Explanation:
Q=mc(T2-T1)
or
q = mcΔT ,
where m is the mass of the sample,
c is the specific heat,
and ΔT is the temperature change.
Q=2.0 × 2000 × 5
Q=20000J⋅kg −1 ⋅K −1
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The more exercise a person takes the fewer medical problems they report. This is an example of:
O A. statistical independence.
B. a positive correlation.
O C. a negative correlation.
D. a curvilinear relationship
Answer:
The best answer seems to be B because there is a strong positive correlation that the more exercise a person does, the fewer medical problems they have
Explanation:
Can I have brainliest? It would help me out, if not thanks anyways! Hope this helped and have a nice day!
The more exercise a person takes the fewer medical problems they report. This is an example of a positive correlation. The correct option is B.
What is positive correlation?When two variables rise or decrease simultaneously, there is a positive correlation; when there is a negative correlation, one variable increases as the other falls.
When two variables behave in unison, rising or falling in lockstep with one another, there is a positive correlation.
When two variables move in opposition to one another—that is, when one rises, the other falls—this is known as a negative correlation.
A person reports fewer medical issues the more activity they get. An illustration of a positive correlation would be this.
Thus, the correct option is B.
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(Forces and the Laws of Motion pg. 141; Friction) (Problem 4)
A box of books weighing 325 N moves at a constant velocity across the
floor when the box is pushed with a force of 425 N exerted downward at an
angle of 35.2° below the horizontal. Find μk between the box and the floor.
The coefficient of kinetic friction is determined as 0.75.
What is coefficient of friction?
The coefficient of kinetic friction is calculated by applying the newton's second law of motion.
Fsinθ - Ff = ma
where;
Ff is frictional forceθ is angle of applied forceW = mg
where;
m is mass of the boxm = W/g
m = 325/9.8
m = 33.2 kg
425 sin(35.2) - Ff = 33.2a
425 sin(35.2) - μW = 33.2a
at constant velocity, a = 0
425 sin(35.2) - μW= 0
μW = 244.98
μ = 244.98/W
μ = 244.98/325
μ = 0.75
Thus, the coefficient of kinetic friction is 0.75.
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if sample of silver and lead each had volumes equal to 1ml, which would have the greater mass, and how much would the difference in the masses be?
If sample of silver and lead each had volumes equal to 1ml, Lead would have the greater mass, and the difference in the masses would be around 0.84grams
What do you mean by term mass?The mass of a physical body is a measure of its entire makeup. This also measures inertia, or the body's resistance to acceleration (change in velocity) in the presence of a net force.
The basic mass unit in the SI is the kilogram (kg)
What is the calculation for the given problem?The Density of Silver = 10.5 g / cm^3
The Density of Lead = 11.34 g / cm^3
So the masses given volume of 1 cm^3 is:
mass of Silver = 10.5 grams
mass of Lead = 11.34 grams
So we see that Lead has greater mass for similar volume.
On solving the given problem we get
The difference is
11.34 – 10.5 = 0.84 grams
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If a rocket initially at rest accelerates at a rate of 49.3 m/s/s for 8.7 seconds, its speed will be
decimal place.
Answer:
428.9 m/s
Explanation:
Vf = at = 49.3 m/s^2 * 8.7 s = 428.9 m/s
5.
In 1934, the wind speed on Mt. Washington in New Hampshire reached a record high.
Suppose a very sturdy glider is launched in this wind, so that in 45s the glider reaches the
speed of the wind. If the glider undergoes constant acceleration of 2.29m/s², what is the
wind's speed? Assume the glider is initially at rest.
The Speed of wind will be 103.5 m/s.
It is stated in the question that a glider is launched into the wind and in 45 seconds it attains the speed of the wind. Also, It is given that it attains a constant acceleration of 2.29m/s² and it starts moving from a state of rest.
We know the relation between velocity, time, and acceleration can be represented by Newton's first equation: v = u + at
where, v = Final velocity, u = Initial velocity, a = Acceleration, and t = Time
In this case, we have to find the final velocity of the glider to know the speed of the wind, and u = 0, a = 2.29m/s², t = 45sec
Putting values in the equation we get :
=> v = 0 + (2.29)*45
=> v = 103.5
Hence, the Speed of wind will be 103.5 m/s
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A 200 kg car has a constant velocity of 40 m/s. Suddenly the driver steps on the
brakes, and the force of friction that slows down the car is 1,000 N. What is the
acceleration of the car?
Answer:
acceleration =Force/mass
a=1000/200=5m/s
An object is launched at a velocity of 20 / in a direction
making an angle of 25° upward with the horizontal. What is the
maximum height reached by the object? What is the total flight time
(between launch and touching the ground) of the object? What is the
horizontal range (maximum x above ground) of the object? What is the
magnitude of the velocity of the object just before it hits the
When an object is thrown with an angle with horizontal, it makes projectile motion
It is given that angle of projectile was 25 degree
The formulas of projectile motion is as follows:
component of velocity at time t = Vxcos[tex]\alpha[/tex]
time of maximum height= vsin[tex]\alpha[/tex] /g
maximum height = (v sin[tex]\alpha[/tex] )^2/2g
horizontal range = v^2 sin2[tex]\alpha[/tex]/g
v is given to be 20 m/s
time of flight is given by v 2sin[tex]\alpha[/tex]/g
therefore, time of flight = 20 x 2x0.4226 /10 = 1.690 seconds
maximum horizontal range = 20 x 20 x 0.766/10 =30.641 meters
Disclaimer: The value of acceleration due to gravity is assumed to be 10 m/s^2 also the speed of velocity has no unit and hence m/s has been considered
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True or false - The vector for a negative acceleration points in the opposite direction when
compared to the vector for a positive acceleration.
Explanation:
the ratio between two circles vqjoizxcvu g çm
A speedboat moves west at 108 km/h for 22.0 min. It then moves at 60.0° south of west at 90.0 km/h for 10.0 min.
What is the average speed for the trip?
What is the magnitude of average velocity for the trip?
What is the direction of average velocity for the trip? Enter the angle in degrees where negative indicates north of west and positive indicates south of west.
The average speed for the trip is 102.4 km/h.
The magnitude of average velocity for the trip is 171.7 km/h in the direction of 27⁰ south of west.
What is average speed?
The average speed of an object is the ratio of total distance traveled by an object to the total time of motion.
avg. speed = total distance / total time of motion
total time of motion = (10 min/60 min/hr) + (22 min/60 min/hr)
total time of motion = (0.167 hr) + (0.367 hr) = 0.534 hr
total distance = (108 km/hr x 0.367 hr) + (90 km/h x 0.167 hr) = 54.67 km
avg. speed = (54.67 km)/(0.534 hr) = 102.4 km/h
Average velocity of the tripThe average velocity of the trip is the resultant velocity of the trip.
Vy = -90 km/h x sin(60) = -77.94 km/h
Vx = (-108 km/h) + (-90 km/h x cos 60)
Vx = -153 km/h
V = √Vy² + Vx²
V = √[(-77.94)² + (-153²)]
V = 171.7 km/h
Direction of the velocityθ = arc tan(Vy/Vx)
θ = arc tan (-77.94/-153)
θ = 27⁰ south of west
Thus, the magnitude of average velocity for the trip is 171.7 km/h in the direction of 27⁰ south of west.
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What is the largest structure people have put into space?
Hubble Space Telescope
International Space Station
Space Shuttle
Mars rover Curiosity
Answer:
International Space Station
Explanation:
I did the test and I’m 100% sure
Answer:
b) International Space Station
Explanation:
International Space Station (ISS) is the largest structure, which people have put into space. Hence, option (b) is correct.
A rightward force of 125 N is applied to a book to move it across a desk with a rightward
acceleration. The net force is 75 N to the right. A free-body diagram for this situation looks like
this:
The free body diagram of this situation involves a rightward force of 125 N and frictional force of 50 N.
What is free body diagram?A free-body diagram is a sketch of an object of interest with all the surrounding objects stripped away and all of the forces acting on the body shown.
Frictional force on the objectF - ff = F(net)
where;
F is the rightward applied forceff is the frictional forceF(net) is the net force125 - ff = 75
ff = 125 - 75
ff = 50 N
Free body diagram of the forces125 N → Ф ← 50 N
Thus, the free body diagram of this situation involves a rightward force of 125 N and frictional force of 50 N.
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2.819 to the nearest 10th's place.
Answer:
2.8 would be the correct answer as 1 rounds down
Raoul and Maria set out walking from their aunt's house. Raoul walks a certain distance straight east and then a certain distance straight north. A crow passing overhead starts from the same point as Raoul, but flies in a straight line. Raoul observes that the crow flies a total distance of 500 m in a direction 35° north of east to reach the same final point as Raoul. Maria starts from the same point as Raoul, but she walks first straight west and then straight south. Her final point is 700 m from the starting point in a direction that is 55° south of west. How far did Raoul walk on the east leg of his trip? How far on the north leg? Similarly, how far did Maria walk on the west leg and how far on the south leg? Express these quantities in terms of displacement vectors and their components, using a coordinate system with the +x axis pointing east and the +y axis pointing north.
Answer:
no entiendo tu pregunta
Which option best describes the average acceleration from 40 to 70 s?
C. The average acceleration is positive and smaller in magnitude than the initial acceleration.
What is average velocity?Average velocity is defined as the change in position or displacement (∆x) divided by the time intervals (∆t) in which the displacement occurs.
a = Δv/Δt
where;
Δv is change in velocityΔt is change in timea = (250 - 248) / (70 - 40)
a = 0.067 m/s²
Thus, we can conclude that the average acceleration is positive and smaller in magnitude than the initial acceleration.
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Please refer to the picture.
The graph is displayed in the following attachment.
The graph shows that the answers to the problem are x = -1.2 and x = 1.7.
From the image, we may deduce that
The graph is displayed in the following attachment.
The graph shows that the answers to the problem are x = -1.2 and x = 1.7.
We must create the graph of the function for the given range of values based on the image (that is for values of x from -3 to 3)
We will first establish the function's table of values.
Values for the function x y -3 in a table 1.33 -2 2 -1 4 0 Definable
1 -4 2 -2\s3 -1.33
(The docx attachment provides a better view.)
Additionally, the function's graph (purple lines) is
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The space shuttle undergoes an acceleration of 53.9 m/s. How fast is it traveling at the end of 55.2 s?
It is traveling at the end of 55.2 s in the speed of 2975,28m/s
acceleration: the rate at which the speed and direction of a moving object vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates. In this instance, you requested the speed and provided the time, acceleration, and speed. Speed is calculated as follows: speed = distance * time. Knowing the units for distance and time is necessary to calculate the units for speed. Since acceleration is equal to time, multiplying the two numbers equals speed. The formula would be:
Acceleration x Time Equals Velocity
Velocity: 53.9 m/s2 x 55.2
= 2975,28 m/s
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What is the mass of a 10.4 cm³ cube of lead.
The mass of a 10.4 cm³ is, approximately, 117.42 grams.
Explanation:Volume of the cube: 10.4 cm³
Now, let's look up the density of lead:
Density of lead: 11.29 g/cm³.
This value fo density tells us that 1 cm³ of lead has a mass of 11.29g. Hence, we can stablish the following rule of 3 to find the mass of our cube.
1 cm³ ----------------> 11.29 g
10.4 cm³------------> x
x= (10.4 cm³ ⋅ 11.29 g)/1 cm³
x= 117.42 g.
Conclusion.
The mass of a 10.4 cm³ is, approximately, 117.42 g.
phys 181 magnitiude of a vector
The y component of the vector is 37.7 N and the angle between the vectors is 26.2⁰.
Y-component of the vectorThe y component of the vector will be determined from the resultant vector and the x component of the vector.
R² = Y² + X²
Y² = R² - X²
Where;
Y is the y-component of the vectorX is the x component of the vectorR is the resultant vectorY² = 85.2² - 76.4²
Y² = 1,422.08
Y = √1,422.08
Y = 37.7 N
Angle between the vectorsθ = arc tan (Y/X)
θ = arc tan (37.7/76.4)
θ = 26.2⁰
Thus, the y component of the vector is 37.7 N and the angle between the vectors is 26.2⁰.
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A ball dropped from a window strikes the ground 2.71 seconds later. How high is the window above the ground?
[tex]s=36.52m[/tex]
Given ,
Time =2.71 second
We apply the formula
[tex]s=ut+12at^2[/tex]
[tex]u=0,t=2.73 \\a=g \\So, the \\height \\ s=36.52m[/tex]
When a body is lying on a horizontal surface, the object is subjected to a downward force due to the action of gravity. These gravitational forces always aim to attract the item, confirming the force's nature as an attractive force. Consider an object of mass "M" resting on a horizontal surface; the force exerted to the object by gravity is equal to the weight of the object "W." The acceleration owing to gravity, indicated as "g," is the acceleration by which an object is drawn towards the ground. As a result, Newton's second law states that when the values in the above connection are substituted.
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what enables cellular customers to continue making voice calls and connect to the internet when away from home
Answer:
Voice over Internet Protocol (VoIP)
Explanation:
is a technology that allows you to make voice calls using a broadband Internet connection instead of a regular (or analog) phone line.
Kalea throws a baseball directly upward at time t = 0 at an initial speed of 14.3 m/s. How high h does the ball rise above its release point? Ignore air resistance and use g = 9.80 m/s^2.
The ball reaches a height of 9.57 meters against gravity.
The acceleration an object experiences as a result of gravitational force is known as acceleration due to gravity. M/s2 is its SI unit. Its vector nature—which includes both magnitude and direction—makes it a quantity. The unit g stands for gravitational acceleration. At sea level, the standard value of g on the earth's surface is 9.8 m/s2.
A body is drawn toward the center of the earth by the force of gravity. Let's have a look at two bodies with masses ma and mb. When two bodies are subjected to equal forces, the force in terms of mass is given by:
The inertial mass of a body is defined as mb = ma [aA/aB].
In response to the gravitational pull of two bodies,
FA = GMmA/r2,
FB = GMmB/r2,
mB = [FB/FA] × mA
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A person travels by car from one city to an-
other. She drives for 21.1 min at 86.8 km/h
10.6 min at 106 km/h, 36.5 min at 30.9 km/h,
and spends 17.4 min along the way eating
lunch and buying gas.
Determine the distance between the cities
along this route.
Answer in units of km.
68.31 km.
Explanation:First, let's refer to the distance formula:
[tex]d=v*t[/tex], where d is distance, v is velocity or speed and t is time.
Now, let's find the distance covered by each individual speed that the car had:
1. Speed 1.In order to use the formula, we need to convert minutes into hours since the speed is given in km/h.
21.1 min/60= 0.35 h.
Now, apply the distance formula.
d=(0.35h)*(86.8km/h)= 30.38 km.
2. Speed 2.Convert minutes to hours again and do the same calculations.
10.6min/60=0.18h
d=(0.18h)*(106km/h)= 19.08 km.
3. Speed 3.36.5min/60= 0.61h
d=(0.61h)*(30.9km/h)= 18.85 km.
4. Obtain the total distance.The total distance must be given by the addition of all individual distances traveled by the car on each speed:
Total distance= 30.38 km + 19.08 km + 18.85 km= 68.31 km.
find the component form of the vector V (0,1) (6,7/2)
Answer:
I would interpret it to mean:
Vx = (6 - 0) = 6
Vy = (3.5 - 1) = 2.5
or V = (6, 2.5)
V refers to the vector itself and not its relative position in space
Average velocity is different than average
speed because calculating average velocity involves
The correct answer is displacement.
Average velocity differs from average speed because displacement is used to calculate average velocity.
What is displacement?
Being a vector, displacement has both magnitude and direction. In one-dimensional motion, the direction should be stated with a plus or minus sign to ensure sure the direction is right. It always occurs in a straight line between two sites. Although it is not a vector variable and lacks a direction sign, the word "distance traveled" is also used to refer to the length of the path that was taken to get from one place to another. The distance traveled is not always equal in both magnitude and direction; on occasion, it may exceed the magnitude of the displacement between the sites.
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A remote controlled toy car starts from rest and begins to accelerate in a straight line. The figure below represents "snapshots" of the car's position at equal 0.5 s time intervals. (Assume the positive direction is to the right. Indicate the direction with the sign of your answer.)
A. The car's average velocity (in m/s) in the interval between t = 1.0 s to t = 1.5 s is 1 m/s
B. The car's acceleration (in m/s²) at t = 1.5 s is 0.4 m/s²
C. The speed of the car is increasing with time
A. How to determine the average velocity between t = 1.0 s to t = 1.5 sTotal time = 1.5 - 1 = 0.5 sTotal distance = 0.9 - 0.4 = 0.5 mAverage velocity =?Average velocity = total distance / total time
Average velocity = 0.5 / 0.5
Average velocity = 1 m/s
B. How to determine the acceleration at t = 1.5 sWe'll begin by calculating the velocity at t = 1.5 s. This can be obtained as follow:
Distance = 0.9 mTime = 1.5 sVelocity =?Velocity = Distance / time
Velocity = 0.9 / 1.5
Velocity = 0.6 m/s
Finally, we shall determine the acceleration . This is shown below:
Time = 1.5 sVelocity = 0.6 m/sAcceleration =?Acceleration = velocity / time
Acceleration = 0.6 / 1.5
Acceleration = 0.4 m/s²
C. How to determine if the speed is increasing or notThe acceleration we calculated above (i.e 0.4 m/s²) is positive. This simply indicates that the speed of the car is increasing.
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Missing part of the question:
(a) What is the car's average velocity (in m/s) in the interval between t = 1.0 s to t = 1.5 s?
(b) Using data from t = 1.0 s to t = 2.0 s, what is the car's acceleration (in m/s2) at t = 1.5 s?
(c) Is the car's speed increasing or decreasing with time?
If I stop applying a force to an object, will it continue to accelerate? Why?
Answer:
As long as the force is applied to a given object, it will to accelerate. Once the force is withdrawn, the object will continue to move at a constant velocity, according to the Law of Inertia.
Explanation:
. Which of the following is the last part of the technological design process? test and evaluate a solution research existing solutions refine the original solution design decide on a solution
According to the research, the correct option is to refine the original solution design. It is the last part of the technological design process.
What is the technological design process?It is the process and problem solving using design as a methodological strategy that allows identifying and solving a problem through inductive procedures and logical reasoning.
In this sense, the last part of this process includes what refers to the production of a first model of the solution, which is tested to evaluate its performance, the result of this evaluation must influence the modification or refinement of the original solution design that is implemented in the solution of the problem that gave rise to the generation of the project.
Therefore, we can conclude that according to the research, the correct option is to refine the original solution design. It is the last part of the technological design process.
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Carrie has experienced brain damage to her left hemisphere. She will most likely experience difficulty with which ability?
A) putting a puzzle together
B) recognizing faces
C)judging time and rhythm
D)understanding sarcasm and irony
Part A
What is the instantaneous velocity of a freely falling object 5.0 s after it is released from a position of rest?
Express your answer to two significant figures and include the appropriate units.
v=
The instantaneous velocity of a freely falling object is 49.0 m/s
the instantaneous velocity is calculated by the first equation of the motion that is v = u + at here u = initial velocity and a is acceleration and t is time since its freely falling object the acceleration is acceleration due to gravity that is 9.8 m/s and the initial velocity is 0m /s the time given is 5 sec so putting it into equation 0+ 9.8X 5= 49.0 m/s
The instantaneous velocity of an object is the limit of the average velocity as the elapsed time approaches zero, or the derivative of x with respect to t: v ( t ) = d d t x ( t ) . v ( t ) = d d t x ( t ) . Like average velocity, instantaneous velocity is a vector with dimension of length per time.
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What is the total capacity in gallons of a rectangular tank 5 meters in height knowing that it will hold 200 liters per foot?
The total capacity in gallons of the rectangular tank is 866.58 gallons
How to find the total capacity in gallons of the rectangular tank?Since the rectangular tank is 5 meters in height knowing that it will hold 200 liters per foot, we need to know the total capacity of water it contains for the height of 5 meters.
Converting 5 m to feet, we have
Since 1 m = 3.28 ft, we have
5 m = 5 × 1 m = 5 × 3.28 ft = 16.4 ft
Since the height of the tank in feet is 16.4 ft and the tank holds 200 L/ft, then the total capacity of water in 16.4 ft is D = 200 L/ft × 16.4 ft
= 3280 L
To know the total capacity of the tank in gallons,we convert 3280 L to gallons
Since 1 L = 0.2642 gallons, converting 3280 L to gallons, we have
3280 L = 3280 × 1 L = 3280 × 0.2642 gallons
= 866.576 gallons
≡ 866.58 gallons
So, the total capacity in gallons of the rectangular tank is 866.58 gallons
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