Answer: B
Explanation:
Key words "across the whole country"
Find the limit of the function (if it exists). (If an answer does not exist, enter DNE.) x3 - 8 lim X-2 X-2 Write a simpler function that agrees with the given function at all but one point. Use a graphing utility to confirm your result. g(x)
Answer:
The answer to the limit would be [tex]\lim_{x \to 2} \frac{x^3-8}{x-2}=12[/tex]. The simpler equation would be: [tex]\frac{x^2+2x+4}{1} \\[/tex]
Explanation:
The equation has a hole at at x=2. A hole is a type of removable discontinuity which allows us to solve the limit problem without receiving a DNE result. When examining the equation [tex]\frac{x^3-8}{x-2}[/tex], it is noted that the numerator can be expanded using the formula for the difference of cubes. The formula for the difference of cubes is: [tex]a^3-b^3=(a-b)(a^2+ab+b^2)[/tex]. We identify [tex]x[/tex] as [tex]a[/tex] and [tex]2[/tex] as [tex]b[/tex]. Plugging these numbers into the difference of cubes expansion formula we get: [tex]\frac{(x-2)(x^2+2x+4)}{(x-2)}[/tex]. Notice that [tex](x-2)[/tex] is present in both the numerator and denominator. Because of this, we can cancel both of them out, resulting in the simplified equation: [tex]x^2+2x+4[/tex]. We then plug [tex]2[/tex] in for [tex]x[/tex] and get [tex]12[/tex] as the final answer to the limit.