(cube root of x) + 5 all over cube root of x

Answer:

Leon has $15 and Laci has $61

Step-by-step explanation:

Let x = the amount Leon has.  So 4 times that plus $1 would be 4x+1.  Our equation is:

x + (4x+1) = 76

Combine like terms

5x + 1 = 76

Subtract 1 from both sides

5x = 75

Divide both sides by 5

x = 15.  This is Leon.  Laci is 4(15) +1, or 61.

Answer:986

Explanation? Calculator;)

Answer: 986

Step-by-step explanation? It’s easier to use a calculator.

Based on the definition of a function,

1. The relation on the right is not a function.

2. Domain: {20, 70, -60}

Range: {3, -6, 2, 5}

A relation that is defined as a function has each domain value that is assigned to only one possible range value, in such a way that, each of the domain element cannot have two different range element that corresponds to it.

1. The relation on the right has a domain element, -60, which corresponds to two different range element, -6 and 2.

Therefore, the relation on the right is not a function.

2. The domain of the relation that is not a function is: {20, 70, -60}

The range of the relation that is not a function is: {3, -6, 2, 5}

In summary, based on the definition of a function,

1. The relation on the right is not a function.

2. Domain: {20, 70, -60}

Range: {3, -6, 2, 5}

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Answer:

The cost per unit of an item is called unit cost

Answer:

P = -8

Step-by-step explanation:

Answer:

y = 2x + 3

Step-by-step explanation:

i gotchu

Answer:e=8/7=1.143

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    4*e-5+2*e-(e+3-2*e)=0

Add  8  to both sides of the equation :

                     7e = 8

Divide both sides of the equation by 7:

                    e = 8/7 = 1.143

And then you get

Divide both sides of the equation by 7:

                    e = 8/7 = 1.143

Answer:

                   4*e-5+2*e-(e+3-2*e)=0

Add  8  to both sides of the equation :

                    7e = 8

Divide both sides of the equation by 7:

                   e = 8/7 = 1.143

And then you get

Divide both sides of the equation by 7:

                   e = 8/7 = 1.143

Step-by-step explanation:

if value1 = 2.0 and value2 = 12, then the output of a following command = 24.0

The correct option is A.

The output of the given document is issued is 24.0 (2.0 * 12=24, i.e., it is simply the multiplication operation) if both values, i.e., value 1 and value 2, are taken into consideration as decimal data type values.

There is only one value represented by simple data types. Integer: a basic data type used in the creation of policies. A positive or negative whole number is represented by the integer data type. 0, 1, 2, 3, and 4 are examples of integers.

An attribute of data that instructs a computer system how to interpret its value is called the data type. Knowing the different types of data makes it possible to collect information in the desired format and ensure that the values of each property are as expected.

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I understand that the question you are looking for is:

What is the output of the following command, given that value1 = 2.0 and value2 = 12? print (value+ value2)

A) 24.0

B) value + value2

C) 24

D) 2.0 + 12

Answer:

[tex]x=27, \quad x= \dfrac{1}{27}[/tex]

Step-by-step explanation:

[tex]\boxed{\begin{minipage}{3.7 cm}\underline{Logs Laws}\\\\$\log_ba=\dfrac{\log_ca}{\log_cb}$\\\\\\$\log_ab=c \iff a^c=b$\\\end{minipage}}[/tex]

Given equation:

[tex]\log_3x=9\log_x3[/tex]

Change the base of  9logₓ3  to base 3:

[tex]\begin{aligned}\implies \log_3x & =9\log_x3\\\\& =\dfrac{9\log_33}{\log_3x}\\\\&=\dfrac{9(1)}{\log_3x}\\\\&=\dfrac{9}{\log_3x}\end{aligned}[/tex]

Therefore:

[tex]\implies \log_3x=\dfrac{9}{\log_3x}[/tex]

[tex]\textsf{Let }\log_3x=u:[/tex]

[tex]\implies u=\dfrac{9}{u}[/tex]

[tex]\implies u^2=9[/tex]

[tex]\implies u=\pm3[/tex]

[tex]\textsf{Substitute back in }u=\log_3x:[/tex]

[tex]\implies \log_3x=\pm3[/tex]

Case 1

[tex]\implies \log_3x=3[/tex]

[tex]\implies 3^3=x[/tex]

[tex]\implies x=27[/tex]

Case 2

[tex]\implies \log_3x=-3[/tex]

[tex]\implies 3^{-3}=x[/tex]

[tex]\implies \dfrac{1}{3^3}=x[/tex]

[tex]\implies x=\dfrac{1}{27}[/tex]

Answer: x=3   x=1/27

Step-by-step explanation:

[tex]log_3x=9log_x3\\[/tex]

The area of acceptable values:

[tex]x > 0\ \ \ \ x\neq 1\\Hence,\\x\in(0,1)U(1,+\infty)[/tex]

Solution:

[tex]\displaystyle\\log_3x=\frac{9}{log_3x} \ \ \ \ \ \boxed{ log_ab=\frac{1}{log_ba} }\\\\Multiply\ both\ parts\ of\ the\ equation\ by\ log_3x :\\\\log^2_3x=9\\log^2_3x=3^2\\ log_3x=б3\\\\log_3x=3\\\\x=3^3\\x=3*3*3\\x=27\\\\\\log_3x=-3\\x=3^{-3}\\\displaystyle\\x=(\frac{1}{3})^3\\ x=\frac{1}{3}*\frac{1}{3}*\frac{1}{3} \\ x=\frac{1}{27}[/tex]

Answer:

(E) 6x+12

relations: A relation R is the subset of the cartesian product of X x Y, where X and Y are two non-empty elements. It is derived by stating the relationship between the first element and second element of the ordered pair of X × Y. The set of all primary elements of the ordered pairs is called a domain of R and the set of all second elements of the ordered pairs is called a range of R.

functions: A relation ‘f’ is said to be a function, if every element of a non-empty set X, has only one image or range to a non-empty set Y.

f(x) = 3x + 4

2 * f(x) + 4 = (2 × f(x)) + 4

From above equation

= (2 × (3x + 4)) + 4

= (2 × 3x) + (2 × 4) + 4

= 6x + 8 + 4

= 6x + 12

Therefore, the value of 2f(x) + 4 is ′6x + 12′.

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Answer:

Step-by-step explanation:

30 feet.

Answer:

Angle Bisector I believe

Step-by-step explanation:

Apologies if I am wrong

Answer:

128 feet²

Step-by-step explanation:

48 = x + x + 2x + 2x = 6x

x = 8

x × 2x = 8 × 16 = 128

Answer:

Step-by-step explanation:

There are 25 numbers between and including 1-25, so there are 25 possibilities. The possible outcomes are:

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25

Answer:

It would be 3710.

Step-by-step explanation:

The solution to the expression is x= 18

15 over x=2 equals 3 over 4 can be written as follows

15/x+2 = 3/4

Cross multiply both sides

15×4= 3(x+2)

60= 3x +6

collect the like terms

3x= 60-6

3x= 54

divide both sides by the coefficient of x which is 3

3x/3 = 54/3

x= 18

Hence the value of x in the expression is 18

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The given bounded region is the set

[tex]R = \left\{(x,y) ~:~ 0 \le x \le 1 \text{ and } x^4 \le y \le x^{1/4} \right\}[/tex]

assuming the curves are [tex]y=x^4[/tex] and [tex]x=y^4\implies y=x^{1/4}[/tex] (since [tex]x>0[/tex] in the first quadrant).

The coordinates of the centroid are [tex](\bar x, \bar y)[/tex] where [tex]\bar x[/tex] and [tex]\bar y[/tex] are the average values of [tex]x[/tex] and [tex]y[/tex], respectively, over the region [tex]R[/tex]. These are given by the ratios

[tex]\bar x = \dfrac{\displaystyle \iint_R x \, dA}{\displaystyle \iint_R dA} \text{ and } \bar y = \dfrac{\displaystyle \iint_R y\,dA}{\displaystyle \iint_R dA}[/tex]

Compute the area of [tex]R[/tex].

[tex]\displaystyle \iint_R dA = \int_0^1 \int_{x^4}^{x^{1/4}} dy \, dx \\\\ ~~~~~~~~ = \int_0^1 \left(x^{1/4} - x^4\right) \, dx \\\\ ~~~~~~~~ = \frac45 - \frac15 = \frac35[/tex]

Integrate [tex]x[/tex] and [tex]y[/tex] over [tex]R[/tex].

[tex]\displaystyle \iint_R x \, dA = \int_0^1 \int_{x^4}^{x^{1/4}} x \, dy \, dx \\\\ ~~~~~~~~ = \int_0^1 x \left(x^{1/4} - x^4\right) \, dx \\\\ ~~~~~~~~ = \int_0^1 \left(x^{5/4} - x^5\right) \, dx \\\\ ~~~~~~~~ = \frac49 - \frac16 = \frac5{18}[/tex]

[tex]\displaystyle \iint_R y \, dA = \int_0^1 \int_{x^4}^{x^{1/4}} y \, dy \, dx \\\\ ~~~~~~~~ = \frac12 \int_0^1 \left((x^{1/4})^2 - (x^4)^2\right) \, dx \\\\ ~~~~~~~~ = \frac12 \int_0^1 \left(x^{1/2} - x^8\right) \, dx \\\\ ~~~~~~~~ = \frac12 \left(\frac23 - \frac19\right) = \frac5{18}[/tex]

Then the centroid's coordinates are

[tex]\bar x = \dfrac{\frac5{18}}{\frac35} = \boxed{\frac{25}{54}} \approx 0.463[/tex]

[tex]\bar y = \dfrac{\frac5{18}}{\frac35} = \boxed{\frac{25}{54}}[/tex]

Answer:

The smaller number is 27 and the larger number is 44

Step-by-step explanation:

Let x = the larger number

Let y = the smaller number

x + y = 71

x = y + 17  Substitute in y + 17 for x in the first equation.

x + y = 71

y +17 + y = 71  Combine the y's.

2y + 17 = 71  Subtract 17 from both sides of the equation

2y = 54  Divide both sides of the equation by 2

y = 27.  Plug 27 in for y for either of the two original equation to find x

x + y = 71

x + 27 = 71  Subtract 27 from both sides of the equation

x = 44

First order equations include linear equations. In the coordinate system, the linear equations are defined for lines. A linear equation in one variable is one in which there is a homogeneous variable of degree 1 (i.e., only one variable). Multiple variables may be present in a linear equation. Linear equations in two variables, for example, are used when a linear equation contains two variables. Examples of linear equations include 2x - 3 = 0, 2y = 8, m + 1 = 0, x/2 = 3, and 3x - y + z = 3.

10) -6(-5+r) = 102

     30 -6r =102

     -6r = 72

        r = -12

11) -1 = x - 4 +4

      x =-1

12) 0 = -6x -2x

     -8x = 0

 x= 0

13)5n+ 4n =9

      n =1

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The correct option is C. x² + (x – 2)² = 100.

The equation which depicts x, the side length of the greater square is  x² + (x – 2)² = 100.

In geometry, a square is a plane figure with 4 equal sides as well as 4 right (90°) angles. A square is a subset of a rectangle (an equilateral rectangle) and a subset of a parallelogram (an equilateral & equiangular one).

Now, as per the question;

This is given by relation shown by expression;

x² + (x-2)² = 100

Therefore, the equation which represents x, the side length of the greater square is x² + (x-2)² = 100.

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The complete question is-

A group of students is given a 10 by 10 grid to cut into individual unit squares. The challenge is to create two squares using all of the unit squares. Their teacher states that after the two new squares are formed, one should have a side length two units greater than the other.

Which equation represents x, the side length of the greater square?

A. x² + (x – 2)² = 10

B. x² + 2x² = 10

C. x² + (x – 2)² = 100

D. x² + 2x² = 100

Answer:

x = 14    y = 59

Step-by-step explanation:

the angle (5x - 11) is equal to the angle (3x + 17) and 3x+ 17 is equal to y

5x - 11 = 3x + 17

5x - 3x = 17 + 11

2x = 28

x = 28/2

x = 14

3x+17 = y

3(14) + 17 = y

y = 59

Step-by-step explanation:

Fact 1: Alternate angles are equal.

Angles, (5x-11)° and (3x+17)° are ALTERNATE angles and so,

(5x-11)° = (3x+17)°

5x - 3x = 17 + 11

2x = 28

x = 28 ÷ 2

x = 14

NB: x does NOT have the degree sign because it's NOT an angle on its own, but rather within the bracket/part of the calculation to get the angle degree.

Fact 2: Opposite angles are equal.

Y° and (3x+17)° are OPPOSITE angles

y = (3x+17)°

y = (3x14) + 17

y= 42 + 17

y = 59°

Hope this helps!

Answer:

20%

Step-by-step explanation:

20/25 = blue

This means 5/25 of the balls in the bag are NOT blue

(25-20 = 5)

We need to convert 5/25 to a percentage

[tex]\dfrac{5}{25} = \dfrac{5\times4}{25\times4}=\dfrac{20}{100}[/tex]

% = per cent

"per" means "out of"

"cent" means "one hundred"

so

20/100 = 20%

The value of x in the hexagon given in the image above is: 132°.

The sum of all interior angles of an n-sided polygon = (n - 2)180, where n is the number of angles/sides of the polygon.

The polygon shown is a hexagon with six (6) interior angles. Find its sum.

Sum of the hexagon = (6 - 2)180

Sum of the hexagon = 720°

This means that if we add the measures of all the six interior angles of the given hexagon, we would get 720°.

Therefore:

x + 108 + 113 + 132 + 75 + 160 = 720

x + 588 = 720

x = 720 - 588

x = 132°

Thus, the value of x in the hexagon given in the image above is: 132°.

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Answer: The equations are:

X+3=Y;

45X + 75Y  = 1455 ;

The variables used are X and Y specifying number of small and large boxes

Step-by-step explanation:

Let X be  the number of small boxes

Let Y be  the number of big boxes

The first equation is:  X+3=Y;  (  Since there were 3 more small boxes shipped than large boxes )

The second equation is:    45X + 75Y  = 1455   ( this is because the small box weighs 45 pounds and big box weighs 75 pounds.  The total weight of the small boxes is 45 times the weight of each individual box. And the total weight of the second boxes is equal to 75Y.)

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Answer:

Step-by-step explanation:

The variables used are A and B specifying number of small and large boxes

Let the number of small box is A

Let the number of large box is B

The first equation is:  A+3=B;

(  Since there were 3 more small boxes shipped than large boxes )

The second equation is:    45A + 75B  = 1455   ( this is because the small box weighs 45 pounds and large box weighs 75 pounds.  The total weight of the small boxes is 45 times the weight of each  box. And the total weight of the second boxes is equal to 75B.)

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Answer:

3 over 4 is the slope

Step-by-step explanation:

y2 - y1 over x2 - x1 is how you get the slope. To get those points you simply pick two points, it doesn’t matter which 2.

Answer:

slope = [tex]\frac{3}{4}[/tex]

Step-by-step explanation:

calculate the slope m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 9, 4) and (x₂, y₂ ) = (7, 16) ← 2 ordered pairs from the table

m = [tex]\frac{16-4}{7-(-9)}[/tex] = [tex]\frac{12}{7+9}[/tex] = [tex]\frac{12}{16}[/tex] = [tex]\frac{3}{4}[/tex]