A ray of light in air strikes a glass surface. is there a range of angles for which total internal reflection occurs? explain.

The number of p - orbital electrons in cyclopentadienyl anion are

6 electrons.

We have Cyclopentadienyl anion.

We have to determine number of p - orbital electrons in it.

Atomic orbitals are the 3-dimensional spaces around the nucleus where the probability of finding an electron is maximum.

According to the question -

The Cyclopentadienyl Anion is planar and has a continuous overlap of 5 p-orbitals with 6 electrons. It is an aromatic system  which is highly stable and has a closed shell configuration. The deprotonated form of cyclopentadiene is represented as the cyclopentadienyl anion C5H5⁻.

Hence, the number of p - orbital electrons in cyclopentadienyl anion are

6 electrons.

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The kinetic energy and the speed of the electrons ejected by light of wavelength is

To find the Kinetic energy and speed of the electron, the given values are,

Work function of metallic Caesium - 2.14 ev.

The phenomenon in which electrically charged particles are released from or within a material when it absorbs electromagnetic radiation is called Photoelectric effect. When the electrons on the metal plate gets ejected when the light beam passed on the metal plate.

From the basic equation of photoelectric effect we have

hν = Φ + ½ mv²      

where,

hν - hc/ λ ,is the energy of the incident radiation

Φ - work function of the metal

½ mv² - kinetic energy of the emitted electrons

Thus applying values,

1) For wavelength of 580 nanometers, we have

The energy of incident radiation equals,

6.636× 10⁻³⁴× ((3× 10⁸)/(580× 10⁻⁹× 1.6 × 10 ⁻¹⁹)

=2.14 ev

Since the energy of incident radiation is lesser than or equal to the work function of the metal hence no electron's will be emitted.

2. The Kinetic energy can be,

K.E = 6.636× 10⁻³⁴× ((3× 10⁸)/(580× 10⁻⁹) - 2.14 × 1.6 × 10 ⁻¹⁹)

=2.837 ev.

Thus kinetic energy for the wavelength is 2.837 ev.

Speed of the energy  can be calculated as,

υ = √2E/m = √2×2.837×1.6×10⁻¹⁹/(9.8 × 10⁻³¹)

  = 0.9988×10⁶ m/s.

So, the speed of the energy is 0.9988×10⁶ m/s.

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Two locomotives with a speed of 150 km/h each, reach the other in: 1.9 min

The formula of reach time and procedure we will use to solve this problem is:

Tr = x/(v2+v1)

Where:

Information about the problem:

Applying the reach time formula we get:

Tr = x/(v2+v1)

Tr =  9.5 km/(150 km/h + 150 km/h)

Tr = 9.5 km/(300 km/h)

Tr = 0.032 h

By converting the time units from (h) to (min) we have:

0.032 h * (60 min / 1h) = 1.9 min

It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).

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Answer:

Rutherford's experiment

Explanation:

Rutherford's experiment prompted a change in the atomic model. If the positive alpha particles mostly passed through the foil, but some bounced back. AND if they already knew that the electron was small and negative, then the atom must have a small positive nucleus with the electrons around them.

By using the power formula, the resistance of the bulb is 121 Ω.

We need to know about dissipated power to solve this problem. Power is energy dissipated to resistance as heat energy. It can be determined as

P = I . V

where P is power, I is current and V is voltage.

From Ohm's Law, we can substitute the current to

I = V / R

Hence, we can write the power equation to

P = (V/R) . V

P = V² / R

From the question above, we know that:

P = 100 watt

V = 110 volt

By substituting the following parameters, we get

P = V² / R

100 = 110² / R

R = 121 Ω

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The resultant internal loading acting on the cross section of C are Normal force of 0 N, Shear force of 233.33 N and Bending moment of 433.325 N.

We know that Moment = Force * Distance.

Given that,

Force along span C = 600 N / m

First chart a free body diagram as shown in Fig 1.

The distributed load along span c is replaced by a point load F at its midpoint.

Force at midpoint of span C = 600 * 2 N

Take moments about point A

Σ [tex]M_{A}[/tex] = 0

-600 * ( 2 ) * [ 1 + ( ( 1 + 1 ) / 2 ) ] + [tex]B_{y}[/tex] ( 4.5 ) - 900 ( 6 ) = 0

- 2400 + 4.5 [tex]B_{y}[/tex] - 5400 = 0

[tex]B_{y}[/tex] = 1733.33 N

Consider a section at Point C and draw a free body diagram as shown in Fig 2.

In fig 2,

[tex]V_{C}[/tex] = Shear force at point C

[tex]N_{C}[/tex] = Normal force at point C

[tex]M_{C}[/tex] = Bending moment at point C

Applying equilibrium condition to the system. Consider equilibrium of Forces along X direction

Σ [tex]F_{x}[/tex] = 0

[tex]N_{C}[/tex] = 0 N

Consider equilibrium of Forces along Y direction

Σ [tex]F_{y}[/tex] = 0

[tex]V_{C}[/tex] - 600 ( 1 ) + [tex]B_{y}[/tex] - 900 = 0

[tex]V_{C}[/tex] = 600 - 1733.33 + 900

[tex]V_{C}[/tex] = 233.33 N

Take moment about point C

Σ [tex]M_{C}[/tex] = 0

- [tex]M_{C}[/tex] - 600 ( 1 ) ( 1 / 2 * 1 ) +  [tex]B_{y}[/tex] ( 2.5 ) - 900 ( 4 ) = 0

- [tex]M_{C}[/tex] - 300 + 2.5 ( 1733.33 ) - 3600 = 0

[tex]M_{C}[/tex] = 433.325 N

The resultant internal loading acting on the cross section are Normal force, Shear force and Bending moment

Therefore, The resultant internal loading acting on the cross section of C are as follows

Normal force [tex]N_{C}[/tex] = 0 N

Shear force [tex]V_{C}[/tex] = 233.33 N

Bending moment [tex]M_{C}[/tex] = 433.325 N

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The only dissimilarity between Coulomb's law and Newton's law of gravitation other than the type of force considered is Newton's law only considers negative force while Coulomb's law considers both forces.

In these contexts, it is considered that repulsive forces are positive and attractive forces are negative. So, Newton's law of gravitation considers gravitational force which only attracts. So, Newton's law of gravitation takes only negative force into account while Coulomb's law considers both electric charges.

According to Newton's law of gravitation,

F = G [tex]m_{1} m_{2}[/tex] / [tex]r^{2}[/tex]

According to Coulomb's law

F = k [tex]q_{1} q_{2}[/tex] / [tex]r^{2}[/tex]

Therefore, the only dissimilarity between Coulomb's law and Newton's law of gravitation other than the type of force considered is Newton's law only considers negative force while Coulomb's law considers both positive and negative forces.

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A ship travels 20 km to the south and then 40 km to the west. The ship's displacement from its starting point is approximately 44.7 km. Hence, the displacement is approximately 45 km.

Here, the calculation is done,

a = 20 km (southward movement)

b = 40 km (westward movement)

Now, one can find the displacement (d) using the Pythagorean theorem:

d² = a² + b²

d² = (20 km)² + (40 km)²

d² = 400 km² + 1600 km²

d² = 2000 km²

Now, by taking the square root of both sides to find the displacement (d):

d = √(2000 km²) d ≈ 44.7 km (rounded to one decimal place)

So, the ship's displacement from its starting point is approximately 44.7 km.

Hence, the displacement is approximately 45 km.

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A protective layer that shields the surface from lethal ultraviolet light is found in second layer of the atmosphere i.e., stratosphere.

More about ozone

The ozone layer is a component of the stratosphere, which is the second layer of the Earth’s atmosphere. The stratosphere is the name given to the layer of insulating gases that clings to our globe.

Ozone is a trace gas since there are only around 3 of its molecules in the atmosphere for every 10 million air molecules. But it serves an important purpose.

Like a sponge, the ozone layer absorbs sunlight that reaches Earth. While some of the sun’s radiation is essential for our survival, excessive amounts can be harmful to other living things.

The ozone layer shields life on Earth.

Benefits of ozone

Ozone does a good job of trapping ultraviolet radiation, also known as UV light, which may damage DNA molecules in plants and animals and penetrate protective layers on creatures like the epidermis.

The two primary subtypes of UV light are UVB and UVA.

UVB causes skin conditions including sunburns and cancers like basal cell carcinoma and squamous cell carcinoma.

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Answer:

In the Stratosphere

The protective layer is made of OZONE (O3). It shields us from the Sun's ultraviolet light. If the Ozone layer in the stratosphere becomes thin (letting more ultraviolet light through) it can lead to light and severe health effects, both to humans and animals, and can even affect food webs. In people, excess UV light can lead to certain forms of cataracts, increase in burns, cataracts, and sometimes even mutations (according to my FLVS Envornmental science course).

Have a great day!

The time taken by the rock to travel another 67m is 1.5 s.

Taking +y direction downward and y₀= 0, we have y = V₀t+1/2 gt², which (with V₀≠0) yields t= [tex]\sqrt{\frac{2y}{g(a)} }[/tex]

(a) For this part of motion, y₁ = 67m, so that

                           t₁ = [tex]\sqrt{\frac{2(67)}{9.8 m/s^{2} } }[/tex] = 3.7 s

(b) For this next part of motion. we note that the total displacement is

                      y₂= 134m

Therefore, the total time is t₂ = [tex]\sqrt{\frac{2(134)}{9.8m/s^{2} } }[/tex] = 5.2 s

The difference between this and the answer to part (a) is the time required to fall through that second 67m distance:

Δt = t₂-t₁ = 5.2s - 3.7s = 1.5s

Therefore the time taken by the rock to travel another 67m is 1.5 s.

Gravity causes a body to descend faster, and as it does, the air resistance that slows it down rises. This keeps happening until the weight of the object and the force of air resistance are equal.

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The average speed of a horse that gallops a distance of 10 km in a time of 30 min is: b. 20km/h.

The formula and procedure we will use to solve this problem is:

v = x/t

Where:

Information about the problem:

By converting the time units from (min) to (h) we have:

t = 30 min * 1 h/60 min

t= 0.5 h

Applying the velocity  formula we get:

v = x/t

v = 10 km/0.5 h

v = 20 km/h

It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).

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Answer:

See below

Explanation:

(180 000 - 10) km  /  36 km/s = 4999.7 =~ 5000 seconds = 83 .3 min

Rinse chemicals from your hands and arms with water in the sink

In the chemistry lab we use to work with chemical solutions, because of that we must learn what is the best way to manipulate the chemicals with we are going to work, so an proper way to maintain our hands and arms clean is using the lab's sink in order to wash our hands and arms with enough water

In chemistry a solution is known as a homogeneous mixture of two or more components called:

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Explanation

23.6/100= 0.236

The magnitude of ax is given by |ax|= | v₀²/2(d −v₀t) |

acceleration: change in velocity with respect to time.

It is a vector quantity. That means it has both magnitude. As well as direction.

a = dv/dt

where

dv = change in velocity

dt = Time

the unit of acceleration is m/s²

magnitude of  acceleration is represented by its unit and the direction is represented by a unit vector.

according to the Newton's Second Law acceleration is proportional to the total force and inversely proportional to the objects mass.

magnitude of acceleration is proportional to magnitude of this force.

The magnitude of ax is given by |ax|= | v₀²/2(d −v₀t) |

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The net forces on the first car is zero, the middle car is zero, and the last car is also zero.

In mechanics, the net force is the vector sum of all forces acting on a particle or object. The original forces' impact on the particle's motion is replaced by the net force, which is a single force. It causes the particle to accelerate at a rate equal to the sum of all those actual forces, as stated by Newton's second law of motion.

It is possible to figure out the torque connected to the point at which a net force is applied in order to keep the object's jets moving in the direction of the initial force field. Its resulting torque, the net force, has the same impact on the object's rotational motion as all actual forces combined.

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The badgers displacement from its position at point t = 2, to its position at point t = 3 is 25 meters

The points on the graph are;

(0, 0), (1, 5), (3, -5), (6, -5)

The point t = 2 is between (1, 5) and (3, -5)

The slope, m, of the line containing the point t = 2 is therefore;

The equation of the line is therefore;

v - 5 = -5•(t - 1)

v = -5•t + 5 + 5 = -5•t + 10

v = -5•t + 10

At t = 2, we have;

v = -5×2 + 10 = 0

The velocity at t = 2 is 0 m/s

The value of the acceleration is the same as the slope, m = a = -5

Given that the initial velocity at t = 2 is 0, we have;

∆x = u•t + 0.5•a•t²

At t = 3, the time of travel from the time t = 2 is 1 seconds, which gives;

∆x = 0×5 + 0.5×(-5)×1² = -2.5

The distance traveled between points, t = 2 and t = 3 is ∆x = -2.5, which is 2.5 meters in the direction opposite to the initial direction.

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The temperature when the pressure in the thermometer is 6.00 atm is T2= 30.933 K

As specified by the IUPAC since 1982, one mole of an ideal gas has a volume of 22.710947(13) litres at standard conditions of temperature and pressure (273.15 K and precisely 105 Pa).

continuous volume,

Constant = PT

P equals pressure.

temperature, or T

Then

TTtri=PPtri

PPtriTtr = 273.16 SoT

Water's triple point temperature is i.

We have provided

P =0.0630 atm

T =348 K

T = 273.16 is the triple point value.

P/Ptri

Ptri = 273.16 then.

PT= 273.16 × 0.0630/348

Ptri = 0.0494 atm.

P =0.00560 atm

Ideal gas is present here at constant volume.

Thus, PT = Constant

P2T2=P1T1

T2 = P2

T1P1=0.00560×348

=0.0630

T2= 30.933 K

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When listening to this issue, add 10.5% by mass glucose solution. We must ascertain the density, modularity, and morality of the answer. Given currently 10.5% by mass glucose solution, 1.3 milliliters.

Molarity = 54.50 M

Explanation:

Thus, a 100 g solution would contain 10.5 g of glucose. Therefore, the solvent in this instance has a huge mass and is a solution. That is 100 g less the solute’s mass.

Molarity is defined as the number of moles of a solute in 1 liter of solution. It has mol/l unit.

Molar mass of glucose, C6H12O6 = (6*12) + (1*12) + (16*6)

= 72 + 12 + 96 = 180g/mol

Density of glucose solution = 1.03g/ml

Density in g/l = 1.03g/ml * 1ml/10^-3l

= 1030g/l

10.5% mass of glucose = 10.5/100 * 180

= 18.9g/mol

Molarity = density (g/l)/molar mass (g/mol)

= 1030/18.9

= 54.50 M

Therefore, we arrive at the solution of 54.50M

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The statement is incorrect as the Speed of anything cannot be negative.

The speed of a body is a scalar quantity and the speed of anybody may be defined as the distance covered by the body per unit of time. the speed of anybody is represented in the form of Distance and time as:

Speed = Distance/time

As both Distance and time are quantities that can never have a negative value therefore the speed of a body also can never have a negative value. In this statement a student refers to a bird and says that its speed is - 7m/s which indicates that the speed is negative that is why this statement is wrong as speed can never have a negative value. The speed of a body is always positive or zero.

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According to Stefan’s law, a hotter body radiates 68 times more energy per unit area per second

As per Stefan’s law, Fhotter/Fcooler = 68

The Stefan law or the Stefan-Boltzmann law, states that the total radiant heat power that is emitted from a surface per unit area at the absolute temperature is directly proportional to the fourth power of its temperature.

The unit used in Stefan’s law is σ which equals to Wattm−2k−4

This law was formulated by Josef Stefan in 1879 through his experimental studies and again by Ludwig Boltzmann in 1844 from thermodynamic considerations.

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Answer:

d = 2.70 g/mL

Explanation:

search the next one up on go ogle it will give you an answer i promise

The highest precision for determining a particle's position will rise as the maximum accuracy for determining its velocity will fall.

The pace at which an object's position changes as perceived from a particular point of view and as measured by a particular unit of time (for example, 60 km/h northbound) is defined as its velocity. Velocity is a fundamental concept in kinematics, the branch of classical mechanics that deals with the motion of bodies.

In order to be defined, the physical vector quantity known as velocity needs to have both a magnitude and a direction. In the SI, speed is expressed in meters per second (m/s or m/s1), a coherently derived unit (metric system). Speed is the magnitude of a scalar absolute value of velocity.

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When the elevator is at rest, the scale reads 75 kg.

The scale will read higher than when the elevator is at rest if you stand on it as it accelerates upward, making you feel heavier due to the elevator's floor pressing more forcefully on your feet. On the other hand, you feel lighter as the elevator speeds down. The scale will display the normal force, which is less than it was at rest, as N = m(g - a). An elevator scale is being used by a 75 kg individual to demonstrate the issue. The scale reads 100 kg as the elevator starts to rise.

In the case of a rest, the combined force acting on the elevator is caused by the person's mass and Earth's gravitational pull. As a result, the scale reads 75 kg when the elevator is at rest.

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The solution to the problems in correct significant figures are;

a. 10.8 g - 8.264 g = 2.536 g

b. 4.75 m - 0.4168 m = 4.3332 g

c. 139 cm x 2.3 cm = 319.7 cm²

d. 13.78 g/11.3 mL = 1.22 g/ml

e. 1.6 km + 1.62 m + 1200 cm =  1,613.62 m

Significant figures are used to establish the number which is presented in the form of digits.

a. 10.8 g - 8.264 g = 2.536 g

b. 4.75 m - 0.4168 m = 4.3332 g

c. 139 cm x 2.3 cm = 319.7 cm²

d. 13.78 g/11.3 mL = 1.22 g/ml

e. 1.6 km + 1.62 m + 1200 cm = 1,600 m + 1.62 m + 12 m = 1,613.62 m

Thus, the solution to the problems in correct significant figures are;

a. 10.8 g - 8.264 g = 2.536 g

b. 4.75 m - 0.4168 m = 4.3332 g

c. 139 cm x 2.3 cm = 319.7 cm²

d. 13.78 g/11.3 mL = 1.22 g/ml

e. 1.6 km + 1.62 m + 1200 cm =  1,613.62 m

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Answer:

1100 kg

Explanation:

500 lb x 2.20lb (1kg) =1100kg

A cyclist starts from rest and accelerates at 4.0 m/s^2 for 3.0 s. After that, the biker travels for 20 seconds at a steady speed. The cyclist travels 258 meters.

This kind of motion is described as the motion of an item traveling in a straight line while maintaining a constant speed along that path while it traverses equal distances in similar amounts of the time, regardless of the length of the time.

A body's acceleration must be zero if it is moving rectilinearly and is doing so consistently.

When an object is travelling uniformly, its speed remains constant. When an item moves uniformly, its displacement is given by the formula x=vt, where v stands for constant velocity and t for the motion's time interval.

Given by, is the displacement of a motion with constant acceleration.

v is constant velocity

t is time interval of the motion.

Given by, is the displacement of a motion with constant acceleration.

[tex]x=v_{i}t+\frac{1}{2}at^{2}[/tex], where

It has a constant acceleration of a

[tex]v_{i}[/tex] is the motion's time interval, and t is the beginning velocity.

Answer and justification

Given: The cyclist's starting speed is,

[tex]v_{i}[/tex]=0

The cyclist's initial acceleration is 4 m/s2.

The span of time during which motion has a constant acceleration is,

[tex]t_{1}[/tex]=3s

The cyclist's displacement in 3 seconds will be,

[tex]x_{1}= v_{i}t_{1}+\frac{1}{2}at_{1}^{2}=0(3)+\frac{1}{2}(4)(3)^{2}=18m[/tex]

After 3 seconds, the cyclist's final speed will be,

[tex]v_{f}= v_{i}+at_{1}=0+4(3)=12m/s[/tex]

t2=20s is the time interval for a cyclist traveling at a steady speed.

The biker will move x2 in the following 20 seconds at a constant speed,

x2=[tex]v_{f}t^{2}[/tex]=(1/2)(20)=240m

The biker will have covered a total distance of

x=x1+x2=18+240=258m.

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The correct option is (b) 1.25

The CPI of the project is 1.25. Earned Value (EV) is divided by Actual Cost (AC) to determine CPI.

CPI is calculated as follows: EV / AC. In this case, 250 / 200 = 1.25.

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The volume of the solid is [tex]V=128\frac{r^{3} }{3}[/tex]

What do you understand by Volume ?

A liquid, solid, or gas's volume is the amount of three-dimensional space it occupies. Although there are many different units that can be used to indicate volume, the most common ones are liters, cubic meters, gallons, milliliters, teaspoons, and ounces.

base is x2+y2=(2r)2

==>y=-√(4r2-x2) ,√(4r2-x2)

So each cross section parallel has base = √(4r2-x2) - -(√(4r2-x2)) = 2√(4r2-x2) and height = base

So area of each cross section is 2√(4r2-x2)*2√(4r2-x2)= 4(4r2-x2)

Now we integrate from left side of circle to right side of circle (-2r to 2r)

V = 4 ∫[ -2r to 2r] (4r2-x2)dx

V = 4 (4r2x - x3/3) [ -2r to 2r]

V = 4 [(4r2(2r) - (2r)3/3) - (4r2(-2r) - (-2r)3/3)]

V = 4 [ (8r3 - 8r3/3) - (-8r3 + 8r3/3)]

V = 4 (16r3 - 16r3/3)

V = 4 (32r3/3)

V = 128r3/3

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The density of the metal is 0.006 Kg / [tex]cm^{3}[/tex]

We know that,

ρ = m / V

V = l w h

where,

ρ = Density

m = Mass

V = Volume

l = Length

w = Width

h = Height

Given that,

m = 1.5 kg

l = 17.1 cm

w = 3.2 cm

h = 4.5 cm

V = 17.1 * 3.2 * 4.5

V = 246.24 [tex]cm^{3}[/tex]

ρ = 1.5 / 246.24

ρ = 0.006 Kg / [tex]cm^{3}[/tex]

Density is defined as the amount of matter present in an enclosed boundary. It is represented as ρ.

Therefore, the density of the metal is 0.006 Kg / [tex]cm^{3}[/tex]

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