In Fairbanks the temperature went down 20 degrees in 6 hours

The four numbers are: -4, -2 ,0, 2 Answer.

How do you solve this: the sum of four consecutive even integers is equal to least of the integer

Solution: Let the numbers be n, n+2, n+4 and n+6.

Their sum = 4n+12 = n or

3n+12 = , or

3n = -12,

n= -4

therefore we get -4, -2, 0, 2

The four numbers are: -4, -2 ,0, 2 . Answer.

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According to the image, the figure moved four times to return to its initial position.

The starting position of the figure is in the lower left corner of the frame.

The movement made by the figure from position 1 to position 2 is that it moves from the lower left corner to the lower right corner.

The movement made by the figure from position 2 to position 3 is that it moves from the lower right corner to the upper right corner. Additionally, the figure rotates to the left 180°.

The movement that the figure performs from position 3 to position 4 is that it moves from the upper right corner to the upper left corner.

The movement made by the figure from position 4 to position 5 is that it moves from the upper left corner to the lower left corner. Additionally, the figure is rotated 180° to the left again.

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Answer:

[tex]\sf (A' \cap B) \cup (A' \cap C') =\{1,6,7\}[/tex]

Step-by-step explanation:

[tex]\begin{array}{|c|c|l|} \cline{1-3} \sf Symbol & \sf N\:\!ame & \sf Meaning \\\cline{1-3} \{ \: \} & \sf Set & \sf A\:collection\:of\:elements\\\cline{1-3} \cup & \sf Union & \sf A \cup B=elements\:in\:A\:or\:B\:(or\:both)}\\\cline{1-3} \cap & \sf Intersection & \sf A \cap B=elements\: in \:both\: A \:and \:B} \\\cline{1-3} \sf ' \:or\: ^c & \sf Complement & \sf A'=elements\: not\: in\: A \\\cline{1-3} \sf - & \sf Difference & \sf A-B=elements \:in \:A \:but\: not\: in \:B}\\\cline{1-3} \end{array}[/tex]

Given sets:

Therefore, the complement sets are:

[tex]\begin{aligned}\sf A' & = \text{U}-\sf A\\& = \{1,2,3,4,5,6,7,8 \}- \{2,4,5,8 \}\\& = \{1,3,6,7 \}\end{aligned}[/tex]

[tex]\begin{aligned}\sf B' & = \text{U}-\sf B\\& = \{1,2,3,4,5,6,7,8 \}- \{1,4,6 \}\\& = \{2,3,5,7,8 \}\end{aligned}[/tex]

[tex]\begin{aligned}\sf C' & = \text{U}-\sf C\\& = \{1,2,3,4,5,6,7,8 \}- \{1,2,3,4,5 \}\\& = \{6,7,8 \}\end{aligned}[/tex]

Solution

[tex]\begin{aligned}\sf (A' \cap B) \cup (A' \cap C') & = \sf \left(\{1,3,6,7 \} \cap \{1,4,6\} \right) \cup \left(\{1,3,6,7 \} \cap \{6, 7, 8 \} \right)\\\\& = \sf \{1,6\} \cup \{6,7 \} \\\\& = \sf \{1,6,7\} \end{aligned}[/tex]

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The proportional relationship of the given statement is a between x and y and the constant of proportionality is 0.5.

According to the statement

We have to find that the constant of proportionality.

So, For this purpose, we know that the

An equation is a mathematical statement that is made up of two expressions connected by an equal sign.

From the given information:

each equation represents a proportional relationship.

Then

We know that the A proportional relationship is one in which two quantities vary directly with each other

That's why

An equation has a proportional relationship if it can be written in the form y=kx where k is the constant of proportionality.

A linear function of x is given as y = 0.5x - 2.

Yes, this function of x represents a proportional relationship between x and y.

The constant of proportionality is given to be 0.5 provided that the dependent variable y has an initial value of - 2 at x = 0.

The graph of this equation will be a straight line and that means that the equation consists of a proportional relationship.

So, The proportional relationship of the given statement is a between x and y and the constant of proportionality is 0.5.

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Disclaimer: This question was incomplete. Please find the full content below.

Question:

Determine whether each equation represents a proportional relationship. if it does identify the constant of proportionality. y = 0.5 x -2

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A linear pair is formed of ∠1 and ∠2. The measures of the angle ∠1 is 20 and ∠2 is 160.

Given that,

A linear pair is formed of ∠1 and ∠2.

We have to find the measurements of both angles if m∠1 is eight more than m∠2.

When they refer to something as "linear," they mean that two angles create a straight line (or, 180 degrees). In other words, the two angles add up to 180.

Let us take the ∠1 as x

Then ∠2 will be 8x.

Now, we can write as

x+8x=180

9x=180

x=180/9

x=20

Therefore, the measures of the angle ∠1 is 20 and ∠2 is 8×20=160.

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The correct answer is option A that is 74.

First, we need to put the expression in the form of mathematical equation. A mathematical equation may be defined as the combination of numbers and arithmetic symbols which are related to each other according to the expression given. The expression in the form of mathematical expression can be written as:

(9 - 2/3×√9)² + (1-6)²

Solving the brackets separately.

(9 - 2/3×3)² + (-5)²

Now in the next step, simplify the equation.

=>(9 - 2)² + 25

=>(7)² + 25

=>49 + 25

=>74.

Therefore, the required answer is 74.

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Answer:

22 divided by 2.630= 8 remainder 0.96

Answer: 22/2.630 is 8, remainder is 0.365 or 73/200

Step-by-step explanation:

80.3÷9.4

80/3÷9/4

80/3×4/9

26.6×4/9

=17.733

This means that Kenna will get 18 pieces from one lenght of pipe

The figure KLMN is being rotated by 90°, which is a rigid transformation, the true statements are therefore;

(D) Figure RSTU is congruent to figure KLMN

(E) [tex] \angle T[/tex] is the same measure as [tex] \angle M[/tex]

The given parameters are;

In KLMN, KN||LM

The transformation applied to figure KLMN = A 90° clockwise rotation about point P.

The image of KLMN following the rotation transformation is Figure RSTU.

Please find attached a drawing of the possible diagram in the question obtained from a similar question online.

The options from the question are;

(A) [tex] \overline{ST}[/tex] is parallel to [tex] \overline{RU}[/tex]

(B) [tex] \angle R[/tex] is the same measure as [tex] \angle N[/tex]

(C) [tex] \overline{RS} [/tex] is the same length as \overline{MN}

(D) Figure RSTU is congruent to figure KLMN

(E) [tex] \angle T[/tex] is the same measure as [tex] \angle M[/tex]

A rotation transformation is a rigid transformation, therefore;

The distances between any two points on the pre–image is the same as the distance between corresponding points on the image, which gives;

Figure KLMN [tex] is congruent to [/tex] Figure RSTU

Figure KLMN [tex] \cong [/tex] Figure RSTU

According to the postulate, Corresponding Angles of Congruent Figures are Congruent, we have;

[tex] \angle T \cong \angle M[/tex]

Which gives;

[tex] \angle T[/tex] = [tex] \angle M[/tex]

[tex] \angle T[/tex] is the same measure as [tex] \angle M[/tex]

The correct options are therefore;

(D) Figure RSTU is congruent to figure KLMN

(E) [tex] \angle T[/tex] is the same measure as [tex] \angle M[/tex]

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The Area of the given composite shape is; 40 square units

We can breakdown the shape into triangle and rectangle and as such we know that;

Formula for area of triangle is;

Area = ¹/₂ * base * height

Formula for area of rectangle is;

Area = Length * Width

Thus;

Area of composite shape = (10 * 3) + (¹/₂ * 10 * 2)

Area of composite shape = 30 + 10

Area of composite shape = 40 square units

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Answer:

1.002, -0.02

Step-by-step explanation:

Probabilities range between 0 and 1.

The liquidity premium for the corporate bond is 0.25%.

Any additional compensation needed to stimulate investment in assets that cannot be quickly and effectively converted into cash at fair market value is known as a liquidity premium. For instance, due to its relative illiquidity, a long-term bond will have a higher interest rate than a short-term bond.

Liquidity premium for corporate bond will be:

= 5.25 - 3.5 - 1.5

= Interest - Treasury - Default risk

= 0.25%.

Therefore, the liquidity is 1.25%.

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To two decimal places,

√70

must lie between 8.3

and 8.4

The value of 9 - √7 is between 6 and 7:

4 < 7 < 9

⇒   √4 < √7 < √9

⇒   2 < √7 < 3

⇒   -3 < -√7 < -2

⇒   9 - 3 < 9 - √7 < 9 - 2

⇒   6 < 9 - √7 < 7

Answer:

Step-by-step explanation:

you can't really solve for x because there is no equal sign to determine how much x needs to be in order to get the sum.

Step-by-step explanation:

the average change rate for a function g(x) is defined for an interval of x values as

(g(interval end) - g(interval begin))/(interval end - interval begin)

in our case that is

(g(2013) - g(2008))/(2013 - 2008) =

= (24 mil. - 186 mil)/5 = -162 mil./5 =

= -162,000,000 / 5 = -32,400,000

that means that as a mean value there were 32,400,000 digital cameras shipped less every year.

in other words, fewer and fewer digital cameras are sold. the demand is strongly declining.

actually, following the mean values and their trend, there should have been no new digital cameras shipped in 2014 anymore (as 24 mil. - 32.4 mil is less than 0).

A member of the senate will serve for (h+4) years.

An expression, in mathematics, is a finite set of combinations and/ or numbers and variables that accurately represents the the context in question. When two or more expressions are connected using the equality sign then an equation is formed.

Here, we are given that in the US government a member of the senate serves for 4 years longer than a member of the House of Representatives.

Also the House of Representatives serves for- h years

Thus, the number of years a member of the Senate will serve will be 4 more than the number h

= h + 4

Thus, a member of the senate serves for (h+4) years.

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The answer of part a is y = 8

The answer of part b is RS = 69, ST = 28

Step-by-step explanation:

a. Since RT = RS + RT, subsitute values of RS and RT in the equation

    97 = (8y + 5) + (3y + 4)

    97 = 11y + 9

    97 - 9 = 11y

    88 = 11y

     y = 8

b. Subsitute the value of y in RS and ST just like done in part a

Answer:

????

Step-by-step explanation:

I don't get this

at all

Based on the calculations, the coordinates of the other end of the fence are equal to (-1, -7).

A line segment can be defined as the part of a line in a geometric figure such as a triangle, circle, quadrilateral, etc., that is bounded by two (2) distinct points and it typically has a fixed length.

In order to determine the midpoint of a line segment with two (2) endpoints, we would add each point together and divide by two (2).

Midpoint on x-coordinate is given by:

xm = (x₁ + x₂)/2

3.5 = (8 + x₂)/2

Cross-multiplying, we have:

7 = 8 + x₂

x₂ = 7 - 8

x₂ = -1.

Midpoint on y-coordinate is given by:

ym = (y₁ + y₂)/2

-1 = (5 + y₂)/2

Cross-multiplying, we have:

-2 = 5 + y₂

y₂ = -2 - 5

y₂ = -7.

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Answer:5.1,5.2,5.3,5.4,5.6,5.7,5.8,5.9,

Step-by-step explanation:

The piecewise linear function that models the situation is given as follows:

A linear function is modeled by:

y = mx + b

In which:

A piecewise function is a function that has different definitions based on the input.

For x between -9 and -3, the function decreases by 8 when x increases by 6, hence the slope is given by:

m = -8/6 = -4/3, hence:

y = -4/3x + b.

When x = -9, y = 9, hence we use it to find b as follows:

9 = -4/3(-9) + b

9 = 12 + b

b = -3.

Thus the first definition is:

y = -4/3x + b, −9 ≤ x ≤ −3

For x between -3 and 4, the function decreases by 8 when x increases by 7, hence the slope is given by:

m = -8/7

y = -8/7x + b.

When x = -3, y = 1, hence we use it to find b as follows:

1 = -8/7(-3) + b

1 = 24/7 + b

b = -17/7

Thus the second definition is:

y = -8/7x - 17/7, −3 < x ≤ 4.

For x between 4 and 10, the function increases by 17 when x increases by 6, hence the slope is given by:

m = 17/6

y = 17/6x + b.

When x = 10, y = 10, hence we use it to find b as follows:

10 = 17/6(10) + b

b = 10 - 170/6

b = -110/6

Thus the third definition is:

y = 17/6x - 110/6, 4 < x ≤ 10

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The conditional statement is that; If generally a person is 1% shorter in the evening than in the morning, then my height is about 1.62326 m in the evening.

First, we will calculate how much is one percent of your height and then subtract that percentage from the total height to get your" height in the evening".

For example:

If my height is 1.64 m, then;

0.01 * 1.64 m = 0.0164 m

Step 2 is;

1.64m - 0.0164m = 1.62326 m

​

Now, using these height, let's write a conditional that uses the described fact:

Conditional:

If generally a person is 1% shorter in the evening than in the morning, then my height is about 1.62326 m in the evening.

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Answer:

The slope would be [tex]-\frac{4}{3}[/tex]

Step-by-step explanation:

Answer:use demos cauculator

Step-by-step explanation:

Domain: (−∞,∞) , {x|x ∈ R}

Range: [0,∞) , {y|y ≥ 0}

Continuity: y=3x^2 is a parabola opening upwards, the vertex is at (0,0) and the focus is (0,1/12)

Max's and Min's: the minimum and maximum x value goes to infinity while for the y value the minimum is 0 and goes up to infinity.

Intervals: both x and y start to increase from the origin

Symmetry: the axis of symmetry is x=0 so therefore there the parabola is symmetrical

Answer:

Step-by-step explanation:

Given function:

[tex]y=3x^2[/tex]

The domain is the set of all possible input values (x-values).

The domain of the given function is unrestricted.

Therefore, the domain is (-∞, ∞).

The range is the set of all possible output values (y-values).

As x² ≥ 0, the range of the given function is [0, ∞).

A function f(x) is continuous when, for every value [tex]c[/tex] in its domain:

[tex]\text{$f(c)$ is de\:\!fined \quad and \quad $\displaystyle \lim_{x \to c} f(x) = f(c)$}[/tex]

Therefore, the function is continuous on its domain (-∞, ∞).

Stationary points occur when the gradient of a graph is zero.

Therefore, to find the x-coordinate(s) of the stationary points of a function, differentiate the function, set it to zero and solve for x.

[tex]\begin{aligned}y & = 3x^2\\\implies \dfrac{\text{d}y}{\text{d}x} & = 6x\\\\\dfrac{\text{d}y}{\text{d}x} & = 0\\\implies 6x & = 0\\x & = 0\end{aligned}[/tex]

[tex]\textsf{When} \:x = 0 \implies y=3(0)^2=0[/tex]

Therefore, the stationary point of the given function is (0, 0).

To determine if a stationary point is minimum or maximum, differentiate the function again and substitute the x-value of the stationary point:

[tex]\begin{aligned}\dfrac{\text{d}y}{\text{d}x} & = 6x\\\implies \dfrac{\text{d}^2y}{\text{d}x^2} & = 6 \end{aligned}[/tex]

As the second derivative is positive regardless of the x-value of the stationary point, the stationary point is a minimum.

[tex]\textsf{A function is \textbf{increasing} when the \underline{gradient is positive}} \implies \dfrac{\text{d}y}{\text{d}x} > 0[/tex]

[tex]\textsf{A function is \textbf{decreasing} when the \underline{gradient is negative}} \implies \dfrac{\text{d}y}{\text{d}x} < 0[/tex]

Increasing

[tex]\begin{aligned}\dfrac{\text{d}y}{\text{d}x} & > 0 \\ \implies 6x & > 0 \\ x & > 0\end{aligned}[/tex]

Decreasing

[tex]\begin{aligned}\dfrac{\text{d}y}{\text{d}x} & < 0 \\ \implies 6x & < 0 \\ x & < 0\end{aligned}[/tex]

Therefore:

[tex]\textsf{A function is \underline{even} when $f(x) = f(-x)$ for all $x$.}[/tex]

[tex]\textsf{A function is \underline{odd} when $-f(x) = f(-x)$ for all $x$.}[/tex]

As x² ≥ 0 and there is symmetry about the y-axis,

[tex]\textsf{then $f(x)=f-x)$ for all $x$,}[/tex]
so the function is even.

The cordinates of the turning point of the graph of y=f(x) occurs at (1.1) and (5/3, 23/27)

2

(x−2)+1

Now, differentiating w.r.t. x, we get

f

′

(x)=2(x−1)(x−2)+(x−1)

2

=(x−1)[2(x−2)+x−1]

=(x−1)[3x−5]

Hence,

f

′

(x)=0 implies x=1 and x=

3

5

​

Corresponding values of y are y=1 and y=

27

23

​

 respectively.

∴ Co-ordinates of turning point of the graph of f(x) occurs at (1,1) and (

3

5

​

,

27

23

​

)

Now,

f(x)=(x−1)

2

(x−2)+1

=(x

2

−2x+1)(x−2)+1

=x

3

−2x

2

−2x

2

+4x+x−2+1

=x

3

−4x

2

+5x−1

The value of p for which the equation f(x)=p has 3 distinct solutions lies in interval (

27

23

​

,1)

Area enclosed by f(x),x=0,y=1 and x=1 is

A=∫

0

1

​

(1−f(x))dx

⇒∫

0

1

​

(4x

2

−x

3

−5x+2) dx

⇒A=

12

7\

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