear equation in one variable is one in which there is a homogeneous variable of degree 1 (i.e., only one variable). Multiple variables may be present in a linear equation. Linear equations in two variables, for example, are used when a linear equation contains two variables. Examples of linear equations include 2x - 3 = 0, 2y = 8, m + 1 = 0, x/2 = 3, and 3x - y + z = 3.

10) -6(-5+r) = 102

     30 -6r =102

     -6r = 72

        r = -12

11) -1 = x - 4 +4

      x =-1

12) 0 = -6x -2x

     -8x = 0

 x= 0

13)5n+ 4n =9

      n =1

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Answer:e=8/7=1.143

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    4*e-5+2*e-(e+3-2*e)=0

Add  8  to both sides of the equation :

                     7e = 8

Divide both sides of the equation by 7:

                    e = 8/7 = 1.143

And then you get

Divide both sides of the equation by 7:

                    e = 8/7 = 1.143

Answer:

                   4*e-5+2*e-(e+3-2*e)=0

Add  8  to both sides of the equation :

                    7e = 8

Divide both sides of the equation by 7:

                   e = 8/7 = 1.143

And then you get

Divide both sides of the equation by 7:

                   e = 8/7 = 1.143

Step-by-step explanation:

The slope of the line shown is 1/5, and being parallel means having the same slope. So it’s either a or b.

Next, you plug in (-2, 2) into y=1/5x+b to find b.

Solving you get: 2=1/5 * -2 +b

2=-2/5+b

B=2 2/5

12/5 = 2 2/5

So the answer is b.

Hope this helps!