A standard train ticket in a certain city costs 3 per ride. people who use the train also have the option of purchasing a frequent-rider pass for 18.75 each month. with the pass, a ticket costs only 2.25 per ride. how many train rides in a month make the frequent-rider pass a better deal than standard train tickets?



a. 26 or more rides

b. 24 or more rides

c. 25 or more rides

d. 27 or more rides

Answer:

37.5

Step-by-step explanation:

Answer: 37.5

Step-by-step explanation:

12.5% of 300=37.5

Answer:

5x + 3y = 18

Step-by-step explanation:

First find slope.  m = (y2 - y1)/(x2 - x1) = (6 -1)/(-6 --3)  = 5/-3

then. use. y - y1 =. m (x - x1).  which gives. y - 1 = -5/3(x - 3)

then. y - 1 = -5/3x + 5

then y = -5/3 x + 6. or. 5x + 3y = 18

Answer:

b=7

Step-by-step explanation:

3-5b=-32

-5b=-32-3

-5b=-35

Divide both sides by -5

b=7

( I also had trouble with these kind of expressions)

Answer:

240 miles

Step-by-step explanation:

Because it took 5 hours going 48 miles per hour, therefore 5 x 48 =240

Answer:

First term = 53,

Step-by-step explanation:

a10 = a1 + (10 - 1)d so:

98 = a1 + 9*5

a1 = 98 - 45

    = 53,

Answer:

n = 3p

Step-by-step explanation:

12n + 7p - 6n = 25p

12n - 6n +7p = 25p

12n - 6n = 25p - 7p

6n = 18p

[tex]n=\frac{18p}{6}[/tex]

n = 3p

(a) Differentiate [tex]s(t)[/tex] to get the velocity.

[tex]s(t) = \cos(t^2 - 1)[/tex]

Use the chain rule.

[tex]u = t^2 - 1 \implies \dfrac{du}{dt} = 2t[/tex]

[tex]s(u) = \cos(u) \implies \dfrac{ds}{du} = -\sin(u)[/tex]

[tex]\implies \dfrac{ds}{dt} = \dfrac{ds}{du} \dfrac{du}{dt} = \boxed{-2t\sin(t^2-1)}[/tex]

(b) Evaluate the derivative from (a) at [tex]t=0[/tex].

[tex]\dfrac{ds}{dt}\bigg|_{t=0} = -2\cdot0\cdot\sin(0^2-1) = \boxed{0}[/tex]

(c) The object is stationary when the derivative is zero. This happens for

[tex]-2t \sin(t^2 - 1) = 0[/tex]

[tex]-2t = 0 \text{ or } \sin(t^2 - 1) = 0[/tex]

[tex]t = 0 \text{ or } t^2 - 1 = n\pi[/tex]

(where [tex]n[/tex] is any integer)

[tex]t = 0 \text{ or } t = \pm\sqrt{n\pi + 1}[/tex]

We omit the first case. In the second case, we must have [tex]n\ge0[/tex] for the square root to be defined. Then in the given interval, we have two solutions when [tex]n=\in\{0,1\}[/tex], so the times are

[tex]t_1 = \sqrt{1} = \boxed{1}[/tex]

[tex]t_2 = \boxed{\sqrt{\pi + 1}} \approx 2.035[/tex]

(d) A picture is worth a thousand words. See the attached plot. If you're looking for a verbal description, you can list as many features of the plot as are relevant, such as

• intercepts (solve [tex]s(t)=0[/tex] to find [tex]t[/tex]-intercepts and evaluate [tex]s(0)[/tex] to find the [tex]s[/tex]-intercept)

• intervals where [tex]s(t)[/tex] is increasing or decreasing (first derivative test)

• intervals where [tex]s(t)[/tex] is concave upward or concave downward (second derivative test; at the same time you can determine any local extrema of [tex]s(t)[/tex], which you can see in the plot agrees with the critical points found in (c))

Answer:

I'm pretty sure the answer is D

Step-by-step explanation:

I took the test

The sentence that contains a dangling modifier is D. Searching frantically, the homework was finally found and turned in.

A word or phrase that modifies a term that is not explicitly expressed in the sentence is known as a dangling modifier. A modifier provides a concept's definition, clarification, or more information.

A grammatical modifier that could be mistakenly understood as being connected to a word other than the one intended is known as a hanging modifier. A hanging modifier, which usually refers to a participle, has no subject.

Therefore, the sentence that contains a dangling modifier is Searching frantically, the homework was finally found and turned in.

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The midpoint of the given line segment with the given endpoints

(-3, 8) and (2, -4) is (-0.5, 2)

The formula for calculating the midpoint of coordinate is expressed as;

M(x, y) = (x₁+x₂/2, y₁+y₋/2 )

Given the coordinate points( -3, 8) and (2, -4)

Substitute

M(x, y) = (-3+2/2, 8-4/2)

M(x, y)= (-1/2, 4/2)

M(x, y) =(-0.5, 2)

Hence the midpoint of the given line segment with the given endpoints

(-3, 8) and (2, -4) is (-0.5, 2)

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Equation have infinity solution

Here the equation is 2q-3q =-q.

After solving this we have

                    -q = -q

As Left-hand side is equal to the right-hand side.

Therefore whatever the value we will put for the q, the left and right hand side remains the same.

Therefore this equation has an infinity solution.

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Answer:

The sum is negative because the number with the greatest value is negative.

Step-by-step explanation:

If the it's the same sign add, if not subtract.

8-3=5

keep the sign of the bigger number.

-5

Hope It Helps

Sorry If I'm Wrong

Answer: Yes

Step-by-step explanation:

The answer is negative. That is because you are adding three to negative 8.

Think about it. 8 is greater than three, right?

-8 + 3 = -5

You are bringing -8 closer to 0:

-8, -7, -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5...

Bring -8 three spaces closer to 0. You get -5.

Hope this helps.

The composite function or combined functions of x(A) and V(x) is V(x(A)) = (√A/6)³ option (C) is correct.

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

A function relates an input to an output.

x2 (squaring) is a function

x3+1 is also a function

Sine, Cosine, and Tangent are functions used in trigonometry.

Although part of the question is missing the question is The function x(A)= √A/6 can be used to determine the side length, x, of a cube given the surface area of the cube, A. The function V(x)= x³ can be used to find the volume of a cube. how can these functions be combined?

a. x(v(A))= sqrt x^3/6

b. V(x(A)) = sqrt x3/6

c. V(x(A))=(sqrt A/6)^3

d. x(v(A))= (sqrt A/6)^3

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Answer:

VU = 120° , WX = 100°

Step-by-step explanation:

(7)

An inscribed angle is half the measure of its intercepted arc , or

the intercepted arc is twice its inscribed angle, then

arc TV = 2 × 30° = 60°

the diameter is TU then arc TU = 180°

the sum of the arcs in the circle = 360° , so

VU + TV + TU = 360°

VU + 60°  + 180° = 360°

VU + 240° = 360° ( subtract 240° from both sides )

VU = 120°

(8)

WY = 2 × 75° = 150°

WX + WY + YX = 360°

WX + 150° + 110° = 360°

WX + 260° = 360° ( subtract 260° from both sides )

WX = 100°

Answer:

====================

Total number of outcomes is 16, count of all outcomes.

Number of outcomes with 3 or more tiles is 5:

The probability is:

Correct choice is D.

What we answering with these 2 points ?

Where's the question?

Answer:

y=-x-3

Step-by-step explanation:

Write in slope-intercept form, the equation is y=mx+b .

y=−x−3

Answer:

x² + (y + 3)² = 25

Step-by-step explanation:

the centre (C) of the circle is at the midpoint of the diameter.

using the midpoint formula

midpoint = ( [tex]\frac{x_{1}+x_{2} }{2}[/tex] , [tex]\frac{y_{1}+y_{2} }{2}[/tex] )

with (x₁, y₁ ) = P (3, 1 ) and (x₂, y₂ ) = Q (- 3, - 7 )

C = ( [tex]\frac{3-3}{2}[/tex] , [tex]\frac{1-7}{2}[/tex] ) = ( [tex]\frac{0}{2}[/tex] , [tex]\frac{-6}{2}[/tex] ) = (0, - 3 )

the radius r is the distance from the centre to either P or Q

using the distance formula

r = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]

with (x₁, y₁ ) = C (0, - 3 ) and (x₂, y₂ ) = P (3, 1 )

r = [tex]\sqrt{(3-0)^2+(1-(-3)^2}[/tex]  

 = [tex]\sqrt{3^2+(1+3)^2}[/tex]

 = [tex]\sqrt{3^2+4^2}[/tex]

 = [tex]\sqrt{9+16}[/tex]

 = [tex]\sqrt{25}[/tex]

 = 5

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r is the radius

here (h, k ) = (0, - 3 ) and r = 5 , then

(x - 0 )² + (y - (- 3) )² = 5² , that is

x² + (y + 3)² = 25

Answer:

3.64

Step-by-step explanation:

collect like terms

divide both sides by x coefficient

Answer:

x=51/14

Step-by-step explanation:

28x-2=100

+2. +2

28x=98

28x/28=102/28

×=51/14

A function assigns the values. The output(y) of the function y=20x + 38 if the input is -9 is -142.

A function assigns the value of each element of one set to the other specific element of another set.

Given the function y=20x+38, therefore, if the input of the function is -9, then the output can be calculated by substituting the value of x as -9. Therefore, we can write the function as,

y = 20x + 38

y = 20(-9) + 38

y = -180 + 38

y = -142

Hence, the output(y) of the function y=20x + 38 if the input is -9 is -142.

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Answer:

8

Step-by-step explanation:

this is because If you multiply the denominator by 2 you will get 32

so if you likewise multiply the numerator by 2 you will get 8

The name of the metric system prefix are :  10^-6: micro , 1/100: centi , 0.001: milli, 1000: kilo

In mathematical exponents, prefixes are referred to as the alphabetic names related to the mathematical factors, such as 10⁻⁹:  it nano ,10⁻¹²: Pico and so on.In order to identify the prefixes of the metric system, we first convert from factor to exponent form.

such :

10^-6  is micro  

1/100 = 0.01x 10^2: centi

0.001 = 1x 10 ^-3 : milli

1000 =  1x 10^3 : kilo

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Write the name of the metric system prefix associated with each mathematical factor. Do not use any hyphens in your answers and do not abbreviate the prefixes. Spelling counts.

10^-6 ______________

1/100 ______________

0.001 _____________

1000 ______________

The derivative of the function using the definition of derivative is 3.

The given function is g(t) = 3t.

We have to find the derivative of the function using the definition of derivative.

We know that,

Definition of derivative:-

The derivative of a function is the rate of change of the function's output relative to its input value.

Here,

Input value = t

Output value = g(t)

Given y = g(t), the derivative of g(t), denoted g'(t) (or dg(t)/dt), is defined by the following limit:

[tex]g'(t)= \lim_{h \to 0} \frac{g(t+h)-g(t)}{h}[/tex]

We have the function:-

g(t) = 3t

Hence, according to the data given in the question, we can write,

g'(t) =

[tex]\lim_{h \to 0} \frac{g(t+h)-g(t)}{h} \\\\ \lim_{h \to 0} \frac{3(t+h)-3(t)}{h}\\\\ \lim_{h \to 0} \frac{3t+3h-3t}{h}\\\\ \lim_{h \to 0} \frac{3h}{h}\\\\\lim_{h \to 0} 3[/tex]

g'(t) = 3

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Answer:

Graph A

Step-by-step explanation:

First, isolate the y variable and simplify

12 = 3x + 4y

-3x+12=4y

-(3/4)x+3=y

From here, you can tell that your graph has a negative slope and a y-intercept at 3.

Graph A is the only graph with a negative slope.

The acres of vacant land that the county have now will be 144 acres.

Since 36% has been used, the remaining percentage will be:

= 1 - 36%

= 64%

Therefore, the acres of vacant land that the county have now will be:

= 64% × 225

= 64/100 × 225

= 0.64 × 225

= 144

Therefore, the acres of vacant land that the county have now will be 144 acres.

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The expression c = 9.10 + 0.42(w-5) ; w > 5 will represent the cost c in terms of w, the total weight in pounds of a package weighing over 5 lbs.

Determine the known quantities and designate the unknown quantity as a variable while trying to set up or construct a linear equation to fit a real-world application.

In other words, an equation is a set of variables that are constrained through a situation or case.

Total cost below 5 lbs = base fee

Total cost over 5 lbs = base fee + additional 0.42/pound

Let's say the total cost is c and the total pounds is w

Then,

c = 9.10 + 0.42(w-5) ; w > 5

Here for w = 6 it will gives w - 5 = 6 - 5 = 1 lbs.

Hence "The expression c = 9.10 + 0.42(w) ; w > 5 will represent the cost c in terms of w".

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Answer:

8(n+5)=5-n

Step-by-step explanation:

First it says "the product of". A product is formed when you multiply two numbers or expressions. The word "and" is used to divide the two items being multiplied. So "The product of 8 and ---" means that you are multiplying 8 and what ever follows the "and" in the problem, in this case it is "the sum of a number and 5". Since what follows the "and" is another expression, it would be written in parentheses. To this point we have: 8 * ( ?? ), where the ?? replaces the expression.

The words "the sum" means that we are adding two numbers or expressions. As with multiplication, "and" separates the two addends. The first addend in the sum is "a number" - thus we know it isn't another expression and that we need to use a variable, because we aren't told the number. You can choose any letter or figure for your variable name, so lets call it "n". The part following the "and" is the number 5. Putting it together results in (n + 5), which will now be combined with the 8 * in the product, resulting in 8 * (n + 5).

The next thing that comes in your problem is "results in". This means "is equal to" and may also be written "is". Mathematical replacement is "=". Following the "=" is another expression: "the difference between 5 and the number". A difference is subtraction and, again, the "and" represents the break between the two values. The first number is 5 the second number is "the number" meaning the same number as before, so we use the same variable. The "difference between 5 and the number" is written: 5 - n

Putting it all together: "The product of 8 and the sum of a number and 5results in the difference of 5 and the number." Translates into math as:

Answer:

d^2/c^3

Step-by-step explanation:

write problem with negative exponent rule

(1/c^6 d^4)^1/2

combine 1/c^6 & d^4

(d^4/c^6)^1/2

use exponent rules to finish simplifying

d^2/c^3