A nuclear of 208pb has 82 protons with a sphere of radius 6.34 * [tex]10^{-15}[/tex]m. The electric field at the surface of the nucleus is 2.24 x [tex]10^{11}[/tex] N/C.
The electric field at the surface of a nucleus can be calculated using Coulomb's law, which states that the electric field produced by a point charge is proportional to the charge and inversely proportional to the square of the distance from the point charge.
E = k * q / [tex]r^{2}[/tex]
where,
E = the electric field in N/C
k = the Coulomb constant, equal to 8.99 x [tex]10^{9}[/tex] N [tex]m^{2}[/tex] / [tex]C^{2}[/tex]
q = the charge on the nucleus, equal to 82 times the charge on a proton, or 82 * 1.60 x [tex]10^{-19}[/tex] C
r is the radius of the nucleus, equal to 6.34 x [tex]10^{-15}[/tex]m
Plugging in these values, we get:
E = 8.99 x [tex]10^{9}[/tex] N [tex]m^{2}[/tex] / [tex]C^{2}[/tex] * 82 * 1.60 x [tex]10^{-19}[/tex] C / 6.34 x [tex]10^{-15}[/tex]m ^2
E = 2.24 x [tex]10^{11}[/tex] N/C.
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a football is kicked from ground level at a speed of 28 m/s m / s . if it reaches a maximum height of 26 m m , at what angle was it kicked (relative to horizontal)?
The football was kicked at an angle of approximately 8.2 degrees relative to the horizontal.
The problem can be solved using kinematic equations of motion and conservation of energy. The initial vertical velocity component of the football can be calculated from the initial velocity, maximum height, and time of flight, which can be calculated from the vertical motion of the football.
The initial vertical velocity component, v0y, can be calculated as follows:
v0y = v0sinθ
where v0 is the initial velocity and θ is the angle at which the football was kicked. The maximum height, h, is related to the initial vertical velocity and the acceleration due to gravity, g, by the following equation:
h = v0ysinθ * t - 1/2 * g * t^2
Rearranging and substituting the values:
sinθ = (h + 1/2 * g * t^2) / (v0 * t)
where t is the time of flight and can be calculated as:
t = (2 * v0sinθ) / g
So,
t = (2 * 28 * sinθ) / 9.8
And the maximum height is:
h = 28sinθ * t - 1/2 * 9.8 * t^2
Substituting the given values:
26 = 28sinθ * (2 * 28 * sinθ) / 9.8 - 1/2 * 9.8 * (2 * 28 * sinθ)^2 / 9.8^2
Solving for sinθ:
sinθ = sqrt(520 / 506) = sqrt(13 / 127)
So,
θ = sin^-1(sqrt(13 / 127)) = approximately 8.2 degrees
Thus, the football was kicked at an angle of approximately 8.2 degrees relative to the horizontal.
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near the end of a marathon race, the first two runners are separated by a distance of 65.0 m . the front runner has a velocity of 3.25 m/s , and the second runner has a velocity of 4.75 m/s . what is the magnitude of the velocity of the second runner relative to the first?
The magnitude of the velocity of the second runner relative to the first is 1.50 m/s
The velocity of the second runner relative to the first runner can be found using the following formula:
v_rel = v_2 - v_1
Where v_rel is the relative velocity, v_2 is the velocity of the second runner (4.75 m/s), and v_1 is the velocity of the first runner (3.25 m/s). Plugging in the values, we get:
v_rel = 4.75 m/s - 3.25 m/s = 1.50 m/s
The magnitude of the velocity of the second runner relative to the first is the absolute value of v_rel:
|v_rel| = |1.50 m/s| = 1.50 m/s
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how does the law of superposition help determine the age of fossils compared to others?
A circuit with 0.7 A running through the battery and two 16 Ω resistors in parallel. What is the voltage of the battery?
Answer:
Below
Explanation:
The two PARALLEL resistors equal: 1 / (1/16 + 1/16) = 8 Ω
V = IR = .7 (8) = 5.6 v
(a) a runner starts from rest and in 2 s reaches a speed of 9 m/s. if we assume that the speed changed at a constant rate (constant net force), what was the average speed during this 2 s interval? average speed
The average speed of an object during a time interval can be found by dividing the total distance traveled by the time interval. So the average speed during the 2 s interval was 4.5 m/s.
If the speed changed at a constant rate during the interval, then we can use the average speed as an approximation for the speed at the midpoint of the interval.
In this case, the runner started from rest and reached a speed of 9 m/s in 2 s, so the average speed would be half of the final speed:
average speed = (0 + 9 m/s) / 2
= 4.5 m/s
So the average speed during the 2 s interval was 4.5 m/s.
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how long is the flea in the air from the time it jumps to the time it hits the ground? express your answer in seconds to three significant figures.
The time a flea spends in the air from the time it jumps to the time it hits the ground depends on the initial velocity of the jump and the acceleration due to gravity.
To calculate the time, we need to know the initial velocity and the height the flea jumps. Without this information, it is not possible to determine the time the flea spends in the air.
You will use kinematic equations to analyze a jumping flea in this problem. Assume that the free-fall acceleration is 9.80.
In standard athletics, the running leap and standing jump have an initial velocity of 9.15 and 2.70 m/s and an initial angle of jump of 21 and 38 degrees, respectively. Maximal beginning velocity strength, angle of engaged force, and height are all strongly correlated with the maximum horizontal velocity of 9.15 m/s.
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a 95.0 kg fullback moving south with a speed of 5.0 m/s has a perfectly inelastic collision with a 90.0 kg opponent running north at 3.0 m/s. a. calculate the velocity of the players just after the tackle. b. calculate the decrease in total kinetic energy as a result of the collision.
The velocity of the players just after the tackle 4.027 m/s and the change in kinetic energy will be 92 J
The system's overall momentum is conserved in an inelastic collision because the two bodies travel at the same speed.
Assuming v as the final speed, we obtain the following by maintaining momentum:
(m + M)v = mu - MU
where
m = 95 kg is the fullback's mass
M = 90 kg is the opponent's mass.
u = 5 m/s for the fullback's pace
opponent's speed, U = 3 m/s
The opponent's momentum is negative since he must be travelling in the opposite direction from the fullback.
(m + M)v = mv + Mv
95×5 + 90×3 = (90 +95)v
205 = 185v
v = 4.027 m/s
Consequently, both players move at a 4.027 m/s speed.
Similarly final KE of the player
KE = 1/2 (m+M) V²
KE = 1/2 (95+90)x 4.027 ²
KE = 1500 J
so the change in KE will be
1592-1500 = 92 J
Thus the velocity of the players just after the tackle 4.027 m/s and the change in kinetic energy will be 92 J
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a car and a truck start from rest at the same instant, with the car initially at some distance behind the truck. the truck has a constant acceleration of 2.10 m/s2 and the car an acceleration of 3.40 m/s2. the automobile overtakes the truck after the truck has moved 60.0 m. a) t=7.56s b) how far was the car behind the truck initially? c) what is the speed of the truck when they are abreast? d) what is the speed of the car when they are abreast?
Each moves past the other at a pace of 15.876 meters per second.
A constant acceleration is defined.How rapidly a particle's velocity varies in proportion to time is referred to as its "acceleration." When a subatomic particle velocity varies at a set rate, the change is referred to as constant acceleration.
A = v v 0 t does exist. This means that, for a certain period of time, is if difference between the and end velocity is small, the velocity is negligible and goes to zero in the limit when they are equal. Consider a particle moving uniformly around a circle; it accelerates since the motion's vector is changing, but it keeps its speed constant along perpendicular throughout the motion.
In this question, we'll be making use of
x - x₁ = v₁t + ½at²
The above equation is a modification of
x = vt + ½at²
Where x = distance
v = velocity of the body
a = acceleration of the body
t = time
x - x₁ = v₁t + ½at²
Assuming the starting point of the bodies x₁ = 0 which is at rest, the car sped past the truck at 60m.
x - x₁ = v₁t + ½at²
x₁ = 0
v₁ = 0
x = 60
a = 2.10
t = ?
60 - 0 = 0 × t = ½ × 2.10t²
Solve for t
60 = 1.05t²
t² = 60 / 1.05
t² = 57.14
t = √(57.14)
t = 7.56s
The time it took the car to over take the truck is 7.56s
b).From our previous equation,
x - x₁ = v₁t + ½at²
Same variable except
a = 3.40m/s² and t = 7.56s
60 - x₁ = 0 + ½ × 3.40 × 7.56²
60 - x₁ = 97.16
x₁ = 60 - 97.16
x₁ = -37.16m
The car was behind the truck by 37.16m or the truck was ahead of the car by 37.16m.
c).The initial speed of the car ?
v = u + at
u = 0m/s
a = 3.40m/s²
v = 0 + 3.40 × 7.56
v = 25.704m/s
The initial speed of the truck = ?
v = u + at
u = 0m/s
a = 2.10m/s
v = 0 + 2.10 × 7.56
v = 15.876m/s
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an express train passes through a station. it enters with an initial velocity of 22.0 m/s and decelerates at a rate of 0.160 m/s2 as it goes through. the station is 205 m long. how long did the nose of the train stay in the station?
3.05s is taken for the nose of the train stay in the station which enters with an initial velocity of 22.0m/s and decelerates at a rate of 0.160 m/s^2 as it goes through the station is 205 m long.
Given the initial velocity of train (u) = 22m/s
The deceleration of train (a) = -0.160m/s^2
The length of station (Δd) = 205m
Time taken for the train to cross the station = t
From Newtons laws of motion, we know that Δd = ut + 1/2at^2
Then, 205 = 22 x t - 1/2 x 0.160 x t^2
22t - 0.08t^2 - 205 = 0
Then t = 3.05s
Hence the time required for nose of the train stay in the station is 3.05s.
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why do we need to be careful about work done on the system versus work done by the system in calculations?
We have to be careful about work done by system and work done on system because they are completely different in nature.
In physics, work is said to be done on a system when force is applied to it and the system suffers displacement. Work is considered to be done by a system when it applies a force to something else and produces displacement.
Work done on the system indicates that anything outside the system (other than heat flow into the system) accomplished something to enhance the internal energy of the system. Because the system worked on anything outside the system, the system's internal energy diminished.
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two resistors can be either connected to a battery in series or in parallel. in which case, if either, is the equivalent resistance the smallest?
In a circuit with two resistors, the equivalent resistance is smallest when the resistors are connected in parallel.
In a parallel circuit, the total resistance is smaller than the smallest individual resistor because the current is divided among the resistors. Each resistor in the circuit has its own current, and the total current is equal to the sum of the individual currents. This means that the total resistance in a parallel circuit is less than the smallest individual resistor, since the current flowing through each resistor adds up to the total current.
In a series circuit, the total resistance is equal to the sum of the individual resistors, so the total resistance is greater than the smallest individual resistor. This is because in a series circuit, the current flows through each resistor one after the other, so the total resistance is the sum of the resistances of each resistor.
Therefore, the equivalent resistance is smallest in a parallel circuit.
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the force of attraction between two or more objects
The offered statement claims that gravity is the gravitational pull amongst two or more things.
What in physics is a force?The essence of force in quantum mechanics is: The pull or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.
What is the scientific definition of force?The term "force" has a specific meaning in science. At this level, calling a force a pushes or a yank is quite appropriate. A spirit is not a substance an item "has in it" or that it "contains." One thing experiences a force from another.
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a box sits on a horizontal table. a string with tension t pulls to the right, but static friction between the box and the table prevents the box from moving. 1)what is the magnitude of the static frictional force acting on the box
Magnitude of the static frictional force acting on box is : c)T. Hence option c) is the correct answer. It is not moving therefore static friction needs to equal to force so that net force is zero.
What is static friction?The force of friction on an object that is not moving is called as static friction. If you push on stationary block and it doesn't move, then it is being held by static friction which is equal and opposite to your push.
Force acting on an object is said to be static force if it does not change the size, position, or direction of the particular object. Force applied to a structure acts as load to that structure, which is why static force is also known as static load.
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Note: The question given on portal is incomplete. Here is the complete question.
Question: A box sits on a horizontal table. A string with tension T pulls to the right, but static friction between the box and the table prevents the box from moving.
1)What is the magnitude of the static frictional force acting on the box?
a) Mg
b) μMg
c) T
d) 0
which would you measure in kilograms? (1 point) the mass of a butterfly, the capacity of a bottle, the mass of a basketball, the length of a river
in getting ready to slam-dunk the ball, a basketball player starts from rest and sprints to a speed of 6.26 m/s in 2.20 s. assuming that the player accelerates uniformly, determine the distance he runs.
The basketball player runs a distance of 12.54 meters to reach the speed of 6.26 m/s.
The average velocity of the basketball player can be calculated using the equation:
v = v0 + a * t
Where v is the final velocity, v0 is the initial velocity (0 m/s), a is the acceleration, and t is the time taken. We can rearrange this equation to solve for a:
a = (v - v0) / t = (6.26 m/s - 0 m/s) / 2.20 s = 2.83 m/s^2
Next, we can use the equation for distance travelled under constant acceleration:
d = v0 * t + 0.5 * a * t^2
Plugging in the given values, we get:
d = 0 * 2.20 s + 0.5 * 2.83 m/s^2 * 2.20 s^2 = 12.54 m
So the basketball player runs a distance of 12.54 meters to reach the speed of 6.26 m/s.
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Did Earth's inner core stop spinning? Is it true that new study finds Earth may soon spin in reverse?
Answer:
Earth's inner core may have stopped turning and could go into reverse, study suggests. The rotation of Earth's inner core may have paused and it could even go into reverse, new research suggests. The Earth is formed of the crust, the mantle and the inner and outer cores.
Explanation:
how does a voltage in one coil result in a different voltage in a second coil in a microwave transformer?
Answer:
A changing current in the primary coil induces an e.m.f in the secondary. Since the e.m.f generated depends on the number of turns, the voltage induced in the secondary can be changed - stepped up or down - by altering the turn's ratio.
what are the units of k for a third order reaction?
The unit of a third-order reaction is mol-2L2s-1.
What are some examples of the order of reaction?
The total of the exponents that the concentration terms in the rate law are increased to determine the reaction's overall order. Take the products of the reaction aA+bB, for instance. Reactants A and B are in that sequence in the reaction, which is a and b, respectively. The reaction happens in the general order a+b.
Which reaction order's units of k are appropriate?
The overall reaction sequence affects the units of the rate constant, k. M/s, 1/s, and 1/(Ms) are the units of k for zero-order reactions, first-order reactions, and second-order reactions, respectively.
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if the electric field is 108 n/c at a distance of 59 cm from a point charge q, what is the value of q (in c)? (enter the magnitude.)
If the electric field is 108 n/c at a distance of 59 cm from a point charge q, the charge on the point charge is 9.98 x [tex]10^{-19}[/tex] Coulombs.
We can use the equation for the electric field produced by a point charge to find the charge:
E = k * q / [tex]r^{2}[/tex]
where,
E = the electric field, equal to 108 N/C
k = the Coulomb constant, equal to 8.99 x [tex]10^{9}[/tex] N [tex]m^{2}[/tex] / [tex]C^{2}[/tex]
q = the charge
r = the distance from the point charge, equal to 59 cm = 0.59 m
Rearranging the equation to solve for q, we get:
q = E * [tex]r^{2}[/tex] / k
Plugging in the values, we get:
q = 108 N/C * [tex](0.59 m)^{2}[/tex] / 8.99 x [tex]10^{9}[/tex] N [tex]m^{2}[/tex] / [tex]C^{2}[/tex] )
q = 9.98 x [tex]10^{-19}[/tex] C
So the charge on the point charge is 9.98 x [tex]10^{-19}[/tex] C, or 9.98 x [tex]10^{-19}[/tex] Coulombs.
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a 1.0-cm-diameter pipe widens to 2.0 cm, then narrows to 5.0 mm. liquid flows through the first segment at a speed of 4.0 m/s. what is the speed in the second and third segments?
The speed of the liquid in the second segment is V2 = 2.8284 m/s and The speed of the liquid in the third segment is V3 = 14.1421 m/s.
What is speed?
The velocity (commonly denoted as v) of an object is the amount of change in its position over time, or the amount of change in its position per unit time. it is therefore a scalar quantity. The average speed of an object over a period of time is the distance traveled by the object divided by the duration of the interval; The instantaneous speed is the limit of the average speed when the duration of the time interval approaches zero. Speed is not the same as speed.
The speed of the liquid in the second segment is calculated as follows:
V2 = V1 * (A1/A2)^0.5
V2 = 4.0 m/s * (pi * 0.01^2 / pi * 0.02^2)^0.5
V2 = 2.8284 m/s
The speed of the liquid in the third segment is calculated as follows:
V3 = V2 * (A2/A3)^0.5
V3 = 2.8284 m/s * (pi * 0.02^2 / pi * 0.005^2)^0.5
V3 = 14.1421 m/s.
The SI unit of speed is meters per second (m/s), but the most common everyday unit of speed is kilometers per hour (km/h) or miles per hour (mph) in the US and UK. .For air and sea travel, the knot is widely used.
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What will happen if the positive and negative connections on the voltmeter are reversed?
If the applied voltage is polarised in the opposite direction (negative on red and positive on black), the metre will display "backwards."
What happens when polarity reverses?Some devices may be electrically charged at all times if an outlet has reverse polarity. Electricity will flow to the switch in a properly connected outlet; with reversed polarity, it will be present in the item even when it is not switched on.Reverse polarity protection is an internal circuit that ensures the device is not destroyed if the polarity of the power source is reversed. The reverse polarity protection circuit disables power to the transmitter or transducer's sensitive electronic circuitry.If you reside in a house that has had amateur electrical work done, there's a strong chance you have some outlets with reversed polarity. That essentially means that some of your channels may surprise you. Uh oh! While not all shocks are lethal, they are all painful and unpleasant. Only a qualified electrical contractor in North Scottsdale, AZ can perform electrical repairs in your home.
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what is a general rule relating the directions of the applied force, friction force and direction of motion?
According to the general laws, the direction of friction is always the opposite of the direction of motion, parallel to the surface between objects, and perpendicular to the normal force.
According to general laws, the force of friction acts on moving objects in the opposite direction of motion. Frictional force always operates in the opposite direction of applied force.
The normal force is opposite of the object's surface, which implies that if the object is laying on the ground, the normal force will be opposite in direction of the surface on which the surface is lying, which in this case is the ground.
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Which liquid has a specific heat capacity of 1000 J/kg degrees Celsius?
Paraffin has a specific heat capacity of 1000 J/kg degrees Celsius.
What is specific heat capacity?The massic heat capacity, also known as the specific heat capacity or symbol c in thermodynamics, is the quotient of the heat capacity of a sample of a substance and its mass.
Informally, it is the quantity of heat needed to raise a substance's temperature by one degree for every unit of mass that is added to it.
SI unit of specific heat capacity is J-kg⁻¹-K⁻¹.
The specific heat capacity of paraffin is about 1000 J/kg degrees Celsius. Hence, paraffin is the liquid.
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Rank the following worlds by the strength of wind erosion currently operating on their surfaces, from greatest to least:
a. Mercury
b. Venus
c. Earth
d. Moon
e. Mars
The required rank is; a. Mars, b. Earth, c. Moon, d. Venus,e. Mercury
What is wind erosion ?The natural process of wind erosion involves the movement of dirt from one place to another. Significant economic and environmental harm may result from it.
According to question:Wind erosion is primarily caused by the combination of wind speed and wind duration. On Mars, wind speeds can reach up to 60 meters per second and has a thin atmosphere which allows it to erode the surface. Earth has strong winds in certain regions, but not enough to cause significant erosion.
The Moon and Venus have very little or no atmosphere, therefore no wind erosion occurs.
Mercury has a very thin atmosphere, but wind speeds are not enough to cause significant erosion.
Thus, required rank is;
a. Mars
b. Earth
c. Moon
d. Venus
e. Mercury
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prior to starting the engine, which test should be made of the electric gyroscopic instruments prior to ifr flight?
Before starting the engine, a pre-flight functional check should be performed on the electric gyroscopic instruments prior to an IFR flight.
The electric gyroscopic instruments should undergo a pre-flight functional check before the engine is started for an IFR (Instrument Flight Rules) flight. The following steps should be included in this check:
Check the power supply: Make that the instruments are powered by the appropriate, functional source.
Verify the display on each instrument to make sure it is operating properly and producing a visible and legible display.
Check the movements of the indicators: Look at each indicator's movement to make sure it is correct and fluid.
Verify electrical systems: Verify that the electrical systems connected to each instrument are in good working order and don't exhibit any symptoms of wear or damage.
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suppose a ball is thrown straight up and experiences no appreciable air resistance. what is its horizontal acceleration just before it reaches its highest point?
The horizontal acceleration of a ball thrown straight up just before it reaches its highest point is zero. As the ball is thrown vertically upward, its only acceleration is due to gravity, which acts in the downward direction. There is no force acting horizontally, so the horizontal acceleration is zero.
When a ball is thrown straight up, it experiences a gravitational force pulling it down. This results in a vertical acceleration of the ball towards the ground. However, at the highest point of its trajectory, the ball has stopped rising and has not yet started to fall. At this moment, there is no horizontal component of velocity and thus no horizontal acceleration. The ball is only being affected by gravity, which acts vertically, so the horizontal acceleration is zero. This means that the ball does not change its horizontal position or speed as it reaches its highest point.
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a mouse sees a piece of cheese on a conveyor belt moving at 3 m/s. the mouse runs straight toward the cheese at 4 m/s. once on the conveyor belt, what is the speed of the mouse relative to the floor? a mouse sees a piece of cheese on a conveyor belt moving at 3 m/s. the mouse runs straight toward the cheese at 4 m/s. once on the conveyor belt, what is the speed of the mouse relative to the floor? 3 m/s 4 m/s 5 m/s 6 m/s 7 m/s
Once the mouse is on the conveyor belt, its speed relative to the floor will be 7 m/s, as the conveyor belt is moving at a speed of 3 m/s and the mouse is running at a speed of 4 m/s.
The speed of the conveyor belt relative to the floor is 3 m/s.The speed of the mouse relative to the conveyor belt is 4 m/s.The speed of the mouse relative to the floor is the sum of the speed of the conveyor belt relative to the floor and the speed of the mouse relative to the conveyor belt.Therefore, the speed of the mouse relative to the floor is 3 m/s + 4 m/s = 7 m/s.Learn more about speed:
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a physics student places an object 6.0 cm from a converging lens of focal length 9.0 cm. what is the magnitude of the magnification of the image produced?
The magnitude of the magnification of the image produced is 3.0 cm.
In optics, magnification refers to the image's size in relation to the item that produced it. The ratio of the image length to the object length, as measured in planes perpendicular to the optical axis, is referred to as linear magnification, also known as lateral or transverse magnification. An inverted image is shown by a linear magnification value that is negative. The size-increasing factor, as determined along the optical axis, is known as longitudinal magnification. When measured from a specific point in the instrument, as is the case with magnifiers and binoculars, angular magnification is equal to the ratio of the tangents of the angles subtended by an object and its image.
[tex]\frac{1}{f}=\frac{1}{v}+\frac{1}{u}[/tex]
[tex]\frac{1}{9.0cm}=\frac{1}{v}+\frac{1}{6.0}[/tex]
[tex]\frac{1}{v}=\frac{1}{9}-\frac{1}{6}[/tex]
v=-18.0 cm
[tex]M=\frac{-v}{u}[/tex]
[tex]M=\frac{-18}{6}[/tex]
M=3.0 cm
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Rock A is thrown horizontally off of a cliff with a velocity of 20 m/s. The rock lands 60 m from the base of the cliff. Om/s? V=20 m/s 3 m/s? 9.8 m/s? 20 m/s? 60 m CLEAR ALL According to the information and diagram shown above, what is the magnitude of the vertical acceleration for Rock A after it is released?
After being released, Rock A experiences a vertical acceleration of 9.8 m/s2. The acceleration brought on by gravity, which is constant for all objects close to the Earth's surface.
What is called velocity?The vectorial representation of a particle or object's motion with respect to time is called velocity. The metre per second (m/s), usually referred to as speed, is the accepted unit of velocity magnitude. As an alternative, the velocity magnitude can be expressed in centimetres per second (cm/s). Simply said, velocity is the rate of motion of an object in a specific direction. Using an automobile driving north on a highway as an example, or a rocket after it has launched, as an example of speed.
Why is velocity a vector?Speed is a scalar quantity because it just has magnitude and no direction. A vector is necessary to "carry" something from point A to point B; the Latin root of the word vector denotes "carrier". The first to use it were astronomers in the 18th century who were researching planetary rotation around the Sun.
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on the surface of planet x an object has a mass of 22.5 kg and a weighs 63.5 n. what is the gravitational field strength on the surface?
Weight/mass = gravitational field strength is the formula. The gravitational fields of other planets differ in strength.
Why is uniform motion referred to as rapid motion?When an object goes on a circular path at a constant speed, its magnitude of velocity remains constant. Only its orientation is always changing. As a result, it is classified as evenly accelerated motion.
Uniform linear motion is defined as traveling along a straight line at the same velocity. The magnitude or direction of the velocity varies in uniform circular motion, whereas magnitude and direction remain constant in uniform linear motion.
Learn more about gravitational field
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