The rate of acceleration of an object with a mass of 3 kilograms that is pulled by the same force is given as follows:
18 m/s².
What is the relation between force, mass and acceleration?According to Newton's Second Law, the force is given by the multiplication of the mass and of the acceleration, as follows:
F = ma.
The force is obtained as follows, considering a mass of 27 kg and an acceleration of 2 m/s².
F = 27 x 2
F = 54N.
Then the acceleration of an object of 3 kilograms with the same force is given as follows:
3a = 54
a = 54/3
a = 18 m/s².
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Two lines p and q intersect at X at an angle of 34 degrees Let A be a point inside the 34 degrees angle formed by p and q. Let B be the reflection of A through line p, and let C be the reflection of A through line q. Find angle BAC, in degrees.
Angle BAC is equal to 72 degrees, which is calculated by subtracting 2 times the angle of intersection between lines p and q (34 degrees) from 180 degrees.
Given that two lines p and q intersect at X at an angle of 34 degrees
Let A be a point inside the 34 degree angle formed by p and q
Then, let B be the reflection of A through line p, and let C be the reflection of A through line q
To find angle BAC,
we must first understand that a reflection of a point across a line results in an angle equal in measure to its original angle, but on opposite sides of the line of reflection.
In this case, because A is inside the 34 degree angle formed by lines p and q,
angle AXB must be equal to 34 degrees
angle AXC must also be equal to 34 degrees
Therefore, angle BAC must be equal to 180 degrees minus 2 times 34 degrees, or 72 degrees.
In conclusion, the angle BAC is equal to 72 degrees.
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Solve to find the value of n
57,491
1,885
N=?
The value of n from the given equation is 30.5.
What is an equation?In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.
The given equation is 57,491 = 1,885n
The solution of an equation is the set of all values that, when substituted for unknowns, make an equation true.
Now, n=57,491/1885
n=30.5
Therefore, the value of n is 30.5.
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"Your question is incomplete, probably the complete question/missing part is:"
Solve to find the value of n
57,491 = 1,885n
(50 POINTS AND BRAINLYEST)
Find the area of the following shape. Make sure to indicate what shapes were used, by sketching on the image, listing
formulas, and show work listed for each shape. (5 total points – 2 for accurate shapes, 2 for accurate work, 1 for total
area answer)
The total area from given figure is 53.13 square units.
What is area?Area is the amount of space occupied by a two-dimensional figure. In other words, it is the quantity that measures the number of unit squares that cover the surface of a closed figure. The standard unit of area is square units which is generally represented as square inches, square feet, etc.
From the graph, we can see three shapes rectangle with length= 6 units and width= 5 units, triangle with height = 6 units and base = 3 units and semicircle with diameter = 6 units
Here, area of a rectangle is Length×Width
= 6×5
= 30 square units
Area of a triangle = 1/2 ×Base×Height
= 1/2 ×3×6
= 9 square units
Area of a semicircle = πr²/2
= 3.14×3²/2
= 3.14×4.5
= 14.13 square units
Total area = 30+9+14.13
= 53.13 square units
Therefore, the total area from given figure is 53.13 square units.
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Graph the following system of equations.
y = 3x + 9
6x − 2y = 6
What is the solution to the system?
A There is no solution.
B There is one unique solution (−1, −6).
C There is one unique solution (0, −3).
D There are infinitely many solutions.
The given system of simultaneous equations has no solutions.
What is system of simultaneous equations?In mathematics, a set of simultaneous equations, also known as a system of equations or an equation system, is a finite set of equations for which common solutions are sought.
Given is the system of simultaneous equations as -
y = 3x + 9
6x − 2y = 6
Refer to the graph of the equations attached. The value of {x} and {y} for which both the equations are true is given by the point of intersection of both lines. Since both lines are parallel, there is no point of intersection and hence no solution.
Therefore, the given system of simultaneous equations has no solutions.
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construct a 95% confidence interval for the following data set: round to the nearest whole number. sample mean: 1,245 sample standard deviation: 38 sample size: 16
The 95% confidence interval for the population mean is approximately (1,218, 1,271)
A 95% confidence interval for the population mean can be calculated as follows:
Calculate the standard error (SE) of the mean: SE = standard deviation/sqrt (sample size) = 38 / sqrt(16) = 12.56
Use the t-distribution to find the critical value, t*, for a 95% confidence level and degrees of freedom (df) = sample size - 1 = 15.
Calculate the margin of error (ME) as ME = t* * SE = t* * 12.56.
Calculate the lower bound and upper bound of the confidence interval: lower bound = sample mean - ME = 1,245 - ME; upper bound = sample mean + ME = 1,245 + ME.
Since the degrees of freedom for this sample size is quite small, the critical value for t-distribution can be approximated using a t-table for a 95% confidence level and df = 15. The critical value is approximately 2.131.
So, the margin of error is ME = 2.131 * 12.56 = 26.86, and the 95% confidence interval for the population mean is:
Lower bound: 1,245 - 26.86 = 1,218 (rounded to the nearest whole number)
Upper bound: 1,245 + 26.86 = 1,271 (rounded to the nearest whole number)
Therefore, the 95% confidence interval for the population mean is approximately (1,218, 1,271).
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Given the following historical data, what is the simple three-period moving average forecast for period 6?
Period Demand
1 73
2 67
3 66
4 70
5 69
(Keep two decimal places in your answer)
The simple three-period moving average forecast for period 6 is 68.33.
The simple three-period moving average is a method for smoothing out fluctuations in a time series data by taking the average of the three most recent data points. To find the forecast for period 6, we calculate the average of the demand in periods 4, 5, and 6. In this case, the forecast for period 6 is 68.33. To find this, we sum the demand in periods 4, 5, and 6 and divide by 3. (70 + 69 + ?)/3 = 68.33, where the '?' represents the demand in period 6.
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Vanessa earned 76.00 in 8 hours how much is earned a hour
Answer:
She earned $9.50 an hour
Step-by-step explanation:
Answer:
she earned $9.50
Step-by-step explanation:
76.00 ÷ 8 = $9.50
since we know that by theorem, if a is a prime number and if a divides p2, then a divides p, where a is a positive integer)
This is referred to Fermat's Little Theorem, which states that if p is a prime number and a is an integer such that 0 < a < p, then a^(p-1) ≡ 1 (mod p).
In other words, if we raise a to the power of p-1 and divide by p, the remainder will always be 1. This theorem can be used to efficiently test the primality of a number or to find modular inverses in modular arithmetic.
Fermat's Little Theorem is a fundamental result in number theory and has important applications in cryptography and computer science. The theorem states that if p is a prime number and a is an integer such that 0 < a < p, then a^(p-1) ≡ 1 (mod p). This can be expressed as:
a^(p-1) = 1 + kp where k is an integer.
This theorem is a direct consequence of the fact that the set of integers from 1 to p-1 (mod p) form a group under multiplication (mod p). This group is known as the group of units modulo p, and the order of this group is p-1. Hence, a^(p-1) must be congruent to 1 (mod p) since it is the product of all elements in the group.
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The expression 7w + 200 liters are the water level which drops in a particular reservoir in w days. Calculate the water level if today is the 5th day.
The solution is, the water level if today is the 5th day is 235 lit.
What is multiplication?In mathematics, multiplication is a method of finding the product of two or more numbers. It is one of the basic arithmetic operations, that we use in everyday life.
here, we have,
The expression 7w + 200 liters are the water level which drops in a particular reservoir in w days.
then, for 5 days it will be,
7*5 + 200
=35+200
= 235
Hence, The solution is, the water level if today is the 5th day is 235 lit.
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Help!! I need to find the domain and range of this
The domain of the function is [-2, 2) while the range is [4, 2) (along the y -axis).
How to find the domain and range of a function?The domain of a function is the input value for which the function exists while the range is the output value for which the function exists.
here, we have,
For the graph, the domain lie across the x-axis. The domain of the function is [-2, 2) while the range is [4, 2) (along the y -axis).
Note that point where the circles are shaded shows a closed interval
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if there are 28 dogs and 42 cats at a pet daycare, fill out all of the possible ratios of dogs to cats that could be made.
Determine which of the following equations is linear or nonlinear. If the equation is nonlinear, circle all the nonlinear terms. Also, determine the order of each equation and the independent variable used int Show all the work to justify your answer. (Remark: A differential equation is stil called linear when it can be reduced to a linear one despite its different original form. So be extra careful!) ㄧ孛e,.lmt (a) 員411| dt2 dt (b) y, + yy" = 1 (c) ety/ = 1 1+ty =2t
Equations (a) and (c) are linear, while equation (b) is nonlinear.
(a) This is a second order linear differential equation. The order of the equation is 2, and the independent variable used is t. There are no nonlinear terms.
(b) This is a nonlinear differential equation. The order of the equation is 2, and the independent variable used is y. The nonlinear terms are y and y'.
(c) This is a first order linear differential equation. The order of the equation is 1, and the independent variable used is t. There are no nonlinear terms.
Equations (a) and (c) are linear, while equation (b) is nonlinear.
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3. Suppose X is a continuous random variable with probability density function (pdf) fx(x) = cx, 0
The probability density function (pdf) of X can be written as fx(x) = 3x, where 0 < x < 1.
The given probability density function (pdf) is fx(x) = cx, where 0 < x < 1 and c is a constant. To find the value of c, we can use the property that the integral of the pdf over the entire sample space must equal 1, as the sum of all probabilities in the sample space must equal 1. Thus, the equation to find c is:
[tex]\int\limits^1_0{cx} \,dx = 1[/tex]
Solving for c, we have:
c = 3.
Therefore, the pdf of X can be written as fx(x) = 3x, where 0 < x < 1. This function can be used to find probabilities and other statistical measures related to the random variable X.
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The EQUATION for the estimated Least Squares Regression Line for a study on how long equipment will last is AGE in months = -178 + 12 CORE STRENGTH i. What would be the age in months of a unit with a core strength of 100?
The equation is linear, with the independent variable (CORE STRENGTH) being multiplied by 12 and the constant term being -178. The constant term represents the estimated age in months of a unit with a core strength of 0, which is not likely to occur in reality.
The age in months of a unit with a core strength of 100 can be calculated by plugging the value into the equation
AGE in months = -178 + 12 * 100
AGE in months = 12 * 100 - 178
AGE in months = 1200 - 178
AGE in months = 1022
So, the estimated age in months of a unit with a core strength of 100 would be 1022 months.
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On application Rs. 30 On allotment Rs. 40 A Company with an authorized capital of Rs.10,00,000 invited applications for 5,000 share of Rs.100 each at 10% premium. The amounts were payable as follows: On first and final call Rs. 40 There was over subscription and applications were received for 10,000 shares. Allotmen of shares was made as under: To Applicants for 2,000 shares To Applicants for 3,000 shares. To Applicants for 4,000 shares. To Applicants for 1,000 shares. Excess money paid on application was adjusted against sum due on allotment and first and final call. All monies were duly received. ed: Journal entries 1,000 shares allotted 1,000 shares allotted 3,000 shares allotted Nil Ans.: Excess application money transfer to share allotment Rs.1,00,000 and share first and final call Rs.20,000
The journal entries to record the receipt of the application money and its allotment to share capital and Allotment Account are as follows:
Journal Entries:Debit Cash Rs. 300,000
Credit Share Application Account Rs. 300,000
(To record the receipt of the money on application)
Debit Share Application Account Rs. 300,000
Credit Share Capital Rs. 150,000
Credit Share Allotment Account Rs. 150,000
(To record the transfer of the application money to the Share Capital and the Allotment accounts, respectively.)
What are journal entries?Journal entries are the initial records kept of business transactions.
Journal entries are made as transactions occur on a daily basis.
Transaction Analysis:Authorized capital = Rs. 1,000,000
The number of shares issued = 5,000
The par value = Rs. 100
The premium = Rs. 10 (Rs. 100 x 10%)
The issuance price per share = Rs. 110 (Rs. 100 + Rs. 10)
The expected amount to be received on application = Rs. 30 per share
The number of applications received = 10,000
Application money = Rs. 300,000
Excess Application = Rs. 150,000
Cash Rs. 300,000
Share Application Account Rs. 300,000
Share Application Account Rs. 300,000
Share Capital Rs. 150,000
Share Allotment Account Rs. 150,000
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What kind of polynomials is 3x?
Answer:
I believe this is a zero polynomial since it has only one number
Answer:
3x is a monomial
Step-by-step explanation:
Monomial (One term) – 3x
Binomial (Two Term) – 7a-5
Trinomial (Three Term) – x^2-x-2
The mean and standard deviation of the sample data collected on continuous variable x are -0.25 and 0.03, respectively. The following table shows the relative frequencies of the data in the given intervals.
IntervalRelative Frequency−0.34≤x≤−0.31−0.34≤x≤−0.310.02−0.31≤x≤−0.28−0.31≤x≤−0.280.15−0.28≤x≤−0.25−0.28≤x≤−0.250.33−0.25≤x≤−0.22−0.25≤x≤−0.220.36−0.22≤x≤−0.19−0.22≤x≤−0.190.11−0.19≤x≤−0.16−0.19≤x≤−0.160.03
Based on the table, do the data support the use of a normal model to approximate population characteristics?
According to the table, the information does indeed justify using a normal model to approximation population characteristics.
Explain about the normal model of approximation?Since it is frequently simpler to utilize the area there under normal curve than to add together multiple discrete values, this normal approximation is employed to estimate probabilities. The discrete binomial distribution, however, can have statistical characteristics that are dissimilar from those of the normal distribution, as demonstrated in the second article.The answer to the query is:
The following numbers are one standard deviation away:
= 0.33 + 0.36
= 0.69
According to the empirical rule, this value is:
= 0.68
As a result, and in accordance with the empirical rule, the quantities were always 0.95 with two standard deviations. Consequently, the data's empirical rule was followed.
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The correct question is-
The mean and standard deviation of the sample data collected on continuous variable x are −0.25 and 0.03, respectively. The following table shows the relative frequencies of the data in the given intervals.
Based on the table, do the data support the use of a normal model to approximate population characteristics?
Richard has 17 coins with a value of 76 cents. The coins are nickels, dimes, and pennies. He has twice as many pennies as dimes. How many nickels does Richard have?
There are 8 nickels does Richard have.
What is an expression?Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.
We have to given that;
Richard has 17 coins with a value of 76 cents.
And, The coins are nickels, dimes, and pennies. He has twice as many pennies as dimes.
Now, Let p = number of pennies
n = number of nickels
d = number of dimes
Hence, We can formulate;
⇒ p(1) + n(5) + d(10) = 76
⇒ p + 5n + 10d = 76 .. (i)
Here, He has twice as many pennies as dimes.
⇒ p = 2d
And, Richard has 17 coins.
⇒ p + d + n = 17 .. (ii)
Substitute p = 2d in equation (i) and (ii),
⇒ p + 5n + 10d = 76
⇒ 2d + 5n + 10d = 76
⇒ 5n + 12d = 76 .. (iii)
⇒ p + d + n = 17
⇒ 2d + d + n = 17
⇒ n + 3d = 17 .. (iv)
Solve equation (iii) and (iv), we get;
⇒ d = 3
⇒ n = 8
Hence, There are 8 nickels.
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ANSWER TO GET BRANLIEST!!!A soda company would like to replace the label on a can of soda with a radius of 4 and one fourth cm. If the label touches end to end with no overlap, what is the length of the label? Use 22 over 7 for π.
Step-by-step explanation:
The circumference of the can is 22/7 * 4 = 88/7 cm.
Since the label needs to touch end-to-end with no overlap, the length of the label is equal to the circumference of the can, so it is 88/7 cm.
Graciela begins the month with $300 and is spending $20 per
week. Her brother Sergio begins the month with $150 and is saving $10 per week. Sergio wants to know when they will have the same amount of money.
W
Let represent the number of weeks since the beginning of the
month. Which equation represents this situation?
Answer:
300-20w=?
150+10w=?
Step-by-step explanation:
Answer:
Step-by-step explanation:
320
In a rectangle the ratio of the length to the width is 5 to 2 the length of the rectangle is 12.5 feet what are the perimeter and the area of the rectangle
Answer:
62.5 square feet
Step-by-step explanation:
Let's call the width of the rectangle w. Since the ratio of the length to the width is 5 to 2, the length can be expressed as 5/2 times the width:
l = 5/2 * w
We know the length is 12.5 feet, so we can use that information to solve for the width:
12.5 = 5/2 * w
w = 12.5 * 2/5
w = 5
The width of the rectangle is 5 feet.
The perimeter of the rectangle is calculated by adding up the lengths of all four sides:
p = 2 * (l + w)
p = 2 * (12.5 + 5)
p = 2 * 17.5
p = 35
The perimeter of the rectangle is 35 feet.
The area of the rectangle is calculated by multiplying the length and width:
a = l * w
a = 12.5 * 5
a = 62.5
The area of the rectangle is 62.5 square feet.
Find the area of the figure on the right.
Find the perimeter of the figure on the right.
Use 3.14 for
Please show work
The perimeter of the figure on the right is 40.26 yrd. .
What is perimeter?A perimeter is a closed path that encompasses, surrounds, or outlines either a two dimensional shape or a one-dimensional length. The perimeter of a circle or an ellipse is called its circumference. Calculating the perimeter has several practical applications.
Perimeter refers to the total outside length of an object.
here, we have,
from the given figure we get,
the radius of the circle = 6 yrd.
then, the perimeter = 2*pi* 6
= 37.68 yrd.
now, the figure is 3/4 th of the circle,
so, perimeter = 37.68 * 3/4 + 12
= 40.26 yrd.
Hence, The perimeter of the figure on the right is 40.26 yrd. .
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How much did Speedy Movers borrow for a debt that accumulated to $52,467.60 in four years? The interest rate was 4.68% compounded semi-annually.
The amount (present value) that Speedy Movers borrowed for a debt that accumulated to $52,467.60 in four years was $43,604.16.
What is the difference between the present value and future value?The present value is the amount that Speedy Movers borrowed four years ago at 4.68% interest compounded semi-annually to accumulate to a future value of $52,467.60.
The present value is determined using discounting while the future value is computed by compounding.
We can determine both the present value and the future value using an online finance calculator.
N (# of periods) = 8 semiannual periods (4 years x 2)
I/Y (Interest per year) = 4.68%
PMT (Periodic Payment) = $0
FV (Future Value) = $52467.60
Results:
Present Value (PV) = $43,604.16
Total Interest = $8,863.44
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In ΔHIJ, i = 2.8 inches, mm∠I=68° and mm∠J=50°. Find the length of j, to the nearest 10th of an inch.
The measure of the j of triangle ΔHIJ is given by the law of sine and is given by j = 2.3 inches
What is the law of sines?The relationship between a triangle's sides and angles is provided by the Law of Sines. Trigonometry's law of sines can be expressed as a/sinA = b/sinB = c/sinC, where a, b, and c are the lengths of the triangle's sides, and A, B, and C are the triangle's respective opposite angles.
Law of Sines :
a / sin A = b / sin B = c / sin C
Given data ,
Let the triangle be represented as ΔHIJ
Now , the equation will be
The measure of i = 2.8 inches
The measure of ∠I = 68°
The measure of j = j
The measure of ∠J = 50°
Now , from the law of sines , we get
a / sin A = b / sin B
Substituting the values in the equation , we get
2.8 / sin ( 68 )° = j / sin ( 50 )°
On simplifying the equation , we get
2.8 / 0.92718 = j / 0.766044
Multiply by 0.766044 on both sides of the equation , we get
j = 3.0198972 x 0.766044
On further simplification , we get
j = 2.3 inches
Hence , the measure of j of triangle is 2.3 inches
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Which of the following measures would create an infinite number of triangles?
three angles: 62°, 34°, and 84°
three sides: 3 cm, 5 cm, and 10 cm
two sides of 4 cm and 7 cm with an angle of 54° between them
three sides: 3 cm, 5 cm, and 7 cm
Answer:
(a) three angles: 62°, 34°, and 84°
Step-by-step explanation:
You want to know which specification can result in an infinite number of triangles.
Angles onlyIf only the angles are specified, the sides can have an infinite number of (related) lengths.
three angles: 62°, 34°, and 84° will create an infinite number of triangles
Sides onlyAssuming the side lengths can form a triangle, they will specify exactly one triangle.
Lengths 3 cm, 5 cm, and 10 cm cannot form a triangle.
Sides and angle betweenWhen two sides are specified along with the angle between them, exactly one triangle can be formed.
find and solve x and y.
Answer:
x and Y 5=(a+5)
Step-by-step explanation:
...................
Isaac is buying ingredients to bake 4 batches of chocolate chip walnut cookies, and each batch requires 1 bag each of chocolate chips and walnuts. His receipt shows a total of $17.92. He remembers that the chocolate chips were $2.59 per bag, but he can't remember how much each bag of walnuts costs. How can Isaac determine the cost per bag of walnuts? Match each step of the arithmetic solution with the correct description. Step 1 Step 2 :: Divide 17.92 by 4. II :: Subtract 2.59 from 4.48. :: Add 2.59 to 4.48. :: Multiply 17.92 by 4. :: Subtract 2.59 from 71.68.
The cost of each bag of walnut can be determined following the below steps and each bag of walnut is $1.89
What is the cost of each bag of walnut?Total receipt= $17.92
4 batches of chocolate chip walnut cookies requires 4 bags each of chocolate chips and walnuts if each batch requires 1 bag each of chocolate chips and walnuts
Cost of chocolate chips = $2.59
Cost of 4 bags of chocolate chips = 4($2.59)
= $10.36
Total cost of 4 bags of walnuts = Total receipt - Cost of 4 bags of chocolate chips
= $17.92 - $10.36
= $7.56
Cost of each bag of walnut= Total cost of 4 bags of walnuts / 4
= $7.56 / 4
= $1.89
Therefore, each bag of walnut cost $1.89
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Answer: Step 1: Divide 17.92 by 4
Step 2: Subtract 2.59 from 4.48
Step-by-step explanation:
What is halfway between 39.8 and 39.81
Answer: 39.805
Step-by-step explanation: 39.81 - 39.8 = 0.01
0.01 x 0.5 = 0.005
39.8 + 0.005 = 39.805
Dilate pint C using center D and scale factor 3/4
The dilations relation is C'D = (3/4)CD.
How does dilation works?Dilation of a figure will leave its sides get scaled (multiplied) by same number. That number is called the scale factor of that dilation.
Its also called scaling of a figure, but due the involvement of coordinates, it involves a center of a dilation, which is like a pinned point which stays at same place after dilation.
Its like we enlarge or shorten the size of the figure (or keep it same, when scale factor = 1).
Given;
First, we want to dilate point C using D as the center of dilation with a scale factor = 3/4.
This only means that we will have the new point C', such that:
C'D = (3/4)*CD
Where CD is the distance between points C and D
Therefore, the dilation will be C'D = (3/4)*CD.
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consider the following code segment, which is intended to store the sum of all multiples of 10 between 10 and 100, inclusive (10 20 ... 100), in the variable total. int x
The missing code that can be used to replace / missing code / so that the code segment works as intended is x >= 10.
The code segment is intended to store the sum of all multiples of 10 between 10 and 100, inclusive. The value of x starts at 100 and is decremented by 10 on each iteration of the loop, until it reaches 10. The sum of all the multiples of 10 between 10 and 100 is stored in the variable total.
The missing code in the while statement determines when the loop will stop. If we use x >= 10 as a replacement for / missing code /, the loop will run as long as x is greater than or equal to 10. When x reaches 10, the loop will stop.
Here's the complete code:
int x = 100;
int total = 0;
while(x >= 10)
{
total = total + x;
x = x - 10;
}
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Your question is incomplete but probably the complete question is:
Consider the following code segment, which is intended to store the sum of all multiples of 10 between 10 and 100, inclusive (10 + 20 + ... + 100), in the variable total.
int x = 100;
int total = 0;
while( / missing code / )
{
total = total + x;
x = x - 10;
}
Which of the following can be used as a replacement for / missing code / so that the code segment works as intended?
A x < 100
B x <= 100
C x > 10
D x >= 10
E x != 10