Kayla has a red number cube and a blue number cube. Each number cube has faces labeled 1 through 6.
What is the probability Kayla rolls an even number on the red cube and a multiple of 3 on the blue cube?

the number x, you must deduct another number from it , conditions will the response be unfavorable,

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In an expression, a positive number is subtracted from two other integers. If the value of the negative number is higher than that of the positive number, then the expression's value will be considered negative. Additionally, according to the fundamental rule of integers, the number's sign-bearer must always have a higher value.

For instance,

1. 2 - 3 = -1

2. 10 + (- 8) + (- 11) = -9

3. -6 + 3 = -3

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Answer: 139

Step-by-step explanation:

first, 4 can go into 5 once so you would put one down --> 5-5= 1

bring down the one and then put down the 5 from the tens place

4 can go into 15 three times which would be 15-12 = 3

so at the top, you would have 13 so far

then with the 3 left bring down the 6 from the hundreds place from the 556

lastly, since 4 can go into 36 nine times you would put 9 down next to 13 on the top which would make it 139

(Sorry if it doesn't make that much sense)

The base-ten numeration system is the system that utmost of the world uses moment. Place value refers to the value of each number in a number. The English language is a transnational language.

What is the base ten number system, place value?

The base-ten numeration system is the system that utmost of the world uses moment. No one knows exactly why the number ten was chosen as the base for this system, but it's theorized that it's due to the number of fritters that humans retain. Fingers are veritably fluently assessable as counting tools. The base-ten numeration system consists of ten integers( 0, 1, 2, 3, 4, 5, 6, 7, 8, 9), and groups figures into ten.

     2. Understanding Place Value -

Place value refers to the value of each number in a number. For illustration, the number 753 has three" places" or columns each with a specific value. In this three-number number, the 3 is in the" bones " place, the 5 is in the" knockouts" place, and the 7 is in the" hundreds" place.

Beginning ideas of Place Value and Base Ten:

In other words, the 3(three) represents three single units, so the value of this number is three. The 5(five) is in the knockout place, where values increase by multiples of 10(ten). So, the 5(five) is worth (5)five units of 10(ten), or 5(five) x 10(ten), which equals 50(fifty). The 7(seven) is in the hundreds(100) place, so it represents seven units of 100(hundred), or 700(seven hundred).

Problems Faced by Students in Speaking the English Language -

The English language is a transnational language. It's a demand of the moment’s world. For surviving in society, people have to understand and speak the English language easily.

In this world, you go far and wide people can speak the English language or indeed understand the English language.

The English language plays a lesser part for the people in a society. The English language is an important subject for people whose English language isn't their native language.

The base-ten numeration system is the system that utmost of the world uses moment.

Place value refers to the value of each number in a number.

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Answer: N * (n+7) = n^2 + 7n

Step-by-step explanation:

This equation would be the number, n, times n+7 because n+7 is 7 more than n. To do this, you have an equation like this:

N * (N+7). You would then do distributive property, and n*n would be n squared, and n*7 would be 7n. This would give you a combined answer of n squared + 7n, or n^2 +7n.

We use parenthesis if an interval is infinite on both boundries in order to exclude end-points .

Square brackets mean the set of all points from a to b .

If we use square brackets , it would mean we are including - infinity and + infinity , which is practically impossible .

When we , use parenthesis only the nos . lying between the two points are taken into consideration , the two points are not included .

So , we use parenthesis to exclude - infinity and + infinity .

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The solutions of the equations of the situation can be:

z = 1 , y = 5, x = 4

z= 2 , y = 3, x = 5

z=3 , y = 1, x = 6

z = 0 , y = 7, x =3

The question can be expressed as a equation

6 x + 8 y + 10 z = 84

also, x + y + z = 10

⇒ x = 10- y - z

Putting it in first equation,

6(10 - y - z ) +8y + 10z = 84

⇒ 60 +2y + 4z = 84

⇒2(y + 2z ) = 14

⇒ y + 2z = 7

Now putting

z = 1 , we get y = 5,

z= 2 , y = 3

z=3 , y = 1

z = 0 , y = 7

So, only 4 possible solutions.

Therefore, there can only be 4 possible solutions for the equations.

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The complete table of values is

x     |   f(x)

-1.4  |  -13.92

-0.7 |  -7.48

0    |  -3

0.7 |   -0.48

1.4 |  0.08

The function is given as:

f(x) = -2x^2 +5x - 3

Next, we calculate the values of the functions at the given x values

So, we have:

f(-1.4) = -2(-1.4)^2 + 5(-1.4) - 3 = -13.92

f(-0.7) = -2(-0.7)^2 + 5(-0.7) - 3 = -7.48

f(0) = -2(0)^2 + 5(0) - 3 = -3

f(0.7) = -2(0.7)^2 + 5(0.7) - 3 = -0.48

f(1.4) = -2(1.4)^2 + 5(1.4) - 3 = 0.08

Hence, the complete table of values is

x     |   f(x)

-1.4  |  -13.92

-0.7 |  -7.48

0    |  -3

0.7 |   -0.48

1.4 |  0.08

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Answer:

  6 quarts

Step-by-step explanation:

You want to know the number of quarts of 100% antifreeze to add to 6 quarts of 20% antifreeze to make a 60% solution.

Let x represent the number of quarts of 100% antifreeze added to the solution. Then the total amount of antifreeze in the mixture is ...

  20%(6) +100%(x) = 60%(6 +x)

Simplifying the equation, we have ...

  1.2 +x = 3.6 +0.6x

  0.4x = 2.4 . . . . . . . . . subtract 0.6x+1.2 from both sides

  x = 6 . . . . . . . . . . divide by 0.4

6 quarts of pure antifreeze must be added.

Answer:

4n^2 + 5n.

Step-by-step explanation:

If the number is n, then:

4n^2 + 5n.

Answer:

less than

Step-by-step explanation:

|-5| is 5 so -|-5| is negative 5 (-5)

-5 is less than 5

the domain of the following graph= [-5,10)

Domain :

The domain of a function is the set of its possible inputs, i.e., the set of input values where for which the function is defined. In the function machine metaphor, the domain is the set of objects that the machine will accept as inputs.

For example, when we use the function notation f: R→R, we mean that f is a function from the real numbers to the real numbers. In other words, the domain of f is the set of real numbers R (and its set of possible outputs or codomain is also the set of real numbers R).

To,  identify the domain and range of functions by using graphs. Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the

x-axis. The range is the set of possible output values, which are shown on the

y-axis. Keep in mind that if the graph continues beyond the portion of the graph we can see, the domain and range may be greater than the visible values.

We can observe that the horizontal extent of the graph is -5 to 10, so the domain of f is [-5,10)

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.

3(x+5) + 2(x-3) = 6(3(1/6))

3x + 15 + 2x - 6 = 3 X 1

5x + 9 = 3

5x = - 7

x = - 7/5

Answer:

48,236.7

Step-by-step explanation:

40,000 + 8,000 + 200 + 30 + 6 + 7/10

7/10 can also be written .7

If a region’s average movie theater ticket price in 2007 was $6.51. For 2017, it was estimated to be $8.57, the percent of increase in average movie theater ticket price is 16%

A region's average movie ticket price in 2007 was $6. 51

A region's average movie ticket price in 2017 was $8. 57

Increase in price = 8.57 - 6. 51 = $1.06

Percentage of increase = (increase in price / original price)*100

= (1.06/6.51)*100

16%

If a region’s average movie theater ticket price in 2007 was $6.51. For 2017, it was estimated to be $8.57, the percent of increase in average movie theater ticket price is 16%

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The correct answer is option D.

The polygon ABCD can be mapped on to WXYZ but first it must be enlarged and then it must be mirrored along BC.

The mirror image of ABCD along BC must be enlarged with a scale factor of 2 to map ABCD to WXYZ.

The scale factor is the ratio of the the object to be transformed to the object with which it is to be compared.

Here, the scale factor is 2 and we must enlarge the image of ABCD along BC to get the desired mapping.

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[tex]\huge\textsf{Hey there!}[/tex]

[tex]\mathsf{16 \dfrac{40}{50}}[/tex]

[tex]\mathsf{= \dfrac{16\times50 + 40}{50}}[/tex]

[tex]\mathsf{= \dfrac{800 + 40}{50}}[/tex]

[tex]\mathsf{= \dfrac{840}{50}}[/tex]

[tex]\mathsf{= 840\div50}[/tex]

[tex]\mathsf{= 16.8}[/tex]

[tex]\huge\textbf{Therefore, your answer should be:}[/tex]

[tex]\huge\boxed{\mathsf{16.8}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

Answer:

Step-by-step explanation:

To get your answer, you would want to use the expression -3.5/60. So your answer will be -0.058.

Answer is ADEF

Given that, two right tringle = R + ΔHEL , R +ΔPME

Hypotenuse equal , A set of corresponding right angles are equal.{HL};

LL=LE

So ∠E(M tringle HEL)∠LM (M tringle PME)

∠H=∠P 90°

∠L=∠E                        ⇒AAS

HE PM or LE =EM

∠E = ∠M

EL = ME                      ⇒ASA

∠L = ∠E

HF = PM

∠E = ∠M                       ⇒SAS

EL = ME

Hence choose A.D.E.F

{Determination of congruence of right tringle }

explanation of  Determination of congruence of right tringle

A plane figure bounded by three finite line segments to form a closed figure is known as a triangle. A right-angled triangle is a special case of the triangle. In a right-angled triangle, one of the interior angles measures 90°. Two right triangles are said to be congruent if they are of the same shape and size. In other words, two right triangles are said to be conger

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Answer: One Solution

Step-by-step explanation:

Only the number 0 can solve this equation so it may be correct.

First approaching this problem, I would try to get x on one side of the equation by subtracting 2.5x from both sides.

This leaves us with 7.5x = 0

Therefore, this equation has only one solution, 0.

Answer:

22.5

Step-by-step explanation:

∠EAB=2x (alternate interior angles)

∠AEB=180°-4x (linear pair)

Answer:

You either lose everything or gain everything (losing is more probable :) )

Step-by-step explanation:

The cost per item for maximum profit is $7.50 .

The maximum and minimum value of a function f(x) is calculated by finding the first and second derivative of f(x).

The cost to produce x pies is given by the cost function

[tex]C(x)=3x+36[/tex]

The price demand function for each pie is given by

[tex]p(x)=12-0.5x[/tex]

Revenue gained from selling x pies

[tex]R(x)=x\times p(x)\\or,R(x)=x\times(12-0.5x)\\or,R(x)=12x-0.5x^2[/tex]

Now profit function is given by

[tex]P(x)=R(x)-C(x)\\or,P(x)=-0.5x^2+12x-3x-36\\or,P(x)=-0.5x^2+9x-36[/tex]

Now we have to find the maximum profit. We know that for a function

[tex]P(x)=-0.5x^2+9x-36\\P'(x)=-x+9[/tex]

[tex]P''(x)=-1[/tex]

At P'(x)=0

or,-x+9=0

or, x=9

As P''(x)<0 therefore the profit function P(x) is maximum for x at P'(x)=0.

The profit is maximum at x=9

Price to charge per item=12-0.5x

Substituting the value of x we get:

[tex]p(x)=12-(0.5\times 9)\\or,p(x)=12-4.5\\or,p(x)=7.5[/tex]

Therefore the cost per item for maximum profit is $7.50 .

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The Lagrangian is

[tex]L(x,y,\lambda) = x^2 + y^2 - \lambda (x + y - 1)[/tex]

Find its critical points.

[tex]\dfrac{\partial L}{\partial x} = 2x - \lambda = 0 \implies x = \dfrac\lambda2[/tex]

[tex]\dfrac{\partial L}{\partial y} = 2y - \lambda = 0 \implies y = \dfrac\lambda2[/tex]

[tex]\dfrac{\partial L}{\partial\lambda} = -(x+y-1) = 0 \implies x + y = 1[/tex]

From the first two conditions, [tex]x=y[/tex], so

[tex]x + y = 2x = 1 \implies x = y = \dfrac12[/tex]

At the point (1/2, 1/2), compute the Hessian determinant of [tex]f(x,y)[/tex].

[tex]H(x,y) = \begin{bmatrix} \dfrac{\partial^2f}{\partial x^2} & \dfrac{\partial^2f}{\partial x \partial y} \\\\ \dfrac{\partial^2f}{\partial y\partial x} & \dfrac{\partial^2f}{\partial y^2} \end{bmatrix} = \begin{bmatrix}2&0\\0&2\end{bmatrix}[/tex]

[tex]H(x,y)[/tex] is positive definite for all [tex]x,y[/tex], which indeed indicates a local minimum at (1/2, 1/2), so that

[tex]\min\left\{x^2+y^2 \mid x+y=1\right\} = f\left(\dfrac12,\dfrac12\right) = \dfrac14+\dfrac14 = \boxed{\dfrac12}[/tex]

Answer:

Given as at the end of the proof flowchart we are only left with one unknown m∠3, the logical conclusion is that we're proving that m∠3 = 180° - 54° = 126°

Answer:

$105

Step-by-step explanation:

$5 initial cost + $50 (teal shirt) + $50 (purple shirt)

Answer:

Only one equation fits all the information on the table which is:

y = 1/6x

Answer:

y = 1/6x

Step-by-step explanation:

To find the equation, let's see if each option works by plugging in x into each equation.

y = –1/4x

Plug -6 into x

y = –1/4(-6)

y = 1.5

y = –1/4x doesn't work because we didn't get -1.

y = 6x

Plug -6 into x

y = 6(-6)

y = -36

y = 6x doesn't work because we didn't get -1.

y = 1/6x

Plug 1/6x into x

y = 1/6(-6)

y = -1

Let's see if the other x values work.

Plug 0 into x

y = 1/6(0)

y = 0

Plug 12 into x

y = 1/6(12)

y = 2

y = 1/6x works.

y = –2x

Plug -6 into x

y = –2(-6)

y = 12

y = -2x doesn't work because we didn't get -1.

y = 1/6x is the only linear equation that worked and got all y values, so that is your answer.

Hope that helped and have a lovely rest of your day!

Greetings from Brasil...

Checking the side limits of the function f(x), we find that they are equal, so there is a limit of f(x) as x approaches 4

check the attachment

Answer:

1440

Step-by-step explanation:

3(4+4)(4+1)(4+2)(4-2)

3*8*5*6*2

1440