Arianys wants to ride her bicyle 55.5 miles this week. she has already ridden 19 miles. if she rides 5 more days, which equation could be used to determine, m, the average number of miles she would have to ride to meet her goal?
​

Answer:

-3=-18

-1=-8

0=-3

1=2

4=17

Step-by-step explanation:

if g(x)=5x-3 s substitute all x figures and calculate

Answer:

24:40

Step-by-step explanation:

3:5

This means there are 8 divisions altogether - 8 parts to be split (3+5=8)

64 / 8 = 8

8x3 = 24

8x5 = 40

£24:£40

Hope this makes sense!

The weights that are significantly low z₁ = 5.361308 grams and significantly high z₂ = 5.48057 grams  

A Z-score is defined as the fractional representation of data point to the mean using standard deviations.

z -score = (z₁ - μ₀) / σ

where μ₀  is the mean and σ the standard deviation.

Consider a value to be significantly low if its z score is less than or equal to -2 or consider a value to be significantly high if its z score is greater than or equal to 2.

Here μ₀ = 5,37215 and σ = 0.05421

Substitute z -score = -2

⇒ -2  = (z₁ - 5,37215)/0.05421

⇒ (-2)(0.05421) = z₁ - 5.37215

⇒ -0.10842 = z₁ - 5.37215

⇒ z₁ = 5.37215 - 0.010842

⇒ z₁ = 5.361308

And if z = 2

Here μ₀ = 5,37215 and σ = 0.05421

Substitute z -score = 2

⇒ 2(0.05421) = z₂ -  5.37215

⇒ 0.10842 = z₂ - 5.37215

⇒z₂ = 5.37215 + 0.10842

⇒ z₂ = 5.48057  

Therefore, the weights that are significantly low z₁ = 5.361308 grams and significantly high z₂ = 5.48057 grams

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Your question is incomplete, probably the complete question is:

A data set lists the weights​ (grams) of a type of coin. Those weights have a mean of 5.37215 g and a standard deviation of .05421 g. Identify the weights that are significantly low or significantly high.

Consider a value to be significantly low if its z score is less than or equal to -2 or consider a value to be significantly high if its z score is greater than or equal to 2.

Answer:

(i)  2² · 3 · 7

(ii)  3024

(iii) k = 16

(iv) 12 cm

Step-by-step explanation:

The first few prime numbers are:  2, 3, 5, 7, 11, 13, 17, ...

To find which prime numbers multiply together to make 84, start by dividing 84 by the first prime number, 2:

⇒ 84 ÷ 2 = 42

As 42 is not a prime number, we need to divide again:

⇒ 42 ÷ 2 = 21

As 21 is not a prime number, we need to divide again.  

21 is not divisible by 2, so let's try dividing by the next prime number, 3:

⇒ 21 ÷ 3 = 7

As 7 is a prime number, we can stop.

Therefore, 84 is the product of:

⇒ 84 = 2 · 2 · 3 · 7

As 2 appears two times, we can write this using exponents:

⇒ 84 = 2² · 3 · 7

Lowest Common Multiple (LCM):  The lowest multiple shared by two or more numbers.

Prime Factors Method of finding LCM

Step 1

Find the prime factorization of each number.

From part (i):            84 = 2² · 3 · 7

Given in part (ii):    432 = 2⁴ · 3³

Step 2

Write each number as a product of primes, matching primes vertically where possible:

[tex]\begin{array}{ r c c c c c c c ccccccccc}84&=& 2 & \cdot & 2 & \cdot & & & & & 3& \cdot & & & && 7\\\\432 &=& 2 & \cdot & 2 &\cdot & 2& \cdot & 2& \cdot & 3& \cdot & 3& \cdot & 3\\\\\cline{1-17} \\\sf LCM & = & 2 & \cdot & 2 &\cdot & 2& \cdot & 2& \cdot & 3& \cdot & 3& \cdot & 3 &\cdot & 7\end{array}[/tex]

Step 3

Bring down the primes in each column then multiply the factors to get the LCM:

⇒ LCM = 2 · 2 · 2 · 2 · 3 · 3 · 3 · 7

⇒ LCM = 2⁴ · 3³ · 7

⇒ LCM = 3024

From part (ii) we know that the prime factorization of 432 is:

432 = 2⁴ · 3³

A perfect cube is a number multiplied by itself three times.

One of the factors of 432 is a perfect cube → 3³.

Therefore,

[tex]\begin{aligned}432 & = 2^4 \cdot 3^3\\\\\implies \dfrac{432}{2^4} & = 3^3\\\\\dfrac{432}{16} & = 3^3\end{aligned}[/tex]

So we need to divide 432 by 2⁴ to get the perfect cube 3³.

Therefore,

⇒ k = 2⁴

⇒ k = 2 · 2 · 2 · 2

⇒ k = 16

To find the largest possible length of the side of the square, we need to find the greatest common factor of 432 and 84.

Prime Factors Method of finding GCF

Step 1

Find the prime factorization of each number.

From part (i):            84 = 2² · 3 · 7

Given in part (ii):    432 = 2⁴ · 3³

Step 2

Write each number as a product of primes, matching primes vertically where possible:

[tex]\begin{array}{ r c c c c c c c ccccccccc}84&=& 2 & \cdot & 2 & \cdot & & & & & 3& \cdot & & & && 7\\\\432 &=& 2 & \cdot & 2 &\cdot & 2& \cdot & 2& \cdot & 3& \cdot & 3& \cdot & 3\\\\\cline{1-17} \\\sf GCF & = & 2 & \cdot & 2 & \cdot & & & & & 3& & & & && \end{array}[/tex]

Step 3

Bring down the primes in the columns where both numbers have the factor, then multiply the factors to get the GCF:

⇒ GCF = 2 · 2 · 3

⇒ GCF = 12

Therefore, the largest possible length of the side of the square is 12 cm.

Answer:ACF

Step-by-step explanation:

Answer:

Starting paragraphs:

My name is _______. I was born on a cloudy night on the ___ of _______, _____ in ___________ . My parents were very happy as they had been blessed with a baby boy/girl, and that girl/boy is me!

1 year passed by and my 1st birthday was celebrated with much joy and it turned out to be a super extravagant event.

I do not remember much of my early childhood but my parents said that I was a very active, curious and a communicative child. I would ask dozen of questions each minute, without waiting for the answers. I suppose that's why my parents offered me books as early as my third birthday.

Ending paragraph:

I am thankful for my parents, teachers and friends for making me the person who I am today.

Explanation:

Compose your autobiography with the help of the following points:

Answer:

is that the equation ? is that all they gave you

im going to answer but do you mean

(x +2y+3)

Step-by-step explanation:

The assumption that the population variances are not equal and that the two populations are normally distributed is −35.713332; 0.313332.

To assume that the population variances are not equal and that the two populations are normally distributed:

Given:

So, df = n1 + n2 - 2; 11 + 18 - 2 = 27.

T critical = T0.01, 27 = 2.473

Let,

Then,

Now,

Therefore, the assumption that the population variances are not equal and that the two populations are normally distributed is −35.713332; 0.313332.

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Answer:

x = - 4 , x = 0

Step-by-step explanation:

7x³ + 28x² = 0 ← factor out 7x² from each term on the left side

7x²(x + 4) = 0

equate each factor to zero and solve for x

7x² = 0 ⇒ x² = 0 ⇒ x = 0

x + 4 = 0 ⇒ x = - 4

Answer:

64

Step-by-step explanation:

[tex]3 \times 4\\= 12\\= 12 + 52\\= 64[/tex]

Answer:

64

Step-by-step explanation:

first 3 x 4 = 12

12+52=64

Answer:

the option Si mark as light green are correct

Answer:

17 because you have to sutract them

Step-by-step explanation:

Answer:

Step-by-step explanation:

the answer is 30

Answer:

If real GDP in a particular year is $80 billion and nominal GDP is $240 billion, the GDP price index for that year is: 300.

Step-by-step explanation:

Answer:

102

Step-by-step explanation:

x = 5th test

(82 + 76 + 90 + 0 + x) /5 = 70

248 + x = 70*5

x = 350 - 248

x = 102

Answer:

3 3/5

Step-by-step explanation:

Suppose that every student in a discrete mathematics class of 25 students is a sophomore, a junior, or a senior: FALSE

As in the description, it is given that a sophomore in high school is equivalent to a tenth-grade or Class-10 student.

So, the above-given statement becomes false as it says that every student is a sophomore but the class has juniors and seniors.

Therefore, the statement "suppose that every student in a discrete mathematics class of 25 students is a sophomore, a junior, or a senior" is FALSE.

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The complete question is given below:

Suppose that every student in a discrete mathematics class of 25 students is a sophomore, a junior, or a senior. Is the following statement true or false:

"The course must have at least five sophomores, or at least 20 juniors, or at least 10 seniors."

The integer solutions of each of the system of inequalities are 0, 1, 2, 3, .....65, 66, 67, 68. There are total 69 integer values that y can take.

In the question, we are given the inequalities:-

y ≥ 0 and 72 - y  ≥ 4

We have to find the integer solutions of each of the system of inequalities.

From 72 - y  ≥ 4, we can write,

72-4 ≥ y

68 ≥ y

Hence, from 68 ≥ y and y ≥ 0, we can write,

68 ≥ y ≥ 0

Hence, y can take 69 integer values from 0 to 68, both included.

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The value of the functions are:

a. g(-4) + f(-2) = 24

b..  f(1) - g(0) = 1

A function can be defined as an expression showing the relationship between two variables.

Given the functions;

g(-4); substitute the value of x as - 4 in g(x)

g(-4) = (-4)² + 1

g(-4) = 16 + 1

g(-4)  = 17

f(-2); substitute the value of x as - 2 in f(x)

f(-2) = 3(-2) - 1

f(-2 = -7

a.  g(-4) + f(-2) = 17 -(-7)

g(-4) + f(-2) = = 24

f(1) = 3(1) - 1

f(1)  = 2

g(0) = (0)² + 1

g(0) = 1

b. f(1) - g(0) = 2 - 1

f(1) - g(0) = 1

Thus, the value of g(-4) + f(-2) and f(1) - g(0)  are 24 and 1 respectively.

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The domain of the function:{x|x<-1 and x>1} or (-∞,-1] ∪[1,∞) and the range of the function {y|y∈R} or (-∞,∞) .

A function's range is the set of all values that the function accepts, and its domain is the set of all values for which the function is defined.

The sets of all the x-coordinates and all the y-coordinates of ordered pairs, respectively, are the domain and range of a relation.

In the given graph we can see that the values of x are all real values greater than 1 and all real values less than 1

Therefore the domain of the function is set-builder notation is given by:

{x|x<-1 and x>1}

The domain of the function in interval notation is given by:

(-∞,-1] ∪[1,∞)

Therefore the range of the function is set-builder notation is given by:

{y|y∈R}

The range of the function in interval notation is given by:

(-∞,∞)

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A bird flies from a nest that is 822 3/10 feet above sea level to the bottom of a canyon that is 56 1/10 feet below it.

The canyon is 737 feet higher than the bird's nest, by a difference of 3 feet.

based on the facts provided, we know that;

The depth below sea level is 52 3/ 5 feet, hence the value would be negative.

The height above sea level is 789 3/ 10, which requires a positive number.

Let's convert the improper fractions from the mixed fractions;

= - 263/ 5 = - 52. 6 feet

789 3/ 10 = 7893/ 10 = 789. 3 ft

the canyon's and the bird's nest's contrasting elevations;

= -52. 6 + 789. 9

Equals 737. 3 feet

Consequently, there is a 737. 3 foot difference in height between the canyon and the bird's nest.

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Three principles of experimental design: Control, Random, Enough.

What is the principle of an experiment?

The guiding principles of experimental designs are randomization, replication, and local control. These recommendations offer a valid test of significance.

What are the three experimental design principles, and can you briefly describe how each one reduces experimental error?

How many experimental design principles are there?

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Answer:

Find the rate of change for each set of ordered pairs. What is

the average rate of change of all three sets?

(1, 15), (2, 12)

(-1,14), (3, 10)

(3,11), (5, 15)

Write your answer to the average rate of change as a fraction,

a/b.

Step-by-step explanation:

The relative frequency are

i) Pilot error = 15.9 percent

ii)   Human Error =3.8 percent

iii)   Weather = 19.3 percent

iv)  Mechanical problem = 42 percent

v)  Sabotage = 19.2 percent

The formula for the relative frequency is = f/n

                             Where, f = the number of times the data occurred in an observation

                                           n = total number of observations.

If we have to convert it into percentage form we will multiply it by 100

Thus we have been given that

       Crashes due to pilot error = 260

       Crashes due to other human error = 62

       Crashes due to weather = 315

      Crashes due to mechanical problem = 682

       Crashes due to sabotage = 313

Total number of errors occurred = 260+62+315+682+313

                                                           = 1632

Hence, the relative frequency are

 i) Pilot error = 260/1632 * 100 = 15.9 percent

 ii) Human Error = 62/1632 * 100 =3.8 percent

iii)  Weather = 315/1632 * 100 = 19.3 percent

iv) Mechanical problem = 686/1632 * 100 = 42 percent

v) Sabotage = 313/1632 * 100 = 19.2 percent

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