Answer: 9.25
Step-by-step explanation: Round each number to the nearest place. For example, 26 would round to 30. Round each number until you get a certain number right before the hundredth place.
X - 2(X + 10) = 12
What is this??!?!!?
Answer:
-32
Step-by-step explanation:
Pal, it's M A T H
Answer:
-32
Step-by-step explanation:
x-2x-20=12
-x=32
x=-32
.....................
Just give me the answer, Dont explain, Thank you.
The general term of the function is y = 4000 + 100x
How to determine the general term of the function?The given parameters are
Guaranteed = $4000
Monthly raise = $100
Let the number of months be x, and the total earning be y
So, we have:
y = Guaranteed + Monthly raise * x
This gives
y = 4000 + 100 * x
Evaluate
y = 4000 + 100x
Hence, the general term of the function is y = 4000 + 100x
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Find the slope of the lines containing the following points
(-2, 1) & (-5,5)
The slope of the lines containing the following points (-2, 1) & (-5,5) is [tex]\frac{-4}{3}[/tex].
As per the question statement, two points lie (-2, 1) & (-5,5) on a line.
We are supposed to find the slope of the line.
To solve this question, we need to know the formula to calculate the Slope of line passing through two points [tex](x_{1} ,y_{1} )[/tex] and [tex](x_{2} ,y_{2} )[/tex] which is given by
[tex]m=\frac{y_{2}-y_{1} }{x_{2}-x_{1}}[/tex]
Since given in the question statement, our concerned points are (-2, 1) & (-5,5), we can consider [tex][x_{1}=(-2)] , [x_{2}=(-5)], [y_{1}=1][/tex] and [tex][y_{2}=5][/tex].
Using these values into above mentioned formula, we get,
Slope (m) = [tex]\frac{5-1}{[(-5)-(-2)]}=\frac{4}{-3}=\frac{-4}{3}[/tex].
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2. Polygon EFGH is a scaled copy of Polygon ABCD.
Name the segment in the scaled copy that
corresponds to segment AB.
1A
The name of the segment in the scaled copy that corresponds to segment AB is segment EF
How to name the segment in the scaled copy that corresponds to segment AB?The given parameters are:
Polygon EFGH is a scaled copy of Polygon ABCD.
This means that the corresponding points are
E = A
F = B
G = C
H = D
Remove points C and D
So, we have
E = A
F = B
Hence, the name of the segment in the scaled copy that corresponds to segment AB is segment EF
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Which ordered pairs make the open sentence true?
4x+y>9
Answer:
Step-by-step explanation:
let x = 5, y = 0
so the equation is 4x+y>9
and put the value of x and y in the equation
4 (5) + 0 > 9
20 + 0 > 9
20 > 9, therefore the order pair ( 5,0) satisfies the condition. true
please help with question 20! thank you. it’s similar to a previous question i asked but i’m still not too sure how to approach it. thank you.
Answer:
118
Step-by-step explanation:
The key piece of information to focus on is that there are around 120 fruits. 15 is the biggest of the given divisors, and the gaps between multiples of 15 is the greatest (compared to 4 and 6) which will narrow down our options. Therefore we can first try approaching the problem by finding multiples of 15 that are close to 120.
The question says that when the number (let's call it A) is divided by 15, it leaves 13. Therefore we can express A as such:
A-13 = 15x OR 15x + 13 = A
Where 'x' represents a whole number showing that the number is divisible by 15.
The closest multiples of 15 to 120 are 105 (15*7), 120 (15*8), and 135 (15*9).
A is one of these numbers + 13, let's see which ones are closest:
105+13 = 118, 120+13 = 133, 135+13 = 148
118 is very close to 120, so let's check it with the other numbers:
118/4 = 29 r 2
118/6 = 19 r 4
The exact number of fruits is 118.
Hope this helped!
Answer:
118
Step-by-step explanation:
We are told that there are about 120 fruits.
Fruits divided equally among 4 students
Multiples of 4: 4, 8, 12, ... 112, 116, 120, 124, ...
Therefore, 116, 120 and 124 are closest to 120.
Add the given remainder of 2 to these numbers:
116 + 2 = 118120 + 2 = 122124 + 2 = 126Fruits divided equally among 6 students
Multiples of 6: 6, 12, 18, ... 108, 114, 120, 126 ...
Therefore, 114, 120 and 126 are closest to 120.
Add the given remainder of 4 to these numbers:
114 + 4 = 118120 + 4 = 124126 + 4 = 130Fruits divided equally among 15 students
Multiples of 15: 15, 30, 45, ... 105, 120, 135, ...
Therefore, 105, 120 and 135 are closest to 120.
Add the given remainder of 13 to these numbers:
105 + 13 = 118120 + 13 = 133135 + 13 = 148Therefore, as the total of 118 fruits is common to all three groups the exact number of fruits is 118.
Check
Divide 118 by each group of students:
118 ÷ 4 = 29 r 2118 ÷ 6 = 19 r 4118 ÷ 15 = 7 r 13As the remainders concur with the given amount of fruit left over for each group of students, this verifies that the exact number of fruits is 118.
12÷3×5-4 to the 2nd power
I have two answers depending on the format. I'm not sure if the entire function is to the 2ndpower or not. Either way, it's either 256 or 4.
systems of liner equations in three variables using substitution method
2x + y + 3z = -2
x - y - z = -3
3x - 2y + 3z = -12
Above given the the linear equations. Systems of liner equations in three variables using substitution method, the variables are (-3.2, -0.218, 0.06).
What do you mean by linear equation?The standard form for the linear equations in two variables is Ax+ By =C. For example, 2x+3y=5 is a linear equation in the standard form. When an equation is given in this form, it's pretty easy to find the both intercepts (x and y). This form is also very useful when solving systems of the two linear equations.
Solve one of the equation for one of it's variables. From the given three variables, there is no incorrect choice so choose to solve for any variable.
x= y+ z -3
Substitute the value from the first variable we solved for into the other equation and solve for the next variable.
(y+z-3) +y +3z = -2
2y+4z= 1
y= [tex]\frac{1+4z}{2}[/tex]
Substitute the value from the two variables that we solved and plug it into the remaining equation and solve for the last remaining variable.
3([tex]\frac{1+4z}{2}[/tex]+z-3) - 2 ([tex]\frac{1+4z}{2}[/tex]) + 3z= -12
3([tex]\frac{1+4z+2z-6}{2}[/tex])- 2([tex]\frac{1+4z}{2}[/tex])+ 3z= -12
3([tex]\frac{6z-5}{2}[/tex])- 2([tex]\frac{1+4z}{2}[/tex])+3z = -12
[tex]\frac{18z-15}{2}[/tex]- 1+ 4z+ 3z= -12
18z-15-2+8z +6z= -24
32z-17=-24
32z=-24+17
z=[tex]\frac{-7}{32}[/tex]= -0.218
therefore, y= 0.06
Now substitute the values:
x= 0.06+(-0.218)-3= -3.2
The three variables are (-3.2, -0.218, 0.06)
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guys im new and i need help withe some first one
1. -2 2/3 divided by 4/3
2. -2 1/4 divided by (-5/8)
3. 1/2 divided by 2/5
4.11/3 divided by 4/5
Answer:
#1 = -2
Step-by-step explanation:
First, we need to make -2 2/3 an improper fraction. An improper fraction is a fraction whose numerator is bigger than its denominator.
you first multiply the whole number (ignoring the negative sign for now) by the denominator:
2*3=6
then you add the numerator:
6+2=8
finally you put that number over the denominator and then put the negative sign back:
-8/3
Next, you can use keep change flip to solve the division
You keep the first fraction, change the division sign to a multiplication sign, and flip the numerator and the denominator of the second fraction:
-8/3 divided by 4/3 becomes -8/3 x 3/4
finally you multiply across as you would normally and simplify
-8/3 x 3/4= -24/12
-24/12 simplified is -2
:D
if you need help with the rest just comment on this response and I'll try to answer as soon as I can
the sum of two numbers is 51, five times the larger number decreased by 7 equals one, more than 8 times the smaller number. find the numbers
Answer: A=32 B=19
Step-by-step explanation:
The temperature in a town is 12.5°F during the day and -23.3°F at night. Find the difference in the temperatures.
Answer:
Explanation
temperature in a town during day=12.5The temperature in a town is 12.5°F
temperature at night is -23.3°F
difference -23.3°F+12.5°F
=. -10.8
One bar of candy A and two bars of candy B have 768 calories. Two bars of candy A and one bar of candy B contain 783 calories. Find the caloric content of each candy bar.
Answer:
Bar A : 266 calories; Bar B : 251 calories
Step-by-step explanation:
Assume bar A's caloric content is "a" and bar B's caloric content is "b".
1. a + 2b = 768
2. 2a + b = 783
Add both equations together.
3. 3a + 3b = 1551
Divide both sides by 3.
4. a + b = 517
Subtract equation 4 from equation 1.
5. a + 2b - a - b = 768 - 517
Evaluate.
6. b = 251
Subtract b's value from equation 2.
7. 2a + b - b = 783 - 251
Evaluate.
8. 2a = 532
Divide both sides by 2.
9. a = 266
Water flows through a cylindrical pipe of radius 0.74 cm.
It fills a 12 l bucket in 4 minutes. When the 12 l bucket is emptied in to a circular pool, the water level rises by 5 mm. Calculate the radius of the pool.
The radius of the pool with height as 0.5 cm and volume as 12,000 cm³ is 87.39 cm.
We have that:
Radius of the water pipe = 0.74 cm
r = 0.74 cm
It fills a 12 L bucket in 4 minutes
1 L = 1000 cm³
12 L = 12,000 cm³
Volume of water put in the pool = 12,000 cm³
Height of the pool that rise = 5 mm = 0.5 cm.
H = 0.5 cm
Let the radius of the pool be R.
Volume = π r² h
Substituting the values, we get that:
12,000 = ( 22 / 7 ) R² ( 0.5 )
R² = 7636.36
R = 87.39 cm
Therefore, we get that, the radius of the pool with height as 0.5 cm and volume as 12,000 cm³ is 87.39 cm.
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10. Determine whether the inequality is always, sometimes, or never true. (1 point)
4x-8>1 + 4(x+3)
always
sometimes
Onever
Answer: onever
Step-by-step explanation:
4x-8>1+4(x+3)
4x-8>1+4(x)+4(3)
4x-8>1+4x+12
4x-8>4x+13
4x-8-4x>4x+13-4x
-8>13
Hence, inequality is never true
"
Question
Normal
Shane earns $8 per hour babysitting and $6 per hour walking dogs. He also earns tips for each job. Last week Shane spent 2 more hours walking dogs than babysitting. He received $12 in tips for babysitting and
$10 in tips for dog-walking. Shane earned the same total amount for each job.
Write an equation to represent the situation. Use the variable h to represent the number of hours Shane spent babysitting
The equation to represent the situation is given as $2h -$10 = 0
We have been given that
Money earned by Shane for babysitting = $8 per hour
Money earned by Shane for walking dogs = $6 per hour
Let the number of hours spent by Shane be h hours
Tips she received for babysitting = $12
Tip she received for walking dogs = $10
Total amount earned by Shane for babysitting = $8*h + $12
Also Shane worked two more hours for walking dogs then the amount will be = 2*$6 = $12
Total amount earned by Shane for walking dogs = $6*h + $12 + $10
= $6h + $22
As she earned the same total amount of job the equation will be given as
$8h + $12 = $6h + $22
$2h -$10 = 0
Which is the required equation
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Express the interval using inequality notation.
(-∞, -11] U l-8, ∞)
The inequality notation for the given interval is -∞ < x ≤ -11 and -8 ≤ x < ∞
Disclaimer:
Considering the given interval as (-∞, -11] ∪ [-8, ∞).
Given interval is a union of two intervals.
The first interval denotes the set of all real numbers which are less than or equal to -11.
And the second interval denotes the set of all real numbers which are greater than or equal to -8.
The inequalities can be written as below:
(-∞, -11] ⇒ x ≤ -11 (or) -∞ < x ≤ -11
[-8, ∞) ⇒ x ≥ -8 (or) -8 ≤ x < ∞
And there is a union symbol between these two intervals.
So, x should satisfy both inequalities.
x ≤ -11 and x ≥ -8
or the above can be written as
-∞ < x ≤ -11 and -8 ≤ x < ∞
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A scientist has 20 grams of the radioactive isotope sodium-24. The isotope decays exponentially as shown in the table.
Time (hours)
Mass (grams)
5
15.9
10
12.6
15
10
20
7.9
25
6.3
30
5
Approximately what will the mass of the isotope be after 45 hours?
A 1.5 grams
B. 2.5 grams
C. 3.5 grams
D. 4.5 grams
The mass of the isotope after 45 hours is 2.5 grams.
Given, from the table we can find that when time is 10 hours,
the mass is 12.6 grams;
when time is 25 hours the mass is 6.3 grams .
And 12.6 × 1/2 = 6.3
Also we can find when time is 15 hours the mass is 10 grams,
when time is 30 hours, the mass is 5 grams as:
10 × 1/2 = 5
so we know that half life period is:
25 - 10 = 30 - 15 = 15 hours.
When time is 45 hours,
45 = 15+115
= 3 half life periods, so the mass is :
20 × 1/2 × 1/2 × 1/2
= 2.5 grams.
Hence the mass of the isotope after 45 hours is 2.5 grams.
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Cylinder A has radius 3 cm and
height 10 cm
Cylinder B has radius 6 cm and
height 8 cm
10 cm
Cylinder A
8 cm
Cylinder B
6 cm
Cylinder A is half full of water.
Work out the volume of water in
Cylinder A.
Give your answer in terms of Pie
The volume of the water filled in the cylinder A is 141.77 cm³.
How do you describe a cylinder?A cylinder is a 3 solid that contains two parallel bases connected at a fixed distance by a curved surface.
These bases are typically circular in shape (such as a circle), with the center of a two bases connected by a line segment known as the axis.A cylinder does have two flat ends shaped like circles. A curved face which resembles a tube connects these two faces. A flat net for just a cylinder resembles a rectangle with such a circle connected at each end.The formula for the volume of the cylinder is;
Volume = πr²h
Where, π = 3.14,
radius r = 3 cm.
height h = 10 cm.
Put the values and obtain the volume.
Volume = (3.14)(3)²(10)
Volume = 282.74 cm³.
As, the cylinder is half filled with water;
Water volume = 282.74/2 cm³
Water volume = 141.77 cm³
Thus, the volume of water filled in cylinder A is 141.77 cm³.
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The correct question is-
Cylinder A has radius 3 cm and height 10 cm. Cylinder A is half full of water.
Work out the volume of water in Cylinder A.
Can someone explain why this is a false equation
Step-by-step explanation:
I think the answer is just no solution to begin with since the value of an absolute value will never be a negative number or in this case less than -2. therefore the equation is false
what is the perimeter in terms of x? in other words find the pereimeter.
Answer:
Step-by-step explanation:
perimeter of rectangular: 2(a+b)
we know from the graph, assume that a = 2x b = x+ 3
so the perimeter (C) in terms of x is C = 2(2x + x +3) = 6x + 6
Question 6(Multiple Choice Worth 1 points)
(02.05 MC)
If the parent function f(x) = [x] is transformed to g(x) = |x-31, what transformation occurs from f(x) to g(x)?
O The graph of f(x) is shifted upward to create g(x).
O The graph of f(x) is shifted downward to create g(x).
O The graph of f(x) is shifted to the right to create g(x).
O The graph of f(x) is shifted to the left to create g(x).
Using translation concepts, the correct option is given as follows:
The graph of f(x) is shifted to the right to create g(x).
What is a translation?A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction either in it’s definition or in it’s domain. Examples are shift left/right or bottom/up, vertical or horizontal stretching or compression, and reflections over the x-axis or the y-axis.
For this problem, the functions are given as follows:
f(x) = |x|.g(x) = |x - 31|.That is, g(x) = f(x - 31), hence the function was shifted 31 units to the right and the correct option is given by:
The graph of f(x) is shifted to the right to create g(x).
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Complete the table (again)
How to I do part (ii)?
Answer:
Step-by-step explanation:
7(i)
[tex]\displaystyle\\\frac{d}{dx}\{x*(3x-5)^\frac{5}{3} \}=\frac{dx}{dx} *(3x-5)^\frac{5}{3}+x*\frac{d}{dx} \{(3x-5)^\frac{5}{3} \}\\\\ \frac{d}{dx}\{x*(3x-5)^\frac{5}{3} \}=1*(3x-5)^\frac{5}{3} +x*\frac{5}{3}*(3x-5)^{\frac{5}{3} -1}*\frac{d}{dx} \{(3x-5)\}\\\\ \frac{d}{dx}\{x*(3x-5)^\frac{5}{3} \}=(3x-5)^\frac{5}{3} +\frac{x*5*(3x-5)^{\frac{2}{3}}*3 }{3} \\\\\frac{d}{dx}\{x*(3x-5)^\frac{5}{3} \}=(3x-5)^\frac{5}{3} +5x*(3x-5)^\frac{2}{3} \\\\[/tex]
[tex]\displaystyle\\\frac{d}{dx}\{x*(3x-5)^\frac{2}{3} \}=(3x-5)^\frac{2}{3}*((3x-5)^{\frac{5}{3}-\frac{2}{3}} + 5x)\\\\\frac{d}{dx}\{x*(3x-5)^\frac{2}{3} \}=(3x-5)^\frac{2}{3} *(3x-5)^\frac{3}{3}+5x) \\\\\frac{d}{dx}\{x*(3x-5)^\frac{2}{3} \}=(3x-5)^\frac{2}{3} *(3x-5+5x)\\\ \frac{d}{dx}\{x*(3x-5)^\frac{2}{3} \}=(8x-5)*(3x-5)^\frac{2}{3}[/tex]
7(ii)
[tex]\int\limits {(x*(3x-5)^\frac{2}{3}) } \, dx \\Let\ \sqrt[3]{3x-5} =u\\Hence,\\(\sqrt[3]{3x-5})^3=u^3\\ 3x-5=u^3\\3x-5+5=u^3+5\\3x=u^3+5\\[/tex]
Divide both parts of the equation by 3:
[tex]\displaystyle\\x=\frac{u^3+5}{3}\\\\dx=\frac{d}{du} \{\frac{u^3+5}{3}\} \\dx=\frac{3u^2}{3} du=\\\\dx=u^2du\\Hence,\\\\\int\limits {\frac{u^3+5}{3}* u^2*u^2} \, du =\\\\\int\limits {\frac{u^3+5}{3} *u^4} \, du =\\\\\int\limits {\frac{u^7+5u^4}{3} } \, du =\\\\\frac{1}{3} \int\limits {u^7} \, du +\frac{1}{3}\int\limits {5u^4} \, dxu =\\\\[/tex]
40 35 37 40 39 41 39 39 36 38 36 39 36 39 35 39 36 37 41 37 38 36 35 40 40 41 39 38 39 35 35 40 39 39 37 38 38 39 35 35 41 37 40 39 38 37 37. Calculate the mode
The mode of the data is 39 as it's frequency is highest .
Mode is a measure of central tendency . It is the no . which has highest frequency in data .
Data - Frequency
40 - 6
35 - 7
37 - 7
39 - 12 ( max . )
36 - 5
38 - 6
41 - 4
The value of frequency corresponding to 39 is maximum .
Therefore , as 39 occurs most of the time in the data , hence it is the mode of this data .
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3. The graph below shows the number of points that Lebron scored in each of his first
four games of a season.
On average, how many more points per game did Lebron score in the last two games than the
first two games?
Using the mean concept, it is found that LeBron scored 10 more points per game on his last two games than on his first two.
What is the mean?The mean of a data-set is given by the sum of all observations in the data-set divided by the number of observations.
For his first two games, he scored 20 + 15 = 35 points, hence the mean is:
35/2 = 17.5 points per game.
For his last two games, he scored 25 + 30 = 55 points, hence the mean is:
55/2 = 27.5 points per game.
The difference is:
27.5 - 17.5 = 10.
On average, LeBron scored 10 more points per game on his last two games than on his first two.
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Using heron's formula the sides of the tringleare 70cm,80cm and 90cm.find its area(use root 5=2.23)
The area of the triangle is 1200√5 cm².
Given that, the sides of the triangle are 70cm,80cm and 90cm.
We need to find the area of a triangle using Heron's formula.
What is Heron's formula?As per Heron's formula, the value of the area of any triangle having lengths, a, b, c, perimeter of the triangle, P, and semi-perimeter of the triangle as 's' is determined using the below-given formula:
Area of triangle = √s(s-a)(s-b)(s-c), where s = Perimeter/2 = (a + b + c)/2
Now, semi perimeter = (70+80+90)/2=120
Area of triangle=√120(120-70)(120-80)(120-90)
=√120×50×40×30
=√40×3×2×25×40×30
=40×5√3×2×3×2×5
=40×5×3×2√5
=1200√5 cm²
Therefore, the area of the triangle is 1200√5 cm².
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8x=2 |6x -2| please show me the first step
well, tis noteworthy that whenever we have an absolute value equation is really a piece-wise function in disguise, namely the absolute expression is really two in disguise.
[tex]8x=2|6x-2|\implies \cfrac{8x}{2}=|6x-2|\implies 4x=|6x-2|\implies \begin{cases} 4x=+(6x-2)\\ 4x=-(6x-2) \end{cases} \\\\[-0.35em] ~\dotfill\\\\ 4x=+(6x-2)\implies 4x=6x-2\implies 0=2x-2 \\\\\\ 2=2x\implies \cfrac{2}{2}=x\implies \boxed{1=x} \\\\[-0.35em] ~\dotfill\\\\ 4x=-(6x-2)\implies 4x=-6x+2\implies 10x=2\implies x=\cfrac{2}{10}\implies \boxed{x=\cfrac{1}{5}} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill x= \begin{cases} 1\\[1em] \frac{1}{5} \end{cases}~\hfill[/tex]
can someone help me solve this problem?
Answer:
No
Step-by-step explanation:
If Q is the midpoint of PR, then PQ=QR.
[tex]5(x+2)=8x-3 \\ \\ 5x+10=8x-3 \\ \\ 3x=13 \\ \\ x=\frac{13}{3} \\ \\ \implies PQ=5\left(\frac{8}{3} +2 \right) \neq 36[/tex]
This means PQ + QR = PR isn't 72, and thus Q is not the midpoint of PR.
which statements are true regarding the sequence below? check all that apply. 10/3,4,24/5,144/25,...
Answer:
A) It can be represented using the formula f(x + 1) = 6/5(f(x)) when f(1) = 10/3.
C) It can be represented using the formula f (x) = 10/3(6/5)/\x-1
What is sequence?
A sequence is an enumerated collection of objects in which repetitions are allowed and order matters.
Given:
10/3, 4, 24/5, 144/25, ...
From the above sequence we can generate the formula,
f (x) = 10/3
Also, for f(x+1) we can have
x=1,
f(1)= 10/3
f(2)= 4
So, f(x + 1) = 6/5(f(x))
Step-by-step explanation:
Explain why V8 is
a rational number, but √8 is not a rational
number.