A rectangle has a length of 3x+ 1 and a width of 2x - 9 write an expression for the perimeter of the rectangle

Answers

Answer 1

Given the length and width, the expression for the perimeter of the rectangle is 10x - 16.

What is the expression for the perimeter of the rectangle?

The perimeter of rectangle is expressed as;

P = 2( l + w )

Where l is length and w is width.

Given the data in the question;

Length l =  3x+ 1Width w = 2x - 9

Plug the given values in the equation above

Perimeter = 2( l + w )

Perimeter = 2( (3x+ 1) + ( 2x - 9) )

We can go on and simplify.

Perimeter = 2( (3x+ 1) + ( 2x - 9) )

Perimeter = (6x+ 2) + (4x - 18)

Perimeter = 6x+ 2 + 4x - 18

Perimeter = 10x - 16

Given the length and width, the expression for the perimeter of the rectangle is 10x - 16.

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Related Questions

Order the numbers from least to greatest -3 , -8, |-6|, 2

Answers

Answer: -8, -3, 2, |-6|

Step-by-step explanation:

-3 , -8, |-6|, 2

|-6|=6

6>2

-3>-8 since a negative number closer to 0 is the greater number.

Order: -8, -3, 2, 6 ==> -8, -3, 2, |-6|

Answer
-8, -3, 2, |-6l
I’m pretty sure .

What numbers are a distance of 34 unit from 18 on a number line?


Select the locations on the number line to plot the points.

Answers

Answer:

[tex]\dfrac{7}{8} \textsf{ and } -\dfrac{5}{8}[/tex]

Step-by-step explanation:

To find numbers that are [tex]\dfrac{3}{4}[/tex] units distance from [tex]\displaystyle \dfrac{1}{8}[/tex] , add and subtract [tex]\dfrac{3}{4}[/tex] to and from [tex]\displaystyle \dfrac{1}{8}[/tex]

One of the points is at [tex]\displaystyle \dfrac{1}{8} + \dfrac{3}{4}[/tex] units away and the other at [tex]\displaystyle \dfrac{1}{8} - \dfrac{3}{4}[/tex] units away

Compute    [tex]\displaystyle \dfrac{1}{8} + \dfrac{3}{4} :[/tex]

[tex]\mathrm{For}\:\frac{3}{4}:\:\mathrm{multiply\:the\:denominator\:and\:numerator\:by\:}\:2[/tex]:

[tex]\frac{3}{4}=\frac{3\cdot \:2}{4\cdot \:2}=\frac{6}{8}[/tex]

[tex]\displaystyle \dfrac{1}{8} + \dfrac{3}{4} = \frac{1}{8}+\frac{6}{8} = \frac{7}{8}[/tex]
Compute    [tex]\frac{1}{8}-\frac{3}{4}[/tex]
Again for [tex]\frac{3}{4}:\:\mathrm{multiply\:the\:denominator\:and\:numerator\:by\:}\:2[/tex]
[tex]\frac{3}{4}=\frac{3\cdot \:2}{4\cdot \:2}=\frac{6}{8}[/tex]

[tex]\frac{1}{8}-\frac{3}{4} = \frac{1-6}{8} = \frac{-5}{8}[/tex]

Linear Equations: Mastery Test
Select the correct answer.
Which property of equality was used to solve this equation?
X-5=-14
X-5+5=14+5
X=-9b
A addition property of equality
B. subtraction property of equality
C. multiplication property of equality
D. division property of equality

Answers

The  property of equality was used to solve this equation is addition property of equality

Addition property of equality

The property states that the additive property of equality states that if we add or subtract the same number to both sides of an equation, the sides remain equal.

Given the expression

X-5=-14

Add 5 to both sides to have;

x-5 + 5 = -14 + 5

x = -14 + 4

x = -9

Hence the  property of equality was used to solve this equation is addition property of equality

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What is the solution to this inequality?
X-8>-3
OA. x < -11
OB. x>-11
OC. x<5
OD. x>5

Answers

Answer:

OD

Step-by-step explanation:

move the -8 to the right, and change its sign

x > 5

when a pipe constricts as shown in the figure below, the velocity v of fluid flowing through the pipe is inversely proportional to the pipes cross sectional area a. suppose water flows through a section of pipe of area 10 cm^2 at a velocity of 4 m/s. if the pipe constricts to an area of 2.5 cm^2, what will its velocity be in this section of pipe

Answers

Answer:

A because of the way the pipe is designed

a parte inferior de una escalera debe colocarse a 3 pies de una pared. La escalera mide 10 pies de largo. ¿Qué tan por encima del suelo toca la escalera la pared?

Answers

[tex]\sqrt{10^2 - 3^2}=\boxed{\sqrt{91} \text{ ft}}[/tex]

What kind of passenger be considered a true negative ?

Answers

Answer: A someone with dangerous material passed by security

Step-by-step explanation:

The U.S. Census Bureau defines a household as all of the people who occupy a housing unit as their usual
place of residence. The number of households is not equal to the population because multiple people may
live in the same housing unit.
82.1% of Cincinnati households have a computer. If 111.804 households in Cincinnati have a computer, how
many households are there altogether in Cincinnati? Show your work. Round to the nearest whole number.

Answers

Answer: total household present are 136

Step-by-step explanation:

Given:

82.1% of Cincinnati households have a computer.

111.804 households in Cincinnati have a computer.

According to ratio and proportions we have:

let total number of houses be x;

then

(111.804/x)*100=percentage of Cincinnati households having  a computer.    [[tex]gain/total*100 =gain %[/tex]]

then

(111.804/x)*100=82.1

cross multiplying we have

x=(111.804*100)/82.1

x=136 households  (Round to the nearest whole number.)

so total household present are 136

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i need help asap. plsss give me the right answer

Answers

Answer:

x < 3

Step-by-step explain: I used quizlet

group of 280 elementary school students and 40 adults are going on a field trip. They are planning to use two different types of buses to get to the destination. The first type of bus holds 50 people and the second type of bus holds 56 people.



Andre says that 3 of the first type of bus and 3 of the second type of bus will hold all of the students and adults going on the field trip.

Is Andre correct?

Answers

Answer:

yes!!! because the first 3 types of bus can hold 50 people and the other 3 types of bus can hold 56 people so the total will be 320 people

[tex] \: \: \: \: \: \: \: \: \: \: \: [/tex]​​

Answers

Find the critical points of [tex]f_1[/tex] and [tex]f_2[/tex].

By the fundamental theorem of calculus,

[tex]{f_1}'(x) = \displaystyle \prod_{j=1}^{21} (x-j)^j = (x-1) (x-2)^2 (x-3)^3 \cdots (x-21)^{21}[/tex]

and [tex]{f_1}'=0[/tex] for [tex]x\in\{1,2,3,\ldots,21\}[/tex]. The stationary points at odd values have odd multiplicity, while the even ones have even multiplicity. At the points of odd multiplicity, [tex]{f_1}'[/tex] passes through the [tex]x[/tex]-axis and the sign of [tex]{f_1}'[/tex] changes, while at the points of even multiplicity, [tex]{f_1}'[/tex] is tangent the to [tex]x[/tex]-axis. We also have

[tex]\displaystyle \lim_{x\to-\infty} {f_1}'(x) = (-1)^{1+3+5+\cdots+21} \infty = (-1)^{11^2} \infty = -\infty[/tex]

[tex]\displaystyle \lim_{x\to\infty} {f_1}'(x) = \infty[/tex]

so the plot of [tex]{f_1}'[/tex] looks more or less like the attached curve. (Not drawn to scale)

Wherever the sign of [tex]{f_1}'[/tex] changes from negative to positive, as it does in the case of [tex]x\in\{1,5,9,13,17,21\}[/tex], there is a local minimum, so [tex]m_1 = 6[/tex]. Similarly, wherever the sign changes from negative to positive, as it does when [tex]x\in\{3,7,11,15,19\}[/tex], there is a local maximum, so [tex]n_1 = 5[/tex].

Repeat for [tex]f_2[/tex].

[tex]{f_2}'(x) = 4900 (x-1)^{49} - 29400 (x-1)^{48} = 4900 (x-1)^{48} (x-7)[/tex]

has roots at [tex]x=1[/tex] and [tex]x=7[/tex], but only the latter is a critical point due to odd multiplicity. A rough sketch of the plot of [tex]{f_2}'[/tex] is also attached. The sign of [tex]{f_2}'[/tex] changes from negative to positive at [tex]x=7[/tex], so [tex]m_2 = 1[/tex] and [tex]n_2=0[/tex].

We conclude that

Q.9) [tex]2m_1+3n_1+m_1n_1 = \boxed{57}[/tex]

Q.10) [tex]6m_2+4n_2+8m_2n_2 = \boxed{6}[/tex]

pls help asap I’ll give brainliest immediately.. plsss..

Answers

Answer:

You have the right form (vertex form). All that you have left to do is learn what parts of the equation signify what.

Step-by-step explanation:

Explanation:

In a quadratic function of form y = a

(

x

p

)

2

+ q, the axis of symmetry is found at x = p. As a result, in y = -4

(

x

8

)

2

+ 3, the axis of symmetry is at x = 8, since the formula is x - p = x - (+8).

The vertex of a parabola is at (p, q). As for the axis of symmetry, the p value is 8, and in this function the q value is 3. So the vertex is at (8,3).

With this information, the x and y intercepts, and a few other points found by plugging in x values and solving for y, you will be able to graph this parabola. Your graph, if done properly, will look like the following:

graph{y = -4(x - 8)^2 + 3 [-20, 20, -10, 10]}

Find the sum of 3√2 and 2√8 in simplest form. Also, determine whether the result
is rational or irrational and explain your answer.

Answers

Answer:

7√2

7√2 is irrational since √2 is irrational

Step-by-step explanation:

3√2 + 2√8 = 3√2 + 2 × 2√2 = 3√2 + 4√2 = 7√2

7√2 is irrational since √2 is irrational

What is the greatest common factor of 18 12 16

Answers

The greatest common factor of 18 12 16 is the number 2.

Apply it
What is the value of the expression 4(x - y)
when x = 7 and y = 1?
A 26
7
B 29
C 32
D 48
Apply your thinking
Students, write your response!
Pear Deck Interactive Slide
Curriculum Associal Do not remove this bar

Answers

Answer:

USE AIR MATH!!

Step-by-step explanation:

maths geometry question

Answers

Step-by-step explanation:

with ABCD and ABDE being parallelograms, this means a indicated by the marks

AB = ED = CD

and with BD = DF that means that the line segments BF and CE are intersecting each other at their midpoint.

so they represent a pair of diagonals of a parallelogram, which makes BCFE a parallelogram.

Simplify the expression. (2+1)×42÷2

Answers

Answer:

63

Step-by-step explanation:

Simplifying the expression,

→ (2+1) × 42 ÷ 2

→ 3 × 42 ÷ 2

→ 126 ÷ 2 = 63

Hence, the answer is 63.

to construct a rectangle you must have one side and :
(1) it’s opposite sides
(2) it’s adjacent sides
(3) two angles
(4) four angles

If u answer this question i will give brainlyest and 40 marks

Answers

Answer:

Adjacent sides.

Step-by-step explanation:

Answer:

To construct a rectangle, you must have the measurement of one side and it's adjacent side.

Step-by-step explanation:

to construct a rectangle you must have one side and :

(1) it’s opposite sides

(2) it’s adjacent sides

(3) two angles

(4) four angles

i need help with 23-26 help please​

Answers

2.5, 0.92, 0.75, 0.925

A certain hybrid car can travel 1 9/11 times as far as a similar no hybrid car will on one gallon of gasoline . If the non hybrid car can travel 33 miles per gallon of gasoline, how far can the hybrid travel on 4/5 gallon of gasoline ?

Answers

On 4/5 gallon of gasoline, hybrid car will travel a distance of 48 miles.

How to solve Algebra Word Problems?

Suppose, non hybrid car travel "x" distance in 1 gallon of gasoline

Then, hybrid will travel " 1 ⁹/₁₁ * x" distance in 1 gallon of gasoline

Given that, non hybrid car travel distance per gallon is; x = 33 miles per gallon

Then, hybrid car travel,  1 ⁹/₁₁ * x =  1 ⁹/₁₁ * x * 33 = 60 miles per gallon

On 1 gallon of gasoline hybrid car travel 60 miles

On 4/5 gallon of gasoline hybrid car will travel = 4/5 * 60 = 48 miles

On 4/5 gallon of gasoline, hybrid car will travel 48 miles of distance.

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The value of the 7 in 57,264 is ten times greater than the value of the 7 in which of these numbers?
A. 17,810
C. 78,893
B. 61,715
D. 95,371

Answers

C.78893

Step-by-step explanation:

-_-_+_(*;#-✓✓

If anyone can help me to solve this!!​

Answers

Answer:

[tex]\textsf{1.} \quad x=-6, \quad x=6[/tex]

[tex]\textsf{2.} \quad x=-5, \quad x=2[/tex]

[tex]\textsf{3.} \quad x=-3, \quad x=7[/tex]

[tex]\textsf{4.} \quad x=\dfrac{-5 +\sqrt{57} }{4}, \quad x=\dfrac{-5 -\sqrt{57} }{4}[/tex]

[tex]\textsf{5.} \quad x=\dfrac{7+ \sqrt{309} }{10}, \quad x=\dfrac{7-\sqrt{309} }{10}[/tex]

Step-by-step explanation:

Question 1

Method: Extracting the Square Root

[tex]\begin{aligned}& \textsf{Given}: & x^2 & = 36\\& \textsf{Square root both sides}: & \sqrt{x^2} & = \sqrt{36}\\& \textsf{Simplify}: & x & = \pm 6\\&\textsf{Solution}:&x& = -6, 6\end{aligned}[/tex]

Question 2

Method: Factoring

[tex]\begin{aligned}& \textsf{Given}: & x^2+3x-10 & = 0\\& \textsf{Split the middle term}: & x^2+5x-2x-10 & = 0\\& \textsf{Factor the first two and the last two terms}: & x(x+5)-2(x+5)&=0\\& \textsf{Factor out the common term $(x+5)$}: & (x-2)(x+5)&=0\\& \textsf{Apply the zero-product property}: & (x-2)=0 \implies x&=2\\ &&(x+5)=0 \implies x&=-5\\ & \textsf{Solution}: & x&=-5,2\end{aligned}[/tex]

Question 3

Method: Factoring

[tex]\begin{aligned}& \textsf{Given}: & x^2-4x-21 & = 0\\& \textsf{Split the middle term}: & x^2-7x+3x-21 & = 0\\& \textsf{Factor the first two and the last two terms}: & x(x-7)+3(x-7)&=0\\& \textsf{Factor out the common term $(x-7)$}: & (x+3)(x-7)&=0\\& \textsf{Apply the zero-product property}: & (x+3)=0 \implies x&=-3\\&&(x-7)=0 \implies x&=7\\& \textsf{Solution}: & x & = -3, 7\end{aligned}[/tex]

Question 4

Method: Quadratic  Formula

[tex]\boxed{\begin{minipage}{4 cm}\begin{center}\underline{Quadratic Formula}\end{center}\\\\\begin{center}$x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$\end{center}\\\\\\\begin{center}when $ax^2+bx+c=0$\end{center}\end{minipage}}[/tex]

Given:

[tex]5x-4=-2x^2[/tex]

Rearrange into standard form by adding 2x² to both sides:

[tex]\implies 2x^2+5x-4=0[/tex]

Therefore:

[tex]a=2, \quad b=5, \quad c=-4[/tex]

Substitute the values into the quadratic formula and solve for x:

[tex]\implies x=\dfrac{-5 \pm \sqrt{5^2-4(2)(-4)} }{2(2)}[/tex]

[tex]\implies x=\dfrac{-5 \pm \sqrt{25+32} }{4}[/tex]

[tex]\implies x=\dfrac{-5 \pm \sqrt{57} }{4}[/tex]

Therefore, the solutions are:

[tex]x=\dfrac{-5 +\sqrt{57} }{4}, \quad x=\dfrac{-5 -\sqrt{57} }{4}[/tex]

Question 5

Method: Quadratic  Formula

[tex]\boxed{\begin{minipage}{4 cm}\begin{center}\underline{Quadratic Formula}\end{center}\\\\\begin{center}$x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$\end{center}\\\\\\\begin{center}when $ax^2+bx+c=0$\end{center}\end{minipage}}[/tex]

Given:

[tex]5x^2-7x-13=0[/tex]

Therefore:

[tex]a=5, \quad b=-7, \quad c=-13[/tex]

Substitute the values into the quadratic formula and solve for x:

[tex]\implies x=\dfrac{-(-7) \pm \sqrt{(-7)^2-4(5)(-13)} }{2(5)}[/tex]

[tex]\implies x=\dfrac{7 \pm \sqrt{49+260} }{10}[/tex]

[tex]\implies x=\dfrac{7 \pm \sqrt{309} }{10}[/tex]

Therefore, the solutions are:

[tex]x=\dfrac{7+ \sqrt{309} }{10}, \quad x=\dfrac{7-\sqrt{309} }{10}[/tex]

Find the area of a rectangle that has a length of 4.5 units and a width of 7.2 units. Write the numerical answer only.

Answers

32.4. All you have to do is multiply length times width to find the area.

What do I write for 23???

Answers

By adding all of the prices together is how you get the total cost.

The total cost should be estimated around $60.43

order of operations MC

Joshua purchased a game card for the arcade for a total of $15. He played two basketball hoop games for $2.75 each and three rounds of air hockey for $1.25 each. How much did he have left on the game card?

Answers

Answer: $5.75

Step-by-step explanation: 2.75 x 2 = 5.5    1.25 x 3 = 2.75    2.75 + 5.5 = 9.25     $15 - $9.25 = $5.75

How do I factor 7.2x2y - 0.9xy2

Answers

Answer:

[tex]xy\left(7.2x-0.9y\right)[/tex]

Step-by-step explanation:

[tex]Rule: a^{b+c}=a^ba^c\\(x^2y=xxy,\:xy^2=xyy)\\=7.2x(xy)-0.9xyy\\=xy\left(7.2x-0.9y\right)[/tex]

what is the angle of depression zipline ​

Answers

Answer and Explanation:

The problem provides the following information:

Hypotenuse

=

h

y

p

=

5129

ft

Vertical drop

=

o

p

p

=

1275

ft

To find the angle of depression, the best trigonometric ratio to use is the sine ratio. After equating it with the ratio of the opposite side over the hypotenuse, get the inverse of the sine ratio as shown:

sin

θ

=

o

p

p

h

y

p

θ

=

sin

1

(

o

p

p

h

y

p

)

θ

=

sin

1

(

1275

ft

5129

ft

)

θ

=

sin

1

(

0.2485864691

)

θ

=

14.3938824691

14.4

The angle of depression is

14.4

Find X if
• B is between A and C;
• AB = x+5;
BC= 2 (x-3); and
AB ~ BC

Answers

The awnser is x=11. Since AB=BC you can’t write this equation: X+5=2(X-3) and then solve for x

Use the factor theorem to write a polynomial equation that has solutions of 2, -2, and 4. (Hint: Suppose the solutions of a quadratic equation are 3 and 5. This means that x = 3 or x = 5 which gives us x - 3 = 0 or x - 5 = 0. The expressions are the factors of the polynomial which means that the equation is (x - 3)(x - 5) = 0.)

Answers

The equation of the polynomial with the given roots of 2, -2, and 4 is x³ - 4x² - 4x + 16 = 0.

What is the polynomial equation that has solutions of 2, -2, and 4?

Roots are the points where the graph intercepts with the x-axis ( y = 0 ).

Given the roots in the question;

x = 2, -2, 3

Now, the root of x = 2 was found solving for x when x - (2) = y but y = 0.

Hence, (x - 2) is a factor.

Next, the root of x = -2 was found solving for x when x - (-2) = y but y = 0.

Hence, (x + 2) is a factor

And the root of x = 4 was found solving for x when x - (4) = y but y = 0.

Hence, (x + 2) is a factor

Now, combine all the factors into a single equation and simplify.

( x-2 )( x + 2 )( x - 4 ) = y

( x² + 2x - 2x - 4 )( x - 4) = 0

( x² - 4 )( x - 4) = 0

x( x² - 4 ) -4( x² - 4 ) = 0

x³ - 4x - 4x² + 16 = 0

x³ - 4x² - 4x + 16 = 0

x³ - 4x² - 4x + 16 = 0

Therefore, the equation of the polynomial with the given roots of 2, -2, and 4 is x³ - 4x² - 4x + 16 = 0.

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I WILL GIVE BRAINLYIST Which number is prime? Choose each correct answer. 41 41 42 42 43 43 44 44 45 45 46 46 47. THIS IS MULTIPLE ANSWER.

Answers

41, 43, 47

(Blank space filler)

Answer:

It is 41, 43, 47! :D

Step-by-step explanation:

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