Set B = {a,b,c,d} and Set C = { b,d,f,g}. Find B u C.

The base-ten numeration system is the system that utmost of the world uses moment. Place value refers to the value of each number in a number. The English language is a transnational language.

What is the base ten number system, place value?

The base-ten numeration system is the system that utmost of the world uses moment. No one knows exactly why the number ten was chosen as the base for this system, but it's theorized that it's due to the number of fritters that humans retain. Fingers are veritably fluently assessable as counting tools. The base-ten numeration system consists of ten integers( 0, 1, 2, 3, 4, 5, 6, 7, 8, 9), and groups figures into ten.

     2. Understanding Place Value -

Place value refers to the value of each number in a number. For illustration, the number 753 has three" places" or columns each with a specific value. In this three-number number, the 3 is in the" bones " place, the 5 is in the" knockouts" place, and the 7 is in the" hundreds" place.

Beginning ideas of Place Value and Base Ten:

In other words, the 3(three) represents three single units, so the value of this number is three. The 5(five) is in the knockout place, where values increase by multiples of 10(ten). So, the 5(five) is worth (5)five units of 10(ten), or 5(five) x 10(ten), which equals 50(fifty). The 7(seven) is in the hundreds(100) place, so it represents seven units of 100(hundred), or 700(seven hundred).

Problems Faced by Students in Speaking the English Language -

The English language is a transnational language. It's a demand of the moment’s world. For surviving in society, people have to understand and speak the English language easily.

In this world, you go far and wide people can speak the English language or indeed understand the English language.

The English language plays a lesser part for the people in a society. The English language is an important subject for people whose English language isn't their native language.

The base-ten numeration system is the system that utmost of the world uses moment.

Place value refers to the value of each number in a number.

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Answer:

  6 quarts

Step-by-step explanation:

You want to know the number of quarts of 100% antifreeze to add to 6 quarts of 20% antifreeze to make a 60% solution.

Let x represent the number of quarts of 100% antifreeze added to the solution. Then the total amount of antifreeze in the mixture is ...

  20%(6) +100%(x) = 60%(6 +x)

Simplifying the equation, we have ...

  1.2 +x = 3.6 +0.6x

  0.4x = 2.4 . . . . . . . . . subtract 0.6x+1.2 from both sides

  x = 6 . . . . . . . . . . divide by 0.4

6 quarts of pure antifreeze must be added.

Answer:

$105

Step-by-step explanation:

$5 initial cost + $50 (teal shirt) + $50 (purple shirt)

The cost per item for maximum profit is $7.50 .

The maximum and minimum value of a function f(x) is calculated by finding the first and second derivative of f(x).

The cost to produce x pies is given by the cost function

[tex]C(x)=3x+36[/tex]

The price demand function for each pie is given by

[tex]p(x)=12-0.5x[/tex]

Revenue gained from selling x pies

[tex]R(x)=x\times p(x)\\or,R(x)=x\times(12-0.5x)\\or,R(x)=12x-0.5x^2[/tex]

Now profit function is given by

[tex]P(x)=R(x)-C(x)\\or,P(x)=-0.5x^2+12x-3x-36\\or,P(x)=-0.5x^2+9x-36[/tex]

Now we have to find the maximum profit. We know that for a function

[tex]P(x)=-0.5x^2+9x-36\\P'(x)=-x+9[/tex]

[tex]P''(x)=-1[/tex]

At P'(x)=0

or,-x+9=0

or, x=9

As P''(x)<0 therefore the profit function P(x) is maximum for x at P'(x)=0.

The profit is maximum at x=9

Price to charge per item=12-0.5x

Substituting the value of x we get:

[tex]p(x)=12-(0.5\times 9)\\or,p(x)=12-4.5\\or,p(x)=7.5[/tex]

Therefore the cost per item for maximum profit is $7.50 .

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Answer: One Solution

Step-by-step explanation:

Only the number 0 can solve this equation so it may be correct.

First approaching this problem, I would try to get x on one side of the equation by subtracting 2.5x from both sides.

This leaves us with 7.5x = 0

Therefore, this equation has only one solution, 0.

Product Y would be allocated 20% of the machine setups cost

Product Z  would be allocated 80% of the machine setups cost

What is activity-based costing?

Activity-based costing is a costing method where overhead cost of production are allocated based on the cost driver responsible for the overhead rather than using the plantwide overhead rate based on direct labor-hours.

In this case, we need to first of all determine the machine setups cost per per setups, based on the fact there 300 setups for both products Y and Z

machine setup  cost per setup=Machine setups cost/Number of setups

Machine setups cost=$180,000

Number of setups=300

machine setup  cost per setup=$180,000/300

machine setup  cost per setup=$600

Total set up cost for product Y=60*$600=$36000

Total set up cost for product Y as %=$36,000/$180,000=20%

Total set up cost for product Z=240*$600=$144,000

Total set up cost for product Z as %=$144,000/$180,000=80%

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Answer: no 25 is a perfect square

Step-by-step explanation:

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\mathsf{16 \dfrac{40}{50}}[/tex]

[tex]\mathsf{= \dfrac{16\times50 + 40}{50}}[/tex]

[tex]\mathsf{= \dfrac{800 + 40}{50}}[/tex]

[tex]\mathsf{= \dfrac{840}{50}}[/tex]

[tex]\mathsf{= 840\div50}[/tex]

[tex]\mathsf{= 16.8}[/tex]

[tex]\huge\textbf{Therefore, your answer should be:}[/tex]

[tex]\huge\boxed{\mathsf{16.8}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

Answer is ADEF

Given that, two right tringle = R + ΔHEL , R +ΔPME

Hypotenuse equal , A set of corresponding right angles are equal.{HL};

LL=LE

So ∠E(M tringle HEL)∠LM (M tringle PME)

∠H=∠P 90°

∠L=∠E                        ⇒AAS

HE PM or LE =EM

∠E = ∠M

EL = ME                      ⇒ASA

∠L = ∠E

HF = PM

∠E = ∠M                       ⇒SAS

EL = ME

Hence choose A.D.E.F

{Determination of congruence of right tringle }

explanation of  Determination of congruence of right tringle

A plane figure bounded by three finite line segments to form a closed figure is known as a triangle. A right-angled triangle is a special case of the triangle. In a right-angled triangle, one of the interior angles measures 90°. Two right triangles are said to be congruent if they are of the same shape and size. In other words, two right triangles are said to be conger

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Answer:

22.5

Step-by-step explanation:

∠EAB=2x (alternate interior angles)

∠AEB=180°-4x (linear pair)

Distance of upper bond and lower bond is 120,000 and 150,000 centimeter

Given:

Number of steps walk = 1500 steps

Each step count = 90 centimeters

Correction in each step = 10 cm nearest

Find:

Lower bound and upper bound for d

Computation:

Lower bound step length = 90 - 10

Lower bound step length = 80 centimeters

Upper bound step length = 90 + 10

Upper bound step length = 100 centimeters

Lower bound d = 1500 × 80

Lower bound d = 120,000 centimeters

Upper bound d = 1500 × 100

Upper bound d = 150,000 centimeters

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The Lagrangian is

[tex]L(x,y,\lambda) = x^2 + y^2 - \lambda (x + y - 1)[/tex]

Find its critical points.

[tex]\dfrac{\partial L}{\partial x} = 2x - \lambda = 0 \implies x = \dfrac\lambda2[/tex]

[tex]\dfrac{\partial L}{\partial y} = 2y - \lambda = 0 \implies y = \dfrac\lambda2[/tex]

[tex]\dfrac{\partial L}{\partial\lambda} = -(x+y-1) = 0 \implies x + y = 1[/tex]

From the first two conditions, [tex]x=y[/tex], so

[tex]x + y = 2x = 1 \implies x = y = \dfrac12[/tex]

At the point (1/2, 1/2), compute the Hessian determinant of [tex]f(x,y)[/tex].

[tex]H(x,y) = \begin{bmatrix} \dfrac{\partial^2f}{\partial x^2} & \dfrac{\partial^2f}{\partial x \partial y} \\\\ \dfrac{\partial^2f}{\partial y\partial x} & \dfrac{\partial^2f}{\partial y^2} \end{bmatrix} = \begin{bmatrix}2&0\\0&2\end{bmatrix}[/tex]

[tex]H(x,y)[/tex] is positive definite for all [tex]x,y[/tex], which indeed indicates a local minimum at (1/2, 1/2), so that

[tex]\min\left\{x^2+y^2 \mid x+y=1\right\} = f\left(\dfrac12,\dfrac12\right) = \dfrac14+\dfrac14 = \boxed{\dfrac12}[/tex]

The solutions of the equations of the situation can be:

z = 1 , y = 5, x = 4

z= 2 , y = 3, x = 5

z=3 , y = 1, x = 6

z = 0 , y = 7, x =3

The question can be expressed as a equation

6 x + 8 y + 10 z = 84

also, x + y + z = 10

⇒ x = 10- y - z

Putting it in first equation,

6(10 - y - z ) +8y + 10z = 84

⇒ 60 +2y + 4z = 84

⇒2(y + 2z ) = 14

⇒ y + 2z = 7

Now putting

z = 1 , we get y = 5,

z= 2 , y = 3

z=3 , y = 1

z = 0 , y = 7

So, only 4 possible solutions.

Therefore, there can only be 4 possible solutions for the equations.

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To solve an linear equation we need to use BODMAS rule.

Here the given equation is;

(x+8-x+8)

We know very well that if two like numbers have opposite sign and are added then it gets cancelled and gives zero as the result.

Similarly, here x and -x gets cancelled and we get 16 as the result.

If we get the solution of an equation as zero then we may say that the equation has no real solution. That means there are no values of the unknown which will complete the equation.

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Answer:

Given as at the end of the proof flowchart we are only left with one unknown m∠3, the logical conclusion is that we're proving that m∠3 = 180° - 54° = 126°

Answer:

[tex]=4620000x[/tex]

Step-by-step explanation:

[tex]=1000000\cdot \:4.62x[/tex]
[tex]=4620000x[/tex]

Answer:

4620000

Step-by-step explanation:

4.62x10^6

1000000x4.62

Answer: by doing math

Step-by-step explanation:

Answer:

Step-by-step explanation:

To get your answer, you would want to use the expression -3.5/60. So your answer will be -0.058.

Answer:

1440

Step-by-step explanation:

3(4+4)(4+1)(4+2)(4-2)

3*8*5*6*2

1440

Answer: N * (n+7) = n^2 + 7n

Step-by-step explanation:

This equation would be the number, n, times n+7 because n+7 is 7 more than n. To do this, you have an equation like this:

N * (N+7). You would then do distributive property, and n*n would be n squared, and n*7 would be 7n. This would give you a combined answer of n squared + 7n, or n^2 +7n.

Answer: 139

Step-by-step explanation:

first, 4 can go into 5 once so you would put one down --> 5-5= 1

bring down the one and then put down the 5 from the tens place

4 can go into 15 three times which would be 15-12 = 3

so at the top, you would have 13 so far

then with the 3 left bring down the 6 from the hundreds place from the 556

lastly, since 4 can go into 36 nine times you would put 9 down next to 13 on the top which would make it 139

(Sorry if it doesn't make that much sense)

Greetings from Brasil...

Checking the side limits of the function f(x), we find that they are equal, so there is a limit of f(x) as x approaches 4

check the attachment

The equation in slope-intercept firm for this line is y = -4/3x - 13

Linear equations are equations that have constant average rates of change. Note that the constant average rates of change can also be regarded as the slope or the gradient

The given parameters are

Slope, m = -4/3

Point (x1, y1) = (-6, -5)

The linear equation is calculated as

y = m(x - x1) + y1

So, we have

y = -4/3(x + 6) - 5

Open the bracket

y = -4/3x - 8 - 5

Evaluate the difference

y = -4/3x - 13

Hence, the equation in slope-intercept firm for this line is y = -4/3x - 13

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If the point N lying on the Line segment MP, divides MP such that the ratio of MN to NP is 6 to 1, and the coordinates of M(-13, 20) and P(1-1), then the coordinates of "N" is

As per the question statement, N lying on the Line segment MP, divides MP such that the ratio of MN to NP is 6 to 1.

We are required to find out the coordinates of "N".

To solve this question, we need to know the formula to calculate the coordinates of a point (Say "c") that divides a line segment AB in the ratio of (m:n).

The formula goes as:

Abscissa of c [tex](x_{3})=\frac{mx_{2}-nx_{1} }{m-n}[/tex]

and, Ordinate of c [tex](y_{3})=\frac{my_{2}-ny_{1} }{m-n}[/tex]

where, [tex](x_{1}, y_{1})[/tex] are the coordinates of point A, while

[tex](x_{2}, y_{2})[/tex] are the coordinates of point B.

Using our given data in the above formulae, we get

Abscissa of N =  [tex]\frac{(6*1)-[1*(-13)]}{6-1} =\frac{6-(-13)}{5}=\frac{6+13}{5}=\frac{19}{5}[/tex]

And, Ordinate of N = [tex]\frac{[6*(-1)-(1*20)}{6-1} =\frac{(-6)-20}{5}=\frac{-(20+6)}{5}=\frac{-26}{5}[/tex].

Hence, our concerned point N = [tex](\frac{19}{5}, \frac{-26}{5})\\[/tex].

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the number x, you must deduct another number from it , conditions will the response be unfavorable,

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In an expression, a positive number is subtracted from two other integers. If the value of the negative number is higher than that of the positive number, then the expression's value will be considered negative. Additionally, according to the fundamental rule of integers, the number's sign-bearer must always have a higher value.

For instance,

1. 2 - 3 = -1

2. 10 + (- 8) + (- 11) = -9

3. -6 + 3 = -3

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Answer:

You either lose everything or gain everything (losing is more probable :) )

Step-by-step explanation:

The numbers that are equivalent to two and seven fifteenths are; thirty-seven fifteenths, 2.46 repeating where the 6 is repeating

We want to find  the numbers that are equivalent to two and seven fifteenths. This fraction is a mixed fraction and can be expressed as;

2⁷/₁₅

Converting this to an improper fraction gives us;

37/15

Now, in the first mixed fraction, we can turn the fraction into decimal like this; 2 + 7/15 = 2 + 0.46666 = 2.466666....

Thus, looking at the given options, the only correct option is;

C: thirty-seven fifteenths, 2.46 repeating where the 6 is repeating

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Answer:

less than

Step-by-step explanation:

|-5| is 5 so -|-5| is negative 5 (-5)

-5 is less than 5

The complete table of values is

x     |   f(x)

-1.4  |  -13.92

-0.7 |  -7.48

0    |  -3

0.7 |   -0.48

1.4 |  0.08

The function is given as:

f(x) = -2x^2 +5x - 3

Next, we calculate the values of the functions at the given x values

So, we have:

f(-1.4) = -2(-1.4)^2 + 5(-1.4) - 3 = -13.92

f(-0.7) = -2(-0.7)^2 + 5(-0.7) - 3 = -7.48

f(0) = -2(0)^2 + 5(0) - 3 = -3

f(0.7) = -2(0.7)^2 + 5(0.7) - 3 = -0.48

f(1.4) = -2(1.4)^2 + 5(1.4) - 3 = 0.08

Hence, the complete table of values is

x     |   f(x)

-1.4  |  -13.92

-0.7 |  -7.48

0    |  -3

0.7 |   -0.48

1.4 |  0.08

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