Isosceles triangles have two equal angles. The two equal angles are the bottom left and bottom right.
X = 28
Y = 152
See picture for explanation
- Jeron
b) A (-3,-5), B (2,-5), C (2, 2) are three of the four vertices of a rectangle ABCD and D is the vertex opposite to B. Plot these vertices in graph paper and find: (i) the coordinates of the vertex D (ii) the area of the rectangle ABCD.
1. Determine whether the following differential equation is exact. If it is, calculate a general solution in an implicit form. a. (y2cos(x−y)−xy 2sin(x−y))dx+(2xycos(x−y)+xy 2sin(x−y))dy=0 b. (2x+12y 2)dx+(12x+2y)dy=0 c. (12x 2+2y)dx+(2x+12y)dy=0
The differential equation (y^2 cos(x−y) −x^2 sin(x−y)) dx+(2xycos(x−y) +x^2 sin(x−y)) dy =0 is not exact, because it cannot be written in the form F(x,y)dx + G(x,y)dy = 0 for some functions F and G.
b. The differential equation (2x+12y^2)dx+(12x+2y)dy=0 is exact, because it can be written in the form F(x,y)dx + G(x,y)dy = 0 for F(x,y) = 2x + 12y^2 and G(x,y) = 12x + 2y.
To find a general solution in an implicit form, we can integrate both sides:
∫ (2x + 12y^2) dx + ∫ (12x + 2y)dy = C
x^2 + 6y^2 + 12xy = C
c. The differential equation (12x^2 + 2y) dx+(2x + 12y^2)dy=0 is not exact, because it cannot be written in the form F(x,y)dx + G(x,y)dy = 0 for some functions F and G.
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the sum of 5/6 and six times a number is equal to 1/2
Answer:
x = -1/18
Step-by-step explanation:
[tex]\frac{5}{6} +6x=\frac{1}{2}[/tex]
[tex]6x=\frac{1}{2} -\frac{5}{6}[/tex]
[tex]6x=\frac{6-10}{12}[/tex]
[tex]6x=\frac{-4}{12}[/tex]
[tex]6x=-\frac{1}{3}[/tex]
[tex]x=\frac{-\frac{1}{3} }{6} =\frac{-1}{(3)(6)}[/tex]
[tex]x=-\frac{1}{18}[/tex]
Hope this helps
C=1/30x^2-2x+1530
what is the companys start up cost
Answer:
Step-by-step explanation:
ito answer: Combine 130 and x2.C=x230−2x+1530
Tickets for a reserved seat, r, for the basketball game cost $4 each and student tickets, s, cost $3 each. There were 1,787 people who attended the basketball game and a total of $5,792 was earned in ticket sales. Select the two equations that represent the situation.
A) r+s=5,792
B) r+s=1,787
C) 3r+4s=5,792
D) 4r+s=5,792
E) 4r+3s=5,792
The two equations which can be used to represent the situation are;
r + s = 1787
4r + 3s = 5,792
The correct answer choice is option B and E
Write two equations that represent the situation?Reserved seat for basketball game = r
Students seat for basketball game = s
Cost of reserved seat tickets = $4
Cost of students tickets = $3
Total number of people who attended the basketball game= 1,787 people
Total amount earned for tickets sales= $5,792
r + s = 1787
4r + 3s = 5,792
Therefore, the basketball game situation can be represented by the equation r + s = 1787; 4r + 3s = 5,792
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The difference between 5/2 of a number and 17 is 48
The numerical form of the statement is (5/2)n - 17 = 48.
What is a numerical expression?A numerical expression is a mathematical statement written in the form of numbers and unknown variables. We can form numerical expressions from statements.
Let, 'n' be the unknown number,
So, the statement The difference between 5/2 of a number and 17 is 48
can be written as,
(5/2)n - 17 = 48.
5n - 34 = 96.
5n = 96 + 34.
5n = 130.
n = 130/5.
n = 26.
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A Salesman bought a computer from a manufacturer. The salesman then sold the computer for $15,600 making a profit of 25%. How much did the salesman pay the manufacturer for the computer?
Ivan sells beaded necklaces. Each large necklace sells for $5.90 and each small necklace sells for $4.90. How much will he earn from selling 1 large necklace and 7 small necklaces?
The total amount spent by Ivan is given by the equation A = $ 40.20
What is an Equation?Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.
It demonstrates the equality of the relationship between the expressions printed on the left and right sides.
Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.
Given data ,
Let the total amount spent by Ivan be represented as A
Now , the equation will be
The cost of one large necklace = $ 5.90
The cost of one small necklace = $ 4.90
The number of large necklaces = 1
The number of small necklaces = 7
So , the cost of 7 small necklaces = 7 x cost of one small necklace
Substituting the values in the equation , we get
The cost of 7 small necklaces = 7 x $ 4.90
The cost of 7 small necklaces = $ 34.30
And , the total amount spent by Ivan = cost of one large necklace + cost of 7 small necklaces
On simplifying the equation , we get
The total amount spent by Ivan A = 5.90 + 34.30
The total amount spent by Ivan A = $ 40.20
Hence , the equation is A = $ 40.20
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What is 1000+5*33+555
Answer:
The answer is 1720ㅤㅤㅤㅤㅤㅤㅤㅤ
Airline companies are interested in the consistency of the number of babies on each flight, so that they have adequate safety equipment. Suppose an airline conducts a survey. Over Thanksgiving weekend, it surveys 6 flights from Boston to Salt Lake City to determine the number of babies on the flights. R determines the amount of safety equipment reeded by the result of that study. Select the things that were wrong with the way the survey was conducted. Conducting the survey on a holiday weekend will not produce representative results The survey uses systematic sampling. The survey was conducted using six similar flights. The survey would not be a true representation of the entire population of air travelers. Choosing 6 flights represents a stratified sample. Select the ways that you would improve the survey if it were to be repeated. Ask travelers to fill out a questionnaire Conduct the survey at the entrance to the airport. Conduct the survey during different times of the year. Conduct the survey on different days of the week. Conduct the survey using flights to and from various locations
Survey was wrong: holiday, systematic sample, 6 similar flights. To improve: questionnaire, various times/locations, entrance, different days.
The problems with the survey conducted by the airline are:
1) Conducting the survey on a holiday weekend is not representative of the entire population of air travelers;
2) The survey uses systematic sampling which may not accurately reflect the entire population;
3) The survey was only conducted on 6 similar flights and does not represent the entire population of air travelers.
To improve the survey, the following steps can be taken:
1) Ask travelers to fill out a questionnaire;
2) Conduct the survey at the entrance to the airport;
3) Conduct the survey during different times of the year;
4) Use various days of the week to conduct the survey;
5) Conduct the survey using flights to and from various locations.
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X+1/2 + 5x-3/10
When X=3
Answer:
18.2
Step-by-step explanation:
replace where x is with 3
[tex]3 + \frac{1}{2} + (5 \times 3) - \frac{3}{10} [/tex]
[tex]3 \frac{1}{2} + 15 - \frac{3}{10} [/tex]
[tex]15 - \frac{3}{10} = 14 \frac{7}{10} [/tex]
[tex]3 \frac{1}{2} + 14 \frac{7}{10} = 18 \frac{1}{5} [/tex]
or[tex]3.5 + 15 - 0.3 = 18.2[/tex]
given two independent random variables such that x has a mean of 50 and a standard deviation of 8 and that y has a mean of 100 and a standard deviation of 6, find the mean and standard deviation of the variable x 50.
The standard deviation is 19.21 while the mean is 20.785.
a) Because E(Y) = 12, var(Y) = 9.
then, for 2Y+20
E(2Y+20)=2E(Y)+20=24+20=44
Var(2Y+20)=4(9)=36.
The average deviation is six.
b)E(X) = 80 var(X) = 144
so, for 3X
E(3X)=3(80)=240
Var(3X)=9Var(X)=9(144)=1296
The average deviation is 36.
c)0.25x+y
E(0.25x+y)=0.25E(x)+E(y)=0.25(80)+12=32
Var(0.25x+y)=0.0625 var(x)+var(y) +2(0.25)Cov(x,y)
Cov(x,y)=0 since x and y are independent.
Var(0.25x+y)=18
Standard deviation = 4.24 d) x – 5 y
E(x-5y)=E(x)-5E(y)=80-5(12)=20
Var(x-5y)=var(x)+25var(y)-2(5)Cov(x,y)
Because X and Y are unrelated, Cov(x,y) = 0
Var(x-5y)=369
The standard deviation is 19.21, while the mean is 20.785
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Which equation below does not show equivalent expressions when y = 2
The equation below that does not show equivalent expressions when y = 2, is 5y + 25 = 5 ( y + 4 ).
option C.
Which equation does not follow the equivalent expression?
The equation below that does not show equivalent expressions when y = 2, is determined by solving for y in all the given equation.
y + 4y = y ( 1 + 4 )
y + 4y = y + 4y
5y = 5y
y = y
y + y + y = 3y
3y = 3y
y = y
5y + 25 = 5 ( y + 4 )
5y + 25 = 5y + 20
5y + 5 = 5y
5 ( y + 1 ) = 5y
y + 1 = y
2 (y + 2 ) = 2y + 4
2y + 4 = 2y + 4
2y = 2y
y = y
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guess the value of the limit (if it exists) by evaluating the function at the given numbers (correct to six decimal places).
The value of the limit that exists at the given numbers is approximately 0.5.
First of all at x = 3.1, the value of [tex]$$\lim _{x \rightarrow 3} \frac{x^2-3 x}{x^2-9} $$[/tex] will be
[tex]$$\lim _{x \rightarrow 3.1} \frac{x^2-3 x}{x^2-9} $$[/tex] = [tex]\frac{x^2-3 (x) }{x^2-9}$$[/tex] = [tex]\frac{(3.1)^2-3(3.1)}{(3.1)^2-9}[/tex] = [tex]\frac{0.31}{0.61}[/tex] ≅ 0.508197
At x = 3.05, the value of [tex]$$\lim _{x \rightarrow 3} \frac{x^2-3 x}{x^2-9} $$[/tex] will be
[tex]$$\lim _{x \rightarrow 3.05} \frac{x^2-3 x}{x^2-9} $$[/tex] = [tex]\frac{x^2-3 (x) }{x^2-9}$$[/tex] = [tex]$\frac{(3.05)^2-3(3.05)}{(3.05)^2-9}=\frac{0.1525}{0.3025}$[/tex] ≅ 0.504132
At x = 3.01, the value of [tex]$$\lim _{x \rightarrow 3} \frac{x^2-3 x}{x^2-9} $$[/tex] will be
[tex]$$\lim _{x \rightarrow 3.01} \frac{x^2-3 x}{x^2-9} $$[/tex] = [tex]\frac{x^2-3 (x) }{x^2-9}$$[/tex] = [tex]$\frac{(3.01)^2-3(3.01)}{(3.01)^2-9}=\frac{0.0301}{0.0601}$[/tex] ≅ 0.500832
At x = 3.001, the value of [tex]$$\lim _{x \rightarrow 3} \frac{x^2-3 x}{x^2-9} $$[/tex] will be
[tex]$$\lim _{x \rightarrow 3.001} \frac{x^2-3 x}{x^2-9} $$[/tex] = [tex]\frac{x^2-3 (x) }{x^2-9}$$[/tex] = [tex]$\frac{(3.001)^2-3(3.001)}{(3.001)^2-9} $[/tex]= [tex]$\frac{3.001 \times 10^{-3}}{6.001 \times 10^{-3}}$[/tex] ≅0.500083
At x = 3.0001, the value of [tex]$$\lim _{x \rightarrow 3} \frac{x^2-3 x}{x^2-9} $$[/tex] will be
[tex]$$\lim _{x \rightarrow 3.0001} \frac{x^2-3 x}{x^2-9} $$[/tex] = [tex]\frac{x^2-3 (x) }{x^2-9}$$[/tex] = [tex]$\frac{(3.0001)^2-3(3.0001)}{(3.0001)^2-9} $[/tex]= [tex]$\frac{3.001 \times 10^{-4}}{6.001 \times 10^{-4}}$[/tex] ≅ 0.500008
At x = 2.9, the value of [tex]$$\lim _{x \rightarrow 3} \frac{x^2-3 x}{x^2-9} $$[/tex] will be
[tex]$$\lim _{x \rightarrow 2.9} \frac{x^2-3 x}{x^2-9} $$[/tex] = [tex]\frac{x^2-3 (x) }{x^2-9}$$[/tex] = [tex]$\frac{(2.9)^2-3(2.9)}{(2.9)^2-9} $[/tex]= [tex]$\frac{-0.29}{-0.59}$[/tex] = 0.491525
At x = 2.95, the value of [tex]$$\lim _{x \rightarrow 3} \frac{x^2-3 x}{x^2-9} $$[/tex] will be
[tex]$$\lim _{x \rightarrow 2.95} \frac{x^2-3 x}{x^2-9} $$[/tex] = [tex]\frac{x^2-3 (x) }{x^2-9}$$[/tex] = [tex]$\frac{(2.95)^2-3(2.95)}{(2.95)^2-9} $[/tex]= [tex]$\frac{-0.1475}{-0.2975}$[/tex] = 0.495798
At x = 2.99, the value of [tex]$$\lim _{x \rightarrow 3} \frac{x^2-3 x}{x^2-9} $$[/tex] will be
[tex]$$\lim _{x \rightarrow 2.99} \frac{x^2-3 x}{x^2-9} $$[/tex] = [tex]\frac{x^2-3 (x) }{x^2-9}$$[/tex] = [tex]$\frac{(2.99)^2-3(2.99)}{(2.99)^2-9} $[/tex]= [tex]$\frac{-0.0299}{-0.0599}$[/tex] = 0.499165
At x = 2.999, the value of [tex]$$\lim _{x \rightarrow 3} \frac{x^2-3 x}{x^2-9} $$[/tex] will be
[tex]$$\lim _{x \rightarrow 2.999} \frac{x^2-3 x}{x^2-9} $$[/tex] = [tex]\frac{x^2-3 (x) }{x^2-9}$$[/tex] = [tex]$\frac{(2.999)^2-3(2.999)}{(2.999)^2-9} $[/tex]= [tex]$\frac{-2.999 \times 10^{-3}}{-5.999 \times 10^{-3}}$[/tex] = 0.499917
At x = 2.9999, the value of [tex]$$\lim _{x \rightarrow 3} \frac{x^2-3 x}{x^2-9} $$[/tex] will be
[tex]$$\lim _{x \rightarrow 2.9999} \frac{x^2-3 x}{x^2-9} $$[/tex] = [tex]\frac{x^2-3 (x) }{x^2-9}$$[/tex] = [tex]$\frac{(2.9999)^2-3(2.9999)}{(2.9999)^2-9} $[/tex]= [tex]$\frac{-2.999 \times 10^{-4}}{-5.999 \times 10^{-4}}$[/tex] = 0.499992
From above all, we can see that the limit is approximately equal to and tends towards 0.5. So 0.5 will be our answer.
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Your question was incomplete, your most probable question was:
Guess the value of the limit (if it exists) by evaluating the function at the given numbers (correct to six decimal places).
[tex]$$\lim _{x \rightarrow 3} \frac{x^2-3 x}{x^2-9}[/tex], x = 3.1, 3.05, 3.01, 3.001, 3.0001, 2.9, 2.95, 2.99, 2.999, 2.9999
The volume of a right cone is 4275\piπ units^3
3
. If its circumference measures 30\piπ units, find its height.
The height of the right cone will be 57 units.
What is the volume of the cone?The area a cone takes up in a three-dimensional plane is known as its volume. A cone's base is circular, so it is made of a radius and a diameter.
Given that the volume of a right cone is 4275π cubic units. The circumference of the cone is 30π.
The height of the cone will be calculated as below:-
First, calculate the radius of the base of the cone,
Circumference = 2πr
30π = 2πr
r = 15 units
The height of the cone:-
Volume = 4275π
( 1 / 3 ) πr²h = 4275π
h = ( 4275 x 3 ) / r²
h = ( 4275 x 3 ) / ( 15)²
h = 57 units
Hence, the height will be 57 units.
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Draw the base plan for the set of stacked cubes. Assume that no cubes are hidden form view.
Answer:
Given Figure has set of Stacked cubes.
To Draw the Base Plan, lets see its right side, Left Side and Front side view.
Right side:
It has 3 cubes in base.
2 cubes in 2nd layer clearly seen in figure and only 1 cube in 3rd layer.
Left Side:
It has 2 Cubes in base.
Both Cubes attached to 1st and 2nd cube of right side cubes.
Front Side:
It can be seen that, here base only has 2 rows of cubes.
Therefore, 1st Figure is correct Base Plan (or enclosed figure)
Note: Numbers in enclosed figure just shows the total no. of cubes in that stack.
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2
In order to calculate marginal cost, producers must compare the difference in the cost of producing orie unit to the cost
of
O purchasing a unit.
O distributing that unit.
31:27
O producing the next unit.
O producing a different unit.
The solution is Marginal cost is (1200 - 1000) / (30 - 20) = 12.
What is Subtraction?Subtraction is the process of taking away a number from another. It is a primary arithmetic operation that is denoted by a subtraction symbol (-) and is the method of calculating the difference between two numbers.
here, we have,
In order to calculate marginal cost, producers must compare the difference of producing one unit to the cost of producing the next unit
Marginal cost is the change in total cost as a result of increasing output produced by one unit.
For example, if the total cost of producing 20 units of a good is 1000 and the total cost of producing 30units is 1200.
Marginal cost is (1200 - 1000) / (30 - 20) = 12
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Find the x coordinates of the points where the curve with equation y = x³ - 4x² + 5x + 4 has a gradient of 1
Answer:
Step-by-step explanation:
To find the x-coordinates of the points where the curve with the equation y = x³ - 4x² + 5x + 4 has a gradient of 1, we need to find the points where the derivative of the equation y = x³ - 4x² + 5x + 4 is equal to 1. The derivative of the equation y = x³ - 4x² + 5x + 4 is given by:
dy/dx = 3x² - 8x + 5
So, we need to find the solutions of the equation:
3x² - 8x + 5 = 1
This is a quadratic equation that can be solved by factoring, completing the square, or using the quadratic formula. To use the quadratic formula, we can write:
x = (-b ± √(b² - 4ac)) / (2a)
Where a = 3, b = -8, and c = 4. Plugging in these values, we get:
x = (-(-8) ± √((-8)² - 4 * 3 * 4)) / (2 * 3)
x = (8 ± √(64 - 36)) / 6
x = (8 ± √(28)) / 6
x = (8 ± 2√7) / 6
So, the two solutions are:
x = (8 + 2√7) / 6 and x = (8 - 2√7) / 6
These are the x-coordinates of the points where the curve with the equation y = x³ - 4x² + 5x + 4 has a gradient of 1.
think about what the terms density-dependent and density-independent mean mean which of the followung statemets about how
The difference between density-dependent and independent is given below.
By controlling population density-related factors including disease, competition, and prediction, density dependence regulates the population.
A huge population is often where density-dependent operates.
The rate of increase and decrease determines this.
Food, housing, prediction, competition, and disease are factors that depend on population density.
Density Independence: Natural disasters and the weather are examples of things that govern the population without taking density into account.
It is possible to use density independence in both small and big populations.
Both small and large populations can be served by density-independent.
Fluctuations, fires, droughts, extremely high temperatures, and tornadoes are examples of density-independent variables.
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in order to determine cash flows from operating activities, firms may use a method in which every item on the income statement is adjusted from accrual accounting to cash accounting.
In order to determine cash flows from operating activities, firms may use a method in which every item on the income statement is adjusted from accrual accounting to cash accounting which is called Modified cash basis.
What is Modified cash basis?This is referred to as an accounting method that combines elements of the two primary bookkeeping practices known as cash and accrual accounting.
In this scenario, different adjustments are made so as to get the accurate value of the income generated by the company or organization.
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Un rectángulo está inscrito en un círculo de radio igual a 3 centímetros. Exprese el área A del rectángu- lo como una función de la longitud de uno de sus lados.
Therefore , the solution of the given problem of rectangle comes out to be A= b* √6²-b².
Describe the rectangle.In the Euclidean plane, a rectangle is merely a cube with four right angles. It is sometimes referred to as an equiangular quadrilateral or a quadrant that seems to have equal angles. The parallelogram also has the option of a straight angle. Four of a square's sides are all the same length. Rectangular quadrilaterals have four equal sides and four 90° vertices. It is sometimes referred as an "equirectangular square" as a result. A rectangle is also referred to as a parallelogram due to the identical and parallel lengths of its opposite sides.
Here,
radio= 3 cm
Al estar un rectángulo inscrito en un círculo, el diámetro del círculo corresponderá a la diagonal del rectángulo
Siendo b la base del rectángulo y a la altura, se tiene que:
6²= a²+b²
a²= √6²-b²
Nota: Se empleó el teorema de Pitágoras
El área del rectángulo está dado por:
A= base* altura
A= b*a
Reemplazando a:
A= b* √6²-b²
Therefore , the solution of the given problem of rectangle comes out to be A= b* √6²-b².
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A sales representative must visit four cities. Omaha, Dallas, Wichita and Oklahoma City. There are direct air connections between each of the cities. Use the multiplication rule of counting to determine the number of differenct choices the sales representative has for the order in which to visit the cities. Use the multiplciation rule of counting to determine the number of possible sequences of the cities. There are four choices for the first city, three choices for the second city, two choices for the third city and one choice for the fourth city.
The sales representative has 24 possible sequences of cities to visit.
The multiplication rule of counting states that if there are n choices for the first event, m choices for the second event, p choices for the third event, and q choices for the fourth event, then there are a total of n x m x p x q possible sequences of choices. Applying this to the situation of the sales representative visiting four cities, we can say that there are 4 x 3 x 2 x 1 = 24 possible sequences of the cities.
To break this down further, the sales representative has 4 choices for the first city, Omaha, Dallas, Wichita, and Oklahoma City. Once the first city has been chosen, there are then 3 choices for the second city, Omaha, Dallas, and Wichita. From these 3 choices, there are then 2 choices for the third city, Omaha and Dallas. And then finally, there is 1 choice for the fourth city, Omaha. Multiplying these numbers together gives us 4 x 3 x 2 x 1 = 24 possible sequences of cities.
Therefore, the sales representative has 24 possible sequences of cities to visit.
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What is the simplify answer for 3v+2v+5
Answer: 5 (v+1)
Step-by-step explanation:
( i_i )
A salesman earns 7% commission on all the merchandise that he sells. Last month he sold $7000 worth of merchandise. How much commission (in dollars) did he earn last month
A salesman earns $490 as commission on his sales.
What is percentage?Percentage is defined as a given part or amount in every hundred. It is a fraction with 100 as the denominator and is represented by the symbol "%".
Given that, a salesman earns 7% commission on all the merchandise that he sells.
Last month he sold $7000 worth of merchandise.
Now, the commission is 7% of 7000
7/100 ×7000
= 0.07×7000
= $490
Therefore, a salesman earns $490.
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There are 6 onion bagels and 18 plain bagels in a box of 24 bagels. What is the ratio of the number of onion bagels to the number of plain bagels in the box?
Round to the indicated place: 9,83(9),038
The number 9,839,038 after indicated rounding off gives the number 9,839,000.
What is Rounding Off?Rounding off of a number is defined as the simplification of the number by keeping the value of the number same but is made closer to the next number.
Rounding can be done for whole numbers as well as decimals.
Given is a whole number 9,839,038.
We have to round it to the place shown where the digit is 9.
Look at the next digit right to 9.
It is 0, which is less than 5.
So replace all the digits next to 9 by 0.
We get the number 9,839,000.
Hence the rounded number is 9,839,000.
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Can anyone assist me with this, many thanks.
Answer:
1.a) x = g(2)
1.b) See below
2.a) See below
2.b) α = 60°
3.a) 2 + h
3.b) 2
4.a) Interval [3, 4] = 3 m/s
Interval [3, 3.1] = 2.1 m/s
4.b) 2 m/s
Step-by-step explanation:
Question 1Part (a)
Given function f(x):
[tex]f(x)=\dfrac{x}{x-2}[/tex]
If the range of f is (-∞, 1) U (1, ∞), then a value of y in the range of f is y=2.
Set the function equal to the value of y and solve for x:
[tex]\begin{aligned}y=2 \implies \dfrac{x}{x-2}&=2\\x&=2(x-2)\\x&=2x-4\\-x&=-4\\x&=4\end{aligned}[/tex]
The solution written as a function x = g(y) is:
x = g(2)Part (b)
Given function g(y):
[tex]g(y)=\dfrac{2y}{y-1}[/tex]
Verify that g is the inverse function of f by calculating g(f(x)):
[tex]\begin{aligned}\implies g(f(x)) &=\dfrac{2f(x)}{f(x)-1}\\\\&=\dfrac{2\left(\frac{x}{x-2}\right)}{\left(\frac{x}{x-2}\right)-1}\\\\&=\dfrac{2\left(\frac{x}{x-2}\right)}{\left(\frac{x-(x-2)}{x-2}\right)}\\\\&=\dfrac{\left(\dfrac{2x}{x-2}\right)}{\left(\dfrac{2}{x-2}\right)}\\\\&=\dfrac{2x}{2}\\\\&=x \quad (\text{for all $x\neq 2$})\end{aligned}[/tex]
Similarly, calculate f(g(y)):
[tex]\begin{aligned}\implies f(g(y))&=\dfrac{g(y)}{g(y)-2}\\\\&=\dfrac{\left(\frac{2y}{y-1}\right)}{\left(\frac{2y}{y-1}\right)-2}\\\\&=\dfrac{\left(\frac{2y}{y-1}\right)}{\left(\frac{2y-2(y-1)}{y-1}\right)}\\\\&=\dfrac{\left(\dfrac{2y}{y-1}\right)}{\left(\dfrac{2}{y-1}\right)}\\\\&=\dfrac{2y}{2}\\\\&=y \quad \text{(for all $y \neq 1$)}\end{aligned}[/tex]
Hence verifying that g is the inverse function of f.
Question 2[tex]\boxed{\begin{minipage}{5 cm}\underline{Trigonometric Identities}\\\\$\tan x=\dfrac{\sin x}{\cos x}$\\\\\\$\cos \left(\arctan \left(x\right)\right)=\dfrac{1}{\sqrt{1+x^2}}$\\\\\\$\sin\left(\arctan \left(x\right)\right)=\dfrac{x}{\sqrt{1+x^2}}$\\\end{minipage}}[/tex]
Part (a)
If y = arctan(x) then tan(y) = x.
Use the trigonometric identities to express sin(y) and cos(y) in terms of x.
[tex]\boxed{\begin{aligned}\tan(y) &= x\\\implies \dfrac{\sin y}{\cos y}&=x\\\sin y&=x \cos y\\ \sin y&=x \cos (\arctan x)\\ \sin y&=\dfrac{x}{\sqrt{1+x^2}}\end{aligned}}[/tex]
[tex]\boxed{\begin{aligned}\tan(y) &= x\\\\\implies \dfrac{\sin y}{\cos y}&=x\\\\\dfrac{\sin y}{x}&= \cos y\\\\ \cos y&=\dfrac{\sin(\arctan x)}{x}\\\\ \cos y&=\dfrac{\dfrac{x}{\sqrt{1+x^2}}}{x}\\\\\cos y&=\dfrac{x}{\sqrt{x^2+1}x}\\\\\cos y&=\dfrac{1}{\sqrt{x^2+1}}\end{aligned}}[/tex]
Part (b)
Given linear equation:
[tex]y=\sqrt{3}x+1[/tex]
As the slope of a linear equation y = mx + b is m, then the slope (m) of the given line is √3.
If m = tan(α) then:
[tex]\begin{aligned}\implies m&=\sqrt{3}\\\tan (\alpha)&=\sqrt{3}\\\alpha&=\arctan \sqrt{3}\\\alpha&=60^{\circ}+180^{\circ}n\\\end{aligned}[/tex]
If α is the angle the line forms with the x-axis, then α = 60°.
Question 3Given function:
[tex]f(x)=x^2-1[/tex]
Part (a)
[tex]\begin{aligned}\dfrac{f(1+h)-f(1)}{h} &=\dfrac{((1+h)^2-1)-(1^2-1)}{h}\\\\&=\dfrac{(1+2h+h^2-1)-0}{h}\\\\&=\dfrac{2h+h^2}{h}\\\\&=2+h\end{aligned}[/tex]
Part (b)
Part a used differentiating from first principles to find the gradient of f(x) at x = 1. As h gets smaller, the gradient of the straight line gets closer and closer to the gradient of the curve. Therefore, as h gets close to zero, (2 + h) gets close to 2. Therefore, the slope of the tangent line to the graph of f(x) at the point where x = 1 is 2.
Question 4A particle is moving on the x-axis and its position at time is given by
[tex]x(t)=t^2-4t+3[/tex]
Evaluate the position of the particle at t = 3, t = 4 and t = 3.1:
[tex]x(3)=3^2-4(3)+3=0[/tex]
[tex]x(4)=4^2-4(4)+3=3[/tex]
[tex]x(3.1)=(3.1)^2-4(3.1)+3=0.21[/tex]
Average velocity formula
[tex]\overline{v}=\dfrac{s(t_2)-s(t_1)}{t_2-t_1}[/tex]
Therefore, the average velocity of this particle over the interval [3, 4]:
[tex]\overline{v}=\dfrac{x(4)-x(3)}{4-3}=\dfrac{3-0}{1}=3\;\; \rm m/s[/tex]
The average velocity over the interval [3, 3.1] is:
[tex]\overline{v}=\dfrac{x(3.1)-x(3)}{3.1-3}=\dfrac{0.21-0}{0.1}=2.1\;\; \rm m/s[/tex]
Part (b)
To find an equation for velocity, differentiate the given equation for displacement:
[tex]v(t)=\dfrac{\text{d}x}{\text{d}t}=2t-4[/tex]
To calculate the instantaneous velocity of the particle at time t = 3, substitute t = 3 into the equation for velocity:
[tex]v(3)=2(3)-4=2\;\; \rm m/s[/tex]
what is the negative square root of 16/9
Answer:
-0.4444444444 or just -0.4
How to find the area of a square
Answer: Find the length of one side and square it
Example: Lets say one side of the square has a length of 7. The area would be 49 because 7x7=49
Ellen is playing a video game in wich she captures butterflies/ There are 3 butterflies onscreen, but the number of butterflies doubles every minute. After 4 minutes, she was able to capture 7 of the butterflies.
Write an expression for the number of butterflies after 4 minutes. Use a power of 2 in your answer
The expression for the number of butterflies after 4 minutes 3([tex]2^4[/tex]) - 7.
What is Sequence?A grouping of numbers in a specific order is known as a sequence. On the other hand, a series is described as the accumulation of a sequence's constituent parts.
An ordered list of numbers is a sequence. The three dots indicate that the established pattern should move forward.
Given:
Initially we have 3 butterflies
After one minute = 3(2)
= 6 butterflies
After two minutes = 3(2)(2)
= 3(2²) butterflies
After three minutes = 3(2³) butterflies
After four minutes = 3([tex]2^4[/tex]) butterflies
as, she captured 7 butterflies
Then, after 4 min the number of butterflies on screen
= 3([tex]2^4[/tex]) - 7
= 3(16) - 7
= 48-7
= 41
Learn more about sequence here:
https://brainly.com/question/30262438
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