If the force of gravity exerted on the sun by the earth is the same as the force exerted by the earth on the sun, why does the earth orbit the sun, and not the other way around?

The magnitude of ax is given by |ax|= | v₀²/2(d −v₀t) |

acceleration: change in velocity with respect to time.

It is a vector quantity. That means it has both magnitude. As well as direction.

a = dv/dt

where

dv = change in velocity

dt = Time

the unit of acceleration is m/s²

magnitude of  acceleration is represented by its unit and the direction is represented by a unit vector.

according to the Newton's Second Law acceleration is proportional to the total force and inversely proportional to the objects mass.

magnitude of acceleration is proportional to magnitude of this force.

The magnitude of ax is given by |ax|= | v₀²/2(d −v₀t) |

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Rinse chemicals from your hands and arms with water in the sink

In the chemistry lab we use to work with chemical solutions, because of that we must learn what is the best way to manipulate the chemicals with we are going to work, so an proper way to maintain our hands and arms clean is using the lab's sink in order to wash our hands and arms with enough water

In chemistry a solution is known as a homogeneous mixture of two or more components called:

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The volume of the solid is [tex]V=128\frac{r^{3} }{3}[/tex]

What do you understand by Volume ?

A liquid, solid, or gas's volume is the amount of three-dimensional space it occupies. Although there are many different units that can be used to indicate volume, the most common ones are liters, cubic meters, gallons, milliliters, teaspoons, and ounces.

base is x2+y2=(2r)2

==>y=-√(4r2-x2) ,√(4r2-x2)

So each cross section parallel has base = √(4r2-x2) - -(√(4r2-x2)) = 2√(4r2-x2) and height = base

So area of each cross section is 2√(4r2-x2)*2√(4r2-x2)= 4(4r2-x2)

Now we integrate from left side of circle to right side of circle (-2r to 2r)

V = 4 ∫[ -2r to 2r] (4r2-x2)dx

V = 4 (4r2x - x3/3) [ -2r to 2r]

V = 4 [(4r2(2r) - (2r)3/3) - (4r2(-2r) - (-2r)3/3)]

V = 4 [ (8r3 - 8r3/3) - (-8r3 + 8r3/3)]

V = 4 (16r3 - 16r3/3)

V = 4 (32r3/3)

V = 128r3/3

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Answer:

See below

Explanation:

(180 000 - 10) km  /  36 km/s = 4999.7 =~ 5000 seconds = 83 .3 min

According to Stefan’s law, a hotter body radiates 68 times more energy per unit area per second

As per Stefan’s law, Fhotter/Fcooler = 68

The Stefan law or the Stefan-Boltzmann law, states that the total radiant heat power that is emitted from a surface per unit area at the absolute temperature is directly proportional to the fourth power of its temperature.

The unit used in Stefan’s law is σ which equals to Wattm−2k−4

This law was formulated by Josef Stefan in 1879 through his experimental studies and again by Ludwig Boltzmann in 1844 from thermodynamic considerations.

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A ship travels 20 km to the south and then 40 km to the west. The ship's displacement from its starting point is approximately 44.7 km. Hence, the displacement is approximately 45 km.

Here, the calculation is done,

a = 20 km (southward movement)

b = 40 km (westward movement)

Now, one can find the displacement (d) using the Pythagorean theorem:

d² = a² + b²

d² = (20 km)² + (40 km)²

d² = 400 km² + 1600 km²

d² = 2000 km²

Now, by taking the square root of both sides to find the displacement (d):

d = √(2000 km²) d ≈ 44.7 km (rounded to one decimal place)

So, the ship's displacement from its starting point is approximately 44.7 km.

Hence, the displacement is approximately 45 km.

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The wavelength of the photon is 377nm.

The Balmer series is the series that begins or ends at n=2. It is one of the series of the hydrogen spectrum.

Now;

1/λ = RH([tex]\frac{1}{n_{2} ^{2} }[/tex] - [tex]\frac{1}{n_{1} ^{2} }[/tex])

λ = Wavelength

RH = Rydberg constant for hydrogen

[tex]n_{2[/tex] = final energy level

[tex]n_{1}[/tex] = initial energy level

1/λ = 1.097 * 10^7(1/2^2 - 1/12^2)

1/λ = 1.097 * 10^7(0.25 - 0.0069)

λ = 3.77 * 10^-7 m or 377nm

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The net forces on the first car is zero, the middle car is zero, and the last car is also zero.

In mechanics, the net force is the vector sum of all forces acting on a particle or object. The original forces' impact on the particle's motion is replaced by the net force, which is a single force. It causes the particle to accelerate at a rate equal to the sum of all those actual forces, as stated by Newton's second law of motion.

It is possible to figure out the torque connected to the point at which a net force is applied in order to keep the object's jets moving in the direction of the initial force field. Its resulting torque, the net force, has the same impact on the object's rotational motion as all actual forces combined.

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By using the power formula, the resistance of the bulb is 121 Ω.

We need to know about dissipated power to solve this problem. Power is energy dissipated to resistance as heat energy. It can be determined as

P = I . V

where P is power, I is current and V is voltage.

From Ohm's Law, we can substitute the current to

I = V / R

Hence, we can write the power equation to

P = (V/R) . V

P = V² / R

From the question above, we know that:

P = 100 watt

V = 110 volt

By substituting the following parameters, we get

P = V² / R

100 = 110² / R

R = 121 Ω

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A protective layer that shields the surface from lethal ultraviolet light is found in second layer of the atmosphere i.e., stratosphere.

More about ozone

The ozone layer is a component of the stratosphere, which is the second layer of the Earth’s atmosphere. The stratosphere is the name given to the layer of insulating gases that clings to our globe.

Ozone is a trace gas since there are only around 3 of its molecules in the atmosphere for every 10 million air molecules. But it serves an important purpose.

Like a sponge, the ozone layer absorbs sunlight that reaches Earth. While some of the sun’s radiation is essential for our survival, excessive amounts can be harmful to other living things.

The ozone layer shields life on Earth.

Benefits of ozone

Ozone does a good job of trapping ultraviolet radiation, also known as UV light, which may damage DNA molecules in plants and animals and penetrate protective layers on creatures like the epidermis.

The two primary subtypes of UV light are UVB and UVA.

UVB causes skin conditions including sunburns and cancers like basal cell carcinoma and squamous cell carcinoma.

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Answer:

In the Stratosphere

The protective layer is made of OZONE (O3). It shields us from the Sun's ultraviolet light. If the Ozone layer in the stratosphere becomes thin (letting more ultraviolet light through) it can lead to light and severe health effects, both to humans and animals, and can even affect food webs. In people, excess UV light can lead to certain forms of cataracts, increase in burns, cataracts, and sometimes even mutations (according to my FLVS Envornmental science course).

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The badgers displacement from its position at point t = 2, to its position at point t = 3 is 25 meters

The points on the graph are;

(0, 0), (1, 5), (3, -5), (6, -5)

The point t = 2 is between (1, 5) and (3, -5)

The slope, m, of the line containing the point t = 2 is therefore;

The equation of the line is therefore;

v - 5 = -5•(t - 1)

v = -5•t + 5 + 5 = -5•t + 10

v = -5•t + 10

At t = 2, we have;

v = -5×2 + 10 = 0

The velocity at t = 2 is 0 m/s

The value of the acceleration is the same as the slope, m = a = -5

Given that the initial velocity at t = 2 is 0, we have;

∆x = u•t + 0.5•a•t²

At t = 3, the time of travel from the time t = 2 is 1 seconds, which gives;

∆x = 0×5 + 0.5×(-5)×1² = -2.5

The distance traveled between points, t = 2 and t = 3 is ∆x = -2.5, which is 2.5 meters in the direction opposite to the initial direction.

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Explanation

23.6/100= 0.236

The volume of the balloon after 67 hours would be 119.98 L

mol of he = 4.90 mol

wt. of he = 4.90x 4 = 19.60 g

after 67 hours,

67 x 10 x [tex]10^{-3}[/tex] x 4 = 2.68 g

we know 1 L = 1000 g

so, volume of gas = 2.68 x [tex]10^{-3}[/tex] L

amount left = 16.92 g = 16.92 x [tex]10^{-3}[/tex] L

thus, volume after 67 hours = 119.98 L

A weather balloon, or also known as the sounding balloon, is a specially crafted balloon that is used to carry instruments above to the sky to send back information to the radio signal centres about atmospheric pressure, temperature, humidity and wind speed by means of a small, expendable measuring device called a radiosonde.

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After the core of a sun-like star starts to fuse helium on the horizontal branch, the core becomes hotter.

This stage of stellar evolution is experienced by intermediate-mass stars, or those with masses between 0.8 and 8 M$, which includes the bulk of the galaxy's stars, including the Sun. These stars spend time on the Red Giant Branch after leaving the Main Sequence, where hydrogen burning in a shell around the central core causes their atmospheres to expand. Helium, a byproduct of the hydrogen shell-burning, is deposited in the core, raising its temperature to the point at which the triple alpha process is triggered. Three helium nuclei, often known as "alpha particles," combine during this process to create carbon-12. If this and another helium nucleus fuse, oxygen-16 is created.

The helium flash, which marks the beginning of this helium fusion in the star core, causes the temperature to rise as the radius falls, maintaining a steady luminosity. Stars in this phase are known as Horizontal Branch stars because they travel to the left, roughly horizontally, over the Hertzsprung-Russell diagram as a result of their constant luminosity and rising temperature.

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The only dissimilarity between Coulomb's law and Newton's law of gravitation other than the type of force considered is Newton's law only considers negative force while Coulomb's law considers both forces.

In these contexts, it is considered that repulsive forces are positive and attractive forces are negative. So, Newton's law of gravitation considers gravitational force which only attracts. So, Newton's law of gravitation takes only negative force into account while Coulomb's law considers both electric charges.

According to Newton's law of gravitation,

F = G [tex]m_{1} m_{2}[/tex] / [tex]r^{2}[/tex]

According to Coulomb's law

F = k [tex]q_{1} q_{2}[/tex] / [tex]r^{2}[/tex]

Therefore, the only dissimilarity between Coulomb's law and Newton's law of gravitation other than the type of force considered is Newton's law only considers negative force while Coulomb's law considers both positive and negative forces.

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Answer:

1100 kg

Explanation:

500 lb x 2.20lb (1kg) =1100kg

The solution to the problems in correct significant figures are;

a. 10.8 g - 8.264 g = 2.536 g

b. 4.75 m - 0.4168 m = 4.3332 g

c. 139 cm x 2.3 cm = 319.7 cm²

d. 13.78 g/11.3 mL = 1.22 g/ml

e. 1.6 km + 1.62 m + 1200 cm =  1,613.62 m

Significant figures are used to establish the number which is presented in the form of digits.

a. 10.8 g - 8.264 g = 2.536 g

b. 4.75 m - 0.4168 m = 4.3332 g

c. 139 cm x 2.3 cm = 319.7 cm²

d. 13.78 g/11.3 mL = 1.22 g/ml

e. 1.6 km + 1.62 m + 1200 cm = 1,600 m + 1.62 m + 12 m = 1,613.62 m

Thus, the solution to the problems in correct significant figures are;

a. 10.8 g - 8.264 g = 2.536 g

b. 4.75 m - 0.4168 m = 4.3332 g

c. 139 cm x 2.3 cm = 319.7 cm²

d. 13.78 g/11.3 mL = 1.22 g/ml

e. 1.6 km + 1.62 m + 1200 cm =  1,613.62 m

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When the elevator is at rest, the scale reads 75 kg.

The scale will read higher than when the elevator is at rest if you stand on it as it accelerates upward, making you feel heavier due to the elevator's floor pressing more forcefully on your feet. On the other hand, you feel lighter as the elevator speeds down. The scale will display the normal force, which is less than it was at rest, as N = m(g - a). An elevator scale is being used by a 75 kg individual to demonstrate the issue. The scale reads 100 kg as the elevator starts to rise.

In the case of a rest, the combined force acting on the elevator is caused by the person's mass and Earth's gravitational pull. As a result, the scale reads 75 kg when the elevator is at rest.

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No, you cannot physically touch a person without that person touching you with the same amount of force.

According to Newton's third law of motion, for every action there is an equal and opposite reaction which means that when two objects come in physical contact with each other the exert forces on one another that is equal in terms of magnitude and opposite in terms of direction.

So, in this case you physically touch a person with x amounts of force and basically they exert the same amount of force on you.

Therefore, you cannot physically touch a person without that person touching you with the same amount of force.

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Answer:

Rutherford's experiment

Explanation:

Rutherford's experiment prompted a change in the atomic model. If the positive alpha particles mostly passed through the foil, but some bounced back. AND if they already knew that the electron was small and negative, then the atom must have a small positive nucleus with the electrons around them.

Using the Newton's second law the net force of the runner is 131.25 N

To solve this exercise the formula for net force and the formula for uniformly varied rectilinear motion (UVRM) to be applied are:

Where:

Information about the problem:

Applying the formula for UVRM we can calculate the acceleration of the runner:

a = (vf - vi) /t

a = (7 m/s - 0 m/s) / 4s

a = 7 m/s / 4s

a = 1.75 m/s²

With the acceleration we can apply the net force formula and get:

F = m * a

F = 75 kg * 1.75 m/s²

F = 131.25 N

It is the physical magnitude that expresses the effort necessary to move the mass of one kilogram with an acceleration of one meter per second squared, this is expressed in units of the international system in Newton.

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The resultant internal loading acting on the cross section of C are Normal force of 0 N, Shear force of 233.33 N and Bending moment of 433.325 N.

We know that Moment = Force * Distance.

Given that,

Force along span C = 600 N / m

First chart a free body diagram as shown in Fig 1.

The distributed load along span c is replaced by a point load F at its midpoint.

Force at midpoint of span C = 600 * 2 N

Take moments about point A

Σ [tex]M_{A}[/tex] = 0

-600 * ( 2 ) * [ 1 + ( ( 1 + 1 ) / 2 ) ] + [tex]B_{y}[/tex] ( 4.5 ) - 900 ( 6 ) = 0

- 2400 + 4.5 [tex]B_{y}[/tex] - 5400 = 0

[tex]B_{y}[/tex] = 1733.33 N

Consider a section at Point C and draw a free body diagram as shown in Fig 2.

In fig 2,

[tex]V_{C}[/tex] = Shear force at point C

[tex]N_{C}[/tex] = Normal force at point C

[tex]M_{C}[/tex] = Bending moment at point C

Applying equilibrium condition to the system. Consider equilibrium of Forces along X direction

Σ [tex]F_{x}[/tex] = 0

[tex]N_{C}[/tex] = 0 N

Consider equilibrium of Forces along Y direction

Σ [tex]F_{y}[/tex] = 0

[tex]V_{C}[/tex] - 600 ( 1 ) + [tex]B_{y}[/tex] - 900 = 0

[tex]V_{C}[/tex] = 600 - 1733.33 + 900

[tex]V_{C}[/tex] = 233.33 N

Take moment about point C

Σ [tex]M_{C}[/tex] = 0

- [tex]M_{C}[/tex] - 600 ( 1 ) ( 1 / 2 * 1 ) +  [tex]B_{y}[/tex] ( 2.5 ) - 900 ( 4 ) = 0

- [tex]M_{C}[/tex] - 300 + 2.5 ( 1733.33 ) - 3600 = 0

[tex]M_{C}[/tex] = 433.325 N

The resultant internal loading acting on the cross section are Normal force, Shear force and Bending moment

Therefore, The resultant internal loading acting on the cross section of C are as follows

Normal force [tex]N_{C}[/tex] = 0 N

Shear force [tex]V_{C}[/tex] = 233.33 N

Bending moment [tex]M_{C}[/tex] = 433.325 N

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The time taken by the rock to travel another 67m is 1.5 s.

Taking +y direction downward and y₀= 0, we have y = V₀t+1/2 gt², which (with V₀≠0) yields t= [tex]\sqrt{\frac{2y}{g(a)} }[/tex]

(a) For this part of motion, y₁ = 67m, so that

                           t₁ = [tex]\sqrt{\frac{2(67)}{9.8 m/s^{2} } }[/tex] = 3.7 s

(b) For this next part of motion. we note that the total displacement is

                      y₂= 134m

Therefore, the total time is t₂ = [tex]\sqrt{\frac{2(134)}{9.8m/s^{2} } }[/tex] = 5.2 s

The difference between this and the answer to part (a) is the time required to fall through that second 67m distance:

Δt = t₂-t₁ = 5.2s - 3.7s = 1.5s

Therefore the time taken by the rock to travel another 67m is 1.5 s.

Gravity causes a body to descend faster, and as it does, the air resistance that slows it down rises. This keeps happening until the weight of the object and the force of air resistance are equal.

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The number of p - orbital electrons in cyclopentadienyl anion are

6 electrons.

We have Cyclopentadienyl anion.

We have to determine number of p - orbital electrons in it.

Atomic orbitals are the 3-dimensional spaces around the nucleus where the probability of finding an electron is maximum.

According to the question -

The Cyclopentadienyl Anion is planar and has a continuous overlap of 5 p-orbitals with 6 electrons. It is an aromatic system  which is highly stable and has a closed shell configuration. The deprotonated form of cyclopentadiene is represented as the cyclopentadienyl anion C5H5⁻.

Hence, the number of p - orbital electrons in cyclopentadienyl anion are

6 electrons.

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The correct option is (b) 1.25

The CPI of the project is 1.25. Earned Value (EV) is divided by Actual Cost (AC) to determine CPI.

CPI is calculated as follows: EV / AC. In this case, 250 / 200 = 1.25.

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The density of the metal is 0.006 Kg / [tex]cm^{3}[/tex]

We know that,

ρ = m / V

V = l w h

where,

ρ = Density

m = Mass

V = Volume

l = Length

w = Width

h = Height

Given that,

m = 1.5 kg

l = 17.1 cm

w = 3.2 cm

h = 4.5 cm

V = 17.1 * 3.2 * 4.5

V = 246.24 [tex]cm^{3}[/tex]

ρ = 1.5 / 246.24

ρ = 0.006 Kg / [tex]cm^{3}[/tex]

Density is defined as the amount of matter present in an enclosed boundary. It is represented as ρ.

Therefore, the density of the metal is 0.006 Kg / [tex]cm^{3}[/tex]

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Magnetic flux density - It is the force acting per unit current per unit length on a wire placed to magnetic field at right angle.

It is denoted by B

unit of B is tesla (T)

The total no. of magnetic field lines passing through a area is called magnetic flux.

Magnitude of the magnetic flux - It is equal to the area of the surface and having perpendicular direction to the plane of the surface.

Its unit is weber (Wb)

Direction to the magnetic flux density - The direction is north pole to the south pole.

The magnetic field lines are known as lines of magnetic flux.

flux lines are not in direction of force but perpendicular.

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The kinetic energy and the speed of the electrons ejected by light of wavelength is

To find the Kinetic energy and speed of the electron, the given values are,

Work function of metallic Caesium - 2.14 ev.

The phenomenon in which electrically charged particles are released from or within a material when it absorbs electromagnetic radiation is called Photoelectric effect. When the electrons on the metal plate gets ejected when the light beam passed on the metal plate.

From the basic equation of photoelectric effect we have

hν = Φ + ½ mv²      

where,

hν - hc/ λ ,is the energy of the incident radiation

Φ - work function of the metal

½ mv² - kinetic energy of the emitted electrons

Thus applying values,

1) For wavelength of 580 nanometers, we have

The energy of incident radiation equals,

6.636× 10⁻³⁴× ((3× 10⁸)/(580× 10⁻⁹× 1.6 × 10 ⁻¹⁹)

=2.14 ev

Since the energy of incident radiation is lesser than or equal to the work function of the metal hence no electron's will be emitted.

2. The Kinetic energy can be,

K.E = 6.636× 10⁻³⁴× ((3× 10⁸)/(580× 10⁻⁹) - 2.14 × 1.6 × 10 ⁻¹⁹)

=2.837 ev.

Thus kinetic energy for the wavelength is 2.837 ev.

Speed of the energy  can be calculated as,

υ = √2E/m = √2×2.837×1.6×10⁻¹⁹/(9.8 × 10⁻³¹)

  = 0.9988×10⁶ m/s.

So, the speed of the energy is 0.9988×10⁶ m/s.

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Two locomotives with a speed of 150 km/h each, reach the other in: 1.9 min

The formula of reach time and procedure we will use to solve this problem is:

Tr = x/(v2+v1)

Where:

Information about the problem:

Applying the reach time formula we get:

Tr = x/(v2+v1)

Tr =  9.5 km/(150 km/h + 150 km/h)

Tr = 9.5 km/(300 km/h)

Tr = 0.032 h

By converting the time units from (h) to (min) we have:

0.032 h * (60 min / 1h) = 1.9 min

It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).

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