The given expression can be written as in the simplified form, 5/3
What are expressions?An expression is a sentence with at least two numbers or variables having mathematical operation. Math operations can be addition, subtraction, multiplication, division.
For example, 2x+3
Given that,
The expression,
[tex]1 + \frac{1}{1+ \frac{1}{1+1} }[/tex]
It can be solved by various steps,
First step,
1/(1+1) can be written as 1/2
[tex]1 + \frac{1}{1+ \frac{1}{2} }[/tex]
Second step,
1 + 1/2 can be written as 3/2
[tex]1 + \frac{1}{\frac{3}{2} }[/tex]
Now, 1/(3/2) can be written as 2/3
[tex]1 + \frac{2}{3}[/tex]
Further, it can be written as,
5/3
Hence, the simplified form is 5/3
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Write the expanded form of the expression of 4(3 + 4x - 2)
Answer:
12+16x-8
Step-by-step explanation:
What is the measure of b enter a number.
Answer:
21
Step-by-step explanation:
We can use Pythagorean theorem a^2 + b^2 = c^2
a = 20
b = x
c = 29
20^2+b^2=29^2
resulting our b value being 21
100 Points rewarded for this Algebraic expression.
The equation of the linear function in slope intercept form is;
y = -0.5x + (-5)
How to write the equation of a line in slope intercept form?The equation of a line in slope intercept form is expressed as;
y = mx + c
where;
m is slope
c is y-intercept
From the given table, we can see that the slope is;
m = (y2 - y1)/(x2 - x1)
m = (-4.5 - (-4))/(-1 - (-2))
m = -0.5/1
m = -0.5
At x = 0, y = -5 and so the y-intercept is -5. Thus the equation is;
y = -0.5x + (-5)
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how many 1/3 cubes would it take to fill a rectangular prism that is 2 1/5 m long, 5 m tall, and 3/4 m wide
We need to calculate the total of the rectangular prism and divide it with the volume of single 1/3 cubes to get the number of cubes. It takes almost 25 cubes to fill the rectangular prism of given dimension.
The rectangular prism has 2.5 m length, 5 m tall and 0.75 m wide.
The total volume of the rectangular prism will be 2.5 m × 5 m × 0.75 m = 8.25 m³.
The volume of single cube will be (1/3) m³ = 0.33 m³
Now to find the number of cubes to fill the rectangular prism, we can divide the volume of the prism with the volume of single cube.
8.25 m³ / 0.33 m³ = 25 cubes.
It takes almost 25 cubes to fill the rectangular prism of dimension 2.5 m length, 5 m tall and 0.75 m wide.
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a 3 pound bag of apples cost $6. if ther is approximately 8 apples in a pound how much would one apple cost?
Therefore , the solution of the given problem of unitary method comes out to be $1.5 one apple cost.
Define unitary method.To finish a work using the unitary strategy, multiply the quantity by two after computing the size of a small slice. The unit variable technique, which is just an expression, helps to distinguish a coded item from a specific group or collection of groups. For example, 40 pens would cost Rs. 400 (or $1.01 or 400 pounds). There is a chance that one nation will have complete control over the technique used to do this. Almost all living things have a unique trait.
Here,
Given :
=> 3 pound bag of apples cost $16
=> 8 apples in a pound
So,
In 3 pounds there are 3*8 = 24 apples
=> 24/16
=> 12/8
=> 3/2
=> 1.5
Therefore , the solution of the given problem of unitary method comes out to be $1.5 one apple cost.
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pls help.
At a hockey game, a vender sold a combined total of 232 sodas and hot dogs. The number of sodas sold was three times the number of hot dogs sold. Find the number of sodas and the number of hot dogs sold.
Number of sodas sold:
Number of hot dogs sold:
The Number of sodas sold: 174,
The number of hot dogs sold: 58.
What is a linear equation?Each term in a linear equation has an exponent of 1, and when this algebraic equation is graphed, it always produces a straight line. It is called a "linear equation" for this reason.
Both linear equations with one variable and those with two variables exist.
Given a vendor sold a combined total of 232 sodas and hot dogs.
let S for the number of sodas sold and H for the number of hot dogs sold,
S + H = 232
The number of sodas sold was three times the number of hot dogs sold
S = 3H
substitute the values,
S + H = 232
3H + H = 232
4H = 232
H = 232/4
H = 58
and the number of sodas sold
S = 3H
S = 3*58
S = 174
Hence the number of sodas sold = 174,
and the number of hot dogs sold = 58.
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The heights of the 20 players on a school soccer
team are recorded in the box-and-whisker plot
shown below.
According to the graph, it can be inferred that the average height of the students is 63 inches.
How to find the height of seventh grade soccer players?To find the height of the seventh grade soccer players we must analyze the graph. In this case we have a height range from 60 inches to 65 inches. However, we do not know what the individual heights of each of the players are.
In the graph, an intermediate line is also shown in the height segment that signifies the average height of soccer players. In this case it would be 63 inches. Based on the above, the average height would be 63 inches.
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F(3) given f(x)=2x+3 evaluate the function
The value of the function is f ( 3 ) = 9
What is an Equation?Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.
It demonstrates the equality of the relationship between the expressions printed on the left and right sides.
Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.
Given data ,
Let the function be represented as f ( x )
Now , the equation will be
Substituting the values in the equation , we get
f ( x ) = 2x + 3 be equation (1)
On simplifying the equation , we get
y = 2x + 3
And , when x = 3
Substitute the value of x =3 in the equation , we get
f ( 3 ) = 2 ( 3 ) + 3
On further simplification , we get
f ( 3 ) = 6 + 3
f ( 3 ) = 9
Therefore , the value of f ( 3 ) is 9
Hence , the equation is f ( 3 ) = 9
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A hockey player ran a simulation twice to estimate the proportion of wins to expect using a new game strategy. Each time, the simulation ran a trial of 1,000 games. The first simulation returned 590 wins, and the second simulation returned 640 wins. Construct and interpret 95% confidence intervals for the outcomes of each simulation.
---------------
A: The confidence interval from the first simulation is (0.560, 0.620), and the confidence interval from the second simulation is (0.610, 0.670). For the first trial, we are 90% confident the true proportion of wins with the new game strategy is between 0.560 and 0.620. For the second trial, we are 90% confident the true proportion of wins with the new game strategy is between 0.610 and 0.670.
B: The confidence interval from the first simulation is (0.564, 0.616), and the confidence interval from the second simulation is (0.615, 0.665). For the first trial, we are 90% confident the true proportion of wins with the new game strategy is between 0.564 and 0.616. For the second trial, we are 90% confident the true proportion of wins with the new game strategy is between 0.615 and 0.665.
C:The confidence interval from the first simulation is (0.564, 0.616), and the confidence interval from the second simulation is (0.615, 0.665). For the first trial, we are 95% confident the true proportion of wins with the new game strategy is between 0.564 and 0.616. For the second trial, we are 95% confident the true proportion of wins with the new game strategy is between 0.615 and 0.665.
D:The confidence interval from the first simulation is (0.560, 0.620), and the confidence interval from the second simulation is (0.610, 0.670). For the first trial, we are 95% confident the true proportion of wins with the new game strategy is between 0.560 and 0.620. For the second trial, we are 95% confident the true proportion of wins with the new game strategy is between 0.610 and 0.670.
To construct and interpret 95% confidence intervals for the outcomes of each simulation, then option C. The confidence interval from the first simulation is (0.564, 0.616), and the confidence interval from the second simulation is (0.615, 0.665). For the first trial, we are 95% confident the true proportion of wins with the new game strategy is between 0.564 and 0.616. For the second trial, we are 95% confident the true proportion of wins with the new game strategy is between 0.615 and 0.665 is correct.
How did we determine the confidence interval?To calculate the confidence interval, we can use the formula for a normal approximation to the binomial distribution.
The standard error of the proportion is given by the formula SE = sqrt(p(1-p)/n), where p is the proportion of wins, and n is the number of games played. The 95% confidence interval is given by p +/- 1.96 * SE.
Plugging in the values from the first simulation, we have p = 590/1000 = 0.59, and n = 1000. So, SE = sqrt(0.59(1-0.59)/1000) = 0.0242. The 95% confidence interval is 0.59 +/- 1.96 * 0.0242 = (0.564, 0.616).
Similarly, for the second simulation, p = 640/1000 = 0.64, and n = 1000. So, SE = sqrt(0.64(1-0.64)/1000) = 0.0244. The 95% confidence interval is 0.64 +/- 1.96 * 0.0244 = (0.615, 0.665).
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Determine how (if possible) the triangles can be proved similar.
To prove that two triangles are similar, we must show that they have the same shape, but not necessarily the same size. This can be done by showing that the corresponding angles of the two triangles are equal and that the corresponding sides are in proportion.
To do this, we can use the Side-Side-Side (SSS) Similarity Theorem. This theorem states that if all three pairs of corresponding sides of two triangles are in proportion, then the two triangles are similar. To prove this, we must show that the ratio of each pair of corresponding sides is equal.
For example, let's say we have two triangles ABC and DEF. To prove that these two triangles are similar, we must show that the ratio of AB to DE is equal to the ratio of BC to EF. We can do this by solving the following equation:
AB/DE = BC/EF
If the equation is true, then the two triangles are similar.
We can also use the Angle-Angle-Angle (AAA) Similarity Theorem to prove that two triangles are similar. This theorem states that if all three pairs of corresponding angles of two triangles are equal, then the two triangles are similar. To prove this, we must show that the measure of each pair of corresponding angles is equal.
For example, let's say we have two triangles ABC and DEF. To prove that these two triangles are similar, we must show that the measure of angle A is equal to the measure of angle D, the measure of angle B is equal to the measure of angle E, and the measure of angle C is equal to the measure of angle F.
If the measures of the corresponding angles are equal, then the two triangles are similar.
Therefore, to prove that two triangles are similar, we must show that either the corresponding sides are in proportion (using the SSS Similarity Theorem) or the corresponding angles are equal (using the AAA Similarity Theorem).
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Which expression is equivalent to 3x2 - 10x - 8?
(3x - 2)(x - 4)
(3x - 4)(x - 2)
(x - 4)(3x + 2)
(3x - 4)(x + 2)
The expression which is equivalent to 3x² - 10x - 8 is (x - 4)(3x + 2).
The correct answer option is option C
Which is the equivalent expression?3x² - 10x - 8
check all that applies:
(3x - 2)(x - 4)
= 3x² - 12x - 2x + 8
= 3x² - 14x + 8
(3x - 4)(x - 2)
= 3x² - 6x - 4x + 8
= 3x² - 10x + 8
(x - 4)(3x + 2)
open parenthesis
= 3x² + 2x - 12x - 8
= 3x² - 10x - 8
(3x - 4)(x + 2)
= 3x² + 6x - 4x - 8.
collect like terms
= 3x² + 2x - 8
Therefore, (x - 4)(3x + 2) is equivalent to the expression 3x² - 10x - 8
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La respuesta de esta pregunta quiero pues
The value of {x} would be 11.872.
What is cosine of angle is a right angled triangle?Cosine of the angle is defined as the ratio of base and hypotenuse. Mathematically -
cosθ = (base)/(hypotenuse)
Given is a right angled triangle as shown in the figure.
We can write the value of {x} as -
cos{32} = x/14
{x} = 14 cos (32)
{x} = 14 x 0.848
{x} = 11.872
Therefore, the value of {x} would be 11.872.
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you are concerned that outside factors may bias the bexp. in the regression equation above. in what direction does the outside factor of average property price of the local neighborhood bias bexp?
The outside factor of the average property price of the local neighborhood would bias bexp in a positive direction.
This is because an increase in average property price will increase the value of the dependent variable (bexp). If the average property price of the local neighborhood increases, it will likely lead to an increase in the value of bexp.
This is because the increase in average property price will lead to an increase in the value of properties in the local neighborhood, which will in turn increase the value of bexp. Therefore, an increase in the average property price of the local neighborhood will lead to an increase in the value of bexp.
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150 to 132
275 to 242
300 to 255
12% 15% 85% 88%
Answer:
88%, 88%, 85%
Step-by-step explanation:
You can check these by multiplying the first number given by the percentages below. (or finding how much the 2nd number is of the first number)
150 × .88 = 132
275 × .88 = 242
300 × .85 = 255
Mr and Mrs Tan and their three children bought tickets for a 'Holiday- On-Ice' show. An adult's ticket cost twice as much as a child's ticket. If they spent $87.50 in all, how much did each type of ticket cost?
A child's ticket cost is $12.50 and an adult's ticket cost $25.00.
What is Equation?Two or more expressions with an Equal sign is called as Equation.
Given that Mr and Mrs Tan and their three children bought tickets for a 'Holiday- On-Ice' show.
Let x be the cost of a child's ticket, 2x be the cost of adult's ticket
The cost of all three children's tickets would be 3x and total cost of Mr. and Mrs. Tan's tickets would be 4x
So the total cost of all five tickets would be 3x + 4x = 7x.
We know that the total cost was $87.50
7x = 87.50
Divide both sides by 7
x = 87.50 / 7
x=12.50
Hence, a child's ticket cost is $12.50 and an adult's ticket cost $25.00.
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suppose five students from the class are chosen at random. what is the probability that none are mechanical engineering majors?
The probability that none are mechanical engineering majors is 0.51.
The number of students who are not mechanical engineering majors is 100 - 49 = 51. The probability of choosing a student who is not a mechanical engineering major in one draw is 51/100. The probability of choosing five students in a row who are not mechanical engineering majors is (51/100)^5. Thus, the answer is (51/100)^5 = 0.1517816.
Probability refers to potential. From 0 to 1 is used to express the value. To determine how likely an event is to occur, probability has been introduced in mathematics. This is the fundamental theory of probability, which is also applied to the probability distribution, and from which you will discover the likelihood of results for a random experiment. The complete number of possibilities that can occur should be known before calculating the likelihood that a certain event will occur.
The complete question is:-
In a class of 100 students, 30 are computer science majors, 49 are mechaincal engineering majors, 13 are civil engineers and the rest are general engineering majors. Assume students only have one major.Suppose five students from the class are chosen at random what is the probability none are mechanical engineering majors?My info I know: The mechanical engineers account for 49% of the students, making 51% not mechanical engineers? Do I take five out of the 51, so 0.05 X 0.51?
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Celia has 58 coins in her bank, all dimes and quarters. Altogether the value is $12.55. How many of each coin does she have?
Taking into account the definition of a system of linear equations, Celia has 58 coins in her bank, 13 dimes and 45 quarters.
System of linear equationsA system of linear equations is a set of two or more equations of the first degree, in which two or more unknowns are related.
In the systems of equations, the values of the unknowns must be found, with which, when replaced, they must give the solution proposed in both equations.
Amount of each coinIn this case, a system of linear equations must be proposed taking into account that:
"d" is the amount of dimes."q" is the amount of quarters.You know:
Celia has 58 coins in her bank, all dimes and quarters. Altogether the value is $12.55.So, the system of equations to be solved is
d + q= 58
0.10d + 0.25q= 12.55
It is decided to solve it using the substitution method, which consists of clearing one of the two variables in one of the equations of the system and substituting its value in the other equation.
In this case, Isolating the variable "d" from the first equation, we obtain:
d= 58 -q
Substituting in the second equation you get:
0.10× (58-q) + 0.25q= 12.55
Solving:
0.10×58 - 0.10q + 0.25q= 12.55
5.8 - 0.10q + 0.25q= 12.55
- 0.10q + 0.25q= 12.55 -5.8
0.15q= 6.75
q= 6.75÷ 0.15
q= 45
Remembering that d=58 - q, you get:
d= 58 - 45
d= 13
Finally, she has 13 dimes and 45 quarters.
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if the cost of eggs was originally $2.80 how much will eggs cost after a 20% increase
Answer:
3.36 dollars
Step-by-step explanation:
Original price is 2.80 dollars
we take 20% of 2.80 aka the original price.
(p.s 20% in just [tex]\frac{20}{100}[/tex] since % sign means divide by 100)
so,
= [tex]2.80 * \frac{20}{100}[/tex]
=0.56
This means that 20% increase results in 0.56 increase in dollars
So the price after this increase would become
2.80 + 0.56
=3.36 dollars
hope that helped
-4/-16 please help me with terminating/repeating decimal
The expression as a terminating decimal is 0.2499999....
How to evaluate the expressionFrom the question, we have the following parameters that can be used in our computation:
-4/-16
Evaluate the expression by dividing 4 and 16 by 4
So, we have the following representation
1/4
Next, we divide 1 by 4
This gives
0.25
As a repeating decimal, we have
0.2499999....
Hence, the solution is 0.2499999....
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how would a 90 confidence interval based on a sample of size 200 compare to the original 90 interval
A 90% confidence interval based on a sample of size 200 would be more reliable than the original 90% interval.
This is because the larger sample size gives the interval a larger margin of error, meaning the interval is more likely to contain the true population means. This is due to the greater number of data points used to calculate the mean, which reduces the possibility of outliers skewing the results.
Additionally, the larger sample size increases the power of the test, meaning that the probability of getting a statistically significant result is increased. Therefore, the 90% confidence interval based on a sample of size 200 would be more reliable than the original 90% interval.
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a three-digit number is chosen among all three-digit numbers. what is the probability that it will have distinct even digits?
The probability that it will have distinct even digits is 6/1000.
The first digit can take on 5 values (0,2,4,6,8).
The second digit could take on 4 values (one less than 5 to be unique).
The third digit could take on 3 values (two less than 5 to be unique).
So that makes,
N=5.4.3
N=60
P= 60/1000
P=3/50
So there are 60 unique three digit even numbers.
There are 1000 possible outcomes.
ABOUT PROBABILITYProbability and statistics are two fundamental concepts in mathematics. Probability is about the probability of an event, whereas statistics are about how different techniques are used to process different data.
Probability and statistics allow us to process complex data in a very understandable way.
Probability is one of the most popular topics in statistics. The reason is that this one theory is often used when trying to predict something. For example, figuring out what comes out of a random series of events. For simplicity, probability is also called chance or probability.
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11.the admission fee at a small fair is $2 for children and $4 for adults. on a certain day, 50 people enter the fair and $140 is collected. how many children and how many adults attended?
On a certain day, If 50 people enter the fair and $140 is collected, then there were 30 children and 20 adults attended the fair.
Let number of children be x
and let number of adult be y
Now, according to question
x+y = 50 …. ( equation 1)
and, according to cost of fair,
2x+4y= 140
x + 2y = 70 …. (equation 2)
solving equation 1 and equation 2 we get
y = 20
putting the value of y in equation 2 we get
x + 2y = 70
x + 2(20) = 70
x = 70-40
x = 30
Hence, there are 30 children and 20 adults in the fair.
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5 times 5 plus 25 times 5
Answer:
150
Step-by-step explanation:
(5)(5)=25
(25)(5)=125
add: =150
[tex]5\times5+25\times5[/tex]
[tex]5\times5=25\\25\times5=125[/tex]
[tex]25+125[/tex]
[tex]=\fbox{150}[/tex]
1) There are 6 roses, 8 carnations, and 12 tulips.
Write the ratio of carnations to all flowers in all
three forms (simplify first, then write in all three
forms).
Ratio of carnations to all flowers
= 4/13 or 4:13 or 4 carnations to 13 flowers.
What is ratio?A ratio can be defined as the relationship or comparison between two numbers of the same unit to check how bigger is one number than the other one.
Given,
There are 6 roses 8 carnations and 12 tulips
Total flowers = 6 + 8 + 12 = 26
Ratio of carnations to all flowers
= 8/26
= 4/13
or 4:13
or 4 carnations to 13 flowers.
Hence,
4/13 or 4:13 or 4 carnations to 13 flowers
is the ratio of carnations to all flowers.
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Find the solution to the system of equations
Answer:
(- 1, 1 )
Step-by-step explanation:
the solution to a system of equations given graphically is at the point of intersection of the lines.
the lines intersect at (- 1, 1 ) , then
the solution is (- 1, 1 )
there are three hospitals in the tulsa, oklahoma, area. the following data show the number of outpatient surgeries performed on monday, tuesday, wednesday, thursday, and friday at each hospital last week. at the 0.05 significance level, can we conclude there is a difference in the mean number of surgeries performed by hospital or by day of the week?
No, we cannot conclude that there is a difference in the mean number of surgeries performed by hospital or by day of the week.
The data provided would need to be further analyzed to determine if there is a statistically significant difference between the means. A t-test or ANOVA could be used to test for differences between the means.
1. The data provided shows the number of outpatient surgeries performed at three hospitals in the Tulsa, Oklahoma, area on each day of the week.
2. To determine if there is a difference in the mean number of surgeries performed by hospital or by day of the week, a statistical test needs to be conducted.
3. A t-test or ANOVA could be used to test for differences between the means.
4. The results of the test would need to be examined to determine if there is a statistically significant difference between the means.
5. At the 0.05 significance level, we cannot conclude there is a difference in the mean number of surgeries performed by hospital or by day of the week.
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a poker hand consisting of 7 cards is dealt from a standard deck of 52 cards. find the probability that the hand contains exactly 3 face cards.
The probability that the hand contains exactly 3 face cards is 0.1503.
Combinations of 7 cards out of a choice of 52.
52!/(45! *7!)= 52*51*50*49*48*47*46/7*6*5*4*3*2 = 133,784,560
Combinations of 3 face cards out of 12
12*11*10/3*2 = 220
Combinations of 4 non-face cards out of 40
40*39*38*37/4*3*2 = 91,390
Combinations of 5 face cards and 2 non-face cards
220 * 91,390 = 20,105,800
So the probability is 20,105,800/133,784,560 or 0.1503
About ProbabilityProbability theory is the theory used to model uncertainty. Probability value o events show how likely it is the event will occur with an interval of values between zero up to one. However, probability theory can only used for events that have information that complete.
For events that have no information complete can be represented by imprecise probability. One model of imprecise probability is the set-valued probability. Probability worth the set is the non-empty set with every the elements are the results of the probability selector mapping.
Then a set-valued measure is constructed which is constructed by set-valued probabilities.
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in a class of 25 students 15 of them have a cat 16 of them have a dog and 3 of them have neither find the probability that a student that chosse
The probability of students chosen have a cat and a dog is:P(cat and dog) = 9/25.
How it was obtainedThere are 25 students
Those that have cats 15
those that have a dog 16
while, 3 of them have neither
Take x = number of students who own a cat and a dog.
Consequently, the total number of students who own a cat, a dog, both or neither is as follows;
15-x + x + 16-x + 3 = 25.
-x = 25 - 34
In essence, x = 9
Therefore, the number of students who own a cat and a dog is 9.
The probability that a student chosen at random has a cat and a dog is therefore;
P(cat and dog) = 9/25.
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In a class of 25 students, 15 of them have a cat , 16 of them have a dog and 3 of them have neither. Find the probability that a student chosen at random has a cat and a dog. Find the probability that a student chosen at random has a cat and a dog
a heated election is coming up where people will select the all-time favorite cartoon. we take a poll before the election to see how the race is shaping up. according to this poll, 34% of the people say they will vote for bugs bunny and 26% say they will vote for baby shark. the poll has an error of /- 6%. based on this result, can one say that in the population, more people clearly support bugs bunny over baby shark?
No, as the confidence intervals for the two groups overlap.
From the given data,
The poll has an error of 34% of the people say they will vote for Bugs Bunny
The confidence interval for the percentage of people supporting Bugs Bunny is⇒(34 ± 6)% ≈ 28% to 40%
⇒26% say they will vote for Baby Shark.
The confidence interval for the percentage of people supporting Baby Shark is
⇒(26 ± 6)% ≈ 20% to 32%
No, it is not possible to say with certainty that more people in the population support Bugs Bunny over Baby Shark based on this poll.
The poll only provides an estimate of the percentage of people who say they will vote for each cartoon, and has a margin of error of ±6%. This means that the true percentage of people who will vote for Bugs Bunny or Baby Shark in the population could be as much as 6% higher or lower than the results from the poll.Since the confidence intervals for the two groups overlap , we cannot say that in population, more people clearly support Bugs Bunny over Baby Shark.
Hence, the correct answer is: no, as the confidence intervals for the two groups overlap.
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a box of cookies contains 4 chocolate and 6 butter cookies. miguel randomly selects a cookie and eats it. then he randomly selects another cookie and eats it. (how many cookies did he take?)
4 chocolate and 6 butter cookies are included in a box of cookies. Miguel chooses a cookie at random and consumes it. He then chooses another cookie at random and eats it. He take 10 cookies.
Science, art, statistics, encryption, gaming, gambling, and other industries all make extensive use of randomness. To test hypotheses, for instance, random assignment in randomized controlled trials and pseudorandom or random numbers in computer games like video poker. In order to produce non-deterministic data (such as a series of integers) to seed security algorithms, a TRNG is a function or apparatus based on an unpredictably occurring physical event termed an entropy source. Although chance and randomness are sometimes used interchangeably, they can have different meanings in various scientific contexts as well as in everyday life. Chance specifically has a wider range than randomness, which is frequently interpreted in accordance with more specialized mathematical connotations.
Based on the given condition,
4+6
Calculate the sum.
10
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