Suppose you throw a 0.0520 kg ball with a speed of 10.0 m/s and
at an angle of 30.0° above the horizontal from a building 12.0 m high.
a) What will be its kinetic energy when it hits the ground?
b) What will be its speed when it hits the ground?

The ability of a metal to be stretched in any direction by hammering, rolling, etc. without rupturing is known as malleability. One example of a malleable metal is lead.

Ductility is the ability of metals to be pulled into thin wires. The only non-ductile metals are zinc and mercury, whereas gold has a high degree of ductility.

The capacity of a metal to be permanently pulled or stretched without rupture or fracture is known as ductility (Figure 2-5). Metals with a low degree of ductility will break or crack before they bend. The capacity of a metal to be hammered, rolled, or pressed into different shapes without rupturing or breaking is known as malleability.

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We can express the answer using two significant figures, which would be [tex]"750 kg/m^3".[/tex]

To find the mass of the cube, we need to know the density of the material it is made of. The density of an object is its mass per unit volume. If the cube floats so that it is 75% in the water and 25% in the oil, then its average density is equal to the weighted average of the densities of water and oil.

Let's assume that the density of water is 1000 kg/m^3 and the density of oil is 800 kg/m^3. The average density of the cube would be:

[tex](0.75 * 1000 kg/m^3) + (0.25 * 800 kg/m^3) = 750 kg/m^3.[/tex]

Since the cube is floating, its density must be equal to or less than the density of the liquid it is in, which in this case is [tex]750 kg/m^3.[/tex] So, we can calculate the mass of the cube using its volume and average density:

[tex]mass = volume * density = V * 750 kg/m^3[/tex]

Without knowing the volume of the cube, we cannot determine its exact mass. However, we can express the answer using two significant figures, which would be [tex]"750 kg/m^3".[/tex]

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Mary should speed up at a rate of 70 ms - 2 if she and Sally must crossing an end of the race side by side.

Acceleration refers to the speed at which velocity changes. It's not always the case, but acceleration frequently denotes a shift in pace. The direction of an object's motion is changing, even though it moves in a circular pattern and keeps the same speed.

In physics, acceleration is the rate at which the velocity of the an object changes in relation to time. According to Newton's Second Law, the sum of all loads exerted on an item results in its acceleration. Meter per seconds squared (m s2) is the unit of acceleration used in the SI system.

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Electrons are moved into or out from the leaves by an electroscope in response to the existence of a charge. The charged object's positive or negative charge cannot be determined by the electroscope.

Electrons went back through copper to your palm when you contacted the electroscope, then through you body to the earth. The metals inside the electroscope lost its charge as a result of the ground dispersing the energy away from you. They hang lifeless in the jar without any charge and no longer repel.

Create some electrical currents by rubbing the Polystyrene on a piece of wool to test your electroscope. With the wool, repeatedly rub the Styrofoam. Hold your electrically charged Styrofoam quickly in close proximity to the metal wire's coiled portion on your electroscope. Don't touch the wire, please!

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The ball to hit the floor time at  t = 0.342 seconds.

The speed of the ball has no bearing on how long it takes to strike the ground. The fact that the ball is traveling along the horizontal axis means that it will only reach the end of the table faster.

y = v*t + 0.5*a*t^2

where:

  y = vertical distance is = -1 m

  v = initial velocity is = 1.25m/s

  a = acceleration is= 9.81 m/s^2

  t = time

Required: t

so,

y = v*t + 0.5*a*(t^2)

1 = (1.25)*t + 0.5*9.81*(t^2)

0 = -1 + 1.25t + 4.905(t^2)

Applying completing  square, we get

t = 0.342 s or - 0.597s

so, we don't have time with negative value Thus,  ball to hit the floor is t = 0.342 seconds.

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The flow speed in a 2.6-cm diameter pipe on the second floor 5.0 m above a 4.0-cm diameter pipe will be 0.43 m/s with a pressure of 3.35 atm.

The flow speed of the water will decrease and the pressure will increase as the diameter of the pipe decreases and the height increases. The flow speed can be calculated using the equation of continuity (A1v1 = A2v2), where A is the cross-sectional area of the pipe and v is the flow speed. The pressure can be calculated using the equation of Bernoulli's theorem ,stated as follows :

[tex]P + 1/2ρv^2 + ρgh = constant[/tex]

The increase in height results in an increase in pressure.

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The statement " mechanical waves move through a medium, particles of the medium undergo a periodic and repeated vibration about a fixed position." is TRUE.

Mechanical waves are waves that require a medium for their propagation, such as sound waves in air, seismic waves in the Earth's crust, or ocean waves on the surface of water. These waves are generated by a source that causes a disturbance in the medium, and the energy of the wave travels through the medium by causing the particles to vibrate periodically and repetitively.

For example, when a sound wave passes through air, the particles of air undergo a periodic and repeated vibration about a fixed position, compressing and expanding as the wave passes through. These vibrations cause the energy of the sound wave to be transferred from one particle to the next, allowing the wave to propagate through the medium. The same process occurs in other mechanical waves, with the particles of the medium vibrating about a fixed position as the wave travels through.

It's important to note that the particles of the medium do not move along with the wave, but rather undergo a periodic vibration about their fixed position. The wave itself is a disturbance that travels through the medium, transferring energy from one point to another, but the medium particles do not move with the wave.

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58,741.1 joules.the energy (in j) stored in a fully charged battery if the phone requires charging after 8.03 hours of use.

The energy stored in the battery is equal to 8.03 hour x battery voltage x battery capacity.

The total energy (in joules) is equal to 8.03 x battery voltage x battery capacity.

if the battery voltage is 3.7V

the battery capacity is 2100mAh,

the energy stored in the battery is

8.03 x 3.7V x 2100mAh

= 58,741.1 joules.

the energy (in j) stored in a fully charged battery if the phone requires charging after 8.03 hours of use  is  58,741.1

To calculate the energy (in joules) stored in a fully charged battery, you need to know the battery's capacity and voltage. The capacity of the battery is the amount of energy (in joules) it can store. The voltage is the amount of energy (in volts) that the battery is able to produce.

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The different circuit elements in parallel have the same voltage drop across them.

The key hallmark of parallel circuits is that the elements connected in parallel have the same voltage drop across them. It doesn’t matter if the circuit element is a resistor, capacitor, or an inductor, battery or diodes; the voltage drop across all elements is the same.

This means that the voltage across different circuit elements (batteries, resistors, capacitors, etc.) is the same. On the other hand, circuit elements connected in series have the same current flowing through them; however, they have different voltage drops.

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The magnitude of the acceleration of a baseball thrown vertically into the air at its highest point is 9.8 m/s^2.

This is due to the fact that gravity is the only force acting on the baseball at its highest position. The amount of this force, which has a downward direction, is equal to the baseball's mass times the gravitational acceleration (g = 9.8 m/s2). The magnitude of the net force exerted on the baseball is equal to its weight, which is determined by multiplying its mass by the gravitational acceleration. As a result, the acceleration at the highest point is 9.8 m/s2, which is the same as the acceleration caused by gravity.

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It is true that the measure of compactness is the extent to which the district is spread out from its center.

The measure of compactness is defined as the the spread of the area of the space, the term compactness here do not have its regular meaning of the less area. It signifies that how much an area is spread in the space so do not get confused with the terms.

There are various compactness measure and one of them is the spread of the area from the center of the body. It means if we are measuring a square than we should measure its compactness by taking the center of the square as the point of origin.

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The average speed on the trip of her journey is 30 mi/h.

The average speed of an object over a certain distance is equal to the total distance traveled divided by the total time it took to travel that distance.

Let's say the total distance the driver travels is d miles.

For the first half of the distance (d/2 miles), the driver travels at 20 mi/h, so the time it takes her to cover that distance is:

t1 = d/2 / 20 mi/h = d / 40 h

For the second half of the distance (d/2 miles), the driver travels at 60 mi/h, so the time it takes her to cover that distance is:

t2 = d/2 / 60 mi/h = d / 120 h

The total time it takes the driver to complete the journey is:

t = t1 + t2 = d/40 + d/120 = (3d + d) / 120  = 4d / 120 h = d / 30 h

So, the average speed of the driver over the entire journey is:

average speed = d / t = d / (d / 30) = 30 mi/h

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The potential energy is converted to the kinetic energy and transfered to the kids.

Potential energy is energy that is stored in an object or substance, this is based on the position, arrangement or state of the object or substance.

Kinetic energy is the energy an object has because of its motion. If we want to accelerate an object, then we must apply a force. After work has been done, energy has been transferred to the object, and the object will be moving with a new constant speed.

Energy is being converted from potential to kinetic energy, and the energy is being transferred to the kids when the water moves past them.

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The speed of the small stone lodged in the tire is approximately 6.077 m/s and the magnitude of its acceleration is approximately 957.39 m/s^2.

First, we need to convert the rotational speed of the wheel from revolutions per minute (rev/min) to radians per second (rad/s).

w = (2 * pi * n) / 60

Where w is the angular velocity in rad/s, pi is the mathematical constant (3.14159), and n is the rotational speed in rev/min.

So,

w = (2 * pi * 120) / 60

= 2 * pi * 2

= 4 * pi rad/s

= 12.566 rad/s

The speed of a point at a distance r from the center of rotation is given by:

v = r * w

Where v is the speed and r is the distance from the center of rotation (0.48 m).

So,

v = 0.48 m * 12.566 rad/s

= 6.077 m/s

Finally, to calculate the magnitude of the acceleration of the small stone, we use the equation:

a = r * w^2

Where a is the magnitude of the acceleration.

So,

a = 0.48 m * (12.566 rad/s)^2

= 957.39 m/s^2

Rotational speed, also known as angular velocity, is a measure of the rate of change of the angular position of an object. It is expressed in units of radians per second (rad/s) or degrees per second (deg/s). In simpler terms, the rotational speed is how fast an object is rotating around its axis. The axis of rotation can be any line that passes through an object, and the direction of rotation is usually determined by the right-hand rule.

The rotational speed is a crucial concept in physics and engineering, as it affects the behavior of objects and systems. For example, the rotational speed of a car's wheels affects its speed and stability, while the rotational speed of a spinning top affects its stability and precession. In machinery, the rotational speed is an important factor in determining the efficiency and performance of equipment, such as turbines, generators, and motors.

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Explanation:

If no force is exerted on a moving object, it will continue to move at a constant velocity. This is described by Newton's first law of motion, which states that an object will remain at rest or continue to move at a constant velocity in a straight line unless acted upon by an external force. In other words, if no net force acts on an object, the object will maintain its velocity, neither speeding up nor slowing down.

The car's new speed will be 11.56 m/s.

Speed is the amount of distance covered in a unit of time. It refers to how quickly an object is moving. The scalar quantity speed symbolizes the size of the velocity vector. It's lost its feeling of purpose. An object is moving quicker when it is moving at a higher speed. It is moving more slowly if the speed is lower. If something isn't moving at all, it has no speed.

The momentum is conserved here, so Initial momentum = Final momentum.

Initial mass, m = 13000 kg

Initial velocity = 16 m/s

Final mass after load = 13000 + 5000 = 18,000 kg

Based on the above point,

13000 × 16 = 18000 × v

v = [tex]\frac{208000}{18000}[/tex]

v = 11.56 m/s

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The car would need to sustain an acceleration of 9 m/s² due east.

This shows that if a constant acceleration is applied, the car will be able to reach the desired velocity within the given time limit.

The car needs to sustain an acceleration of 9 m/s² due east in order to reach a velocity of 27 m/s due east in 3.0 seconds, starting from rest.

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The relationship between the object distance (d_o), the image distance (d_i), and the focal length (f) of a thin lens is given by the lens equation:

1/d_o + 1/d_i = 1/f

We know that the focal length of the lens is 42 cm, so the lens equation becomes:

1/d_o + 1/d_i = 1/42

Let's call the height of the object "h_o".

We also know that the image is 5.2 times as high as the object,

so the height of the image (h_i) is given by:

h_i = 5.2 * h_o

Since the image is real,

we also know that the image distance is positive, so d_i is positive.

We can now use the magnification equation to find the ratio of the image height to the object height:

magnification (m) = h_i/h_o

= 5.2

Since the magnification is equal to the ratio of the image height to the object height,

we can write:

h_i/h_o = d_i/d_o

Now we can substitute the expression for h_i/h_o into the lens equation:

1/d_o + 1/d_i = 1/42

d_i/d_o = 5.2

1/d_o + 1/5.2d_o = 1/42

Solving for d_o, we find:

d_o = 21.6 cm

And since d_i/d_o = 5.2, we can find d_i:

d_i = 5.2 * d_o = 5.2 * 21.6

= 112.32 cm

So the object is 21.6 cm away from the lens, and

the image is 112.32 cm away from the lens.

The distance between the object and the image is

112.32 cm - 21.6 cm

= 90.72 cm.

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The northern celestial pole as well as the stars that surround it will look higher up in the sky as you travel further north, whereas all the stars in the south will appear lower as you travel farther south.

The daily movement of stars as well as other celestial objects across the sky is known as diurnal motion. Celestial bodies appear to move from east because of the Earth's west to east rotation, which creates this motion.

The rotation of the Earth is what causes this motion. Stars can be seen rising in the eastern, flying overhead, and set in the west as the Earth spins us eastward at a speed of about a thousand miles per hour.

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The microphone impedance of the yaesu-ft-70 dr is 2kΩ and the antenna impedance is 50Ω.

Impedance is the opposition to the alternating current, arising from the combined effect of the ohmic resistance and reactance in the circuit. The unit of Impedance is the ohm. The Ft-70Dr is a compact system with a fusion transceiver providing both a conventional analog FM operation system and the advance C4FM digital mode.

It is built for commercial grade standard for Dust and water protection, making this radio suitable for hardest environment. The frequency of Ft-70Dr is 108MHz-580Mhz, and the output power is 5 watt, with microphone impedence of 2kΩ.

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The average velocity for each time period is as follows: t = 1 sec: 4.9 ft/s, t = 2 sec: 5.3 ft/s, t = 3 sec: 7.7 ft/s, t = 4 sec: 12.5 ft/s, t = 5 sec: 21.9 ft/s, t = 6 sec: 39.7 ft/s

To find the average velocity for each time period, we need to calculate the change in position (displacement) and divide it by the change in time. The formula for average velocity is:

v = Δs / Δt

Where Δs is the change in position (displacement) and Δt is the change in time.

Here's the calculation for each time period:

t = 1 sec: Δs = 4.9 ft, Δt = 1 sec, v = Δs / Δt = 4.9 ft/s

t = 2 sec: Δs = 10.6 ft, Δt = 1 sec, v = Δs / Δt = 5.3 ft/s

t = 3 sec: Δs = 23.1 ft, Δt = 1 sec, v = Δs / Δt = 7.7 ft/s

t = 4 sec: Δs = 50.2 ft, Δt = 1 sec, v = Δs / Δt = 12.5 ft/s

t = 5 sec: Δs = 109.4 ft, Δt = 1 sec, v = Δs / Δt = 21.9 ft/s

t = 6 sec: Δs = 238.3 ft, Δt = 1 sec, v = Δs / Δt = 39.7 ft/s

So the average velocity for each time period is as follows:

t = 1 sec: 4.9 ft/s

t = 2 sec: 5.3 ft/s

t = 3 sec: 7.7 ft/s

t = 4 sec: 12.5 ft/s

t = 5 sec: 21.9 ft/s

t = 6 sec: 39.7 ft/s

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It takes her 1.43 s to reach a speed of 2.00 m/s. Therefore, the magnitude of the deceleration of the car is -2.5 m/s^2

Let's call the magnitude of the deceleration a. Then, the final velocity v_f of the car after decelerating for t = 0.800s can be calculated using the equation:

v_f = v_i + a * t

where v_i = 2.00 m/s is the initial velocity of the car. Since the car comes to a stop, v_f = 0.

So, we can solve for a:

0 = 2.00 m/s + a * 0.800s

a = -2.00 m/s / 0.800s = -2.5 m/s^2

Deceleration refers to the slowing down of an object in motion. This can occur due to various reasons such as friction, air resistance, or the application of a force that opposes the direction of motion. Deceleration is expressed as a negative acceleration, as it is opposite in direction to acceleration, which is the rate of change of velocity. The formula for deceleration is expressed as a=-(v-u)/t, where v is the final velocity, u is the initial velocity, and t is the time taken for the deceleration to occur.

In physics, deceleration is a crucial concept that is used to study various aspects of motion. For instance, in automobile engineering, deceleration is used to calculate the braking distance of a vehicle, which is the distance required to bring a vehicle to a stop. This information is crucial in designing safe and efficient vehicles. Deceleration is also important in sports and biomechanics where it is used to study the motion of athletes and the effects of impact on the body.

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The echo from the other mountain is heard 1.0 s after the first echo. So, the two mountains are approximately 600.25 meters apart.

The time for the sound to travel to the first mountain and back is 1.5 seconds, so we can use that time to calculate the distance traveled.

The distance traveled is equal to the speed of sound multiplied by the time it takes for the sound to travel that distance.

d = v * t

d = 343 m/s * 1.5 s = 514.5 m

This distance is the total distance traveled by the sound to reach the first mountain and back to the listener. Since this is a round trip, the distance to the first mountain is half of this value:

d1 = 514.5 m / 2 = 257.25 m

Next, we can use the time it took for the second echo to arrive (1.0 s) to find the distance to the second mountain:

d2 = 343 m/s * 1.0 s = 343 m

Finally, to find the distance between the two mountains, we simply add the distances to the two mountains:

d = d1 + d2 = 257.25 m + 343 m = 600.25 m

Echo is a technology that allows sound to be reflected and repeated back to its source. It is commonly used in a variety of applications including sonar, radar, and audio systems. In sonar and radar, echo is used to determine the distance, speed, and direction of objects. In audio systems, echo is used to create a sense of space and depth in sound recordings. Echo can also be used to reinforce sound in concert halls and other large spaces.

Echo is created by reflecting sound waves off of a surface, such as a wall or a solid object. The time it takes for the echo to return to its source is called the echo delay time, and it can be used to determine the distance of the reflecting surface. In audio systems, echo can be added artificially by using echo chambers, digital signal processors, or other electronic devices.

Echo can also cause problems in audio systems, particularly in communication systems, where echoes can interfere with the clarity of speech. To reduce unwanted echoes, many audio systems use echo cancellers, which are algorithms that identify and subtract echoes from the audio signal.

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The ratio of rotational and kinetic energy of center-of-mass is, 1/2.

If a solid cylinder is placed at top of inclined plane due to mgsinθ linear velocity increases and friction apply torque so angular velocity increases.

If cylinder is performing rolling without friction then displacement of point of contact is zero so work done by friction is zero so mechanical energy is conserved here.

So it's kinetic energy = (1/2) m v²

And rotational energy is, (1/2) I ω²

The moment of inertia is, I = (1/2) m r², and the angular velocity, ω = v/r.

Using these values, rotational energy is,

[tex]\dfrac{1}{2} \times \dfrac{1}{2} \times m r^2 ({\dfrac{v}{r}})^2\\= \dfrac{1}{4} \times m v^2[/tex]

Now, the ratio of rotational and kinetic energy is, 1/2.

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To determine whether the rocket is moving forward at a constant speed in deep space, without looking outside the rocket or making any contact with the outside world, you could perform a number of experiments inside the rocket.

These are a few examples of the types of experiments you could perform inside the rocket to determine whether it is moving at a constant speed in deep space.

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Hollow bones in birds, gills in fish and warm-blooded mammals are internal adaptations.

There are three similar definitions of adaptation in biology. First, the dynamic evolutionary process of natural selection improves the evolutionary fitness of organisms by adapting them to their environments. Second, it's a state that the populace reaches during that process.

Various strategies can be used by organisms to adapt to their surroundings. They are capable of biological adaptation, which entails changing how the body works. The bodies of people who reside in high altitudes are an illustration of biological adaptability which is essential for survival.

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The velocity of the ball which is projected straight upward after 3 sec is found to be 49.4m/s.

When an object falls through with a vacuum, it is solely subject to one external force: gravitational force, which corresponds to the object's weight. Free falling is the term for an item that is only moving due to the pull of gravity, and Newton's second rule of motion describes this motion.

U => 20m/s

t=3s

V= u+gt ; According to law of motion

V= 20 + 9.8x3   (+ve g since the projected straight upward)

  => 49.4m/s

When the body is propelled upward, it rises vertically until both the ball's velocity and the force acting on it are zero. The ball then experiences zero velocity as it accelerates due to gravity it until touches the earth.

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True, An electric field contacts the face of a circuit at a straight angle when electrostatic forces are present.

Only when there are both positive and negative charges present may electric field lines cross. When a conductor is electrostatically positioned in an electric field, the electric field was excluded from the conductor's interior.

We now have a force acting on the electrons along the surface because the electric field pulls on the charges. Due to the unbalanced nature of this force, surface currents, or the movement of charges, will result. Therefore, the electric field must emerge perpendicular to surfaces to prevent this.

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Answer:

Height of the cliff: approximately [tex]51.7\; {\rm m}[/tex].

Speed right before landing: approximately [tex]27.4\; {\rm m\cdot s^{-1}}[/tex].

Maximum height reached: approximately [tex]67.4\; {\rm m}[/tex] above the ground (relative to the base of cliff.)

(Assumption: air resistance is negligible, and that [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex].)

Explanation:

Let [tex]u[/tex] denote the velocity of the projectile at launch.

Under the assumptions, velocity in the vertical direction changes at a constant [tex]a_{y} = (-9.81)\; {\rm m\cdot s^{-2}}[/tex]. Velocity in the horizontal direction would be constant.

Apply the SUVAT equation [tex]x = (1/2)\, a\, t^{2} + u\, t[/tex] to find the vertical displacement after the [tex]t = 5.50\; {\rm s}[/tex] flight:

[tex]\begin{aligned}x_{y} &= \frac{1}{2}\, a_{y}\, t^{2} + u_{y}\, t \\ &= \frac{1}{2}\, (-9.81)\, (5.50)^{2} + (21.0\, \sqrt{3})\, (5.50) \\ &\approx 51.7\; {\rm m}\end{aligned}[/tex].

Thus, the cliff is approximately [tex]51.7\; {\rm m}[/tex] above the ground.

It is given that the flight took [tex]t = 5.50\; {\rm s}[/tex]. At a rate of [tex]a_{y} = (-9.81)\; {\rm m\cdot s^{-2}}[/tex], vertical velocity would have changed by [tex]a_{y}\, t[/tex] during the flight. Hence, the vertical velocity right before landing would be:

[tex]\begin{aligned}v_{y} &= u_{y} + a_{y}\, t \\ &= 21.0 \sqrt{3} + (-9.81)\, (5.50) \\ &\approx 17.582\; {\rm m\cdot s^{-1}} \end{aligned}[/tex].

Under the assumptions, horizontal velocity would stay constant: [tex]v_{x} = u_{x} = 21.0\; {\rm m\cdot s^{-1}}[/tex].

Apply the Pythagorean Theorem to find the overall velocity right before landing:

[tex]\begin{aligned}v &= \sqrt{{v_{x}}^{2} + {v_{y}}^{2}} \\ &\approx \sqrt{21.0^{2} + (17.582)^{2}} \\ &\approx 27.4\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].

When height is maximized, vertical velocity would be [tex]0[/tex]. Apply the SUVAT equation [tex]x = (v^{2} - u^{2}) / (2\, a)[/tex] to find the vertical displacement when vertical velocity is exactly [tex]0\; {\rm m\cdot s^{-1}}[/tex]:

[tex]\begin{aligned}x_{y} &= \frac{{v_{y}}^{2} - {u_{y}}^{2}}{2\, a_{y}} \\ &= \frac{0^{2} - (21.0 \sqrt{3})^{2}}{2\, (-9.81)} \\ &\approx 67.4\; {\rm m} \end{aligned}[/tex].

The motor oil, where the metal sphere takes least time to fall, has  the least viscosity.

We refer to this resistance to motion that most fluids provide as "viscosity." When there is relative motion between the fluid's layers, viscosity develops.

More specifically, it measures flow resistance brought on by internal friction between fluid layers that occur when they pass one another during fluid flow.

Strong intermolecular forces provide a lot of internal friction in a fluid with a high viscosity, which makes it difficult for layers to move past one another.

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