maths midpoint theorem
please help

Answer:

Angle 1: 28 degrees

Angle 2: 52 degrees

Angle 3: 52 degrees

Angle 4: 28degrees

Angle 5: 28degrees

Angle 6 : 52degrees

Angle 7 : 52degrees

Angle 8 : 28degrees

To two decimal places ✓70 just be between 8.36 and 8.37.

It should be noted that we simply have to calculate the information is to find the square root of 70.

Therefore, this is approximately 8.366

Therefore, to two decimal places ✓70 just be between 8.36 and 8.37.

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[tex]\stackrel{\textit{lbs of candy}}{\cfrac{1}{3}}\div \stackrel{people}{5}\implies \cfrac{1}{3}\div\cfrac{5}{1}\implies \cfrac{1}{3}\cdot \cfrac{1}{5}\implies \stackrel{\textit{lbs of candy}}{\cfrac{1}{15}}[/tex]

The domain of the function g ( x ) = √ x − 3 / x − 11 is R - 11.

Inputs are assigned outputs by functions. The collection of all potential inputs for a function is its domain. For instance, the domain of f(x)=x2 and g(x)=1/x are all real integers with the exception of x=0.

Consider the function y = f(x), which has the independent variable x and the dependent variable y. A value for x is said to be in the domain of a function f if it successfully allows the production of a single value y using another value for x.

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She will spend 5 dollars extra if she only buys packs of 3 tickets.

A numerical expression is written in form of numbers and their operations.

According to the given question we can buy 15 tickets in two ways either buying 5 packs which contain 3 tickets and cost 6.25 dollars each pack or we can buy 3 packs which contain 5 tickets which costs 8.75 dollars.

For the first case if we buy 5 packs of tickets that contain 3 tickets it will cost (5×6.25) dollars = 31.25 dollars.

In the second case buying 3 packs of tickets that contain 5 tickets that will cost us (3×8.75) = 26.25 dollars.

∴ She will spend (31.25 - 26.25) = 5 dollars she will spend extra if she only buys packs of 3 tickets.

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The elements of (A∪B∪C) = {1, 4, 5, 6, 7, 8, 9, 11, 12, 13, 14, 15, 16, 17, 18, 19}

The elements of (A∩B∩C) = DNE

From the question, we are to list the elements of the given sets

From the given information,

Set A = {7, 9, 12, 13, 14}

Set B = {1, 4, 5, 7, 16, 18, 19}

Set C = {4, 6, 8, 9, 11, 13, 15, 16, 17, 19}

We are to list the elements of (A∪B∪C)

(A∪B∪C) = {1, 4, 5, 6, 7, 8, 9, 11, 12, 13, 14, 15, 16, 17, 18, 19}

Also, we are to list the elements of (A∩B∩C)

(A∩B∩C) = { } OR ∅

Since this is an empty set

(A∩B∩C) = DNE

Hence,

The elements of (A∪B∪C) = {1, 4, 5, 6, 7, 8, 9, 11, 12, 13, 14, 15, 16, 17, 18, 19}

The elements of (A∩B∩C) = DNE

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Answer:

Your answer is correct

Step-by-step explanation:

Use the rules of exponents to simplify the expression.

To raise a power to another power, multiply the exponents.

Multiply 6 by 2.

The correct option is the third.

Answer:

10°C

Step-by-step explanation:

F = 50

C = 5/9 * (F - 32) = 5/9 * (50 - 32) = 5/9 * 18 = 5 * 2 = 10

The value of x is 1 and -8.

To solve this problem we need to understand the concept of quadratic equation.

To solve Quadratic equation we need to understand the concept of equation which says the factor of the product of coefficient of [tex]x^{2}[/tex] and constant must on adding or substracting give the coefficient of x.

Here the equation is [tex]x^{2} +7x-8=0[/tex]

The product of coefficient  is 8. The factors of 8 is 8 and 1 which gives 7 on substracting.

Now,

[tex]x^{2} +8x-x-8=0[/tex]

⇒[tex]x(x+8)-1(x+8)=0\\[/tex]

⇒[tex](x-1)(x+8)=0[/tex]

∴ x=1,-8.

So, the required values of x is 1 and -8.

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Using z-scores, it is found that a scale of 40 on the first scale is equivalent to a score of 55 in the new standardized scale.

The z-score of a measure X of a distribution with mean represented by [tex]\mu[/tex] and standard deviation represented by [tex]\sigma[/tex] is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

For the first scale, the parameters are given as follows:

[tex]X = 40, \mu = 37, \sigma = 6[/tex]

Hence the z-score is:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

Z = (40 - 37)/6

Z = 0.5.

For the second scale, we want to find X when Z = 0.5, considering the following mean and standard deviation:

[tex]\mu = 50, \sigma = 10[/tex]

Hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

0.5 = (X - 50)/10

X - 50 = 5

X = 55.

A scale of 40 on the first scale is equivalent to a score of 55 in the new standardized scale.

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Answer:  380.5

Step-by-step explanation: you can type it into desmos graphing calculator

The width of the rectangle = 10 ft

The length of the rectangle = 15 ft.

The formula for the perimeter of a rectangle is given as:

Perimeter = 2(length + width).

Let x represent the width of the rectangle

Width of the rectangle = x

Length of the rectangle = x + 5

Perimeter of the rectangle = 50 ft

Thus, we would have the following equation:

2(x + 5 + x) = 50

2(2x + 5) = 50

4x + 10 = 50

4x = 50 - 10

4x = 40

4x/4 = 40/4

x = 10

Width of the rectangle = x = 10 ft

Length of the rectangle = x + 5 = 10 + 5 = 15 ft.

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The interval notation is { 5/ 2 < x > 0 }

Given the inequalities;

To determine the value of x, we have;

2x - 1 < 4

collect like terms

2x < 4 + 1

2x < 5

Make 'x' the subject

x < 5/ 2

−5x −3 > −3

collect like terms

-5x > -3 + 3

-5x > 0

x > 0

Thus, the interval notation is { 5/ 2 < x > 0 }

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Answer:

the area of the rectangle is A=L•W

The length is 3m less than twice its width W: L+ 3m=2W...->, L=2W-3m

A=L-W

27m²=(2W-3m)-W

27m2=2w2-3m-W

2w2-3wm-27m2=0

....use quadratic formula -(-3m)+ (-3m)²-4-2-(-27m²)

W=

2-2

w=(3m± √9m²+216m²)

w=(3m+ √225m²)

W=(3m± 15m...you need only positive root because width cannot be negative

W= 3m+15m

4

W=. 4

18m

W=4.5m ......now find the L

L=2.4.5m-3m

L=9m-3m

L=6m

Answer:

W = 4.5cm

L = 6cm

Step-by-step explanation:

Answer:

The answer to the question is the third answer

The number multiplied by 7/9 to get a product of one will be 9/7.

It is defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has basic four operators that are +, -, ×, and ÷.

Suppose the number when multiplied by 7/9 as a product of one be x,

When the product of two numbers is 1, they are termed multiplicative inverses. To make the expressions simpler, use the multiplicative inverse. When we solve division problems, the multiplicative inverse is one application. When dividing two numbers, the dividend is multiplied by the reciprocal of the divisor.

x × 7/9 = 1

x=9/7

Thus, the number multiplied by 7/9 to get a product of one will be 9/7.

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Answer: P= 2 6/7

Step-by-step explanation:

a baby blue whale weigh= 2000 kg

Simple equation :

A linear equation that involves only one variable is known as a simple equation or a linear equation in one variable. For example, \(3x + 2 = 23,x = 7,2x + 6 = 3x – 4,\)etc., are simple equations.Let us assume a situation, in which you go to the market to buy mangoes in a supermarket. Your mother gave you Rs.100 and said that you can keep Rs.40 for buying chocolates and for the remaining amount, you need to buy mangoes. When you went to the market, you found out that the price of one kg of mangoes was Rs.12. So, the final question is how many mangoes you should buy, so that everyone is satisfied. Recall the concept of simple equations from previous classes and proceed. Let us assume that you have to purchase kg of mangoes, so the total amount of money that you will be spent on buying mangoes will be Rs.12x. Now, you have Rs.40 for yourself, so you have an equation:

12 x + 40 = 100

12x = 100 – 40

12x = 60

x = 60/12 = 5, This is the same equation as above. Now when you will solve this, you will get to know the value of 5kg of mangoes. It means that you can buy 5 kg mangoes and spend Rs.40 on buying chocolates

weigh: to measure how heavy something is, especially by using a machine (scales)

given :

A baby American bison weighs=20kg

The solution according to Question  =

Let the weight of baby blue whale = b

the baby blue whale weighs =100(a baby American bison)

b=100(20)

b=2000 weigh

a baby blue whale weigh= 2000 kg

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The number is 280

In mathematics, Least Common Multiple is referred to by its entire name, whereas Highest Common Factor is its complete name. The L.C.M. defines the least number that is exactly divisible by two or more numbers, whereas the H.C.F. describes the biggest factor existing between any given pair of two or more numbers. LCM is also known as the Least Common Multiple (LCM), and HCF is also known as the Greatest Common Factor (GCF).

Two key techniques—the division method and the prime factorization approach—can be used to determine H.C.F. and L.C.M.

So we need to find the LCM of 2,5 and 7. Furthermore, we need to find multiply the LCM with a number which can make its sum of digits equal to 10.

LCM of 2,5 and 7 is 70

70 x 4 = 280

Sum of digits of 280 is 10, which is also less than 500

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Answer:

$243 is his profit

Step-by-step explanation:

Answer: $4100

Step-by-step explanation:

discount = [tex]\frac{1800}{90}[/tex]×100 = 2000

profit = [tex]\frac{115}{100}[/tex]×2000 = 2300

market price = 2300 + 1800 = 4100

Answer:

A)50°F = 10°C

B)75°C = 167°F

C)-40°C = -40°F

Step-by-step explanation:

A) 50°F = 10°C

Formula

(50°F − 32) × 5/9 = 10°C

B) 75°C = 167°F

Formula

(75°C × 9/5) + 32 = 167°F

C) -40°C = -40°F

Formula

(-40°C × 9/5) + 32 = -40°F

Answer:

4x-3y=21.

Step-by-step explanation:

1) the common view of slope-interception form is y=slope*x+interception;

2) if according to the condition the slope=4/3, then the required equation is

[tex]y=\frac{4}{3}x +interception;[/tex]

3) in order to calculate the interception it is enough to substitute the given coordinates into this equation:

[tex]1=6*\frac{4}{3} +interception; \ = > \ interception=-7;[/tex]

4) the slope interception form of the required equation is:

[tex]y=\frac{4}{3}x-7;[/tex]

5) if to re-write the equation in slope-interception form into the required, then (A=4; B=-3; C=21):

4x-3y=21.

37.375 kg of peanuts must be added to the 4 kg of mixed nuts to make a mixture containing 92 % of peanuts.

Total mixture of mixed nuts = 4 kg

60 % of them are peanuts.

So, we will calculate the percentage:

Let x be the amount of peanuts.

60 / 100 x = 4 kg

0.6 x = 4 kg

x = 4 kg / 0.6

x = 6.67 kg

Now let the peanuts added be y

So, 92 % of ( 4 kg + y )  should be peanuts.

So, we get the equation as:

0.92 ( 4 ) + 0.92 y = 6.67 + y

3.68 + 0.92 y = 6.67 + y

0.08 y = 2.99

y = 37.375 kg

Therefore, 37.375 kg of peanuts must be added to the 4 kg of mixed nuts to make a mixture containing 92 % of peanuts.

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a = amount invested at 4%.

b = amount invested at 7%.

we know that whatever "a" and "b" may be, they total 27000, so we can say that a + b = 27000, likewise we can say that b = 27000 - a.

how much will it be for 4% of "a"? well, that's just (4/100) * a, or 0.04a.

how much will it be for 7% of "b"? well, that's just (7/100) * a, or 0.07b.

we also know that the earned interest by those two interest amounts is 1440, so

[tex]\begin{cases} a + b = 27000\\ b = 27000 - a \end{cases}\hspace{5em}0.04a~~ + ~~0.07b~~ = ~~1440 \\\\\\ \stackrel{\textit{substituting "b"}}{0.04a~~ + ~~0.07(27000-a)~~ = ~~1440}\implies 0.04a+1890-0.07a=1440 \\\\\\ 1890-0.03a=1440\implies -0.03a=-450\implies a=\cfrac{-450}{-0.03} \\\\\\ 15000=\textit{\LARGE a}\hspace{15em}\stackrel{27000~~ - ~~15000}{\textit{\LARGE b}=12000}[/tex]

Using relations in a right triangle, the secant of angle θ is given by:

D. 5/4.

The relations in a right triangle are given as follows:

Using the Pythagorean Theorem, the hypotenuse of the triangle is given as follows:

h² = 9² + 12²

h = sqrt(9² + 12²)

h = 15.

The secant of an angle is 1 divided by the cosine, hence:

Which means that option D is correct.

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Step-by-step explanation:

you mean the slope of the line between (8, 9) and (23, 9).

we can see that right away, as the y value does not change. it means it is a flat line, and that means the slope is 0.

now, formally :

the slope of a line is (y coordinate change / x coordinate change) when going from one point on the line to another.

the direction does not matter, but once we pick one for the comparison of one coordinate, we have to use the same direction also for the other.

I prefer to go from left to right.

so, from (8, 9) to (23, 9).

x changes by +15 (from 8 to 23).

y changes by 0 (from 9 to 9).

the slope is therefore 0/+15 = 0.

Step-by-step explanation:

[tex] = ( \frac{3}{5} {)}^{2} [/tex]

[tex] = \frac{ {3}^{2} = 3 × 3 }{ {5}^{2} = 5 × 5 } \\ [/tex]

[tex] = \frac{9}{25} \\ [/tex]

☘️☘️☘️...

Answer:

[tex] \frac{9}{25} [/tex]

Step-by-step explanation:

[tex] { ( \frac{3}{5} )}^{2} \\ = ( \frac{ {3}^{2} }{ {5}^{2} } ) \\ = \frac{9}{25} [/tex]

Disclaimer: The conversion graph is missing in the question.

60 gallons is equal to 227.125 litres.

Refer to the attached image for the conversion of litres to gallons.

And gallons to litres.

In this image, a vertical line is drawn from the given value of gallon until it meets the cross line. And then a horizontal line is drawn, which touches the litres line.

At the point at which this horizontal line touches the litres line, that value is considered as the corresponding litres for the given gallons.

Similarly, a vertical line is drawn from the litres line until it meets the cross line. And then a vertical line is drawn, which touches the gallons line.

At the point at which this vertical line touches the gallons line, that value is considered as the corresponding gallons for the given litres.

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1. Recording the events under an accounting equation is as follows:

                      Assets      =  Liabilities +  Equity

             Cash  +   Supplies              Common Stock + Revenue - Expenses    

1.          $26,500                                                             $26,500

2.                           $7,200   $7,200

3.                            (5,690)                                                                  ($5,690)

Balance $26,500  $1,510   $7,200                             $26,500   -     $5,690

2. The preparation of the income statement, balance sheet, and statement of cash flows for the Year 1 accounting period is as follows:

Yard Professionals

For the Year 1 accounting period

Revenue                 $26,500

Supplies Expense     (5,690)

Net income             $20,810

Yard Professionals

Year 1 accounting period

Cash                               $26,500

Supplies                             $1,510

Total assets                    $28,010

Accounts Payable           $7,200

Equity: Net income          20,810

Total liabilities + equity $28,010

Yard Professionals

For the Year 1 accounting period

Net income               $20,810

Supplies                        (1,510)

Accounts Payable       7,200

Cash (Operations)  $26,500

3. The balance in the Supplies account as of January 1, Year 2 is $1,510.

4. The balance in the Supplies Expenses account as of January 1, Year 2 is $5,690.

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Answer:

Put S=(1,-10) R(-10,-8) T(-8,-9) Make sure to put a ´ after these letters when you put them down

Step-by-step explanation: