what is the Inverse of
Y=2x-1?

Each child would get 1/12 th part of the whole watermelon.

For given question,

8 children have to share two thirds of a watermelon equally .

This means we need to equally distribute 2/3 of whole watermelon to 8 children.

To divide 2/3 part of of a watermelon equally into 8 parts, we need to divide 2/3 by 8.

(2/3) ÷ 8

= [tex]\frac{(\frac{2}{3} )}{8}[/tex]

We know that in 8 = 8/1

So, we rewrite the denominator of above fraction as,

[tex]\frac{(\frac{2}{3} )}{8} \\\\= \frac{(\frac{2}{3} )}{(\frac{8}{1} )} \\\\=\frac{2}{3} \times \frac{1}{8} \\\\=\frac{1}{12}[/tex]

This means, each child will get 1/12 part of the whole watermelon.

Therefore, each child would get 1/12 part of the whole watermelon.

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The intersection of three sets A,B and C is {₋2 , 11}.

Given set A = {₋2,7,8,11}

set B = {₋2,7,11}

set C = {₋2,8,11}

we need to find A∩B∩C.

The components shared by all the sets A, B, and C are given by the intersection of A and B as a set. A ∩ B ∩ C is a notation that can be used to indicate the intersection of A, B, and C.

To obtain A intersection B intersection C, first determine the common elements of sets A and B, or A ∩ B. Then determine the common elements of sets B and C, or B ∩ C. Finally, compute the common elements of these two results.

we first find:

A∩B = {₋2,7,8,11} ∩  {₋2,7,11}

=  {₋2,7,11}

then B ∩ C =  {₋2,7,11} ∩  {₋2,8,11}

= {₋2 , 11}

now (A∩B) ∩ (B∩C) =  {₋2,7,11} ∩ {₋2 , 11}

= {₋2 , 11}

hence we get the intersection of three sets as {₋2 , 11}

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Answer:

x = 5

Step-by-step explanation:

3x + 15 = 30  Subtract 15 from both sides of the equation

3x = 15  Divide both sides by 3

x = 5

The total goal distance Sarah run is 7/8.

The distance covered by Sarah is found to be more than Tori.

A number's exponent indicates what many times a number has been multiplied by itself. For instance,  2×2×2×2 can be composed as 2⁴.

If a fraction does have a negative exponent, we take its reciprocal to make this same exponent positive.

If a fraction does have a negative exponent, we take its reciprocal to create the exponent positive.

Some properties of exponents are-

Now, as pet the given question;

Tori has covered 2⁻³ of the total distance;

Thus, it can be written as;

= 1/2³

= 1/8

Lets consider the total distance covered by both of them is 1.

Then, the distance covered by Sarah will be;

= 1 - 1/8

= 7/8

Thus, the distance covered by Sarah is 7/8.

As, 7/8 > 1/8

Therefore, the distance covered by Sarah is more than Tori.

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Answer:

1. x = 9

2. x = 4

3 x =

4. x = 10

5. x =

6. x = 11

7. x = -1

8.x =

9. x = -4

10. x =

11. x = 10

12.x = -10

Answer:

50.96 days can be rounded to 51

73381
1223
51

Step-by-step explanation:

Too bad I can't see the choices. I will give the numbers both as exact figures rounded to integers and you have to choose the closest to these.

Part A

50.96 days

Part B

6.6043 x 10⁵ gallons at 9 gallons per minute = (6.6043 x 10⁵)/9 = 660,430/9 = 73,381.11 gallons per minute  rounded to 73,381 minutes

73,381 minutes = 73,381 /60 = 1223.02  hours 1223  hours

1223 hours = 1223/24 = 50.96 days rounded to 51 days

Hope that helps. Ask if you need further info

Answer:

a) P(X < 24) = 0.1151

b) P(24 < X < 36) = 0.7698

c) X value for P(x < X) = 0.95 is X = 38.225

Step-by-step explanation:

a) P(X < 24)

Since μ = 30  and   σ = 5 we have:

[tex]\text {z value = } \dfrac{24-30}{5}} = -1.2[/tex]

P(X < 24) =  P(Z < -1.2) = 0.1151
You can use a calculator or the standard normal tables to determine P(Z < -1.2)

b) P(24 < X < 36)

First find P(X < 36) using the technique detailed in part a)

For 36, the Z value is  
[tex]\dfrac{36-30}{5} = 1.2[/tex]

P(X < 36) = P(z < 1.2) = 0.8849

P(24 < X < 36) = P(X < 36) - P(X < 24) = 0.8849 - 0.1151 = 0.7698

c) X value below which 95% of the area is covered

Using a calculator (or tables) the z value corresponding to P(z < Z) = 0.95 is Z = 1.65(approx)

[tex]\text{We have } \dfrac{X - \mu}{\sigma} = z\\\\\dfrac{X - 30}{5} = 1.645\\\\\text{Multiplying both sides by 5: }\\\\X - 30 = 1.645 \times 5 = 8.225\\\\X = 30 + 8.225 = 38.225[/tex]

So X value is 38.225-

Answer: y=[tex]\frac{5-9x}{2}[/tex]

s=-30+10t

Step-by-step explanation:

9x + 2y = 5; y

9x-9x+2y = 5-9x

2y=5-9x

y=[tex]\frac{5-9x}{2}[/tex]

1/15s - 2/3t = -2; s

(1/15s - 2/3t = -2)*15     ==> Get rid of fraction by multiplying both sides by 15

s - 30/3 t=-30

s-10t=-30

s=-30+10t

The time it will take for the money in the bank to reach a total of 29500 dollars would be = 30 years.

To calculate the time for the interest compounded annually the formula below is used:

Simple interest = principal× time×rate/ 100

Simple interest = principal× time×rate/ 100Simple interest = total amount in the bank - principal amount

= 29500 - 10000

= $19,500

Principal = $10000

Rate = 6.5%

Time = ?

From the given formula, make t that subject of formula;

T = $19,500 ×100/$10000×6.5

T = 1950000/65000

T = 30 years.

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Answer:

C. y = 2x + 2

Step-by-step explanation:

There are 2 points on the line (0,2) and (-3,-4)

from (-3,-4) to (0,2), rise over run is 6/3 so slope is 2

You can calculate it too

m = (y2-y1)/(x2-x1)

m = (-4 - 2)/(-3 - 0) = -6/-3 = 2

Using m = 2, x = 0, y = 2

y = mx + b

2 = 2(0) + b

b = 2

therefore

y = 2x + 2

[tex]111.2[/tex]

Step-by-step explanation:

As per the question, 15 times 15 i.e. 225

[tex]15 \times 15 = 225[/tex]

225 divide by 20 i.e. 11.25

[tex] \frac{225}{20} = 11.25[/tex]

take away five from the 11.25 then it will be 11.2

Add 100 to 11.2 i.e

[tex]11.2 + 100 = 111.2[/tex]

Answer: 115

Step-by-step explanation:

[tex]\displaystyle\\\frac{15*15}{20-5} +100=\\\\\frac{15*15}{15} +100=\\\\15+100=\\\\115[/tex]

The sum will be negative.

The product of two negative numbers is always positive and if we add two numbers, the sign of the greater number is used in the result.

Here, we are given an expression 4a + (-3b)

Also we are told that a < b and b is a negative number

Mow, since b is a negative number, (-3b) will always be positive. This is because the product of two negative numbers, here -3 and b, will always be positive.

Now, a can be positive or negative. If a is positive, the sum will always be positive. However, if it is negative, the sum can be either positive or negative.

Here, in fact, since a < b, a will always be negative only

Let us take an example, say a = -3 and b = -2

Then the sum becomes 4(-3) + (-3)(-2)

= -12 + 6

= -6

If we observe closely since a and be are both negative and a < b, in absolute terms a will always be greater than b since for negative numbers higher the value, smaller is the number.

Thus, we can conclude that 4a > (-3b) for all values of a and b

and since 4a will always be negative, the sum will also be negative.

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Based on the number of seals that were tagged near Avila Beach, the approximate number of seals near Avila Beach is 44 seals

The number of seals near Avila beach can be said to be x. If it is x, then the formula is:
12 = 27% x ×

27%x = 12

0.27x = 12

Solving for x then gives:

x = 12 / 0.27

x = 44.44

= 44 seals

In conclusion, there are approximately 44 seals near Avila beach.

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Answer:

4 [tex]\sqrt{10}[/tex]

Step-by-step explanation:

Simplify

[tex]\sqrt{160}[/tex]

We can rewrite this as

[tex]\sqrt{16 * 10}[/tex]

Breaking this up

[tex]\sqrt{16} \sqrt{10}[/tex]

We know the square root of 16 is 4

4 [tex]\sqrt{10}[/tex]

sqrt(10) cannot be simplified so

Answer:

[tex]4\sqrt{10}[/tex]

Step-by-step explanation:

160 = 16 * 10

[tex]\sqrt{160} = \sqrt{16 \cdot 10} = \sqrt{16} \cdot \sqrt{10} = 4\sqrt{10}[/tex]

we cannot simplify further as 10 is 2*5, there are no more squares to simplify.

Blaise Pascal invented the statistical method known as regression. False. The author learned through the reading that adding a bathroom increases home prices more than adding a bedroom does.

What does a statistical regression mean?

What does regression mean?

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Answer:the graph is not linear

Step-by-step explanation:

Based on the baths, nail trims, brush-outs, and ear cleanings the pet groomer gave, for every 5 nails, the groomer gave 3 baths.

The pet groomer gave out a total of 15 nail trims. To find out the service that the pet groomer gave 3 of for every 5 nail trims, find out the number that takes 15 nail trims to 5 nail trims and then use this number to divide the number of the other services given.

The service that comes to a quantity of 3 would be the answer.

= 15 nail trims / 5

= 3

Use 3 to divide the rest. When baths are divided by 3 we get:

= 9 / 3

= 3 baths

In conclusion, for every 5 nail trims, the groomer gave out 3 baths.

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The equivalent expression to -1/3-(-5/12) is 1/12.

From the information, the expression given is -1/3-(-5/12).

Therefore, this will be computed thus:

= -1/3-(-5/12)

= - 1/3 + 5/12

= 5/12 - 1/3

= 5/12 - 4/12

= 1/12

Therefore, the equivalent expression to -1/3-(-5/12) is 1/12.

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The original amount borrowed was $517.

Simple Interest is the method to calculate the interest charged for a given number of years and given rate , in simple interest the principle remains same for each year.

Simple interest =[tex]\frac{P*R*T}{100}[/tex]

where P= principle, R=rate in % , T= time

We know that Amount= Principle+ Simple Interest........(1)

According to the question

Amount=$610.06

Rate=18%

time = 1yr

Substituting the value in equation (1) we get

[tex]610.06=P+\frac{P*18*1}{100}[/tex]

[tex]610.06=\frac{100P+18P}{100}[/tex]

[tex]610.06=\frac{118P}{100}[/tex]

[tex]61006=118P[/tex]

[tex]P=\frac{61006}{118}[/tex]

[tex]P=517[/tex]

Therefore  , The original amount borrowed was $517.

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Holy will take 13/5 or 2.6 hours to finish the bookcase.

The relation between time and work is

Work Done = Time Taken × Rate of Work ·

or, Rate of Work = 1 / Time Taken ·

or, Time Taken = 1 / Rate of Work ·

Now it is given that,

Time taken by Fritz to build a bookcase =  8 hours

So, Bookcase build by Fritz in 1 hour = 1/8

Similarly,

Time taken by Holly to build a bookcase =  10 hours

So, Bookcase build by Holly in 1 hour = 1/10

So, bookcase build in 3 hours

Fritz = 3/8

Holly = 3/10

Total bookcase build in 3 hours =  3/8 + 3/10 =  27/40

So. remaining work =  1 - 27/40 =  13/40

Thus, Time taken by Fritz to complete the bookcase =  8 * (13/40) hours

                                                                                         =  13/5 or 2.6 hours

Thus, Holy will take 13/5 or 2.6 hours to finish the bookcase.

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The function shows that the cost of hotdogs is 1.75 and the cost of hamburger is 1.5.

Let hotdogs = h

Let hamburger = x

The expression will be:

h + x = 3.25

h + 7x = 12.25

Subtract the functions

6x = 9

x = 1.5

Therefore, hot dogs will be:

= 3.25 - 1.5

= 1.75

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At a concession stand, one hot dog and one hamburger cost $3.25; one hot dog and seven hamburger cost $12.25. Find the cost of one hotdog and the cost of one hamburger.

The linear equation to calculate the height is H(t)=33t.

Given that the elevator descends at the speed of 33 feet/second.

If a person gets on the elevator at the observer deck and after 10 seconds he finds himself at 1490 feet above the ground then height descended  in 10 seconds= 33×10

                                         = 330 feet

The height of the observer deck from the ground = 1490+330

                                                                             = 1820 feet

The required equation to calculate the height of above the ground H(t)=33t.

We can calculate  the height of the elevator at any instant using the above expression.

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When compared to other scheduling methods for real-time systems, EDF is quite effective. It can maintain all work deadlines while increasing CPU utilization to around 100%.

The earliest deadline first (EDF) algorithm is a dynamic priority scheduling algorithm that is used in real-time systems.

EDF is an optimal algorithm, it will schedule a task set if possible. EDF is also independent of the task's period and can be used to schedule aperiodic tasks because it makes no assumptions about job periodicity. If two jobs have the same absolute deadline, choose one at random.

When compared to fixed priority scheduling techniques such as rate-monotonic scheduling, EDF can guarantee all system deadlines at higher loading. On non-preemptive uniprocessors, EDF is also an optimal scheduling algorithm, but only among scheduling algorithms that do not allow inserted idle time.

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Answer: Ali is correct because all of the negatives are mostly in quadrant 2.

Step-by-step explanation:

Answer:

x= 2/7

Step-by-step explanation:

Multiply both sides by the common denominator

3x^2 +6x−2=3x^2 −x

Move everything to the left side.

3x^2+6x-2-3x^2+x=0

Simply.

7x-2=0

Separate the cosntants and variables.

7x=0+2

Add or subtract zero

7x=2

Then divide both sides by 7.

7x/7=2/7

Cancel out common factors in the numerator and denominator

x=2/7

Answer:

  x = 2/7

Step-by-step explanation:

You want to solve the equation 3x/(3x-1) + 2/x = 1.

It works nicely to subtract 1 from both sides, then simplify.

  [tex]\dfrac{3x}{3x-1}+\dfrac{2}{x}=1\\\\\dfrac{3x}{3x-1}\cdot\dfrac{x}{x}+\dfrac{2}{x}\cdot\dfrac{3x-1}{3x-1}-\dfrac{x(3x-1)}{x(3x-1)}=0\\\\\dfrac{3x^2+6x-2-3x^2+x}{x(3x-1)}=0\qquad\text{combine terms}\\\\\dfrac{7x-2}{x(3x-1)}=0\qquad\text{simplify}\\\\7x-2=0\qquad\text{expression is 0 when numerator is 0}\\\\\boxed{x=\dfrac{2}{7}}\qquad\text{add 2, divide by 7}[/tex]

__

Additional comment

The values x=0 and x=1/3 would make the denominator zero, so are excluded from the domain of the equation. By working the problem this way, we ensure that extraneous solutions do not present themselves.

Answer:

horizontal shift 5 units left

Vertical shift 1 unit down

reflection on the x-axis: Reflected

Vertical stretch: stretched

Step-by-step explanation:

Check the picture below.

[tex]\textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2 + b^2} \qquad \begin{cases} c=hypotenuse\\ a=\stackrel{adjacent}{7}\\ b=\stackrel{opposite}{\sqrt{95}}\\ \end{cases} \\\\\\ c=\sqrt{7^2~~ + ~~(\sqrt{95})^2}\implies c=\sqrt{49+95}\implies c=\sqrt{144}\implies c=12 \\\\[-0.35em] ~\dotfill\\\\ sin(C )=\cfrac{\stackrel{opposite}{\sqrt{95}}}{\underset{hypotenuse}{12}}\implies sin(C)\approx \text{\LARGE 0.81}[/tex]