11. A proton is uniformly accelerated from rest to 80.0% of the speed of light in
18 hours, 6 minutes, 45 seconds. What is the acceleration of the proton?

Answer:

The table lists the chemical elements in order of increasing atomic number, which is the number of protons in an atom of an element.

Explanation:

The periodic table is a graphical collection of element data. The table lists the chemical elements in order of increasing atomic number, which is the number of protons in an atom of an element. The rows (periods) and columns (groups) organize elements according to similar properties.

The atomic number, or the number of protons in an element's atom, is used in the table to organize the chemical elements.

The Gaussian Model in subatomic particles, which allows the known elementary particles to be arranged according to their inherent properties, can be compared to the periodic table. The table is significant because it is set up to offer a wealth of knowledge on elements and their interactions in a single reference. Even elements that have yet to be found can have their properties predicted using the table.

All known elements are grouped together in the periodic table of the elements into groupings with related properties. It becomes a crucial tool for chemists, nanotechnologists, as well as other scientists as a result. You can forecast how chemicals will react if we learn to use and comprehend the periodic table.

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1.549×10-19lJ is the energy of a photon emitted when an electron in a hydrogen atom undergoes a transition from =7 to =1.

The equation E= hcE =hc, where h is Planck's constant and c is the speed of light, describes the inverse relationship between a photon's energy (E) and the wavelength of light ().

The Rydberg formula is used to determine the energy change.

Rydberg's original formula used wavelengths, but we may rewrite it using units of energy instead. The result is the following.

aaΔE=R(1n2f−1n2i) aa

were

2.17810-18lJ is the Rydberg constant.

The initial and ultimate energy levels are ni and nf.

As a change of pace from

n=5 to n=3 gives us

ΔE

=2.178×10-18lJ (132−152)

=2.178×10-18lJ (19−125)

=2.178×10-18lJ×25 - 9/25×9

=2.178×10-18lJ×16/225

=1.549×10-19lJ

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In ppm the concentration of NH2- ions is 5.6 ppm.

We have 1 L sample of water contains 0.0056 g of NH2- ions.

We have to determine the concentration of NH2- ions in ppm.

PPM is a term used in chemistry to denote a very, very low concentration of a solution.

According to the question -

Mass of the aqueous solution of NH2- ions → density x volume →

1 L x 1000 mL x 1 g/mL = 1000g

Now, the ratio of chloride ion mass to the solution mass will give the concentration of NH2- ions →

c = 0.0056/1000

Now, in order to express the concentration in parts per million -

c = (0.0056/0.001 x 10⁶) = 5.6/10⁶

Now -

c = 5.6 g of NH2- ions per 1 million grams of solution which is equal to concentration in ppm.

Hence, in ppm the concentration of NH2- ions is 5.6 ppm.

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The maximum speed by which a ball is thrown vertically upward is 34.1255 ft/sec.  as the height in the given data is 18.1 ft.

In physics, vertical launch upward may be characterized as the motion that is illustrated by an object that has been set afloat vertically upwards in which the height and the consequences of the earth's gravitational force set in motion of an object are taken into consideration.

According to the question,

The formula for the vertical launch upward may be as follows:

where v₀ = initial velocity

           g = gravity max = maximum height.

We know that,

g = 32.17 ft/s²

On applying the formula of maximum speed and clearing the initial velocity we get:

y max = v₀²/(2*g)

v₀ = √(y max * (2*g)

v₀ = √( 18.1 ft * (2 * 32.17 ft/s²)

v₀ = √( 18.1 ft * 64.34 ft/s²)

v₀ = √1164.554 ft²/s²v₀ = 34.1255 ft/sec.

Therefore, the maximum speed by which a ball is thrown vertically upward is 34.1255 ft/sec.  as the height in the given data is 18.1 ft.

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Stack temperatures typically range from 350 to 450 degrees Fahrenheit. A 2.5% efficiency loss occurs for every 100 degrees over that temperature. The majority of buildings schedule annual boiler cleanings at regular intervals, but if you see those figures rise, it's time for a cleaning.

Excess air is required to completely burn the fuel since the air and fuel cannot combine exactly in a burner. Additionally, any leaks in the heater will draw air into the firebox that doesn't pass through the burners since the furnace or boiler firebox operates at a little negative gauge pressure. Fuels that are gaseous, like natural gas, burn more readily than fuels that are liquid or solid. Depending on the fuel type, different surplus air requirements will apply.

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(a) The magnitude of →B is 2.43 km,

(b) The angle relative to due south is 56.7o in anti-clockwise direction.

© The magnitude of the →A−→B displacement is |→A−→B|=4.45 km

(d) The angle relative to due south is 326.7o in counterclockwise direction

326.7o

If there is a given vector →A then its opposite vector will be −→A

If the vector →A makes an angle θ above the positive x axis then the vector −→A will make the same angle below the negative x axis.

Given that:  

The first displacement vector is →A=−2.95 ^j km

The second displacement vector is →B=B^i

The magnitude of the resultant displacement is |→A+→B|=4.45 km

Let this resultant makes an angle θ above the positive x axis.

The resultant of the given vectors is,

→A+→B=−2.95 ^j km + B ^i (4.45 cos θ ^i+4.45 sin θ ^j) km

=−2.95 ^j km + B ^i

By comparing both sides, we get

(4.45 sin θ ^j) km

=−2.95 ^j km

⟹θ=−56.7∘

or 90∘−56.7∘= 33.3∘ with south.

and (4.45 cosθ ^i) km

=B ^i(4.45 cos (−33.3∘) ^i) km

=B ^i

B=2.43 km

The magnitude of →B

is 2.43 km

b.) The angle relative to due south is 56.7o in anti-clockwise direction.

The magnitude of the →A−→B

displacement is |→A−→B|=4.45 km

Let this resultant makes an angle αabove the positive x axis.

c.) The difference of the given vectors is,

→A−→B=−2.95 ^j km−B ^i(4.45 cosα ^i+4.45 sinα ^j) km

=−2.95 ^j km−B ^i

By comparing both sides, we get

(1.77 sinα ^j) km

=−1.32 ^j km

α=−56.7o

or 270∘+56.7∘=326.7o

with south.

and (4.45 cosα ^i) km

=−B ^i(4.45 cos(−56.7∘) ^i) km

=−B ^i

B=−2.43 km

The magnitude of →B

Is 2.43km

(d) Hence, the angle relative to due south is 326.7o in counterclockwise direction

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The mass of nitrogen is calculated as 1.092 grams

According to Dalton's Law of partial pressure:

Pn2 = Ptotal Xn2

Were,

Pn2is the partial pressure of nitrogen

Ptotal is the Total pressure

Xn2is the mole fraction of nitrogen

Given:

Total pressure = 1.0 atm

Mole fraction of nitrogen = 0.78

Partial pressure of nitrogen:

Pn2= 1.0 x 0.78 atm

According to Henry's law:

Solubility = Henry's constant (k)×Partial pressure

k = 6.26×10⁻⁴ mol/L-atm

Thus,

Solubility of nitrogen = 6.26×10⁻⁴ mol/L-atm×0.78 atm = 4.8828×10⁻⁴ mol/L

Given: Volume = 80.0 L

So, Moles of nitrogen gas dissolved:

Moles = Solubility (Concentration dissolved) ×Volume

Moles = 4.8828×10⁻⁴ mol/L×80.0 L = 0.0390 moles

Also,

moles = mass (m) / molar mass (M)

mass of nitrogen = moles x molar mass

Molar mass of nitrogen gas = 28 g/mol

So,

Mass of nitrogen gas dissolved = 0.0390 moles×28 g/mol = 1.092 grams

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Work done is 158 joule

Given that, the force of a moving object is,

F = (8i - 6j + 9k) N

The object is moving from point (0,10,8) to the point (6,12,20)

Now we can calculate the displacement by the formula,

dr = (x2-x2)i + (y2 - Y2)j + (z2 - z2)k

Put all the values from the given values.

dr = (6 - 0)x + (12 - 10)j + (20 - 8)k

dr = (6i-2j+12k) meters

Now, the work done can be calculated as,

W = F.dr

W = (8i - 6j + 9k).(6i-2j+12k)

W = 158 J

Hence, work done is 158 joule

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Incidence is referred to as the frequency of new cases of a disorder in a given period of time.

The prevalence of an illness over a specific time period can be calculated using the incidence metric, which measures disease prevalence. In light of this, the incidence of a disease is the quantity of newly discovered cases. An illness' incidence rate is calculated by dividing the number of people at risk for the illness by the number of new cases of the illness. Out of 200 women who participated in the study (and who were free of breast cancer at the start of the study period), five would be diagnosed with breast cancer during the course of a year. In this case, the incidence of breast cancer in this cohort would be 0.025. (Or 2,500 per 100,000 study years among women)

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Answer:

1.28E11 / 8.0E3 = 1.60E7 computers  (16,000,000 computers)

The correct answer for percentage of the compound is left after 3.32 minutes is 55 % .

We use the formula A(t) = A0e-kt for decomposition, where A0 is the initial amount of decomposed substance at t = 0, k is the decay constant, t is the time elapsed, and A(t) is the amount after time t.

The percentage of decomposed compound left after a time t is, [A(t)], divided the the initial amount, [A0], time 100, or A/A0*100:

A = A0e-kt

A/A0 = e^- 0.00586t, [k = 0.00299, divide both sides by A0]

A/Ao = e^(-0.00299*199), [t = 3.32 min*(60 sec/ 1 min) =199 sec]

A/A0 = . 0.551= 55%, (* 100, rounded)

The Arrhenius equation is k = Ae(-Ea/kT), where A is the frequency or pre-exponential factor and e(-Ea/RT) is the fraction of collisions at temperature T that have enough energy to overcome the activation barrier (i.e., have energy greater than or equal to the activation energy Ea).

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Answer:

1.82 seconds

Explanation:

∆ y = 1/2at^2 + Vi*t
a is acceleration, y is height, and Vi is initial velocity
30.6 = 1/2*9.8*t^2 + 7.95 * t
simplify and rearrange
4.9t^2 + 7.95t - 30.6 = 0
solve the quadratic
t = 1.816128... and a negative number, but since this is physics, in this case time can't be negative
Round to 3 significant figures
t = 1.82

Answer: Volts.

Explanation: bc its right

When the position of a block in simple harmonic motion on a spring is zero, acceleration of the block is also zero.

Position of a block performing simple harmonic oscillation is given by

[tex]x(t) = ASin(wt - \phi)[/tex]  where, '[tex]A[/tex]' , '[tex]w[/tex]' and '[tex]\phi[/tex]' are the amplitude, angular velocity and phase difference of the particle performing simple harmonic oscillation. Substituting time [tex]t = \frac{1}{w} + \phi[/tex] in the [tex]x(t) = ASin(wt - \phi)[/tex] we get position of the block to be zero. This implies the position of the block is zero at time [tex]t = \frac{1}{w} + \phi[/tex].

Now, the acceleration is the second derivative of position w.r.t time, thus, [tex]a(t) = -w^{2}ASin(wt - \phi)[/tex] is the acceleration of the block. Now, the acceleration of the block at time [tex]t = \frac{1}{w} + \phi[/tex] becomes zero.

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By using ideal gas approximation, the final pressure is 9.6 atm.

We need to know about ideal gas to solve this problem. The ideal gas will follow the rule

P . V = n . R . T

where P is pressure, V is volume, n is the amount of substance, R is the ideal gas constant (8.31 J/mol.K) and T is temperature.

In the isochoric process where the initial and final volume is the same, the temperature and pressure will follow the rule

P1/T1 = P2/T2

where P1 is initial pressure, P2 is final pressure, T1 is initial temperature and T2 is final temperature. (Temperature in Kelvin)

From the question above, we know that:

P1 = 5.0 atm

T1 = 76°C = 349 K

T2 = 399°C = 672 K

By substituting the parameters, we get

P1/T1 = P2/T2

5.0/349 = P2/672

P2 = 9.6 atm

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Electrical forces can be divided into two categories: attractive electrical forces and repellent electrical forces. Similar charges repel one another whereas opposite charges attract one another.

The electric force attracts the nucleus and electrons to one another. The emptiness that a positive or negative charge leaves behind is known as an electric field because a field is produced there.

Electrical forces can be categorized into two groups: those that attract and those that repel. While opposite charges attract one another, similar charges repel one another.

Electrical forces are produced when two charges come into contact with one another. The electric force exerted on a single charge when there are three or more charges present is just the culmination of the results of each charge's interactions with the other charges.

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At 8.3145 k temperature will the reaction proceed 3.503.50 times faster than it did at 359 k.

Enactment energy is the base measure of energy expected to start a response. It is the level of the potential energy obstruction between the potential energy minima of the reactants and items. Actuation energy is indicated by E and normally has units of kilojoules per mole (kJ/mol) or kilocalories per mole (kcal/mol). Regardless of whether the energy of reactants is more prominent than that of its items and the outcome is a general loss of energy, energy actually should be input at first for the response to happen. Nonetheless, in a large number of the cases in which a response is thermodynamically plausible it has likewise demonstrated conceivable to track down an impetus, dynamic and particular enough to understand this response.

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When the capacitor is fully charged, the potential difference across the capacitor is equal to the voltage source.

Capacitor is a device which stores charges. Charges come from the current passing through it.

The charges stored in a capacitor is called capacitance.

Its unit is farad (F)

No current flows in the circuit when a capacitor is fully charged because the potential difference across the capacitor is equal to the voltage source.

Here, the charging current will be zero such that capacitor voltage equal to source voltage.

When the capacitor is fully charged, the potential difference across the capacitor is equal to the voltage source.

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Answer:

30s

Explanation:

Q = charge in C(coulombs)

I = current in A(amps)

t = time in s(seconds)

Q = I × t

t = Q/I

Substitute in the given values.

t = 450C/15A = 30

t = 30s

Hope this helps! ^^

The heater was switched on for 30 seconds to allow 450 C of charge to flow through it.

To find the time the heater was switched on, we can use the equation Q = It,

where Q represents the total charge in coulombs, I is the current in amperes, and t is the time in seconds.

Given that the current (I) is 15 A and the total charge (Q) is 450 C, we can rearrange the equation to solve for time (t):

t = Q / I

Substitute the values:

t = 450 C / 15 A

t = 30 seconds

Therefore, the heater was switched on for 30 seconds to allow 450 C of charge to flow through it.

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a. The risk of injury must be predictable.

b. A "breach of duty" is when a professional fails to uphold a level of care.

c. There must be a standard of care in place, and the practitioner must assume responsibility for the patient.

d. There must be a clear link between the treatment received and the harm.

Malpractice, commonly referred to as professional negligence, is defined as "an incident of carelessness or incompetence on the part of a professional" under tort law.

The following professionals might be the target of malpractice claims:

Medical professionals: If a doctor or other healthcare practitioner does not exercise the level of care and competence that a similarly situated professional in the same medical field would deliver under the circumstances, a medical malpractice claim may be made against them.

Lawyers: Failure to provide services with the amount of competence, care, and diligence that a reasonable lawyer would use in the same situation may be grounds for a legal malpractice claim.

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The final acceleration of the object is 2 m/[tex]s^{2}[/tex].

In this problem,

Applied force(F) = 10 N

The object’s mass (m) is 5 kg.

Having said that,

An object’s force is equal to the product of its mass and the acceleration it experiences as a result of the applied force.

i.e., Mass + Acceleration = Force (a)

F= m×a

Therefore,

A= F÷m

A= (10÷5) m/sec²

A= 2 m/sec²

Consequently, the object’s acceleration,

A=2 m/sec²

Concept of force and acceleration:

This states that the rate of velocity change of an object is directly proportional to the applied force and moves in the direction of the applied force.

It can be expressed mathematically as force (N) = mass (kg) x acceleration (m/s2). Therefore, an object with constant mass will accelerate in direct proportion to the applied force.

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The statement given "A chemical process with an e-factor of 1 creates less waste than an E-factor of 25" is True.

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Air starts exerting more and more pressure on the walls of the syringe

What will happen to air particles when the are being compressed in a syringe?

Although the space has grown, the individual atoms and molecules can now go farther before running into a nearby atom or molecule because they can now bounce off the walls of the syringe instead of directly bouncing into one other.

Additionally, as the syringe is compressed, you are essentially cramming the same molecules into less space, which causes them to traverse shorter distances and collide more frequently.

This has to do with pressure because when molecules strike the syringe's walls, they bounce off, creating a force and response force that keeps the syringe's walls stiff against the environment it's in or the outside atmosphere. Atoms and molecules essentially bounce off the walls inside the syringe just as much as molecules outside the syringe do when the pressure inside and outside is equal. When the volume of the syringe is increased, the air molecules fill it up, which results in fewer impacts with the inner wall and less force holding the interior rigid to the exterior. Conversely, when the volume is decreased, the impacts happen more frequently because the molecules have nowhere else to go and no more space to travel before encountering another molecule or a wall, so the increase in the frequency of the impacts leads to an increase in the force holding the interior rigid to the exterior.

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Nicolaus Copernicus advocated that the Earth and all other planets orbits around the sun in circular paths at uniform speeds.

Nicolaus Copernicus named this model as Copernicus's Heliocentric Model in 1543. Until his theory was published, it was believed that the Earth is the center of the solar system and the sun moves around it.

The mistake in his theory is that the orbits are circle in shape whereas the correct shape is elliptical which was later corrected by Kepler's model in 1609 which was later proved by Galileo Galilei with the help of telescope.

Therefore, Nicolaus Copernicus advocated that the Earth and all other planets orbits around the sun in circular paths at uniform speeds.

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The initial velocity of particle is 7.568 m/s

Given:

Acceleration = a = 6.14 m/s2

Time = t = 0.300 s.

final velocity = v = 9.41 m/s.

To Find:

initial velocity = u

Solution: Velocity is the prime indicator of the position as well as the rapidity of the object.

v = u + at

u = v - at = 9.41 - 6.14*0.3 = 7.568 m/s

Hence, initial velocity of particle is 7.568 m/s

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The force of collision with the ground will change by a factor of 4

The formula for momentum shows an inverse relationship between force and time, in other words, force varies inversely as time. Hence, if the time of collision between the brick and the ground is increased by a factor of four, the force of collision is with the ground changes by a factor of four. In this case, the resulting force reduces by a factor of four. Momentum is defined as the product of the mass of an object with the changes in the velocity of the same object per time.

F=m(v-u)/t

Where F= momentum

v= final velocity

u= initial velocity

t = time taken

The earth diameter is about 3 and 2 thirds times the diameter of the moon. what is the angular diameter of the earth seen by an observer on the moon?

We calculate the angular diameter of the Earth using the equation:

a=arctanD/d

where a is the angular diameter, D is the physical diameter of the Earth, and d is the distance from the Moon to the Earth.

The equatorial radius of the Earth is rE=6378.1km, the diameter is therefore

D=2×rE=12756.2.

   The mean distance to the Moon is d=384399km. This gives a (mean) angular diameter of a=1.90065°.

At Perigee the distance is d=362,600km. This gives an angular diameter of a=2.01482°

At Apogee the distance is d=405,400km. This gives an angular diameter of a=1.80226°

These Moon-Earth distances are as seen from the centre of the Moon. To calculate the diameter from the surface of the Moon, to subtract the position of the observer along the Moon-Earth axis.

If the observer is on the Moon's equator and the Earth is at zero-hour angle, the distance to the Earth needs to be subtracted by rM=1738.14km. Thus, we have;

 The mean distance to the Moon is d=384399−1738=382661km, giving an angular diameter of a=1.90928°.

At Perigee the distance is d=362600−1738=360862km. We have an angular diameter of a=2.02452°

At Apogee the distance is d=405400−1738=403662km. We have an angular diameter of a=1.81001°

The angular diameter of the Earth from the surface of the Moon is, therefore, between a=1.80226° (at apogee and the Earth is near the horizon) and a=2.02452° (at perigee and for an observer at the equator and when the Earth is at maximum altitude on the meridian).

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Answer:

(a) At U = 3, 9 , v = 4, 2, the projection of u onto v is w1=<2,8>

(b)At U = 3, 9 , v = 4, 2,  the vector component of u orthogonal to v is w2 = <4,-1>

Explanation:

A

The projection of u onto v is given by:

w1= projvu = (u⋅v||v||2)v

Given that  u= <6,7> and v=<1,4>, we can find the projection of u onto v as shown below:

w1= projvu = (u⋅v||v||2v=(<6,7>⋅<1,4><1,4>⋅<1,)

=(6⋅1+7⋅41⋅1+4⋅4)<1,4>

=3417<1,4>

=<2,8>

Part B

The vector component of u orthogonal to v is given by:

Using the given vectors and the projection found in part (a), we can find the vector component of u orthogonal to v as shown below:

w2=u−projvu

=<6,7≻<2,8>

=<(6−2),(7−8)>

=<4,−1>

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The resultant pH= 4.95

A weak acid solution and a conjugate base solution can be combined to create a buffer.

Strong acid or strong base addition does not result in a significant pH shift when a weak acid and conjugate base are present in the solution.

A buffer's pH can be determined using the Henderson-Hasselbalch equation:

pH = Pka + log [base] / [acid]

Let 0.05-x represent the amount of acetate in the buffer and x represent the amount of acetic acid in the buffer.

5.2 = 4.75 + log 0.05− x / x

0.05− x = 0.0369 M

HA = 0.0130 M × 800 mL+ 50 mL× 0.1 M = 15.47 mmol

A = 0.0369 M× 800 mL− 50 mL×0.1 M = 24.52 mmol

The new pH is:

pH= 4.75 + log 25.42 / 15.47

pH= 4.95

The resultant pH of the solution= 4.95

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The total distance travelled during the vehicle's journey as found from the speed-time graph is 6.125 m

V = d / t

V = ( u + v ) / 2

V = Average Speed

d = Distance

t = Time

u = Initial velocity

v = Final velocity

During the first 0.5 s, u = 0 and v = 1 m / s.

d = ( 0 + 1 ) * 0.5 / 2

d = 0.25 m

During the next 0.5 s, u and v are equal meaning constant velocity ( V = 1 m / s ).

d = 1 * 0.5

d = 0.5 m

During the next 1 s, u = 1 m / s and v = 1.5 m / s.

d = ( 1 + 1.5 ) * 1 / 2

d = 1.25 m

During the next 2.5 s, u and v are equal meaning constant velocity ( V = 1.5 m / s ).

d = 1.5 * 2.5

d = 3.75 m

During the next 0.5 s, u = 1.5 m / s and v = 0.

d = ( 1.5 + 0 ) * 0.5 / 2

d = 0.375 m

Total distance travelled is the sum of all the individual distances calculated.

Total distance travelled = 0.25 + 0.5 + 1.25 + 3.75 + 0.375

Total distance travelled = 6.125 m

Therefore, the total distance travelled during the vehicle's journey as found from the speed-time graph is 6.125 m

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