Answer:
The nucleus contains two types of subatomic particles, protons and neutrons. The protons have a positive electrical charge and the neutrons have no electrical charge. A third type of subatomic particle, electrons, move around the nucleus. The electrons have a negative electrical charge.
Haaaaaaaalllllllpppppp
Name 2 Triangular Items that are something you can hold. And then name those items' Length, Width, Height, Area, or Volume.
Answer:
ice creem cone candy
Explanation
why is the potassium atom larger than the kypton atom
A certain rifle bullet has a mass of 6.93 g. Calculate the de Broglie wavelength of the bullet traveling at 1649 miles per hour.
The de Broglie wavelength of the bullet traveling at 1649 miles per hour is 1.3 x 10^34 m.
What is de Broglie wavelength?
The wavelength that is associated with an object in relation to its quantum and mass is known as de Broglie wavelength.
The particles de Broglie wavelength is inversely proportional to its force.
de Broglie wavelength is expressed as : ^ = h/mv
Where ^ is wavelength, h is plank constant, m is mass and v is velocity.
1 miles = 1.60934 km
So 1649 miles = 2653.8 km
Then 2653.8 x 1000/ 60x60 = 737.2 ms -1.
The momentum of bullet is p = mv = 0.00693kg x 737.2 ms-1
= 5.109 kg/ms
Now, de Broglie wavelength = h/p = 6.63 x 10^-34 / 5.109 kg/ms
= 1.3 x 10^34 m
Thus, de Broglie wavelength of the bullet traveling at 1649 miles per hour is 1.3 x 10^34 m.
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Which branch of chemistry is concerned with the chemical processes that occur within living organisms? A. Physical B. Inorganic C. Biochemistry D. Organic
Answer: C. Biochemistry
Explanation:
Merriam-Webster Dictionary defines Biochemistry as:
"chemistry that deals with the chemical compounds and processes occurring in organisms"
“Definition of BIOCHEMISTRY.” Merriam-Webster.com, 2018, www.merriam-webster.com/dictionary/biochemistry.
A sample of natural gas was found to contain 0.070% (percent by volume) of hydrogen sulfide, H2S. Calculate the mass of H2S present in 2.00 L of natural gas at 298 K.
The mass of H₂s present in 2.00 L of natural gas at 298 K is 0.002156 g.
What is the volume of hydrogen sulfide in 2.00 L of natural gas at 298 K?The volume hydrogen sulfide in 2.00 L of natural gas at 298 K is calculated as follows:
Volume of hydrogen sulfide = percent composition * volume of natural gas
Volume of hydrogen sulfide = 0.07/100 * 2.00 L
Volume of hydrogen sulfide = 0.014 L
The given temperature is standard temperature.
Density of H₂s at STP is equal to 1.54 g/L.
mass of H₂s = density * volume
mass of H₂s = 0.0014 * 1.54
mass of H₂s = 0.002156 g
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If the oxide contains 22.24 % O by mass, what is the identity of the metal?
Express your answer as a chemical symbol.
The oxide contains 22.24% O by mass, so the identity of the metal as a chemical symbol is lead (Pb).
What is metal?A substance with high electrical conductivity, luster, and malleability, which readily loses electrons to form positive ions (cations) are called metals.
Mass percentage of oxygen in the oxide, i.e.,
ω(O) divided by 100 ω(O)
=22.24% ÷ 100%.
Mass percentage of oxygen in the oxide, i.e .ω(O) = 0.2224
Now the mass percentage of oxygen in the oxide multiplied by 100 ten we get the mass of oxygen in the oxide. If we take 100 grams of compound:
1) m(O) = ω(O) * 100 g.
Mass of oxygen in the oxide, i.e. m(O) = 0.2224 * 100 g.
Mass of oxygen in the oxide. i.e., m(O) =22.24g
Amount of oxygen, i.e.,
n(O) = mass of oxygen in the oxide ÷ molar mass of oxygen.
n(O) = m(O) ÷ M(O) amount of oxygen
n(O) = 22.24g ÷ 16 g/mol,
amount of oxygen i.e. n(O) = 1.39 mol
Mass of metal in the oxide, i.e., m(M) = 100 g - 22.24 g.
Mass of metal in the oxide i.e., m(M) = 77.76g
Now we to find the molar mass of metal oxide,
Molar mass of the metal :
= mass of metal in the oxide ÷ amount of oxygen(M)
= m(M) ÷ n(M). M(M)
= 77.76 g ÷ 1.39 mol.
Molar mass of the metal will be 5.94 g/mol.
Therefore, The identity of the metal is lead (Pb).
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2. How many grams of copper(II) chloride contain 2.17 grams of Cu²+?
4.63 gram of Cooper(II) chloride contain 2.17 grams of Cu²+
Molar mass of copper(II) chloride = 134.45 g/mol
Molar mass of copper = 63 grams
The average mass of an element's atoms expressed in atomic mass units is known as its atomic mass (amu, also known as daltons, D). The mass of each isotope is multiplied by its abundance to produce the atomic mass, which is a weighted average of all the isotopes of that element.
63 gram of copper is present in 134.45 g/mol of copper(II) chloride
1 gram copper is present in copper(II) chloride = 134.45/63 = 2.13 gram
2.17 gram Cu²+ in copper(II) chloride = 2.13 gram x 2.17 gram = 4.63 gram
Hence, 4.63 gram of Copper(ii) chloride contain 2.17 grams of Cu²+
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I have a tube filled with water with a temperature of 20.0°C and with a vapor pressure of 17.5 torr. If I collect gas over this water, and the total gas pressure of the gas solution is found to be 453.0 torr, what would be the pressure of the pure gas in atm? Question 21 options:
The pure gas has a pressure of 0.573 atm.
How does pressure work?Pressure is the amount of force applied perpendicularly to an object's surface divided by the surface area across which it is applied. In comparison to the surrounding pressure, gauge pressure is the pressure. Pressure is expressed using a variety of units.
What in chemistry is ATM?The definition of the standard atmosphere, or atm, as a unit of pressure is 101325 Pa. It is occasionally used as a standard pressure or a reference pressure. It roughly corresponds to the average atmospheric pressure at sea level on Earth.
based on the specified value;
we know that,
P(t)=P(water)+P(pure gas)
where,
P(t)=TOTAL PRESSURE OF THE GAS
P(water)= Vapour pressure of water
P(pure gas)=Pressure of pure gas
GIVEN;
P(pure gas)=P(t)-P(water)
=(453.0-17.5)
=435.5 torr
or P(pure gas)=435.5/760
=0.573
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what is the mass number of iron with 19 neutrons?
Answer:
Explanation:
The mass number of iron is 55.845amu. The mass number is equal to the number of protons added to he number of neutrons in an atom. Each neutron or proton has a mass of about 1amu.Thus we say 55.84500 atomic mass units * 19 =
1 061.055 atomic mass units
What is the meaning of the word string in string coffe and string acid? How do we deal with this difference?
It ought to be "strong." Otherwise, string acid and string coffee would be absurd. So, the proper query would be:
What does the word "strong" mean in the context of strong coffee and strong acid?
Strong coffee indicates that there are more solids and coffee dissolved in the solution. It implies that strong coffee will typically be darker in color. It will also include a lot of caffeine. Strong coffee includes espresso and Death Wish Coffee.
The only acid that totally ionizes in aqueous solution is a strong acid. As soon as it is dissolved in water, it releases one proton H+. Its pH range will be between 0 and 1.
Strong acids include hydrochloric acid and sulphuric acid, for instance.
When strong coffee is dissolved in water, no chemical reaction occurs. When strong acid is dissolved in water, a chemical reaction occurs.
Strong coffee can be consumed, but strong acid cannot because they are both extremely corrosive.
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If you make a Carbon (C) atom that has an overall charge of -1. How many protons does it have? How many electrons?=
Students measured the area of Mr. Gandelman’s classroom. They noted that it is 74.27 square meters. According to measurements indicated in the architect’s plans, the room’s actual area is 78.5 square meters. What is the % error in the students’ measurement?
Answer:
Personally I think thatthr answer could be 5.38853503%, you can round it however you need.
Explanation:
There's a value of error between the noted square meters and the actual room's area. which is 4.23. Using the formula to get the percentage of error is getting the value (78.5 - 74.27 = 4.23) and dividing it by 78.5. Then just multiply it by 100 to get the percentage.
AgNo3(aq) +KSCN(aq) = KNO3(aq) + AgSCN(s) what is the equilibrium constan
The equilibrium constant is K=[KNO3]/[AgNO3][KSCN]
The equilibrium constant is defined as the ratio of the concentration of products upon reactants.The species present in solid phase are taken as unity.Substituting the values, we getK=[KNO3][AgSCN]/AgNO3][KSCN]K=[KNO3]×1/[AgNO3][KSCN]k=[KNO3]/[AgNO3][KSCN]The ratio of reactant to product amounts that is used to predict chemical behavior is the definition of the equilibrium constant for a chemical process. The rate constants are constant at a certain temperature.The value of a chemical reaction's reaction quotient at chemical equilibrium, a condition that a dynamic chemical system approaches is the equilibrium constant for that reaction when enough time has passed and at which its composition shows no evident tendency to change further.The equilibrium constant is independent of the initial analytical concentrations of the species of the reactant and product in the mixture given a certain set of reaction conditions.As a result, the composition of a system at equilibrium may be calculated from its starting composition using known equilibrium constant values. However, factors affecting the reaction such as temperature, solvent, and ionic strength may all affect the equilibrium constant's value.To learn more about equilibrium constant visit:
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Add curved arrows(s) to show the resonance using the following pattern: a lone pair (on nitrogen) next to a pi bond. Modify the second structure given to draw the new resonance structure. Include lone pairs and charges in your structure. Using the + and - tools to add charges to an atom, and use the single bond tool to add/remove double bonds.
Answer:
ddddxddddddddddddddddddddddddd
Zootopia movie: Why is Judy Hopps placement at the police academy so unusual?
Answer:
down below
Explanation:
Judy Hopps was one of the smaller prey animal while the others were predators or bigger prey animals. Meaning, she was tiny and in some minds, was easier to take down or may not be able to do the job as well as the bigger animals. Also, she was, less noticeably, the only female prey animal.
Which statement about reversible reactions is correct? (1 point)
O The forward and reverse reactions must happen at the same rate.
O They are always at equilibrium.
O They always involve gases.
O They can occur in either direction.
Answer: the last one
Explanation: it is the only one that makes sense \
sorry if its wrong
What type of scientist uses mathematics to propose untested ideas
Answer: theoretical scientist
Explanation:
What is the limiting reactant if 0.5 g Al is reacted with 0.5 g CuCl2?
What is the theoretical yield of copper produced by this reaction?
Taking into account the reaction stoichiometry ,CuCl₂ is the limiting reagent and the theoretical yield of copper produced is 0.2363 grams.
Reaction stoichiometryIn first place, the balanced reaction is:
2 Al + 3 CuCl₂ → 3 Cu + 2 AlCl₃
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
Al: 2 molesCuCl₂: 3 molesCu: 3 molesAlCl₃: 2 molesThe molar mass of the compounds is:
Al: 27 g/moleCuCl₂: 134.44 g/moleCu: 63.54 g/moleAlCl₃: 133.35 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
Al: 2 moles ×27 g/mole= 54 gramsCuCl₂: 3 moles ×134.44 g/mole= 403.32 gramsCu: 3 moles ×63.54 g/mole= 190.62 gramsAlCl₃: 2 moles ×133.35 g/mole= 266.7 gramsLimiting reagentThe limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
Limiting reagent in this caseTo determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 54 grams of Al reacts with 403.32 grams of CuCl₂, 0.5 grams of Al reacts with how much mass of CuCl₂?
mass of CuCl₂= (0.5 grams of Al× 403.32 grams of CuCl₂)÷ 54 grams of Al
mass of CuCl₂= 3.734 grams
But 3.734 grams of CuCl₂ are not available, 0.5 grams are available. Since you have less mass than you need to react with 0.5 grams of Al, CuCl₂ will be the limiting reagent.
Definition of theoretical yieldThe theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.
Theoretical yield of copperConsidering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 403.32 grams of CuCl₂ form 190.62 grams of Cu, 0.5 grams of CuCl₂ form how much mass of Cu?
mass of Cu= (0.5 grams of CuCl₂× 190.62 grams of Cu)÷ 403.32 grams of CuCl₂
mass of Cu= 0.2363 grams
Then, the theoretical yield of copper produced is 0.2363 grams.
SummaryIn summary, you obtain:
CuCl₂ is the limiting reagent.the theoretical yield of copper produced is 0.2363 grams.Learn more about theoretical yield:
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Write the formula for the compounds below:
Sodium iodide
Potassium perchlorate
Calcium nitrite
Copper(||) sulfate
Answer:
check explanation
Explanation:
Sodium Iodide=NaI
Potassium perchlorate=KClO4
Calcium nitrate= Ca(NO3)2
Copper (ii) sulfate=CuSO4
What is the volume of each of the following at STP?
A.44.00 g N2
B.0.25 mol NH3
Considering the definition of STP conditions, you obtain:
A. 44 grams of N₂ will ocupy at STP 35.168 L.
B. 0.25 moles of NH₃ will ocupy at STP 5.6 L.
Definition of STP conditionsThe STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.
Definition of molar massThe molar mass of substance is a property defined as the amount of mass that a substance contains in one mole.
Volume in this caseIn this case, you have:
44 grams of N₂, with a molar mass of 28 g/mole0.25 moles NH₃You can apply the following rule of three to know the number of moles of N₂: if 28 grams of the compound are contained in 1 mole, 44 grams are contained in how many moles?
number of moles of N₂= (44 grams× 1 mole)÷ 28 grams
number of moles of N₂= 1.57 moles
Now, you can apply the following rules of three to know the volume of N₂ and NH₃:
if by definition of STP conditions 1 mole of N₂ occupies a volume of 22.4 liters, 1.57 moles occupies how much volume?volume of N₂= (1.57 moles× 22.4 L)÷ 1 mole
volume of N₂= 35.168 L
if by definition of STP conditions 1 mole of NH₃ occupies a volume of 22.4 liters, 0.25 moles occupies how much volume?volume of NH₃= (0.25 moles× 22.4 L)÷ 1 mole
volume of NH₃= 5.6 L
Finally, you obtain:
A. 44 grams of N₂ will ocupy at STP 35.168 L.
B. 0.25 moles of NH₃ will ocupy at STP 5.6 L.
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A student creates a scale model of planets where 1 centimeter (cm) is equal to 10,000 kilometers (km). In this model, which planet would have a diameter of approximately 12 cm?
The planet that would have a diameter of approximately 12 cm is Saturn.
What is a scale model?A scale model is a model which is used to represent another object using a given scale.
Scale models can be used to make small object bigger or larger objects smaller.
Considering the scale model of the planets where 1 centimeter (cm) is equal to 10,000 kilometers (km);
1 centimeter = 10,000 kilometers
12 centimeter = 1.2 × 10⁵ kilometers
The planet with a diameter of approximately 1.2 × 10⁵ kilometers is Saturn.
In conclusion, scale models are used to model objects.
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1.3511, 2.473, 5.687524, 7.555, 8.235 rounded to one significant figure. Please help, I'm stuck!
Answer:
1,2,6,8,8
Explanation:
1.3511=1
2.473 =3
5.687524=6
7.555=8
8.235=8
Calculate the areas and densities. Report the answers in the correct units.
a. the area of a rectangle with sides measuring 3 x 10^1 cm and 3 x 10^-2 cm
b. the area of a rectangle with sides measuring 1 x 10^3 cm and 5 x 10^-1 cm
c. the density of a substance having a mass of 9 x 10^5 g and a volume of 3 x 10^-1 cm3
d. the density of a substance having a mass of 4 x 10^-3 g and a volume of 2 x 10^-2 cm3
Considering the defintion of area of a rectangle and definition of density, you obtain the following areas and densities:
a. the area of the rectangle is 9×10⁻¹ cm².
b. the area of the rectangle is 5×10⁻²cm².
c. the density of the substance is 3×10⁶ g/cm³.
d. the density of the substance is 0.2 g/cm³.
Area of a rectangleA rectangle is a flat geometric figure with four sides, of which two sides that are opposite parallel to each other have the same length and the remaining two have another length.
The area of a rectangle is the product of the two contiguous sides of the rectangle:
Area of a rectangle= a×b
where a and b are the measures of the two sides.
Definition of densityDensity is a quantity that allows us to measure the amount of mass in a certain volume of a substance.
The expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:
density= mass÷ volume
a. Area of the rectangleIn this case, you know that the rectangle has:
a side of the rectangle is 3×10¹ cm.a side of the rectangle is 3×10⁻² cm.Then, the area of the rectangle can be calculated as:
Area of the rectangle= 3×10¹ cm× 3×10⁻² cm
To multiply numbers in scientific notation, you multiply the numbers that are not powers of 10 and add the exponents that are powers of ten. In this case:
Area of the rectangle= (3× 3)×10¹⁻² cm²
Area of the rectangle= 9×10⁻¹ cm²
Finally, the area of the rectangle is 9×10⁻¹ cm².
b. Area of the rectangleIn this case, you know that the rectangle has:
a side of the rectangle is 1×10³ cm.a side of the rectangle is 5×10⁻¹ cm.Then, the area of the rectangle can be calculated as:
Area of the rectangle= 1×10³ cm× 5×10⁻¹ cm
Solving
Area of the rectangle= (1× 5)×10³⁻¹ cm²
Area of the rectangle= 5×10⁻²cm²
Finally, the area of the rectangle is 5×10⁻²cm².
c. Density of the substanceIn this case, you know:
mass= 9×10⁵ gvolume= 3×10⁻¹ cm³Replacing in the definition of density:
density= 9×10⁵ g÷ 3×10⁻¹ cm³
Solving:
density= 3×10⁶ g/cm³
Finally, the density of the substance is 3×10⁶ g/cm³.
c. Density of the substanceIn this case, you know:
mass= 4×10⁻³ gvolume= 2×10⁻² cm³Replacing in the definition of density:
density= 4×10⁻³ g÷ 2×10⁻² cm³
Solving:
density= 0.2 g/cm³
Finally, the density of the substance is 0.2 g/cm³.
SummaryIn summary, you obtain the following areas and densities:
a. the area of the rectangle is 9×10⁻¹ cm².
b. the area of the rectangle is 5×10⁻²cm².
c. the density of the substance is 3×10⁶ g/cm³.
d. the density of the substance is 0.2 g/cm³.
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A rectangular piece of copper, 2.13 cm by 0.79 cm by 1.14 cm, weighs 17.11g. What is the density of the copper?
Density of copper is 8.92 g/cm3.
The mass of a substance per unit of volume is its density. Density is most frequently represented by the symbol(p), although Latin letter D may also be used.
Given:
weight of copper = 12.11 g
Volume = 2.13 cm * 0.79 cm * 1.14 cm
= 1.918 cm3
As we know that ,
Density = mass / volume
d = m/v
d = 17.11 / 1.918
density = 8.92 g/cm3
Density of copper is 8.92 g/cm3.
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an enclosed gas is at a pressure of 143,95kpa .if the volume is increased by 40% at constant temperature. what is the new pressure in kilopascals ?
All processes for which the temperature stays constant are described by Boyle's law.
Boyle's law is expressed as p1 * V1 = p2 * V2, where p1 and V1 are starting pressure and volume, respectively. The ultimate values of these gas parameters are p2 and V2.
Boyle's law formula can be stated in a variety of ways, depending on the parameter we want to estimate. Let's imagine we wish to determine the pressure that results from changing a gas' volume under isothermal conditions. The Boyle's law equation thus reads: p2 = p1 * V1 / V2 or p2 / p1 = V1 / V2.
As we can see, the final-to-initial pressure ratio is the opposite of the volume ratio.
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Red gold is a gold-copper alloy used to make jewlery. A piece of jewlery made of red gold weighs 8.97g and has a volume of 0.528cm3. Gold has a density of 19.3g/cm3 and copper has a density of 8.96g/cm3. Calculate the percentage by mass of each metal in jewelry. Assume the total volume of the jewelry is the sum of the volumes of the two metals it contains
Percent of gold and copper are 88.2 and 11.8
Red gold is a gold-copper alloy used to make jewelry .
Let the mass of gold be m1
Let the mass of copper be m2
We are given that m1+m2 =8.97 g
We know that volume is the ratio of mass to density
Thus
m1/d1 + m2/d2 = 0.528 cm3
where d1 and d2 is the density of gold and copper
m1/19.3 + m2/8.96 = 0.528
8.96m1 +19.3 m2 = 0.528 x 19.3 x 8.96 = 91.305
putting m1 = 8.97 - m2
8.96 ( 8.97 - m2 ) + 19.3 m2 = 91.305
80.3712 - 8.96m2 + 19.3 m2 =91.305
10.34 m2 = 91.305-80.3712
m2 = 10.9338 /10.34
=1.0537gm
m1=8.97-1.0537
=7.91gm
Therefore, percent of gold = 7.91/8.97 x 100 =88.20%
percent of copper = 100-88.2=11.8%
Therefore, percent of gold and copper are 88.2 and 11.8
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Which of the following best describes the reaction seen below?
2H2(g) + O2(g) → 2H2O(l)
a.
Two grams of hydrogen gas combine with 1 gram of oxygen gas to form 2 grams of water.
b.
Two molecules of hydrogen gas combine with 1 molecule of oxygen gas to form 2 molecules of water.
c.
Two liters of hydrogen gas combine with 2 liters of oxygen gas to form 2 liters of water.
d.
Two hydrogen atoms combine with 1 oxygen atom to form 2 water molecules.
Two molecules of hydrogen gas combine with 1 molecule of oxygen gas to form 2 molecules of water.
What is a word equation?A word equation is one in which the equation that is shown in the reaction is written in words rather than by the use of the chemical symbols of the elements that are involved.
We have the reaction; [tex]2H_{2} (g) + O_{2} (g) ---- > 2H_{2} O(l)[/tex], in order for this reaction to be written in the word equation form we have; Two molecules of hydrogen gas combine with 1 molecule of oxygen gas to form 2 molecules of water.
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The lab procedure says, "weigh 1.0 g of sodium chloride." Which of the following are acceptable masses?
The lab procedure
The 150 mL beaker's contents should be emptied into the sink, followed by a thorough water rinse of the beaker and temperature probe sodium . Add 20 g of ice to the beaker after weighing it.
sufficient water to make the combined weight match the combined weight of the ice and water consumed above. Put the thermometer in the slush, press the green button, and agitate the mixture.
For two minutes, slush. sodium Stir the slush while adding the 1.0 g of salt chloride. five minutes Simply press the red button. After saving the data, select Store Latest Run from the list.
The menu for experiments print the graph with both the sodium chloride and urea plots visible at once. sodium Which plot corresponds to which solid should be noted on the printout.
The 150 mL beaker's contents should be emptied into the sink, followed by a thorough water rinse of the beaker and temperature sodium .
Simply select Show Data Set from the Data menu, followed by the Run # you want to display, to examine one of your earlier plots. It is possible to display multiple pieces of data at once.
The Latest Run is the most recent Run, and the Runs are numbered consecutively in the order in which they were acquired. To display the chosen plot or plots, just use the commands Hide Data Set and Show Data Set. The plot display settings (such as axes scaling, etc.) may need to be changed.
Display one or both students' temperature charts using the y-axis label, as desired. The Data menu also includes options for deleting individual data sets.
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please answer holy its been an hour
Reverse the sign of the second equation, change the sign of the enthalpy and add. Option B
What is the enthalpy?The enthalpy could be obtained by the use of the Hess law of constant heat summation. As such, we have a number steps and it is possible for use to obtain the enthalpy of the final reaction as shown by a series of manipulations.
By inspection, we can see that, if we desire to obtain the enthalpy of the final reaction as shown, then we have to reverse the sign of the second equation, change the sign of the enthalpy and add. Option B
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Calculate the density in g/ml of 2.0 L of gasoline that weighs 1.32 kg
Answer: 0.66 g/mL
Explanation: The formula for density is d= m/v where m=mass and v=volume.
The mass was given in the problem, m= 1.32kg
The volume was also given in the problem, v= 2.0L
d= m/v ---> d= 1.32kg/2.0L ---> d=0.66kg/L
The problem calls for the answer to be written in g/mL, so we must convert the units. 1 kg contains 1000g and 1 L contains 1000 mL.
1000g/1000mL = 1 so the units change but the 0.66 does not. Therefore, your answer is 0.66g/mL (Two significant figures because 2.0 only has 2 significant figures).