Answer:
No
Explanation:
The chemical identity of the substance is the same. The substance is merely in a different state.
Four people participate in a rope competition. Two of them pull the rope right exerting forces of magnitude 330 N and 380 N. The other two pull left exerting forces of magnitude 320 N and 410N.
A rope competition is played out between four participants. They both pull on the rope to the right while producing forces between 330 N and 380 N. The other two pull to the left with forces of 320 N and 410 N, respectively.
T2 = 250 and T1 = 250.57 [N] .57[N]
In order to create a free body diagram with all the forces acting on the body, we must first extract all the information they provide about the issue.
The free body diagram and associated forces are shown in the accompanying figure.
The T1 and T2 forces can be found by adding up the forces on the Y-axis; these forces are equal because they are a precondition for the problem. Therefore, this equation can be solved.
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An object with a mass of 20 kg has a het force of 80 N acting on it. What is the acceleration of the object?
Explanation:
f=ma
a=f/m
a=80/20 = 4m/s
If a dolphin swims at 1.85 m/s, how far will the dolphin have traveled after 6.0 s?
The distance traveled by by the dolphin is determined as 11.1 m.
What is distance?The distance traveled by an object is the product of speed and time of motion of the object. It measures the total path covered by the object.
The distance traveled by by the dolphin is calculated as follows;
Distance = speed x time of motion
Distance = 1.85 m/s x 6 s
Distance = 11.1 m
Thus, the distance traveled by by the dolphin is determined as 11.1 m.
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2. The longest snake ever found was a python that was 10.0 m long. Sup-
pose a coordinate system large enough to measure the python's length is
drawn on the ground. The snake's tail is then placed at the origin and the
snake's body is stretched so that it makes an angle of 60.0° with the posi-
tive x-axis. Find the x and y coordinates of the snake's head. (Hint: The y-
coordinate is positive.)
Answer:
See below
Explanation:
Hypotenuse is snake length 10 m
y coordinate = 10 sin 60 = 8.7 m
x coordinate = 10 cos 60 = 5m
Two birds are flying south for the winter. Bird 1 reaches its destination in 6 hours, while bird 2 reaches its destination in 12 hours. If bird 2 covers twice as much distance as bird 1, what is the ratio of their average speeds (bird 1/bird 2)?
1.0
0.8
1.2
0.5
The correct answer is option ( A) the ratio of their average speeds (bird 1/bird 2) is 1.0
velocity = distance / Time
Let us assume distance covered by Bird 1 = d
case 1 (Bird 1) :-
time = 6 hours
velocity(Bird1) = d/6 = 0.167*d
case 2 (Bird 2) :-
time = 12 hours
distance is twice of Bird 1 = 2d
velocity(Bird2) = 2d/12 = 0.167*d
now, velocity of Bird1/Bird2 = (0.167*d)/(0.167*d) = 1.0
So,velocity of (Bird1/Bird2) is 1.0 .
Average velocity / Average speed = Total displacement / Total distance. Remember that the numerator is less than or equal to the denominator. As a result, the ratio is always equal to or less than one. Distance traveled divided by time taken is the most commonly used formula for calculating average speed. The other formula is to add the initial and final speeds together and divide by two.
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Sasha is measuring the rate of heat energy given off by an incandescent light bulb. The theoretical value is 55.4 watts. Her measurement has a 2.17 error. Which of the following values may have been Sasha's measurement? (Choose all that apply)
A. 1.20 watts
B. 54.2watts
C.56.6watts
D.53.23watts
E. 57.57watts
The measurement of Sasha, given the data from the question is 57.57 watts (Option E)
How to determine Sasha's measurementThe following data were obtained from the question:
Theoretical value = 55.4 wattsAbsolute error = 2.17 wattsSasha' measurement =?To obtain Sasha's measurement, we shall determine the experimental measurement. This is illustrated below:
Absolute error = Experimental measure - theoretical measurement
2.17 = Experimental measure - 55.4
Collect like terms
Experimental measure = 2.17 + 55.4
Experimental measure = 57.57
Thus, we can conclude that Sasha' measurement is 57.57 watts (Option E)
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1. A bullet is fired into a tree trunk (Figure 1.12), striking it with an ini- tial velocity of 350 m/s. If the bullet penetrates the tree trunk to a depth of 8.0 cm and comes to rest, what is the acceleration of the bullet?
rtdgsehrtejffej0.345
what type of force os your answer in number 4?
The electromagnetic force, the weak nuclear force, the strong nuclear force, and gravity.
The strong force, weak force, electromagnetic force, and gravitational force are the four fundamental forces operating in the universe. They each operate within different parameters and have unique strengths. Although gravity has an infinite range, it is the weakest force. Although it has an infinite range, the electromagnetic force is much stronger than gravity. The weak and strong forces are dominant only at the level of subatomic particles and are only effective over very small distances. Even though it has a weaker name than gravity, the weak force is actually the weakest of the three. The strongest of the four fundamental interactions is the strong force, as its name suggests.
Actually, out of the four fundamental forces, gravity is the weakest. The four forces are the electromagnetic force, gravity, the weak nuclear force, and the strong nuclear force, in that order.
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In a longitudinal wave, the medium moves
left to right
up and down
in circles
In a longitudinal wave, the particles of the medium have to and fro motion about their mean motion, along the direction of wave motion.
Longitudinal waves are waves in which the displacement of the medium is in the same (or the opposite) direction as the wave propagation and the medium vibration is parallel ("along") to the direction the wave travels. Because they create compression and rarefaction when passing through a material, mechanical longitudinal waves are also known as compressional or compression waves. A nice illustration is a wave down the length of a stretched Slinky toy, where the space between the coils grows and shrinks. Examples from the real world include seismic P-waves and sound waves (which are oscillations in pressure, a particle's displacement, and a particle's velocity) (created by earthquakes and explosions).
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A 50-cm-long spring is suspended from the ceiling. A 210 g mass is connected to the end and held at rest with the spring unstretched. The mass is released and falls, stretching the spring by 16 cm before coming to rest at its lowest point. It then continues to oscillate vertically.
The value of spring constant (k) is 25 N/m.
Conservation of energy, potential energy of a stretched spring, gravitational potential energy, frequency of oscillation in a spring coupled to a mass, and variation of acceleration due to gravity with altitude are the principles necessary to answer the given problem.
To begin, use energy conservation to equal change in gravitational potential energy on mass attached to spring and elastic potential energy of stretched spring. Then, in the equation, substitute the specified numbers and solve for the spring constant. Then, calculate the amplitude by taking half of the value of spring stretching from equilibrium, and the frequency of oscillation by using the calculation for frequency of oscillation in a stretched string in terms of mass and spring constant.
Formula apply
U=mgh
U=1/2kx^2
putting the value of K ,x ,mass and g then
k is 25N/m
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If one pound of force acts through a distance of two feet, one foot-pound of work is done.
True
False
It is false that if one pound of force acts through a distance of two feet, one foot-pound of work is done.
What is work?Work is a measure of energy expended in moving an object. It is most commonly calculated by multiplying the force by distance.
It is said that no work is done if the object does not move.
According to this question, if one pound of force acts through a distance of two feet, a work of one pound-two feet is done.
It is therefore, false that if one pound of force acts through a distance of two feet, one foot-pound of work is done.
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phys 181 check picture
Answer:
see below
Explanation:
a^3 = 125 m^3
b^2 = 8.41 s^2
c = 45 m/s Plug these values into the equation
125 / ( 8.41 * 45) = .33 m^2 / s
The surface of the pool table is ℎ=0.790 m from the floor.
The winner of the competition wants to know if he has broken the world speed record for the break shot of 32 mph (about 14.3 m/s ). If the winner's ball landed at a distance of =5.05 m from the table's edge, calculate the speed of his break shot 0. Assume friction is negligible.
At what speed 1 did his pool ball hit the ground?
The calculated velocity is 3.88 m/s
Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. In other words, velocity is a vector, whereas speed is a scalar value. The parameters of speed are time divided by distance. The most often used unit of speed in daily life is the kilometer per hour (km/h), or miles per hour in the US and the UK. The SI's unit of speed is the meter per second (m/s) (mph).
h = 0.5g*t² = 0.77 4.9t²
= 0.77\st²
= 0.1571
t = 0.396 seconds or fall.
Dx = Xo*t, or 5.15 meters.
Xo * 0.396 = 5.15
Break speed is X= 13 m/s.
V² = V² + 2g*h.
V² = 0 + 19.6*0.77
= 15.09
V = 3.88 m/s
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Is the following equation dimensionally correct?
P=√pgh.
where
P is pressure in units of Kg.m/s²/m².
p is density in units of Kg/m³.
g is gravitational acceleration in units of m/s².
h is height in units of m.
The correct answer is :
P = ρgh yields the hydrostatic pressure, which is accurate.
The pressure a liquid applies to nearby bodies when it is at rest is known as hydrostatic pressure.
Water at rest exerts a force known as hydrostatic pressure. It is caused by the water's continual pressure on the basement walls.
The force that blood applies to blood channel walls is a typical illustration of hydrostatic pressure.
Depending on the liquid's density ('ρ'), the height of the water column ('h'), and the acceleration caused by gravity ('g'), the hydrostatic pressure is indicated by the letter "P" of a liquid column.
Because of this, the parameters and the supplied equation P = gh are both accurate.
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the tension T in Newtons in the string of a yoyo of mass 0.001kg is give by the function of two variables (see equation in photo).
find the approximate change in T if R increases from 4cm to 4.1cm and r increases from 0.8cm to 0.9cm. use your answer to explain if the tension increases or decreases.
The change in the tension if the radii r changes from 4.0 cm to 4.1 cm, and R changed from 0.8 cm to 0.9 cm is negative, therefore, tension reduces.
How can the correct description of the change in the graph of the function be found?
Mass of the yoyo = 0.001 kg
Initial value of the spindle radius, R = 4 cm
Initial length of the radius of the yo–yo, r = 0.8 cm
The final values are;
R2 = 4.1 cm, r2 = 0.9 cm
Which gives;
[tex]T_{r \:R} = \frac{0.001 \cdot g \cdot R }{2 \cdot r^{2} + R^2} [/tex]
Which gives;
[tex]T_{{r _1 \:R _1 }} = \frac{0.001 \times 9.8 \times 0.04 }{2 \times 0.008^{2} + 0.04²} = \frac{49}{216} [/tex]
[tex]T_{{r _2 \:R _2 }} = \frac{0.001 \times 9.8 \times 0.041 }{2 \times 0.009^{2} + 0.041^2} = frac{2009}{9215} [/tex]
Therefore;
[tex] \Delta T_{{r \:R }} = frac{2009}{9215} - \frac{49}{216} = - \frac{17591}{1990440} [/tex]
Given that difference between the final and the initial states is negative, the the value of the tension decreases
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a body of mass 7.5kg is moving with the velocity of 1.2, if a force of 15newton is applied to the body calculate its velocity after 2 seconds
The velocity is 5.2 m/s
Force as per the Newton's second law of motion is defined as, for constant mass, mass times the acceleration
F= m x a
where m is the mass of the body in kilograms and a is the acceleration is m/s^2
Now we know that acceleration is nothing but rate of change of velocity
i.e. a= (v -u)/t
where v is the final velocity
u is the initial velocity
and t is the time frame in which change takes place
Now the data given to us is as follows:
Force F= 15 Newton
initial velocity u =1.2 m/s
t= 2 seconds
We are required to find the final velocity v
Now putting the values in the equation,
F= m (v-u)/t
15 = 7.5 (v-1.2)/2
30= 7.5v -9
7.5v=39
v=39/7.5= 5.2 m/s
Hence the velocity is 5.2m/s
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1.
A car is driving on a circular track tha has a diameter of 6km and
traveled across the black shaded region in 1 hour. What will the
cars velocity be in meters/seconds. 1 km= 1000 meters
6 km
V=²& D=vt T = ²
The velocity of the car moving in the circular path is determined as 1.67 m/s.
What is linear velocity?Linear velocity is the measure of the rate of change of displacement with respect to time when the object moves along a straight path.
v = d/t
where;
d is the distance of the objectt is time of motionv = (6 x 1000 m) / (1 x 3600 s)
v = 1.67 m/s
Thus, the velocity of the car moving in the circular path is determined as 1.67 m/s.
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A reconnaissance plane flies 512 km away
from its base at 742 m/s, then flies back to its
base at 1113 m/s.
What is its average speed?
Answer in units of m/s.
Answer in units of m/s
The average speed of round trip is 1192.8 m/s
Average speed of the round trip is
2*994*1491/(994+1491)
= 1192.8 m/s
The overall distance the object covers in a given amount of time is its average speed. A scalar value represents the average speed. It has no direction and is indicated by the magnitude.The mean value of a body's speed over a period of time is its average speed. Since a moving body's speed is not constant over time and fluctuates, the average speed formula is required. The numbers of total time and total distance travelled can be used even with fluctuating speed.Learn more about average speed at:
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The actual mass of a metal sphere was reported in the manual catalog to be 3.53 kg.
A group of 4 students were assigned to perform an experiment and measure the mass of the sphere each one of them using a different scale or balance.
Student 1 reported 3.6 kg
Student 2 reported 3.5 kg
Student 3 reported 3.12 kg
Student 4 reported 3.476 kg
Which of the four students reported the most precise measurement?
1. Student 1
2. Student 2
3. Student 3
4. Student 4
The student that gave the most precise measurement is student 2.
What is a precise measurement?A precise measurement is one that is close together especially when we have a replicate measurement. The measurements that are close together are said to be presence. A measurement is accurate when the measurement is quite close to the true value. Precision ad accuracy are very important in a measurement.
In this case, let us consider the measurement of each student;
Student 1 reported 3.6 kgStudent 2 reported 3.5 kgStudent 3 reported 3.12 kgStudent 4 reported 3.476 kgWe can see that the student that gave the most precise measurement is student 2.
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Rattlesnake Frequency A timber rattlesnake (Crotalus horridus) shakes its rattle at a characteristic frequency of about 3100 shakes per minuteWhat is this frequency in shakes per second?
Answer:
See below
Explanation:
31 00 sh / min / 60 s / min = 51 2/3 shakes per second
What is the escape speed from the Moon?
The Moon’s mass is 7.4×10^22 kg and its radius is 1700 km.
The speed of a spacecraft moving in a circular orbit just above the lunar surface: v = 1700 m/s
Express your answer using two significant figures.
v = __________ m/s
Answer:
1/2 m v^2 - G M m / R escape velocity equal to energy at surface
v^2 = 2 G M / R = 2 * 6.67E-11 * 7.4E22 / 1.7E6
v^2 = 2 * 6.67 * 7.4 / 1.7 * 105 = 5.81E6
v = 2410 m/s = 2400 m/s
Select the correct answer.
A force Fmaking an angle 9 with the horizontal is acting on an object resting on the table. Which statement Is true for the motion of sliding the
object on the table?
• A. It Is Independent of all the forces acting on the object.
O B. It depends only on the forces acting along the x-axis.
O C. It depends only on the forces acting along the y axis.
O D. It depends only on the normal force acting on the object.
O E. It depends only on the frictional force acting on the object.
bgGjzbxvbhijhFgavvBbzvghzjznbbgzgh
You are asked to do an experiment to measure g. You set up a device that drops a metal ball from rest from a height of 1.650 meters. Using an accurate timing device that detects the release of the ball and it’s landing in the floor, you measure the average time of the falling ball to be 0.585 seconds. What do you measure the value of g as?
The value of g of the metal ball that falls from a height of 1.65 m at an average of 0.585 seconds is 4.82 m / s²
a = v / t
v = d / t
a = Acceleration
v = Velocity
d = Distance
t = Time
d = 1.65 m
t = 0.585 s
v = 1.65 / 0.585
v = 2.82 m / s
g = a = 2.82 / 0.585
g = 4.82 m / s²
Here the acceleration is called as g because the ball is falling vertically. That is why it is called as g ( Acceleration due to gravity )
Therefore, the value of g of the metal ball that falls from a height of 1.65 m at an average of 0.585 seconds is 4.82 m / s²
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The speed of a train increases from 100 km/hr to 250 km/hr in 5 minutes. What is its acceleration?
Answer:30 km/hr2 is the exal
Explanation:
Which of these objects could be falling with constant acceleration?
Object 1 and Object 2 will have a constant acceleration.
We know the expression for Displacement, Acceleration, and Time can be represented by the equation: S = ut + 1/2at². We will compare cases for each object at a given position and time and check if the object maintains a constant acceleration.
=> S = ut +1/2at², where S = Displacement/position of object, u = Initial velocity, t = time, a = acceleration.
For Object 1,
Case 1 : 0.44 = 0*0.3 + 1/2*a*(0.3)²
a = 9.78
Case 2 : 3.14 = 0*0.08 + 1/2*a*(0.8)²
a = 9.81
Acceleration is approximately constant for object 1.
For Object 2:
Case 1 : 0.06 = (0) (0.3) + ½ a (0.3)²
a = 1.33
Case 2: 3.09 = (0) (2.1) + ½ a (2.1)²
a = 1.40
Acceleration is approximately constant for object 2.
For Object 3:
Case 1 : 0.44 = (0) (0.3) + ½ a (0.3)²
a = 9.78
Case 2: 3.09 = (0) (2.1) + ½ a (2.1)²
a = 1.40
Acceleration has a lot of differences in both cases of Object 3 so it's not constant.
Hence, Object 1 and Object 2 have constant acceleration.
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Sam's mom says: "We're about to eat dinner! Don't go more than a few blocks from home!" Is Sam's mom
more worried about Sam's distance or his displacement? Circle one and explain why you picked it.
Answer:
Displacement
Explanation:
I think Sam's mom isn't worried with how far away he goes, but will be upset if he isn't home fast enough for dinner.
II Two electrons are in the vicinity of a proton. The potential energy of the
proton is
-1.6 x 10-25 J. (a) What is the potential at the proton's position? (b) If one of
the electrons is 1.0 cm from the proton, what is the distance of the second
electron from the proton?
Please explain HOW to answer this(especially part B)
There are two electrons close to a proton. The proton's potential energy is
the energy possessed by a body by virtue of its position relative to others, stresses within itself, electric charge, and other factors.
9.216 x 10^-8 N
q1 = 1.6 x 10^-19 C
q2 = - 1.6 x 10^-19 C
r = 5 x 10^-11 m
A source of electrostatic force is
F = k q1 q2 / r^2
F = (5 x 10-11)2 / (9 x 109 x 1.6 x 10-19 x 1.6 x 10-19)
F = 9.216 x 10^-8 N
Due to the nature of the charges being in opposition to one another, this force is appealing.
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Applying a constant net force to an object causes it to accelerate at 0=9.0 m/s2.
What will the acceleration 3 of the object be if the force is doubled and the mass is doubled?
The acceleration of the object be if the force is doubled and the mass is doubled is equal to 9m/s².
let the initial mass of the object be m₁.
given:
initial acceleration (a₁) = 9m/s²
initial constant force (F₁) = constant (k)
therefore,
F₁= m₁×a₁ ------------------------------- equation 1
now,
according to the the question the force is doubled
i.e.
new force (F) = 2×F₁
and the mass too is doubled,
i.e.
new mass of the object(m)=2×m₁
new equation for force and acceleration:
F= m ×a
2F=2m₁×a --------------------------equation 2
dividing equation 2 by equation 1
we get,
[tex]\frac{2F}{F}=\frac{2m₁×a}{m₁×a₁ }[/tex]
a = a₁
a=9m/s²
the acceleration of the object be if the force is doubled and the mass is doubled is equal to 9m/s².
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At the end of a race a runner decelerates from a velocity of 9.00 m/s at a rate of 0.300 m/s2.
(a) How far does she travel in the next 15.0 s?
(b) What is her final velocity?
(a)In the next 15.0s, she traveled 101.250 m.
(b) 4.50 m/s is the runner's final speed.
Given:- initial velocity = 9m/s , deacceleration = 0.3 m/s2
distana(d), she moves in time (t)=15 s,
and we must determine this using the second equation of motion.
S = ut + 1/2 at2,
where s = the distance
u = initial velocity
t = time
a=-d = 0.300m/s
t=15.0
By putting all values in the formula above,
we have
d = (9.00)x(15.0)-1/2 (0.300) (15.0)²
d= 101.250 m.
In the next 15.0s, she traveled 101.250 m.
final speed (v) =?
from 1 Equation of Motion : v = u+at.
To solve, v=?
u=9.00 m/s
a= -d= 0.300 m/s²
t=15.0
v=u+at
v= 9 - 0.300 X15.0
= 4.50 m/s
4.50 m/s is the runner's final speed.
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76. Two electric charges -6μC and
+6μC are placed respectively in two
points A and B distant of 1m apart. The
electric field is null at the point C:
A.Located in the middle of the
segment AB
B.Located outside segment AB at
1m from A.
C.Located outside segment AB at
1m from B
D.Outside the line AB
E.No answer is right.
The correct answer is option (A) Located in the middle of the segment AB the electric field is null at the point C .
When a positive and negative charge interact, their forces act in the same direction, from positive to negative. As a result, opposite charges attract each other: the electric field and forces generated by two electrical charges of opposite polarity.
The two charges are to each other.The electric field will not be zero between two opposite charges. For opposite charges, the point of zero electric fields will lie outside the system along the line joining attracted the two charges.The field is strongest where the lines are closest together. The electric field lines converge toward charge one and away from charge two, indicating that charge one is negative and charge two is positive.
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