the markup over dealer’s cost of a new car ranges from 13% to 20%. if the sticker price is $15,000, over what range will the dealers cost vary? HELPP

A division problem that have an estimated quotient of 12 is: C. 47.6 ÷ 3.9.

In Mathematics, a quotient can be defined as a mathematical expression that is typically used for the representation of the division of a number by another number.

This ultimately implies that, a quotient in terms of numerical data simply refers to a division of a number (numerator) by another number (denominator).

Quotient = 8 ÷ 0.95 = 8.42

Quotient = 18 ÷ 2.2 = 8.18.

Quotient = 47.6 ÷ 3.9 = 12.21 ≈ 12.0.

Quotient = 10.6 ÷ 1.89 = 5.61.

Quotient = 71.9 ÷ 6.5 = 11.06.

Quotient = 123.4 ÷ 9.2 = 13.41.

Quotient = 157.4 ÷ 16.4 = 9.60.

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In order to calculate a 95% confidence interval for the mean chromatic contrast of crab spiders on daisies, you would need to have the sample mean and standard deviation of the chromatic contrast data.

Additionally, you would need to know the sample size. With this information, you could use a t-distribution or a normal distribution to calculate the confidence interval. Once the confidence interval is calculated, it can be interpreted as a range of values that you can be 95% confident contains the true population mean chromatic contrast of crab spiders on daisies. The confidence interval takes into account both the variability of the data and the sample size, and gives a range of values that is likely to contain the population mean with a certain degree of confidence.

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The mean of the data set is 58.3. The standard deviation of the data set is 10.8.

In descriptive statistics, the standard deviation measures how widely the data points vary from the mean. It describes how values are distributed throughout the data sample and measures how widely apart data points are from the mean.

Sum of all values divided by the number of values.

Mean = ( 64 + 46 + 54 + 47 + 70 + 78 ) / 6

Mean = 58.3

The mean of the data set is 58.3.

The square root of the sum of the difference squared between each value and the mean is divided by the number of values subtracted by 1. So

[tex]\sigma =\sqrt{\dfrac{(X-\bar X)^2}{n- 1 }[/tex]

[tex]\sigma = \sqrt{\dfrac{(64 - 58.3)^2+(46 - 58.3)^2+(54 - 58.3)^2+(47-58.3)^2+(70-58.3)^2+(78-58.3)^2}{6-1}\\[/tex]

σ = 10.8

The standard deviation of the data set is 10.8.

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Answer: 1/3=4/12 is true

Step-by-step explanation:

the others are false because 6/12 is smaller than 2/3, 8/12 is greater than 2/3 and 1/3 is equal to 4/12 not less than.

The monthly payment is $1727.82.

The percentage is calculated by dividing the required value by the total value and multiplying by 100.

Example:

Required percentage value = a

total value = b

Percentage = a/b x 100

Example:

50% = 50/100 = 1/2

25% = 25/100 = 1/4

20% = 20/100 = 1/5

10% = 10/100 = 1/10

We have,

Price of the house = $218,500

Down payment = 3.5%

This means,

= 3.5/100 x 218,500

= 7647.5

Now,

Time of loan = 30 years.

This means,

30 years = 30 x 12 = 360 months.

Now,

Rate = 6.5%

This means,

The amount of interest rate for 30 years.

Simple interest.

SI = PRT/100

So,

P = 218,500 - 7647.5 = 210852.5

T = 30

R = 6.5

SI = (210852.5 x 6.5 x 30)/100

SI = 411162.375

Now,

Total amount to pay in 30 years.

= SI + P

= 411162.375 +  210852.5

= 622014.875

Now,

Monthly payment.

= 622014.875 / 360

= $1727.82

Thus,

$1727.82 is the monthly payment.

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An equation for the arithmetic sequence is aₙ=14.6-0.6n.

An arithmetic sequence is a sequence of numbers where the differences between every two consecutive terms is the same. The general form an arithmetic sequence is aₙ=a+(n-1)d.

Given that, Zariah's dash times for her first four races were 14, 13.4, 12.8, and 12.2.

Here, first term (a)=14 and common difference (d)= 13.4-14= -0.6

Now, aₙ=14+(n-1)×(-0.6)

aₙ=14-0.6n+0.6

aₙ=14.6-0.6n

Therefore, an equation for the arithmetic sequence is aₙ=14.6-0.6n.

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Answer:

169m^2

Step-by-step explanation:

8m x 8m =64m^2

(the area of square = side length x side length)

15m x 7m= 105m^2

(the area of parallelogram= length x height)

so the are of the figure is: 64m^2 + 105m^2= 169m^2

The equation to be used by Janet to predict number of hours is 60 (h + 4.5) = 420.

Firstly let us form the expression and then match with the provided options. So, the distance covered on first day and the distance covered on second day will be the sum of overall distance between original and target location. Now, we know, speed, distance and time are related to each other as -

speed = distance / time

So, distance covered on first day = 4.5 × 60

Distance covered on second day = 60 × h

Now, overall equation will form is -

60 × h + 4.5 × 60 = 420

Taking 60 common on Left Hand Side of the equation

60 (h + 4.5) = 420

We see the equation is same as fourth option, and hence, it is the correct answer.

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The number of line segments that are determined by joining the dots on the last two circles is 20.

A line segment is a piece of a line that is connected to two points or has two points on either end. A line segment in geometry is a section of a straight line that is enclosed by two clearly defined end points and contains all of the points on the line that lie inside those endpoints.

The Euclidean distance between two ends of a line segment determines its length. A line segment's length can be calculated using either metric measurements like millimeters or centimeters, or conventional measurements like feet or inches. In this case, the number is 20.

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Answer:

This equation is not complete please

Or it is a simultaneous linear equation

Answer:

[tex]4x + y = 5[/tex]

[tex]4x + y - y = 5 - y[/tex]

[tex]4x = 5 - y[/tex]

[tex] \frac{4x}{4} = \frac{5 - y}{4} [/tex]

[tex]x = \frac{5 - y}{4} [/tex]

This means that both Andre and Noah will save a total of $40 after his five months. 

Andre's formula y = 5x +15

The intersection point is (5, 40)

Noah's equation

y = 7.5x + 2.5

x = number of weeks

y = savings

Andre's equation

y = 5x + 15

Find two points on each line 

x=0

y=2.5

(0, 2.5)

x=0

y=1.5

(0,1.5)

y=0

x=-15/5=-3

(-3, 0)

draw a line through each point

The intersection point is (5, 40)

This means that both Andre and Noah will save a total of $40 after his five months. 

Graph can be interpreted or defined as follows:

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The inequality that describes the problem is,

⇒ x + $49.95 < $120

Where, x represent the cost of the headset.

A relation by which we can compare two or more mathematical expression is called an inequality.

We have to given that;

Allie planned to spend up to $120 on a gaming mouse and headset. She spent $49.95 on a mouse.

Let x represent the cost of the headset.

Hence, We can formulate;

The inequality that describes the problem is,

⇒ x + $49.95 < $120

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The number of users after 8 months is 47612.

An equation is a mathematical statement that is made up of two expressions connected by an equal sign.

Example:

2x + 4 = 7 is an equation.

We have,

Percentage increase per month = 3%

Number of current users = 37,490

The equation for the number of users after x months.

y = 37,490 x [tex]1.03^x[/tex]

Now,

The number of users after 8 months.

= 37,490 x [tex]1.03^x[/tex]

= 37,490 x [tex]1.03^8[/tex]

= 37,490 x 1.27

= 47612.3

= 47612

Thus,

There will be 47612 users after 8 months.

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double average = (double)(num1 + num2 + num3) / 3;

1. Declare and assign a double variable named avg

double avg;

2. Calculate the average of the variables num1, num2, num3 and assign that value to avg

avg = (double)(num1 + num2 + num3) / 3;

double avg;  Declare and assign a double variable named avg

int num1, num2, num3;  Declare three int variables

Assign values to the three int variables

num1 = 10;

num2 = 20;

num3 = 30;

Calculate the average of the three int variables and assign that value to the double variable avg

avg = (double)(num1 + num2 + num3) / 3;  Typecast the result of the addition to a double to get the accurate value

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The exact values of the sine, cosine and tangent of 11 is 0.1908, 0.9816 and 0.1944 respectively.

Trigonometric functions are defined as the real functions which are simply the functions of an angle of a triangle. They are basically the periodic functions which relate an angle in a right angled triangle to the ratios of the length of two sides.

11 degrees can be represented in radians as 0.192

Sine of the angle 11 is,

sin (0.192) = 0.1908

Cosine of the angle 11 is,

cos (0.192) = 0.9816

Tangent of the angle 11 is,

tan (0.192) = 0.1908 / 0.9816 = 0.1944

Hence the trigonometric functions of 11 are sin (0.192) = 0.1908, cos (0.192) = 0.9816 and tan (0.192) = 0.1944.

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to subtract a negative number from a positive is no different than adding 2 positives together.
The way i remember this is by looking at "-(-" and kind of squinting. If you squint hard enough, it kind of looks like a distorted +.
To solve this, just add them as if they were too positives.

The hypotenuse can be found using the Pythagorean formula, which is c=√a²+b².

The longest side of a right-angled triangle, or the side opposite the right angle, is known as the hypotenuse in geometry.

The Pythagorean theorem, which asserts that the square of the length of the hypotenuse equals the sum of the squares of the lengths of the other two sides, can be used to determine the length of the hypotenuse.

In this case, if one of the other sides is 3 (when squared, 9) and the other is 4 (when squared, 16), then the sum of their squares is 25.

The square root of 25, or 5, is the length of the hypotenuse.

With the help of the Pythagorean formula, which is c = √a² + b², we can determine the hypotenuse.

Therefore, the hypotenuse can be found using the Pythagorean formula, which is c=√a²+b².

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I think what you are looking for is:

Random Selection Method

The parameter p is the population proportion, that is the proportion of the population that thinks the tuition is too high.  POPULATION=Students at Glenn's school. (b). The numerical value of that estimates p is [tex]\hat{p}[/tex][tex]=\frac{38}{50} =0.76[/tex].  (c). Yes, the population is more than 10 times as large as the sample size.

(a). He conducts SRS interviews with 50 of his college's 2400 pupils. Of those surveyed, 38 believe that tuition is too costly.

The people under study make up the population.

POPULATION=Students at Glenn's school

The parameter p is the population proportion, that is the proportion of the population that thinks the tuition is too high.

This sample proportion can be used to estimate the true proportion of students in the entire population who think tuition is too high. However, it's important to note that the sample proportion is only an estimate and may not be exactly equal to the true population proportion. The level of precision of this estimate can be quantified using a confidence interval.

(b) The sample proportions is the number of people who think the dorm food is good divided by the sample size:

⇒[tex]\hat{p}=\frac{38}{50} =0.76[/tex]

(c). Yes, the population is larger than the sample size by more than 10 times.

⇒n[tex]\hat{p}[/tex]=38>10

⇒n(1-[tex]\hat{p}[/tex])=12>10 and the sample is a simple random sample.

Therefore, the POPULATION=Students at Glenn's school. The numerical value of that estimates p is [tex]\hat{p}=\frac{38}{50} =0.76[/tex].  Yes, the population is more than 10 times as large as the sample size.

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The trace of any two matricess A, B is tr(AB)=tr(A)+tr(B) and tr(AB)=tr(BA).

a) Let A and B be two matrices with dimensions [tex]$n \times n$[/tex]. Then the trace of a matrix is defined as the sum of its diagonal elements, so the trace of A can be written as [tex]$\text{tr}(A) = \sum\limits_{i=1}^n A[i,i]$[/tex] and the trace of B can be written as [tex]$\text{tr}(B) = \sum\limits_{i=1}^n B[i,i]$[/tex].

The product of matrices A and B is a matrix C with dimensions [tex]$n \times n$[/tex], where [tex]$C[i,j] = \sum\limits_{k=1}^n A[i,k] B[k,j]$[/tex].

The trace of the product of matrices A and B can be written as [tex]$\text{tr}(AB) = \sum\limits_{i=1}^n (AB)[i,i] = \sum\limits_{i=1}^n \sum\limits_{k=1}^n A[i,k] B[k,i] = \sum\limits_{k=1}^n A[k,k] B[k,k]$[/tex].

By the distributive property of multiplication, [tex]$\text{tr}(AB) = \sum\limits_{k=1}^n A[k,k] B[k,k] = (\sum\limits_{k=1}^n A[k,k]) + (\sum\limits_{k=1}^n B[k,k]) = \text{tr}(A) + \text{tr}(B)$[/tex].

So, we have shown that [tex]$\text{tr}(AB) = \text{tr}(A) + \text{tr}(B)$[/tex].

b) Let A and B be two matrices for which the products AB and BA are defined. Then the trace of the product AB can be written as [tex]$\text{tr}(AB) = \sum\limits_{i=1}^n (AB)[i,i]$[/tex]

and the trace of the product BA can be written as

[tex]$\text{tr}(BA) = \sum\limits_{i=1}^n (BA)[i,i]$[/tex].

By definition, the elements of the matrices AB and BA are given by [tex]$(AB)[i,j] = \sum\limits_{k=1}^n A[i,k] B[k,j]$[/tex] and [tex]$(BA)[i,j] = \sum\limits_{k=1}^n B[i,k] A[k,j]$[/tex],

respectively. By switching the order of summation, we have [tex]$\text{tr}(AB) = \sum\limits_{i=1}^n \sum\limits_{k=1}^n A[i,k] B[k,i] = \sum\limits_{k=1}^n \sum\limits_{i=1}^n A[i,k] B[k,i] = \text{tr}(BA)$[/tex].

So, we have shown that [tex]$\text{tr}(AB) = \text{tr}(BA)$[/tex].

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The area of the triangle is 32 [tex]cm^2.[/tex]We can use horizontal slices to find the area of any two-dimensional shape.

We can use horizontal slices to find the area of the isosceles triangle with height 4 cm and width 8 cm. We set a slice at height h and determine the width of the slice, which is 8 cm. We then integrate the area of the slice (width x height) with respect to h, from 0 to 4 cm. This gives us the area of the triangle, which is 32[tex]cm^2[/tex].

We can use horizontal slices to find the area of any two-dimensional shape. We set a slice at a given height h, and determine the width of the slice. We then integrate the area of the slice (width x height) with respect to h, from the lower boundary of the shape to the upper boundary. This gives us the area of the shape. For example, to determine the area of an isosceles triangle with height 4 cm and width 8 cm, we would set a slice at height h and determine the width of the slice, which is 8 cm. We then integrate the area of the slice (width x height) with respect to h, from 0 to 4 cm. This gives us the area of the triangle, which is 32 [tex]cm^2.[/tex]

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A linear relationship represents by the table that is also proportional is x -4 -2 0 y -2 0 2.

A straight-line link between two variables is referred to statistically as a linear relationship (or linear association). Both a graphical representation of a linear relationship, in which the variable and constant are connected by a straight line, and a mathematical representation, in which the dependent variable is determined by multiplying the independent variable by the slope coefficient and a constant.

In given tables

(i) x -3 0 3

   y  0 2 4

These are not in linear relationship nor in proportional because there is no relation between the value of x and y.

(ii) x -4 -2 0

    y -2  0 2

These are in linear relationship and also in proportional because there is a relation between the value of x and y and the relation is y = x + 2.

(iii) x -4 0  4

     y  1  0 -1

These are not in linear relationship nor in proportional because there is no relation between the value of x and y.

(iv) x -1   0  1

     y -5 -3 -1

These are not in linear relationship nor in proportional because there is no relation between the value of x and y.

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To multiply 64 × 8.32 use the logarithm equation 2)㏒64 + ㏒8.32 and y=log[2.00(±0.03)×10−4] and hence option a is correct

To answer the question, we need to know what logarithm of a number is

What is the logarithm of a number?

The logarithm of a number x is the power to base 10 of that number.

So, logarithm of x to base 10 is written as ㏒x.

Since we want to multiply 64 × 83.2, we convert this to logarithmic equation using the addition rule of logarithm.

Addition rule of logarithm

㏒ab = ㏒a + ㏒b

So, 64 × 8.32 to logarithm is ㏒(64 × 8.32) = ㏒64 + ㏒8.32

So, to multiply 64 × 8.32 use the logarithm equation 2)㏒64 + ㏒8.32

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An image of the resulting geometric shape based on a scale factor of 2 using O as the center of enlargement is shown below.

In Geometry, dilation is a type of transformation which typically changes the size of a geometric shape, but not its shape. This ultimately implies that, the size of the geometric shape would be increased (enlarged) or decreased (reduced) based on the scale factor applied.

In Mathematics, the following rules are applied to interpret and understand the dilation of a geometric shape:

In this context, we can logically deduce that the size of this geometric shape would be doubled because the scale factor is greater than 1.

Construction of a circumscribed circle mainly includes three steps.

A circumscribed circle is a circle that passes through all the vertices of a polygon. The center of the circumscribed circle is equidistant from all the vertices of the polygon, making it the largest circle that can be drawn around the polygon.

In order to construct a circumscribed circle for a given polygon, we follow a given set of steps.

Step 1: Create perpendicular bisector of the sides of the triangles.

Step 2: They will intersect at the circumcenter.

Step 3: Draw a circle with the center at the point obtained in step 2 and touching the sides of the triangle.

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Answer:

please take a picture of the triangle so I can help you.

The best solution is to use the elimination method. The best approach to utilize is the elimination technique while trying to solve a problem 4x+y=1 2x+y=8.

First-order kinetics of elimination Elimination of a fixed portion of the drug amount existing in the body per unit of time. The fraction of elimination to drug concentration.

4x + y = 1 --------(1)

2x + y = 8---------(2)

subtract (2) from (1)

2x = -7

divide bothside by 2

2x/2 = -7/2

x= -7/2

we can substitute x = -7/2 in any of the equations.

Lets take equation (1)

4x + y = 1

4(-7/2) + y =1

2(-7) + y = 1

-14 + y = 1

y = 1+14

y =15

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We can use the normal approximation to the binomial distribution to find the interval that contains approximately 95.44 percent of all the possible sample proportions when p=.5 and n=250.

The mean of the distribution of sample proportions is equal to the population proportion (p), which is 0.5 in this case. The standard deviation of the distribution is given by:

σ = sqrt(p(1-p) / n) = sqrt (0.5 * 0.5 / 250) = sqrt (0.0002) = 0.014

Using a z-score of 1.96 to correspond to a confidence level of 95.44 percent (since the standard normal distribution has a proportion of approximately 0.9544 within 1.96 standard deviations of the mean), we find the lower and upper bounds of the interval:

lower bound = p - zσ = 0.5 - 1.96 * 0.014 = 0.471

upper bound = p + zσ = 0.5 + 1.96 * 0.014 = 0.529

Therefore, the interval that contains approximately 95.44 percent of all the possible sample proportions is (0.471, 0.529).

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The future value F of the given principal under compound interest for the

time period and interest rate specified is $17,149.99.

It is the interest we earned on the interest.

The formula for the amount earned with compound interest after n years is given as:

A = P [tex](1 + r/n)^{nt}[/tex]

P = principal

R = rate

t = time in years

n = the number of times compounded in a year.

We have,

t = 13 years

r = 2.75%

Compounded monthly

This means,

n = 12

P = $12,000

Now,

A = P [tex](1 + r/n)^{nt}[/tex]

A = 12000 [tex](1 + 0.00229)^{156}[/tex]

A = $17,149.99

Thus,

The future value is $17,149.99.

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On solving the provided question we can say that - s and t be function subsets of a. show that x ∈  f(S) V f(T) ∈  f(y) as f(y) = x => x∈f(S)∨x∈f(T)

What is function?

One kind of rule is a function, which gives an output in exchange for an input. Alex Federspiel is the photo's source. In this instance, y=x2. I receive the output from something I placed in x in y. We may say that y is a function of x since x serves as the input value. A relation between a collection of inputs, each with an output, is referred to as a function. A function is a connection between inputs that each have precisely one output, to put it simply.

let S contains all elements that are the image of an element in f(s)

and let T  contains all elements that are the image of an element inf(T)

f(y) ∈ f(s) V f(y)

x ∈  f(S) V f(T) ∈  f(y)

as f(y) = x

x ∈ f(S)   ∨    x  ∈  f(T)

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