In Exercises 19-24, solve the equation. Determine
whether the equation has one solution, no solution, or
infinitely many solutions. (See Example 3.)
19. 3t+ 4 = 12 + 3t
20. 6d+ 8 = 14 + 3d
21. 2(h+ 1) = 5h - 7
22. 12y + 6 = 6(2y + 1)
23. 3(4g + 6) = 2(6g + 9)
24.
5(1+2m)=(8 + 20m)

Answer:

no

Step-by-step explanation:

x=5

5(5+2)=35

8(5)-3=37

37 does not equal 35

[tex]Answer: Q\ is\ not\ midpoint\ of\ \overline {PR}[/tex]

Step-by-step explanation:

[tex]\displaystyle\\\overline {PQ}+\overline {QR}=\overline {PR}\\5(x+2)+(8x-3)=72[/tex]

Expand the parentheses on the left side of the equation:

x(5)+2*(5)+8x-3=72

5x+10+8x-3=72

13x+7=72

13x+7-7=72-7

13x=65

Divide both parts of the equation by 13:

x=5

Hence,

5(5+2)=

5(5)+2(5)=

25+10=

35

8(5)-3=

40-3=

37

35≠37

Lines can be perpendicular or parallel to one another.

What do we mean by linear equation?

So,

A linear equation is written as:  y = mx + b

Where, m = slope.

(A) Parallel equation:

The slope of a line parallel to y = mx + b is the same as the slope of y = mx + b, that is the slope is the equation in m.

The equation is then solved as follows:

Where:

Now, put (x₁,y₁) = (a,c) in y = m(x - x₁) + y₁ as follows:

y = m (x - a) + c

y = mx - am + c

So, the equation of a line is y = mx - am + c.

(B) Parallel equation:

The slope (m2) of a perpendicular line to y = mx + b is:

The equation is then solved as follows:

Where:

Now, put (x₁,y₁) = (a,c) in y = m(x - x₁) + y₁

The perpendicular line's equation is y = -(x/m) + a/m + c.

Therefore, lines can be perpendicular or parallel to one another.

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The correct question is given below:
Find the equations for the lines through the point (a,

c.that are parallel to and perpendicular to the line y = mx + b where m ≠ 0. use y for the dependent variable and all letters in lower case.

nxhudkdodisuhaiioavsbos

Step-by-step explanation:

seven-hundred thirty thousand eight-hundred twelve

Answer:

Step-by-step explanation:

1035x-992/840

The equation system to represent these two plans is:

c=100+10d, c=40d where c is the total cost and d represents the data used.

We have to understand the plans provided by AT&K and Verikon separately to find the equation system. We know that the total cost incurred is c and the amount of data used is d. It is given that AT&K charges a monthly flat rate of $100 and additional $10 for every gigabyte of data used. We can say that for a month the total cost incurred from AT&K is $100 plus $10xd, the amount of data used.

c=100+10d

For verikon it is given that it does not have any flat monthly rate and it charges $40 for each gigabyte of data used.We can easily say that the total cost in this case is $40 multiplied to amount of data used.

c=40d

Thus the system of equation for the two different plans is

c=100+10d and c=40d

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Weight of pet & age of pet  are   the two categories that would yield quantitative data.

What foundation does qualitative data have?

Which two sorts of quantitative data are there?

Weight of pet & age of pet  are   the two categories that would yield quantitative data because both quantity can measured or counted.

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Answer:

Hey!

Since we know that both expressions lay on a straight line, we know that when both lines add up it should be 180°

We can write the expression as (7x - 1) + (6x - 1) = 180

Simplify

→ (7x + −1) + (6x + −1) = 180

Combine Like Terms

→ (7x + 6x) + (-1 + -1) = 180 → 13 + -2 = 180

Add 2 To Both Sides

→ 13x - 2 + 2 = 180 + 2 → 13x = 182

Divide 13 To Both Sides

13x/13 = 182/13 → x = 14

Hence, the value of x is 14!

-------------------------------------------------

Hope This Helped! Good Luck!

Answer:

See attached graph for lines

Left side line is y = -3x-2

Right side line is y = 2x + 8

Point of intersection is at (-2,4)

Step-by-step explanation:

The line graphs are attached

The solution for (x, y) is the point of intersection  of the two lines

This is at point (2,4)

We can also solve this algebraically by solving first for x and then y

–3x – 2 = 2x + 8

The two line equations are

y = -3x - 2 and y = 2x+8

3x – 2 = 2x + 8

==> 3x -2x - 2 = 2x-2x + 8   (subtract 2x on both sides)

==>  -5x -2 = 8

==> -5x -2 + 2 = 8 + 2    (add 2 on both sides to isolate the x term)

==> -5x = 10==> -5x/5 = 10/5 (divide by 5 both sides)

==> x = -2

Plug this value of x into the RHS giving

y = 2(-2) + 8 ==> y = -4 + 8 ==> y = 4

So (-2,4) is the point of intersection of the two lines and is consistent with the point of intersection on the graph

Small, random genetic changes that occur over generations is known as genetic drift.

Genetic drift is an evolutionary process in which the frequency of a given gene allele varies randomly across a population. The impacts of genetic drift can be severe, often causing traits to become excessively common or to vanish from a community, even though it predominantly affects small, isolated populations.

Some people might merely by coincidence leave behind a few more offspring (and genes, of course!) than others in each generation. The next generation's DNA and other genetic components will come from the "fortunate" people, not necessarily the healthier or "better" people.

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Answer: x = 24

Step-by-step explanation:

-16 + 24 = 8

The solution to the literal equation is y = x - 2.

To solve inequality in y, we need a number such that the assertion holds if we replace y with that number. Isolating the variable on one side of the inequality and leaving the other terms constant is the first step in resolving the inequality.

From the given information:

4x + 1 = 9 + 4y

To solve for y, we have to switch the sides:

9 + 4y = 4x + 1

Subtract 9 from both sides

9 - 9 + 4y = 4x + 1 - 9

4y = 4x - 8

Divide both sides by 4

[tex]\dfrac{4y}{4}= \dfrac{4x}{4}-\dfrac{8}{4}[/tex]

y = x - 2

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Answer:

a) 512cm³    b) 2 × 2 ×2

Step-by-step explanation:

A CUBE'S LENGTH WIDTH AND HEIGHT ARE EQUAL

a) Volume of a cube = length × width × height

as the length width and height are equal so it will be

8 × 8 × 8 = 512

b) Volume of a cube = length × width × height

as length, width and height are equal lets suppose the value of each of them will be = x

volume = x × x × x

vol = x³

8 = x³

∛8 = x

x = 2

The general solution of the given equation is y² = 8x²Inx + cx².

A first-order linear differential equation is one that has the formula:

[tex]\frac{d y}{d x}+p(x) y=q(x)[/tex]

where p(x) and q(x) are continuous functions of x.

We begin by determining the integrating factor for the first-order linear differential equation.

I.F. = [tex]e^{\int p(x) d x}[/tex]

The solution to the first order linear differential equation is:

[tex]y \cdot e^{\int p(x) d x}=\int q(x) \cdot e^{\int p(x) d x} d x+c .[/tex]

The solution to the first order linear differential equation is:

[tex]\int \frac{1}{x} d x=\ln x+c[/tex]

So, given: [tex]y^{\prime}=\frac{\left(4 x^2+y^2\right)}{(x y)}[/tex]

The above differential equation can be written as:

[tex]\begin{aligned}&\frac{d y}{d x}=4 \frac{x}{y}+\frac{y}{x} \\&\frac{d y}{d x}-\frac{y}{x}=\frac{4 x}{y} \\&y \frac{d y}{d x}-\frac{y^2}{x}=4 x\end{aligned}[/tex]

Substitute, [tex]y^2=t, 2 y \frac{d y}{d x}=\frac{d t}{d x}[/tex].

[tex]\begin{aligned}&\frac{1}{2} \frac{d t}{d x}-\frac{t}{x}=4 x \\&\frac{d t}{d x}-\frac{2 t}{x}=8 x\end{aligned}[/tex]

Because this is a first-order linear differential equation, we must first determine the integrating factor:

[tex]\text { I. F. }=e^{-2 \int \frac{1}{x} d x}=e^{-2 \ln x}\\\text { I.F. } F=\frac{1}{x^2}[/tex]

As a result, the following is the general solution to the given IVP:

[tex]$$t \cdot(I . F .)=\int(I . F .) \cdot 8 x d x+c$$$t \cdot\left(\frac{1}{x^2}\right)=\int\left(\frac{1}{x^2}\right) \cdot 8 x d x+c$$t \cdot\left(\frac{1}{x^2}\right)=8 \int \frac{1}{x} d x+c$$t \cdot\left(\frac{1}{x^2}\right)=8 \ln x+c$$t=8 x^2 \ln x+c x^2$[/tex]

By reversing the value of t:

[tex]y^2=8 x^2 \ln x+c x^2[/tex]

We now test the solution by substituting [tex]y^2=8 x^2 \ln x+c x^2[/tex] it in the original differential equation.

[tex]\begin{aligned}&\frac{d}{d x}\left(y^2\right)=\frac{d}{d x}\left(8 x^2 \ln x+c x^2\right) \\&2 y \frac{d y}{d x}=16 x \ln x+8 x+2 c x \\&\frac{d y}{d x}=\frac{16 x \ln x+8 x+2 c x}{2 y} \\&\frac{d y}{d x}=\frac{8 x \ln x+4 x+c x}{y}\end{aligned}[/tex]

We calculated the value of [tex]y^2[/tex] and [tex]\frac{d y}{d x}[/tex] from the original differential equation:

[tex]\begin{aligned}&\frac{8 x \ln x+4 x+c x}{y}=\frac{4 x^2+8 x^2 \ln x+c x^2}{x y} \\&8 x \ln x+4 x+c x=8 x \ln x+4 x+c x .\end{aligned}[/tex]

Therefore, the general solution of the given equation is y² = 8x²Inx + cx².

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The complete question is given below:
For the following ODE, find a general solution, show the steps of derivation and check your answer by substitution.

[tex]y^{\prime}=\frac{\left(4 x^2+y^2\right)}{(x y)}[/tex]

The base case for which the inductive proof for p(n) is defined, is the smallest value of n for which p(n) is defined.

Mathematical induction refers to a strategy for demonstrating a theorem's correctness by first demonstrating that, if it holds true in one particular situation, it will also hold true in all subsequent cases in the series.

Now,

Hence, the base case for which the inductive proof for p(n) is defined, is the smallest value of n for which p(n) is defined.

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Answer: LCM would be [tex]\sqrt{2}[/tex]

Step-by-step explanation:

First we need to find number of which we need to find lcm

here we dont have any two number but operator (+) is present

so

first we need to solve this operation

=1/[tex]\sqrt{2}[/tex] + 1/[tex]\sqrt{2}[/tex]

=[tex]\sqrt{2}[/tex]

so lcm of  [tex]\sqrt{2}[/tex] would be [tex]\sqrt{2}[/tex].

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The inequality which represents all the possible values for x is (2x/3) - 6 ≥ 24.

It is given in the question that the difference of two-thirds of a number x and 6 is at least -24.

We have to find the inequality which represents all the possible values for x.

In mathematics, Inequality is a statement of an order relationship—greater than, greater than or equal to, less than, or less than or equal to—between two numbers or algebraic expressions.

Hence, according to the data given in the question, we can write,

(2x/3) - 6 ≥ 24

Here, we can also find the possible values of x.

(2x/3) - 6 ≥ 24

2x/3  ≥ 24 + 6

2x/3  ≥ 30

x  ≥ 30*3/2

x  ≥ 45

Hence, every number greater than or equal to 45 will be a possible value of x.

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Answer:

[tex]\textsf{1.} \quad s=\dfrac{8r}{9}[/tex]

[tex]\textsf{2.} \quad s=4[/tex]

[tex]\textsf{1.} \quad x=y(w+z)[/tex]

[tex]\textsf{2.} \quad x=10[/tex]

Step-by-step explanation:

Question 1

1.  Solve for s:

[tex]\implies 2r = \dfrac{5s}{2}-\dfrac{s}{4}[/tex]

[tex]\implies 2r = s\left(\dfrac{5}{2}-\dfrac{1}{4}\right)[/tex]

[tex]\implies 2r = s\left(\dfrac{10}{4}-\dfrac{1}{4}\right)[/tex]

[tex]\implies 2r = s\left(\dfrac{9}{4}\right)[/tex]

[tex]\implies 4(2r) = 9s[/tex]

[tex]\implies 8r = 9s[/tex]

[tex]\implies s=\dfrac{8r}{9}[/tex]

2.  When r = ⁹/₂ :

[tex]\implies s=\dfrac{8\left(\frac{9}{2}\right)}{9}[/tex]

[tex]\implies \dfrac{8}{9} \times \dfrac{9}{2}[/tex]

[tex]\implies \dfrac{8 \times9}{9 \times2}[/tex]

[tex]\implies s=\dfrac{72}{18}[/tex]

[tex]\implies s=4[/tex]

Question 2

1.  Solve for x:

[tex]\implies w=\dfrac{x}{y}-z[/tex]

[tex]\implies w+z=\dfrac{x}{y}[/tex]

[tex]\implies y(w+z)=x[/tex]

[tex]\implies x=y(w+z)[/tex]

2.  When x = -8,  y = -5,  z = 6:

[tex]\implies x=-5(6+(-8))[/tex]

[tex]\implies x=-5(6-8)[/tex]

[tex]\implies x=-5(-2)[/tex]

[tex]\implies x=10[/tex]

Answer: No, Nathan didn't measure angle correctly

Step-by-step explanation:

The sum of angles that are formed on a straight line is equal to 180°

So the value angle q is 80° because the sum of angle q and 100° is 180°

                                  ∠q= 180°-100°

                                    ∠q= 80°

No, Nathan didn't measure angle correctly.

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Answer:

4725

Step-by-step explanation:

105 students

think of 100 students

100 × 45 = 4500

now the remaining 5 students

cost for 10 students will be

45 × 10 = 450

divide 450 by 2 to find out for 5 students

it is 225

4500 + 225 = 4725

In triangle TRS, VZ = 6 inches. Then the length of the line segment RZ will be 12 inches.

A triangle is a three-sided polygon with three angles. The angles of the triangle add up to 180 degrees.

The centroid Z of the triangle TRS. Line sections TW, RV, and SU are created by drawing lines from every point to the center of the opposing side.

We know that the centroid divides the median of the triangle in a ratio of 2: 1.

In triangle TRS, VZ = 6 inches. Then the length of the line segment RZ will be

RZ / ZV = 2 / 1

RZ / 6 = 2

RZ = 6 x 2

RZ = 12 inches

In triangle TRS, VZ = 6 inches. Then the length of the line segment RZ will be 12 inches.

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An equation having variables on both sides can be solved by bringing all variables to one side.

An equation with all variables on one side can be solved by simply keeping the variables on the left and simplifying the value on the right. For example,

5x = 6 + 2x;

3x = 6;

x = 2.

For an equation with variables on both sides, just bring all variables on one side. After that, the same process like above is to be followed. For example,

5y - 3 - 3y = 3y + 5 - 3y;

5y - 3y - 3y + 3y = 5 + 3;

2y = 8;

y = 4;

Thus, methods for solving both kinds of equations is similar.

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An equation having variables on both sides can be solved by bringing all variables to one side.

An equation with all variables on one side can be solved by simply keeping the variables on the left and simplifying the value on the right. For example,

5x = 6 + 2x;

3x = 6;

x = 2.

For an equation with variables on both sides, just bring all variables on one side. After that, the same process like above is to be followed. For example,

5y - 3 - 3y = 3y + 5 - 3y;

5y - 3y - 3y + 3y = 5 + 3;

2y = 8;

y = 4;

Thus, methods for solving both kinds of equations is similar.

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Answer:

x<44

Step-by-step explanation:

The perimeter of the rectangle with length 8x - 1 and width 10x + 3 is 20x + 6

What is perimeter of the rectangle?

The perimeter of the rectangle with length 8x - 1 and width 10x + 3 is 20x+ 6

The formula for calculating the perimeter of a rectangle is expressed as:

P = 2( l + w)

Given the following parameters

length l = 8x - 1

width w = 2x + 4

Substitute the expressions for the length and width into the formula;

P = 2(8x - 1 + 2x + 4)

P = 2(10x + 3)

Distribute 2 over each term in the parenthesis

P = 2(10x) + 2(3)

P = 20x + 6

Hence the perimeter of the rectangle with length 8x - 1 and width 10x + 3 is 20x + 6.

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The complete question is -

The perimeter formula for a rectangle is 2l + 2w, where l is the length and w is the width. Complete the steps to find an expression that represents the perimeter of the rectangle. Substitute the expressions for length and width into the formula 2l + 2w. Distribute 2 to each term in the parentheses. Combine like terms. inches