i am a 5-digit numaeral for five raised to the sixth power.what number am i?​

Answer:

[tex]\boxed{3} \;v^2 + \boxed{4}\;v + \boxed{5}[/tex]

Step-by-step explanation:

Original expression: 3 + v + 4v² + 2 - v² +3v

Combining like terms in a equation means grouping them together to get a single instance of that term instead of multiple

For example in this expression we can see there is a +4v² and a -v². Group these together and simplify algebraically to get a single v² expression. Do the same with the others.

3 + v + 4v² + 2 - v² +3v

Group the v² terms together to get 4v² - v² = 4v² - 1v² = 3v²  (v² == 1v²)
(since the variables are same we can simply add the coefficients

Now group the v terms and simplify

3 + v + 4v² + 2 - v² + 3v
v + 3v = 4v

Finally group the constants
3 + v + 4v² + 2 - v² +3v
3 + 2 = 5

So the final expression is

3v² + 4v + 5

The numbers are what you put in the boxes for each

Usually this process is done in a few steps
3 + v + 4v² + 2 - v² +3v

= (4v² - v²) + (v + 3v) + (3 +2)
= 3v² + 4v + 5

The water level decrease each day is A. 0.25 in.

From the information, the water level in a swimming pool decreases from 60 inches to 58.25 inches in one week.

There are 7 days in a week.

Therefore, the rate if decrease per day will be:

= (60 - 58.25)/7

= 1.75 / 7

= 0.25

Therefore, the correct option is A.

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so you write 16 but i don't speak English very good i want help you 2(6+3)-2 ok you you going multiplying 2×6=12+6=18-2=16 so 16

Step-by-step explanation:

13 is the answer that is need

The angles are 19;  101

Parallel lines are lines in a plane that are always the same distance apart. Parallel lines never intersect.

Given:

x+4, 9x-34

As, the lines are parallel

x+4 + 9x -34 = 180

10x + 30 = 180

10x = 150

x= 150/10

x=15

Hence, the angles are x+4 = 19; 9x-34 = 135 - 34 = 101

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Answer:

1/2

Hope this helps with your question :)

Answer:

I believe the answer is C

Step-by-step explanation:

I think this because I gathered the info of -650, -872, and 50

===================================================

Explanation:

Compare the equation

[tex]y = (x-2)^2 - 4[/tex]

to the vertex form

[tex]y = a(x-h)^2 + k[/tex]

we have:

The vertex is located at (h,k) = (2, -4). Nice job on getting the correct answer for the vertex.

The axis of symmetry is x = 2 since the axis of symmetry goes through the vertex. It's the vertical mirror line.

Because a = 1 is positive, the parabola opens upward. It forms a bowl shape. The vertex is the lowest point.

If a < 0, then the parabola would open downward and have a highest point.

The fractions represented as power of ten are:

a. 1×(10)⁻³

b. 7× (10)⁻⁵

c. 1 × (10)⁻⁶

d. 5 × (10)⁻⁵

Given :

a. 1/1000

we know that 1/(10)³

when we take the reciprocal, the sign changes  from positive to negative.

that is, 1×(10)⁻³

b. 7/100000

we know that 7/(10)⁵

likewise, we get

that is, 1×(10)⁻⁵

c. 1/10000000

we know that 1/(10)⁷

reciprocate it, we get

1×(10)⁻⁷

d. 3/60000

rearrange it.

3/6×10000

divide it.

1/2×10000

divide and multiply by 10.

10/2×10000×10

multiply it.

5/100000

5 × (10)⁻⁵

Hence we calculated the given fractions as powers of ten.

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The Constant of proportionality represented in equation is 4.75

The Constant of Proportionality defines the value which will remain constant in the whole system of equations. In the given equation, Liv earns $9.50 for selling every two bracelets. The equation represents the sale of Liv on the basis of its price and quantity and the Total amount that she gets. The equation is represented as y = 4.75x

Here, y is the total amount she gets, x is the number of pieces that she sold, and 4.75 is the constant of proportionality. In this case, the constant can be defined as the price of one bracelet that she sells.

This constant can be derived by simply dividing the total amount by the total number of pieces that she sells. It can be represented by :

               => y/x = c , where c is the constant

               => 9.5/2 = c  => c = 4.75

Hence, the Constant of Proportionality is 4.75.

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The correct option is B: The larger rectangle can have the length of 7, width 9+9 and the area 7×9 + 7×9.

The two rectangle are given with the same dimensions.

The length are given as 9 and 7.

The, both rectangle are placed such that they forms the larger rectangle;

The placing is such that side with the length of 9 units are joined together.

Thus, the new width of the rectangle will be; 7 + 7.

The length of rectangle will remain same of 9 units.

The area of rectangle = length x breadth

area of larger rectangles = 7×9 + 7×9.

Therefore, the option which correctly points the condition is option B.

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Option A.  [tex]Y = 3(2)^{X}[/tex]

Here, looking at the graph we can see that when x = 0, the value of y will be 3. Thus, (0, 3) is a solution to the given function.

Putting x = 0 in the given options, we see that

A. y = 3(1) = 3 (as anything raised to the power is 1)

B. y = 2(1) = 2

C. y = 4(1) = 4

D. y = 3(1) = 3

Thus, we can eliminate option B and C as (0, 3) does not satisfy these equations.

Now, if we take x = 1, from the graph we can see that the value of y will be 6.

Substituting x = 1 in the remaining two options, we get

A. y = 3(2) = 6

D. y = 3(4) = 12

Thus, D is also eliminated.

Option A, y = 3(2)^x is the correct answer.

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The two most frequent normality tests for assessing a normal distribution are Shapiro-test Wilk's and Kolmogorov-Smirnov test.

A probability distribution that is symmetric around the mean is referred regarded as having a "normal distribution." In certain instances, it is also referred to as the "Gaussian distribution." This demonstrates that data that are near to the mean are more common than data that are far from the mean.

The two most popular normality tests are the Kolmogorov-Smirnov test and the Shapiro-test Wilk's test.

Therefore, Shapiro-and Wilk's Kolmogorov-Smirnov tests are the two normality tests used the most frequently to evaluate a normal distribution.

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Answer:

19, 29, 29, 37, 41

Step-by-step explanation:

1. What we know: x y 29 z 41

(x+y+29+z+41)/5 =31

x y and z each >9 and prime

Possibile numbers: 11, 13, 17, 19, 23, 29, 31, 37, 41

2. (x+y+29+z+41)/5 =31

x+y+29+z+41 = (31×5)

x+y+z = (31×5) -29 -41

x+y+z = 85

z>=29

x<=29

y<=29

x and y can be 11, 13, 17, 19, 23, 29

z could be 29, 31, 37, 41

At least one if them must equal 29 because it's the mode.

So two of them must equal 56

11+29=40 so both numbers cannot be less than or equal to 40

This means y is 29 because x + z has to equal 56 and that wouldn't be possible if x equals 29.

Now we know x+z=56

Possible numbers: 19+37

I found these by doing 56- each possible number for x and seeing if that equaled a possible number for z. For example 56-11=45 but z cannot be 45 therefore x cannot be 11 and so on.

Then you just plug in the numbers!

19, 29, 29, 37, 41

This was so much fun to solve! I hope this is helpful, let me know if you have any questions! You got this :)

Anna's weight is 115 pounds and Janet's weight is 135 pounds.

To find the wight of Anna and Janet:

It is assumed:

Also,

So,

Subtraction of both sides by 20 yields:

By dividing both sides by 2, we get:

So, Anna's weight is 115 pounds and Janet's weight is 115+20=135 pounds.

Therefore, Anna's weight is 115 pounds and Janet's weight is 135 pounds.

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Answer:The angles in a triangle add up to 180 degrees

Consider the composite function g (f (x)) = x startroot 6 endroot. if f(x) = 3x2,  g (x) = StartRoot 2 x EndRoot.

What is squareroot?

Example of a square root-

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This type of sum is Liquidated damages.

Liquidated damages are presented in certain legal contracts as an estimate of otherwise intangible or hard-to-define losses to one of the parties.

As per the given situation we have

parties to a sales contract have stipulated that a specific sum be paid by any party

Liquidated damages occur in such a situation.

The amount of damages that the parties estimate and agree upon at the time of the contract for a breach of the agreement by either party is referred to as liquidated damages.

Regardless of the actual cost of any potential damages due to the breach of the contract, this amount becomes due immediately.

According to Section 74 of the Indian Contract Act, 1972, if parties agree a sum to be paid as damages or a penalty to be imposed for a breach, the harmed party is only entitled to that sum or penalty and no other higher or lesser sum.

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Answer:

never

Step-by-step explanation:

-1=0 is not possible

======================================================

Work Shown:

20% of $9.50 = 0.20*9.50 = 1.90

You earn an extra $1.90 on top of the $9.50 already there. So the new wage is 9.50 + 1.90 = 11.40 dollars per hour

-----------

Shortcut:

1.20*9.50 = 11.40

Think of 1.20 as 100% + 20% = 1 + 0.20 = 1.20, and this represents an increase of 20%

Answer:

What does x=

Solve for x

x=25

Answer:

Step-by-step explanation:

(5x+10)+(2x-5)= 180°

first we simplify as much as possible

so, we can add 5x + 2x to get 7x

then we do 10-5 which equals 5.

now we have

7x+5=180

subtract 5 from both sides

7x= 175

x=25

now we input x into <ABD

5x+10

5(25)+10

125+10

130

<ABD=130°

The locations of the vertices are shown below:

Herein we find four representations of polygons on Cartesian plane and we must determine the coordinates of the images generated by translation, a kind of rigid transformations. Translation is described by the following operation:

P'(x, y) = P(x, y) + T(x, y)

Where:

Case 1 (K(x, y) = (3, - 3), X(x, y) = (4, - 3), R(x, y) = (3, - 5), T(x, y) = (- 8, 7))

K'(x, y) = (3, - 3) + (- 8, 7) = (- 5, 4)

X'(x, y) = (4, - 3) + (- 8, 7) = (- 4, 4)

R'(x, y) = (3, - 5) + (- 8, 7) = (- 5, 2)

Case 2 (E(x, y) = (0, 2), X(x, y) = (3, 3), V(x, y) = (4, 0), Z(x, y) = (2, - 4), T(x, y) = (- 4, - 1))

E'(x, y) = (0, 2) + (- 4, - 1) = (- 4, 1)

X'(x, y) = (3, 3) + (- 4, - 1) = (- 1, 2)

V'(x, y) = (4, 0) + (- 4, - 1) = (0, - 1)

Z'(x, y) = (2, - 4) + (- 4, - 1) = (- 2, - 5)

Case 3 (G(x, y) = (- 4, 5), J(x, y) = (- 3, 4), U(x, y) = (- 5, 2), T(x, y) = (6, 0))

G'(x, y) = (- 4, 5) + (6, 0) = (2, 5)

J'(x, y) = (- 3, 4) + (6, 0) = (3, 4)

U'(x, y) = (- 5, 2) + (6, 0) = (1, 2)

Case 4 (V(x, y) = (0, 0), Y(x, y) = (- 5, 2), F(x, y) = (- 3, 4), T(x, y) = (3, - 5))

V'(x, y) = (0, 0) + (3, - 5) = (3, - 5)

Y'(x, y) = (- 5, 2) + (3, - 5) = (- 2, - 3)

F'(x, y) = (- 3, 4) + (3, - 5) = (0, - 1)

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Answer:

See attachments.

Step-by-step explanation:

A translation is a type of transformation that moves a figure left, right, up or down.  Every point on the original figure is translated (moved) by the same distance in the same direction.

Coordinates of the given pre-image:

Given mapping rule:

[tex](x, y) \rightarrow (x-8, y+7)[/tex]

This tells us to subtract 8 from the x-values and add 7 to the y-values.

[tex]\sf \implies K(3,-3) \rightarrow K'(3-8, -3+7)=K'(-5,4)[/tex]

[tex]\sf \implies R(3,-5) \rightarrow R'(3-8, -5+7)=R'(-5,2)[/tex]

[tex]\sf \implies X(4,-3) \rightarrow X'(4-8, -3+7)=X'(-4,4)[/tex]

Coordinates of the given pre-image:

Given mapping rule:

[tex](x, y) \rightarrow (x-4, y-1)[/tex]

This tells us to subtract 4 from the x-values and subtract 1 from the y-values.

[tex]\sf \implies E(0,1) \rightarrow E'(0-4, 1-1)=E'(-4,0)[/tex]

[tex]\sf \implies X(3,3) \rightarrow X'(3-4, 3-1)=X'(-1,2)[/tex]

[tex]\sf \implies V(4,0) \rightarrow V'(4-4, 0-1)=V'(0,-1)[/tex]

[tex]\sf \implies Z(2,-4) \rightarrow Z'(2-4, -4-1)=Z'(-2,-5)[/tex]

Coordinates of the given pre-image:

Given mapping rule:

[tex](x, y) \rightarrow (x+6, y)[/tex]

This tells us to add 6 to the x-values and the y-values remain unchanged.

[tex]\sf \implies G(-4,5) \rightarrow G'(-4+6, 5)=G'(2,5)[/tex]

[tex]\sf \implies J(-3,4) \rightarrow J'(-3+6, 4)=J'(3,4)[/tex]

[tex]\sf \implies U(-5,2) \rightarrow U'(-5+6, 2)=U'(1,2)[/tex]

Coordinates of the given pre-image:

Given mapping rule:

[tex](x, y) \rightarrow (x+3, y-5)[/tex]

This tells us to add 3 to the x-values and subtract 5 from the y-values.

[tex]\sf \implies F(-3,4) \rightarrow F'( -3+3, 4-5)=F'(0,-1)[/tex]

[tex]\sf \implies V(0,0) \rightarrow V'( 0+3, 0-5)=V'(3,-5)[/tex]

[tex]\sf \implies Y(-5,2) \rightarrow Y'( -5+3, 2-5)=Y'(-2,-3)[/tex]

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The amount of money the women had in the beggining was $75.

Let the total amout of money the women had intially be x.

According to the questio.

A woman went shopping and spent 2/3 of all the money she had. Then she lost 3/5 of what she had left after shopping.

So, the amount of money she spent for shopping = (2/3)x = 2x/3

⇒ The amount of money she had after shopping

= x -2x/3

= 3x -2x/3

= x/3

Now, the amount of money she lost 3/5 × (x/3) = x/5

⇒ Amount of money she have after the lost of money

= x/3  - x/5

= 5x - 3x /15

= 2x/15

It is given that she have $10.

⇒ 2x/15 = 10

⇒ 2x = 150

⇒ x = 150/2

⇒ x = $75

Hence, the amount of money the women had in the beggining was $75.

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The given system is not consistent.

Given system of equations are:

[tex]x_1+x_2+x_3=7\\x_1-x_2+2x_3=7\\2x_1+3x_3=15[/tex]

Here the indeterminants are [tex]x_1,x_2,x_3[/tex]. A system of equations is consistent if it has at least one set of solution values for the indeterminants.

So we try to solve the above system of equations.

Subtracting the first two solutions, we get,

[tex](x_1+x_2+x_3)-(x_1-x_2+2x_3)= 0[/tex]

⇒ [tex]2x_2-x_3=0[/tex]

⇒ [tex]x_3=2x_2[/tex]

Rewriting all the three equations using this substitution,

[tex]x_1+x_2+2x_2=7\\x_1-x_2+4x_2=7\\2x_1+6x_2=15[/tex]

This implies,

[tex]x_1+3x_2=7\\x_1+3x_2=7\\2x_1+6x_2=15[/tex]

Since the first two equations are same, we need to solve the equations,

[tex]x_1+3x_2=7\\2x_1+6x_2=15[/tex]

Multiplying the first equation by 2 and then subtracting, we get,

0 = -1, which is impossible.

So the system has no solutions.

Hence the system is inconsistent.

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Answer:

C is correct

Step-by-step explanation: please let me know if it was rong