Find point G on AB such that the ratio of AG to GB is 3:2.

The equation for DE is [tex]8+9x[/tex]

According to the question statement, Line RQ bisects line DE at S. If DS = 10 + 3x and ES = -2 + 6x. We are supposed to find DE.

For solving this we need to know about Linear Equations and Bisector of a line.

Given that, DS = 10 + 3x and ES = -2 + 6x.

S is mid point of line DE as RQ bisects it.

So DS = SE

And DE = DS + SE

Hence, DE = [tex]10 + 3x + (-2 + 6x)[/tex]

DE = [tex]10 + 3x -2 + 6x[/tex]

DE = [tex]10 -2 +3x+6x[/tex]

DE = [tex]8+9x[/tex]

Hence equation of DE is 8+9x.

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Answer:

it is positive

Step-by-step explanation:

-289+311=22 which is a positive number

Answer:

1/3

Step-by-step explanation:

Any 1 of the following transformations will work. There are others that are also possible.

translation up 4 units, followed by rotation CCW by 90°.

rotation CCW by 90°, followed by translation left 4 units.

rotation CCW 90° about the center (-2, -2).

Step-by-step explanation:

The order of vertices ABC is clockwise, as is the order of vertices A'B'C'. Thus, if reflection is involved, there are two (or some other even number of) reflections.

The orientation of line CA is to the east. The orientation of line C'A' is to the north, so the figure has been rotated 90° CCW. In general, such rotation can be accomplished by a single transformation about a suitably chosen center. Here, we're told there is a sequence of transformations involved, so a single rotation is probably not of interest.

If we rotate the figure 90° CCW, we find it ends up 4 units east of the final position. So, one possible transformation is 90° CCW + translation left 4 units.

If we rotate the final figure 90° CW, we find it ends up 4 units north of the starting position. So, another possible transformation is translation up 4 units + rotation 90° CCW.

Of course, rotation 90° CCW in either case is the same as rotation 270° CW.

_____

Answer:

In mathematics, a complex number is an element of a number system that extends the real numbers with a specific element denoted i, called the imaginary unit and satisfying the equation i2 = −1; every complex number can be expressed in the form a + bi, where a and b are real numbers. Because no real number satisfies the above equation, i was called an imaginary number by René Descartes. For the complex number a + bi, a is called the real part and b is called the imaginary part. The set of complex numbers is denoted by either of the symbols {\displaystyle \mathbb {C} }\mathbb {C} or C. Despite the historical nomenclature "imaginary", complex numbers are regarded in the mathematical sciences as just as "real" as the real numbers and are fundamental in many aspects of the scientific description of the natural world.[1][a]

Step-by-step explanation:

Answer:

we need to add [tex]a^{2}[/tex] to make it a perfect square.

Step-by-step explanation:

since we know

[tex]a^{2}+b^{2}-2ab=(a-b)^{2}[/tex]

then after compairing it with x² - 2xa

we have;

missing term as   [tex]a^{2}[/tex]

hence we need to add [tex]a^{2}[/tex] to make it a perfect square.

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14 is the largest integer.

Let x, x+2 & x+4 be the 3 integers.

x + 2 (x+2)= (x+4)+20

x + 2x + 4 = x + 4 + 20

3x + 4 = x + 24

3x - x = 24 - 4

2x = 20

x = 20/2

x=10 for the smallest integer.

10 + 2 = 12 for the middle integer.

10 + 4 = 14 for the largest integer.

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The marginal benefit from studying one extra hour is 5 percent.

Now,

Given:

To find: Marginal benefit on studying one hour extra.

Finding:

Now, marks scored on studying 4 hours is 80 percent and 5 hours is 85 percent.

Thus, the extra percentage that is scored is because of the 1 hour of extra studying.

The extra percentage = marginal benefit of studying extra = 85 - 80 = 5 percent.

Hence, the marginal benefit from studying one extra hour is 5 percent.

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The gross income over the whole week upon working during the day and at night is; $449.04.

Since, the pay rates during the day and night according to the task content are; $10.05 per hour and $12.01 per hr respectively.

It then means that the total gross total income can be calculated as follows;

(10.05 × 16) + (12.01 × 24)

= 160.8 + 288.24

= $449.04.

Therefore, the gross income over the whole week upon working during the day and at night is; $449.04.

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Step-by-step explanation:

[tex] = (2 {a}^{ - 5} ) \times ( - 5 {a}^{9} )[/tex]

[tex] = (2 \times ( - 5)) {a}^{ - 5 + 9} [/tex]

[tex] = - 10 {a}^{4} [/tex]

Answer:

45 $

Step-by-step explanation:

20 x 2 = 40

40 + 5 = 45

A linear recurrence relation is a function or sequence in which each term is a linear combination of the terms that came before it.

The recurrence relation exists [tex]$T(n)=\Theta\left(3^n\right)$[/tex].

Recurrence relations are used to simplify complex problems by reducing them to an iterative process based on simpler versions of the problem.

Using the substitution method, we find out that

[tex]T(n) &=n+3 T(n-1) \\[/tex]

[tex]&=n+3(n-1)+3^2 T(n-2) \\[/tex]

[tex]&=n+3(n-1)+3^2(n-2)+3^3 T(n-3) \\[/tex]

[tex]&=\cdots \\[/tex]

[tex]&=n+3(n-1)+3^2(n-2)+\cdots+3^{n-1}(n-(n-1))+3^n T(0) \\[/tex]

simplifying the above equation, we get

[tex]$&=\frac{3^{n+1}-2 n-3}{4}+3^n T(0) \\[/tex]

[tex]&=\Theta\left(3^n\right)[/tex]

Even without doing the full calculation it is not hard to check that [tex]$T(n) \geq 3^{n-1}+3^n T(0)$[/tex], and so [tex]$T(n)=\Omega\left(3^n\right)$[/tex].

A cheap way to obtain the corresponding upper bound is by considering

[tex]$S(n)=T(n) / 3^n$[/tex], which satisfies the recurrence relation  

[tex]$S(n)=S(n-1)+n / 3^n$[/tex].

Repeated substitution then gives

[tex]$\frac{T(n)}{3^n}=\sum_{m=1}^n \frac{m}{3^m}+T(0)[/tex]

Since the infinite series [tex]$\sum_{m=1}^{\infty} \frac{m}{3^m}$[/tex] converges, this implies that [tex]$\frac{T(n)}{3^n}=\Theta(1)$[/tex] and so [tex]$T(n)=\Theta\left(3^n\right)$[/tex]

Therefore, the recurrence relation exists [tex]$T(n)=\Theta\left(3^n\right)$[/tex].

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The formula in terms of h is h = 3V/s^2 and the value of h is 5

The equation is given as

V = 1/3s^2h

Divide both sides of the equation by 1/3s^2

So, we have

h = 3V/s^2

The given parameters are

V = 60 and s = 6

So, we have:

h = 3 * 60/6^2

Evaluate

h = 5

Hence, the formula in terms of h is h = 3V/s^2 and the value of h is 5

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=========================================================

Explanation:

The output of an absolute value is never negative.

The result of |2x+2| can never be negative, so we will have no solutions for the portion |2x+2| < 0

There will be one solution for |2x+2| = 0 as shown in the steps below

|2x+2| = 0

2x+2 = 0

2x = -2

x = -2/2

x = -1

------------------

Check:

|2x+2|  ≤ 0

|2(-1)+2| ≤ 0

|-2+2| ≤ 0

|0| ≤ 0

0 ≤ 0

We get a true statement at the end to fully confirm the single solution of x = -1

Answer: 34

Step-by-step explanation:

1.7 miles, just do the total amount of what can be considered distance, then minus what she walked, resulting in the answer to be the amount of time ran.

Between the locations S(4,-3) and T(-2,2), there are 7.81 units between them.

The length of the line segment connecting two locations serves as a measure of the distance between them. Most importantly, the distance between two points is always positive and segments with the same length are known as congruent segments.

P(x1, y1) and Q(x2, y2) are two points, and the formula for their distance is provided by: d (P, Q) = (x2 - x1)2 + (y2 - y1) 2.

The points S(4,-3) and T are given.

Therefore, the distance (d) between S(4,-3) and T(-2,2) is as follows:

⇒ d (S, T) = √

² + (2 - (-3)) ².

⇒ d (S, T) = √ (-6)² + (5) ².

⇒ d (S, T) = √ 36+25

⇒ d (S, T) = √61

D (S, T) equals 7.81 units

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Step-by-step explanation:

y=4x+rx+6

y-6=4x+rxy−6=4x+rx Subtract \ 6 \ from \ both \ sidesSubtract 6 from both sides

y-6=x(4+r)y−6=x(4+r) Factor \ out \ the \ common \ term \ xFactor out the common term x

\dfrac{y-6}{4+r} =x

4+r

y−6

=x Divide \ both \ sides \ by \ 4+rDivide both sides by 4+r

Answer:

Yes

Step-by-step explanation:

If you have a graphing calculator or something similar, that could really help because all you would have to do is plug in the equation and look up the table and it would show that coordinate in there.

The true population mean is (222.52, 227.48) with a 95% confidence interval.

The critical factor for a 90% confidence interval for the true population mean is given by;

Critical factor = (x-μ)/(s/√n)

where, x = sample mean repair cost

s =  standard deviation of a sample

n = sample of stereos

μ  = critical value

⇒ P(-1.96< (x-μ)/(s/√n) < 1.96) = 0.95

⇒ P(-1.96×(s/√n) < (x-μ) < 1.96×(s/√n)) = 0.95

⇒ P(x - 1.96×(s/√n) < μ < x + 1.96×(s/√n)) = 0.95

95% confidence interval for

⇒ μ = (x - 1.96×(s/√n) , x + 1.96×(s/√n))

Here, x = 225, s  = 8.5, and n = 45

⇒ μ = (225- 1.96×(10.81/√13) , 225+ 1.96×(10.81/√13))

⇒ μ = (222.52, 227.48)

Hence, the true population mean is (222.52, 227.48) with a 95% confidence interval.

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The question seems to be incomplete the correct question would be

Calculate the 95% confidence interval for the true population mean based on a sample with x=225, s=8.5, and n=45.

answer:

10:03 am

explanation:

9:00 am + 1 hour (60 min) + 3 min = 10:03 am.

Answer:

20cm^3

Step-by-step explanation:

Divide 90 by 4.5.

90/4.5 = 20

We can multiply the density ratio by this quotient in order to find the volume of a sample 20x the size of the ratio's sample.

(4.5 x 20)/(1cm^3 x 20)
90g/20cm^3

In this step, let's identify the clues provided in the questions. We have:

Since we know the mass and density of titanium, we can apply the density formula to determine the volume of titanium.

Footnote: I have included the formula in case if you need to know it.

[tex]\boxed{\text{Density} = \frac{\text{Mass (Grams)}}{\text{Volume (cm}^{3} \text{)} }} }[/tex]

To work out the volume of the titanium, we need to substitute the given clues from the question, into the formula. We have:

    [tex]\text{Density} = \dfrac{\text{Mass (Grams)}}{\text{Volume (cm}^{3} \text{)} }} }[/tex]

When we substitute the mass and the density of titanium, we have:

    [tex]4.5 \ \text{g/cm}^{3}} = \dfrac{\text{90 grams}}{\text{Volume (cm}^{3} \text{)} }} }[/tex]

Finally, let's simplify the equation.

    [tex]4.5 \ \text{g/cm}^{3}} = \dfrac{\text{90 grams}}{\text{Volume (cm}^{3} \text{)} }} }[/tex]

    [tex]1 \ \text{g/cm}^{3}} = \dfrac{\text{20 grams}}{\text{Volume (cm}^{3} \text{)} }} }[/tex]

    [tex]\text{Volume (cm}^{3}) = \dfrac{\text{20 grams}}{\text{1 g/cm} ^{3} }[/tex]

    [tex]\text{Volume (cm}^{3}) = \dfrac{\text{20 grams}}{\text{1 g/cm} ^{3} } = \dfrac{20 \ \text{grams} \ \times 1 \ \text{cm}^{3} }{1 \ \text{grams}} = \boxed{20 \ \text{cm}^{3}}[/tex]

Therefore, the volume of titanium is 20 cm³.

The squirrel sleeps 2548 hours more than the rabbit.

Difference of the numbers

Difference of the numbers means the result of subtracting one number from another.

Given,

If there are 52 weeks in a year,

Then we need to find how many more hours does a squirrel sleep in a year than a rabbit.

First, we have to find the sleeping pattern of squirrel  and rabbit.

A squirrel spends up to 60% of its day asleep, which means that an average squirrel sleeps for almost 15 hours each day.

Similarly, the rabbits are sleep six to eight hours each day.

So for one day,

Rabbit = 8 hours per day

Squirrel = 15 hours per day.

Then the sleeping hours for one week is

Rabbit = 8 x 7 = 56 hours

Squirrel = 15 x 7 = 105 hours

So, for 52 weeks, they spend

Rabbit = 56 x 52 = 2912

Squirrel = 105 x 52 = 5460

So, the difference is

=> 5460 - 2912

=> 2548

Therefore, the squirrel sleeps 2548 hours more than the rabbit.

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