Selenium-83 has a half-life of 5 days. How many days would it take for a 10.0 mg sample to decay and have only 1.25 mg of it remain?

Answer:Do not take drugs its bad for health

Explanation:

To identify which molecule in each pair has the higher boiling point, you will need to compare the strength of the intermolecular forces between them.

Generally, molecules with stronger intermolecular forces will have a higher boiling point than molecules with weaker intermolecular forces. The intermolecular forces that could be responsible for the difference in boiling points between molecules are hydrogen bonding (HB), dipole-dipole (DD), and London dispersion (LD).

Hydrogen bonding is the strongest of these forces, followed by dipole-dipole forces, and then London dispersion forces. Therefore, if the difference in boiling points between two molecules is very large, it is likely due to hydrogen bonding.

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The percentage error, given that the measured density of the metal is 4.16 g/cm³, is 3.53%

First, we shall determine the absolute error in the measurement. Details below:

Absolute error = accepted value - measured value

Absolute error = 4.018 - 4.16

Absolute error = 0.142 g/cm³

Haven obtain the absolute error, we shall determine the percentage error. This can be obatined as follow:

Percentage error = (Absolute error / accepted value) × 100

Percentage error = (0.142 / 4.018) × 100

Percentage error = 3.53%

Thus, we can conclude that the percentage error is 3.53%

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The index of hydrogen deficiency (IHD) is a measure of the number of unsaturated bonds in a molecule. It can be calculated by subtracting the number of hydrogen atoms from 2 times the number of carbon atoms, and then dividing by 2.

[tex]C_{6}H_{6}[/tex] (no oxygen)

IHD = [tex]\frac{(2*6)-6}{2}[/tex] = 3

This means that the molecule contains 3 unsaturated bonds, which can form 3 aromatic rings.

[tex]C_{7}H_{6}O[/tex] (one oxygen)

IHD = [tex]\frac{(2*7)-6-2}{2}[/tex] = 3

This means that the molecule contains 3 unsaturated bonds, which can form 2 aromatic rings.

[tex]C_{8}H_{7}O_{2}[/tex] (two oxygens)

IHD = [tex]\frac{(2*8)-7-(2*1)}{2}[/tex] = 2

This means that the molecule contains 2 unsaturated bonds, which can form 2 aromatic rings.

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Complete question:

Give a molecular formula for your product if it contains no oxygens. Give the molecular formulas if your product contains one and two oxygens (some may not be possible).

The molecular formula for if my molecule does not have any oxygens is C6H6, if it has one oxygen it would be C7H6O, if it was two it would be C8H7O2.

Calculate the index of hydrogen deficiency, and therefore the number of rings and/or p- bonds in your unknown for each of the molecular formulas in question 3. Show your calculation

The rate law is; Rate = k[X] [Y]

The rate law is an equation that describes how the rate of a chemical reaction is dependent on the concentrations of the reactants. The rate law provides information about the rate of a reaction and the effect of changing the concentrations of reactants on the reaction rate.

The rate law can be expressed as:

rate = k [A]^m [B]^n

We have to note that for X;

1.4 * 10^-3/7.0 * 10^-4 = 0.4/0.2

2= 2^n

n = 1

For Y;

2.8 * 10^-3/1.4 * 10^-3 = 0.4/0.2

2 = 2^n

n = 1

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Due to the relatively narrow range of d-metal radii and the nearly identical sizes of all the metal ions across the series, the d-metals can be combined to create a large variety of alloys.

Since alloys, which are combinations of several elements, offer qualities that are superior to those of pure metals, almost all metals are employed in alloy form. The most common reasons for alloying are to increase strength, improve corrosion resistance, or cut expenses.

D block elements are used to combine other metals in alloys. Due to their huge size, D-lock elements combine with other elements, such as hydrogen, to produce interstitial compounds.

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Concerning the distribution of marine benthic biomass, the following statement or claims about primary production are accurate.

Primary productivity is indeed the process through which organisms transform inorganic elements into straightforward organic materials. Autotrophs, or primary producers, are in charge of this phenomenon. Typical primary examples of producers include coccolithophores, dinoflagellates, and diatoms.

Water in which production is to be assessed is sealed in sealed white as well as dark containers that are painted dark to prevent light from entering. Rating scale can be estimated by the quantity of oxygen utilized by a size of water in a defined amount of time.

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The correct option is B, if na2so4 is added to a saturated aqueous solution of ag2so4, the solubility of ag2so4 will decrease .

Solubility is a term used to describe the ability of a substance to dissolve in a solvent, such as water, to form a homogeneous solution. The solubility of a substance is determined by several factors, including temperature, pressure, and the type and concentration of the solvent. Some substances have a high solubility and can dissolve in large quantities, while others have low solubility and can only dissolve in small amounts. The solubility of a substance can also be influenced by its chemical structure, and how it interacts with the solvent.

The solubility of a substance can be useful in a variety of applications, such as in the pharmaceutical industry, where the solubility of a drug can impact its effectiveness. Solubility can also be important in the food and beverage industry, as the solubility of ingredients can affect the texture and taste of a product. Understanding solubility can also help in environmental issues, as solubility can determine the ability of pollutants to dissolve in water and affect aquatic life.

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Answer:

see below

Explanation:

1) here we are given that one mole of propane releases 2221kJ of energy.

now use unitary method as ,

to burn 1 mol (44g) propane 2221kJ of energy is required

to burn 1g of propane 2221kJ/44g of energy is required

therefore to burn 25g of propane 2221/44*25kJ of energy is required= 1261.93kJ ≈ 1262 kJ

Hence 1262kJ of energy is required to burn 25g propane.

2) amount of heat absorbed= 25kJ

amount of work done = 12J

change in energy= (25-12)kJ = 13kJ

Hence the value of ∆E is 13kJ .

and we are done!

Two liquids are being poured: one is an oxidising chemical and the other is corrosive, flame-flammable chemical. Away from other chemicals, especially flammables, keep oxidizers.

Chemicals ought to be kept in hazard class storage (i.e. flammable with flammable, oxidizers with oxidizers, etc.) During storage, incompatible compounds need to be physically separated from one another. Direct sunlight or intense local heat shouldn't be allowed to touch chemicals. Corrosives should not be near anything with which they might react.

Each pictogram is a symbol on a white backdrop with a red border that denotes a specific danger (s). The classification of the chemical danger determines the pictogram on the label. OSHA will require the use of only eight of the nine pictograms that the GHS employs.

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The isoelectric point (pI) is the pH at which an amino acid or protein.

Functional groups of amino acids in enzymes present have the ability to readily ionize. other amino acids which have ionizable side chains. These include arginine, aspartic acid, cysteine, glutamic acid, histidine, lysine and tyrosine.

There are basically four different classes of amino acids determined by different side chains: (1) non-polar and neutral, (2) polar and neutral, (3) acidic and polar, (4) basic and polar. Principles of Polarity: The greater the electronegativity difference between atoms in a bond, the more polar the bond.

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1. Bonds formed by equal sharing of a pair of electrons are called nonpolar covalent bonds because there is a uniform charge across the molecule along all axes.

2. Non-uniform or unequal sharing of a pair of electrons produces a polar covalent bond where a relative charge distribution is seen across the molecule.

3. Bonds formed when two atoms or compounds respectively donate and receive electrons are called ionic bonds and readily dissociate in water.

4. Attractions between polarized molecules (intermolecular bonding) are called hydrogen bonds and can also form between polarized regions of the same molecule (intramolecular bonding).

5. Attractions between adjacent atoms due to constantly fluctuating electron clouds are called Van der Waals forces.

Van der Waals forces are the weak intermolecular forces that exist between molecules. They are the result of the fluctuating dipoles created by the movement of electrons within a molecule. These forces can cause the molecules to attract or repel one another, leading to the formation of temporary bonds.

The strength of Van der Waals forces is much weaker than other forces like covalent or ionic bonds, but they play a significant role in determining the properties of liquids and gases. For example, the weak nature of these forces means that liquids have a lower boiling point compared to solids.

Van der Waals forces are also responsible for the phenomenon of adsorption, where molecules stick to a surface, and for the formation of supramolecular structures like micelles, vesicles, and liquid crystals. These forces are also crucial in determining the stability of large biomolecules like proteins and DNA.

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Complete Question:

Complete each statement by dragging the proper word into the appropriate blank and then place each sentence in order from the strongest to weakest chemical bond.

1. Bonds formed by equal sharing of a pair of electrons are called ______ covalent bonds because there is a uniform charge across the molecule along all axes.

2. Non-uniform or unequal sharing of a pair of electrons produces a _____ covalent bond where a relative charge distribution is seen across the molecule.

3. Bonds formed when two atoms or compounds respectively donate and receive electrons are called _______ bonds and readily dissociate in water.

4. Attractions between polarized molecules (intermolecular bonding) are called ______ bonds and can also form between polarized regions of the same molecule (intramolecular bonding).

5. Attractions between adjacent atoms due to constantly fluctuating electron clouds are called ______ forces.

The mass of 1.32 × 10²⁰ U atoms is 0.47 g and that of 2.55 × 10²² Zn atoms is 2.76 g Similarly the mass of 4.1 × 10²³ Pb atoms is 141.4 g and that of 6.59 × ²⁴ Si atom is 30.7 g.

The atomic mass of an element is the mass of one mole of that element. One mole of an element contains 6.02 × 10²³ atoms. This number is called Avogadro number.

The number of moles of 1.32 × 10²⁰ U atoms = 1.32 × 10²⁰ /6.02 × 10²³ = 0.0002 moles.

atomic mass of U = 238.02 g/mol.

then mass of 0.0002 = 0.0002 mol × 238 g/mol = 0.47 g.

The number of moles of   2.55 × 10²² Zn atoms =  2.55 × 10²²/6.02 × 10²³ = 0.042 moles.

atomic mass of Zn  = 63.5 g/mol.

then mass of 0.042 mol  = 0.042  mol × 65.3 g/mol = 2.76 g.

The number of moles of 4.1 × 10²³ Pb atoms = 4.1 × 10²³  /6.02 × 10²³ = 0.68 moles.

atomic mass of Pb   = 207.2 g/mol.

then mass of 0.68mol  = 0.68  mol × 207.2 g/mol = 141.4 g.

The number of moles of 6.59 × ²⁴ Si atoms = 6.59 × ²⁴   /6.02 × 10²³ = 1.09 moles

atomic mass of Si   = 28.08 g/mol.

then mass of 1.09 mole  = 1.09 mole × 28.08 g/mol = 30.7g

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A monatomic ion is a type of monatomic atom technically speaking. However, the term "monatomic atom" typically refers to an element's neutral atom. Krypton (Kr) and neon atoms are two examples (Ne).

Cations that have a single conceivable charge are known as monatomic cations. Only Group IA (alkali metals, +1), Group IIA (alkaline metals, +2), zinc (Zn2+), aluminum (Al3+), and silver (Ag+) contain these ions.

An ion that has more than one atom is called polyatomic since the word poly- signifies numerous. This sets polyatomic ions apart from monatomic ions, which are made up of a single atom.

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a.1.54 mole have 3significant figures

b.55.39g of carbon have 4significant figures

In positional notation, significant figures are the digits in a number that are trustworthy and required to denote the amount of something.

a)Determination of the number of mole in 67.7g pf C3H8.

mass of C3H8=67.7g

molar mass of C3H8 =(3*12)+(8*1)=44g/mol

number of mole of C3H8=..?

number of mole=mass/molar mass

number of mole of C3H8=67.7/44

Number of mole of C3H8=1.54mole

The significant figure for 1.54 mole is 3SF

b)Determination of the mass if carbon in the compound.

This is illustrated below:

The mass of C in compound can be obtained as follow:

= 3C/C3H8*67.7

=3*12/44*67.7

=36/44*67.7

=55.39g

Therefore,55.39g of carbon is present in the compound.

The significant figures for 55.39g is 4SF

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complete question:Propane (C3H8) is widely used in liquid form as a fuel for barbecue grills and camp stoves. For 67.7 g of propane, determine the following.(a) Calculate the moles of compound.mol(b) Calculate the grams of carbon.g .round each of your answers to significant figures.

The gas moving the slowest would be Argon (Ar). The speed of a gas molecule is determined by its temperature, which is related to its average kinetic energy.

The gas moving the slowest would be Argon (Ar). The speed of a gas molecule is determined by its temperature, which is related to its average kinetic energy. In general, the heavier a gas molecule is, the slower it will move, as it takes more energy to get it moving. Among the gases listed, Argon has the heaviest molecular weight and therefore would be expected to move the slowest. Helium (He) has the lightest molecular weight and would be expected to move the fastest, followed by Neon (Ne), Krypton (Kr), and Argon (Ar) in order of increasing molecular weight.

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Body fossils are animals, egg and teeth. Trace fossils are burrows and Diplodocus. An animal or plant from a previous geologic era that has been retained in the Earth's crust as a fossil.

An animal or plant from a previous geologic era that has been retained in the Earth's crust as a fossil, remnant, imprint, or trace. The main repository for knowledge regarding the evolution of life on Earth is the complex of information preserved in fossils found all across the planet.

Only a tiny percentage of extinct species have been retained as fossils, and often only those with a sturdy skeleton are capable of doing so. Body fossils are animals, egg and teeth. Trace fossils are burrows and Diplodocus.

Therefore, body fossils are animals, egg and teeth. Trace fossils are burrows and Diplodocus.

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1.Water is used to break bond is hydrolysis

2. Produces water as byproduct in dehydration

3. Dehydration

4.Hydrolysis

5. Dehydration

6. Hydrolysis

7. Hydrolysis

8. hydrolysis

Hydrolysis is a process in which water is used to break the bond.hydrolysis breaks down polymers To form monomers In chemistry and biology, hydrolysis refers to a twofold decomposition reaction in which water participates. Therefore, the hydrolysis reaction may be described by the reversible chemical equation[tex]AB + HOH \leftrightarrow AH + BOH[/tex] If a substance has the chemical formula AB, where A and B are atoms or groups, and water has the chemical formula HOH. Other than water, the reactants in a hydrolysis reaction can be neutral molecules, as they are in the majority of cases when organic compounds are involved, or ionic molecules, as they are in the cases of salts, acids, and bases.

Dehydration is the loss of body fluids which impairs body function . It forms polymer by linking monomer and water is always a by product .

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The element that fits the description and resemble aluminum, is Al.

The element Al is part of the periodic table and is classified as a metal. It is a silvery-white, soft, nonmagnetic and ductile metal in the boron group.

Aluminum is the third most abundant element in the Earth's crust and the most abundant metal. It is an excellent conductor of heat and electricity, and it has a relatively high melting point and boiling point compared to other metals. Aluminum is also highly malleable and can be easily shaped and molded into almost any shape.

It also has excellent corrosion resistance and can be used in a wide variety of applications. Aluminum is often used in construction, as it is lightweight, strong and non-combustible. It is also used in the automotive industry, as it is a good conductor and is highly resistant to corrosion.

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Answer:

13 mins

Explanation:

We need to find how many half lives are required to reach .0313

.0313 = 1/2^n    log both sides and solve for n

log.0313 / log (1/2 )   = n     where n= NUMBER of halflives

n = ~ 5 half lives

   these 5 half lives took up 65 minutes

       so EACH half life is 65/5 = 13 mins

The central box of a boxplot has the median of the data above it.

Median is a mathematical term used to describe the middle value of a set of data or a distribution. It is often used in statistics to describe the central tendency of a set of data. The median is calculated by arranging all the values in a set of data in numerical order and identifying the middle value. If the data set has an odd number of values, then the median is simply the middle value. However, if the data set has an even number of values, then the median is calculated by taking the average of the two middle values.

The median is considered to be a more robust measure of central tendency compared to the mean because it is less affected by extreme values or outliers. It provides a better representation of the central value of a data set when the distribution is skewed or has extreme values. In these cases, the mean can be greatly influenced by the outliers, leading to a misrepresentation of the central tendency.

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Treatment of an alcohol with TsCl in pyridine gives retention of stereochemistry.The alcohols are treated with the TsCl in presence of weak bases such as pyridine. This results in the sulfonate esters.

Alcohols can be transformed to alkyl Tosylate by reacting with p-toluene sulfonyl chloride (TsCl) and pyridine. In this reaction, alcohol, which is a poor leaving group, is substituted by Tosylate, which is a good leaving group.sCl or p-toluenesulfonyl chloride is a reagent that converts the hydroxyl group . The alcohols are treated with the TsCl in presence of weak bases such as pyridine. This results in the sulfonate esters. The secondary alcohol given in the question reacts with TsCl or p-toluenesulfonyl chloride in presence of weak base pyridine .this reaction convert group into the group. that is the tosyl group is treated with the acetate ion in presence of tetra butyl amine in DMF. This reaction replaces the tosyl group with acetate ion. Tosyl group is a good leaving group. It tends to leave the molecule .thus in the presence of an incoming group acetate ion it is removed from the molecules.

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The new pressure of the gas is 15 atm. Option C

We know that the gas laws can be used to obtain the parameters that ahs to do with the idea gas and in this case we have to deal with the relationship of the pressure and the temperature of the gas at a constant volume.

We know that;

Given that;

P1/T1 = P2/T2

P1T2 = P2T1

P1 = initial pressure

P2 = final pressure

T1 = initial temperature

T2 = Final temperature

Thus;

P2 = 10 * 450/300

P2 = 15 atm

The pressure of the gas is 15 atm

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Missing parts;

We are studying the properties of a 10 L vessel of an ideal gas at 300 K and 10 atm of pressure inside. We can fix the volume or the pressure of the vessel as we like.

Question 3

If we increase the temperature of the vessel to 450 K at constant volume, what would the pressure inside the vessel be?

Group of answer choices

10 atm

5 atm

20 atm

15 atm

The reaction between hydroxide ion (OH-) and bromocyclohexane can be an SN2 reaction, which is a type of nucleophilic substitution reaction.

In an SN2 reaction, a nucleophile attacks the substrate from the back side, leading to a concerted (one step) process in which the substrate and nucleophile exchange places. In the reaction between hydroxide ion and bromocyclohexane, the hydroxide ion acts as the nucleophile and attacks the substrate (bromocyclohexane) from the back side, resulting in the formation of a tetrahedral intermediate. This intermediate then collapses, leading to the formation of a new bond between the carbon and the oxygen atom of the hydroxide ion and the breaking of the bond between the carbon and the bromine atom.

Overall, the reaction can be summarized as:

Bromocyclohexane + OH- → Hydroxylcyclohexane + Br-

Note that the reaction conditions, such as temperature and solvent, can affect the rate and mechanism of the reaction.

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The density of the liquid is 0.8125 g/mL.

Density is the mass of a material substance per unit volume. d = M/V, where d is density, M is mass, and V is volume, is the formula for density. Grams per cubic centimeter are a typical unit of measurement for density. For instance, while Earth has a density of 5.51 grams per cubic centimeter, water has a density of 1 gram per cubic centimeter. Another way to state density is in kilograms per cubic meter (in meter-kilogram-second or SI units). For instance, air weighs 1.2 pounds per cubic meter. In textbooks and manuals, the densities of typical solids, liquids, and gases are stated. The mass of a body can easily be determined from its volume or vice versa using a density.

mass of liquid = (mass of container and liquid) - (mass of empty container)

mass of liquid = 194.37 g - 72.5 g = 121.87 g

The volume of the liquid is equal to the volume of the container, which is 150.0 ml. (1 cm3 = 1 mL)

The density of the liquid is the mass of the liquid divided by the volume of the liquid:

density = mass/volume

density = 121.87 g / 150.0 ml

density = 0.81 g/ml

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The number of significant figures is 2 sig figs

The mass of a substance per unit of volume is its density.

Density is most frequently represented by the symbol, however Latin letter D may also be used.

The formula for density is mass divided by volume:

Displaying the style "rho = frac mV" where

m is the mass, V is the volume, and is the density

Hence,

find the smallest number used in the calculation.

There are 2 digits used.

when solving, round to have 2 significant figures

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When an atom in a reactant gains electrons, its oxidation number increases. Option C.

Oxidation is defined in several ways:

In other words, a gain of electrons also translates to an increase in the oxidation number of atoms.

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They alter as a result of the reaction. is not a quality that ribozymes possess.

In a nucleic acids molecule, ribozymes, which are RNA molecules, can both break and create covalent bonds. These compounds can bind and cleave an mRNA substrate with even larger potential advantages then antisense oligodeoxynucleotides.

Ribozymes, also known as catalytic RNA, are proteins that link amino acids to build protein chains. They are located in the ribosome. In addition to these crucial processes, ribozymes also participate in RNA splicing, transferred RNA production, and viral replication.

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Dicer cleaves the pre-miRNA at the level of the loop, yielding a 22-nt, double-stranded RNA molecule.

The pre-miRNA molecule is a precursor to the microRNA (miRNA), which plays an important role in gene regulation. The process of producing mature miRNA from pre-miRNA involves cleavage at specific sites, and this cleavage is facilitated by specific enzymes. DGCR8, Drosha, and RISC are all involved in the processing of pre-miRNA, but it is Dicer that performs the final step of cleaving the pre-miRNA at the level of the loop, yielding a 22-nt double-stranded RNA molecule. This double-stranded RNA molecule is then loaded into the RISC complex, which recognizes and cleaves specific target mRNAs, leading to regulation of gene expression.

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A student assisting with the experiment would observe that all of the following statements about the electron transport chain are true EXCEPT: option (C) i.e. Every single electron carrier is movable and hydrophobic.

This statement is false because electron carriers in the electron transport chain can be hydrophilic or hydrophobic, and they may be mobile or anchored to a membrane. Their properties, such as hydrophobicity and mobility, depend on their specific role in the electron transport chain and the organisms they are found in.

1. In the ETC, carriers travel inside the inner mitochondrial membrane, passing electrons from one to another and pumping protons across the inner mitochondrial membrane.

2. Therefore, they are mobile. In order to travel inside the hydrophobic interior of the membrane, we would expect them to all be hydrophobic.

3. However, cytochrome c is a highly water-soluble protein, unlike other cytochromes.

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Question - A student assisting with the experiment would observe all of the following about the electron transport chain EXCEPT:

A. Electrons are passed from carriers with lower reduction potential to those with higher reduction potential.

B. The first electron carrier is also a proton pump.

C. Every single electron carrier is movable and hydrophobic

D. The electron carriers can transport a maximum of 2 electrons.