A worker at the top of a 459-m-tall television transmitting tower accidentally drops a heavy tool. if air resistance is negligible, how fast (in m/s) is the tool going just before it hits the ground?

Answers

Answer 1

A worker at the top of a 459-m-tall television transmitting tower accidentally drops a heavy tool. If air resistance is negligible, how fast (in m/s) is the tool going just before it hits the ground?

The rule of conservation of energy (the heavy tool’s potential energy at a height of 551 meters above the ground becomes its kinetic energy at ground level) allows us to determine the speed of the object when it hits the ground:

Kinetic Energy Equals Potential Energy

PE=KE

Since mgh=1/2mv2, the mass can cancel out.

In the case where g=9.81m/s2, gh=1/2v2

V=√2gh

=√2*9.81m/s2*459

=3 m/s

It’s possible for an object to have both kinetic and potential energy at once. For instance, a falling object that has not yet hit the ground has both kinetic and potential energy because it is traveling downward and has the capacity to go still further.

The mechanical energy of an object is the total of its potential and kinetic energies.

A falling object loses potential energy while gaining kinetic energy. The difference between the increase in kinetic energy and the decrease in potential energy is exact.

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Related Questions

An airplane lands on a runway with a velocity of 150 m/s. how far will it travel until it stops if its rate of deceleration is constant at -3 m/s^2?

Answers

The airplane lands with a velocity of 150 m/s and its rate of deceleration is constant at -3 m/s^2,

[tex]u = 150 m/s[/tex]

[tex]a = -3 m/s^{2}[/tex]

[tex]v = 0[/tex]

According to the Equation of motion , [tex]v^{2} = u^{2} + 2as[/tex]

[tex]s =\frac{ v^{2} - u^{2} }{2a}[/tex]   [tex]= \frac{0^{2} - 150^{2} }{2*(-3)}[/tex]

s = 3750 m

Equations of motion are the mathematical formula that describes the position, velocity, or acceleration of a body relative to a given frame of reference.

The airplane will have to travel 3750 m until it stops if its rate of deceleration is constant at -3 m/s^2.

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A water pump with a power of 3.4 × 102 watts lifts water at the rate of 7.5 × 10-2 meters/second from a water tank. What is the force exerted by the pump on the water?

Answers

The force exerted by the pump is 4533.33 N

Force can be define as, that it is an external agent capable of changing an object's state of rest or motion. In a very simple word i.e. a push or pull upon an object resulting from the object's interaction with another object is also known as force and it is vector quantity . The unit of force F is Newton (N) .

F = ma

Here, F  is force, m is mass and a is acceleration of the object.

We are given that ,

The power of water pump = P = 3.4 × 10² watts

The rate of water to lift up = v = 7.5 ×10⁻²  m/s

Thus, to get the value of force F exerted by the pump to lift water up can be given as,

P = F × V

Where, p is the power , F is the force and V is the velocity of the pump. Since, the above equation can be express as,

F = P/V

F = (3.4 × 10² watts)/ (7.5 × 10⁻² )m/s

F = 4533.33 N

Therefore, the force exerted by the pump to lifted up water would be 4533.33N

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If you use a horizontal force of 30n to slide a 12kg wooden crate across a floor at a constant velocity. what is the coefficient of kinetic friction?

Answers

The coefficient of kinetic friction is 0.255.

The ratio of the friction force to the normal force felt by a body moving on a dry, uneven surface is known as the kinetic friction coefficient (k).

Equation :

Wb = Mg = 12 X 9.8 = 117.6 N. = Normal

force, Fn.

Fx-Ff = Ma.

Since the velocity is constant, the acceleration is zero.

Fx-Ff = MX0 = 0.

Ff = Fx = 30 N.

Ff = uXFn.

u = Ff/Fn = 30/117.6 = 0.255.

The coefficient of kinetic friction is 0.255

Kinetic Friction :

Kinetic friction is a force that exists between moving surfaces. A body moving on the surface feels a force in the reverse direction of its movement. The magnitude of the force is determined by the kinetic friction coefficient of the two materials.

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A person of weight 80 kg jumped off a platform of height 1 m and safely landed on their feet. what is the magnitude of the momentum change during the collision? give answer in si units.

Answers

The momentum change is 125440 kg.m/s.

We need to know about momentum to solve this problem. Momentum can be defined as the degree of difficulty to stop a moving object. It can be determined by

P = m . v

where P is momentum, m is mass and v is velocity.

Momentum also can be defined by kinetic energy

KE = 1/2 . m . v²

KE = P² / 2m

where KE is kinetic energy

From the question above, we know that:

m = 80 kg

h = 1 m

g = 9.8 m/s²

By conservation of energy, the initial kinetic energy is zero because of the person is in static condition. Hence, the initial momentum is

KEo = Po² / 2m

Po = 0 kgm/s

After the jump, the person will have maximum kinetic energy before landing which can be written

KE = PE

P² / 2m = m . g . h

P² = 2m² . 9.8 . 1

P² = 2.80² . 9.8 . 1

P² = 125440 kg.m/s

The momentum change is

ΔP = P - Po

ΔP = 125440 - 0

ΔP = 125440 kgm/s

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4. What is the density of a cube that when placed on a triple beam balance measures to be 64g and has volume of 8cm 3 ?

Answers

This is an exercise on the density of liquids and gases.

The data provided in the exercise are:

Density (d) = ?

Mass (m) = 64g

Volume (v) = 8cm³

To calculate the density of the cube when it is placed on the balance, divide the mass divided by the volume. We apply the following formula:

d = m/v

We substitute our data in the formula and solve:

d = (64 g)/(8 cm³)d = 8 g/cm³

Answer: The density of the cube placed on the three-beam balance is 8 g/cm³.

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write a hypotheses about the use of an objects physical charecteristics to determine its density use the format "if then because" and be sure to answer the lesson question "how can the density of an object be determined?

Answers

i don't know.

Explanation:

because i don't want responde

use the midpoint rule with n = 4 to estimate the work w (in j) done by the force in moving an object from

Answers

The work w (in j) done by the force in moving an object is 222.4 J

We know that,

[tex]M_{n}[/tex] = ∑[tex]_{i = 1}^{n}[/tex] f ([tex]m_{i}[/tex] ) Δ

where,

i = [tex]i^{th}[/tex] rectangle

n = Number of rectangles

f ([tex]m_{i}[/tex] ) = Function of the curve evaluated at the midpoint of the [tex]i^{th}[/tex]   rectangle

[tex]m_{i}[/tex] = Midpoint of [tex]i^{th}[/tex] interval

Δ = Width of each rectangle

Given that,

x     5    9    13     17   21   25  29   33   37

f(x)  5  5.5  6.8  8.8  9.8  8.1  6.7  5.4  4.2

n = 4

Δ = ( 37 - 5 ) / 4

Δ = 8

∫[tex]_{5} ^{37}[/tex] f (x) dx = ∑[tex]_{i = 1}^{4}[/tex] f ([tex]m_{i}[/tex] ) Δ

∑[tex]_{i = 1}^{4}[/tex] f ([tex]m_{i}[/tex] ) Δ = 8 ( 5.5 +8.8 + 8.1 + 5.4 )

∑[tex]_{i = 1}^{4}[/tex] f ([tex]m_{i}[/tex] ) Δ = 222.4

∫[tex]_{5} ^{37}[/tex] f (x) dx = 222.4 J

The midpoint rule, also known as the midpoint Riemann sum is used to estimate integral of a function or area under a curve.

Therefore, the work w (in j) done by the force in moving an object is 222.4 J

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Define what is meant by a "frame of reference" in physics. as we study motion, what will we normally use as our reference frame? give an example of motion being described using this reference frame. under what conditions would we use a different reference frame to describe motion? give two examples of using a different reference frame to describe motion, explaining why this different reference frame is used.

Answers

A frame of reference is just a set of coordinates that are used in the study of physics to calculate things like position and velocity. Axes that specify the three dimensions of space within the frame of reference are often included in such a frame.

What is the example of a motion being defined using this FOR?

A railway platform is an illustration of an inertial frame of reference. The platform doesn't move, hence it satisfies the requirement for not accelerating. The platform's objects move according to the law of inertia.

Under what conditions do we use a different FOR?

An acceleration with respect to an inertial frame characterizes a non-inertial reference frame. In general, an accelerometer at rest in a non-inertial frame will pick up a non-zero acceleration. While all inertial frames share the same laws of motion, non-inertial frames have different laws of motion depending on the acceleration. For example, let's imagine you are driving through a stop signal in an automobile. The automobile has stopped moving. The automobile accelerates when the light turns green. The car is not an inertial frame of reference when it is accelerating. You will feel yourself "pushed" into the seat if the acceleration is significant enough.

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The intensity of sunlight at the Earth's distance from the Sun is 1370 W/m². Assume the Earth absorbs all the sunlight incident upon it. (b) Explain how this force compares with the Sun's gravitational attraction

Answers

Comparing these two values, Fgav is much greater than Fr.

First, calculate the force produced by the radiation pressure:

The radiation pressure produces a force equal to,

Fr=pr(πRe2)

=(I/c) ( πRe2)

Given that

I= Intensity of sun = 1370 W/m²

c = speed of light = 2.998×108m/s

Re = Radius of the earth=  6.37×106m

Ms= mass of sun = 2.0×1030kg

Me= mass of earth = 5.98×1024kg

des2 = distance of earth and sun apart =1.5×1011m

Substituting the given values according to the question

Fr= π (1.37 × 103 kW/m2) (6.37×106m)2/2.998×108m/s

=6.0×108N

(b) The gravitational pull of the Sun on the Earth is,

Fgav= GMsMe/ des2

putting values according to question

Fgav= (6.67×10−11 N⋅m2/kg2) (2.0×1030kg) (5.98×1024kg) / (1.5×1011m)2

=3.6×1022N.

Comparing these two values, it is obvious that Fgav is much greater than Fr.

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The fuel for a jet engine has a density of 1.32 slug/ft3. if the total volume of fuel tank a is 50 ft3, determine the weight of the fuel when the tanks are completely full?

Answers

The weight of the fuel when the tank is filled is 2.13 kip.

The density of the fuel of the jet engine= 1.32 slug/ft³

The total volume of the fuel that can be filled in the fuel tank of a jet engine = 50 ft³

The specific weight of the fuel when the tank is filled is,

[tex] \gamma = p \times g[/tex]

[tex] \gamma = 1.32 \times 32.2[/tex]

[tex] \gamma = 42.504 \: ib/ft ^{3} [/tex]

The specific weight of the fuel when the tank is filled is 42.504 ib/ft ³.

The weight of the fuel when the tank is filled is,

[tex]w = \gamma \times ∀[/tex]

[tex]w = 42.5.4 \times 50[/tex]

[tex]w = 2.13 \: kip[/tex]

The weight of the fuel is 2.13 kip.

Therefore, the weight of the fuel when the tank is filled is 2.13 kip.

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1. How many milligrams are in 25 grams?

Answers

Answer: 25000 milligrams are in 25 grams

Explanation:

Answer:

25,000

Explanation:

Since 1 gram is 1,000 milligrams, multiply 25 x 1,000 to get the answer.

For a relative frequency distribution, relative frequency is computed is computed as ____________.

Answers

Answer:

For a relative frequency distribution, relative frequency is computed as the class frequency divided by the number of observations.

i need help please thanks

Answers

The burning of fossil fuels is a threat to the environment.

What is pollution?

The term pollution has to do with the introduction of harmful material and energy into the environment. We know that the burning of fossil fuels is one of the chief sources of pollution in the environment. This is can be seen from the images attached.

The burning of fossil fuels introduces carbon dioxide into the environment which in turn causes the temperature of the earth to rise. This is the situation that we call global warming.

The greatest concern of the earth is to ensure that the carbon burden is reduced and that the emission of the carbon to the atmosphere is mitigated in order to reduce the impact of this carbon on the earth.

Thus, the burning of fossil fuels is a threat to the environment.

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What is the electric flux passing through a gaussian surface that surrounds a 0.075 c point charge?

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An 0.075 c point charge's surrounding gaussian surface's electric flux  is 8.5 ×10⁹Nm²/C.

Which is a gaussian surface?

In three dimensions, the Gaussian surface is referred to as a closed surface where the flux of a vector field may be determined. The gravitational field, the electric field, or the magnetic field are all examples of these vector fields.

Why is a Gaussian surface drawn?

We build a fictitious Gaussian surface around the supplied surface when the surface of which an electric field or flux must be established is asymmetrical or the surface area is challenging to obtain, such as the surface area for an infinitely long wire or plane. The Gaussian surface is said to utilize symmetry the best.

When a charge q is surrounded by a gaussian surface, the electric flux that passes through it is

[tex]\phi=q / \epsilon 0[/tex]= 0.075 / ( 8.85 ×10⁻¹²)

= 8.5 ×10⁹Nm²/C.

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When a new path of lesser resistance is made for an existing circuit a(n) _____________ circuit occurs.

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When a new path of lesser resistance is made for an existing circuit a(n) short circuit occurs.

What is short circuit?

An electrical circuit short circuit is when two nodes that are supposed to be connected at different voltages make an improper connection. This leads to an electric current that can damage circuits, cause overheating, fire, or explosions, and is only constrained by the network's remaining nodes' equivalent Thevenin resistance. While short circuits are typically the result of a failure, they can occasionally be brought on purpose, such as when voltage-sensing crowbar circuit protectors are being installed.

An electrical connection that requires two nodes to have the same voltage is known as a short circuit in circuit analysis. Since there is no resistance and hence no voltage drop across the link in a "perfect" short circuit, there is no short circuit.

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Scalar is a _____ having _______ (amount)

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Scalar is a physical quantity  having only magnitude. (amount)

scalar quantity : The physical quantity which are specified with the magnitude are known as scalar quantities.

For example :

length - 5m

speed - 10 m/s , 10km/h etc

Mass - 6kg , 20g etc

energy - 30 joule

density - 56kg/m³

It has no direction. It has only magnitude. Described by real numbers.

There is another quantity known as vector quantity.

vector quantity : The physical quantity which are specified by its magnitude and direction also.

For example, velocity, acceleration, force etc.

Scalar is a physical quantity  having only magnitude. (amount)

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A ball accelerates uniformly at −2.00 m/s2.

If the ball was initially moving at 0.20 m/s and the ball travels for 7.00 s, then what was its final velocity?

−1.8 m/s
negative 1.8 meters per second
−13.8 m/s
negative 13.8 meters per second
−14.2 m/s
negative 14.2 meters per second
+13.8 m/s

Answers

The final velocity of the ball, given the data is –13.8 m/s

What is acceleration?

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

a is the acceleration v is the final velocity u is the initial velocity t is the time

How to determine the final velocity

The final velocity of the ball can be obtained as follow:

Acceleration (a) = −2 m/s² Initial velocity (u) = 0.2 m/sTime (t) = 7 sFinal velocity (v) = ?

a = (v – u) / t

–2 = (v – 0.2) / 7

Cross multiply

v – 0.2 = –2 × 7

v – 0.2 = –14

Collect like terms

v = –14 + 0.2

v = 13.8 m/s

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Unshielded twisted-pair cable capable with a specification of 100 mhz/100 mbps is also called category ________.

Answers

Unshielded twisted-pair cable capable with a specification of 100 MHz/100 maps is also called category of switch.

What is Unshielded twisted-pair cable?

The unshielded turned pair link is 100-ohm copper link that is constitutive of unshielded curved matches which range somewhere in the range of two to 1,000 and 800. They have no metallic covering on top of the contorted wires. This enjoys the benefit of making the link more modest in distance across. One normal use for protected wound pair links is to involve it in outrageous cold circumstances. Many individuals know that critical exploration is being led in very chilly region of the world. Truth be told, turned pair links have tracked down a great deal of utilizations in the media communications industry prior to getting well known in the PC organizing industry.

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The average temperature of ocean surface water is 289 k. oceans behave as black bodies. show that the intensity radiated by the oceans is:_____

Answers

The radius is equal to the Earth’s radius. You can find this information online by computing the Earth’s surface area while assuming that it is a perfect sphere, then multiplying the result by the percentage of the planet that is covered in water.

Actually, you can demonstrate this without knowing the radius.

P/A = e•s•T4

Water has an emissivity, e, of roughly 0.96. And 5.67108 W/m2 K4 is the Stefan-Boltzmann constant.

Stephen Boltzmann law

The power radiated from a black body is described by the Stefan-Boltzmann law in terms of its temperature. The Stefan-Boltzmann constant, often known as the proportionality constant, is derived from several well-known physical constants.

Where k is the Boltzmann constant, h is the Planck’s constant, and c is the speed of light in a vacuum, the constant has the value since 2019

When compared to a black body, a body that does not completely absorb incident radiation (sometimes referred to as a grey body) emits less total energy.

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Consider the following line of code: int[] somearray = new int[30]; which one of the following options is a valid line of code for displaying the twenty-eighth element of somearray?

Answers

Valid line of code for displaying the twenty-eighth element of some array is System.out.println(somearray[27]).

What is an array?

Arrays are among the most well-known and essential data structures, and they are utilized by practically all programs. A wide variety of additional data structures, including lists and strings, are likewise implemented using them. They successfully take advantage of computers' addressing systems. The memory is a one-dimensional array of words whose indices are their addresses in the majority of contemporary computers and many external storage devices. Array operations are frequently optimized for by processors, especially vector processors.

The main reason why arrays are helpful is that the element indices may be calculated in real time. This feature, among other things, enables a single iterative statement to process an array's items in any number.

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The layers in a high-mass star occur in order of:________
a. atomic abundance.
b. fusion temperature.
c. atomic number.
d. spin state.

Answers

A high-mass star has layers that are arranged in order of b. Temperature for fusion.

What is the temperature of fusion?

The temperature at which a substance transforms from a solid to a liquid is known as its melting point. The solid and liquid phases are in equilibrium at the melting point. Pressure affects a substance's melting point, which is typically reported at a standard pressure such 1 atmosphere or 100 kPa. There are two main categories of fusion reactions: those that maintain the ratio of protons to neutrons and those that convert protons to neutrons. The solid-liquid and liquid-to-gas transitions are connected with the typical heats of fusion and vaporization, respectively, for each substance.

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What would be the average fixed cost per unit at an activity level of 5,200 units? assume that this level of activity is within the relevant range.

Answers

The average fixed cost per unit at an activity level of 5,200 units is $6.00.

What is the average fixed cost?

The average fixed cost (AFC) is fixed cost that does not change with the change in the number of goods and services produced by a company. To put it in a nutshell, average fixed cost (AFC) is the fixed cost per unit and is calculated by dividing the total fixed cost by output level.

Since no cost is fixed for a long time, average fixed cost is only for a short run. When units of production increase, the average fixed cost per unit decreases. Similarly, when the business produces less units, average cost increases per unit.

However, only one unit, mostly capital, is fixed. Examples of average fixed cost are the salaries of permanent employees, mortgage payment on machinery and plant, rent, more.

Average Fixed Cost Formula:

AFC = Total fixed cost/Output (Q)

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PLS HELP ILL GIVE BRAINLIEST
AND IF YOURE ABLE TO PLS PROVIDE THE EXPLANATION TYSMMMM

In frustration, a junior drops the APUSH textbook 1.5 m. How long will it take to hit the ground?

Answers

The time taken for the APUSH textbook to hit the ground is determined as 0.55 seconds.

What is time of motion?

The time of motion of an object is the time taken for the object to travel from its initial point to the final point.

The time taken for the APUSH textbook to hit the ground is calculated as follows;

t = √(2h/g)

where;

h is the height of fall of the textbookg is acceleration due to gravity

t = √(2 x 1.5/9.8)

t = 0.55 seconds

Thus, the time taken for the APUSH textbook to hit the ground is determined as 0.55 seconds.

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3. A cube measures 3 mm x 3 mm x 3 mm. What is the volume of the
cube?

Answers

The correct answer 27 mm^3 is the volume of the cube measureing 3 mm x 3 mm x 3 mm.

The cube's volume is 3 in x 3 in x 3 in = 27 mm ^3

The volume of a cube is calculated by multiplying its side by three. Thus, the volume of a cube can be expressed as Volume of cube = s ^3, where s is the cube's side length. A cube's volume is the space enclosed by its six faces. In contrast to 2d shapes, it has additional dimensions in addition to length and width, which are known as height and thickness. As a result, the volume of a cube equals the product of its length, width, and height.

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If the mass of an object is 14 lbm, what is its weight, in lbf, at a location where g = 32.0 ft/s2?

Answers

The mass of the object is 13.924 lbf.

Calculation

Using the formula:

w = m x g ....... eq1

here w is weight of the object.

m is mass of the object, and

g is the acceleration of gravity.

mass, m = 14 lbm (given)

acceleration of gravity, g= 32.0 ft/[tex]s^{2}[/tex]

Now, substituting the values in equation (1):

w = 14lbm x 32.0 ft/[tex]s^{2}[/tex] = 448 lbm ft/[tex]s^{2}[/tex]

since, 1 lbf = 32.174 lbm ft/[tex]s^{2}[/tex]

so, w = 448 x [tex]\frac{1}{32.174}[/tex]

w = 13.924lbf

Hence, the mass of an object is 13.924 lbf.

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The area of an equilaterla triangle is increasing at a rate of 5 m^2/hr. find the rate at witch the height is chganging when the areai is:_________

Answers

The rate at which the height is changing is ( 5 / x ) m / hr

We know that,

Area of an equilateral triangle A = [tex]\sqrt{3}[/tex] [tex]x^{2}[/tex] / 4

h = [tex]\sqrt{3}[/tex] x / 2

Where,

x = Side

h = Height

Given that,

dA / dt = 5 [tex]m^{2}[/tex] / hr

h = [tex]\sqrt{3}[/tex] x / 2

Differentiate both sides with respect to t

dh / dt = ( [tex]\sqrt{3}[/tex]  / 2 ) ( dx / dt )

dx / dt = ( 2 /  [tex]\sqrt{3}[/tex] ) ( dh / dt )

A = [tex]\sqrt{3}[/tex] [tex]x^{2}[/tex] / 4

Differentiate both sides with respect to t

dA / dt = ( [tex]\sqrt{3}[/tex] / 4 ) ( 2x ) ( dx / dt )

5 =  ( [tex]\sqrt{3}[/tex] / 4 ) ( 2x ) ( 2 /  [tex]\sqrt{3}[/tex] ) ( dh / dt )

dh / dt = ( 5 / x ) m / hr

Rate of change of height is defined as the rate at which height of an object changes with respect to time. It is represented as dh / dt

Therefore, the rate at which the height is changing is ( 5 / x ) m / hr

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who drink water with no mouth?

Answers

Answer: Tree

Explanation: Cause they don't have mouth to drink water they just have root

Typically people who are injured will be given their food and drinks straight to their throat by a tube

With light microscopy, if the objective lens (lens closest to the specimen) magnifies 40-fold, and the eyepiece lens magnifies 10-fold, the final magnification will be:_________

Answers

The final magnification will be 400-fold or 400 times the original size of the object.

For magnifying smaller objects, a compound microscope is used.

A compound microscope consists of an objective and an eyepiece, whose diagram is shown in the adjoining image.

The lens  near  the object is called an objective and the other one is the eyepiece.

Let the magnification of the objective be m1

Let the magnification of the eyepiece be m2

The final magnification by the microscope, M, will be

M = m1 x m2

Putting the values in the above equation

M = 40 x 10

M= 400

Thus, the final magnification will be 400-fold or 400 times the original size of the object.

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What is the velocity of the air relative to a person standing on the ground, va/p? what is the velocity of the eagle relative to the air, ve/a?

Answers

The velocity of the eagle relative to the air = 42.0 miles/hour

Calculation

Vwp = Velocity of wind wrt person = 27 miles/hour

Vew = velocity of eagle wrt wind = 15 miles/hour

Vep = velocity of eagle wrt person

= Vew + Vwp

= 27 + 15 = 42 miles/hour

Then,

Vap = velocity of air relative to the person = Vwp = 27

Vap = Vwp = 27 miles/hour

Vea = Velocity of eagle relative to air

= Vea = 15 miles/hour

Vep = Vea + Vap

= 15 + 27 = 42 miles/hour

What does “relative motion” mean?

Any kind of motion that is perceived from or related to a material system that serves as a frame of reference (such as two neighboring walls and the floor of a room) is called as relative motion.

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How many water molecules are present in 222.22 ml sample of water ( molar mass =18.01 g/mol)

Answers

7.4304*10²⁴ molecules water molecules are present in 222.22 ml sample of water ( molar mass =18.01 g/mol).

Mass of water = density * volume

=1.00gm/mμ*222.22mol

=222.22gn

No of moles of water = mass/molar mass

no of water molecules/Avogadro  no.=12.34 mol

no of water molecules= 12.34 mol * 6.022*10²³ mol

=74.304*10²³ molecules

=7.4304*10²⁴ molecules

so, 7.4304*10²⁴ molecules are present in 222.22 ml of water sample

7.4304*10²⁴ molecules.

Describe a molecule:

One or more atoms make up molecules. They may have the same atoms (for example, an oxygen molecule has two oxygen atoms) or different atoms if they have more than one (a water molecule has two hydrogen atoms and one oxygen atom). Proteins and DNA are examples of biological compounds that can contain thousands of atoms.

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