May I have help on This question I’ll give you brainliest

m_train = train_set_x_orig.shape[0], m_test = test_set_x_orig.shape[0], num_px = train_set_x_orig.shape[1] can be used to obtain the values for m_train, m_test, and num_px respectively.

The information provided is related to a machine learning problem where a dataset is split into two parts: training set and test set. The training set is used to train a machine learning model, while the test set is used to evaluate the performance of the model.

The training set is represented as a numpy array named "train_set_x_orig" with shape (m_train, num_px, num_px, 3). The first dimension of the array, m_train, represents the number of training examples. The next two dimensions, num_px, represent the height and width of each training image, and the last dimension, 3, represents the RGB color channels of each pixel in the image.

To access the value of m_train, the following code can be used: m_train = train_set_x_orig.shape[0]

Similarly, the values for m_test and num_px can be obtained by accessing the corresponding test set arrays using the numpy array method "shape".

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The complete question is:

Find the values for: - m_train (number of training examples) - m_test (number of test examples) - num_px (= height = width of a training image) Remember that train_set_x_orig is a numpy-array of shape (m_train, num_px, num_px, 3). For example, you can get to m_train by writing train_set_x_orig.shape[0].

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[tex]\cfrac{12^2}{48^2}=\cfrac{A}{960}\implies \implies \cfrac{144}{2304}=\cfrac{A}{960}\implies \cfrac{1}{16}=\cfrac{A}{960} \\\\\\ 960=16A\implies \cfrac{960}{16}=A\implies \boxed{60=A}[/tex]

The required measure of the angle ∠MON is given as 87°.

Orientation of the one line with respect to the horizontal or other respective line is known as a measure of orientation and this measure is known as the angle.

Here,
For the given circle, the measure of arc MN is given in the form of an angle of 87° which consists of an angle MNO, so the measure of the section is equal to MON i.e.
∠MON = 87°

Thus, the required measure of the angle ∠MON is given as 87°.

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Option D is the counterexample of this given statement.

Supplementary angles are those angles that sum up to 180 degrees. For example, angle 110° and angle 70° are supplementary angles because the sum of 110° and 70° is equal to 180°.

Given a statement, If two angles are supplementary, then one of the angles must be obtuse.

In A, ∠BMC is an obtuse angle.

In B, ∠AMB is an obtuse angle

In C, ∠AMB is an obtuse angle.

But in D, there are two right angles. { two right angles are supplementary. }

Therefore, Option D is the counterexample of this given statement.

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If the rate is tripled and the time increases by 3 hours, the value of d will increase by a factor of 12.

The length along a line or line segment between two points on the line or line segment.

Distance=√(x₂-x₁)²+(y₂-y₁)²

The original distance, d(r,t), can be expressed as d(r,t) = rt.

Value of d if the rate is tripled and the time increases by 3 hours

The new distance, d(3r,t + 3), can be expressed as d(3r,t + 3) = 3r(t + 3).

The new distance d(3r,t + 3) = 3r(t + 3)

= 3rt + 3(3r)

= 3rt +9r

= 3d(r,t) + 9r

Therefore, if the rate is tripled and the time increases by 3 hours, the value of d will increase by a factor of 3 + 9 = 12.

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There are 120 different shirts you can make from different combinations of sleeves, colors, and sizes.

To find the number of different shirts that can be made, use the fundamental counting principle wherein we multiply the number of options for each characteristic:

Long sleeves or short sleeves: 2 options

Three different colors: 3 options

Five different designs: 5 options

Four different sizes: 4 options

2 x 3 x 5 x 4 = 120

Therefore, the total number of different shirts that can be made is 120.

This calculation assumes that all of the characteristics are independent and can be combined in any way, which means that each shirt can have a unique combination of long/short sleeves, color, design, and size.

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Answer:

Let's call the number of $5 child tickets sold "x".

According to the problem, the number of $adult tickets was 14 less than twice the number of child tickets, so the number of $adult tickets sold can be represented as 2x - 14.

The total revenue from ticket sales was $728, so we can set up an equation:

5x + 20(2x - 14) = 728

Expanding the second term on the left side of the equation:

5x + 40x - 280 = 728

Combining like terms:

45x = 1008

Dividing both sides of the equation by 45:

x = 22.4

So the number of child tickets sold was 22 and the number of adult tickets sold was 2 * 22 - 14 = 36.

The option C.(1, -1) is correct. The solution for the system of equations y = -3x + 2 and y = 4x - 5 is x = 1 and y = -1.

We shall write the equations as:

y = -3x + 2...(1)

y = 4x - 5...(2)

to get the value of x, we evaluate as follows:

4x - 5 = -3x + 2

4x + 3x = 5 + 2 {collect like terms}

7x = 7

x = 7/7 {divide through by 7}

x = 1

put the value 1 for x in equation (1) we have;

y = -3(1) + 2

y = -3 + 2

y = -1.

Therefore, the solution for the system of equations y = -3x + 2 and y = 4x - 5 is x = 1 and y = -1.

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The total area of the garden is given as follows:

52 ft².

The area of a rectangle of length l and width w is given by the multiplication of these dimensions, as follows:

A = lw.

For the new rectangle, the dimensions are given as follows:

Hence the area of the new part is of:

A = 4 x 8

A = 32 ft².

Considering the previous part of 20 ft², the total area is given as follows:

32 + 20 = 52 ft².

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The macrostate s of two six-sided dice can be defined as the sum of the top faces of the dice.

The macrostate of a system refers to a comprehensive description of the system in terms of its properties and variables that are used to characterize it. In the case of two six-sided dice, the macrostate is described by the sum of the numbers on the top faces of the two dice, which determines the total score or outcome. This macrostate, represented by the variable "s", is a measurable quantity that summarizes the state of the system, providing information about the distribution of the outcomes over all possible configurations of the two dice.

It's important to note that a macrostate does not specify the exact configuration of the system, but rather provides a probabilistic description of it. In other words, the macrostate "s" only describes the sum of the two dice and does not specify which number is on each die. In thermodynamics, macrostates are used to characterize the thermodynamic properties of a system, such as its temperature, pressure, and entropy. The study of macrostates and their distributions helps us to understand the behavior of complex systems and make predictions about their future behavior.

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Answer:

x = -3

Step-by-step explanation:

-3x - 8 = 1

-3x = 9

3x = -9

x = -9/3

x = -3

From the given rates, the unit rates are as follows 9/1 and 10:1. That is option D and E.

A unit rate of a measurement of the distance of a traveling vehicle or of a moving object is the rate for per one of the value of interest.

A unit rate can only be two figures that shows the relationship that exists between them and a whole value.

Therefore the given rates that shows unit rate are 9/1 and 10:1

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The forecasts for September sales volume using a linear trend equation, a five-month moving average, exponential smoothing with a smoothing constant of 0.40, the naive approach, and a weighted average are 17.86, 18.60, 18.72, 21.00, and 19.60 thousands, respectively.

1. A linear trend equation:

This is a method of extrapolating future values from existing data by fitting a linear line to the data points by calculating the slope and y-intercept of the line. To calculate the trend equation, we use the formula Yt = mXt + b, where Yt is the forecasted value, m is the slope of the line, Xt is the independent variable, and b is the intercept. We can calculate m and b by using the formula m = (n∑XY - (∑X)(∑Y)) / (n∑X2 - (∑X)2) and b = (∑Y - m(∑X)) / n. To calculate the forecast for September, we substitute the September value with the 7th month value and solve the equation. Y7 = mX7 + b. Therefore, the forecast for September is 17.86 thousands.

2. A five-month moving average:

This is a method of smoothing data points by taking the average of the preceding five data points and using this average value as the forecast. To calculate the five-month moving average, we use the formula Yt = (Yt-1 + Yt-2 + Yt-3 + Yt-4 + Yt-5) / 5. Therefore, the forecast for September is 18.60 thousands.

3. Exponential smoothing with a smoothing constant equal to .40, assuming a March forecast of 19(000):

This is a method of forecasting future values by using a weighted average of the past data points and the previous forecast. To calculate the forecast, we use the formula Yt = αYt-1 + (1-α)Ft-1, where Yt is the forecasted value, α is the smoothing constant, Yt-1 is the previous data point, and Ft-1 is the previous forecast. Therefore, the forecast for September is 18.72 thousands.

4. The naive approach:

This is a method of forecasting future values by simply taking the most recent data point as the forecast. Therefore, the forecast for September is 21.00 thousands.

5. A weighted average using .50 for August, .20 for July, and .30 for June:

This is a method of forecasting future values by taking a weighted average of the past data points. To calculate the forecast, we use the formula Yt = (0.5Yt-1 + 0.2Yt-2 + 0.3Yt-3) / (0.5 + 0.2 + 0.3). Therefore, the forecast for September is 19.60 thousands.

The forecasts for September sales volume using a linear trend equation, a five-month moving average, exponential smoothing with a smoothing constant of 0.40, the naive approach, and a weighted average are 17.86, 18.60, 18.72, 21.00, and 19.60 thousands, respectively.

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The tables represents a relation that is a function will be table number 3. Then the correct option is C.

A function is an assertion, concept, or principle that establishes an association between two variables. Functions may be found throughout mathematics and are essential for the development of significant links.

The number of value of the variable 'y' mush be one for a given value of 'x'. Then the relation will be a function.

If the number of value of the variable 'y' is 2 or more than two. Then the relation will not be a function.

Let's check the third option. Then we have

    x                y

   −3              0

   −1               3

    0               4

    3               0

    4               3

The tables represents a relation that is a function will be table number 3. Then the correct option is C.

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B. No, the reduced row echelon form of the augmented matrix is which is an inconsistent system. In this case, the vector u is [0 26 8] and the matrix A is [5 -3 1; -3 7 1].

To check if u is in the plane spanned by the columns of A, we can form the augmented matrix by appending u to A, and attempt to reduce it to the reduced row echelon form.

If the resulting augmented matrix is an inconsistent system (i.e. the last row has a non-zero coefficient in the last column and a zero in the right-hand side), then u cannot be written as a linear combination of the columns of A, and thus it is not in the plane spanned by the columns of A.

In this case, the reduced row echelon form of the augmented matrix is an inconsistent system, which means that u cannot be written as a linear combination of the columns of A, and thus it is not in the plane spanned by the columns of A.

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The probability of rolling 1 (R), 1 (G), 1 (B) is 1/216, odd (R), even (G), any number (B) is 1/36, 6 or 5 (R), 4 or 3 (G), 1, 2 or 3 (B) is 1/18, no fives at all is 125/216, and a different number on each dice is 1/6.

a. The probability of rolling 1 (R), 1 (G), 1 (B) is 1/216. This is because there are 6 faces on each die, and 6 x 6 x 6 = 216 total possible outcomes. Since there is only one way to roll the dice and get 1 (R), 1 (G), 1 (B), the probability of this outcome is 1/216.

b. The probability of rolling odd (R), even (G), any number (B) is (3/6) x (3/6) x (1/6) = 1/36. This is because there are 3 odd numbers on the red die, 3 even numbers on the green die, and 6 numbers on the blue die, thus making the total number of outcomes (3/6) x (3/6) x (6/6) = 1/36.

c. The probability of rolling 6 or 5 (R), 4 or 3 (G), 1, 2 or 3 (B) is (2/6) x (2/6) x (3/6) = 1/18. This is because there are 2 faces with a 6 or 5 on the red die, 2 faces with a 4 or 3 on the green die, and 3 faces with a 1, 2, or 3 on the blue die, thus making the total number of outcomes (2/6) x (2/6) x (3/6) = 1/18.

d. The probability of rolling no fives at all is (5/6) x (5/6) x (5/6) = 125/216. This is because there are 5 faces on each die that do not have a 5, thus making the total number of outcomes (5/6) x (5/6) x (5/6) = 125/216.

e. The probability of rolling a different number on each dice is (6/6) x (5/6) x (4/6) = 1/6. This is because there are 6 different numbers on the red die, 5 different numbers on the green die, and 4 different numbers on the blue die, thus making the total number of outcomes (6/6) x (5/6) x (4/6) = 1/6.

In conclusion, the probability of rolling 1 (R), 1 (G), 1 (B) is 1/216, odd (R), even (G), any number (B) is 1/36, 6 or 5 (R), 4 or 3 (G), 1, 2 or 3 (B) is 1/18, no fives at all is 125/216, and a different number on each dice is 1/6.

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The correct statement is: C. You may use the t procedure, provided your sample size is large, say at least fifty.

A t-test is a statistical test used to determine whether two sets of data are significantly different from one another. When the population standard deviation is unknown and the sample size is small, a t-test is usually used. The normality assumption is not crucial for the validity of a t-test, as long as the sample size is large enough (typically over 30). However, the more the sample deviates from normality, the more likely it is that the t-test will produce incorrect results. To deal with non-normal data, the t-test is robust, meaning it is not highly sensitive to deviations from normality, when the sample size is large enough.

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The claim that if x is even then 9x - 5 is odd is false for all x < 0, as demonstrated by an example where x = -2 and 9x - 5 = -17, which is an even number.

The smallest counterexample method is used to prove that a claim is false by providing an example that does not follow the claim. To prove the claim that if x is even then 9x 5 is odd, for all x < 0, we can use the smallest counterexample method by finding the smallest value of x that would disprove the claim.

Let x = -2, then 9(-2) - 5 = -17. Since -17 is even, it does not follow the claim that if x is even then 9x - 5 is odd, thus disproving the claim for all x < 0.

To explain this with formula and calculation, let x = -2, then 9x - 5 = 9(-2) - 5 = -17. Since -17 is even, the claim that if x is even then 9x - 5 is odd is false. Therefore, the claim is false for all x < 0.

The claim that if x is even then 9x - 5 is odd is false for all x < 0, as demonstrated by an example where x = -2 and 9x - 5 = -17, which is an even number.

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Answer: 77

Step-by-step explanation:

The algebraic expression that Danielle should write is 2x - 4

From the question, we have the following parameters that can be used in our computation:

4 less than twice a number

Represent the number with x

So, we have the following representation

4 less than twice x

Twice x means 2x

So, we have

4 less than 2x

Less than here means minut

So, we have the following representation

2x - 4

Hence, the expression is 2x - 4

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The area of the given figure is 43.3 units².

A trapezium is a quadrilateral with four sides where two sides are parallel to each other.

We have,

The figure has two shapes:

Trapezium and a semicircle.

Now,

We will consider one box as one unit.

Trapezium:

Height = 6 units

Parallel sides = 8 units and 5 units

Area = 1/2 x height x (sum of the parallel sides)

Area = 1/2 x 6 x (8 + 5)

Area = 3 x 13

Area = 39 units²

Semicircle:

Diamter = 6 units

Radius = 3 units

Area = 1/2 x πr²

Area = 1/2 x 3.14 x 3²

Area = 4.3 units²

Now,

Area of the figure.

= 39 + 4.3

= 43.3 units²

Thus,

The area is 43.3 units².

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Answer: The angle of elevation that Peter should set the camera to is 35.3°, rounded to the nearest degree (35°).

Step-by-step explanation:  To find the angle of elevation, we can use the tangent function. Let's call the angle of elevation "x". Then:

tan(x) = 66/135

We can find the value of x using the inverse tangent (arctan) function:

x = arctan(66/135)

Finally, we can convert the result from radians to degrees:

x = arctan(66/135) * 180/π

x = 35.3° (rounded to nearest degree)

The order of the matrix is

The order of a matrix is the number of rows and columns it has.

It is represented as "m x n",

where

m is the number of rows and

n is the number of columns.

For example, a matrix with 3 rows and 4 columns has an order of 3 x 4.

In the problem, the matrix has 5 rows and 3 columns and hence the order is 5 x 3

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Truth tables are utilized to decide redundancies by assessing reality an incentive for every single imaginable mix. Both [(p ^ q) - > r] <-> [p - > (q - > r)] and [(p ∧ q) ^ (~q)] - > p were viewed as repetitions.

a. We should assemble reality table for [(p ^ q) - > r] <-> [p - > (q - > r)].

p | q | r | (p ^ q) - > r | p - > (q - > r) | [(p ^ q) - > r] <-> [p - > (q - > r)]

T | T | T | T | T | T, T | T | F | F | F | F, T | F | T | T | T | T, T | F | F | T | T | T,

F | T | T | T | T | T, F | T | F | T | T | T, F | F | T | T | T | T, F | F | F | T | T | T

Since every one of the qualities in the last segment are "T", the assertion [(p ^ q) - > r] <-> [p - > (q - > r)] is a redundancy.

b. We should construct reality table for [(p ∧ q) ^ (~q)] - > p.

p | q | ~q | (p ∧ q) ^ (~q) | [(p ∧ q) ^ (~q)] - > p

T | T | F | F | T, T | F | T | T | T, F | T | F | F | T, F | F | T | F | T

Since every one of the qualities in the last section are "T", the assertion [(p ∧ q) ^ (~q)] - > p is a repetition.

A repetition is a coherent explanation that is in every case valid, no matter what reality values doled out to its singular parts. To decide whether an assertion is a repetition, we can utilize a reality table which records generally potential blends of truth values for the parts and assesses reality worth of the whole assertion. In the event that reality worth of the assertion is generally "Valid" for every conceivable mix, then, at that point, the assertion is a redundancy. In the models given, the two explanations [(p ^ q) - > r] <-> [p - > (q - > r)] and [(p ∧ q) ^ (~q)] - > p were viewed as repetitions through truth tables.

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The length of EH is determined as 10.72.

The length of EH can be determined if the length of the each side is properly identified as shown below.

In the given figure, H is the circumcenter of triangle BCD,

Triangle BHD is isosceles, therefore BH = HD

Point E is midpoint of BC, therefore BE = ¹/₂ of BC

Using Pythagorean, calculated the value of EH as follows;

EH = √ (BH² - BE²)

EH = √ ( 14² -  ( 18 /2) ² )

EH = √ ( 196 - 81 )

EH = √115 = 10.72

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The side length of BE is 40 units

From the question, we have the following parameters that can be used in our computation:

H is the circumcenter.

BD= 80 and HB=50

Using the above as a guide, we have the following:

BE = 1/2 * BD

Substitute the known values in the above equation, so, we have the following representation

BE = 1/2 * 80

Evaluate

BE = 40 units

Hence, the side length of BE is 40 units

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The area of the composite figure is  54 inches².

The perimeter of the figure is 35 inches.

A composite figures is a figure with 2 or more 2 dimensional figures. The composite figure can be divided into three shapes.

Let's find the area of the composite figure as follows:]

area of the composite figure = area of the trapezium + area of the square + area of the rectangle

area of the trapezium  = 1 / 2 (a + b)h

area of the trapezium  = 1 / 2 (5 + 8)4

area of the trapezium  = 1 / 2 × 4 × 13

area of the trapezium  = 52 / 2

area of the trapezium  = 26 inches²

Therefore,

area of the square = 4² = 16 inches²

area of the rectangle = 4 × 3 = 12 inches²

Therefore,

area of the composite figure = 12 + 16 + 26

area of the composite figure = 54 inches²

Let's find the perimeter of the composite figure as follows:

perimeter of the composite figure = 12 + 7 + 4 + 3 + 5 + 4

perimeter of the composite figure = 35 inches

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If Auberon swim 52 meters in five minutes then at this rate the number of meters would he swim in 10 minutes & 12 minutes are respectively,

104 meters & 124.8 meters

The distance covered by the object is equal to the product of the speed at which the object is moving and time taken for covering the distance.

Distance = Time × Speed

Since Auberon swim 52 meters in 5 minutes,

you can find his average rate of swimming by dividing the distance by the time:

Rate = 52 meters / 5 minutes

        = 10.4 meters per minute

To find the distance he would swim in 10 minutes, you can multiply his average rate by the time:

Distance in 10 minutes = 10.4 meters per minute x 10 minutes

                                      = 104 meters

To find the distance he would swim in 12 minutes, you can multiply his average rate by the time:

Distance in 12 minutes = 10.4 meters per minute x 12 minutes

                                      = 124.8 meters

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The probability that "Relaxation Through Mathematics" is first to review is 1/k, and the probability that "Relaxation Through Mathematics" and "The Joy of Calculus" are next to each other in the stack is (1/k)*(1/(k-1)).

A) The probability that "Relaxation Through Mathematics" is first to review is 1/k. This is because there are k documents to review, and the order in which they are reviewed is random with each ordering being equally likely. Therefore, the probability that any given document is chosen first is 1/k.

B) The probability that "Relaxation Through Mathematics" and "The Joy of Calculus" are next to each other in the stack is (1/k)*(1/(k-1)). This is because there are k documents to review, and the probability that the first document is "Relaxation Through Mathematics" is 1/k. Then, since there are k-1 documents remaining in the stack, the probability that the second document is "The Joy of Calculus" is 1/(k-1). Therefore, the probability that both documents are next to each other is (1/k)*(1/(k-1)).

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Answer:

[tex]\displaystyle P(x)=-\frac{1}{10}(x-3)^2(x+2)[/tex]

Step-by-step explanation:

Multiplicity is basically how much of a factor of a polynomial appears. In this case, if we disregard the y-intercept, we can show a multiplicity of 2 at x = 3 and a multiplicity of 1 at x=-2 with [tex]y=(x-3)^2(x+2)[/tex].

Of course, there will need to be a scale factor for the function so that the y-intercept will be at y = -1.8, so we can solve the following:

[tex]-1.8=a(0-3)^2(0+2)\\-1.8=a(3)^2(2)\\-1.8=a(9)(2)\\-1.8=18a\\-0.1=a[/tex]

Thus, we can write the function as [tex]\displaystyle P(x)=-\frac{1}{10}(x-3)^2(x+2)[/tex]. See below for a visual.

The error to 3 decimal place is 0.036

The percentage error is solved to be 1.61%

The error is calculated using the formula

= Approximate value – Exact Value

where

the approximate value = 2.2

Exact value from the table = 2.236

error = 2.2 - 2.236

error= -0.036

The percentage error

=(Approximate value – Exact Value) / Exact value * 100

= 0.036 / 2.236 * 100

= 0.0161 * 100

= 1.61%

The percentage error is 1.61%

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