HELP WITH MATH INDUCTIVE OR DEDUCTIVE PLEASE



"Anyone who protrices a hocethorn will be dribbed. Steve was not
dribbed. Therefore, he did not protrice a hocethorn."
O Invalid. The inner circle is those who are dribbed, and the outer circle is those
who protrice a hocethorn.
O Valid. The inner circle is those who are dribbed, and the outer circle is those
who protrice a hocethorn.
O Invalid. The inner circle is those who protrice a hocethorn, and the outer
circle is those who are dribbed.
O Valid. The inner circle is those who protrice a hocethorn, and the outer circle
is those who are dribbed.

Answer:

63

Step-by-step explanation:

Simplifying the expression,

→ (2+1) × 42 ÷ 2

→ 3 × 42 ÷ 2

→ 126 ÷ 2 = 63

Hence, the answer is 63.

Find the critical points of [tex]f_1[/tex] and [tex]f_2[/tex].

By the fundamental theorem of calculus,

[tex]{f_1}'(x) = \displaystyle \prod_{j=1}^{21} (x-j)^j = (x-1) (x-2)^2 (x-3)^3 \cdots (x-21)^{21}[/tex]

and [tex]{f_1}'=0[/tex] for [tex]x\in\{1,2,3,\ldots,21\}[/tex]. The stationary points at odd values have odd multiplicity, while the even ones have even multiplicity. At the points of odd multiplicity, [tex]{f_1}'[/tex] passes through the [tex]x[/tex]-axis and the sign of [tex]{f_1}'[/tex] changes, while at the points of even multiplicity, [tex]{f_1}'[/tex] is tangent the to [tex]x[/tex]-axis. We also have

[tex]\displaystyle \lim_{x\to-\infty} {f_1}'(x) = (-1)^{1+3+5+\cdots+21} \infty = (-1)^{11^2} \infty = -\infty[/tex]

[tex]\displaystyle \lim_{x\to\infty} {f_1}'(x) = \infty[/tex]

so the plot of [tex]{f_1}'[/tex] looks more or less like the attached curve. (Not drawn to scale)

Wherever the sign of [tex]{f_1}'[/tex] changes from negative to positive, as it does in the case of [tex]x\in\{1,5,9,13,17,21\}[/tex], there is a local minimum, so [tex]m_1 = 6[/tex]. Similarly, wherever the sign changes from negative to positive, as it does when [tex]x\in\{3,7,11,15,19\}[/tex], there is a local maximum, so [tex]n_1 = 5[/tex].

Repeat for [tex]f_2[/tex].

[tex]{f_2}'(x) = 4900 (x-1)^{49} - 29400 (x-1)^{48} = 4900 (x-1)^{48} (x-7)[/tex]

has roots at [tex]x=1[/tex] and [tex]x=7[/tex], but only the latter is a critical point due to odd multiplicity. A rough sketch of the plot of [tex]{f_2}'[/tex] is also attached. The sign of [tex]{f_2}'[/tex] changes from negative to positive at [tex]x=7[/tex], so [tex]m_2 = 1[/tex] and [tex]n_2=0[/tex].

We conclude that

Q.9) [tex]2m_1+3n_1+m_1n_1 = \boxed{57}[/tex]

Q.10) [tex]6m_2+4n_2+8m_2n_2 = \boxed{6}[/tex]

Step-by-step explanation:

with ABCD and ABDE being parallelograms, this means a indicated by the marks

AB = ED = CD

and with BD = DF that means that the line segments BF and CE are intersecting each other at their midpoint.

so they represent a pair of diagonals of a parallelogram, which makes BCFE a parallelogram.

Answer: total household present are 136

Step-by-step explanation:

Given:

82.1% of Cincinnati households have a computer.

111.804 households in Cincinnati have a computer.

According to ratio and proportions we have:

let total number of houses be x;

then

(111.804/x)*100=percentage of Cincinnati households having  a computer.    [[tex]gain/total*100 =gain %[/tex]]

then

(111.804/x)*100=82.1

cross multiplying we have

x=(111.804*100)/82.1

x=136 households  (Round to the nearest whole number.)

so total household present are 136

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C.78893

Step-by-step explanation:

-_-_+_(*;#-✓✓

[tex]\sqrt{10^2 - 3^2}=\boxed{\sqrt{91} \text{ ft}}[/tex]

Answer: A someone with dangerous material passed by security

Step-by-step explanation:

Answer:

A because of the way the pipe is designed

2.5, 0.92, 0.75, 0.925

The equation of the polynomial with the given roots of 2, -2, and 4 is x³ - 4x² - 4x + 16 = 0.

Roots are the points where the graph intercepts with the x-axis ( y = 0 ).

Given the roots in the question;

x = 2, -2, 3

Now, the root of x = 2 was found solving for x when x - (2) = y but y = 0.

Hence, (x - 2) is a factor.

Next, the root of x = -2 was found solving for x when x - (-2) = y but y = 0.

Hence, (x + 2) is a factor

And the root of x = 4 was found solving for x when x - (4) = y but y = 0.

Hence, (x + 2) is a factor

Now, combine all the factors into a single equation and simplify.

( x-2 )( x + 2 )( x - 4 ) = y

( x² + 2x - 2x - 4 )( x - 4) = 0

( x² - 4 )( x - 4) = 0

x( x² - 4 ) -4( x² - 4 ) = 0

x³ - 4x - 4x² + 16 = 0

x³ - 4x² - 4x + 16 = 0

x³ - 4x² - 4x + 16 = 0

Therefore, the equation of the polynomial with the given roots of 2, -2, and 4 is x³ - 4x² - 4x + 16 = 0.

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Answer: -8, -3, 2, |-6|

Step-by-step explanation:

-3 , -8, |-6|, 2

|-6|=6

6>2

-3>-8 since a negative number closer to 0 is the greater number.

Order: -8, -3, 2, 6 ==> -8, -3, 2, |-6|

Answer:

[tex]\dfrac{7}{8} \textsf{ and } -\dfrac{5}{8}[/tex]

Step-by-step explanation:

To find numbers that are [tex]\dfrac{3}{4}[/tex] units distance from [tex]\displaystyle \dfrac{1}{8}[/tex] , add and subtract [tex]\dfrac{3}{4}[/tex] to and from [tex]\displaystyle \dfrac{1}{8}[/tex]

One of the points is at [tex]\displaystyle \dfrac{1}{8} + \dfrac{3}{4}[/tex] units away and the other at [tex]\displaystyle \dfrac{1}{8} - \dfrac{3}{4}[/tex] units away

Answer:

You have the right form (vertex form). All that you have left to do is learn what parts of the equation signify what.

Step-by-step explanation:

Explanation:

In a quadratic function of form y = a

(

x

−

p

)

2

+ q, the axis of symmetry is found at x = p. As a result, in y = -4

(

x

−

8

)

2

+ 3, the axis of symmetry is at x = 8, since the formula is x - p = x - (+8).

The vertex of a parabola is at (p, q). As for the axis of symmetry, the p value is 8, and in this function the q value is 3. So the vertex is at (8,3).

With this information, the x and y intercepts, and a few other points found by plugging in x values and solving for y, you will be able to graph this parabola. Your graph, if done properly, will look like the following:

graph{y = -4(x - 8)^2 + 3 [-20, 20, -10, 10]}

Answer:

USE AIR MATH!!

Step-by-step explanation:

The  property of equality was used to solve this equation is addition property of equality

The property states that the additive property of equality states that if we add or subtract the same number to both sides of an equation, the sides remain equal.

Given the expression

X-5=-14

Add 5 to both sides to have;

x-5 + 5 = -14 + 5

x = -14 + 4

x = -9

Hence the  property of equality was used to solve this equation is addition property of equality

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Answer:

7√2

7√2 is irrational since √2 is irrational

Step-by-step explanation:

3√2 + 2√8 = 3√2 + 2 × 2√2 = 3√2 + 4√2 = 7√2

7√2 is irrational since √2 is irrational

On 4/5 gallon of gasoline, hybrid car will travel a distance of 48 miles.

Suppose, non hybrid car travel "x" distance in 1 gallon of gasoline

Then, hybrid will travel " 1 ⁹/₁₁ * x" distance in 1 gallon of gasoline

Given that, non hybrid car travel distance per gallon is; x = 33 miles per gallon

Then, hybrid car travel,  1 ⁹/₁₁ * x =  1 ⁹/₁₁ * x * 33 = 60 miles per gallon

On 1 gallon of gasoline hybrid car travel 60 miles

On 4/5 gallon of gasoline hybrid car will travel = 4/5 * 60 = 48 miles

On 4/5 gallon of gasoline, hybrid car will travel 48 miles of distance.

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Answer:

It is 41, 43, 47! :D

Step-by-step explanation:

Answer:

Adjacent sides.

Step-by-step explanation:

Answer:

To construct a rectangle, you must have the measurement of one side and it's adjacent side.

Step-by-step explanation:

to construct a rectangle you must have one side and :

(1) it’s opposite sides

(2) it’s adjacent sides

(3) two angles

(4) four angles

Answer:

yes!!! because the first 3 types of bus can hold 50 people and the other 3 types of bus can hold 56 people so the total will be 320 people

Answer:

[tex]\textsf{1.} \quad x=-6, \quad x=6[/tex]

[tex]\textsf{2.} \quad x=-5, \quad x=2[/tex]

[tex]\textsf{3.} \quad x=-3, \quad x=7[/tex]

[tex]\textsf{4.} \quad x=\dfrac{-5 +\sqrt{57} }{4}, \quad x=\dfrac{-5 -\sqrt{57} }{4}[/tex]

[tex]\textsf{5.} \quad x=\dfrac{7+ \sqrt{309} }{10}, \quad x=\dfrac{7-\sqrt{309} }{10}[/tex]

Step-by-step explanation:

Method: Extracting the Square Root

[tex]\begin{aligned}& \textsf{Given}: & x^2 & = 36\\& \textsf{Square root both sides}: & \sqrt{x^2} & = \sqrt{36}\\& \textsf{Simplify}: & x & = \pm 6\\&\textsf{Solution}:&x& = -6, 6\end{aligned}[/tex]

Method: Factoring

[tex]\begin{aligned}& \textsf{Given}: & x^2+3x-10 & = 0\\& \textsf{Split the middle term}: & x^2+5x-2x-10 & = 0\\& \textsf{Factor the first two and the last two terms}: & x(x+5)-2(x+5)&=0\\& \textsf{Factor out the common term $(x+5)$}: & (x-2)(x+5)&=0\\& \textsf{Apply the zero-product property}: & (x-2)=0 \implies x&=2\\ &&(x+5)=0 \implies x&=-5\\ & \textsf{Solution}: & x&=-5,2\end{aligned}[/tex]

Method: Factoring

[tex]\begin{aligned}& \textsf{Given}: & x^2-4x-21 & = 0\\& \textsf{Split the middle term}: & x^2-7x+3x-21 & = 0\\& \textsf{Factor the first two and the last two terms}: & x(x-7)+3(x-7)&=0\\& \textsf{Factor out the common term $(x-7)$}: & (x+3)(x-7)&=0\\& \textsf{Apply the zero-product property}: & (x+3)=0 \implies x&=-3\\&&(x-7)=0 \implies x&=7\\& \textsf{Solution}: & x & = -3, 7\end{aligned}[/tex]

Method: Quadratic  Formula

[tex]\boxed{\begin{minipage}{4 cm}\begin{center}\underline{Quadratic Formula}\end{center}\\\\\begin{center}$x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$\end{center}\\\\\\\begin{center}when $ax^2+bx+c=0$\end{center}\end{minipage}}[/tex]

Given:

[tex]5x-4=-2x^2[/tex]

Rearrange into standard form by adding 2x² to both sides:

[tex]\implies 2x^2+5x-4=0[/tex]

Therefore:

[tex]a=2, \quad b=5, \quad c=-4[/tex]

Substitute the values into the quadratic formula and solve for x:

[tex]\implies x=\dfrac{-5 \pm \sqrt{5^2-4(2)(-4)} }{2(2)}[/tex]

[tex]\implies x=\dfrac{-5 \pm \sqrt{25+32} }{4}[/tex]

[tex]\implies x=\dfrac{-5 \pm \sqrt{57} }{4}[/tex]

Therefore, the solutions are:

[tex]x=\dfrac{-5 +\sqrt{57} }{4}, \quad x=\dfrac{-5 -\sqrt{57} }{4}[/tex]

Method: Quadratic  Formula

[tex]\boxed{\begin{minipage}{4 cm}\begin{center}\underline{Quadratic Formula}\end{center}\\\\\begin{center}$x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$\end{center}\\\\\\\begin{center}when $ax^2+bx+c=0$\end{center}\end{minipage}}[/tex]

Given:

[tex]5x^2-7x-13=0[/tex]

Therefore:

[tex]a=5, \quad b=-7, \quad c=-13[/tex]

Substitute the values into the quadratic formula and solve for x:

[tex]\implies x=\dfrac{-(-7) \pm \sqrt{(-7)^2-4(5)(-13)} }{2(5)}[/tex]

[tex]\implies x=\dfrac{7 \pm \sqrt{49+260} }{10}[/tex]

[tex]\implies x=\dfrac{7 \pm \sqrt{309} }{10}[/tex]

Therefore, the solutions are:

[tex]x=\dfrac{7+ \sqrt{309} }{10}, \quad x=\dfrac{7-\sqrt{309} }{10}[/tex]

Answer: $5.75

Step-by-step explanation: 2.75 x 2 = 5.5    1.25 x 3 = 2.75    2.75 + 5.5 = 9.25     $15 - $9.25 = $5.75

Answer and Explanation:

The problem provides the following information:

Hypotenuse

=

h

y

p

=

5129

ft

Vertical drop

=

o

p

p

=

1275

ft

To find the angle of depression, the best trigonometric ratio to use is the sine ratio. After equating it with the ratio of the opposite side over the hypotenuse, get the inverse of the sine ratio as shown:

sin

θ

=

o

p

p

h

y

p

θ

=

sin

−

1

(

o

p

p

h

y

p

)

θ

=

sin

−

1

(

1275

ft

5129

ft

)

θ

=

sin

−

1

(

0.2485864691

)

θ

=

14.3938824691

≈

14.4

∘

The angle of depression is

14.4

The greatest common factor of 18 12 16 is the number 2.

Answer:

[tex]xy\left(7.2x-0.9y\right)[/tex]

Step-by-step explanation:

[tex]Rule: a^{b+c}=a^ba^c\\(x^2y=xxy,\:xy^2=xyy)\\=7.2x(xy)-0.9xyy\\=xy\left(7.2x-0.9y\right)[/tex]

Answer:

x < 3

Step-by-step explain: I used quizlet

Answer:

OD

Step-by-step explanation:

move the -8 to the right, and change its sign

x > 5