Palmitate, Laurate, and Arachidate: (2.1, 1.6, and 2.6) nm
Clarification:
The C-C bond measures 1.5 A°, or 0.15 nm.
Tetrahedron bond angle = 109 °C
Trigonometrically, the distance between the first and third carbons in an acyl chain is 0.26 nm, while the distance between the first and second carbons is 0.26/2 = 0.13. (Length extended by each methylene group)
Palmitate's (16 carbon) fully expanded length is therefore equal to 16*0.13 or ~2.1 nm.
Similar to this, the length of a fully expanded laurate (12 carbon) is equal to 12*0.13 and is 1.56 nm or ~1.6nm.
Arachidate (20 carbon) fully expanded length equals 20*0.13 = 2.6 nm.
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what is the difference between intramolecular and intermolecular?
The difference between intramolecular and intermolecular is described below.
What is inter and intra molecular?Intramolecular means between different parts of the same molecule while intermolecular denotes from one molecule to another i.e. between molecules.
Based on the above definition, it can be said that intramolecular forces are the forces that hold atoms together within a molecule while intermolecular forces are forces that exist between molecules.
For example, the force that holds oxygen and hydrogen atoms together in water molecule is called intramolecular force while the force that holds two water molecules together is intermolecular force.
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when 17.08 g of an unknown non-electrolyte is dissolved in 50.0 g of carbon tetrachloride, the boiling point increased to 82.1 degrees c from 76.5 degrees c. if the kbp of the solvent is 4.95 k/m, calculate the molar mass of the unknown solute.
The molar mass of the unknown non-electrolyte solute is 19.47 g/mol.
The boiling point elevation can be used to calculate the molality of the solution, which is defined as the number of moles of solute per kilogram of solvent. This can then be used to calculate the molar mass of the solute.
The formula for boiling point elevation is:
ΔTb = Kb x molality
where ΔTb is the change in boiling point, Kb is the boiling point elevation constant for the solvent, and molality is the number of moles of solute per kilogram of solvent.
First, we need to calculate the molality of the solution:
molality = ΔTb / Kb
molality = (82.1°C - 76.5°C) / 4.95 K/m
molality = 0.0177 m
Next, we can calculate the number of moles of solute in the solution:
moles = molality x mass of solvent
moles = 0.0177 m x 50.0 g / 1000 g/kg
moles = 0.88 g
Finally, we can calculate the molar mass of the solute:
molar mass = mass of solute / moles
molar mass = 17.08 g / 0.88 moles
molar mass = 19.47 g/mol
Therefore, the molar mass of the unknown non-electrolyte solute is 19.47 g/mol.
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A 251 mL aqueous solution containing 0.400 g of an unknown polymer has an osmotic pressure of 26.9 torr at 30.0 °C. What is the molar mass of the polymer?
The response to the question is that the polymer's molar mass is (7.99 × 10^-3 g/torr-L)
What are molar mass and a mole?Avogadro's quantity (6.022 x 1023) of atoms or formula units make up one mole of a substance. The volume of mole of a substance of a chemical is indicated by its molar mass.
The Van 't Hoff method may be used to get the polymer's molarity from its osmotic pressure: = iRT/V.
where P is the gas constant, I the van 't Hock factor (number of nanoparticles per molecule), R the osmotic, T the temp in Kelvin, and V the volume a mole of solute occupies.
By rewriting the equation and inserting therefore first, one may get the molar mass (M):
Substituting the given values:
M = (i)(0.0821 Latm/molK)(303 K)/(26.9 torr)(0.251 L) =
7.99 × 10^-3 g/torr-L
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The nucleus contains protons and _________.
Responses
A electronselectrons
B neutrons
The nucleus contains protons and neutrons.
A electrons
B neutrons
how many grams of co2 are contained in 2 liters of sparking water that was prepared at a pressure of 2.4 atm (25 c). the density of the solution is 1.10 g/ml.
[tex]5.76 grams[/tex] of CO2 are included in 2 litres of sparkling water.
At 2.4 atm (25 °C), 2 litres of sparkling water have a capacity of 2.4 litres.
Following is the mass of CO2 in 2 litres of sparkling water:
[tex]1.10 g/ml * 2.4 atm *2.4 litres\\ \\= 5.76 g of CO2[/tex]
2 litres of sparkling water have [tex]5.76 grams[/tex] of CO2 in them.
Sparkling water and still water both hydrate. All sparkling waters, however, are not made equal. It's important to read the nutrition label before purchasing a sparkling water product since some may include extra sugars or artificial sweeteners. Dehydration can be aided by sparkling water.Chronic dehydration can result in constipation, cardiac and kidney issues, as well as digestive issues.
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what is 25.0 g sample of warm water at 40.0⁰c was added to a 25.0 g sample of water in a styrofoam coffee cup calorimeter initially at 20.0⁰c. the final temperature of the mixed water and calorimeter was 29.5⁰c. calculate the heat capacity of the coffee cup calorimeter. the specific heat of water is 4.184 j/g∙⁰c?
Answer:
2024.70 J
Explanation:
The heat capacity of the coffee cup calorimeter can be calculated using the following formula:
q_calorimeter = q_water + q_water_final
where q_calorimeter is the heat absorbed by the coffee cup calorimeter, q_water is the heat lost by the warm water, and q_water_final is the heat gained by the cold water.
First, calculate q_water:
q_water = m_water * c_water * ΔT
where m_water = 25.0 g is the mass of the warm water, c_water = 4.184 J/g°C is the specific heat of water, and ΔT = (40.0°C - 29.5°C) = 10.5°C is the change in temperature.
q_water = 25.0 g * 4.184 J/g°C * 10.5°C = 1057.35 J
Next, calculate q_water_final:
q_water_final = m_water * c_water * ΔT
where m_water = 25.0 g is the mass of the cold water, c_water = 4.184 J/g°C is the specific heat of water, and ΔT = (29.5°C - 20.0°C) = 9.5°C is the change in temperature.
q_water_final = 25.0 g * 4.184 J/g°C * 9.5°C = 967.35 J
Finally, calculate the heat capacity of the coffee cup calorimeter:
q_calorimeter = q_water + q_water_final = 1057.35 J + 967.35 J = 2024.70 J
So the heat capacity of the coffee cup calorimeter is 2024.70 J.
Does the temperature rise or drop in the thermosphere?
Temperature in thermosphere increases with increase in altitude.
Layers of the atmosphere are troposphere, stratosphere, mesosphere and thermosphere. The thermosphere is the uppermost layer of the Earth's atmosphere which ranges from 90 km to 600 km, located above the mesosphere and below the exosphere.
Thermosphere has very low atmospheric density due to this it is highly energetic with many ions and electrons. Even if the atmospheric density is very low in the thermosphere the temperature was actually increased in a dramatic manner.
While the temperature rises in the thermosphere, the overall energy density is low, making it feel cold to the touch. Heat is not effectively transferred to the lower atmospheric layers in the absence of convection.
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an aerosol can is at a pressure of 8.6 atm at a temperatue of 22.6 c. it is then placed in a fire and the pressure rises to 39.3 atm. what is the temperature of the fire?
According to Gay-Lussac's law, the temperature of the fire at 39.3 atmospheres is 1350.82 Kelvin.
What is Gay-Lussac's law?It is defined as a gas law which states that the pressure which is exerted by the gas directly varies with its temperature and at a constant volume.The law was proposed by Joseph Gay-Lussac in the year 1808.
The pressure of the gas at constant volume reduces constantly as it is cooled till it undergoes condensation .It is given as, P₁/T₁=P₂/T₂, thus T₂= 295.6×39.3/8.6=1350.82 kelvin
Thus, the temperature of the fire at 39.3 atmospheres is 1350.82 Kelvin.
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Calculate the percent composition of O in K3PO4
The percent composition of oxygen in tripotassium phosphate is 30.15%.
What is percent composition?Percent composition is defined as a convenient way to record concentration of solution.It is a expression which relates mass of an element to compound as,mass of element/mass of compound ×100.
In the given compound of tripotassium phosphate the molar mass is 212.27 g/mole, while that of oxygen is 16×4=64 g/mole.Thus, the percent composition of oxygen in tripotassium phosphate is 64/212.27×100=30.15%.
Thus, the percent composition of oxygen in tripotassium phosphate is 30.15%.
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what volume should you write in your lab book if the meniscus in the buret is exactly between the 11 ml graduated mark and the 12 ml graduated mark?
If the meniscus is between 11 mL and 12 mL, the volume can be estimated as 11.5 mL.
A buret is a laboratory tool used to dispense and measure the volume of liquid. It has a cylindrical shape and graduated marks along its length to indicate the volume of liquid it contains. To measure the volume of liquid, the meniscus, the curved surface of the liquid, is read at the lowest point.
When the meniscus is exactly between two graduated marks, the volume can be estimated by taking the average of the two marks. In this case, if the meniscus is between 11 mL and 12 mL, the volume can be estimated as:
(11 mL + 12 mL) / 2
= 11.5 mL.
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the molecular formula of fructose is the c6h12o6. what would be the molecular formula for a polymer made by linking three fructose molecules together by dehydration synthesis reaction
The molecular formula for a polymer made by linking three fructose molecules [tex]C_6H_{12} O_6[/tex] together by a dehydration synthesis reaction is n[tex]C_6H_{12} O_6[/tex], where n represents the number of fructose units in the polymer.
The dehydration synthesis reaction between three fructose molecules forms a glycosidic bond, which eliminates a molecule of water and results in the formation of a single molecule with three fructose units. The molecular formula for the polymer will depend on the number of fructose units linked together, but in general, the molecular formula for a polymer made by linking multiple fructose molecules together will be n [tex]C_6H_{12} O_6[/tex], where n represents the number of fructose units in the polymer.
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you titrate a 200 ml hbr solution with 0.5 m koh. if it takes 150 ml of koh to reach the equivalence point, what was the concentration of the original acid solution?
Titration is a method of chemical analysis where the quantity of a sample's constituents is determined. Therefore, the concentration of the original acid is 0.0021M.
What is titration?Titration is a method of chemical analysis where the quantity of a sample's constituents is determined by adding a precisely measured amount of a different substance to which the desired ingredient will react in a specific, known proportion.
A burette, which is simply a long, graduated measurement tube with a stopcock as well as a delivery tube at its bottom end, is used to gradually administer a standard solution of titrating reagents, or titrant, to a specified concentration.
HBr+ KOH→ KBr + H[tex]_2[/tex]O
moles of KOH = 0.5 × 150/100=1.50× 0.5 =0.75moles
at equivalence,
moles of HBr = moles of KOH
moles of HBr = 0.75moles
concentration of HBr= 0.75/ 350= 0.0021M
Therefore, the concentration of the original acid is 0.0021M.
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at conditions of standard temperature and pressure, determine how many liters of hydrogen gas are produced by completely reacting a zinc nail with a mass of 2.2g with an excess of hydrochloric acid.
a.0.75L
b.0.0015L
c.6.42L
d.1.33L
Hydrochloric acid would totally react with 2.2 grams of zinc nail to yield 0.75 liters of hydrogen.
Hydrogen gas is created when zinc plus hydrochloric acid combine. We must understand proper balanced chemical equation of the reaction and the quantity of zinc that reacts in order to calculate the number of liters of water vapor generated.
The balanced chemical equation is:
Zn + 2HCl → ZnCl2 + H2
We may get the amount of moles using mass of zinc:
n = m/M
where n is the number of moles, m is the mass of zinc (2.2 g), and M is the molar mass of zinc (65.38 g/mol).
n = 2.2 g / 65.38 g/mol = 0.0337 mol
The volume of hydrogen gas generated may be determined using the formula below since one mole has a density of 22.4 L at normal pressure and temperature (STP):
V = n * 22.4 L/mol = 0.0337 mol * 22.4 L/mol = 0.75 L
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A mixture has a mas of 450 grams. Of that mixture,35 grams is sulfur . What is the percentage of sulfur in the mixture
A mixture has a mas of 450 grams. Of that mixture,35 grams is sulfur . Therefore, 11% is the percentage of sulfur in the mixture.
What is mass percentage?The mass percent equation is defined as the mass of each element in one mole of the compound, as well as the molar mass. With these masses, you can calculate each element's mass proportion.
In order to represent the mass percent of a solution, the kilograms of solute are divided by the kilograms of solution, and the result is multiplied by 100.
percentage of sulfur = mass of sulfur/ mass of mixture×100
mass of sulfur= 5 grams
mass of mixture =450 grams
substituting all the given values in the above equation, we get
percentage of sulfur = 5 / 450=0.011×100= 11%
Therefore, 11% is the percentage of sulfur in the mixture.
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What two types of energy is usually a product of combustion reactions?
Heat and light are the two types of energy which are usually a product of combustion reactions.
A combustion reaction is a type of chemical reaction in which any combustible material reacts with an oxidizer to create an oxidised product. The release of energy in the form of heat and light are frequently associated with combustion reactions.
A fuel and an oxidant, often atmospheric oxygen, undergo a high-temperature exothermic redox chemical reaction known as combustion reactions or burning to generate oxidised, frequently gaseous products in a mixture known as smoke.
Oxygen combines with another substance to produce chemical reaction processes, which release heat and light. Examples of common combustion reactions are the burning of coal, methane gas.
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what is the mass/volume percent of a solution prepared from 15.0 g nacl in 75.0 g solution? the density of the solution is 1.00 g/ml.
20% is the mass/volume percent of a solution prepared from 15.0 g NaCl in 75.0 g solution if the density of the solution is 1.00 g/ml.
The volume percentage of a component = (Volume of the component/Total volume of the solution) x 100
Mass by volume percentage: It is the mass of solute dissolved in 100 mL of the solution.
The measure of how densely a material is packed together is called density. As the mass per unit volume, it has that definition. Density Formula: = m/V, where is the density, m is the object's mass, and V is its volume.
mass of solute = 15.0 g of NaCl
mass of solvent = 75.0 g of water
solute + solvent = 15.0+ 75.0 = 90g
(15g/90g) x 100 = 20%
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there are three signals (listed below as i, ii, and ii) in the 1h nmr spectrum of a compound with the molecular formula c6h14o. for each of the three signals, the chemical shift and relative integration value are provided. how many protons are represented by each signal? signal i: 0.9 ppm, integration
The correct option is D, I = 3H; II = 4H; III = 4H protons are represented by each signal. Signal I: 0.9 ppm, integration = 3.3 Signal II: 1.4 ppm, integration = 2.2 Signal III: 3.5 ppm, integration = 2.2.
A proton is a subatomic particle that is found in the nucleus of an atom. It has a positive charge and, along with neutrons, makes up the atomic nucleus. Protons are one of the building blocks of matter, and their number determines an element's atomic number and chemical properties.
Protons are made up of two "up" quarks and one "down" quark, held together by the strong force. The strong force is one of the four fundamental forces of nature and is responsible for binding the protons and neutrons in the nucleus. The proton's positive charge also plays a crucial role in determining the behavior of atoms and molecules, as it interacts with the electrons in the outer shell of an atom.
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Complete question: -
There are three signals (listed below as I, II, and II) in the 'H NMR spectrum of a compound with the molecular formula C6H140. For each of the three signals, the chemical shift and relative integration value are provided. How many protons are represented by each signal? Signal I: 0.9 ppm, integration = 3.3 Signal II: 1.4 ppm, integration = 2.2 Signal III: 3.5 ppm, integration = 2.2
A. I = 3H; II = 2H; III = 2H
B. I = 6H; II = 2H; III = 2H
C. I = 6H; II = 4H; III = 4H
D. I = 3H; II = 4H; III = 4H
Can a chemical reaction of iron pipes form rust? Chemical reactions lesson 2.3
Answer:
Yes
Explanation:
Although rust is considered the result of an oxidation reaction, it's worth noting not all iron oxides are rust. Rust forms when oxygen reacts with iron, but simply putting iron and oxygen together isn't sufficient. Although about 21% of air consists of oxygen,1 rusting doesn't occur in dry air. It occurs in moist air and in water.
a balloon that is permeable to water but not to glucose contains a 10% glucose solution. a beaker contains a 5% glucose solution. which statement correctly classifies the solutions?
The statement correctly classifies the solutions is:
The solution in the balloon is hypertonic relative to the solution in the beaker.
As per the given data a balloon that is permeable to water but not to glucose contains a 10% glucose solution.
A beaker contains a 5% glucose solution.
Here we have to determine which statement correctly classifies the solutions.
A solution which has higher solute concentration than other solution is called a hypertonic solution.
The solution with lower solute concentration than other solution is called hypotonic solution and the solutions with same solute concentration is called isotonic solution. Here the concentration of solute insolation in balloon is higher than that of concentration of solutes in the beaker solution, so relatively it is hypertonic.
The correct answer is option,
b) The solution in the balloon is hypertonic relative to the solution in the beaker.
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A balloon permeable to water but not to glucose contains a 10 % glucose solution. A beaker contains a 5 % glucose solution. Which of the following is true?
(a)When placed in the beaker, the balloon will lose water by osmosis.
(b)The solution in the balloon is hypertonic relative to the solution in the beaker.
(c)The solution in the balloon is isotonic; the solution in the beaker is hypertonic.
(d)The solution in the beaker is hypertonic relative to the solution in the balloon.
a sample of a metal has a mass of 14.5 g. when the sample is placed in a graduated cylinder that contains 32.3 ml of water, the volume changes to 36.4 ml. what is the density of the metal?
Answer:
3.53 g/mL
Explanation:
to start this we need to find the displacement volume which we do by subtracting 36.4-32.3= 4.1 mL then we can plug in these numbers to the density formula p=m/v where m=14.5 and v=4.1
14.5/4.1 = 3.53 g/ml
The density of the metal in the given problem is calculated by dividing its given mass (14.5g) by the volume displacement in the graduated cylinder (4.1ml). The calculated density of the metal is approximately 3.54 g/ml.
Explanation:To determine the density of the metal, we need to use the formula density = mass/volume. In this case, the volume of the metal can be found by subtracting the initial water volume in the graduated cylinder from the final volume - so 36.4 ml - 32.3 ml, gives us 4.1 ml for the volume of the metal. The given mass of the metal is 14.5 g. Using these numbers in our density formula, we find that the density of the metal = 14.5 g / 4.1 ml = approximately 3.54 g/ml.
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an isotope of an element has a mass number of 153 and an atomic number of 63. select the correct number of subatomic particles this isotope has.
The number of subatomic particles that the isotope has is 63 protons, 63 electrons, and 90 neutrons.
Subatomic particle is a particle that composes an atom. In general, an atom can be broken down into three types of subatomic particles: protons, electrons, and neutrons.
By the question above, we are given this information:
The mass number of the isotope = 153The atomic number of the isotope = 63The atomic number is the number of protons, which means that the isotope has 63 protons.
The atomic number is also the number of electrons, which means that the isotope has 63 electrons.
The number of neutrons is the mass number - atomic number, which means that the isotope has 153 - 63 = 90 neutrons.
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What is the number of copper atoms in a unit cell of a face-centered cubic lattice of copper?
In a face-centered cubic (FCC) lattice, each unit cell has 8 corner atoms and 1 center atom. Thus, a unit cell of a FCC lattice of copper would contain 8 corner copper atoms and 1 center copper atom, giving a total of 8 + 1 = 9 copper atoms in the unit cell.
In a face-centered cubic (FCC) lattice of copper, the unit cell is made up of 8 corner atoms and a single atom in the center. Each corner atom of the unit cell is shared with 8 other unit cells and the center atom is shared with a total of 8 unit cells. Therefore, the number of copper atoms in a unit cell of an FCC lattice of copper is 8 corner atoms + 1 center atom = 9 atoms. This is a basic characteristic of FCC structures, which are very commonly found in metals and are known for their high packing efficiency and close-packed arrangement of atoms.
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a can of cola contains about 39 grams of sucrose, c12h22o11. how many moles of sucrose does this represent?
Sucrose is included in the package at an amount of 0.113 moles. Number of moles = Mass of substance / Mass of one mole.
One mole of sucrose contains how many moles?Each element's symbol is followed by a subscript that counts how many atoms of that element are present in the molecule. As a result, 12 moles of carbon, 22 moles of hydrogen, and 11 moles of oxygen make up 1 mole of sucrose.
Why are moles calculated?For instance, if we are aware of a substance's mass and chemical make-up, we can compute its molecular weight and estimate the number of atoms or molecules present. Similar to how we can calculate the number of atoms or molecules in a substance by knowing its mass, we can do the same thing if we know its number of moles.
39 g makes up the sucrose's bulk.
The mole ratio of sucrose is 342.3 g/mol.
To determine the sugar moles, we
Sucrose moles equal 39g /342.3 = 0.113
The molecules of sucrose are therefore 0.113 mol.
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what are the characteristic properties of metals, nonmetals, and metalloids? drag the appropriate items to their respective bins
A characteristic property of metals, non-metals, and metalloids is that if a metal is an electropositive element (as a positive ion), it can generally form basic compounds and ionic compounds. Meanwhile, non-metallic elements exhibit properties that are opposite to those of metals and metalloid elements that have a low level of metallic behavior.
Characteristics of metals, nonmetals and metalloidsMetal or metal elements are elements that have general physical properties such as being solid, having a high melting point, flexible (not easily broken), easy to shape (can be forged and pulled), good conductors of heat and electricity, and can be alloyed with each other. metal. While its chemical properties include electropositive elements (as positive ions), generally it can form basic compounds and ionic compounds.
Non-metallic elements are groups of elements that exhibit properties that are opposite to those of metals, Group that has almost no metallic properties; a group of elements whose properties include: not hard, not tough (brittle and easily broken), can conduct heat and electricity, and has a low melting point.
Metalloids are elements that have a low degree of metallic behavior. Metalloids exhibit some metallic and some nonmetallic properties. The appearance of metalloids can be dull or shiny. Although they are not very good thermal and electrical conductors, metalloids are capable of conducting heat and electricity.
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molality is the relationship between moles of solute per kg of solvent (water)
example: 20.0 o grams of NaOH with 2000 gram of water is:
20.0 /40.0 =0.500 moles
m= 0.500 moles /2.00 kg = 0.250 m
* 2000 grams=2.00 kg
40,0 is the gram formula mass of NaOH
Na=23.0 0=16.0 H-1.0
1, 10.0 grams NaH dissolved in 2.000 kg water
2. 40.0 grams NaOH dissolved in 1500 grams of water
3. 80.0 grams NaOH dissolved in 1.000 kg of water
4. 20.0 grams of NaOH dissolved in 2.000 kg of water
Following are the answers:
1. 10.0 grams NaH dissolved in 2.000 kg of water:
10.0 / (23.0 + 1.0) = 0.400 moles
m = 0.400 moles / 2.000 kg = 0.200 m
2. 40.0 grams NaOH dissolved in 1500 grams of water:
1500 grams = 1.500 kg
40.0 / 40.0 = 1.000 moles
m = 1.000 moles / 1.500 kg = 0.667 m
3. 80.0 grams NaOH dissolved in 1.000 kg of water:
80.0 / 40.0 = 2.000 moles
m = 2.000 moles / 1.000 kg = 2.000 m
4. 20.0 grams of NaOH dissolved in 2.000 kg of water:
20.0 / 40.0 = 0.500 moles
m = 0.500 moles / 2.000 kg = 0.250 m
What is molality?
Molality is a measure of the concentration of a solution that expresses the number of moles of solute present in a specified mass of solvent, typically per kilogram of solvent. It is represented by the symbol "m" and is calculated by dividing the number of moles of solute by the mass of the solvent in kilograms.
Molality is commonly used in chemical and biological applications, as it provides a more accurate measure of solution concentration than other measures such as molarity, which is based on the volume of the solvent. Molality is particularly useful in situations where temperature changes could cause significant changes in the volume of the solvent, as it is independent of temperature.
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The molality is an important method to calculate the concentration of a solution. The molality of the given solutions are 0.209 mol kg⁻¹, 0.66 mol kg⁻¹, 2 mol kg⁻¹ and 0.25 mol kg⁻¹.
What is molality?The molality of a solution is defined as the number of moles of the solute dissolved in 1 kg of the solvent. It is usually denoted by the symbol 'm'. The equation used to calculate the molality is:
m = Number of moles of the solute / Mass in kg of the solvent
n = Given mass / Molar mass
1. 10.0 / 23.9 = 0.41 moles
m = 0.41 / 2.0 = 0.209 mol kg⁻¹
2. 40.0 / 39.99 = 1. 0 moles
m = 1.0 / 1.5 = 0.66 mol kg⁻¹
3. 80.0 / 39.99 = 2.0 moles
m = 2.0 / 1.0 = 2 mol kg⁻¹
4. 20. 0 / 39.99 = 0.50
m = 0.50 / 2.0 = 0.25 mol kg⁻¹
Thus the molality of the given solutions calculated.
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question 5: why did rutherford choose gold for his experiment? could he have used any other material? which properties should this material have?
Rutherford chooses gold because of it's most malleable property of this metal. no, he couldn't use other metal as gold is the thickest property and can be beaten to the thinnest sheet.
Rutherford picked gold because it is the most malleable metal and he desired the thinnest coating possible for his scattering experiment. The used goldsheet had a thickness of roughly 1000 atoms. Rutherford chose a Gold foil as a result for his alpha scattering experiment. Gold is the most malleable metal, and Rutherford sought the thinnest layer possible for his scattering experiment. The gold sheet utilised had a thickness of about 1000 atoms. Rutherford chose a Gold foil as a result for his alpha scattering experiment. thin gold foil, very thin. A heavy metal with a high mass number is gold. Because the atom of a light metal will simply be pushed ahead when struck by a fast-moving a-particle, no scattering can take place, the material cannot be used. Gold is also the most malleable metal. To acquire the clear observations, a gold foil only 1000 atoms thick can be created.
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until 20% of the original liquid is evaporated. determine the composition of the vapor and liquid phases and find the operating temperature. (3 pts.)
Since liquids are frequently flammable, they will transition into the vapor phase when the temperature is raised high enough.
The total vapor pressure above a mixture of two volatile liquids can be forecast using Raoult's law. In fact, the more volatile molecule will have a larger mole fraction in the vapor phase than in the liquid phase, resulting in a composition of the vapor that differs from that of the two liquids.
Condensation is the term for this action. The pressure exerted by a vapour with its condensed phases (solid or liquid) in a closed system at a specific temperature is referred to as vapour pressure, also known as vapour equilibrium pressure.
The partial pressures of the constituents dictate the composition of the vapour phase in equilibrium with the solution.
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a physician has ordered 0.50 mg of atropine, intramuscularly. if atropine were available as 0.30 mg/ml of solution, how many milliliters would you need to give?
To calculate the milliliters of atropine needed, divide the dose ordered by the concentration of the solution. So, you would need to give 1.67 ml of the 0.30 mg/ml atropine solution intramuscularly.
Calculating the Dosage of AtropineWhen a physician orders a specific dose of atropine, such as 0.50 mg intramuscularly, it is necessary to determine the volume of the solution that should be administered. This calculation can be done by dividing the dose ordered by the concentration of the solution. In this case, if the atropine is available as 0.30 mg/ml, the calculation would be 0.50 mg ÷ 0.30 mg/ml = 1.67 ml. This means that 1.67 ml of the 0.30 mg/ml atropine solution would need to be given intramuscularly to meet the 0.50 mg dose ordered by the physician. This calculation is important to ensure that the correct dose of medication is given to the patient for optimal therapeutic effect
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which one of the following substances will have hydrogen bonding as one of its intermolecular forces? question 12 options: a) b) c) d) e)
The forces of attraction respective to the intermolecular forces is a hydrogen bond. It is a very specialized type of dispersion force.
What are the intermolecular forces?
Types of Intermolecular Forces are:
Dispersion,
Dipole–Dipole,
Hydrogen Bonding, and
Ion-Dipole
A hydrogen bond is a very specialized type of dispersion force regarding intermolecular force.
Noble gases are monoatomic as they are unlikely to react with any other atoms since they exist in a stable state and are also nonpolar. This implies that the strongest intermolecular forces they can experience are London Dispersion forces(LDFs). LDFs are the weakest interactive forces that are found in any molecule.They are temporary attractive forces formed when electrons between two atoms are unevenly distributed forming temporary dipoles.
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how much heat does it take to increase the temperature of 2.10 mol of an ideal gas by 60.0 k near room temperature if the gas is held at constant volume and is diatomic?
The heat that is required to increase the temperature of 2.10 mol of an ideal gas by 60.0 k near room temperature if the gas is held at constant volume and is diatomic is 2618.91 J.
n = no. of mol= 2.10 mol
T = Temperature = 60.0 K
Q = nCv × ∆T .........eqn(1)
Where CV = molar heat capacity =5/2R for diatomic particle ,such as H₂
CV = molar heat capacity = 3/2R for diatomic, such as H
R = gas constant = 8.314 J/mol × K
Q = heat energy
For a diatomic molecules
Q = n Cv × T
But
Cv = molar heat capacity = 5/2R = 5/2(8.314) = 20.785
CV = 20.785
∆T= Temperature= 60.0 K
Then substitute the values into the eqn(1)
Q = 2.10 × 5/2(8.314) × 60
Q = 2.10 × 20.785 × 60
⇒ Q = 2618.91 J
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