The correct toption is (C) 13
The neutral atom of aluminum possess 13 protons.
Aluminum, denoted by the letter Al, is a group 3 element on the periodic chart. Total weight is 27 kilos. Since the number of electrons and protons in a neutral atom are equal, an aluminum atom that is neutral or uncharged has 13 electrons, 13 protons, and 14 neutrons. Keep in mind that the product of protons and electrons determines mass.The solution to this is that a 3+ charge on an aluminum ion means that an aluminum atom has lost three electrons, or 13 electrons - 3 electrons = 10. An aluminum atom will consequently have 10 electrons because it has a +3 charge. The fact that an aluminum atom possesses 13 protons when it is in a neutral state is unaffected by this.Learn more about the quantum mechanics with the help of the given link:
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Calculate the wavelength of a photon (in nm) emitted when an electron transitions from the n = 3 state to the n = 1 state in the hydrogen atom.
The wavelength of a photon (in nm) emitted when an electron transitions from the n = 3 state to the n = 1 state in the hydrogen atom is 103 nm
What is a Wavelength ?A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places (adjacent crests) in the consecutive cycles.
There are two energy levels, n1 and n2.
Beginning with Rydberg's equation, write:
The Rydberg is useful for figuring out the wavelength of light emitted when an electron switches from one energy level of an atom to another, for as from higher to lower or lower to higher. When an electron moves from one orbital to another, the energy will change.
1/λ = R(1/n1^2 - 1/n2^2)
1/λ = 1.097 x 10^7 (1/1^2 - 1/3^2)
1/λ = 1.097 x 10^7(8/9)
1/λ = 9/8.776 x 10^7 = 103 x 10^-9 m = 103 nm
Hence, the wavelength of a photon is 103 nm
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Which period of the mesozoic era had the lowest temperatures & co2 levels, and had large tropical forests that lacked flowering trees (but later formed extensive coal deposits)?
The Mesozoic era's Jurassic epoch featured the lowest CO2 concentrations and temperatures, as well as vast tropical forests devoid of flowering trees.
The correct option is B.
What features did the Jurassic Period have?Dinosaurs thrived for 180 million years during the Jurassic Period, which was their heyday. Huge herbivorous and carnivorous sauropods like the 35-foot-long Allosaurus and the 87-foot-long Diplodocus evolved. Imagine yourself sprinting as quickly as you can, and that's how big these beasts were.
What led to the Jurassic Period's demise?Some have proposed that the Triassic-Jurassic extinction may have been brought on by an asteroid or comet impact, similar to an extraterrestrial object that is thought to have contributed significantly to the Cretaceous-Paleogene extinction about 66 million years ago as shown by the Chicxulub crater in Mexico.
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Which period of the Mesozoic era had the lowest temperatures and CO2 levels, and had large tropical forests that lacked flowering trees (but later formed extensive coal deposits)?
a. Triassic
b. Jurassic
c. cretaceous
Why are there flat spots on
heating curves of substances like
water?
When 5.0 a at 110 v flows in the primary of an ideal transformer, how many amps at 24 v can flow in the secondary?
The current that can flow in the secondary is 23 A
According to Transformation ratio,
[tex]V_{p}[/tex] / [tex]V_{s}[/tex] = [tex]I_{s}[/tex] / [tex]I_{p}[/tex]
where,
[tex]V_{p}[/tex] = Voltage across the primary coil
[tex]V_{s}[/tex] = Voltage across the secondary coil
[tex]I_{s}[/tex] = Current in the primary coil
[tex]I_{p}[/tex] = Current in the secondary coil
Given that,
[tex]V_{p}[/tex] = 110 V
[tex]V_{s}[/tex] = 24 V
[tex]I_{p}[/tex] = 5 A
[tex]V_{p}[/tex] / [tex]V_{s}[/tex] = [tex]I_{s}[/tex] / [tex]I_{p}[/tex]
110 / 24 = [tex]I_{s}[/tex] / 5
[tex]I_{s}[/tex] = 22.9 = 23 A
Transformation ratio is the ratio of secondary voltage to primary voltage.
Therefore, The current that can flow in the secondary is 23 A
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If the lead can be extracted with 92.5fficiency, what mass of ore is required to make a lead sphere with a 7.00 cm radius? the density of lead is 11.4 g/c
If the lead can be extracted with 92.5 efficiency, the mass of ore is required to make a lead sphere with a 7.00 cm radius is 17.707 kg.
To find the mass of ore, the given values are,
The radius of the lead sphere is r = 7.0 cm,
The lead can be extracted with, η = 92.5% = 0.925 efficiency.
What is the Density?Density is the substance's mass per unit of volume.
We know the density of lead as,
⇒ p = 11.4 g/cm³ .
The volume of the lead sphere is,
V = 4/3πr³
= 4/3π(7)³
V = 1436.7 cm³.
Mass of the lead present in the lead sphere is,
m = p . V
= 11.4 × 1436.7
= 16379 g
m = 16.379 kg
From the expression of efficiency, we calculate the mass of the ore,
η = Mass of lead obtained / Mass of the ore to be taken
0.925 = 16.379 kg / Mass of the ore to be taken
Mass of the ore to be taken = 17.707 kg
If the lead can be extracted with 92.5 efficiency, the mass of ore is required to make a lead sphere with a 7.00 cm radius is 17.707 kg.
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A car is traveling at a speed of 33 m/s . (a) what is its speed in kilometers per hour? (b) is it exceeding the 90 km/h speed limit?
According to the statement:
a) speed is equal to 118 km/h in kilometres per hour.
b) yes it is exceeding 90km/h.
What does speed mean?The pace at which an object's position changes in any direction is referred to as speed. Speed is defined as the ratio of something like the distance traversed to the time required to cover that distance. . . Speed is a scalar quantity since it just has a direction and no magnitude..
How are the speeds determined?Speed is determined by dividing the distance by the time. Calculating the units for speed requires knowledge of the units for both time and distance.. The units in this example will be meters per second (m/s), since the distance is measured in meters (m) and the time is measured in seconds (s).
(a)s₂= 118.km/h is its speed in kilometres per hour.
1h = 3600s
1km = 1000m
s₂= (33m/s) *[tex]\left(\frac{60 \times 60}{1000}\right)[/tex]
= 118.8km/h
s₂= 118.km/h
(b) yes it is exceeding 90km/h.
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If the frequency of a wave is
20
H
z
, what is the period of the wave?
6. Predicting If you added salt instead of sugar
to a pitcher of lemonade, how would this
change the properties of the lemonade?
—NEED HELPP NOWW
also wouldn’t the properties stay the same because every substance has the the same properties and table salt and table sugar are examples of pure substance??
The lifespan of lemonade is significantly extended if salt is used in place of sugar. In other words, it lasts a lot longer than it would typically.
Despite having a similar appearance, salt and sugar taste considerably differently. Chemically, they differ greatly as well. Salt is an ionic compound comprised of sodium and chloride. Contrarily, sugar contains covalent bonds and is made up of carbon, oxygen, and hydrogen. Similar to adding a pinch of the traditional sodium chloride to baked goods like pies or cakes, adding salt to lemonade can help enhance the sweet flavors and lessen any bitterness that may be present.
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A tortoise can run with a speed of 16.3 cm/s, and a hare can run 220.2 cm/s. In a race, they both start at the same time, but the hare stops to rest for 1.6 min. The tortoise wins by 108 cm.
What was the length of the race in cm?
The correct answer is 369.2765m
Speed of tortoise = v_t= 16.3cm/s=0.163m/s
Speed of hare= v_h=220.2cm/s=2.202m/s
Rest time of hare is t_r=1.6min
Tortoise wins by distance of x = 108cm=1.08m
Consider that S is the length of a racetrack.
At the conclusion of the race, calculate the tortoise's distance travelled.
S=v_t×t
S=0.163m/s×t ______(1)
Here, t is the race's actual time.
Find out how long the hare spent racing.
t_h=t-t_r
t_h=t-1.6min×(60s/1min)
t_h=(t-2160)s
At the conclusion of the race, determine the hare's distance travelled.
S-x=v_h×t_h
S-1.08m=2.2×(t-2160)s
S=2.2×(t-2160)s+1.08m_____(2)
To determine the race time, substitute equation (1) for equation (2).
0.163m/s×t=S=2.2×(t-2160)s+1.08m
0.163t=2.26t-4752+1.08
4752-1.08=2.26t-0.163t
4750.92=2.097t
4750.92/2.097=t
2265.5=t
To determine the length of the race or the track, substitute the amount of time in equation (1).
S=0.163m/s×t
S=0.163×2265.5
S=369.2765m
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using a(n) researchers can examine the brain's magnetic fields, which help researchers understand how certain tasks influence brain activity based on the speed and strength of the magnetic field.
Magnetoencephalography (MEG) allows researchers to examine the brain's magnetic field. Which helped researchers to understand how certain tasks influence brain activity.
It isn't. Invaluable tool to study the large scale brain activity. And interactions with the body.
MEG was developed in 1960s .
In this technique weak magnetic forces associated with electrical activities of brain are monitored .
It collects activity from neurons visualized as brain waves and it is used with MRI in magnetic source imaging.
Med fields passes through the head without any distortion.
It provides a Spatial and temporal resolution.
Magnetoencephalography (MEG) allows researchers to examine the brain's magnetic field.
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Which persuasive writing strategy involves quoting a consumer, who is satisfied with a specific product or service, in a news release?
In a news release, using a consumer who is happy with a particular good or service as a testimonial might be persuasive.
What do you understand by consumer?Consumers are described as people or organizations who utilize or consume goods and services. Customers might be consumers or exist solely as customers; they are the buyers of products and services inside the economy.
Businesses may select how to promote their goods and services most effectively by comprehending how consumers think, feel, and make decisions. This aids in predicting consumer behavior and helps marketers promote their already-available goods and services.
Consumer behavior is the study of how consumers choose things based on their needs, wants, and desires as well as how they purchase and utilize them.
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6. Read the following statements. If the italicized word is used correctly,
answer "correct." If the italicized word is not used correctly, rewrite the
statement with the correct word.
a. Taylor's weight is 65 kilograms.
b. I went on a diet and my mass decreased.
c.
I went to the Moon and I lost mass, even though I didn't lose any of
my matter.
The following statements have italicized word, and has 2 correct statement and 1 incorrect statement.
a. Taylor's weight is 65 kilograms. : Its correct.
b. I went on a diet and my mass decreased. : Its correct.
c. I went to the Moon and I lost mass, even though I didn't lose any of my matter. : Its incorrect.
What is weight?The weight is a term shows the mass of the object and the gravity working on it. Example is that a person who feel heavy in earth that same person feel very light on moon cause the gravity will work on that object verry small in comparison to earth.
How can we say that the third statement is incorrect?a. Taylor's weight is 65 kilograms. It is a complete sentence. So its a correct statement.
b. I went on a diet and my mass decreased. : Its correct. Its also a complete sentence. So its a correct statement.
But, c. I went to the Moon and I lost mass, even though I didn't lose any of my matter. This sentence is incorrect because the mass of the person remains same in the moon but the gravity become lesser in the moon so he felt lighter.
So, according to the theory the statement is incorrect.
The correct statement would be:
c. I went to the Moon and I lost weight, even though I didn't lose any of my matter.
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How far does an object go after the pushing force is removed till it stops. the object's speed is 1.70 m/s when the pushing force is removed. friction is 52.0 n and mass of object is 80.0kg
By using uniform motion, the object will travel 2.22 meters until it stops.
We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule
vt = vo + a . t
vt² = vo² + 2a . s
s = vo . t + 1/2 . a . t²
where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.
From the question above, we know that
vo = 1.70 m/s
F = -52 N
m = 80 kg
vt = 0 m/s
Find the deceleration
F = m . a
-52 = 80 . a
a = -0.65 m/s²
Find the distance using the second equation
vt² = vo² + 2a . s
0² = 1.7² + 2(-0.65) . s
1.3s = 2.89
s = 2.22 meters
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A proton, which is the nucleus of a hydrogen atom, can be modeled as a sphere with a diameter of 2.4fm and a mass of 1.67x10-27kg. determine the density of the proton.
The density of a proton is 2.87 x 10^19 kg/m^3.
The density of a proton can be calculated by dividing its mass by its volume i.e.,
Density = Mass/Volume
The mass of a proton is given to be 1.67 x 10^-27 kg.
As the proton is assumed to be a sphere, its volume will be 4/3 π r^3.
Thus, density = 1.67 x 10^-27/ (4/3 x π x r^3)
Putting radius of proton(r) = 2.4 fm = 2.4 x 10^-15 m
The density comes out to be 2.87 x 10^19 kg/m^3.
Thus, the density of a proton is 2.87 x 10^19 kg/m^3.
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Which ball takes a greater force to stop: a slow-moving ball or a fast-moving ball of the same mass? explain your reasoning in terms of newton's second law.
The fast-moving ball will require a greater force to stop than the slow-moving ball of the same mass because the fast-moving ball has more acceleration than the slow-moving ball.
Newton's second law of motion states that "the magnitude of the force acting on an object is equal to the mass of that object and and the acceleration with which it moves.
In other words, the rate of acceleration with which a body moves is directly proportional to the force needed to stop it, and inversely proportional to the mass of the body. Thus, the faster an object moves, the greater the force that will be required to stop it.
That is why the fast-moving ball in the question needed a greater force to stop it than the slow-moving ball, even though they are of the same mass.
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At what temperature will 1.30 mole of an ideal gas in a 1.30 l container exert a pressure of 1.05 atm?
The temperature of the ideal gas is 12.76 K.
We need to know about the ideal gas theory to solve this problem. The ideal gas is assumed that there is no interaction between particles in a gas. It can be determined by the equation
P . V = n . R . T
where P is pressure, V is volume, n is the number of moles gas, R is the ideal gas constant (8.31 J/mol.K) and T is temperature.
From the question above, we know that
n = 1.3 mol
V = 1.30 l = 1.3 x 10¯³ m³
P = 1.05 atm = 1.05 x 1.01 x 10⁵ Pa = 106050 Pa
By substituting the following parameters, we can calculate the temperature
P . V = n . R . T
106050 . 1.3 x 10¯³ = 1.3 . 8.31 . T
T = 137.865 / 10.803
T = 12.76 K
Hence, the temperature of the gas is 12.76 K.
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After you perform gel electrophoresis on your pcr product, you see that one sample has a 200 bp band and the other does not. what can you conclude from these results?
After performing gel electrophoresis on the pcr product, you see that one sample has a 200 bp band and the other does not this shows that 200 bp band is significantly larger than the size of primer dimers unless the primers are 100 bp long, they are not visible.
Gel electrophoresis is the process used to evaluate the success of the PCR reaction.A closer examination of the suitability of agarose gel electrophoresis is done for assessing PCR product yield.
PCR is a series of chemical reactions that take place outside a living cell
Use of 2% agarose gel and 100bp marker and spreading the marker strips properly with 80-90V is done to avoid heating.
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Part A: Resolve t = 8 (interpolate)
The displacement and velocity values at time, t = 8 seconds are; 11.76 and -0.545 respectively
How can interpolating be used to find variable values at a given time?Part A
The possible values in the table are;
Displacement;
t = 7 seconds, y = 10.02
t = 8 seconds, y = 11.01
t = 9 seconds, y = 13.5
Velocity;
t = 7 seconds, y = 0.06
t = 8 seconds, y = -0.05
t = 9 seconds, y = -1.15
The equation for interpretation which is a form of linear equation is presented as follows;
[tex]y - y_0 = \frac{y_1 - y_0}{x_1 -x_0} \times (x - x_0)[/tex]
Interpolating for the displacement at t = 8.0 seconds is as follows;
[tex]y - 10.02 = \frac{13.5 - 10.02}{9 - 7} \times (8 - 7)[/tex]
Which gives the displacement at t = 8.0 seconds as 11.76
Interpolating for the velocity at t = 8.0 seconds is as follows;
[tex]y - 0.06 = \frac{(-1.15) - 0.06}{9 - 7} \times (8 - 7)[/tex]
Which gives the velocity at t = 8.0 seconds as -0.545
The values for the displacement and velocity obtained by interpolation (11.76 and -0.545) are different from the displacement and velocity values in the table at t = 8 which are; 11.01 and -0.05 respectively
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What is the net force on a crate sliding at an unchanging speed when pushed with a steady force of 75 n?
The net force on a crate sliding at an unchanging speed when pushed with a steady force of 75 n is zero.
The total of all forces exerted on an object is known as the net force. A mass can accelerate due to net force. A body is subject to another force whether it is at rest or in motion. When there are a lot of forces acting on a system, the term "net force" is employed.
The total force acting on an object is its net force. Newton's second law, which states that F = ma, where F represents the net force, can be used to compute the net force. The object's mass is given by m. Acceleration is a.
The vector sum of all forces acting on an object is known as the net force. As a result of the fact that a force is a vector and that two forces with identical magnitudes and opposing directions cancel each other out, the net force is the sum of all the forces, or put another way, the net force is the sum of all the forces.
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a bag is dropped from a hovering helicopter. the bag has fallen for 1.6 s. what is the bag's velocity?
The bag's velocity when a bag is dropped from a hovering helicopter is 15.68m/s
Its initial velocity is zero. In a free-falling body, the value of the final velocity is obtained through the equation
Vf =u + gt
u = o ( because the bag is dropped, so it falls starting from rest)
Vf = gt
u is initial velocity
Vf is final velocity
t is time
where g is the acceleration due to gravity, 9.8 m/s².
using above values we get
Vf = (9.8 m/s²)(1.6s)
= 15.68m/s
The bag's velocity when a bag is dropped from a hovering helicopter is 15.68m/s
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If you travel 100km west and then 500km west, what is the total displacement
Answer: 600 km west
Explanation:
When looking at total distance/displacement, simply add the two given quantities together. Note- in the future, make sure to pay attention to units and directions of components. For example, if it was 100 km east and then 500 km west, your total would be -100 km west + 500 km west, giving you 400 km west.
Apartment traveling on a straight road at 15.0m/s accelerate uniformly to a speed of 21.0m/s in 12.0 seconds the total distance traveled by the car in this 12.0 seconds time interval is
By using uniform motion, the distance traveled by the car is 216 m.
We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule
vt = vo + a . t
vt² = vo² + 2a . s
s = vo . t + 1/2 . a . t²
where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.
From the question above, we know that
vo = 15 m/s
vt = 21 m/s
t = 12 s
Find the acceleration
vt = vo + a . t
21 = 15 + a . 12
12a = 6
a = 0.5 m/s²
By using the third equation, we can calculate the distance
s = vo . t + 1/2 . a . t²
s = 15 . 12 + 1/2 . 0.5 . 12²
s = 180 + 36
s = 216 m
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Which of the points a(9, 0, 1), b(9, 7, 3), and c(1, 8, 6) is closest to the yz-plane? which point lies in the xz-plane?
The distance of a point to the yz-plane is given by the absolute value of the x coordinate. So, for point A, the distance is equal to,
Dyz = | -4 | = 4 units
Next, for point B, the distance is equal to,
Dyz = | 3 | = 3 units
Lastly, for point C, the distance is equal to,
Dyz = | 2 | = 2 units
Since point C has the smallest distance to the yz -plane, this point is closest to the yz-plane.
Unlike the regular 2-dimensional Cartesian coordinate system, a three-dimensional coordinate system contains three axes. To plot points in this coordinate system, the point's ordered triple must be known, (x,y,z,).Each coordinate on the ordered triple represents a point that lies on one of the axes
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Sound travels faster in air if the air temperature is group of answer choices warm. average. cold.
Sound travels faster in the air if the air temperature is warm
Everything comes down to the chemical composition of air and sound. Sound molecules travel faster through the air particles in warm air. So, at an air temp of 70°F at sea level, the scientific estimation of the sound speed is 767 mph. Sound, on the other hand, travels the fastest in warmer temperatures air. It moves at 740 miles per hour in subzero temperatures.
Although sound travels slower in cooler air temperatures, it can travel further. The waves are refracted from wallets of warm air and returned to the ground as a result. This sound wave then oscillates between cold and warm air and the surface, causing it to travel further.
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At which lettered point or points is the object moving to the left, if the positive x-direction corresponds to its rightward movement?
At F the object moving to the left, if the positive x-direction corresponds to its rightward movement.
Δx = [tex]X _{2}[/tex] - [tex]X_{1}[/tex]
where,
Δx = Change in position
[tex]X _{2}[/tex] = Final position
[tex]X_{1}[/tex] = Initial position
If Δx is positive, the object is moving forwards ( Right ).
If Δx is negative, the object is moving backwards ( Left ).
If the curve is moving from top to bottom Δx will be negative and if the curve is moving from bottom to top Δx will be positive.
So, in this given curve, at the points B, C and D, the curve is moving from bottom to top meaning that the object is moving to the right and at the point F, the curve is moving from top to bottom meaning that the object is moving to the left.
Therefore, At F the object moving to the left, if the positive x-direction corresponds to its rightward movement.
The given question contains no distance - time graph. I considered the attached image as the graph.
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You are given the equation(s) used to solve a problem. write a realistic problem for which this is the correct equation(s) number 72
Complete Question
In Problems 69 through 72 you are given the equation(s) used to solve a problem. For each of these,
(a) Write a realistic problem for which this is the correct equation(s).
The electric field due to a point charge at distance of 1 um is given as 1.5x10^6 N/C
E = (9*10^9 Nm^2/C^2*N*1.6*10^-19 C)/(1*10^-6)^2
E = 1.5x10^6 N/C
Hence, Electric field is 1.5x10^6 N/C
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What would happen to the organisms if the ice was more dense?
Answer:
If solid ice were denser than water, it would sink. In the most extreme conditions, there would be no way to melt the ice in deep lakes and oceans, which would thicken from the bottom to the surface, forming permanently frozen bodies of ice and disrupting Earth's water cycle.
Explanation:
This ice layer insulates the water below it, allowing it to stay liquid, which allows the life within it to survive. If ice sank, the liquid water on top would also freeze and sink, until all the liquid water became frozen. Water is less dense as a solid, than as a liquid, which is why ice floats.
The amount of downward force exerted by an object under the pull of gravity is its?
The correct answer for the amount of downward force exerted by an object under the pull of gravity is its Weight.
Weight is a restraining force. The magnitude of weight is denoted by the symbol w. Galileo was instrumental in demonstrating that, in the absence of air resistance, all objects fall with the same acceleration g. Normal force is defined as the force exerted on an object by a surface. When an object is at rest, its net force is equal to zero; thus, the downward force (weight) must equal the upward force (normal force). Because weight acts downward, it will be negative. It is determined by the object's mass and the acceleration due to gravity, which is 9.8 m/s2 on Earth. The weight formula is F = m 9.8 m/s2, where F is the object's weight in Newtons (N) and m is the mass in kg .
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Flag what horizontally applied force will accelerate a 400 kg crate at 1m/s2 across a factory floor against a friction force half its weight?
A horizontally applied force of 2400 N will accelerate a 400 kg crate at 1 m/s^2.
In the given diagram, the free body diagram (FBD) of a block is shown.
Here the two vertical forces, normal reaction(N) and weight(W) cancel each other while the horizontal forces do not cancel each other and provide acceleration to the block.
According to the given situation,
Applied Force - Frictional Force = ma
Here the frictional force is half the weight of the body 2000 N.
Putting the given values in the above equation,
F - F1 = 400 x 1
F - 2000 = 400
F = 2400 N
Hence, a horizontally applied force of 2400 N will accelerate a 400 kg crate at 1 m/s^2.
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what is nuclear emission?